To begin the experiment, 1. 65g of methane CH4 is burned in a bomb calorimeter containing 1000 grams of water. The initial temperature of water is 18. 98oC. The specific heat of water is 4. 184 J/g oC. The heat capacity of the calorimeter is 615 J/ oC. After the reaction the final temperature of the water is 36. 38oC.

5. The total heat absorbed by the water and the calorimeter can be by adding the heat calculated in steps 3 and 4. The amount of heat released by the reaction is equal to the amount of heat absorbed with the negative sign as this is an exothermic reaction. (2pts)
a. Using the formula ΔH = - (qcal + qwater ) , calculate the total heat of combustion. Show your work.
b. Convert heat of combustion (answer from part a) from joules to kilojoules. Show your work. 6. Evaluate the information contained in this calculation and complete the following sentence: (2pts) This calculation shows that burning _______ grams of methane [TAKES IN] / [GIVES OFF] energy (Choose one).

7. The molar mass of methane is 16. 04 g/mol. Calculate the number of moles of methane burned in the experiment. Show your work. (2pts)

8. What is the experimental molar heat of combustion in KJ/mol? Show your work. (2pts)

9. The accepted value for the heat of combustion of methane is -890 KJ/mol. Explain why the experimental data might differ from the theoretical value in 2-3 complete sentences. (2pts)

10. Given the formula: % error= |(theoretical value - experimental value)/theoretical value)| x 100 Calculate the percent error. Show your work. (2pts)​

Answers

Answer 1

The heat of combustion of methane is -802.41 kJ/mol, indicating that the combustion of methane is an exothermic reaction that releases heat energy.

To calculate the heat of combustion of methane, we can use formula:

q = (m_water x C_water x ΔT) + (C_cal x ΔT)

Plugging in the values, we get:

q = (1000 g x 4.184 J/g°C x 17.4°C) + (615 J/°C x 17.4°C)

q = 21997.45 J

Next, we need to calculate the number of moles of methane burned:

moles [tex]CH_4[/tex] = mass [tex]CH_4[/tex] / molar mass [tex]CH_4[/tex]

moles [tex]CH_4[/tex] = 65 g / 16.04 g/mol

moles [tex]CH_4[/tex] = 4.05 mol

Finally, we can calculate the heat of combustion per mole of methane:

ΔH = q / moles [tex]CH_4[/tex]

ΔH = -802.41 kJ/mol

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--The complete Question is, 1. 65g of methane CH4 is burned in a bomb calorimeter containing 1000 grams of water. The initial temperature of water is 18. 98oC. The specific heat of water is 4. 184 J/g oC. The heat capacity of the calorimeter is 615 J/ oC. After the reaction the final temperature of the water is 36. 38oC.--


Related Questions

6-hydroxy-3,4-dimethyl-2-heptanone forms a cyclic hemiacetal, which predominates at equilibrium in aqueous solution. how many stereoisomers are possible for 6-hydroxy-3,4-dimethyl-2-heptanone? how many stereoisomers are possible for the hemiacetal?

Answers

6-hydroxy-3,4-dimethyl-2-heptanone has four stereoisomers and the cyclic hemiacetal derived from it can exist as two stereoisomers.

6-hydroxy-3,4-dimethyl-2-heptanone has two chiral centers (carbon atoms with four different substituents attached), which gives rise to four possible stereoisomers: two pairs of enantiomers, each pair of which are diastereomers of the other pair.

When 6-hydroxy-3,4-dimethyl-2-heptanone forms a cyclic hemiacetal, it creates another chiral center at the carbon atom that is involved in the formation of the hemiacetal. The hemiacetal can exist as two possible diastereomers, depending on the configuration of the hydroxyl group and the methyl group on the newly formed chiral center. Therefore, there are two possible stereoisomers for the cyclic hemiacetal.

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EXPLAIN Describe the patterns you see among the chemical formulas. How


does the placement of the elements on the periodic table appear to relate to the


numbers in the chemical formula?


PLEASE HELP ME

Answers

The patterns among chemical formulas relate to the placement of elements on the periodic table through their valence electrons and bonding capacity.

Chemical formulas exhibit patterns based on the periodic table's organization. Elements in the same group share similar properties and bonding capacities due to their valence electrons.

For example, elements in Group 1 have one valence electron and typically form +1 ions, while Group 17 elements have seven valence electrons and usually form -1 ions. When combining elements, the numbers in the chemical formula reflect the ratio of atoms required to achieve a stable electron configuration.

For instance, sodium (Na, Group 1) and chlorine (Cl, Group 17) form NaCl, where one sodium atom donates an electron to one chlorine atom, resulting in a stable compound. By understanding the periodic table's arrangement, we can predict chemical formulas and the properties of compounds.

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A) Determine the [OH−] of a solution that is 0. 145 M in CO32− ( Kb=1. 8×10−4 ).


Express your answer using two significant figures.



B) Determine the pH of a solution that is 0. 145 M in CO32−.


Express your answer to two decimal places.



C) Determine the pOH of a solution that is 0. 145 M in CO32−.


Express your answer to two decimal places

Answers

A)  The value of concentration [OH⁻] = √(Kb*[CO₃²⁻]) = √(1.8×10⁻⁴*0.145) = 0.0034 M.

B)  The pH of the solution is pH = -log[H⁺] = -log(2.24×10⁻¹²) = 11.65.

C)  The pOH of the solution is pOH = -log(0.0034) = 2.47.

A) To determine the [OH⁻] of a solution that is 0.145 M in CO₃²⁻ (Kb=1.8×10⁻⁴), we can use the Kb expression of CO₃²⁻ and the fact that Kw (the ion product constant) is equal to [H⁺][OH⁻] to solve for [OH⁻].

The Kb expression for CO₃²⁻ is: Kb = [HCO₃⁻][OH⁻]/[CO₃²⁻]. Since the concentration of HCO₃⁻ is negligible compared to the concentration of CO₃²⁻, we can assume that [HCO₃⁻] is equal to 0.

B) To determine the pH of a solution that is 0.145 M in CO₃²⁻, we need to find the concentration of H⁺ in the solution. Since CO₃²⁻ can act as a base, it can react with water to form HCO₃⁻ and OH⁻.

The Kb expression for CO₃²⁻ can be rewritten as: Kw/Kb = [H⁺][OH⁻]/[CO₃²⁻] = [H⁺][OH⁻]/0.145. Solving for [H⁺], we get [H⁺] = Kw/[OH⁻][CO₃²⁻] = 1.0×10⁻¹⁴/(0.0034*0.145) = 2.24×10⁻¹² M.

C) To determine the pOH of a solution that is 0.145 M in CO₃²⁻, we can use the fact that pOH = -log[OH⁻]. From part A, we know that the [OH⁻] of the solution is 0.0034 M.

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if potassium carbonate is used to selectively precipitate one of the cations while leaving the other cation in solution, which cation will precipitate first? what minimum concentration of will trigger the precipitation of the cation that precipitates first?

Answers

When potassium carbonate is added to a solution containing two cations, the cation that forms a less soluble compound with carbonate will precipitate first.

This is because the less soluble compound will exceed its solubility product and form a solid precipitate. The solubility product is a constant that indicates the maximum amount of solute that can dissolve in a solution at a given temperature and pressure. In the case of the two cations, calcium ion (Ca2+) forms a more insoluble compound with carbonate ion (CO32-) than strontium ion (Sr2+). Therefore, calcium carbonate (CaCO3) will precipitate first, leaving strontium ion in solution.

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An unknown gas with a mass of 205 g occupies a volume of 20. 0 L at 273 K and 1. 00 atm. What is the molar mass of this compound?

Answers

The molar mass of the unknown gas is approximately 221.6 g/mol.

To find the molar mass of the unknown gas, we can use the ideal gas law equation:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

First, we need to convert the given values to their appropriate units:

mass (m) = 205 g

volume (V) = 20.0 L

pressure (P) = 1.00 atm

temperature (T) = 273 K

Next, we can rearrange the ideal gas law equation to solve for the number of moles:

n = PV / RT

Substituting the given values, we get:

n = (1.00 atm) x (20.0 L) / [(0.08206 L atm/mol K) x (273 K)]

n = 0.926 mol

Now we can calculate the molar mass of the unknown gas by dividing its mass by the number of moles:

molar mass = mass / n

molar mass = 205 g / 0.926 mol

molar mass = 221.6 g/mol

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A 500.0-ml canister holds 0.4650 g of co2 gas at 20.00°c. what is the pressure?​

Answers

The pressure of [tex]CO_2[/tex] gas in the canister at 20.00°C is 0.611 atm.

To determine the pressure of [tex]CO_2[/tex] gas in the canister, we can use the ideal gas law:

PV = nRT

First, we need to convert the volume of the canister from milliliters (mL) to liters (L):

500.0 mL = 0.5000 L

Next, we need to calculate the number of moles of [tex]CO_2[/tex] gas:

n = m/MW

where m is the mass of [tex]CO_2[/tex] gas and MW is the molar mass of [tex]CO_2[/tex] (44.01 g/mol).

n = 0.4650 g / 44.01 g/mol = 0.01057 mol

Now we can plug in the values and solve for the pressure:

P = nRT/V = (0.01057 mol)(0.0821 L·atm/mol·K)(293.15 K) / 0.5000 L = 0.611 atm

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How does latitude affect climate?
A
The closer to the poles, the warmer it gets.

B
The closer to the equator, the warmer it gets.

C
The higher you go up a mountain, the colder it gets.

D
The higher you go up a mountain, the warmer it gets.

Answers

Latitude affect climate because the closer to the equator, the warmer it gets. The correct answer is B.

How distance from equator affects climate

The temperature rises as one goes nearer to the equator. One of the key elements that influences climate is latitude. The amount of solar radiation received per unit area rises as you get towards the equator. This raises the temperature and increases evaporation, which causes an increase in precipitation. As a result, the equator's vicinity is typically characterized by a tropical or subtropical climate, marked by warm temperatures and high humidity.

The amount of solar energy received per unit area drops as you move further from the equator, resulting in colder temperatures and less evaporation, which in turn causes less precipitation. As a result, the climate is often colder, with lower temperatures and less humidity, in regions close to the poles.

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A chemist determined by measurements that 0.0750 moles of magnesium participated in a chemical reaction. calculate the mass of magnesium that participated in the chemical reaction.

Answers

To determine the mass of magnesium that participated in the chemical reaction, we need to use the concept of mole-mass relationship. The molar mass of magnesium is 24.31 g/mol. Therefore, we can use the following equation:

Mass of magnesium = number of moles of magnesium x molar mass of magnesium
We know that the number of moles of magnesium that participated in the chemical reaction is 0.0750 moles. Therefore, we can substitute these values in the equation to get:

Mass of magnesium = 0.0750 moles x 24.31 g/mol
Mass of magnesium = 1.823 g
Hence, the mass of magnesium that participated in the chemical reaction is 1.823 g.

In a chemical reaction, the reactants react with each other to form new products. During this process, the reactants undergo a chemical change, which involves the breaking and forming of chemical bonds. In this case, magnesium participated in a chemical reaction, which means it reacted with another substance to form a new product.

The chemist was able to determine the number of moles of magnesium that participated in the reaction by using measurements. This information was used to calculate the mass of magnesium that participated in the reaction using the mole-mass relationship. This relationship helps us to determine the mass of a substance when we know the number of moles of that substance.

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If the mass of aluminum is 1. 80 g and iodine is 2. 30 g how much of the excess reagent remains after the reaction



2Al + 3I2 > 2AlI3

Answers

Total, 0.77 g of I2 is the amount of the excess reagent that remains after the reaction.

To determine the excess reagent remaining, we first need to find the limiting reagent.

The balanced equation tells us that 2 moles of Al react with 3 moles of I₂ to form 2 moles of AlI₃. We can use this information to calculate the theoretical yield of AlI3 based on the amount of each reactant;

moles of Al = 1.80 g / 26.98 g/mol = 0.067 moles

moles of I₂  = 2.30 g / 253.81 g/mol = 0.009 moles

Since the stoichiometry of the reaction is 2:3 for Al and I₂ , respectively, we can see that I₂ is the limiting reagent. Thus, all of the Al will react, while some of the I₂ will be left over.

The amount of AlI₃ that can be formed from the limiting reagent (I2) is:

moles of AlI₃ = 0.009 moles I₂  × (2 moles AlI₃ / 3 moles I₂ )

= 0.006 moles AlI₃

The mass of AlI₃ that can be formed is;

mass of AlI₃ = 0.006 moles × 407.82 g/mol

= 2.47 g

Since we know that only 2.30 g of I₂  was present initially, we can calculate the amount of excess I₂ remaining after the reaction;

excess I₂  = 2.30 g - (0.009 moles I₂  × 253.81 g/mol)

= 0.77 g

Therefore, 0.77 g of reagent that remains after the reaction.

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What substituent(s) might you add to convert benzoic acid into a very strong acid? Draw its structure and explain your reasoning

Answers

To convert benzoic acid into a very strong acid, you can add electron-withdrawing substituents like nitro groups (-NO₂) to the aromatic ring. These substituents increase the acidity of the carboxylic acid group by stabilizing the negative charge on the conjugate base, the benzoate ion.


Let us discuss this in detail.

1. Add a nitro group (-NO₂) as a substituent to the aromatic ring of benzoic acid. You can add more than one nitro group to further increase acidity.

2. The electron-withdrawing nature of the nitro group stabilizes the negative charge on the conjugate base (benzoate ion) by delocalizing the negative charge through resonance.

3. As a result, the equilibrium between benzoic acid and its conjugate base shifts towards the conjugate base, making the modified benzoic acid a stronger acid.

The structure of the modified benzoic acid with a nitro group at the ortho or para position is as follows:

      O
      ||
-C₆H₄-NO₂-C-O-H

Remember, adding more electron-withdrawing substituents like nitro groups will further increase the acidity of the benzoic acid derivative.

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tests show that the hydrogen ion concentration of a sample of apple juice is 0.0003 and that of ammonia is . find the ph of each liquid using the formula , where is the hydronium ion concentration.

Answers

The pH of the apple juice is approximately 3.52.

The pH of ammonia is approximately 11.13.

The pH of the apple juice can be calculated using the formula pH = -log[H₃O⁺], where [H₃O⁺] is the hydronium ion concentration. Given that the hydrogen ion concentration of the apple juice is 0.0003, the hydronium ion concentration can be calculated as follows:

[H₃O⁺] = 10^(-pH)

0.0003 = 10^(-pH)

-pH = ㏒(0.0003)

pH = -㏒(0.0003)

pH = 3.52

As a result, the pH of apple juice is roughly 3.52.

Similarly, the pH of ammonia can be calculated using the same formula. However, we are given the hydrogen ion concentration for ammonia, so we need to calculate the hydronium ion concentration first. Ammonia is a base, so it reacts with water to produce hydroxide ions (OH⁻):

NH₃ + H₂O → NH₄⁺ + OH⁻

The equilibrium constant for this reaction is the base dissociation constant, Kb. For ammonia, Kb = 1.8 x 10⁻⁵ at 25°C. Using this value, we can calculate the concentration of hydroxide ions as follows:

Kb = [NH4⁺][OH⁻]/[NH₃3

1.8 x 10⁻⁵ = x²/0.05

x = 1.34 x 10⁻³

Therefore, the concentration of hydroxide ions is 1.34 x 10⁻³ M. Using the formula for pH, we can now calculate the pH of ammonia:

pOH = -㏒[OH⁻] = -㏒(1.34 x 10⁻³) = 2.87

pH = 14 - pOH = 14 - 2.87 = 11.13

As a result, the pH of ammonia is about 11.13.

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Calculate the voltage generated by a hydrogen - oxygen fuel cell at 73.5°C
when the partial pressures of hydrogen and oxygen are 19.8 atm.

Answers

The voltage generated by a hydrogen-oxygen fuel cell at 73.5°C when the partial pressures of hydrogen and oxygen are 19.8 atm is 1.174 V.

The standard cell potential for the hydrogen-oxygen fuel cell is 1.23 V at 25°C. However, the Nernst equation takes into account the temperature and the partial pressures of the reactants. The Nernst equation is as follows:

Ecell = E°cell - (RT/nF)lnQ

where Ecell is the cell potential, E°cell is the standard cell potential, R is the gas constant (8.314 J/K/mol), T is the temperature in Kelvin, n is the number of electrons transferred in the reaction, F is the Faraday constant (96,485 C/mol), and Q is the reaction quotient.

To calculate Q, we need to know the concentrations of the reactants and products. In the case of a fuel cell, the reactants are the fuels, which are gases, and their concentrations are expressed as partial pressures. The reaction in a hydrogen-oxygen fuel cell is:

2H2 + O2 → 2H2O

The reaction quotient can be expressed as:

Q = (PH2)²(PO2)

where PH2 is the partial pressure of hydrogen and PO2 is the partial pressure of oxygen.

At 73.5°C, the temperature in Kelvin is 346.65 K. The partial pressures of hydrogen and oxygen are 19.8 atm. Substituting these values into the Nernst equation, we get:

Ecell = 1.23 V - (8.314 J/K/mol)(346.65 K/ (2*96,485 C/mol)) ln[(19.8 atm)²(19.8 atm)]

Ecell = 1.23 V - 0.056 V

Ecell = 1.174 V

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Which of the following describes a plant that has been exposed to a heat stimulus?


The plant loses all of its leaves.
The flower on the plant drops its petals.
The plant grows big fruit.
The plant grows tall.

Answers

A plant may go through a physiological response known as thermomorphogenesis in response to a heat stimulus. Option D.The plant grows tall. is correct.

This response may cause the plant to grow and develop in a variety of different ways, including enhanced stem elongation or modifications to the morphology of the leaves. As a result of enhanced stem elongation brought on by heat stress, plants can generally grow taller. This adaptation enables the plant to go away from the heat source and more easily absorb cooler air.

It is unusual for a plant to lose all of its leaves in response to a heat stimulation because this would mean a large loss of resources for the plant. Similar to how producing large fruit is not a usual reaction to heat stress, this is because the plant's energy resources might be diverted from reproduction to survival.

Heat stress may cause flowers to drop their petals, although this is not a universal reaction and would depend on the particular plant type and climatic factors.

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flew by Mercury in 1974; took photographs, temperature readings, and gathered atmosphere information; sent the information back to earth through radio waves

Answers

In 1974, the 1973-launched Mariner 10 spacecraft made history by flying by Mercury for the first time.

What is spacecraft?

A vehicle made specifically for space travel is a spaceship. It can encompass both spacecraft made for study, observation, and the deployment of satellites and other payloads as well as those made for human exploration, communication, and transportation. They typically consist of a propulsion system, navigation system, communications system, and numerous payloads, among other things. Typically, a spacecraft needs a launch vehicle to get off the ground and a re-entry mechanism to land safely.

It recorded temperature readings, snapped pictures, and gathered data on the planet's atmosphere during its flyby. Then, radio waves were used to transmit all of this data back to Earth. The mission was a great success and revealed a tonne of fresh Mercury-related data.

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The complete question is,

passed past Mercury in 1974, taking pictures, measuring temperatures, and gathering data on the atmosphere before radio-transmitting the data back to Earth.

1. when someone says, "i have a theory that excess salt causes high blood pressure," does that person really have a theory? if it is not a theory, what is it?

Answers

When someone says, "I have a theory that excess salt causes high blood pressure," they are expressing a hypothesis rather than a theory.

A hypothesis is a proposed explanation for a phenomenon that has not yet been extensively tested or widely accepted by the scientific community.

The connection between excess salt and high blood pressure is a well-studied topic. Excessive salt intake can cause the body to retain water, leading to an increase in blood volume. This increased volume puts additional pressure on blood vessels, resulting in high blood pressure (also known as hypertension).

Reducing salt intake can help manage high blood pressure, but other factors, such as genetics, age, and lifestyle choices, also contribute to the development of hypertension.

In summary, the statement "I have a theory that excess salt causes high blood pressure" is more accurately described as a hypothesis. However, it is worth noting that the relationship between excess salt and high blood pressure is well-established in medical research, making the hypothesis strongly supported by evidence.

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If 25. 5 mL of a 0. 1 M base solution was required to titrate 60 mL of an unknown acid solution, what is the molarity of the acid solution?

Answers

The molarity of the acid solution is 0.0425 M.

Titration is a common laboratory technique used to determine the concentration of a substance in a solution. In a titration, a known solution (titrant) is added gradually to an unknown solution until the reaction between the two is complete.

The point at which the reaction is complete is called the endpoint, and it is typically identified by an indicator that changes color.

To calculate the molarity of the unknown acid solution, we can use the following formula:

Molarity of acid solution = (Molarity of base solution) x (Volume of base solution) / (Volume of acid solution)

In this case, we know that 25.5 mL of a 0.1 M base solution was required to titrate 60 mL of the unknown acid solution. Using the formula above, we can plug in the values:

Molarity of acid solution = (0.1 M) x (25.5 mL) / (60 mL)
Molarity of acid solution = 0.0425 M

Therefore, the molarity of the acid solution is 0.0425 M.

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Match these items. Match the items in the left column to the items in the right column. 1. Electronegativity sharing bond 2. Covalent tendency to attract electrons 3. Ionic stable electron configurations 4. Inert gas transferring bond

Answers

The correct matches are:

1.A chemical bond between atoms with similar electronegativities - covalent bond

2. a measure of the ability of an atom to attract electrons within a chemical bond - Electronegativity

3. a bond between atoms of greatly differing electronegativities - Ionic bond

4. the bond formed in metals, holding metals together - Metallic bond

A covalent bond is a bond formed by sharing electrons between two atoms that occur in the bond. It generally forms between atoms with similar electronegativity values.

An ionic bond is a bond formed between two oppositely charged ions of her and held by strong electrostatic attraction. It forms between atoms that have vastly different electronegativities.

Electronegativity is the tendency of an atom in a covalent bond to attract a shared pair of electrons.

A metallic bond is a bond formed by electrostatic attraction between a positively charged metal ion and a conduction electron.

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Answer:

Sharing bond: Covalent

Tendency to attract electrons: Electronegativity

Stable electron configurations: Inert gas

Transferred electrons bond: Ionic

Calculate the standard free-energy changes for the following reactions at 25°c: (a) h2(g) + br2(l) → 2hbr(g)

Answers

The standard free-energy change for the reaction H₂(g) + Br₂(l) → 2HBr(g) at 25°C can be calculated using the equation ΔG° = ΔH° - TΔS°, where ΔH° is the standard enthalpy change, T is the temperature, and ΔS° is the standard entropy change.

To calculate the standard free-energy change for the reaction H₂(g) + Br₂(l) → 2HBr(g) at 25°C, you need to use the equation: ΔG° = ΔH° - TΔS°. Follow these steps:

1. Determine the standard enthalpy change (ΔH°) for the reaction.
2. Determine the standard entropy change (ΔS°) for the reaction.
3. Calculate ΔG° using the equation and the given temperature (25°C = 298.15 K).

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Using the lewis dot structures of magnesium and oxygen, predict the ionic formula.

Answers

Magnesium loses two electrons to oxygen to form Mg²⁺ and O²⁻ ions. The ionic formula for this compound can be predicted by writing the formula unit that balances the charges of the two ions. The ionic formula for magnesium oxide is MgO.

The Lewis dot structure of magnesium is Mg with two dots representing its valence electrons. The Lewis dot structure of oxygen is O with six dots representing its valence electrons.

Magnesium and oxygen form an ionic compound because magnesium loses two electrons to oxygen to form Mg²⁺ and O²⁻ ions. The ionic formula for this compound can be predicted by writing the formula unit that balances the charges of the two ions.

Since Mg²⁺ has a 2+ charge and O²⁻ has a 2- charge, the ionic formula for magnesium oxide is MgO.

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For #3 and #4, complete the synthesis reactions by writing the word equation for each
3. potassium + chlorine →
4. hydrogen + iodine →

Answers

potassium + chlorine → potassium chloride

hydrogen + iodine → hydrogen iodide

A synthesis reaction is a type of chemical reaction in which two or more simple substances combine to form a more complex product. In a synthesis reaction, the reactants come together to create a single compound, usually with the release of energy in the form of heat or light. The general equation for a synthesis reaction is A + B → AB, where A and B are the reactants, and AB is the product.

Synthesis reactions are also known as combination reactions because they involve the combination of two or more substances to form a new compound.

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h2o is a molecular compound that is a liquid at room temperature (22 degrees celsius). this is primarily due to the fact that it has relatively what strength of intermolecular forces?

Answers

H2O, or water, is a molecular compound that is a liquid at room temperature (22 degrees Celsius). This state is primarily due to the fact that it has relatively strong intermolecular forces.

These forces are the attractive forces between the molecules of the compound, and in the case of water, these forces are called hydrogen bonds.

Hydrogen bonds are a type of dipole-dipole interaction that occurs between molecules containing a hydrogen atom bonded to a highly electronegative element, such as oxygen in water. The oxygen atom attracts the electrons in the bond, creating a partial negative charge on the oxygen and a partial positive charge on the hydrogen.

This causes an electrostatic attraction between the partially positive hydrogen atom and the partially negative oxygen atom of a neighboring water molecule.

These hydrogen bonds give water its unique properties, such as its relatively high boiling and melting points compared to other molecular compounds with similar molecular weights.

The strong intermolecular forces provided by hydrogen bonding are what make water a liquid at room temperature, as they are strong enough to hold the molecules together, but not so strong that they form a solid at this temperature.

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If the reaction above has 118.3g of CS2 and 3.12 Mol of NaOH determine the limiting reactant in the reaction??3CS2+6NaOH— >2Na2CS3+Na2CO3+3H2O
Answer ASAP pls

Answers

[tex]CS_2[/tex]  is the limiting reactant in the reaction.

The balanced chemical equation for the reaction is:

3 [tex]CS_2[/tex] + 6 [tex]NaOH[/tex] → 2 [tex]Na_2CS_3[/tex] + [tex]Na_2CS_3[/tex] + 3 [tex]H_2O[/tex]

To determine the limiting reactant, we need to calculate the amount of product that each reactant can produce and compare it to the actual amount of product that is formed.

First, we need to convert the mass of [tex]CS_2[/tex] to moles:

118.3 g [tex]CS_2[/tex] × (1 mol [tex]CS_2[/tex] /76.14 g [tex]CS_2[/tex]) = 1.555 mol [tex]CS_2[/tex]

Next, we need to calculate the amount of product that can be formed from 1.555 mol of [tex]CS_2[/tex]. According to the balanced equation, 3 mol of [tex]CS_2[/tex] will produce 2 mol of [tex]Na_2CS_3[/tex]. Therefore, 1.555 mol of [tex]CS_2[/tex] will produce:

(2/3) × 1.555 mol = 1.037 mol [tex]Na_2CS_3[/tex]

Now, let's calculate the amount of product that can be formed from 3.12 mol of [tex]NaOH[/tex]. According to the balanced equation, 6 mol of [tex]NaOH[/tex] will produce 2 mol of [tex]Na_2CS_3[/tex]. Therefore, 3.12 mol of [tex]NaOH[/tex] will produce:

(2/6) × 3.12 mol = 1.04 mol [tex]Na_2CS_3[/tex]

Comparing the amount of product that can be formed from each reactant, we see that 1.037 mol of [tex]Na_2CS_3[/tex] can be produced from the 1.555 mol of [tex]CS_2[/tex], while 1.04 mol of [tex]Na_2CS_3[/tex] can be produced from the 3.12 mol of [tex]NaOH[/tex]. Therefore, the limiting reactant in the reaction is [tex]CS_2[/tex].

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The sequence of amino acids was controlled by the information in the BLANK molecules. (Fill in the blank)

Answers

The sequence of amino acids in a protein is controlled by the information stored in the DNA molecules.

DNA (deoxyribonucleic acid) is the genetic material that contains the instructions for the development, growth, and function of all living organisms. The DNA sequence is made up of four nucleotide bases, which are adenine (A), cytosine (C), guanine (G), and thymine (T). These nucleotide bases form a code that determines the sequence of amino acids in a protein.

The sequence of amino acids is important because it determines the shape and function of the protein. Proteins are essential macromolecules that perform a wide range of functions in living organisms, such as enzymes, hormones, and structural components.

The amino acid sequence is critical in determining the three-dimensional structure of a protein, which is essential for its function.

The process of converting the DNA code into a sequence of amino acids is called protein synthesis. Protein synthesis involves two main steps: transcription and translation. During transcription, the DNA sequence is copied into a molecule called RNA (ribonucleic acid).

The RNA molecule then carries the code to the ribosome, where the sequence of amino acids is assembled according to the code.

In summary, the sequence of amino acids in a protein is controlled by the information stored in the DNA molecules. This sequence is important because it determines the shape and function of the protein, which is essential for the proper functioning of living organisms.

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When 50 ml of water are added to 50 ml of water, the total volume of water is 100 ml. but if 50 ml of water are added to 50 ml of ethanol, the total volume will be less than 100 ml. why is this

Answers

This is because when water is added to ethanol, the two substances form a homogenous solution, meaning the two substances mix together to form a single molecular solution.

As a result, the water molecules and ethanol molecules take up the same amount of space, meaning the total volume of the mixture is less than the sum of the original two volumes (50 ml of water + 50 ml of ethanol = less than 100 ml).

This phenomenon is known as "volume contraction" and is caused by the intermolecular forces between water and ethanol molecules. This contraction also occurs when two other liquids are mixed together in certain combinations.

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I take 50.0 ml of 0.50 m hcl and add it to 150.0 ml of 0.10 m hno3. what is the ph of the resulting solution?

Answers

The pH of the resulting solution is calculated to be 1.40.

To determine the pH of the resulting solution, we need to first calculate the moles of each acid present.

Moles of HCl = (0.50 mol/L) x (0.050 L) = 0.025 mol
Moles of HNO3 = (0.10 mol/L) x (0.150 L) = 0.015 mol

Since the two acids are both strong acids, they will completely dissociate in solution. This means that the resulting solution will contain 0.025 mol of H+ ions from HCl and 0.015 mol of H+ ions from HNO3.

To calculate the pH of this solution, we can use the equation:

pH = -log[H+]

[H+] = (0.025 mol + 0.015 mol) / (0.050 L + 0.150 L) = 0.040 mol/L

pH = -log(0.040) = 1.40

Therefore, the pH of the resulting solution is 1.40.

In summary, when 50.0 ml of 0.50 M HCl is added to 150.0 ml of 0.10 M HNO3, the resulting solution contains 0.025 mol of H+ ions from HCl and 0.015 mol of H+ ions from HNO3. The pH of the resulting solution is calculated to be 1.40.

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A quantity of gas has a volume of 15 liters at 52. 0°C and 89. 9 kPa of pressure. To what volume must the gas be decreased


for the gas to be under standard temperature and pressure conditions?





4. 4L


8. 7L


0. 39 L


11L


Od

Answers

The gas must be decreased to a volume of 4.4 L to be under STP. The answer is option (a).

Using the ideal gas law, PV=nRT, we can solve for the number of moles of gas:

n = PV/RT

where P is pressure, V is volume, R is the gas constant (0.0821 L·atm/mol·K), and T is temperature in Kelvin.

First, we need to convert the temperature to Kelvin:

52.0°C + 273.15 = 325.15 K

Then we can calculate the number of moles of gas:

n = (89.9 kPa)(15 L)/(0.0821 L·atm/mol·K)(325.15 K) = 0.703 mol

To find the volume at standard temperature and pressure (STP), we can use the fact that at STP, the pressure is 1 atm and the temperature is 273.15 K. So we can set up a ratio:

(P1)(V1)/(n1)(T1) = (P2)(V2)/(n2)(T2)

where P1 = 89.9 kPa, V1 = 15 L, n1 = 0.703 mol, T1 = 325.15 K, P2 = 1 atm, T2 = 273.15 K, and we want to solve for V2:

(89.9 kPa)(15 L)/(0.703 mol)(325.15 K) = (1 atm)(V2)/(0.703 mol)(273.15 K)

V2 = (1 atm)(15 L)(0.703 mol)(273.15 K)/(89.9 kPa)(325.15 K) = 4.4 L

Therefore, the gas must be decreased to a volume of 4.4 L to be under STP. The answer is option (a).

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Complete question

A quantity of gas has a volume of 15 liters at 52. 0°C and 89. 9 kPa of pressure. To what volume must the gas be decreased for the gas to be under standard temperature and pressure conditions?

a. 4. 4L

b. 8. 7L

c. 0. 39 L

d. 11L

The decomposition reaction of calcium carbonate is represented by the following balanced equation:


CaCO3(s) --> CaO(s) + CO2(g)



After a 15. 8−g sample of calcium carbonate was heated in an open container to cause decomposition, the mass of the remaining solid was determined to be 9. 10 g. The reaction may or may not have gone to completion, so the solid could contain unreacted CaCO3. Calculate the percent yield of CO2.



Please help! Thank you!

Answers

The percent yield of CO2 in the decomposition reaction of calcium carbonate is 96.20%.

The decomposition reaction of calcium carbonate (CaCO3) is represented by the balanced equation:

CaCO3(s) --> CaO(s) + CO2(g)

To calculate the percent yield of CO2 from a 15.8-g sample of calcium carbonate that decomposed, leaving a solid mass of 9.10 g, follow these steps:

1. Determine the molar mass of CaCO3, CaO, and CO2.
- CaCO3: (40.08 + 12.01 + 3*16.00) = 100.09 g/mol
- CaO: (40.08 + 16.00) = 56.08 g/mol
- CO2: (12.01 + 2*16.00) = 44.01 g/mol

2. Calculate the theoretical amount of CO2 produced by the complete decomposition of 15.8 g of CaCO3.
- moles of CaCO3: (15.8 g) / (100.09 g/mol) = 0.158 mol
- moles of CO2 produced: 0.158 mol (1:1 ratio with CaCO3)
- mass of CO2: (0.158 mol) * (44.01 g/mol) = 6.95 g

3. Calculate the actual amount of CO2 produced based on the remaining solid mass.
- mass of CaO and unreacted CaCO3: 9.10 g
- mass of CaCO3 in the remaining solid: 15.8 g - 9.10 g = 6.70 g
- moles of CO2 actually produced: (6.70 g) / (44.01 g/mol) = 0.152 mol

4. Calculate the percent yield of CO2.
- percent yield: (actual moles of CO2 / theoretical moles of CO2) * 100
- percent yield: (0.152 mol / 0.158 mol) * 100 = 96.20%

The percent yield of CO2 in the decomposition reaction of calcium carbonate is 96.20%.

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What mass of iron (III) oxide


is produced when


3. 88 X 1025 molecules of oxygen


reacts with excess iron?


4Fe + 3O2 → 2Fe2O3

Answers

The mass of iron (III) oxide produced when 3.88 x 10²⁵ molecules of oxygen react with excess iron is 685.58 grams.

Determine the moles of oxygen molecules:
Number of moles = Number of molecules / Avogadro's number
Number of moles = 3.88 x 10²⁵ molecules / 6.022 x 10²³ molecules/mol
Number of moles = 6.44 moles of O₂

Use the balanced chemical equation to find the moles of Fe₂O₃ produced:
4Fe + 3O₂ → 2Fe₂O₃
Since 3 moles of O₂ react to produce 2 moles of Fe₂O₃
=(6.44 moles O₂) x (2 moles Fe₂O₃ / 3 moles O₂)

= 4.29 moles Fe₂O₃

Molar mass of Fe₂O₃ =

2(55.85) + 3(16.00) = 159.70 g/mol

Calculate the mass of Fe₂O₃ produced:
mass = moles x molar mass
mass = 4.29 moles x 159.70 g/mol
mass = 685.58 g


Therefore, when 3.88 x 1025 molecules of oxygen react with excess iron, 685.58 grams of iron (III) oxide are produced.

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A long string is stretched and its left end is oscillated upward and downward. Two points on the string are labeled A and B. Points A and B are indicated on the string. Orient the two vectors, v⃗ A and v⃗ B, to correctly represent the direction of the wave velocity at points A and B. Rotate the given vectors to indicate the direction of the wave velocity at the indicated points

Answers

The resulting diagram should show VA and V B pointing to the right, parallel to V AB.

To determine the direction of the wave velocity at points A and B, we need to consider the direction in which the wave is traveling.

Assuming that the wave is traveling from left to right, the direction of the wave velocity at point A will be to the right, and the direction of the wave velocity at point B will also be to the right.

To represent the direction of the wave velocity at points A and B using vectors, we can use the following steps:

Draw a vector representing the direction from point A to point B. This vector, which we'll call V AB, represents the direction of the string itself.

Draw another vector, V A, originating from point A and pointing in the direction of the wave motion. Since the wave is traveling to the right, this vector should also point to the right.

Similarly, draw another vector, V B, originating from point B and pointing in the direction of the wave motion. This vector should also point to the right.

Rotate V A and V B so that they are both parallel to VAB. This represents the fact that the wave velocity is in the same direction as the direction of the string itself.

The resulting diagram should show VA and V B pointing to the right, parallel to V AB.

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A 634. 5 g sample of helium absorbs 125. 7 calories of heat. The specific heat capacity of helium is 1. 241 cal/(g·°C). By how much did the temperature of this sample change, in degrees Celsius?

Answers

The temperature of the helium sample increased by 0.159 °C.

To solve this problem, we can use the equation:

q = mcΔT

where q is the heat absorbed, m is the mass of the helium sample, c is the specific heat capacity of helium, and ΔT is the change in temperature.

Substituting the given values, we get:

           q = mcΔT

125.7 cal = (634.5 g)(1.241 cal/(g·°C))ΔT

Solving for ΔT, we get:

ΔT = 125.7 cal / (634.5 g * 1.241 cal/(g·°C))

ΔT = 0.159 °C

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