Using dimensional analysis How many mg are there in 8.75 X 107 kilograms?
Conversion factors:
[1000 g = 1 Kg]
[1000 mg = 1 g]
Can you please show the work

Using Dimensional Analysis How Many Mg Are There In 8.75 X 107 Kilograms?Conversion Factors:[1000 G =

Answers

Answer 1

Answer:

8.75×10¹³ mg

Explanation:

From the question given above, we obtained:

Mass (in Kg) = 8.75×10⁷ Kg

Mass (in mg) =?

Next, we shall convert 8.75×10⁷ Kg to grams (g). This can be obtained as follow:

1 Kg = 1000 g

Therefore,

8.75×10⁷ Kg = 8.75×10⁷ Kg × 1000 g/1 kg

8.75×10⁷ Kg = 8.75×10¹⁰ g

Therefore, 8.75×10⁷ Kg is equivalent to 8.75×10¹⁰ g.

Finally, we shall convert 8.75×10¹⁰ g to mg. This can be obtained as illustrated below:

1 g = 1000 mg

Therefore,

8.75×10¹⁰ g = 8.75×10¹⁰ g × 1000 mg/ 1 g

8.75×10¹⁰ g = 8.75×10¹³ mg

Thus, 8.75×10⁷ Kg is equivalent to 8.75×10¹³ mg.


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Answers

Answer:

sulfur

hydrogen

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oxygen

strontium

Explanation:

An atom gets larger as the number of electronic shells increase; therefore the radius of atoms increases as you go down a certain group in the periodic table of elements.

In general, the size of an atom will decrease as you move from left to the right of a certain period.

Order of increasing atomic radius:

O < H < S < I < Sr

Describe the trend of atomic radius.

The atomic radius measures the separation between an atom's nucleus and its farthest electrons.

The trend across a periodAtoms' atomic radii typically decrease from left to right.As electrons are added to the same primary energy level, protons are gradually added to the nucleus. Because of the increased positive charge on the nucleus, these electrons are gradually drawn closer to it. Atomic sizes shrink as the strength of attraction between nuclei and electrons grows.

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The molar absorptivity of a compound at 500 nm wavelength is 252 M-1cm-1. Suppose one prepares a solution by dissolving 0.00140 moles of a solute in enough water to make a 500.0 mL solution. What would be the absorbance in a 3 .00 mm pathlength cell?

Answers

Answer:

The absorbance of the solution is 0.21168.

Explanation:

Given that,

Wavelength = 500 nm

Molar absorptivity = 252 M⁻¹ cm⁻¹

Number of moles = 0.00140

Volume of solution = 500.0 mL

Length = 3.00 mm

We need to calculate the molar concentration

Using formula of the molar concentration

[tex]C=\dfrac{N}{V}[/tex]

Where, N = number of moles

V = volume

Put the value into the formula

[tex]C=\dfrac{0.00140}{0.5000}[/tex]

[tex]C=0.0028\ M[/tex]

We need to calculate the absorbance of the solution

Using formula of absorbance

[tex]A=\epsilon C l[/tex]

Put the value into the formula

[tex]A=252\times0.0028\times0.300[/tex]

[tex]A=0.21168[/tex]

Hence, The absorbance of the solution is 0.21168.

The absorbance of a compound, with a molar absorptivity at 500 nm wavelength of 252 M⁻¹ cm⁻¹, prepared by dissolving 0.00140 moles of a solute in enough water to make a 500.0 mL solution, measured in a 3 .00 mm pathlength cell, is 0.212.

First, we will calculate the molarity of the compound, which is equal to the moles of solute divided by the liters of solution.

[tex]M = \frac{0.00140mol}{0.5000L} = 0.00280 M[/tex]

Then, we will convert 3.00 mm to cm using the conversion factor 1 cm = 10 mm.

[tex]3.00 mm \times \frac{1cm}{10mm} = 0.300 cm[/tex]

Finally, we will calculate the absorbance of the compound using the Beer–Lambert equation.

[tex]A = \epsilon \times b \times C[/tex]

where,

A: absorbanceε: molar absorptivityb: length of light pathC: molar concentration

[tex]A = \epsilon \times b \times C = \frac{252}{M.cm} \times 0.300 cm \times 0.00280 M = 0.212[/tex]

The absorbance of a compound, with a molar absorptivity at 500 nm wavelength of 252 M⁻¹ cm⁻¹, prepared by dissolving 0.00140 moles of a solute in enough water to make a 500.0 mL solution, measured in a 3 .00 mm pathlength cell, is 0.212.

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Jejsjsnxnnsnsbdbbdbdbd

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Answers

Answer:

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Explanation:

The density of a substance can be found by using the formula

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From the question

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Answers

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