The percent of carbon within the sample of octane is 84.25%
A percentage is a fraction of a total amount divided into hundred parts
The percent of carbon within the sample of octane = (grams of carbon / grams of octane) x 100
(78.1 g / 92.7 g) x 100 = 84.25%
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The percent of carbon within the sample of octane in the exercise is:
84.25%Calculation of percentages using the rule of three.
To make a calculation of the percentage of a sample, a simple rule of three can be used, where it is identified:
92.7 g → 100% 78.1 g → x
The octane sample is used as 100% since it is the total sample, while carbon is only a part of it, now we proceed to calculate:
[tex]x=\frac{78.1*100}{92.7}[/tex][tex]x=\frac{7810}{92.7}[/tex]x = 84.25026969x ≅ 84.25%In this way, it can be identified that the percentage of carbon in the octane sample is approximately 84.25%.
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10-7X-5+12x=0
Explain
Answer:
x = -1
Step-by-step explanation:
[tex]10 - 7x - 5 + 12x = 0[/tex]
➡️ [tex]5 - 7x + 12x = 0[/tex]
➡️ [tex]5 + 5x = 0[/tex]
➡️ [tex]5 + 5x - 5 = 0 - 5[/tex]
➡️ [tex]5x = 0 - 5[/tex]
➡️ [tex]5x = - 5[/tex]
➡️ [tex]5x \div 5 = - 5 \div 5[/tex]
➡️ [tex]x = - 5 \div 5[/tex]
➡️ [tex]x = - 1[/tex]
Name the pair of opposite rays with endpoint N.
Answer:
Possible Answers: NA and NX or NM and NC.Step-by-step explanation:
PLS MARK ME BRAINLEIEST AND FLW ME
At a charity fund-raiser, adult tickets were sold for $10 each and children's tickets were sold for $4 each. Write an algebraic expression for the total amount of money raised from the sale of tickets. How much money was raised if the fundraiser sold 244 adult tickets and 387 children's tickets?
Answer:
the all adult tickets made out 2440$
the all children tickets made out 1548
plzzzz help (wrong answers will be deleted )...(100 points!!)
16x^4−24x^3+3 / 4x^2+3 fill in the boxes(spaces lol) = x^2 - x - + /
[tex]\boxed{\sf \dfrac{a^m}{a^n}=a^{m-n}}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{16x^4-24x^3+3}{4x^2+3}[/tex]
Take 4x^2+3 common out[tex]\\ \rm\Rrightarrow 4x^2+3\left(\dfrac{4x^2-24x+1}{1}\right)[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{4x^2-24x+1}{1}[/tex]
[tex]\\ \rm\Rrightarrow 4x^2-24x+1[/tex]
Answer:
4x² - 24x + 1
Step-by-step explanation:
[tex]\frac{16x^{4}-24x^{3}+3}{4x^{2}+3}[/tex]
~Factor out the denominator and apply quotient rule [ a^b / a^c = a^b-c ]
[tex]4x^{2}+3 (\frac{\frac{16}{4} x^{4-2}-24x^{3-2}+\frac{3}{3} }{1})[/tex]
[tex]\frac{4x^{2}-24x+1}{1}[/tex]
~Divide everything by 1
[tex]4x^{2} -24x+1[/tex]
Best of Luck!
IXL PLEASE HELP
Ayana bought new equipment for her bowling alley, including a ball return machine. There is a 55% chance that the machine returns a bowling ball with the finger holes facing up.
If the machine returns 4 bowling balls, what is the probability that exactly 3 will have the finger holes facing up?
Write your answer as a decimal rounded to the nearest thousandth.
The answer would be .090
How can 863.141 be written in expanded form?
Answer:
800 + 60 + 3 + 0.1 + 0.04 + 0.001
I need help with this question please
Simplify.
18 2+6(4+1) -2
Step-by-step explanation:
18 2+6(4+1)-2
18 8(5)-2
18 40-2
18 38
18×38
multiply it to get your answer
Can someone please help me I don’t get this (Due today)
Answer:
Which grade's book exercise is this?
What’s expression is equivalent (1/7x+6)-(-4/7x+3
Answer:
[tex]\frac{5}{7}[/tex] x + 3
Step-by-step explanation:
Given
( [tex]\frac{1}{7}[/tex] x + 6) - ( - [tex]\frac{4}{7}[/tex] x + 3) ← distribute by - 1
= [tex]\frac{1}{7}[/tex] x +6 + [tex]\frac{4}{7}[/tex] x - 3 ← collect like terms
= [tex]\frac{5}{7}[/tex] x + 3
>
→
PQ and RS are in the same plane and do not intersect. What geometric term describes PQ and RS?
perpendicular lines
complementary lines
skew lines
parallel lines
Answer:
Parallel lines
Step-by-step explanation:
finish 9 and 10 (giving lots of points!!!!)
Answer:
#9Rule for rotation 90 clockwise about the origin:
(x, y) → (y, -x)Apply to the given points:
S(1, -4) → S'(-4, -1)W(1, 0) → W'(0, -1)J(3, -4) → J'(-4, -3)#10Rule for rotation 180 about the origin:
(x, y) → (-x, -y)Apply to the given points:
V(-5, -3) → V'(5, 3)A(-3, 1) → A'(3, -1)G(0, -3) → G'(0, 3)Show 713.65 in expanded notation
Answer:
713.65 = (7 x 100) + (1 x 10) + (3 x 1) + (6/10) + (5/100)
Step-by-step explanation:
4) 2x(x+y)-(4x+2y)(3x-y)
Answer:
-10x² + 4xy - 2y²
Step-by-step explanation:
2x(x + y) - (4x + 2y)(3x - y)
= 2x² + 2xy - 12x² - 4xy + 6xy - 2y²
= 2x² - 12x² + 2xy - 4xy + 6xy - 2y²
= -10x² + 4xy - 2y²
A) Addition
B) Subtraction
C) Multiplication
D) Exponent
3+16 divided by 4
4 x 7 - 2 x 6 divided by 3
5 (power of 2) - 4 x (2 power of 3) -3)
(-3 (power of 4) divided 9 x (4-5 (power of 3) + 8
Answer:
3+16 divided by 4 is 4.75
4×7-2×6..... is5.33
168
When a new cellphone is put on the market, the demand each month can be described by the function C of t is equal to negative square root of the quantity t squared plus 4 times t minus 12 end quantity plus 3 where C (t) represents the demand of the cellphone (measured in millions of people) and the time, t, is measured in months. Which of the following solution(s) are valid for a positive demand?
A function is positive where it is above the x-axis
The valid solution for positive demand are; t = 3, and t = 2
The reason the above values are correct is as follows:
Known parameters:
The given function of the demand is; [tex]C(t) = \mathbf{ -\sqrt{t^2 + 4 \times t - 12} +3}[/tex]
Where;
C(t) = The demand of the cellphone (in millions of people)
t = The number of months
The condition positive demand is C(t) ≥ 0
Therefore;
[tex]-\sqrt{t^2 + 4 \times t - 12} +3 \geq 0[/tex]
[tex]-\sqrt{t^2 + 4 \times t - 12} \geq -3[/tex]
[tex]\sqrt{t^2 + 4 \times t - 12} \leq 3[/tex]
t² + 4·t - 12 ≤ 9
t² + 4·t - 12 - 9 ≤ 0
t² + 4·t - 21 ≤ 0
(t - 3) × (t + 7) ≤ 0
∴ t ≤ 3, or t ≥ -7
At t = 2 < 3, we have;
C(2) = -√(2² + 4×2 - 12) + 3 = 3
At t = 1 < 3, the function is; C(1) = -√(1² + 4×1 - 12) + 3 (Is undefined)
Therefore, the valid solution for positive demand are;
t = 3, and t = 2
Learn more about the functions here:
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Answer:
3,3
Step-by-step explanation:
A street map uses a scale of 1 cm: 200 m.
a) Simplify this ratio.
B) Find the actual distance, in kilometres, represented by each scaled distance.
i) 7 cm
ii) 9.5 cm
iii)12.4 cm
C) Find the scaled distance, in centimetres, used to represent each actual distance,
i) 18 km
ii) 1500 m
iii) 9.6 km
Answer:
B)
1400m
1900m
2480m
C)
90cm
7.5cm
4.8cm
Express cos9x cos3x as a sum of two trigonometry function
Step-by-step explanation:
the answer is in the image above
John's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs John $5.95 per pound, and type B coffee costs $4.65 per pound. This month's blend used three times as many pounds of type B coffee as type A, for a total cost of $656.70. How many pounds of type A coffee were used?
Answer:
Let x = the number of lbs of Type A coffee.
We know that this month's blend used 3 times as many pounds of type B coffee as type A coffee.
Total lbs of coffee = x + 3x
The total cost then is:
($ cost for Type A)(x) + ($ cost for Type B)(3x) = $717.60
$5.65x + $4.25(3x) = $717.60
$5.65x + $12.75x = $717.60
$18.40x = $717.60
x = 39 lbs
Given the function g of x is equal to the quantity 2 x squared plus 3 x plus 5 end quantity over the quantity x plus 3 end quantity determine the equation for the slant asymptote.
y = –2x + 3
y = 2x + 3
y = 2x – 3
y = 2x + 9
Answer: 2x-3
Step-by-step explanation:
2x-3
---------------
X+3 /2x^2+3x+5
( - )2x^2+6x Multiply x • 2x^2
______. and subtract it from 2x^2
-3x+5. Multiply x • -3 and subtract it
(-)-3x-9 from -3x
______
14
Answer:
y=2x-3
Step-by-step explanation:
Use the distributive property to write the expression without parentheses.
3(3a+2)
3(3a + 2) = (Simplify your answer.)
[tex]\\ \sf\longmapsto 3(3a+2)[/tex]
[tex]\\ \sf\longmapsto 3(3a)+3(2)[/tex]
[tex]\\ \sf\longmapsto 9a+6[/tex]
Hope it helps
102 A marathon is 26.2 miles long. There is a water station every 1 1/4 miles along the race route. How many water stations are needed for this marathon? tills
Answer:
21 stations
Step-by-step explanation:
1 1/4 = 5/4
26.2 / 5/4 = 20.96
rounded up to 21
PLEASE HELP I NEED HELP!!!!!! 30 POINTS
Figure B is a scaled copy of Figure A.
What is the scale factor from Figure A to figure B?
Answer:
1/3
Step-by-step explanation:
The left side of Figure A is 6 units long
The left side of Figure B is 2 units long
6 * what = 2
Divide each side by 6
what = 2/6
what = 1/3
The scale factor is 1/3
Answer:
[tex]\frac{1}{3}[/tex]
Step-by-step explanation:
Figure A has a base of [tex]6[/tex] units.
Figure B has a base of [tex]2[/tex] units.
So, 6 * [tex]x[/tex] (the scaled factor) = 2 which simplified is [tex]6x=2[/tex].
Now, we divide 6 on both sides giving us [tex]x = \frac{2}{6}[/tex] which can be further simplified into [tex]\frac{1}{3}[/tex]
write 2.5 repeating as a mixed number in simplest form.
Answer:
2 5/9
Step-by-step explanation:
2.5 repeating is 2 5/9 as a fraction (mixed number) or 23/9 (fraction)
The repeating decimal 2.5 can be written as the mixed number 2 5/9 in simplest form.
Here, we have,
To convert the repeating decimal 2.5 to a mixed number in simplest form, we can follow these steps:
Step 1:
Let's assume x = 2.5
Step 2:
Multiply both sides of the equation by 10 to shift the decimal point one place to the right: 10x = 25.5
Step 3:
Subtract the original equation from the one obtained in Step 2 to eliminate the repeating part:
10x - x = 25.5- 2.5
9x = 23 (since the repeating part subtracts to zero).
Step 4: Solve for x by dividing both sides by 9:
x = 23 / 9.
Step 5: Express the fraction 23/9 as a mixed number:
23 ÷ 9 = 2 remainder 5.
Therefore, x = 2 remainder 5/9.
so, we get,
Thus, the repeating decimal 2.5 can be written as the mixed number 2 5/9 in simplest form.
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Find the distance between the points.
(9.7, -2.1), (-3.2, 8.1)
which numbers are equivalent to 3 tenths ? Choose all that apply.
Can someone help me on this?? Im really struggling
Order the numbers from least to greatest.
A) 3.41%, 0.31, 0.314, 0.3333
B) 0.3333, 0.31, 0.314, 3.41%
C) 3.41%, 0.314, 0.3333, 3.51%
D) 0.31, 0.314, 0.333, 3.41%
Answer:
a) 3.41%, 0.31, 0.314, 0.3333
Find the midpoint in geometry.
[tex]\\ \rm\longmapsto (x,y)=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)[/tex]
[tex]\\ \rm\longmapsto (x,y)=\left(\dfrac{3+3}{2},\dfrac{6-2}{2}\right)[/tex]
[tex]\\ \rm\longmapsto (x,y)=\left(\dfrac{6}{2},\dfrac{4}{2}\right)[/tex]
[tex]\\ \rm\longmapsto (x,y)=(3,2)[/tex]
at a certain certain point in time the sun of an alien world is directly overhead that
world's equator
5x-4[7+(2x-4)], for x=-3
Answer:
-3
Step-by-step explanation:
Plug in x = -3
5(-3) - 4[7+(2(-3)-4)]
We'll use order of operations (PEMDAS) from here on out.
Evaluate what is in the innermost parentheses first (2(-3) - 4: the parentheses inside of the brackets). We first multiply 2 * -3, then subtract -4.
2(-3) - 4 = -6 - 4 = -10
So the whole expression becomes
5(-3) - 4[7+ -10]
Now evaluate what is in brackets.
5(-3) - 4[-3]
Multiplication next, before addition.
-15 + 12
Finally, addition
-3