This table shows the time it takes students in Homeroom 203 to get to school each morning: 1 Time Less than 10 min 10-19 min 20-29 min 30-39 min 40-49 min 50 min or more Find the experimental probability of a student in this homeroom taking a certain number of minutes to get to school. Make a probability distribution for this data. Number of Students 3, 5, 10, 7, 2, 3​

The greatest number of tables that can be made is 18 (since 18 is a factor of 72 and we have enough centerpieces to decorate 18 tables).

How to make the  greatest number of tables?

To determine the greatest number of tables that can be made, we need to find the number of chairs needed for each table, as well as the number of centerpieces that can be made with the available supplies.

Since we have 72 chairs and want to distribute them equally among the tables, we can start by finding factors of 72. Factors are numbers that can be multiplied together to get the original number. For example, the factors of 72 are: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, and 72.

We can see that 72 can be divided equally into 2, 3, 4, 6, 8, 9, 12, and 18 tables. However, we also need to make sure that we have enough centerpieces to decorate each table.

To make a centerpiece, we need one balloon, one flower, and one candle. So we need to make sure that we have enough of each item to make the necessary number of centerpieces.

If we use all 48 balloons, 24 flowers, and 32 candles, we can make a maximum of 24 centerpieces (since we have only 24 flowers). This means that we can only have a maximum of 24 tables.

Therefore, the greatest number of tables that can be made is 18 (since 18 is a factor of 72 and we have enough centerpieces to decorate 18 tables).

To summarize, we can make a maximum of 18 tables, with each table having 4 chairs and one centerpiece made of one balloon, one flower, and one candle. This ensures that everything is distributed equally and there are no shortages.

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The derivative of the function f(x) = 2 \sqrt(x) / (8x² + 3x - 9) evaluated at x = 4.

To find f'(x), we need to differentiate the given function f(x) using the power rule and the chain rule of differentiation.

First, we can rewrite the function f(x) as:

f(x) = 2x^{1/2} / (8x² + 3x - 9)

Next, we can differentiate f(x) with respect to x:

f'(x) = d/dx [2x^{1/2} / (8x² + 3x - 9)]

Using the quotient rule of differentiation, we have:

f'(x) = [ (8x² + 3x - 9) d/dx [2x^{1/2}] - 2x^{1/2} d/dx [8x² + 3x - 9] ] / (8x² + 3x - 9)²

Applying the power rule of differentiation, we have:

f'(x) = [ (8x² + 3x - 9)(1/2) - 2x{1/2}(16x + 3) ] / (8x² + 3x - 9)²

Now we can evaluate f'(x) at x = 4 by substituting x = 4 into the expression for f'(x):

f'(4) = [ (8(4)² + 3(4) - 9)(1/2) - 2(4)^(1/2)(16(4) + 3) ] / (8(4)² + 3(4) - 9)²

f'(4) = [ (128 + 12 - 9)(1/2) - 2(4)^(1/2)(67) ] / (128 + 12 - 9)^2

f'(4) = [ 131^(1/2) - 2(4)^(1/2)(67) ] / 12167

Therefore, f'(4) = [ 131^(1/2) - 134(2)^(1/2) ] / 12167.

This is the value of the derivative of f(x) at x = 4.

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Statement #3 is incorrect. To correct the statement:

The box plot does not provide information on the number of days of data collected.

The box plot, also known as a box-and-whisker plot, is a graphical representation of the distribution of a dataset. It displays information about the median, quartiles, and possible outliers.

However, the box plot itself does not directly provide information on the number of days of data collected.

The main components of a box plot include:

Median: This is the line inside the box that represents the middle value of the dataset. It divides the dataset into two equal halves, with 50% of the data falling below the median and 50% above it.

Quartiles: The box in the plot represents the interquartile range (IQR) of the data. The lower edge of the box corresponds to the first quartile (Q1), which is the 25th percentile. The upper edge of the box corresponds to the third quartile (Q3), which is the 75th percentile. The IQR represents the range of the middle 50% of the data.

Whiskers: These are the lines extending from the box. Typically, the whiskers extend to the smallest and largest observations within a certain range, often 1.5 times the IQR. Values outside this range are considered potential outliers and are represented as individual points beyond the whiskers.

The box plot can provide valuable information about the spread, skewness, and potential outliers in a dataset. However, it does not directly convey information about the number of days of data collected. To determine the number of days, one would need to refer to the raw data or other accompanying information.

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Answer:

17.5 feet

Step-by-step explanation:

The picnic are shortest side is 5 units long on the scale drawing

Since each unit on the scale drawing is 1 inch, the shortest side length on the drawing is 5 inches

Each inch on the drawing corresponds to an actual size of 3.5 feet

Therefore 5 inches corresponds to 5 x 3.5ft = 17.5 feet

Therefore the actual length of the shortest side of the picnic area is 17.5 feet

The time taken for $400 to amount to $650 at 6% compound interest annually is 8.33 years.

Compound interest is expressed as below:

[tex]A = P(1+\frac{r}{n})^{nt[/tex]

where A is the amount

P is principal

r is the rate of interest

n is the frequency with which interest is compounded per year

t is the time

A = $650

P = $400

r = 0.06

n = 1 because the interest is compounded annually. Thus the frequency of interest compounded per year is 1

650 = 400 [tex](1+0.06)^t[/tex]

1.625 = [tex]1.06^t[/tex]

t = 8.33 years

Thus, it takes 8.33 years for $400 to convert to $650 at 6% compound interest annually.

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Given d = ba, we can write:

d11 = b1a1 + b2a3

d12 = b1a2 + b2a4

d21 = b3a1 + b4a3

d22 = b3a2 + b4a4

To find the product of d, we need to find the values of b and a such that d11 = d12 = d21 = d22.

Let's assume that d11 = d12 = d21 = d22 = x. Then, we have:

b1a1 + b2a3 = x

b1a2 + b2a4 = x

b3a1 + b4a3 = x

b3a2 + b4a4 = x

We can solve for b1, b2, b3, and b4 in terms of a1, a2, a3, and a4:

b1 = (x - b2a3)/a1

b2 = (x - b1a1)/a3

b3 = (x - b4a3)/a1

b4 = (x - b3a1)/a3

Substituting these values of b1, b2, b3, and b4 into the equation d = ba, we get:

d11 = x = a1(x - b1a3)/a1 + a3(x - b2a1)/a3

= x - b1a3 + x - b2a1

= 2x - (b1a3 + b2a1)

d12 = x = a2(x - b1a3)/a1 + a4(x - b2a1)/a3

= (a2/a1)x - (b1a2 + b2a4) + (a4/a3)x - (b1a4 + b2a4)

= x - (b1a2 + b2a4)

d21 = x = a1(x - b3a3)/a1 + a3(x - b4a1)/a3

= (a1/a1)x - (b3a3 + b4a3) + (a3/a3)x - (b3a1 + b4a3)

= x - (b3a1 + b4a3)

d22 = x = a2(x - b3a3)/a1 + a4(x - b4a1)/a3

= (a2/a1)x - (b3a2 + b4a4) + (a4/a3)x - (b3a4 + b4a4)

= x - (b3a2 + b4a4)

We can rewrite these equations in matrix form as:

| 2 -a3-a1 0 0 || x | | b1a3 + b2a1 |

| 0 a2 0 -a4 || | = | b1a2 + b2a4 |

| -a3-a1 0 2 -a1 || | | b3a1 + b4a3 |

| 0 -a4 -a1 2 || | | b3a2 + b4a4 |

To solve for x, we need to invert the matrix on the left and multiply it by the vector on the right:

| x | | 2 -a3-a1 0

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The integral of ſ(cosa + 3x^4) dx simplifies to ∫cos(x) dx, which can be evaluated as sin(x) + C, where C is the constant of integration.To evaluate the integral of ſ(cosa + 3x^4) dx using even and odd functions, we can decompose the integrand into even and odd parts.

Let's first identify the even and odd parts of the integrand. The function cos(x) is an even function because it is symmetric with respect to the y-axis, i.e., cos(-x) = cos(x). On the other hand, the function 3x^4 is an odd function because it is symmetric with respect to the origin, i.e., (-x)^4 = x^4.

We can rewrite the integrand as a sum of even and odd functions:

cos(x) + 3x^4 = (1/2) * (cos(x) + cos(-x)) + (1/2) * (3x^4 - 3(-x)^4)

Now, we can use the properties of even and odd functions to simplify the integral. The integral of an even function over a symmetric interval is equal to twice the integral of the function over half of the interval. Similarly, the integral of an odd function over a symmetric interval is equal to zero.

So, the integral of (1/2) * (cos(x) + cos(-x)) dx is equal to (1/2) * 2 * ∫cos(x) dx, since cos(x) is an even function.

And the integral of (1/2) * (3x^4 - 3(-x)^4) dx is equal to (1/2) * 0, since 3x^4 - 3(-x)^4 is an odd function and the interval of integration is symmetric.

Therefore, the integral of ſ(cosa + 3x^4) dx simplifies to ∫cos(x) dx, which can be evaluated as sin(x) + C, where C is the constant of integration.

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A graph of the solution to this inequality 3x - 4 > 11 is shown in the image attached below.

In Geometry, a number line simply refers to a type of graph that is composed of a graduated straight line, which typically comprises both negative and positive numerical values (numbers) that are located at equal intervals along its length.

In this scenario and exercise, we would determine the solution to the given inequality by solving for x as follows;

3x - 4 > 11

By adding the numerical value 4 to both sides of the inequality, we have the following:

3x - 4 + 4 > 11 + 4

3x > 15

x > 15/3

x > 5.

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The 95% confidence interval is: b) -1.38 to d) 3.44.

The value of the sample mean difference is 1.74, which falls:

b) within.

Here, we have to determine the 95% confidence interval for the difference of sample means and complete the statements, we need to use the sample mean difference provided and the confidence interval limits given as options.

We'll compare the sample mean difference to the interval to see if it falls within or outside the interval.

Given that the sample mean difference is 1.74, let's analyze the options:

Options for the confidence interval limits:

Lower limit options:

a) -1.26

b) -1.38

c) -3.48

d) -3.44

Upper limit options:

a) 1.26

b) 3.48

c) 1.38

d) 3.44

Since the sample mean difference is 1.74, we need to check if it falls within the interval formed by the lower and upper limits.

Looking at the options for the lower limit, the closest value to 1.74 is -1.38, and the closest value to the upper limit is 3.44.

So, the 95% confidence interval would be:

-1.38 to 3.44

Now, completing the statements:

The 95% confidence interval is: b) -1.38 to d) 3.44

The value of the sample mean difference is 1.74, which falls:

b) within

So, the completed statements are:

The 95% confidence interval is -1.38 to 3.44.

The value of the sample mean difference is 1.74, which falls within the 95% confidence interval.

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The limit of (69²-24) as x approaches infinity is equal to infinity.

As x approaches infinity, the value of (69²-24) becomes very large, and it goes to infinity. Therefore, the limit of (69²-24) as x approaches infinity is infinity.

B) The limit of (4a+2)/(2-a) as a approaches 2 from the left is equal to -6 and as a approaches 2 from the right is equal to 6.

As a approaches 2 from the left, the denominator (2-a) approaches zero from the negative side, and the numerator (4a+2) approaches -6. Therefore, the limit of (4a+2)/(2-a) as a approaches 2 from the left is -6.

As a approaches 2 from the right, the denominator (2-a) approaches zero from the positive side, and the numerator (4a+2) approaches 6. Therefore, the limit of (4a+2)/(2-a) as a approaches 2 from the right is 6.

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Answer:

It took 13 weeks for Jill to get 1275.00 in her savings account

Step-by-step explanation:First off you subtract 1275-300=975.After that you will divide 975 from 75 975÷75=13.So 13 is your final answer.

Marissa needs to score 94% on test five to have a mean of 90% for all five tests.

What is average?

Let's look at the average formula in more detail in this part and use some examples to illustrate how it may be used. The following is an example of the average formula for a specific set of data or observations: Average = (Sum of Observations) ÷ (Total Numbers of Observations).

Let's use the formula for finding the mean:

mean = (sum of all scores) / (number of scores)

We know that Marissa has taken four tests and has a mean score of 89%, so:

(4 x 89) + x = 5 x 90

Simplifying:

356 + x = 450

x = 94

Therefore, Marissa needs to score 94% on test five to have a mean of 90% for all five tests.

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Answer:

25

Step-by-step explanation:

all three angles of a triangle equal to 180º. 135+20=155

180-155=25

this is how u get ur answer

135° + 20° = 155°

Since the angles must have a sum of 180°, we subtract 155° from 180°, which would equal 25°.

To confirm: 135° + 20° + 25° = 180°

Yes, if you were to randomly survey 20 people at 50 random high schools, it would be considered a random sample because the process involves randomly selecting people from randomly selected high schools, which prevents selection bias..

A random sample is a subset of a population in which every individual has an equal chance of being selected. In this case, the population is the students at the high schools.

By randomly selecting the 50 high schools, you ensure that each school has an equal opportunity to be part of the sample. This helps to prevent selection bias, as no specific schools are deliberately chosen. Moreover, by surveying 20 random people within each selected school, you further eliminate bias, as each student at the school has an equal chance of being selected for the survey.

This random sampling method is beneficial because it helps to obtain a more representative sample of the larger population of high school students. By including diverse schools and students, the survey results can provide more accurate and generalizable insights.

However, it is important to note that even with random sampling, there may still be some limitations, such as sampling error or non-response bias. To minimize these, it is essential to ensure that the sample size is large enough and that survey procedures are properly executed.

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a. The data provided enough evidence at a = 0.05 level that the true mean pH of water from this source differs from 7

b. A 95% confidence interval for the true mean pH level of the water is (6.21, 6.59) means  about 95% of those intervals would contain the true mean pH level.

c. The estimated mean pH level of seven is not included in the interval in section (b). This is consistent with the result of the test in part (a), which also rejects the null hypothesis that the true mean pH level is 7.

(a) To test whether the true mean pH of water from this source differs from 7, we can perform a one-sample t-test. The null hypothesis is that the true mean pH is equal to 7, and the alternative hypothesis is that the true mean pH is not equal to 7.

The test statistic can be calculated as follows:

t = (sample mean - hypothesized mean) / (sample standard deviation / sqrt(sample size))

t = (6.4 - 7) / (0.5 / sqrt(30))

t = -3.07

Using a t-table with 29 degrees of freedom at a significance level of 0.05 (two-tailed test), the critical t-value is ±2.045. Since the calculated t-value (-3.07) is outside of the critical t-value range, we can reject the null hypothesis and conclude that there is enough evidence at a = 0.05 level to suggest that the true mean pH of water from this source differs from 7.

(b) A 95% confidence interval for the true mean pH level of the water is (6.21, 6.59). This means that if we were to take many random samples of size 30 from this water source, and construct a 95% confidence interval for each sample mean pH level, then about 95% of those intervals would contain the true mean pH level.

(c) The interval in part (b) does not include the hypothesized mean pH level of 7. This is consistent with the result of the test in part (a), which also rejects the null hypothesis that the true mean pH level is 7.

The confidence interval provides additional information by giving a range of plausible values for the true mean pH level, and we can see that all of the values in this range are below 7, indicating that the water is indeed slightly acidic.

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The quadratic parent function is f(x) = x^2, which is a U-shaped curve that passes through the origin. When we apply transformations to the quadratic parent function, its shape and position change accordingly.

One of the most common transformations applied to the quadratic parent function is vertical translation, which shifts the entire graph up or down. If we add a constant k to the function, the graph is shifted k units up. Similarly, if we subtract a constant k from the function, the graph is shifted k units down.Another common transformation is horizontal translation, which shifts the entire graph left or right.

If we replace x with x + h in the function, the graph is shifted h units to the left. If we replace x with x - h, the graph is shifted h units to the right.These transformations can be combined to create a variety of different quadratic functions. Each transformation changes the position or shape of the graph in a specific way, allowing us to create complex and interesting functions from the simple quadratic parent function.

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Lee spent a total of 33 hours working on all the lawns, as calculated by multiplying the number of lawns for each size category by the respective time required for mowing, trimming, and sweeping.

In order to determine the total number of hours Lee spent working on all the lawns, we need to calculate the time for each task separately. For the average size lawn, Lee takes 1 hour to mow and 2 hours to trim and sweep, totaling 3 hours per lawn. For the large size lawn, Lee takes 3 hours to mow and 3 hours to trim and sweep, totaling 6 hours per lawn.

Given that Lee mowed, trimmed, and swept 5 average size lawns and 3 large size lawns in one week, we can calculate the total hours as follows:

Total hours for average size lawns = 5 lawns * 3 hours/lawn = 15 hours

Total hours for large size lawns = 3 lawns * 6 hours/lawn = 18 hours

Therefore, the total hours Lee spent working on all the lawns is 15 hours + 18 hours = 33 hours.

In conclusion, Lee spent a total of 33 hours working on all the lawns, as calculated by multiplying the number of lawns for each size category by the respective time required for mowing, trimming, and sweeping.

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Answer:

The largest volume that such a box can have is (3/4)²(3/2)²/4 = 1.6875 m³

Step-by-step explanation:

4. Let the sides of the rectangle be 'l' and 'w', where lw = A, the fixed area. The perimeter P is given by P = 2l + 2w. To minimize P, we need to find the values of 'l' and 'w' that make P as small as possible. Solving the equation for 'w' in terms of 'l' from lw = A, we get w = A/l. Substituting this into the equation for P, we get P = 2l + 2(A/l). Taking the derivative of P with respect to 'l' and setting it to zero, we get 2 - 2A/l² = 0, which implies l = √A. Substituting this value into lw = A, we get w = √A. Therefore, a square with sides of length √A has the minimum perimeter among all rectangles with a fixed area of A.

Let the side length of the square base be 'x' and the height of the box be 'h'. Then the volume of the box is V = x²h = 400. We need to minimize the surface area S of the box, which is given by S = x² + 4xh. Solving the equation for 'h' in terms of 'x' from V = x²h, we get h = 400/x². Substituting this into the equation for S, we get S = x²+ 4x(400/x²) = x² + 1600/x. Taking the derivative of S with respect to 'x' and setting it to zero, we get 2x - 1600/x² = 0, which implies x = 10 cm. Therefore, the dimensions of the box that minimizes the amount of material used are 10 cm x 10 cm x 4 cm.

Let the side length of the square cut out from each corner be 'x', and the height of the box be 'h'. Then the volume of the box is V = x²h. The length and width of the base of the box are (3-2x) and (3-2x) respectively. We need to maximize the volume V of the box subject to the constraint that the length and width of the base are positive. Taking the derivative of V with respect to 'x' and setting it to zero, we get h = (3-2x)²/4. Substituting this into the equation for V, we get V = x²(3-2x)²/4. Taking the derivative of V with respect to 'x' and setting it to zero, we get x = 3/4 m. Therefore, the largest volume that such a box can have is (3/4)²(3/2)²/4 = 1.6875 m³

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Ms. Summers gives each child 1/16 gallon of milk.

The amount of milk that Ms. Summers gives to each child can be represented by the following expression:

(1/4 gallon of milk - 1/8 gallon of milk) / 2

This expression represents the amount of milk that remains after Ms. Summers drinks 1/8 gallon of milk, divided equally between her two children.

Simplifying the expression, we get:

(2/8 - 1/8) / 2 = 1/8 / 2 = 1/16

Therefore, Ms. Summers gives each child 1/16 gallon of milk.

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The distance that Anthony will ride down Pine Avenue would be D.) 24 miles .

Anthony's route distance along Pine Avenue can be calculated using the Pythagorean Theorem. This theorem confirms that in a right triangle, when one angle is 90 degrees, the sum of squares of the lengths of the two non-hypotenuse sides equals the square of length of the hypotenuse or the longest side.

Hypothenuse ² = Forrest Lane ² + Pine Avenue ²

26 ² = 10 ² + x ²

676 = 100 + x ²

x ² = 576

x = 24

In conclusion, Anthony will ride down Pine Avenue for 24 miles.

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Full question is:

Anthony was mapping out a route to ride his bike. The route he picked forms a right triangle, as shown in the picture below. If the route takes him 10 miles on Forrest Lane and 26 miles up Cedar Drive, how far will Anthony ride down Pine Avenue?

A.) 16 miles

B.) 36 miles

C.) 30 miles

D.) 24 miles

Guadalupe drove at an average speed of 33.75 miles per hour.

To find the average speed, we need to divide the total distance by the total time:

Average speed = t d/t t

Guadalupe drove 45 miles in 1 1/3 hours, which is the same as 4/3 hours.

So, average speed = 45 miles / (4/3) hours

= 45 x 3/4

= 33.75 miles per hour (rounded to two decimal places)

Therefore, Guadalupe drove at an average speed of 33.75 miles per hour.

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The equation for an exponential that models this data set is: p = 10(2)^t

To determine an equation for an exponential that models the given data set in the form p = a(b)^t, we first need to identify the values of a and b. To do this, we can use two points from the data set and solve for a and b. Let's choose the points (0, 10) and (2, 40):

When t = 0, p = 10: 10 = a(b)^0 = a
When t = 2, p = 40: 40 = a(b)²

Dividing the second equation by the first, we get:

4 = (b)²

Taking the square root of both sides, we get:

b = 2

Now that we have the value of b, we can use one of the original equations to solve for a:

10 = a(2)^0 = a

So, a = 10.

Therefore, the equation for an exponential that models this data set is:

p = 10(2)^t

We can check this equation by plugging in the other data points and verifying that they satisfy the equation. And rounding b to the nearest hundredth gives us b = 2.00.

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The terminal point (x, y, z) of vector v with the given initial point is (3, 0, 7).

To find the terminal point of vector v with initial point given, you can follow these steps:

Add the vector components to the coordinates of the initial point.

The vector v is given as (3, -6, 6) and the initial point is (0, 6, 1).

Add the x-components: 0 + 3 = 3

Add the y-components: 6 + (-6) = 0

Add the z-components: 1 + 6 = 7

The terminal point (x, y, z) of vector v with the given initial point is (3, 0, 7).

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This limit exists and is less than 1 when |x| < 1/3. Therefore, the interval of convergence for the power series is (-1/3, 1/3).

To build a power series for f(x), we can use the geometric series formula:

1 / (1 - r) = ∑(n=0 to infinity) r^n

where r is a constant with |r| < 1. In this case, we have:

f(x) = x^4 / (1 - 3x) = x^4 * 1 / (1 - 3x)

So, we can let r = 3x and use the formula:

1 / (1 - 3x) = ∑(n=0 to infinity) (3x)^n

Multiplying both sides by x^4, we get:

f(x) = x^4 * ∑(n=0 to infinity) (3x)^n

Now we can write the summation notation for the power series as:

f(x) = ∑(n=0 to infinity) (3^n * x^(n+4))

To find the interval of convergence, we can use the ratio test:

lim(n->∞) |(3^(n+1) * x^(n+5)) / (3^n * x^(n+4))| = lim(n->∞) |3x|

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Answer: That made no sense

Step-by-step explanation:

Answer: the median is 26, the first quartile is 19, and the third is 38

Step-by-step explanation:

if you count the numbers and x one by each side you will find the median which in this equation is 26, to find any first quartile you need to find the value under which 25% of data points are found when they are arranged in increasing order, to find the upper quartile you need to find the mean of the values of data point of rank.

The slope at the given points are -1/36 and -1/16 respectively.

Given is a function f(x) = 1/x+6 we need to find the slope of the function,

The slope of a function is given by dy/dx, therefore,
dy/dx = -1/(x+6)²

Therefore, at point (0, 1/6),

The slope = -1/(0+6)² = -1/36

At point (-2, 1/4),

The slope = -1/(-2+6)² = -1/16

Hence the slope at the given points are -1/36 and -1/16 respectively.

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Jones would save $20 over 2 months by choosing Texas Bank over Lone Star Bank for his online banking needs.

To answer this question, we need to know the fees and charges associated with online banking at Texas Bank and Lone Star Bank. Without this information, it's impossible to accurately calculate how much Jones would save by choosing one bank over the other.

Assuming we have this information, we can use the following steps to calculate Jones' potential savings:

Calculate the fees and charges associated with 40 transactions per month at each bank.

Subtract the total fees and charges at Texas Bank from the total fees and charges at Lone Star Bank to determine the difference.

Multiply the difference by 2 to determine how much Jones would save in 2 months by choosing Texas Bank over Lone Star Bank.

For example, let's say that the fees and charges at Lone Star Bank for 40 transactions per month total $20, while the fees and charges at Texas Bank for the same number of transactions total $10. In this case, the difference would be $10 per month.

To calculate Jones' potential savings over 2 months, we would multiply $10 by 2, giving us a total potential savings of $20.

So, in this hypothetical scenario, Jones would save $20 over 2 months by choosing Texas Bank over Lone Star Bank for his online banking needs.

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The correlation coefficient (r) for the given data points is approximately 0.9859, indicating a strong positive relationship between the x and y values.

1. First, let's find the mean of the x-values and the y-values. To do this, add all the x-values together and divide by the total number of points (9). Repeat this for the y-values.
Mean of x = (65 + 71 + 79 + 80 + 86 + 86 + 91 + 95 + 100) / 9 ≈ 83.67
Mean of y = (102 + 133 + 144 + 161 + 191 + 207 + 235 + 237 + 243) / 9 ≈ 183.89

2. Next, calculate the deviations of each point from the mean for both x and y.
For example, for the first point (65,102), the deviations are:
x-deviation = 65 - 83.67 ≈ -18.67
y-deviation = 102 - 183.89 ≈ -81.89

3. Then, multiply the x and y deviations for each point and sum the results. Also, square the deviations for both x and y and sum them separately.
Sum of x*y deviations ≈ 47598.73
Sum of squared x deviations ≈ 2678.89
Sum of squared y deviations ≈ 105426.56

4. Finally, calculate the correlation coefficient (r) by dividing the sum of x*y deviations by the square root of the product of the sum of squared x and y deviations.
r = (47598.73) / √(2678.89 * 105426.56) ≈ 0.9859

The correlation coefficient (r) for the given data points is approximately 0.9859, indicating a strong positive relationship between the x and y values.

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