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Helium is depicted in orbital diagram A. (atomic number 2). It has one s orbital with two electrons in it.

The first to be filled will have a maximum of two electrons. The maximum of two electrons will then be placed in position 2s. The maximum number of six electrons will then be transferred to 2p.

A maximum of two electrons with the opposite spin can fit in any orbital. One 1s orbital and two electrons are contained within the first shell. 8 electrons are located in the second shell, with 2 in a 2s orbital and 6 in three 2p orbitals. There are 18 electrons in the third shell, with 2 in the 3s orbital and 6 in the three 3p orbitals.

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Nucleophilic addition that targets the C=C double bond's electrophilic carbon is known as conjugate addition in,-unsaturated systems.

Changes in temperature, gas production, precipitant formation, and color are common components of chemical reactions. Cooking, digesting, and combustion are a few straightforward examples of common reactions.

When atoms' chemical bonds are established or ruptured, chemical processes take place. The materials that initiate a chemical change are known as reactants, while the materials created as a result of the reaction as known as products.

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These substances C6H1203 don't already exist in their empirical formula.

The empirical formula is CH for both C2H2 and C2H6, as it represents the simplest whole number ratio of the various atoms in a molecule. The compound's molar mass is 314 g/mol, and the empirical formula mass is (2 X 12) + 1 + 80 = 105g. Hence, C6H3Br3 is the molecular formula.

Glucose has the chemical formula C6H12O6 = 6 x CH2O c.The molecular weight of glucose is 180 g/mol.. The empirical and molecular formulas are identical because it equals 6 x 30 g/mol.

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Answer:  2.536 M

Explanation: To calculate the molarity of NaOH in the solution, we need to first calculate the number of moles of NaOH present in the solution.

The formula for calculating the number of moles is:

moles = mass / molar mass

The molar mass of NaOH is 40 g/mol (23 g/mol for Na + 16 g/mol for O + 1 g/mol for H). Therefore, the number of moles of NaOH present in the solution is:

moles of NaOH = 36.5 g / 40 g/mol = 0.9125 mol

The volume of the solution is 360 mL, which is equivalent to 0.360 L. Therefore, the molarity of the NaOH solution is:

Molarity = moles / volume = 0.9125 mol / 0.360 L = 2.536 M

Therefore, the molarity of the NaOH solution is 2.536 M.

No, 28 moles of solid carbon would not be enough to produce 15 moles of [tex]C_2H_6[/tex] (Ethane).

This is because the reaction requires more than 1 mole of carbon to produce 1 mole of [tex]C_2H_6[/tex]. The mole ratio of [tex]C_2H_6[/tex]:C is 2:1, so 28 moles of carbon would only be enough to produce 14 moles of [tex]C_2H_6[/tex].A chemical compound having the molecular formula  [tex]C_2H_6[/tex], ethane is an organic substance. Ethane is an odourless, colourless gas at ordinary pressure and temperature. Ethane is separated from natural gas on an industrial scale, and it is produced as a by-product of the petrochemical process used to refine crude oil. Its primary usage is as a feedstock for the creation of ethylene.The ethane moiety is known as an ethyl group, and it can be used to create related compounds by swapping out a hydrogen atom for another functional group.

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The energy of a photon emitted when an electron in a hydrogen atom transitions from the third to the first energy state can be calculated using the Rydberg formula. For the given transition, the energy equates to approximately 1.63 x 10^-18 Joules.

In quantum physics, the energy of a photon emitted when an electron moves from one energy level to another in a hydrogen atom can be calculated using the Rydberg formula. The formula is E = R_H *(1/ni^2 - 1/nf^2), where R_H is the Rydberg constant for hydrogen (approximately 2.18 x 10^-18 Joules), ni is the initial energy level (3 in this case), and nf is the final energy level (1 in this case).

Plugging these into the equation, we get E = 2.18 x 10^-18 Joules *(1/3^2 - 1/1^2). Then, we find that the energy of the photon is about 1.63 x 10^-18 Joules. This energy corresponds to the energy difference between the two energy levels.

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The energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from n=3 to n=1 can be calculated using the Rydberg formula for hydrogen and the formula for the energy of a photon.

The energy of a photon emitted during an electron transition in a hydrogen atom can be calculated using the formula for the energy of a photon: E = hf, where 'E' is energy, 'h' is Planck's constant, and 'f' is frequency. Moreover, when an electron in a hydrogen atom undergoes a transition from n=3 to n=1, the energy difference between these two energy levels can be calculated using the Rydberg formula for hydrogen: ΔE = RH (1/n1² - 1/n2²), where 'RH' is the Rydberg constant for hydrogen, 'n1' and 'n2' are the initial and final energy levels respectively. By substituting the values, we get ΔE = RH (1/1² - 1/3²). So, this is the energy of the emitted photon when an electron undergoes a transition from n=3 to n=1.

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Hydrogen bonding, which is unquestionably what we have, will occur from the intermolecular force between the molecules of H2O and CH3OH. Atoms trade or exchange valence electrons to create bonds.

Trust and self-esteem are developed in children and adolescents through strong emotional ties. After that, they can leave the family and establish wholesome friendships and other types of social ties. Healthy relationships consequently lower a child's chances of emotional discomfort or antisocial behaviour.

The government of a country issues government bonds, a sort of fixed-interest bond. These bonds are thought of as low-risk investments. Examples of different kinds of government bonds include T - bills, Municipality Bond, Zero-Coupon Bonds, and others.

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Answer: C - The amount of gas

Explanation:

The IUPAC name for the compound given in the question is 2,3-dibromo-5-methylheptane

The IUPAC name for compound can be obtained by using the following steps:

Thus, the IUPAC name for the compound is: 2,3-dibromo-5-methylheptane

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Metals do not hold energy because they can conduct or store energy in various forms, means the electrical or kinetic energy. Different metals have different conductivity and storage capacity for different forms of energy.

Electric energy is a form of energy that results from the flow of electric charge through a conductor. It is used to power many devices and systems, from home appliances to industrial machinery.

Electric energy is measured in units of joules or kilowatt-hours.This is the example of electric energy.

Kinetic energy is an object possesses due to its motion. It is dependent on the mass and velocity of the object and is expressed as 1/2 mv^2, where m is the mass of the object and v is its velocity. Kinetic energy is a scalar quantity and is measured in joules.This is the fine example of kinetic energy.

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Metals can hold different amounts of energy depending on the specific metal and the form of energy like thermal energy, electrical energy and mechanical energy.

1. Thermal energy: Metals are good conductors of heat, so they can absorb and hold a significant amount of thermal energy. The specific amount of thermal energy that a metal can hold depends on factors such as its specific heat capacity and mass.

2. Electrical energy: Metals are also good conductors of electricity, so they can hold and transport electrical energy. The amount of electrical energy that a metal can hold depends on factors such as its conductivity and the amount of current flowing through it.

3. Mechanical energy: Metals can also store mechanical energy in the form of elastic or plastic deformation. The amount of mechanical that a metal can hold depends on factors such as its elasticity and strength.

In the context of electricity and physics, a conductor is a material or substance that allows the flow of electrical current or heat through it. Conductors are typically materials with low electrical resistance or high thermal conductivity, or both.

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Answer:  0.893 g / 84.31

Explanation: Let's first calculate the number of moles of HCl that reacted with the mixture:

moles of HCl = 0.2 N x 0.2 L = 0.04 moles

The balanced chemical equation for the reaction between HCl and CaCO3 is:

CaCO3 + 2HCl → CaCl2 + CO2 + H2O

The balanced chemical equation for the reaction between HCl and MgCO3 is:

MgCO3 + 2HCl → MgCl2 + CO2 + H2O

We can use the number of moles of HCl and the stoichiometry of these reactions to calculate the total number of moles of CaCO3 and MgCO3 in the mixture:

moles of CaCO3 + moles of MgCO3 = 0.04 moles

Let x be the mass of CaCO3 and y be the mass of MgCO3 in the mixture. Then we can write:

x + y = 1.4 g (total mass of mixture)

x/100.09 + y/84.31 = 0.04 (total moles of mixture)

Solving these equations, we get:

x = 0.507 g (approx.)

y = 0.893 g (approx.)

Therefore, the mixture contains approximately 36.2% CaCO3 and 63.8% MgCO3 by mass.

Now, let's calculate the number of moles of NaOH required to neutralize 10 mL of the diluted solution:

moles of NaOH = (12 mL)(1/30 N)(1/1000 L/mL) = 0.0004 moles

The balanced chemical equation for the neutralization reaction between NaOH and HCl is:

NaOH + HCl → NaCl + H2O

We can use the number of moles of NaOH and the stoichiometry of this reaction to calculate the number of moles of HCl that remained in the diluted solution:

moles of HCl remaining = moles of NaOH = 0.0004 moles

The diluted solution has a volume of 250 mL, so its concentration of HCl is:

[HCl] = moles of HCl remaining / volume of solution = 0.0004 moles / 0.250 L = 0.0016 N

The 10 mL of diluted solution used for titration was taken from the original solution that was prepared by dissolving the mixture in 200 mL of 0.2 N HCl. Therefore, the concentration of HCl in the original solution is:

[HCl] = (0.2 N)(200 mL / 250 mL) = 0.16 N

Since the number of moles of HCl in the original solution is equal to the number of moles of HCl that reacted with the mixture, we can calculate the number of moles of the mixture:

moles of mixture = moles of HCl reacted = 0.04 moles

The mass of the mixture is 1.4 g, so its molar mass is:

molar mass of mixture = 1.4 g / 0.04 moles = 35 g/mol

The mass of CaCO3 in the mixture is 0.507 g, so its number of moles is:

moles of CaCO3 = 0.507 g / 100.09 g/mol = 0.005067 moles

The mass of MgCO3 in the mixture is 0.893 g, so its number of moles is:

moles of MgCO3 = 0.893 g / 84.31

1) Protons: 4

Neurons: 5

Electrons: 4

2) atomic number: 4

3) isotope

4) Mass: 9.012

Under the same conditions, the root mean square speed of F2(g) molecules is approximately 400 m/s.

The root mean square (rms) speed of a gas molecule can be calculated using the following equation:

rms speed = sqrt((3RT)/M)

where R is the gas constant, T is the temperature in Kelvin, and M is the molar mass of the gas molecule.

To use this equation to find the rms speed of F2(g) molecules, we need to know the temperature and molar mass of F2(g).

Let's assume that F2(g) is at the same temperature as He(g), and that the molar mass of F2(g) is 38.0 g/mol (the molar mass of F2).

Using the given average kinetic energy of He(g) and the molar mass of He(g) (4.00 g/mol), we can solve for the temperature:

(3/2)kT = average kinetic energy per mole

where k is the Boltzmann constant

(3/2)(1.38 x 10^-23 J/K)(T) = 7450 J/mol

T = 7450 J/mol / ((3/2)(1.38 x 10^-23 J/K)) = 346 K

Now we can use the rms speed equation to find the rms speed of F2(g):

rms speed = sqrt((3RT)/M) = sqrt((3 x 8.31 J/mol K x 346 K)/(38.0 g/mol))

rms speed = 400 m/s (rounded to three significant figures)

Therefore, under the same conditions, the root mean square speed of F2(g) molecules is approximately 400 m/s.

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Answer: click thanks if you like my answer , have a good day !

According to the Ideal Gas Law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

If the number of moles and the temperature are doubled while the pressure remains constant, we can write:

(P)(2V) = (2n)(2R)(T)

Simplifying this equation, we get:

2PV = 4nRT

Dividing both sides by 2, we get:

PV = 2nRT

This equation shows that the new volume is directly proportional to the number of moles and temperature.

If we assume that the initial number of moles and temperature are 1 and T, respectively, and the initial volume is 3.0 L, then the new volume can be calculated as:

V' = (2n)(2R)(2T)/(P)

V' = 8(1)(0.0821)(2T)/P

V' = 1.65T/P

Therefore, the new volume is directly proportional to the temperature and inversely proportional to the pressure. Since the pressure remains constant, the new volume will be directly proportional to the temperature, which is doubled in this case.

Thus, the new volume will be double the original volume, and the correct answer is D: "The new volume is double the original volume."

Explanation:

hope its help <:

To recreate experimental results, follow the same procedure as the original researcher and use the same materials, equipment, and statistical methods. Replicate experimental conditions and repeat the experiment multiple times to ensure consistency.

What are an experimental conditions?

Experimental conditions refer to the set of factors or variables that are intentionally manipulated or controlled during an experiment to observe their effect on the outcome or dependent variable. These conditions can include environmental factors such as temperature, humidity, and lighting, as well as other experimental parameters such as sample size, treatment duration, and measurement techniques.

What is an equipment?

In scientific experiments, equipment refers to the various tools and instruments used to measure, observe, manipulate, or analyze materials and phenomena under investigation. Examples of scientific equipment include microscopes, spectrometers, centrifuges, balances, pipettes, and thermometers.

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Answer:

To solve this problem, we can use the Boyle's Law equation, which states that the pressure and volume of a gas are inversely proportional at constant temperature.

Boyle's Law: P1V1 = P2V2

where P1 and V1 are the initial pressure and volume, and P2 and V2 are the new pressure and volume.

Using the given values:

P1 = 30.0 atm

V1 = 2 L

P2 = 10.0 atm

Substituting these values into the Boyle's Law equation, we get:

30.0 atm x 2 L = 10.0 atm x V2

Simplifying and solving for V2, we get:

V2 = (30.0 atm x 2 L) / 10.0 atm

V2 = 6 L

Therefore, the new volume of the gas will be 6 L if the pressure is reduced to 10.0 atm, assuming the temperature remains constant.

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Carbon tetrachloride (CCl4) is commonly used as solvent in the preparation of alkynes.

CCl4 is a colorless, heavy, nonflammable liquid that was once widely used as a solvent and fire extinguisher.

It has a tetrahedral molecular geometry and is composed of one carbon atom and four chlorine atoms, which are covalently bonded.

However, due to its toxic and environmentally hazardous properties, carbon tetrachloride is no longer widely used in many applications.

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Answer: 3.79

Explanation: The balanced chemical equation for the reaction between formic acid (HCOOH) and KOH is:

HCOOH + KOH → HCOOK + H2O

We can use the stoichiometry of this reaction to calculate the number of moles of formic acid that reacted with the KOH:

moles of KOH = (20.00 mL)(0.500 mol/L) = 0.01000 moles

moles of HCOOH = moles of KOH

Therefore, the initial number of moles of formic acid is:

moles of HCOOH = (10.00 mL)(x mol/L) = 0.01000 moles

where x is the molarity of formic acid.

Solving for x, we get:

x = 1.00 M

Therefore, the molarity of the formic acid is 1.00 M.

At the equivalence point, all of the formic acid has reacted with the KOH, and the solution contains only the salt formed by the reaction, potassium formate (HCOOK). The pH at the equivalence point can be calculated using the equation for the salt hydrolysis constant:

Kb = Kw/Ka

where Kb is the base dissociation constant of the conjugate base (formate ion), Kw is the ion product constant for water (1.0 × 10^-14 at 25°C), and Ka is the acid dissociation constant of the acid (formic acid). Rearranging this equation, we get:

Kb/Ka = [OH^-][HCOO^-]/[HCOOH]

At the equivalence point, the concentration of the formate ion (HCOO^-) is equal to the concentration of the KOH added (0.01000 moles / 30.00 mL = 0.3333 M). We can assume that the concentration of the hydroxide ion (OH^-) is also equal to 0.3333 M, since KOH is a strong base and will dissociate completely. Substituting these values into the equation above, we get:

Kb/Ka = (0.3333)^2 / [HCOOH]

Solving for [HCOOH], we get:

[HCOOH] = (0.3333)^2 / (1.8 × 10^-4) = 6181.5 M

Taking the negative logarithm of this concentration, we get the pH at the equivalence point:

pH = -log[HCOOH] = -log(6181.5) = 3.79

Therefore, the pH at the equivalence point is 3.79.

Regenerate response

Answer:

If the percent yield is 100%, the actual yield will be equal to the theoretical yield.

The new pressure inside the tank would be approximately 101.8 kPa.

What is the relationship between temperature and pressure of a gas?

Increasing the temperature of the tank to 85° C would result in a new pressure inside the tank of approximately 101.8 kPa.

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Answer:

2300J

Explanation:

The first law of thermodynamics states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system:

ΔU = Q - W

Where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system.

In this case, ΔU is what we want to find, Q is 700 J, and W is -400 J (note that the work done by the system is negative because it is done on the surroundings). Substituting these values into the equation:

ΔU = Q - W

ΔU = 700 J - (-400 J)

ΔU = 700 J + 400 J

ΔU = 1100 J

The final internal energy of the system is therefore 1100 J + the initial energy of 1200 J, which equals 2300 J.

Explanation:

First, we need to write a balanced chemical equation for the neutralization reaction:

2 HNO3(aq) + Ba(OH)2(aq) → 2 H2O(l) + Ba(NO3)2(aq)

From the balanced equation, we can see that the stoichiometric ratio of HNO3 to Ba(OH)2 is 2:1. This means that 2 moles of HNO3 react with 1 mole of Ba(OH)2.

Using the given information, we can calculate the number of moles of Ba(OH)2 that reacted:

moles of Ba(OH)2 = Molarity x Volume (in L)

moles of Ba(OH)2 = 0.250 M x (37.9/1000) L

moles of Ba(OH)2 = 0.009475 mol

Since the stoichiometric ratio of HNO3 to Ba(OH)2 is 2:1, the number of moles of HNO3 that reacted is twice the number of moles of Ba(OH)2:

moles of HNO3 = 2 x moles of Ba(OH)2

moles of HNO3 = 2 x 0.009475 mol

moles of HNO3 = 0.01895 mol

Finally, we can calculate the concentration of the HNO3 solution:

concentration of HNO3 = moles of HNO3 / volume of HNO3 solution (in L)

concentration of HNO3 = 0.01895 mol / 0.120 L

concentration of HNO3 = 0.158 mol/L

Therefore, the concentration of the HNO3 solution is 0.158 mol/L.

Answer:

Continuous Spectrum, a spectrum that contains all wavelengths of light within a specific range, with no gaps or lines. It is produced by a hot, dense object such as a star or a light bulb.

Emission Spectrum, a spectrum that contains bright lines or bands of specific wavelengths, with dark spaces in between. It is produced when light is emitted from a hot gas or plasma, and the specific wavelengths of the lines or bands depend on the elements present in the gas.

Absorption Spectrum, a spectrum that contains dark lines or bands of specific wavelengths, with bright spaces in between. It is produced when a continuous spectrum passes through a cool gas, and the specific wavelengths of the lines or bands depend on the elements present in the gas.

The volume of the nitrogen oxide gas is 35.2 L

Stoichiometry is the quantitative study of reactants and products in a chemical reaction. It is used to determine the amount of reactants needed to produce a certain amount of product, or to determine the amount of product that will be produced from a given amount of reactant.

To apply stoichiometry;

We know that;

Number of moles of Cu = 150/ 63.5g/mol = 2.36 moles

If 3 moles of Cu produced 2 moles of NO

2.36 moles of Cu will produce 2.36 * 2/3

= 1.57 moles

If 1 moles of NO occupies 22.4 L

1.57 moles of NO will occupy 1.57 * 22.4/1

= 35.2 L

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Explanation:

I don't have a personal opinion, but I can say that there is no single research method that is effective in all situations.

Different research methods are appropriate for different types of research questions and situations. For example, if the research question is focused on understanding the relationship between two variables, a correlational research method may be appropriate. However, if the research question is focused on understanding the cause-and-effect relationship between variables, an experimental research method may be necessary.

In addition, some research methods may be more appropriate for certain types of data or populations, such as qualitative research methods for exploring subjective experiences or quantitative research methods for analyzing numerical data.

Therefore, researchers need to carefully consider their research question and choose the research method that is most appropriate for their specific situation.

The most standard and widely used research methods

Survey research

This method involves collecting data from a sample of individuals through questionnaires, interviews, or online surveys.

Experimental research

This method involves manipulating one variable (the independent variable) to observe its effect on another variable (the dependent variable) while controlling for other variables.

Observational research

This method involves observing and recording behavior in natural settings without any intervention or manipulation of variables.

Case study research

This method involves in-depth examination and analysis of a single case or a small group of cases to understand a particular phenomenon or situation.

Content analysis

This method involves analyzing and interpreting the content of documents, media, or other communication sources to identify patterns, themes, and trends.

These methods are commonly used across various fields of research, including social sciences, psychology, education, business, and healthcare. However, the choice of research method depends on the research question, the type of data needed, and the availability of resources.

Yes, shining light on metal can cause it to get warm, regardless of the type of light used. When light strikes surface, some of its energy is absorbed by material, which causes atoms to vibrate, leading to increase in material's temperature and this effect is known as thermal radiation.

The amount of heat generated depends on several factors, including the intensity of light, duration of exposure, and material's properties, such as its reflectivity, emissivity and specific heat capacity.

I case of the metal used to make satellites, it absorbs infrared light, which means that it will be heated up if exposed to this type of light. However, metal transmits X-ray light and reflects visible light, so it will not be heated by these types of light.

Therefore, it is essential to consider type of light used when assessing heat generated by material. Different materials have different spectral responses to light, which means that they will absorb, reflect or transmit different types of light, and as a result, they will behave differently when exposed to light.

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The complete balanced equations with the stoichiometric coefficients are:

10) 16Al + 3S₈ → 8Al₂S₃

11)  6 Cs + N₂  →  2Cs₃N

12) Mg + Cl₂ →  MgCl₂

The quantity of molecules involved in the reaction is known as the stoichiometric coefficient or stoichiometric number. Any balanced response has an equal number of components on both sides of the equation, as can be seen by looking at it. The number that is present in front of atoms, molecules, or ions is known as the stoichiometric coefficient.

13)10Rb + 2RbNO₃ → 6Rb₂O + N₂

14) 2C₆H₆ + 15O₂ → 6H₂O + 12CO₂

15) N₂ + 3H₂ →   2NH₃

16)Al(OH)₃ + H₂SO₄ → Al₂(SO₄)₃ + H₂O

17) 2Na + Cl₂ →   2NaCl

18) 16Rb + S₈ → 8Rb₂S

19) 2H₃PO₄ + 3Ca(OH)₂ → Ca₃(PO₄)₂ + 6H₂O

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