The calculated energy change for the given reaction is H° = 83 kJ/mol.
Calculation-
(Bond energies of broken bonds) - H° (bond energies of bonds formed)
H—C—C—H and 2 Br2 are the reactants in the reaction described. Here are the goods: CHBr2—CHBr2.
H—C—C bond's bond energy is 837 kJ/mol.
Br—Br bond's bond energy is 193 kJ/mol (for 1 Br2 molecule)
Thus, the amount of total energy needed to dissolve the reactants' bonds is:
(1,223 kJ/mol) = (837 kJ/mol 1) + (193 kJ/mol 2)
∆H° = Σ (bond energies of bonds broken) - Σ (bond energies of bonds formed)
= (1,223 kJ/mol) - (1,140 kJ/mol)
= 83 kJ/mol
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What volume is occupied by 16.4 grams of mercury? The density of mercury is 13.6g/ml
If the density of mercury is 13.6 g/mL, the volume of a 155-gram sample of mercury is 11.397 mL.
What is meant by volume?The area contained by an object's limits in three-dimensional space is referred to as its volume. Another name for it is an object's capacity.A student could measure the volume of a chemical solution in millilitres using a graduated cylinder as an illustration of volume. A quart of milk might be obtained. Gases are frequently offered for sale in volumetric units like cubic centimetres, or cm3, or cubic litres. For example, the capacity of a rectangular container, the basic formula for understanding volume is length x width x depth. The space an object occupies is simply referred to as its volume. There are several techniques for measuring volume, depending on the physical characteristics of an object.It follows that:
Mercury has a density of 13.6 g/mL.
155 grammes make to the mercury's weight.
The fact is,
A three-dimensional space enclosed by an object or thing is referred to as its volume.
Mass times volume equals density.
13.6 = Volume 155
quantity = 155/13.6
11.397 mL is the capacity.
As a result, assuming mercury has a density of 13.6 g/mL, a 155-gram sample of mercury has a volume of 11.397 mL.
The complete question is:
The density of mercury is 13.6 g/mL. What is the volume of a 155-gram sample of mercury?
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In a weather forecast on a Seattle radio station the barometric pressure was reported to be 29.4 inches. What is the pressure in SI units? (1 inch = 25.4 mm, 1 atm = 760 mmHg)
Answer:
99585.48 Pa or approximately 0.981 atm.
Explanation:
To convert the barometric pressure from inches to SI units (Pascals), we can use the following conversions:
1 inch = 25.4 mm
1 mm = 0.1 cm
1 cm = 10 mm
1 mmHg = 133.322 Pa
1 atm = 760 mmHg
Therefore, we can calculate the pressure in SI units as follows:
Convert inches to mm: 29.4 inches x 25.4 mm/inch = 746.76 mm
Convert mmHg to Pa: 746.76 mm x 133.322 Pa/mmHg = 99585.48 Pa
Convert atm to Pa: 1 atm x 760 mmHg/atm x 133.322 Pa/mmHg = 101325 Pa
Calculate the pressure in SI units: 99585.48 Pa/101325 Pa/atm = 0.981 atm
Therefore, the barometric pressure in SI units is 99585.48 Pa or approximately 0.981 atm.
4.8g of salt(z) dissolved in 250cm³ of distilled water give a concentration of 0.80m/dm³. Calculate the molar mass of the salt(z)
Answer:
24 g/mol.
Explanation:
To calculate the molar mass of the salt (z), we need to use the formula:
concentration = number of moles / volume of solution
We know that the concentration is 0.80 mol/dm^3, and the volume of the solution is 250 cm^3, which is equivalent to 0.25 dm^3. Therefore, we can rearrange the formula to solve for the number of moles of salt (z):
number of moles = concentration x volume of solution
number of moles = 0.80 mol/dm^3 x 0.25 dm^3
number of moles = 0.20 mol
Next, we can calculate the mass of salt (z) in the solution using the formula:
mass = number of moles x molar mass
We know that the mass of salt (z) is 4.8 g, and we just calculated that the number of moles is 0.20 mol. Therefore, we can rearrange the formula to solve for the molar mass:
molar mass = mass / number of moles
molar mass = 4.8 g / 0.20 mol
molar mass = 24 g/mol
Therefore, the molar mass of the salt (z) is 24 g/mol.
Answer:24 g/mo
Explanation:
What allows a person to interact with web browser software?
O user interface
O file transfer protocol
O networking
O URLS
The ability to interact with web browser software is provided by the user interface. It offers a visual user interface that enables entry of commands and response from the programme.
What makes it possible for a user to engage with the web pages?Via a Web browser, a user can interact with data or software running on a remote server using a Web user interface or Web app. The user interacts with the content on a web browser, which functions as a client, after downloading it from the web server.
What is a piece of software that enables user interaction with websites?A web browser is a piece of software that enables a user to view and interact with content that may be found on a website, including text, photos, videos, music, and other types of media. Hyperlinks to other web pages at the same or different websites can be found in the text and images on a web page.
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7.25 g of a mixture of KCl and KClO3 is heated with MnO2 catalyst and the mass of the mixture is found to be 5.50 g after heating. What is the mass percentage of KClO3 in the initial mixture? (K: 39.0 g/mol, Cl: 35.5 g/mol, O: 16.0 g/mol)
The mass percentage of KClO₃ in the initial mixture, given that the initial mixture has a mass of 7.25 g, is 62.2%
How do i determine the mass percentage of KClO₃?First, we shall determine the molar mass of KClO₃ and KCl. Details below:
For KClO₃
Molar mass of K = 39 g/molMolar mass of Cl = 35.5 g/molMolar mass of O = 16 g/molMolar mass of KClO₃ = ?Molar mass of KClO₃ = 39 + 35.5 + (3 × 16)
Molar mass of KClO₃ = 39 + 35.5 + 48
Molar mass of KClO₃ = 122.5 g/mol
For KCl
Molar mass of K = 39 g/molMolar mass of Cl = 35.5 g/molMolar mass of KCl =?Molar mass of KCl = 39 + 35.5
Molar mass of KCl = 74.5 g/mol
Next, we shall determine the mass of KClO₃ in the initial mixture. Details below:
Molar mass of KClO₃ = 122.5 g/molMolar mass of KCl = 74.5 g/molMass of mixture = 7.25 gMass of KClO₃ =?Mass of KClO₃ = [molar mass of KClO₃ / molar mass of (KClO₃ + KCl)] × mass of mixture
Mass of KClO₃ = [122.5 / (122.5 + 74.5)] × 7.25
Mass of KClO₃ = 4.51 g
Finally, we shall determine the mass percentage of KClO₃. Details below:
Mass of KClO₃ = 4.51 gMass of mixture = 7.25 gMass percentage of KClO₃ =?Mass percentage of KClO₃ = (mass of of KClO₃ / mass of mixture) × 100
Mass percentage of KClO₃ = (4.51 / 7.25) × 100
Mass percentage of KClO₃ = 62.2%
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If you measured the absorbance of the copper solution using a wavelength of 610 nanometers during a copper/silver electrolytic cell experiment, would you expect the absorbance to go up, down or stay the same as the reaction proceeds? Justify why
Several sizes of Cu particles' optical absorption spectra are also described; these spectra contain the plasmon band in the 560–580 nm range and a UV band at 222 nm, becoming flatter with increasing particle size.
What wavelength did you employ to gauge the solutions' absorbance of copper II sulphate?From the calibration figure, calculate the copper (II) sulphate concentrations in your two unknown samples. Useful wavelength is 700 nm.
How can you figure out the copper II sulphate solution's concentration?By testing an unknown CuSO4 solution's absorbance with a Colorimeter, you can ascertain its concentration. The corresponding concentration can be obtained on the horizontal axis of the graph by placing the absorbance of the unknown on the vertical axis.
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Which of the following is the correct (and complete) formula for solid sodium sulfide? NaS₂ SOS NaS Na₂S (s) Na₂S
After two emissions an isotope of oxygen-17 becomes a isotope of nitrogen-13. What are the two emissions
The two emissions required for oxygen-17 to become nitrogen-13 are a positron emission and a neutrino emission.
What is neutrino and a positron?A neutrino is a subatomic particle that is similar to an electron in many ways but differs in that it lacks an electrical charge and has a very small mass that might potentially be zero.
Positron is a particle with the same mass as an electron but has a positive charge.
The transformation of oxygen-17 to nitrogen-13 requires the emission of two particles: a positron (also called a positive beta particle) and a neutrino.
The first emission is the positron, which is a particle with the same mass as an electron but with a positive charge. During the emission, a proton in the oxygen-17 nucleus converts into a neutron, and the positron and a neutrino are produced. The positron quickly annihilates with an electron, releasing two gamma rays.
The second emission is the neutrino, which is a subatomic particle with a very small mass and no electrical charge. The neutrino is emitted during the decay of the nitrogen-13 nucleus as it transitions to its ground state.
Therefore, the two emissions required for oxygen-17 to become nitrogen-13 are a positron emission and a neutrino emission.
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When two hydrogen atoms approach each other to form a chemical bond, different interactions occur between the atoms. Identify the correct statements with respect to the interactions involved in the formation of chemical bond. Check all that apply. View Available Hint(s)for Part A When two hydrogen atoms approach each other to form a chemical bond, different interactions occur between the atoms. Identify the correct statements with respect to the interactions involved in the formation of chemical bond.Check all that apply. When two atoms of H approach each other, the two nuclei repel each other. When two atoms of H are infinitely far apart, they show attractive interactions. When two atoms of H approach each other, the electrons attract each other. When two atoms of H approach each other, each electron is attracted by the other nucleus. When two atoms of H approach each other, each electron repels the other nucleus.
H atoms communicate attractively even when they are infinitely apart. Each electron is drawn to the other centre as two H atoms get close to one another. The electrons of two H atoms draw one another when they come close to one another.
Do two H atoms exhibit attractive interactions when they are indefinitely separated from one another?When two atoms of H come close to one another, one electron of each atom repels one nucleus while the other nucleus attracts the other electron. H atoms communicate attractively even when they are infinitely apart.
What transpires if two hydrogen ions are separated greatly?They cannot make a covalent bond if they are too far apart because their individual 1s orbitals cannot overlap; instead, they remain as two separate objects.
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how many hydrogen-bonds does this molecule have?
how many acceptors does it have?
How many h-bonds can this molecule form with another identical
How many h-bonds can it form with water?
The compound would have six hydrogen bonds.
It has 3 H bond acceptors. It can form six H bonds with an identical molecule. It can form three hydrogen bonds with water.
What are hydrogen bonds?Hydrogen bonds are a type of intermolecular force that occurs between a hydrogen atom bonded to an electronegative atom (such as nitrogen, oxygen, or fluorine) and a nearby electronegative atom on another molecule.
The hydrogen bond is a weak electrostatic attraction between the partially positive hydrogen and the partially negative atom, which is typically a lone pair of electrons on the other molecule.
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calculate the % relative error in solubility by using concentrations instead of activities for the following compounds in 0.0440 m using the thermodynamic solubility products listed below.
The relative solubility is, % relative error = |(s - s') / s| × 100 by using concentrations instead of activities. The % Relative error is [tex]1.42*10^-9[/tex]
The % relative error in solubility, can determine by:
Step 1: Calculate the solubility using concentrations
- Determine the solubility product constant (Ksp) of each compound.
- Write the balanced chemical equation and expression for Ksp.
- Solve for the solubility (s) in terms of concentrations.
Step 2: Calculate the solubility using activities
- Replace concentrations in the Ksp expression with activities (use activity coefficients if needed).
- Solve for the solubility (s') using activities.
Step 3: Calculate the % relative error
- Use the formula: % relative error = |(s - s') / s| × 100
Assuming that the ionic strength is low, we can use the Debye-Hückel equation to calculate the activity coefficients at 25°C and 0.0500 M ionic strength:
log γ± = -0.5091 (z+ z- √(I)) / (1+√(I))
where z+ and z- are the charges of the cation and anion, respectively, and I is the ionic strength.
For KNO3, z+ = 1 and z- = 1, so I = [tex]1/2 (1^2 *0.0500 + 1^2*0.0500)[/tex] = 0.0250. Therefore, the activity coefficients are:
γ±(K+) = γ±(NO_3-) = 0.790
Using the activity coefficients, we can calculate the ion concentrations and then the solubility:
(a) CuCl:
[Cu+] = aCu+ × [CuCl] = [tex](0.3 nm) *√(Ksp/[CuCl]) = 3.17*10^-6 M[/tex]
[Cl-] = [Cu+]
Solubility = [CuCl] = [Cu+] = [Cl-] = [tex]3.17*10^-6 M[/tex]
Using concentrations instead of activities, we have:
[Cu+] = [Cl-] = √(Ksp/[CuCl]) = [tex]3.16*10^{-3}[/tex] M
Solubility = [CuCl] = [Cu+] = [Cl-] = [tex]3.16*10^{-3}[/tex] M
% Relative error = |[tex](3.17*10^{-6} - 3.16*10^{-3})/3.17×10^{-6}[/tex]| × 100% ≈ 99.7%
(b) Fe(OH)2:
[tex][Fe^2+] = aFe^2+ * [Fe(OH)_2] = (0.84 nm) * √(Ksp/[Fe(OH)2]) = M[OH-] = 2[Fe^2+][/tex]
Solubility =[tex][Fe(OH)_2] = [Fe^{2+}][/tex]= [tex]1.42*10^{-9} M[/tex]
Using concentrations instead of activities, we have:
[tex][Fe^2+] = [OH^-] = √(Ksp/[Fe(OH)_2])[/tex] = [tex]3.16*10^-8[/tex] M
Solubility = [tex][Fe(OH)_2] = [Fe^{2+}][/tex]= [tex]3.16*10^-8[/tex] M
% Relative error = [tex]1.42*10^-9[/tex]
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The complete question is:
Calculate the % relative error in solubility by using concentrations instead of activities for the following compounds in 0.0500 M KNO3 using the thermodynamic solubility products listed in Appendix 2.
(a) CuCl (aCu+ = 0.3 nm)
(b) Fe(OH)2
(c) Fe(OH)3
(d) La(IO3)3
(e) Ag3AsO4 (αAsO43֊= 0.4 nm)
HELP PLEASE I NEED IT BY TOMORROW photo attached
The specific heat capacity of the metal, given that the metal was heated to 97 °C and transferred to water at 20.5 °C, is 0.203 Cal/gºC
How do I determine the specific heat capacity of the metal?We'll begin by obtaining the heat absorbed by the water. Details below:
Mass of water (M) = 86.0 gInitial temperature (T₁) = 20.5 °CFinal temperature (T₂) = 24.1 °CTemperature change (ΔT) = 24.1 - 20.5 = 3.6 °CSpecific heat capacity of water (C) = 1 Cal/gºC Heat absorbed (Q) =?Q = MCΔT
Q = 86 × 1 × 3.6
Q = 309.6 Cal
Finally, we shall determine the specific heat capacity of the metal. Details below:
Heat absorbed by water (Q) = 309.6 CalHeat released by metal (Q) = -309.6 CalMass of metal (M) = 20.9 gInitial temperature (T₁) = 97 °CFinal temperature (T₂) = 24.1 °CTemperature change (ΔT) = 24.1 - 97 = -72.9 °CSpecific heat capacity of metal (C) = ?Q = MCΔT
-309.6 = 20.9 × C × -72.9
-309.6 = -1523.61 × C
Divide both sides by -1523.61
C = -309.6 / -1523.61
C = 0.203 Cal/gºC
Thus, we can conclude that the specific heat capacity of the metal is 0.203 Cal/gºC
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calculate the formula mass of the unknown acid using the manual titration volume of naoh used to reach an endpoint (procedure step
To calculate the formula mass of an unknown acid using the volume of NaOH required to reach the endpoint of the titration, you will need to use the following formula: Formula mass = (molarity of NaOH) x (volume of NaOH) x (molar ratio of NaOH to acid) / (moles of acid).
Here are the steps to follow: Write the balanced equation for the reaction between the acid and NaOH.
Record the volume of NaOH which is used in the titration.
Determine the molarity of the NaOH solution. This can be done by dividing the number of moles of NaOH used in the titration by the volume of NaOH used.
Determine the molar ratio of NaOH to acid from the balanced equation.
Calculate the number of moles of acid that reacted with the NaOH by multiplying the volume of NaOH used in the titration by the molarity of NaOH.
Calculate the formula mass of the acid by plugging in the values for the molarity of NaOH, volume of NaOH, molar ratio of NaOH to acid, and moles of acid into the formula given above.
For example, suppose that you titrated an unknown acid with 0.100 M NaOH, and it took 25.0 mL of NaOH to reach the endpoint. The chemical equation for the reaction is:
Acid + NaOH → NaA + H₂O
The molar ratio of NaOH to acid is 1:1. Let's assume that you used 0.025 moles of NaOH in the titration. Then:
Molarity of NaOH = 0.100 M
Volume of NaOH =25.0 mL =0.0250 L
Moles of acid = (0.100 M) x (0.0250 L) x (1 mol acid / 1 mol NaOH) = 0.00250 mol acid
Now, let's assume that the formula mass of the acid is X. Then:
Formula mass = (0.100 M) x (0.0250 L) x (1 mol acid / 1 mol NaOH) / (0.00250 mol acid) = X g/mol
Therefore, the formula mass of the unknown acid is X g/mol.
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--The given question is incomplete, the complete question is
"How to calculate the formula mass of an unknown acid using the manual titration volume of NaOH with which it was titrated, used to reach the endpoint?"--
You are a NASA engineer and your superiors have instructed you to analyze the situation. The space craft consists of a command module and a lunar module. The command module is intended to house the three astronauts for most of the duration of the mission and enter lunar orbit, while the lunar module was designed only for the short trip from lunar orbit to the Moon’s surface and back to the command module. The lunar module is only built to support two people, with the third remaining on the command module during a lunar excursion. You have the following information: There are enough CO2 absorbers on the command module to last more than 10 days, but the LiOH cannisters are not easily compatible with the containment units on the lunar module. Each CO2 absorber on the command module contains 600g of lithium hydroxide. Each CO2 absorber on the lunar module contains 365g of lithium hydroxide. The lunar module is expected to reach Earth 3 days from now and has more than enough oxygen supply for the trip. The lunar lander is equipped with six CO2 absorbers. Each astronaut uses approximately 2500 kilocalories per day, and there are 4 kilocalories per gram of glucose. You can assume that metabolism of the astronauts can be approximated by the (unbalanced) equation for glucose metabolism given below: __6126 + __2 → __2 + __2 You need to determine: Can the three astronauts safely make the trip back to Earth with only the CO2 absorbers contained in the lunar module? If not, how many additional CO2 absorbers need to be retrieved from the command module? Write out all calculations and relevant reactions equations that you used to come to this conclusion. Could these calculations be done without using the mole?
Yes, the three astronauts can safely make the trip back to Earth with only the CO2 absorbers contained in the lunar module.
What is lunar module?The Lunar Module (LM) was a spacecraft built by the United States and used in the Apollo program to land humans on the Moon. The LM was designed and built to be used only in the vacuum of space, and it had no capability to operate in the Earth's atmosphere or on the surface of the Moon.
To determine this, we can calculate the amount of glucose needed to sustain the astronauts for the 3-day trip.
We know that each astronaut needs 2500 kilocalories per day, and there are 4 kilocalories per gram of glucose.
Therefore, each astronaut needs 625 grams of glucose per day, or 1875 grams of glucose total for the 3-day trip.
We can then convert this to moles of glucose needed, using the molar mass of glucose (180.156 g/mol).
Therefore, 1875 grams of glucose is equal to 10.4 moles of glucose.
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.In a popular classroom demonstration, solid lithium is added to liquid water and reacts to produce hydrogen gas and aqueous lithium hydroxide.
Part A
Enter a balanced chemical equation for this reaction.
Express your answer as a chemical equation including phases
Because sodium is such a highly reactive metal, it interacts with water quickly to produce sodium hydroxide and hydrogen gas. The correct chemical formula is: H2O + Na(s) = NaOH (aq) + H2 (g)
What is the name of the acid that, when combined with lithium hydroxide, yields lithium chloride and water?Hydrochloric acid and lithium oxide react, neutralising the acid. Lithium chloride and water are the results of the process.
Why does potassium, which releases less energy, react forcefully and catch fire whereas lithium reacts calmly with water?A larger surface area is exposed to the water as the molten metal flows across it. Moreover, among all alkali metals, lithium has the largest hydrated radius. This reduces the ionic mobility, which causes the molten metal to move more slowly.
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2. Radical chlorination of 2-methylpentane yields a mixture of monochlorinated products. (i) Draw all monochlorinated products resulting from reaction of 2 methylpentane. (ii) Identify the major product. Iii) Show step-wise mechanism for the radical halogenation of the major product. (8) i. mixture of isomers 2-methylPentane
The chlorine radicals can also react with each other to form chlorine molecules, which terminates the chain reaction.
(i) The monochlorinated products resulting from the reaction of 2-methylpentane are:
1-chloro-2-methylpentane
2-chloro-2-methylpentane
3-chloro-2-methylpentane
(ii) The major product in this reaction is 2-chloro-2-methylpentane.
(iii) The step-wise mechanism for the radical halogenation of 2-chloro-2-methylpentane are:
1. Initiation :- This step involves the homolytic cleavage of the chlorine molecule to form two chlorine radicals.
[tex]Cl^ 2[/tex]→ [tex]2Cl[/tex]·
2.Propagation:- [tex]Cl[/tex]· + 2-methylpentane → [tex]HCl[/tex] + 2-methylpentyl•
2-methylpentyl• +[tex]Cl^ 2[/tex] → 2-chloro-2-methylpentyl• + [tex]Cl[/tex]·
The 2-methylpentane molecule reacts with the chlorine radical to form a 2-methylpentyl radical and hydrogen chloride. The 2-methylpentyl radical then reacts with another chlorine molecule to form the 2-chloro-2-methylpentyl radical and another chlorine radical.
3.Termination:- 2-methylpentyl• + [tex]Cl[/tex]· → 2-chloro-2-methylpentane
2-methylpentyl• + 2-methylpentyl• → 2,2-dimethylpentane
[tex]Cl[/tex]· + [tex]Cl[/tex]· → [tex]Cl^ 2[/tex]
The 2-chloro-2-methylpentyl radical reacts with a chlorine radical to form the major product, 2-chloro-2-methylpentane. The 2-methylpentyl radical also reacts with another 2-methylpentyl radical to form 2,2-dimethylpentane.
Finally, the chlorine radicals can also react with each other to form chlorine molecules, which terminates the chain reaction.
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If you mastered this assignment, you will do exactly as it says to do.
What’s the Count?
NaC2HO4
Elements found in Formula:
Number of atoms in Element:
H2F5BLi
Elements found in Formula:
Number of atoms in Element:
2He2PSO4
Elements found in Formula:
Number of atoms in Element:
3He2O4PH
Elements found in Formula:
Number of atoms in Element:
The elements are the simplest chemical forms and they cannot be broken down through chemical reactions. There are many elements in the given formulas.
What are elements?
The elements are defined as those substances whose atoms all have the same number of protons. The elements are considered as the building blocks of matter. Each element has an atomic number and a symbol.
Each atom is regarded as an element. The elements create bonds to form molecules. The isotopes are the elements with the same atomic number but different mass numbers.
NaC₂HO₄ - 'N' , 'C', 'H','O'
H₂F₅BLi - 'H','F','B','Li'
He₂PSO₄ - 'He', 'P','S','O'
He₂O₄PH - 'He', 'O','P','H'
Question 7 of 10
When naming a molecule, how do you indicate that the carbons on either side
of the double bond are pointing in opposite directions?
OA. Use the prefix cis-.
OB. Use the prefix methyl-.
OC. Use the number 2 as a prefix.
OD. Use the prefix trans-.
Answer:
use the prefix trans-
Explanation:
trans = opposite orientation across double bond its this one for apex
cis = same orientation across double bond.
Hopefully this helps! :)
1. What is the molarity of a solution that contains 0.25 moles of NaOH dissolved in 3.0 Liters solution?
Answer:
A 3.0 M solution of NaOH has 3.0 moles of NaOH per liter of solution. There are 0.25 L of solution (250mL⋅1L1000mL), so there are 0.25L⋅3.0mol/L=0.75mol of NaOH. The molar mass of NaOH is 40.0 g/mol, so there are 0.75mol⋅40.0g/mol=30g of NaOH, 30.
I hope this can help you! A brainilist is appreciated and helpful! <333
What quantity in moles of precipitate are formed when 52.9 mL of 0.400 M Ca(NO₃)₂ is mixed with excess K₃PO₄ in the following chemical reaction?
3 Ca(NO₃)₂(aq) + 2 K₃PO₄(aq) → Ca₃(PO₄)₂(s) + 6 KNO₃(aq)
Answer:
To determine the number of moles of precipitate formed in the reaction, we first need to find the limiting reagent.
From the balanced chemical equation, we know that 3 moles of Ca(NO₃)₂ react with 2 moles of K₃PO₄ to produce 1 mole of Ca₃(PO₄)₂.
Let's first calculate the number of moles of Ca(NO₃)₂ present in 52.9 mL of 0.400 M solution:
moles of Ca(NO₃)₂ = concentration × volume
= 0.400 mol/L × 0.0529 L
= 0.02116 mol
Since the stoichiometric ratio of Ca(NO₃)₂ to K₃PO₄ is 3:2, we would need 3/2 times the number of moles of K₃PO₄ to react completely with the given amount of Ca(NO₃)₂. However, the problem states that we have an excess of K₃PO₄, which means that all of the Ca(NO₃)₂ will react with the available K₃PO₄.
Therefore, the number of moles of Ca₃(PO₄)₂ that will be formed is equal to the number of moles of Ca(NO₃)₂ used in the reaction, which is 0.02116 mol.
Hence, 0.02116 moles of Ca₃(PO₄)₂ precipitate will be formed when 52.9 mL of 0.400 M Ca(NO₃)₂ is mixed with excess K₃PO₄ in the given chemical reaction.
How many hydrogen donors does the following molecule have?
Determine the quantity of molecules in 2.00 moles of P4
What makes Hess' Law useful? Try to cite the information you provided in question #9 for this.
above is question #9
Magnesium oxide turns a white powder as a result. Magnesium creates by transferring two electrons oxygen atoms. This reaction is exothermic. Magnesium + oxygen → magnesium oxide. 2Mg + O2 → 2MgO.
What happens when magnesium ribbon burns?An illustration of a combination reaction is the burning of magnesium ribbon to produce magnesium oxide. One chemical splits into two compounds, one with a high oxidation state and the other with a low oxidation state, in a disproportionation reaction.
Burning is a form of reaction, right?The evolution of light and heat causes an exothermic chemical reaction that results in fire. Three essential components—oxygen, heat, and fuel—must all be present for such a fire to start. The kind of reaction that results in flames is referred to as a combustion reaction in chemistry.
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How many grams of H3PO4 are produced when 43.6 moles of
water react with an excess of
P40(s) → 4H3PO4(aq)
a. 2850
b. 5.34
c. 158
d. 6410
Answer is closest to option (a) 2850 g. The mole is a fundamental concept in chemistry and is used extensively in calculations involving chemical reactions and stoichiometry.
What is Mole?
The mole is used to convert between the mass of a substance and the number of particles it contains. For example, the molar mass of a substance (the mass of one mole of that substance) can be used to convert the mass of a sample to the number of moles of that substance present.
The balanced chemical equation for the reaction is:
P4O10(s) + 6H2O(l) → 4H3PO4(aq)
From the equation, we can see that for every 6 moles of water that react, 4 moles of H3PO4 are produced.
So, to calculate the moles of H3PO4 produced, we first need to calculate the moles of water that react. The question states that 43.6 moles of water react, so we can use this value to calculate the moles of H3PO4 produced:
moles of H3PO4 = (4/6) x 43.6 = 29.07 moles
Finally, we can use the molar mass of H3PO4 to convert moles to grams:
grams of H3PO4 = moles of H3PO4 x molar mass of H3PO4
= 29.07 moles x 98 g/mol
= 2848.86 g
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PLEASE HELP ASAP LAB QUESTIONS
Experiment 1 Procedure:
1. Measure 50.0 mL of water (tap) into a 100 mL graduated cylinder and pour it into a large coffee cup.
2. Determine the temperature of this water
3. Measure out 2.00 g of sodium hydroxide into a piece of paper towel *tare scale!
4. Add the sodium hydroxide to the water in the coffee cup and put a small cup over it, with the thermometer through the hole. Stir GENTLY with the thermometer and record the temperature every 30 seconds for 3 minutes or until it peaks. Record this in a properly labelled table.
5. Let this stand for 45 minutes before proceeding to Exp. 2.
sodium hydroxide and water lab
PURPOSE OF EXPERIMENT: To find Heat of Solution of sodium hydroxide and to find the heat of neutralization between sodium hydroxide and hydrochloric acid.
EXPERIMENT 1 WHAT WE FOUND:
WHAT WE FOUND IN EXP 1:
T (temp.) initial = 20 degrees C
T (temp) FINAL = 28.5 degrees C
moles of sodium hydroxide = 0.0518mol
the molar mass of sodium hydroxide = 39.969g/mol
C (specific heat of water) = 4.184J/g degrees C
THE NUMBER OF TRIALS FOR TEMP IN EXP 1
1st trial = 21 C
2nd trial = 24.5 C
3rd trial = 26 C
4th trial = 26 C
5th trial = 28 C
6th trial = 28.5 C
7th trial = 28.5 C (final temp)
ANALYSIS FOR EXPERIMENT ONE:
1. Determine the moles of sodium hydroxide (NaOH) from the experiment.
2. Determine Qsurroundings and Qrxn
3. Determine the enthalpy for the dissociation of sodium hydroxide (delta H sol)
4. Write the thermochemical equation for the dissociation of sodium hydroxide TWO ways and write an enthalpy diagram
5. What assumptions did you make to calculate #2? (some example assumptions to make: assume that the solution is water and that heat and density COULD be the same as water, etc)
6. Research the actual value and determine the percent error
7. In terms of bonds breaking and forming, what is RESPONSIBLE FOR ENTHALPY CHANGE?
Answer:
Explanation:
The moles of sodium hydroxide (NaOH) from the experiment is 0.0518 mol.
Qsurroundings = -Qrxn, so Qsurroundings = -(m x C x ΔT) = - (50.0 g x 4.184 J/g°C x (28.5°C - 20.0°C)) = - 3464.96 J; Qrxn = -Qsurroundings = 3464.96 J
ΔHsol = Qrxn / moles of NaOH = 3464.96 J / 0.0518 mol = -66,871.12 J/mol or -66.87 kJ/mol
The thermochemical equation for the dissociation of sodium hydroxide:
2NaOH(s) → 2Na+(aq) + 2OH-(aq) + heat
or
NaOH(s) → Na+(aq) + OH-(aq) + heat
The enthalpy diagram shows an energy input (endothermic) for the dissociation of NaOH.
Some assumptions made to calculate #2 include assuming the specific heat capacity of water is the same as the specific heat capacity of the NaOH solution and that the density of the solution is the same as water.
The actual value of ΔHsol for NaOH is -44.51 kJ/mol, so the percent error is:
|(-44.51 kJ/mol - (-66.87 kJ/mol)) / -44.51 kJ/mol| x 100% = 50.21%
The breaking and forming of chemical bonds are responsible for the enthalpy change. In the case of the dissociation of NaOH, the bond between the Na and OH groups is broken, which requires an input of energy, making the process endothermic.
From the experiment, the moles of sodium hydroxide (NaOH) is found to be 0.0518 mol.
What is Moles?
In chemistry, a mole is a unit used to measure the amount of a substance, typically atoms or molecules. One mole of a substance is defined as the amount of that substance which contains the same number of particles (atoms, molecules, or ions) as there are in exactly 12 grams of carbon-12
In the experiment described, 2.00 grams of sodium hydroxide (NaOH) was added to 50.0 mL of water in a coffee cup. The temperature of the water was measured before adding the NaOH and recorded as the initial temperature (T initial). The NaOH was then added to the water and the mixture was stirred gently with a thermometer, while the temperature was recorded every 30 seconds for 3 minutes or until it peaked. The highest temperature reached during this time was recorded as the final temperature (T final).
Using the formula Q = mCΔT, where Q is the amount of heat transferred, m is the mass of the water, C is the specific heat of water, and ΔT is the change in temperature, the amount of heat released or absorbed by the NaOH and water mixture can be calculated.
Since the reaction between NaOH and water is an exothermic reaction, the heat released by the reaction is equal to the heat absorbed by the water.
From the moles of NaOH added and its molar mass, the mass of NaOH can be calculated.
Then, the heat of solution can be calculated using the formula:
Heat of solution = Q / moles of NaOH
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A car accelerates from 15 m/s to 30 m/s with an acceleration of 5m/s/s how long did this take?
The car took 3 seconds to accelerate from 15 m/s to 30 m/s with an acceleration of 5 m/s^2.
To find how long did this take?
We can use the following kinematic equation to solve this problem:
v = u + at
Where
v is the final velocityu is the initial velocitya is the acceleration t is the time takenGiven:
u = 15 m/s (initial velocity)
v = 30 m/s (final velocity)
a = 5 m/s^2 (acceleration)
Substituting the given values into the equation, we get:
30 m/s = 15 m/s + 5 m/s^2 × t
Simplifying and solving for t, we get:
5 m/s^2 × t = 15 m/s
t = 15 m/s ÷ 5 m/s^2 = 3 seconds
Therefore, the car took 3 seconds to accelerate from 15 m/s to 30 m/s with an acceleration of 5 m/s^2.
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what is percent yield if 56.9 g of WO3 yields 41.4 g of tungsten
Answer: 69.9 g
Explanation:
What happens to the potential energy of the molecules in a reaction? A. The reactants only lose potential energy when forming products. B. The potential energy of the products is equal to that of the reactants. C. The potential energy of the molecules does not change in a reaction. D. The potential energy of the molecules changes during a reaction.
Potential energy is changed into kinetic energy throughout this process, which is the heat produced during reactions. On the contrary, this happens in an endothermic process.
What happens to the molecules' potential energy during a reaction?Bonds break, new bonds form, and protons and electrons move from a structure with greater potential energy to one with lower potential energy during an exothermic reaction. Potential energy is changed into kinetic energy throughout this process.
What is a reaction's potential energy?The energy that is held inside the bonds and phases of the reactants and products is measured by potential energy. The internal energy includes this potential energy. The internal energy of chemical reactions, also known as enthalpy, stands in for the system's total energy.
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Nuclear reactions
A. Involve electrons
B. Can form compounds
C. Can form different elements
D. Depend on chemical combination
Answer: C
Explanation:
Nuclear reactions involve a change in an atom's nucleus, usually producing a different element. Chemical reactions, on the other hand, involve only a rearrangement of electrons and do not involve changes in the nuclei.
How is the outer layer of earth different from the outer layer of Neptune
With a radius of 15,299.4 miles (24,622 kilometers), Neptune is about 4 times wider than Earth. If Earth have been the size of a nickel, Neptune would be about as big as a baseball.
From an common distance of 2.8 billion miles (4.5 billion kilometers), Neptune is 30 astronomical units away from the Sun.
What is the outermost layer of Neptune?Image end result for How is the outer layer of earth one-of-a-kind from the outer layer of Neptune
The outermost layer of Neptune is the atmosphere, forming about 5-10% of the planet's mass, and extending up to 20% of the way down to its core.
What are the three differences between Neptune and Earth?Image end result for How is the outer layer of earth distinct from the outer layer of Neptune
The extent of Neptune is 6.3 x 1013 km3. You could healthy fifty seven Earths inner Neptune and nevertheless have room to spare. A day on Earth is 24 hours, but a day on Neptune is 16 hours and 6 minutes. A yr on Earth is, um, 1 12 months obviously, whilst a year on Neptune is 164.79 years.
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