Use the properties of limits to help decide whether the limit exists. If the limit exists, find its value. x? lim -9 X-3 X+3 Simplify the rational expression. x²-9 x+3 Evaluate the limit or determine that it does not exist. Select the correct choice below and, if necessary, fill in the answer box within your choice. ОА, 9 lim X-3X+3 (Simplify your answer.) B. The limit does not exist and is neither co nor - 00.

The containment area is shrinking at a rate of 280π m²/min when the diameter is 80m and the radius is decreasing at a constant rate of 7m/min.

Let's begin by first finding the radius of the containment area when its diameter is 80m.

The diameter of the containment area is 80m, so its radius is half of that:

[tex]r = 80m / 2 = 40m[/tex]

Now, we need to find the rate at which the containment area is shrinking when the radius is decreasing at a constant rate of 7m/min.

We can use the chain rule of differentiation to find this rate:

[tex]dA/dt = dA/dr * dr/dt[/tex]

where A is the area of the containment, t is time, r is the radius of the containment, and dA/dt and dr/dt are the rates of change of A and r with respect to time, respectively.

We know that dr/dt = -7 m/min (negative because the radius is decreasing), and we can find dA/dr by differentiating the formula for the area of a circle with respect to r:

A = π[tex]r^2[/tex]

[tex]dA/dr = 2πr[/tex]

So, when r = 40m, we have:

[tex]dA/dt = dA/dr * dr/dt[/tex]

= (2πr) * (-7)

= -280π [tex]m^2[/tex]/min

Therefore, the containment area is shrinking at a rate of 280π m^2/min when the radius is decreasing at a constant rate of 7m/min and the diameter of the containment area is 80m.

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Answer:

1email is given by its boss and another email is given by its assistent

Answer:

[tex] \sqrt{125 {p}^{2} } = p \sqrt{25} \sqrt{5} = 5p \sqrt{5} [/tex]

D is the correct answer.

To find the volume of the cone, we first need to find its radius. Since the pyramid is contained within the cone such that the vertices of the base of the pyramid are touching the edge of the cone, the diagonal of the square base of the pyramid is equal to the diameter of the base of the cone. The diagonal of the square base of the pyramid is:

d = √(10^2 + 10^2) = √200 = 10√2 cm

Therefore, the diameter of the base of the cone is 10√2 cm, and the radius is 5√2 cm.

The volume of the cone can be calculated using the formula:

V = (1/3)πr^2h

where r is the radius of the base of the cone and h is the height of the cone.

Substituting the given values, we get:

V = (1/3)π(5√2)^2(20)

V = (1/3)π(50)(20)

V = (1/3)(1000π)

V = 1000/3 * π

Using 3.14 as the decimal approximation for π, we get:

V ≈ 1046.35 cubic centimeters

Therefore, the volume of the cone is approximately 1046.35 cubic centimeters. The answer is A.

The height of the trapezoid is 9 yards. Therefore, the correct answer is option b. 9 yd.

To find the height of the trapezoid with the given area and base lengths, we will use the formula for the area of a trapezoid:

Area = (1/2) * (base1 + base2) * height

Here, the area is given as 126 square yards, base1 is 17 yards, and base2 is 11 yards. We need to find the height.

1. Substitute the given values into the formula:

126 = (1/2) * (17 + 11) * height

2. Simplify the equation:

126 = (1/2) * 28 * height

3. To isolate the height, divide both sides by (1/2) * 28:

height = 126 / ((1/2) * 28)

4. Calculate the result:

height = 126 / 14

height = 9

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The derivative of the function f(x) = (x³ - 5x)(2x-1) after simplification is 6x⁴ - 10x³ - 10x².

We apply the product rule and simplify to determine the derivative of,

f(x) = (x³ - 5x)(2x-1).

The product rule is used to determine the derivative of the given function f(x),

h(x) = a.b, then after applying product rule,

h'(x) = (a)(d/dx)(b) + (b)(d/dx)(a).

Applying this for function f,

f'(x) = 6x⁴ - 25x² - 10x³ + 15x²

f'(x) = 6x⁴ - 10x³ - 10x².

Therefore, f'(x) = 6x⁴ - 10x³ - 10x² is the derivative of f(x) after simplifying the function.

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The solutions for the cube function are x=64 or x= -64.

The main power rules are presented below.

The question gives the equation [tex]x^{2/3}[/tex]=16, you can rewrite it as: [tex]\sqrt[3]{x^2}[/tex]=16.

For eliminating the cubic root, you should apply the power 3 ib both sides. See:

[tex](\sqrt[3]{x^2})^3[/tex]= 16³

x²= 4096

Finally, you have x=64 or x=-64

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Answer:

Another vehicle has a mass of 1290 kg and uses diesel fuel. 1 L of petrol has a mass of 737 g. 1L of diesel has a mass of 820g.

Part A:

The definition provided for a circle is actually correct. However, if we change the definition slightly to say that a circle is the set of all points in a plane that are the same distance from a given point, we can find an example that contradicts it.

For instance, consider a cone in three-dimensional space. If we take a cross-section of the cone that is parallel to the base, we get a circle. However, this circle is not the set of all points that are the same distance from one given point, but rather from the axis of the cone.

To make the definition more accurate, we need to specify that the circle exists in a plane.

Part B:

An example of an undefined term related to a circle is the term "point." A circle is defined as the set of all points that are the same distance from a given point, but the term "point" is not defined within this definition.

A point is typically defined as a location in space that has no size or shape. In the context of a circle, a point can be thought of as any location on the circumference of the circle. However, it is important to note that the definition of a point is not dependent on the definition of a circle, and vice versa.

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Answer:

b=18.7

Step-by-step explanation:

sin112°/37=sin28°/b

b=sin28°/(sin112°/37)

b=18.7

The speed of Fred's snowmobile was 30 miles per hour.

This is calculated by dividing the distance traveled by the time taken for each journey, which gives a speed of 30 mph for both the outward and return journeys.

To find Fred's speed, we can use the formula speed = distance/time. We know that Fred traveled a distance of 360 miles in 12 hours on the outward journey, so his speed was 360/12 = 30 mph.

Similarly, on the return journey, he traveled the same distance of 360 miles, but it took him 15 hours, so his speed was again 360/15 = 24 mph.

However, we are asked to find his constant speed, so we take the average of the two speeds, which gives us (30 + 24)/2 = 27 mph. Therefore, Fred's snowmobile was traveling at a constant speed of 30 mph on both journeys.

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False. Cultural traits that are diffused from one group are not always changed or adopted over time by the people in the receiving culture.

This is because different cultures have their own unique values, beliefs, and practices that may not align with the diffused cultural trait. Additionally, some cultural traits may be seen as a threat to the receiving culture and therefore not adopted.
Moreover, not all diffused elements of culture are successfully integrated into other cultures. Some may be rejected outright, while others may only be partially integrated or adapted to fit the receiving culture. It's important to note that cultural diffusion is a complex and ongoing process that involves a multitude of factors, including social, economic, and political influences, as well as individual attitudes and beliefs.

Therefore, the success of cultural diffusion and integration can vary greatly from one context to another.

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If 1/6 of the boys joined the basketball team, there are 160 boys in the soccer team.

If 1/6 of the boys joined the basketball team, then 5/6 of the boys did not join the basketball team. Similarly, if 2/9 of the boys joined the soccer team, then 7/9 of the boys did not join the soccer team.

Let's first find out how many boys did not join the soccer team:

7/9 x 540 = 380

Therefore, 380 boys did not join the soccer team.

To find out how many boys did join the soccer team, we can subtract the boys who did not join from the total number of boys:

540 - 380 = 160

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Applying the triangle inequality theorem, the possible length of side AC is: C. 18 inches.

The triangle inequality theorem states that lengths of the two sides of a triangle, when added together must be greater than the third side of any given triangle.

Therefore, to determine the possible length of side AC, we can use the triangle inequality theorem, stated above and applying this to triangle ABC, we have the following:

AC < AB + BC

AC < 12 + 20

AC < 32

This implies that, length of side AC must be less than 32 inches. Thus, the answer is: C. 18 inches.

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The equation would be: y = 3 + x

To include the terms you mentioned, we can set up an equation to represent the relationship between the number of weeks Stacy volunteers (x) and the number of cards she has (y).

Since Stacy starts with 3 collector's cards and receives 1 more card each week she volunteers, the equation would be:

y = 3 + x

In this equation, x represents the number of weeks Stacy volunteers, and y represents the total number of collector's cards she has.

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Answer: 2100 square feet

Step-by-step explanation:

To solve this question we must add the areas of the two rectangles.

area = length x width

Rect 1:

a = lw

  = 80 x 15 = 1200 square feet

Rect 2:

a = lw

  = 30 x 30 = 900 square feet

so in total, the driveway is 1200 + 900 = 2100 square feet

Answer:

To find the area of the driveway, we need to find the area of both rectangles and add them together.

The area of the first rectangle is:

80 ft x 15 ft = 1200 sq ft

The area of the second rectangle is:

30 ft x 30 ft = 900 sq ft

To find the total area of the driveway, we add the two areas together:

1200 sq ft + 900 sq ft = 2100 sq ft

Therefore, the area of the driveway is 2100 square feet.

The probability of choosing randomly with replacement an H or P in either selection is derived to be equal to 0.16 which makes the last option correct.

The probability of an event occurring is the fraction of the number of required outcome divided by the total number of possible outcomes.

The total possible outcome = 5

the event of selecting H = 1

probability of selecting H= 1/5

the event of selecting P = 2

probability of selecting H= 2/5

probability of choosing an H or P in either selection = 1/5 × 2/5 + 2/5 × 1/5

probability of choosing an H or P in either selection = 4/25

probability of choosing an H or P in either selection = 0.16

Therefore, the probability of choosing randomly with replacement an H or P in either selection is derived to be equal to 0.16

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The solution to the problems are given below:

Giving each of the letters numbers based on their numerical position on the English alphabet, we can solve below:

n (14) + e (5) = 14 + 5 = 19

t (20) - j (10) = 20 - 10 = 10

d (4) x e (5) = 4 x 5 = 20

p (16) / b (2) = 16 / 2 = 8

It can be seen that with the letter e for example is the 5th letter of the alphabet and the value is used to compute the addition of the problem.

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The particular solution is [tex]y(t) = (1/2c) (t^2/2 + t/2 + 1/2c) + (2 - 1/(4c))e^(-2ct)[/tex].

[tex]dy/dt + 2cy = t^2 + 1[/tex]

To find the general solution of this differential equation, we can start by finding the integrating factor, which is given by:

I(t) = e^(∫2c dt) = [tex]e^(2ct)[/tex]

Next, we can multiply both sides of the differential equation by the integrating factor I(t):

[tex]e^(2ct) dy/dt + 2ce^(2ct) y = (t^2 + 1) e^(2ct)[/tex]

We can now recognize the left-hand side as the product rule of the derivative of the product of y and I(t):

[tex](d/dt)(y e^(2ct)) = (t^2 + 1) e^(2ct)[/tex]

Integrating both sides with respect to t gives:

[tex]y e^(2ct) = ∫(t^2 + 1) e^(2ct) dt + C[/tex]

The integral on the right-hand side can be solved using integration by parts, and we get:

∫([tex]t^2[/tex] + 1) [tex]e^(2ct) dt = (1/2c) e^(2ct) (t^2/2 + t/2 + 1/2c) + K[/tex]

where K is an arbitrary constant of integration.

Substituting this expression back into the previous equation, we get:

[tex]y e^(2ct) = (1/2c) e^(2ct) (t^2/2 + t/2 + 1/2c) + K[/tex]

Dividing both sides by e^(2ct), we obtain the general solution:

[tex]y(t) = (1/2c) (t^2/2 + t/2 + 1/2c) + Ke^(-2ct)[/tex]

where K is an arbitrary constant.

To find the particular solution that satisfies y(0) = 2, we can substitute t = 0 and y(0) = 2 into the general solution and solve for K:

[tex]y(0) = (1/2c) (0^2/2 + 0/2 + 1/2c) + Ke^(0)[/tex]

2 = 1/(4c) + K

Solving for K, we get:

K = 2 - 1/(4c)

Substituting this value of K back into the general solution, we get the particular solution:

[tex]y(t) = (1/2c) (t^2/2 + t/2 + 1/2c) + (2 - 1/(4c))e^(-2ct)[/tex]

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The length of chord segment EG = 6 inches and the length of FG = √23 inches.

Given, chord EG = 8 inches and the distance from the center of J to the chord is 3 inches.

We can draw a diagram as follows:

              J

            /   \

           /     \

          /       \

         /         \

        E-----------G

              |

              |

              |

              |

              |

              F

Here, OJ is perpendicular to chord EG at point F.

As per the theorem, the length of the perpendicular from the center of the circle to a chord is half the length of the diameter intersecting the chord.

So, we can find the length of the diameter intersecting chord EG and then use it to find the radius of the circle.

Length of chord EG = 8 inches

Length of OJ = 3 inches

Using Pythagorean theorem in right triangle OFG, we get:

OG² = OF² + FG²

Let x be the length of FG

We know that OF = OJ = 3 inches

OG = radius of the circle

So, we have:

radius of circle = OG = √(OF² + FG²) = √(3² + x²)

The diameter of the circle = 2(radius) = 2√(3² + x²)

Now, using the theorem mentioned above, we can say:

Length of perpendicular from the center of the circle to chord EG = OF = 3 inches

Length of diameter intersecting chord EG = 2√(3² + x²)

So, we get:

Length of chord segment EG = 2 * length of perpendicular

                            = 2 * 3 inches

                           = 6 inches

Now, we know that the chord segment EG divides the diameter intersecting it into two equal parts.

So, we have:

Length of one part of the diameter = (2√(3² + x²))/2 = √(3² + x²)

Using Pythagorean theorem in right triangle OJF, we get:

OJ² + JF² = OF²

3² + JF² = 8²

JF² = 8² - 3² = 55

JF = √55

Using Pythagorean theorem in right triangle JFG, we get:

JG² + FG² = JF²

(√(3² + x²))² + x² = 55

9 + x² + x² = 55

2x² = 46

x² = 23

x = √23

Therefore, the length of chord segment EG = 6 inches and the length of FG = √23 inches.

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The value of (f + g)(−3) given the functions f(x) = x² − 6x − 4 and g(x) = 5x + 3 is 11.

To find (f + g)(-3), we first need to add the functions f(x) and g(x) together, and then evaluate the resulting function at x = -3.

f(x) = x² - 6x - 4
g(x) = 5x + 3

Now, let's add f(x) and g(x):

(f + g)(x) = (x² - 6x - 4) + (5x + 3) = x² - x - 1

Now that we have the combined function, we can evaluate it at x = -3:

(f + g)(-3) = (-3)² - (-3) - 1 = 9 + 3 - 1 = 11

So, (f + g)(-3) = 11.

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The volume of the sphere that lies between the two cones is approximately 43.53 cubic units.

To find the volume of the sphere that lies between the given cones, we first need to determine the limits of integration.

Since the sphere has a radius of 6 (since x² + y² + z² = 36), we can use spherical coordinates to express the volume as an integral. Let's first consider the cone z = √3x² + 3y².

In spherical coordinates, this is equivalent to z = ρcos(φ)√3, where ρ is the radial distance and φ is the angle between the positive z-axis and the line connecting the origin to the point.

Similarly, the cone z = √(x²+y²)/3 can be expressed in spherical coordinates as z = ρcos(φ)/√3.

Since we're only interested in the volume of the sphere between these cones, we can integrate over the limits of ρ and φ that satisfy both inequalities.

The limits of ρ will be 0 (the origin) to 6 (the radius of the sphere).

To find the limits of φ, we need to solve for the intersection points of the two cones.

Setting the two equations equal to each other, we get:

ρcos(φ)√3 = ρcos(φ)/√3

Solving for φ, we get:

tan(φ) = 1/√3 Using the inverse tangent function, we find that: φ = π/6, 7π/6

So the limits of integration for φ will be π/6 to 7π/6.

Finally, we need to integrate over the full range of θ (the angle between the positive x-axis and the line connecting the origin to the point).

This will be 0 to 2π.

Putting it all together, the volume of the sphere between the two cones is:

∫∫∫ ρ^2sin(φ) dρ dφ dθ

With limits of integration:

0 ≤ ρ ≤ 6 π/6 ≤ φ ≤ 7π/6 0 ≤ θ ≤ 2π

Evaluating this integral gives:

V = 288π/5 - 216√3π/5

So the volume of the sphere that lies between the two cones is approximately 43.53 cubic units.

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The two values of k that satisfy the given equation are approximately 0.1449/t and 1.096/t.

We have the partial differential equation uₜ = 4uₓₓ. Substituting u(x,t) = e¯³ᵗsin(kt) into this equation, we get:

uₜ = e¯³ᵗ(k cos(kt) - 3k sin(kt))

uₓₓ = e¯³ᵗ(-k² sin(kt))

Now, we can compute uₓₓ and uₜ and substitute these expressions back into the partial differential equation:

uₜ = 4uₓₓ

e¯³ᵗ(k cos(kt) - 3k sin(kt)) = -4k²e¯³ᵗ sin(kt)

Dividing both sides by e¯³ᵗ and sin(kt), we get:

k cos(kt) - 3k sin(kt) = -4k²

Dividing both sides by k and simplifying, we get:

tan(kt) - 1 = -4k

Letting z = kt, we can write this equation as:

tan(z) = 4z + 1

We can graph y = tan(z) and y = 4z + 1 and find their intersection points to find the values of z (and therefore k) that satisfy the equation. The first intersection point is approximately z = 0.1449, which corresponds to k ≈ 0.1449/t. The second intersection point is approximately z = 1.096, which corresponds to k ≈ 1.096/t. Therefore, the two values of k that satisfy the given equation are approximately 0.1449/t and 1.096/t.

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The value of the [tex]5000^{th}[/tex] term in the given arithmetic sequence K is 44995.

The sequence that is given in the question is said to be an arithmetic sequence which means the consecutive elements in the series will have common differences.

To find any term in the series first, we need to find the first term and the common difference that the series follows.

Here we know that the first and the second term of the series are 4 and 13 so from this we can find the common difference which is:

13-4=9

so the first term (a) = 4

the common difference (d) = 9

To find the [tex]n^{th}[/tex] term of the series we can use the formula:

[tex]a_n=a_1+(n-1)*d[/tex]

where [tex]a_n[/tex] is the nth term in the sequence, [tex]a_1[/tex] is the first term of the series, n is the no.of term, and d is the common difference.

So to find the 5000th term in the series

[tex]a_{5000}=4+(5000-1)*9\\a_{5000}=4+(4999*9)\\a_{5000}=4+ 44991\\a_{5000}= 44995\\[/tex]

The value of the [tex]5000^{th}[/tex] term is 44995

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The value of FE comes out to be 35.

An angle is a geometric figure formed by two rays or line segments that share a common endpoint, called the vertex. The measure of an angle is typically given in degrees or radians, and it describes the amount of rotation needed to move one of the rays or line segments to coincide with the other. Angles are used in many areas of mathematics, physics, engineering, and other sciences to describe and analyze various phenomena.

Parallel lines have the same slope and will never meet, no matter how far they are extended. Parallel lines are important in geometry and other areas of mathematics, as well as in engineering, architecture, and other fields where precise measurements and constructions are required.

[tex]4x-1/x+5 = 60/24\\5x+25= 8x-2\\27= 3x\\x=9[/tex]

Therefore FE= 4×(9)-1

=35

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To maximize the total weight of bass in the lake, we should stock 3000 smallmouth bass and 4666.67 largemouth bass

To maximize the total weight of bass in the lake, we need to find the optimal values of and that will maximize the total weight of the fish.

Let's start by writing an expression for the total weight of the fish in the lake:

Total weight = (weight of a single smallmouth bass) × (number of smallmouth bass) + (weight of a single largemouth bass) × (number of largemouth bass)

Substituting the given expressions for the weight of a single smallmouth bass and largemouth bass, we get:

Total weight = (0.5 + 0.1) × × + (1.2 + 0.2) ×

Simplifying this expression, we get:

Total weight = (0.6) × × + (1.4) ×

To find the optimal values of and that maximize the total weight, we can take the partial derivatives of this expression with respect to and and set them equal to zero:

[tex]∂ \frac{(Total weight)}{∂} = 0.6-0.0002=0[/tex]

[tex]∂ \frac{(Total weight)}{∂} = 1.4-0.0003=0[/tex]

Solving these equations simultaneously, we get:

= 3000

= 4666.67

Therefore, to maximize the total weight of bass in the lake, we should stock 3000 smallmouth bass and 4666.67 largemouth bass.

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The walls of the archway are approximately 8.9 apart.

To find the distance between the walls of the archway, we need to find the horizontal distance where the function f(x) intersects the x-axis. This is because the archway's walls are vertical, and their distance apart is the same as the horizontal distance between the points where the archway meets them.

To find the x-intercepts of the function f(x) = -0.5x^2 + 10, we need to set f(x) = 0 and solve for x:

0 = -0.5x^2 + 10

0.5x^2 = 10

x^2 = 20

x = ±√20

Since the archway is a physical object, we can discard the negative value for x, which means the archway meets the walls at x = √20 feet.

To find the distance between the walls of the archway, we can double this value:

2√20 ≈ 8.94

Then it's concluded that the walls of the archway are approximately 8.9 feet apart.

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