Tritium, the 3H atom, consists of a nucleus of one proton and two neutrons with a single electron. It is unstable and decays via beta emission to singly ionized helium, 3 He , consisting of a nucleus of two protons and one neutron with a single electron. This decay takes place instantaneously and thus there occurs a sudden doubling of the Coulomb interaction between the atomic electron and the nucleus. If the tritium atom is in its ground state when it decays, determine the probability that the 3He atom is in its ground state immediately after the decay.

Required:
Determine the probability that the 3H^+ atom is in its ground state immediately after decay.

The force needed to accelerate the mass of 100 kg is 500 N.

Force is the product of mass and acceleration. The S.I unit of force is Newton (N).

To calculate the amount of force needed to accelerate the mass of 100 kg, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the force is 500 N.

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Answer:

a

Explanation:

Answer: b. more precipitation

Explanation:

The single cable will pull upward on the sign with a force of 38.3 N.

Single cable is a type of cable that is composed of a single electrical conductor. It is most commonly used in low voltage applications such as wiring for computers and domestic appliances. Single cable is typically insulated with rubber, PVC or other insulating materials. The insulator protects the conductor from short circuits and other electrical hazards.

This is because the sign is supported symmetrically by two cables, which means that the total downward force on the sign is equal to the total upward force. Since the two cables make an angle of 1.0 degrees with the horizontal, the total downward force on the sign is equal to the combined weight of the sign (38.3 N) and the two cables pulling down on it. Therefore, the single cable must pull up with a force of 38.3 N in order to keep the sign in equilibrium.

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Answer:

C

Explanation:

Answer:

a. an increase in the mass on the spring.

Explanation:

An increase in the mass on the spring will increase the period of an oscillating spring mass system.

Mathematically, the period of an oscillating spring mass system is given by the formula;

T = 2π √(m/k)

Where;

T is the period.

m is the mass of the spring.

k is the spring constant.

Hence, the mass of a spring is directly proportional to the period of oscillation of the spring.

This ultimately implies that, as the mass of the spring increases, the period of oscillation will increase. Similarly, the period of oscillation will decrease with an increase in the spring constant i.e there exist an inverse relationship between the period and spring constant.

Answer:

Explanation:

Add a horizontal line.  An object that is not moving has no change in distance with respect to time.

Answer:

i think..its fraction that its have multiple fractions on it..if you minus the 397 000-355 it should be 381+ so i say if you get the 5 multiply it by 9!! so you will get it!

Explanation:

HOPE IT HELPS!!

Answer:

a) Joules

b) W (symbol for work) (J is symbol for Joules)

c) seconds

d) watts

Option C is correct.

The magnitude of the charge on an electron compared to the magnitude of the charge on a proton is same.

We have a electron and a proton.

We have to estimate the fact whether the magnitude of the charge on an electron compared to the magnitude of the charge on a proton is -

a) is greater

or

b) is smaller

or

c) is the same

The sufficiency or deficiency of electrons is called electric charge.

According to the question -

The charge on a electron is -   q(e) = - 1.6 x [tex]10^{-19}[/tex] Coulombs

The charge on a proton is -   q(p) = + 1.6 x  [tex]10^{-19}[/tex] Coulombs

But, according to the property of magnitude :

| + x| = + x

| - x| = - (- x) = + x

In the similar manner -

|q(e)| = |q(p)| = 1.6 x [tex]10^{-19}[/tex] coulombs

Hence, the magnitude of the charge on an electron compared to the magnitude of the charge on a proton is same.

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Answer:

Explanation:

Time elapsed to reach the height of 230 m be t

s = ut + 1/2 at²

230 = .5 x 3.45 t²

t = 11.55 s

velocity at height of 230 m

v = u + at

= 0 + 3.45 x 11.55 = 39.84 m/s

This velocity will be attained by canister .

time to reach zero velocity at the top position t

v = u - gt

0 = 39.84 - 9.8 t

t = 4.06 s

height travelled by canister during this 4.06 s

v² = u² - 2gH

0 = 39.84² - 2 X 9.8 H

H = 80.98 M

Total height attained by canister = 80.98 + 230 = 310.98 m

Time of fall by canister t

s = 1/2 gt²

310.98 = .5 x 9.8 t²

t = 7.97 s

Total time taken by canister to reach the ground after its release from rocket

= 4.06 + 7.97 = 12.03 s

Distance travelled by rocket in 12.03 s

s = ut + 1/2 a t²

= 39.84 x 12.03 + .5 x 3.45 x 12.03²

= 479.27 + 249.64

= 728.91 m

height of rocket required = 230 + 728.91

= 958.91 m

2 )

Distance travelled by canister between its release and fall on the ground

= 80.98 + 80.98 + 230

= 391.96 m.

Answer: Pedaling your bike : acceleration :: applying the brakes : inertia.

The reason I think this to be the answer to the analogy is because there is energy and work used in both processes (and the unit focuses on forces); gravity is constant and does not change whether one pedals or applies brakes. And I do not think it's deceleration, as deceleration tends to equate to acceleration within the physics perspective.

Edit: I should also add that since you clarified that your unit is motion and forces, Newtons 1st law is the law of inertia. The way to change an objects motion for it to slow down is by applying an additional force. That resistance the bike experiences to slow is the process of inertia. Inertia happens in order to accelerate an object (either by slowing it down, or speeding it up): i.e., the resistance to change.

Resistors limits the current/amps but keep the voltage the same.

You don't want to attach them together with a wire since there would be too much current loose through, such that the battery heats up till it blows or something.

Current is directly corresponding to voltage; a doubling of the voltage will double the current. But the current is also inversely comparable to the resistance; a doubling of the resistance will halve the current.

So we can conclude that Resistance residue is the same, but power becomes four times i.e. multiplication. If the current is I and the voltage is V,

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Answer:

2 stays the same 1 it will go bad or go good depends on which material you use

Answer:

628 J

Explanation:

ME = PE + KE

PE = mgh = 0,  because h = 0

KEi (initial KE) = 1/2mv² = 1/2(62.3 kg)(4.49 m/s)² = 628 J

KEf (final KE) = 0, because v-final = 0

All the initial ME, which is all KE, converts to thermal E due to friction

Answer:

12.3 m/s

Explanation:

To calculate the final velocity of Ben, we can use the equation KE = 1/2mv^2, where KE is the kinetic energy and m is the mass of Ben. Inserting the given values, we get:

7100 = 1/2 (63.2 kg) v^2

Therefore, v^2 = 7100/31.6

v = √(7100/31.6)

v = 12.3 m/s

Answer:

Yup

Explanation:

The mass of ball B and the final velocity of ball A can complement the conservation of linear momentum. The answer is yes.

Momentum can simply be defined as the product of mass and velocity. It is a vector quantity.

Given that ball A with a mass of 0.280kg makes an elastic head-on collision with ball B initially at rest. After collision, ball B moves off with half the original speed of ball A.

In an elastic head-on collision, momentum is mostly always conserved. That is, the sum of the momentum before collision will be equal to the sum of the momentum after collision.

Mathematically, MaUa = MaVa + MbVb

Is the momentum conserved in the collision?

The answer is yes!

Why?

Because we need to consider the mass of the ball B and the final velocity of the ball A.

Therefore, In consideration of the mass of the ball B and the final velocity of the ball A, we can say that the momentum is conserved.

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Answer:

Describe how one-dimensional vector quantities are added or subtracted.

Answer:

Explanation:

charge on each proton = 1.6 x 10⁻¹⁹ C

mass of proton = 1.67 x 10⁻²⁷ kg

Electrostatic force of repulsion Fe = 9 x 10⁹ x ( 1.6 x 10⁻¹⁹ )² / d²

= 23.04 x 10⁻²⁹ / d²

Gravitational  force of attraction = G Mm / d²

M = m = 1.67 x 10⁻²⁷ kg

Gravitational  force of attraction  Fg = 6.67  x 10⁻¹¹ x ( 1.67 x 10⁻²⁷ )² / d²

= 18.60 x 10⁻⁻⁶⁵ / d²

So Fg is far less than Fe and former is attractive , later is repulsive .

Fe > Fg, opposite direction , is the answer .

Answer:

6.45

Explanation:

Got it right on Acellus

If an object is working against gravity, that means gravity must have the opposite sign of the object (this is why we see objects slow down at their peak height and return to us if we throw them in the air!). If the object is working with gravity, though, they must both be moving in the same direction, therefore gravitational acceleration would be the same sign as the velocity (positive or negative depending on how you define your axes).

Therefore, your answer should be C. Different sign + or - on the acceleration.

I hope this helps!

Answer:

[tex]\% Error = 2.6\%[/tex]

Explanation:

Given

[tex]x: 1.54, 1.53, 1.44, 1.54, 1.56, 1.45[/tex]

Required

Determine the percentage error

First, we calculate the mean

[tex]\bar x = \frac{\sum x}{n}[/tex]

This gives:

[tex]\bar x = \frac{1.54+ 1.53+ 1.44+ 1.54+ 1.56+ 1.45}{6}[/tex]

[tex]\bar x = \frac{9.06}{6}[/tex]

[tex]\bar x = 1.51[/tex]

Next, calculate the mean absolute error (E)

[tex]|E| = \sqrt{\frac{1}{6}\sum(x - \bar x)^2}[/tex]

This gives:

[tex]|E| = \sqrt{\frac{1}{6}*[(1.54 - 1.51)^2 +(1.53- 1.51)^2 +.... +(1.45- 1.51)^2]}[/tex]

[tex]|E| = \sqrt{\frac{1}{6}*0.0132}[/tex]

[tex]|E| = \sqrt{0.0022}[/tex]

[tex]|E| = 0.04[/tex]

Next, calculate the relative error (R)

[tex]R = \frac{|E|}{\bar x}[/tex]

[tex]R = \frac{0.04}{1.51}[/tex]

[tex]R = 0.026[/tex]

Lastly, the percentage error is calculated as:

[tex]\% Error = R * 100\%[/tex]

[tex]\% Error = 0.026 * 100\%[/tex]

[tex]\% Error = 2.6\%[/tex]

Answer:

True:

F1 = G M1 M2 / R^2

F2 = G (2 M1) * (2 M2) / (2 R)^2

F1 = F2

Answer:

The mass is the amount of matter in something. Weight is mass times gravitational field strength and so also includes gravity. Mass is measured in grams (g) and weight is measured in Newtons (N)

The two charges, each of magnitude 6.0 μC, exert a force of 0.70 N at separation  of 1.47 meters.

Electric force is the attracting or repulsive interaction between any two charged things. Similar to any force, Newton's laws of motion describe how it affects the target body and how it does so. One of the many forces that affect objects is the electric force.

We know that electric force can be defined as:

Force: F = kQq/r²

0.70 = 9.0 × 10⁹ × (6.0×10⁻⁶)²/r²

r = 1.47 meter.

Hence, the separation between them is 1.47 meters.

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Answer: A. Earth to circle the sun one time.