Answer:
a) The forces acting on the box and the table are as follows:
Weight of the box acting downwards (due to gravity)
Normal force acting upwards (from the table)
Frictional force (if the box is not moving, the frictional force will be equal and opposite to any force applied to move it)
b) The weight of the box is given by:
Weight = Mass x Acceleration due to gravity
Weight = 1.5 kg x 9.81 m/s^2
Weight = 14.715 N
The weight acts downwards due to gravity.
The counteraction force of the table is equal in magnitude and opposite in direction to the weight of the box, as per Newton's Third Law of Motion.
Therefore, the counteraction force of the table on the box is also 14.715 N, but it acts upwards to balance the weight of the box.
Explanation:
which wavelength of laser light can be used with the photodiode detector in the atomic force microscope?
The wavelength of laser light that can be used with the photodiode detector in the atomic force microscope is 635nm.
A photodiode is a device that converts light energy into electrical energy by absorbing photons. When photons fall on a photodiode, electron-hole pairs are produced in it. The diode's p-n junction facilitates the flow of these pairs of electrons, which leads to the creation of photocurrent. Photodiodes are frequently employed in cameras, solar cells, medical equipment, and even in AFM machines. A photodiode is a transducer that is sensitive to light. It is made up of a p-type semiconductor and an n-type semiconductor, with a thin insulating layer in between that, is sensitive to light. Photodiodes are similar to regular diodes in terms of current flow. When light photons hit the diode, they are absorbed, resulting in a change in its electrical properties. There are a variety of wavelengths used in microscopes, depending on the type and purpose of the microscope.
The selection of the right wavelength of light to use in a microscope can enhance the contrast and resolution of the image. However, in the atomic force microscope, the 635nm wavelength is utilized with the photodiode detector to obtain a high-resolution image. The AFM microscope employs a laser to achieve high spatial resolution. The beam is directed at the sample, and the laser light is reflected off the sample's surface and onto the detector. The displacement of the cantilever is detected by the photodiode detector.
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when a hammer thrower releases her ball, she is aiming to maximize the distance from the starting ring. assume she releases the ball at an angle of 47.9 degrees above horizontal, and the ball travels a total horizontal distance of 33.6 m. what angular velocity must she have achieved (in radians/s) at the moment of the throw, assuming the ball is 1.16 m from the axis of rotation during the spin?
In order to throw the ball to a distance of 33.6\ m, the hammer thrower must achieve an angular velocity of 15.7 rad/s.
We need to find the velocity of the ball at release. We can use the equations of projectile motion to relate the horizontal distance traveled by the ball to its initial velocity and angle of release. The horizontal distance is given by:
[tex]d = (V^2\times sin(2\theta))/g[/tex]
where d is the horizontal distance, V is the initial velocity, g is the acceleration due to gravity, and θ is the angle of release.
Given horizontal distance d = 33.6\ m and θ = 47.9°
Substituting the given values, we get:
[tex]33.6 m = (V^2sin(2\times47.9^o))/9.8\ m/s^2[/tex]
Solving for V, we get:
V = 18.21 m/s
Now, to find the angular velocity we can use the formula
[tex]\omega = V/r[/tex]
[tex]\omega=18.21/1.16\ rad/s[/tex]
[tex]\omega = 15.705\ rad/s[/tex]
Therefore, the angular velocity the hammer thrower must have achieved at the moment of the throw is [tex]15.705\ rad/s[/tex].
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which of the following statements regarding air masses is not true? group of answer choices air masses are named for both their moisture and thermal characteristics air masses form in relatively flat locations with uniform temperature and moisture characteristics air masses always form over areas featuring complex terrain air masses can be transported by surface high- and low-pressure systems
The statement that is not true regarding air masses is: c. air masses always form over areas featuring complex terrain.
Air masses are large bodies of air with similar temperature and moisture characteristics. They form in relatively flat locations with uniform temperature and moisture conditions, as mentioned in statement b. Complex terrains, such as mountains or varied landscapes, can disrupt the formation of air masses due to uneven heating and variations in moisture levels.
As stated in statement a, air masses are named for both their moisture and thermal characteristics. There are four primary types of air masses, which are categorized based on their source regions: polar (cold), tropical (warm), maritime (moist), and continental (dry). For example, a maritime tropical air mass would be warm and humid, while a continental polar air mass would be cold and dry.
Air masses can be transported by surface high- and low-pressure systems, as mentioned in statement d. High-pressure systems typically move air masses from regions of high pressure to regions of low pressure. As air masses move, they can influence the weather conditions in the areas they pass over. For example, a cold front occurs when a cold air mass moves into an area occupied by a warmer air mass, often leading to precipitation and a drop in temperature.
In summary, air masses form in flat locations with uniform conditions, are named for their moisture and thermal characteristics, and can be transported by surface high- and low-pressure systems. The statement claiming that air masses always form over complex terrain is not true. Therefore, the correct option is C.
The Question was Incomplete, Find the full content below :
which of the following statements regarding air masses is not true?
a. air masses are named for both their moisture and thermal characteristics
b. air masses form in relatively flat locations with uniform temperature and moisture characteristics
c. air masses always form over areas featuring complex terrain
d. air masses can be transported by surface high- and low-pressure systems
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Which of the following is true about poles on magnets?
O A. North poles attract south poles
O B. No th poles repel south poles.
O c. North soles attract north pales
Do Both Bland Care inte
Answer: A. North Poles attract south poles
Explanation:
Opposite poles attract
Same poles repel
which of the following makes titan special? group of answer choices it is the only moon in the solar system with an atmosphere weathering of the surface cryovolcanoes that spew liquid water liquid methane lakes all of the above
All of the above make Titan special.
Titan is the only moon in the solar system with a dense atmosphere, which is mostly made up of nitrogen, and also contains some methane and other gases. The atmosphere creates weather on Titan, including winds and rain, and can cause erosion and other forms of weathering on the moon's surface.
Cryovolcanoes, which spew liquid water and other materials, have been discovered on Titan, making it one of the few places in the solar system where active volcanism has been observed. In addition to water, these cryovolcanoes can also emit liquid methane and other compounds.
Liquid methane lakes have also been observed on Titan's surface. These lakes are made possible by the low temperatures and high atmospheric pressure on the moon, which allow methane to exist in liquid form.
Overall, Titan is a unique and fascinating moon with many special features that make it of great interest to scientists studying the solar system.
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All of the above factors make Titan unique in the solar system. Therefore, the correct option is E.
Titan is a fascinating and distinctive moon of Saturn, with a number of characteristics that set it apart from other moons in the solar system. The following are the features that make titan special:
Atmosphere: Titan is the only moon in the solar system with a thick, Earth-like atmosphere. The majority of Titan's atmosphere is nitrogen, and there are traces of other gases like methane and ethane as well. The presence of an atmosphere on Titan is one of the factors that distinguish it from other moons in the solar system, which either have no atmosphere or only a thin one.
Weathering of the Surface: Titan's surface is carved with intricate patterns that are similar to those found on Earth. There are mountains, canyons, and river systems. However, the atmosphere is responsible for the weathering of Titan's surface. The temperature on Titan is too cold for liquid water to exist, so any flowing liquid on the surface is in the form of methane.
Cryovolcanoes That Spew Liquid Water: Titan has cryovolcanoes, which spew liquid methane and other substances. Volcanoes are typically associated with hot, molten rock on Earth, but on Titan, the volcanoes spew icy substances rather than molten lava. This again sets Titan apart from other moons in the solar system.
Liquid Methane Lakes: Titan is the only moon in the solar system with large bodies of liquid on its surface. However, these are not water lakes but instead contain liquid methane and other hydrocarbons. Despite the fact that the composition of the liquid is different from that of water, the presence of lakes on Titan is still highly unusual.
All of the above factors make Titan unique in the solar system. It is the only moon with an atmosphere and has distinct weathering, cryovolcanoes, and methane lakes that all make it special.
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g why can we ignore expanding of 13 l steel scuba tank when evaluating the mass of air the tank is filled with? is it a good approximation? explain.
The expansion of a 13L steel scuba tank can be ignored when evaluating the mass of air inside because the volume increase due to expansion is very small compared to the tank's original volume. It is a good approximation.
The expansion of a 13L steel scuba tank occurs due to changes in temperature and pressure. When the tank is filled with air, the air inside the tank is also affected by these changes. However, the volume increase due to expansion is typically very small compared to the original volume of the tank. As a result, the mass of air inside the tank can be evaluated without taking into account the expansion of the tank. This is a good approximation because the expansion is negligible in comparison to the total volume of the tank. However, it's worth noting that if a more precise calculation is required, the expansion of the tank should be taken into account.
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which is greater? the annual energy usage of the earth, or the energy released by the sun in 1 second?
The energy released by the sun in one second, also known as the solar luminosity, is much greater than the annual energy usage of the earth.
The solar luminosity is estimated to be about 3.8 x 10^26 watts, while the total energy usage of the earth is estimated to be around 157,481 terawatt-hours per year, or about 18 x 10^12 watts. This means that the energy released by the sun in just one second is many orders of magnitude greater than the total energy used by all human activities on earth in a year. The sun's enormous energy output is what drives most of the physical and biological processes on our planet.
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the image quality of most optical telescopes is limited by differential atmospheric refraction experienced by light as it passes through the earth's atmosphere. question 45 options: true false
The statement, "The image quality of most optical telescopes is limited by differential atmospheric refraction experienced by light as it passes through the earth's atmosphere" is TRUE.
Differential atmospheric refraction is a process by which the direction of a star or celestial object can differ based on the location and height of the star, as well as the time of observation. As light from stars passes through Earth's atmosphere, it is refracted and deflected, resulting in a slight change in the location of the object. Telescopes rely on light rays to form images of distant celestial objects, which are subsequently captured by a camera or observer. This bending of light and the resulting effect on image quality and clarity is referred to as atmospheric refraction. Atmospheric refraction causes the light to curve, causing distortions and wavy patterns in the images formed by telescopes. This distortion limits the sharpness and clarity of the images produced by telescopes. Astronomers and engineers are continuously working to design telescopes that minimize the effects of atmospheric refraction, allowing for clearer images of celestial objects. However, it is still a significant issue for most optical telescopes.
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PLEASE PLEASE PLEASE HELP ME ANSWER THIS QUESTION!
What atoms are found in CO2?
CO2 contains one carbon atom and two oxygen atoms.
C stands for carbon
O for oxygen
an automobile tire turns at a rate of 10 full revolutions per second and results in a forward linear velocity of 17.8 m/s. what is the radius of the tire?
An automobile tire turns at a rate of 10 full revolutions per second and results in a forward linear velocity of 17.8 m/s then the radius of the tire will be 0.283m
The radius of the tire can be determined using the given data from the question.
For instance, using the equation
v = 2πr N.
Where `v` is the forward linear velocity, `r` is the radius, and `N` is the revolutions.
The value of `v` is 17.8m/s and `N` is 10 full revolutions/second.
Plugging in the values,
v = 2πr N
17.8 = 2 × 3.1416 × r × 10
17.8 = 62.8318r
Therefore,
r = 17.8/62.8318
r = 0.283m
Hence, the radius of the tire is 0.283m.
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A wave has an amplitude of 0.5 meters. The wave's amplitude increases to 1.5 meters.
How does the energy transported by the wave change?
The energy transported by the wave increases by a factor of 9,
The energy transported by a wave is proportional to the square of its amplitude. Therefore, if the amplitude of the wave increases from 0.5 meters to 1.5 meters, the energy transported by the wave increases by a factor of
[tex](1.5/0.5)^2 = 9.[/tex]
Wave amplitude is the maximum displacement or distance moved by a particle of the medium from its rest position when a wave passes through it. In simpler terms, it is the height of the wave from its equilibrium position. The amplitude is usually measured in meters (m), centimeters (cm), or sometimes in units of pressure, such as Pascals (Pa) for sound waves.
Energy transferred by a wave refers to the amount of energy that the wave carries as it travels through a medium.
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What is the quantum physics observer paradox?
Answer:
“The paradox means that if quantum theory works to describe observers, scientists would have to give up one of three cherished assumptions about the world,” said Associate Professor Eric Cavalcanti, a senior theory author on the paper.
which is involved in generating electricity through nuclear fission? a positive feedback loop creation of chemical energy release of kinetic energy
"A positive feedback loop creation and release of kinetic energy are involved in generating electricity through nuclear fission. The correct option is E."
Fission is a radioactive decay process in which involves the division nucleus of an atom into two or more fragments, resulting in the release of a large amount of heat energy. It occurs when a neutron slams into a large atomic nucleus, forcing it to split into two smaller parts.
During splitting, new neutrons are released, which can promote extra fission reactions, leading to a nuclear fission chain reaction that generates an enormous amount of heat energy. This is a reference to a positive feedback loop.
1 neutron + large atomic nucleus → 2 smaller atomic nuclei + neutrons in motion (kinetic energy)
Kinetic energy is an energy that an object or a particle has due to its motion. Best choice is E.
The given question is not appropriate. The complete question is 'Which of the following is involved in generating electricity through nuclear fission? I. A positive feedback loop, II. Creation of chemical energy, III. Release of kinetic energy. (a) I only, (b) II only, (c) III only, (d) I and II, (e) I and III.'
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Fill The Blank? at room temperature in a vacuum the speeds of gases are typically ________________ and vary with the inverse square of the ____________.
At room temperature in a vacuum, the speeds of gases are typically 1.4 km/s and vary with the inverse square of the molecular weight.
What is the Kinetic Theory of Gases?The Kinetic Theory of Gases describes the conduct of gases. It explains that the behavior of gases can be explained in terms of the movement of their particles. Gases are composed of a vast number of small particles (molecules) that are continually moving in random directions at high speeds. These particles collide with each other and with the walls of their container. The Kinetic Theory of Gases is concerned with the properties of gases in their motion states at temperatures at which the intermolecular forces are insignificant.
What is the explanation for the relationship between gas temperature and molecular speed?The relationship between gas temperature and molecular speed is due to the fact that the thermal motion of a particle is directly proportional to its temperature. Because gases have a lot of thermal energy and the kinetic energy of particles is proportional to temperature, gas particles travel very quickly. The speed of gas particles is faster than the speed of particles in liquids and solids because the latter is closer together and interact with each other more frequently.
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Please help me with this question:
You're traveling by car to a particular destination.
Your car travels at 60mph when conditions are perfect. Sadly for you, things are not perfect this night, it is raining, and raining hard, you'll only be able to travel 20mph in the heavy rain, and 30mph in the light rain, if it is foggy, you must decrease your speed by 5mph.
You travel for 20 miles in the pouring rain before you reach a patch of fog. You travel for another 30 miles in the heavy rain/fog mixture. The rain lightens up, the fog clears, and you travel another 15 miles before reaching your destination.
How long did it take you to get there?
It took 3 hours and 15 minutes to get to the destination.
Given dataPouring rain: 20 miles, 20mph Heavy rain/fog: 30 miles, 30mph Light rain: 15 miles, 30mph Total distance: 65 milesCalculation procedures
Pouring rain (20mph): 20 miles / 20mph = 1 hour
Heavy rain/fog mixture (30mph): 30 miles / 30mph = 1 hour
Light rain (30mph): 15 miles / 30mph = 30 minutes
Total time: 1 hour + 1 hour + 30 minutes = 3 hours and 15 minutes
Traveling at night in the rain can be difficult and slow. Even with perfect conditions of 60mph, the heavy rain and fog reduced the speed to only 20mph, which added three hours and fifteen minutes to the total travel time.
It's important to drive cautiously and safely when road conditions are not ideal.
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a 500 g rock slides across an ice covered pond and strikes a 725 g object that is at rest. is it possible for both objects to be at rest after the collision?
Yes, it is possible for both objects to be at rest after the collision. This type of collision is known as an elastic collision.
In an elastic collision, both kinetic energy and momentum are conserved. Kinetic energy is the energy that an object possesses due to its motion. In a perfectly elastic collision, the kinetic energy is completely conserved, meaning that it is transferred from one object to another. Momentum is the product of an object's mass and velocity.
In an elastic collision, momentum is conserved.To solve this problem, we can use the conservation of momentum. According to the principle of conservation of momentum, the total momentum of a system of objects is conserved if there is no external force acting on the system. In this case, both objects are on the same surface and are only subjected to the frictional force of the surface.
The momentum of the rock before the collision can be calculated as: p1 = m1v1 = 0.5 kg × 3 m/s = 1.5 kg m/s.The momentum of the object at rest before the collision can be calculated as:p2 = m2v2 = 0.The total momentum of the system before the collision is:p1 + p2 = 1.5 kg m/s.The momentum of both objects after the collision is zero, so the total momentum of the system after the collision is also zero.
Therefore: p1' + p2' = 0.p1' is the momentum of the rock after the collision, and p2' is the momentum of the object at rest after the collision. Since the total momentum of the system is conserved, we can write: p1' + p2' = p1 + p2.0.5 kg × v1' + 0.725 kg × v2' = 1.5 kg m/s.
The two unknown velocities can be solved using the two equations: p1 + p2 = p1' + p2' and 0.5 kg × v1' + 0.725 kg × v2' = 1.5 kg m/s.
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in engineering mechanics, the force component v acting tangent to, or along the face of, the section is called the
In engineering mechanics, the force component that acts tangent to, or along the face of, a section is called the shear force.
In engineering mechanics, the shear force is the component of a force that acts tangent to, or along the face of, a section. It is a type of force that arises when two parts of a material or structure are moved in opposite directions, causing the material to deform or break. Shear forces are commonly encountered in the design and analysis of structures, such as bridges and buildings. Engineers need to understand and account for shear forces in their designs to ensure that the structures can withstand the forces they will be subjected to during use. In general, shear forces can be thought of as a type of sliding force, acting parallel to the face of a section.
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Must an object be rotating to have a nonzero moment of inertia?
No, an object does not have to be rotating to have a nonzero moment of inertia. Moment of inertia is the property of an object that describes its resistance to rotational motion about an axis. It is calculated by summing up the product of the mass of each particle in the object and its distance from the axis squared. The formula for the moment of inertia is I = Σmr².
The moment of inertia depends on the mass distribution of an object. If the mass is evenly distributed around the axis of rotation, then the moment of inertia is the same in all directions. However, if the mass is concentrated at a distance from the axis, then the moment of inertia will be higher.Even if an object is not rotating, it still has a moment of inertia. This is because the moment of inertia depends only on the mass distribution and not on the motion of the object.
For example, a solid sphere and a hollow sphere of the same mass and radius have different moments of inertia, even though they are not rotating.The moment of inertia is an important property in physics, as it is used to calculate the torque required to produce a given angular acceleration. It is also used to predict the motion of objects in rotational motion, such as spinning tops, gyroscopes, and planets.
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UN +4 = 8M 1 Clockwise moment = fxSL 4 In the diagram, a plank weighing 120 N is supported by two trestles at points A and B. A man weighing 480 N is standing on the plank. 7134 1 m -2 m weight of man = 480 N centre of mass of plane weight of plank = 120 N B 2023/3/18 12:47 a Redraw the diagram, showing all the forces acting on the plank. Calculate the total clockwise moment of the two weights about A. c. Use the principle of moments to calculate the upward force from the trestle at B. d What is the total downward force on the trestles? e What is the upward force from the trestle at A? f The man now walks past A towards the left-hand end of the plank. What is the upward force from the trestle at B at the instant the plank starts to tip? g How far is the man from A as the plank tips? Burto atspog
The responses obtained using the principle of moments are;
(a) Please find attached the drawing of the forces acting on the plank created with MS Word
(b) 720 N·m
(c) 180 N
(d) 600 N
(e) 420 N
(f) 0
(g) 0.5 meters from A
What is the principle of moments?
The principle of moments is a fundamental physics principle that is used to explain how objects in equilibrium. The principle states that at equilibrium; The total clockwise moments = The total anticlockwise moment.
(a) Please find attached the drawing showing the weights acting on the plank, created with MS Word
(b) The total clockwise moments of the two weights about A is calculated as follows:
- The moment of the weight of the plank about A is 120 N × 3 m = 240 N·m
- The moment of the weight of the man about A is 480 N × 1 m = 480 N·m
- The total clockwise moment of the two weights about A is 240 N·m + 480 N·m = 720 N·m
(c) The anticlockwise moment about A is; Upward force from trestle B × 4 m
The principle of moments indicates;
∑(Clockwise moment) = ∑(Anticlockwise moment)
Therefore; 720 N·m = Upward force from trestle B × 4 m
Upward force from trestle B = 720 N·m/(4 m) = 180 N
The upward force at trestle B is 180 N
(d) The total downward force on the trestles is; 120 N + 480 N = 600 N
(e) The principle of equilibrium indicates that we get;
The sum of upward forces = The sum of downward forces, therefore;
180 N + The upward force at trestle A = 600 N
The upward force at trestle A = 600 N - 180 N = 420 N
(f) When the man walks past A to the left-hand end of the plank, we get;
The plank starts to be lifted upwards from trestle B such that the upward force from trestle B becomes 0
(g) When the plank tips, we get;
480 × x = 120 × 2
x = 120 × 2/480 = 0.5
The man is 0.5 m from the trestle A as the plank tips.
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if the transfer orbit has a semi-major axis of 195100000 km, how long, in days, would the interplanetary trip last? hint: first, determine the period of the transfer orbit.
The interplanetary trip would last approximately 594 days, or about 1.6 years.
To find the period of the transfer orbit, we can use Kepler's third law, which states that the square of the period of an orbit is proportional to the cube of the semi-major axis,
(T_transfer)^2 / (a_transfer)^3 = (T_earth)^2 / (a_earth)^3
where T_transfer is the period of the transfer orbit, a_transfer is the semi-major axis of the transfer orbit, T_earth is the period of Earth's orbit, and a_earth is the semi-major axis of Earth's orbit.
Assuming that Earth's orbit is circular with a semi-major axis of 149.6 million km, we can substitute the given values and solve for T_transfer:
(T_transfer)^2 / (195100000 km)^3 = (365.25 days)^2 / (149.6 million km)^3
T_transfer = sqrt[(195100000 km)^3 * (365.25 days)^2 / (149.6 million km)^3] = 593.6 days
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if the person lets her arm swing freely from an initial position that is straight out and parallel to the ground, when is the angular acceleration of the arm about the shoulder the greatest?
The angular acceleration of the person's arm about the shoulder is the greatest when the arm is at its lowest point during the swing, perpendicular to the ground.
The angular acceleration of the arm about the shoulder will be the greatest when the arm is at its lowest point during the swing, which is perpendicular to the ground.
1. The person's arm starts in an initial position that is straight out and parallel to the ground.
2. As the person allows her arm to swing freely, gravitational force causes the arm to accelerate downward.
3. The force acting on the arm is the weight of the arm, which can be considered to act at its center of mass.
4. As the arm moves downward, the torque (rotational force) about the shoulder joint increases due to the increased force of gravity acting on the arm.
5. The angular acceleration is directly proportional to the torque and inversely proportional to the moment of inertia.
In this case, the moment of inertia remains constant as the arm's mass and length remain the same throughout the swing.
6. Therefore, the angular acceleration of the arm will be the greatest when the torque about the shoulder is the largest.
7. The torque will be the largest when the arm is at its lowest point during the swing, which is when it is perpendicular to the ground.
This is because the force of gravity acting on the arm has the most significant impact at this position.
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A student was investigating the effect of the size of the current flowing on the strength of an electromagnet
Suggest two important potential variables she would need to control to make her investigation a fair test
Answer:
the student should use the same type and size of iron core for each current level tested
Explanation:
To make the investigation a fair test, the student would need to control for variables that could affect the strength of the electromagnet other than the size of the current flowing through it. Two important potential variables to control are:
The number of turns in the coil: The number of turns in the coil can affect the strength of the electromagnet. More turns in the coil can increase the strength of the electromagnet, and fewer turns can decrease it. Therefore, the student should use the same number of turns in the coil for each current level tested.
The type and size of the iron core: The type and size of the iron core can also affect the strength of the electromagnet. A larger or different type of iron core can increase or decrease the strength of the electromagnet, respectively. Therefore, the student should use the same type and size of iron core for each current level tested
what would have to be the mass of this asteroid for the day to become 20.0% longer than it presently is as a result of the collision? assume that the asteroid is very small compared to the earth and that the earth is uniform throughout. express your answer in terms of the earth's mass m .
The mass of the asteroid for the day to become 20% longer than it presently is as a result of the collision is three times the mass of the Earth.
When an asteroid collides with Earth, the day may become longer or shorter. The asteroid can cause Earth's rotation to slow down, leading to longer days or it may increase Earth's rotation speed, leading to shorter days. To find the mass of the asteroid for the day to become 20% longer than it presently is as a result of the collision, we can use the law of conservation of angular momentum. Angular momentum is the product of mass, velocity, and radius of the rotating object.
According to the law of conservation of angular momentum, the angular momentum of an object is conserved if there is no net external torque acting on it before and after a collision or any other event.
Mathematically, angular momentum is given as:
L = mvr
Where L = angular momentum, m = mass, v = velocity, r = radius of rotation. As the asteroid is very small compared to the Earth, we can assume that the Earth's mass remains constant before and after the collision. Therefore, the angular momentum of the Earth before and after the collision must be the same. Hence, we have:
L initial = L final
m asteroid x v asteroid x r asteroid = (m earth ) x (v earth ) x (r earth )
The speed of rotation of the Earth and the radius of rotation remains constant. Thus, we can substitute
v earth x r earth = constant in the above equation.
m asteroid x v asteroid = (m earth ) x constant x 1.2 {20% increase in length of day = 1.2}
m asteroid/m earth = 1.2/0.4
m asteroid/m earth = 3
The mass of the asteroid for the day to become 20% longer than it presently is as a result of the collision is three times the mass of the Earth.
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suppose the ring rotates once every 4.20 s . if a rider's mass is 59.0 kg , with how much force does the ring push on her at the top of the ride?
The ring exerts a force on the rider at the top of the ride, which is equal to the gravitational force on the rider and is approximately 579.39 N.
The force with which the ring pushes on the rider at the top of the ride is equal to the normal force exerted by the ring on the rider, which is also equal to the gravitational force on the rider. The gravitational force on the rider can be calculated using the formula F = mg, where m is the mass of the rider and g is the acceleration due to gravity. Therefore, the force is approximately 579.39 N. At the top of the ride, the net force acting on the rider is zero, so the normal force exerted by the ring must be equal and opposite to the gravitational force. Without knowing the radius of the ring, we cannot calculate the velocity of the rider or the centripetal force. However, if the radius of the ring is very large compared to the size of the rider, then the centripetal force will be negligible, and the normal force will be approximately equal to the gravitational force.
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If an object does not move in a straight line, which will have a greater value (be bigger)?
A. the distance and displacement will be equal
B. the distance it traveled
C. its displacement from start to finish
Answer: A
Explanation:
a uniform electric field points along the x axis. if a stationary electron is placed in this field, in what direction will it be forced to sstart to move?
The stationary electron placed in a uniform electric field pointing along the x axis will be forced to move in the direction opposite to that of the field, which is along the x axis. To be more specific, the electron will be forced to move along the positive y-axis.
An electric field is defined as the force that is experienced by a charged particle when it is placed in an electric field. It is represented by an electric field line that points in the direction of the electric field's intensity. An electric field is usually created by a charged particle or an electric charge.
Electric field intensity is a vector quantity that represents the strength of the electric field at any given point in space. The electric field is represented by E, and the electric field intensity is represented by E. The electric field is usually directed from the positive charge to the negative charge.
When a stationary electron is placed in an electric field, it will move in the direction opposite to that of the electric field. Therefore, if a uniform electric field is directed along the x-axis and a stationary electron is placed in this field, it will start to move in the direction opposite to that of the electric field or along the y-axis.
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explain why this is so. drag the terms on the left to the appropriate blanks on the right to complete the sentences. resethelp when the barrel is full it has a much blank moment of inertia and resistance to changes in its rotation, so it will be a blank stable moving platform than the empty barrel.target 1 of 2target 2 of 2 request answer provide feedback
Answer:
Saanvi recorded the number of math problems she did for homework each night for 10 days.
Explanation:
astronauts are spun in a device called a centrifuge as a physical test before they fly in space. with what linear speed would an astronaut need to be spinning in order to experience an acceleration of 3 g's at a radius of 10.0 m?
An astronaut would need a linear speed of 30.6 m/s to be spinning in order to experience an acceleration of 3 g's at a radius of 10.0 m.
The linear speed of an astronaut in a centrifuge in order to experience an acceleration of 3 g’s at a radius of 10.0 m can be calculated using the following equation:
Linear Speed = (Centrifugal Acceleration * Radius)/9.81
Therefore, the linear speed of the astronaut in the centrifuge will be:
Linear Speed = (3 * 10.0 m)/9.81
Linear Speed = 30.6 m/s
This means that an astronaut needs to be spinning at a linear speed of 30.6 m/s in a centrifuge in order to experience an acceleration of 3 g’s at a radius of 10.0 m. This is a physical test that astronauts need to undergo before they are allowed to fly in space.
The centrifuge is designed to simulate the gravitational effects on the body that astronauts experience during a space mission. This is done by spinning the astronaut around a fixed point and applying the centripetal force on them, which is calculated using the equation:
Centripetal Force = Mass * Linear Speed^2/Radius
This force provides an artificial gravitational pull on the astronaut and helps them get used to the acceleration effects they will experience in space. The greater the linear speed and radius, the greater the centrifugal force, and hence the greater the acceleration experienced by the astronaut.
It is important that astronauts get used to the acceleration experienced in space as they will be required to work in the space environment and need to be physically prepared. The centrifuge allows astronauts to become acclimatized to the effects of high acceleration and helps them perform better in space.
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a stun gun is shot towards a mugger and travels 3 meter before it hits the mugger how long does it take the stun gun to reach the mugger
A. 0.545
B. 0.06
C. 0.0848
D. 0.848
The time taken by the stun gun to reach the mugger is approximately 0.781 seconds. Answer: C. 0.0848 (rounded to 3 decimal places).
To determine the time taken by the stun gun to reach the mugger, we need to use the equation for distance traveled with constant acceleration:
distance = (1/2) x acceleration x time^2
We can rearrange this equation to solve for time:
time = sqrt((2 x distance) / acceleration)
We don't have the acceleration of the stun gun, but we can assume that it travels at a constant speed. Therefore, we can use the equation:
speed = distance / time
to calculate the speed of the stun gun, and then use the formula:
time = distance / speed
to find the time taken to travel the distance.
Assuming the stun gun travels at a constant speed, we can calculate its speed as:
speed = distance / time
speed = 3 m / time
We don't know the time yet, so we can't solve for the speed directly. However, we do know that the stun gun is moving horizontally, and we can assume that it is affected only by gravity in the vertical direction. Therefore, we can use the formula for the time taken for an object to fall a certain distance under the influence of gravity:
distance = (1/2) x acceleration due to gravity x time^2
to find the time it takes for the stun gun to fall 3 meters (the distance it travels horizontally).
We can rearrange the formula to solve for time:
time = sqrt((2 x distance) / acceleration due to gravity)
Substituting the values, we get:
time = sqrt((2 x 3) / 9.81)
time = sqrt(0.611)
time = 0.781 seconds (approx.)
Now that we know the time taken for the stun gun to fall 3 meters, we can use the formula:
time = distance / speed
to find the time taken to travel the distance:
time = 3 m / speed
Substituting the value of speed we found earlier, we get:
time = 3 m / (3 m / 0.781 s)
time = 0.781 s (approx.)
Therefore, the time taken by the stun gun to reach the mugger is approximately 0.781 seconds. Answer: C. 0.0848 (rounded to 3 decimal places).
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Please help. I need to know why B is the correct answer. I will mark you as brainiest and I can help you with something you need help with, I just really need help on this
B The glider moves to the right because the magnitude of the change in momentum of the rubber ball is greater than the magnitude of the changes in momentum of the clay ball.
How does the force occur?The magnitude of the change in momentum of an object is equal to the force exerted on it multiplied by the time during which the force acts. Since the glider has the same mass as the two balls combined, its change in momentum must be equal and opposite to the total change in momentum of the balls.
The clay ball has a smaller magnitude of change in momentum than the rubber ball because it sticks to the glider and does not rebound. Thus, the magnitude of the change in momentum of the rubber ball is greater than that of the clay ball, and since the two changes in momentum are equal and opposite, the glider must move in the direction of the rubber ball's change in momentum, which is to the right.
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Image transcribed:
A day hall and a rubber ball of identical mass are moving toward a gider that is at rest in a frictionless air track The balls have the same speed, with the rubber ball moving toward the left as shown above. The balls strike the glider at the same time. The day ball sticks to the glider and the rubber ball bounces off it.
Which of the following indicates the direction of motion of the glider after the collisions and explains why it moves in that direction?
A The glider moves to the left because the clay ball has more inertia when it sticks to the glider than the rubber ball does when it bounces off.
B The glider moves to the right because the magnitude of the change in momentum of the rubber ball is greater than the magnitude of the changes in momentum of the clay ball
C The glider moves to the left because the clay ball exerts a force on the glider for a longer time than the rubber ball does.
D The glider moves to the right because the collision with the rubber ball is elastic and conserves energy