Verena sleeps from 11 p.m. until 9a.m. What fraction of a day does Verena sleep? *​

Answer:

ND>MA n type in both 300k and 700k as ND and NA are not affected by rempredure, only NI is affected and it increases the electron and helps with the sane value so always electrons will be greater than holes at T= 300k Ni = 10 10 cm 3

Therefore , the solution of the given problem of perimeter comes out to be the perimeter is represented by the expression of Perimeter = 30 -6x.

In geometry, a shape's perimeter, or overall length, is referred to as its perimeter. The lengths of all a shape's sides and edges are added up to determine its perimeter.

Here,

Given :  length = 5 - 1(x) or

=> length = 5-x

Width is twice the length

thus,

=>Width = 2(5-x)

=>Width = 10-2x

So ,To find the perimeter

We use,

=> Perimeter = 2(length + width)

=> Perimeter = 2( 5-x + 10-2x )

=>  Perimeter = 2( 15 -3x)

=>   Perimeter = 30 -6x

Therefore , the solution of the given problem of perimeter comes out to be the perimeter is represented by the expression of Perimeter = 30 -6x.

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The population of US is 330 million approx.

A percentage is a figure or ratio that can be stated as a fraction of 100. If we need to calculate the percentage of a number, we must divide it by its full value and then multiply it by 100. As a result, the percentage is one part in one hundred. "Per 100" is short for "per percent." The number "%" is used to symbolize it.

Given

population of new york = 2.727272% population of US

population of new york = 9 million

population of US = 1/2.727272% of new york

population of US =  36.6666 x 90,00,000

population of US = 33,00,00,087.9 = 330 million approx

Hence population of US is approx 330 million.

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Answer:

The null hypothesis is [tex]H_0: \mu = 99[/tex]

The alternate hypothesis is [tex]H_a: \mu > 99[/tex]

The test statistic is [tex]z = 0.31[/tex]

The pvalue of the test is 0.3783 > 0.05, which meas that the results are not significant at the 5% level.

Step-by-step explanation:

It is believed that the average amount of money spent per U.S. household per week on food is about $99. We want to test the hypothesis that the mean weekly food budget for all households in this community is higher than the national average.

At the null hypothesis, we test if the mean is the national average of 99, that is:

[tex]H_0: \mu = 99[/tex]

At the alternate hypothesis, we test if the mean is greater than the national average of 99, so:

[tex]H_a: \mu > 99[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

99 is tested at the null hypothesis:

This means that [tex]\mu = 99[/tex]

A random sample of 16 households in a certain affluent community yields a mean weekly food budget of $100. Standard deviation of $13.

This means that [tex]n = 16, X = 100, \sigma = 13[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{100 - 99}{\frac{13}{\sqrt{16}}}[/tex]

[tex]z = 0.31[/tex]

The test statistic is [tex]z = 0.31[/tex].

Determine if the results significant at the 5% level.

The pvalue of the test is the probability of finding a sample mean above 100, which is 1 subtracted by the pvalue of z = 0.31.

Looking at the ztable, z = 0.31 has a pvalue of 0.6217

1 - 0.6217 = 0.3783

The pvalue of the test is 0.3783 > 0.05, which meas that the results are not significant at the 5% level.

Answer:

minimum: 6500

maximum: 18500

Hope this helps

GLL

Step-by-step explanation:

Answer:

Correct answer is below

Step-by-step explanation:

The method illustrated in this example is not a simple random sampling method. Instead, it is a two-stage cluster sampling method.

It is not always possible to interview or survey an entire population. Therefore, in many research studies, a portion of the population that is expected to represent the population is drawn and surveyed instead. The portion that is drawn is called the sample, and the method used to draw the sample is called the sampling method. Broadly, there are two types of sampling methods. The probability sampling method is a method wherein all members of the population have an equal probability to be selected to be included in the sample. The non-probability sampling method is a method wherein not all members of the population have an equal probability to be selected to be included in the sample. Instead, members are recruited into the sample based on the researcher's subjective and personal judgment.

Simple Random Sampling Method:

Simple random sampling method, sometimes abbreviated as SRS, is the purest form of probability sampling. Figuratively, it is like putting the names of the entire population in a hat and drawing each member from the hat with a blindfold. Therefore, every member of the population has an equal chance of being included in the sample.

Two-stage Cluster Sampling Method:

In the first stage of a two-stage cluster sampling method, the population is first divided into subgroups called clusters. For instance, the population is divided into subgroups based on geographic location. Unlike strata in stratified sampling, clusters are heterogeneous and each cluster is supposed to represent the heterogeneity of the population. These clusters are also known as primary sampling units or PSUs. In the second stage, the simple random sampling method is used to draw individuals from each of the PSUs to be included in the study sample.

Hence, The method illustrated in this example is not a simple random sampling method. Instead, it is a two-stage cluster sampling method.

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Answer:

[tex]\displaystyle 1\frac{1}{4}\pi[/tex]

Step-by-step explanation:

[tex]\displaystyle \boxed{y = 4cos\:(1\frac{3}{5}x - 1\frac{3}{10}\pi)} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{13}{16}\pi} \hookrightarrow \frac{1\frac{3}{10}\pi}{1\frac{3}{5}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{-\frac{3}{4}\pi} \hookrightarrow \frac{2}{1\frac{3}{5}}\pi \\ Amplitude \hookrightarrow 4[/tex]

OR

[tex]\displaystyle \boxed{y = 4sin\:(1\frac{3}{5}x + 1\frac{1}{5}\pi)} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{3}{4}} \hookrightarrow \frac{-1\frac{1}{5}\pi}{1\frac{3}{5}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{4}\pi} \hookrightarrow \frac{2}{1\frac{3}{5}}\pi \\ Amplitude \hookrightarrow 4[/tex]

Keep in mind that although this IS a sine function, if you plan on writing your equation as a function of cosine, then by all means, go right ahead. As you can see, the photograph farthest to the right displays the trigonometric graph of [tex]\displaystyle y = 4cos\:1\frac{3}{5}x,[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph farthest to the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cosine graph [photograph farthest to the right] is shifted [tex]\displaystyle \frac{13}{16}\pi\:units[/tex]to the left, which means that in order to match the sine graph [photograph farthest to the left], we need to shift the graph FORWARD [tex]\displaystyle \frac{13}{16}\pi\:units,[/tex]which means the C-term will be positive, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\frac{13}{16}\pi} = \frac{1\frac{3}{10}\pi}{1\frac{3}{5}}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 4cos\:(1\frac{3}{5}x - 1\frac{3}{10}\pi).[/tex]Intermediate, the centre photograph displays the trigonometric graph of [tex]\displaystyle y = 4sin\:1\frac{3}{5}x.[/tex]Again, just like before, we must figure out the appropriate C-term that will make this sine graph horisontally shift and map onto the sine graph in the leftward photograph. So, between the two photographs, we can tell that the centre sine graph is shifted [tex]\displaystyle \frac{3}{4}\pi\:units[/tex]to the right, which means that in order to match the leftward sine graph, we need to shift the graph BACKWARD [tex]\displaystyle \frac{3}{4}\pi\:units,[/tex]which means the C-term will be negative, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{3}{4}\pi} = \frac{-1\frac{1}{5}\pi}{1\frac{3}{5}}.[/tex]So, the sine graph is [tex]\displaystyle y = 4sin\:(1\frac{3}{5}x + 1\frac{1}{5}\pi).[/tex]Now, the amplitude is obvious to figure out because it is the A-term. Moreover, the midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 0,[/tex]in which each crest is extended four units beyond the midline, hence, your amplitude. Now, with all that being said, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Answer:

A) an equilateral triangle with acute angles (60°)

B) isn't the lengths of a triangle

C) is a right triangle

D) is a right triangle

Step-by-step explanation:

A) 2,2,2, all sides and angles are all equal

B) applying cos rule to get the angles, an angle will be zero and a triangle can't have zero angle, thus the lengths are not that of a triangle

C) it's a right triangle as the dimensions are a pythagorean triple

D) it's a right triangle as the dimensions are a pythagorean triple

Answer:

The mean number of books to a box is 11.

Step-by-step explanation:

Given - Garth is packing boxes with books. The list shows how many books are in each of 10 boxes.

6, 14, 6, 18, 9, 9, 12, 10, 11, 15

To find - Which statement is true about the number of books packed to a box?

Solution -

Mean of number of books is equal to

= (6+ 14+ 6+ 18+ 9+ 9+ 12+ 10+ 11+ 15)/10

= 110/10

= 11

∴ we get

The mean number of books to a box is 11.

For Median -

Firstly, arrange the data into increasing order

6, 6, 9, 9, 10, 11, 12, 14, 15, 18

Now, we know that,

If total data(n) is even then median is the average of value at (n/2)th place and [(n/2 + 1]th place

Here n = 10

So,

Median is average of 10 and 11

i.e. Median = (10+11)/2

                  = 21/2 = 10.5

So,

Median number of books to a box is 10.5

∴ we get

The correct option is - The mean number of books to a box is 11.

Answer:

The mean number of books to a box is 11.

Step-by-step explanation:

Answer:

Hello, the answer is 6, C.

Step-by-step explanation:

50 percent of 12 is 6.

Answer:

0.15

Step-by-step explanation:

I just put the fraction in decimal form since there is no photo.

Answer:

x-3

Step-by-step explanation:

hope i helped, tell me if you get it right! :)

Answer:

Step-by-step explanation:

If m∠ABJ = 28 and ∠ABC ≅ ∠DBJ, then we can set up the following equation:

m∠ABC = m∠DBJ

Since angles ∠ABC and ∠DBJ are congruent, they have the same measure, so the equation above is true.

Since we are trying to find m∠JBC, we can use the fact that the measure of an angle is equal to the sum of the measures of the other two angles in the triangle to set up another equation:

m∠JBC = m∠ABC + m∠ABJ

Substituting the value for m∠ABC from the first equation into the second equation, we get:

m∠JBC = m∠DBJ + m∠ABJ

Substituting the given value of m∠ABJ into this equation, we get:

m∠JBC = m∠DBJ + 28

Since m∠ABJ = m∠DBJ, we can substitute m∠ABJ in for m∠DBJ:

m∠JBC = m∠ABJ + 28

Substituting the given value of m∠ABJ into this equation, we get:

m∠JBC = 28 + 28

Solving this equation, we find that m∠JBC = 56.

Therefore, the measure of angle ∠JBC is 56 degrees.

There is a directly proportional relationship between the weight and total cost of bag of of lemons.

The ratio connecting two given numbers in what is known as a proportional relationship is the constant of proportionality. The constant of proportionality may also be referred to as the constant ratio, constant rate, unit rate, constant of variation, or even the rate of change.

When two variables are directly or indirectly proportional to one another, their relationship may be expressed using the formulas y = kx or y = k/x, where k specifies the degree of correspondence between the two variables. The proportionality constant, k, is often used.

As an illustration, we may write y = kx, where x is the amount of gas in gallons, y is the price in dollars, and k is the proportionality constant.

Given data :

One bag weighs 2.4 pounds and cost $5.28.

Another bag weighs 2.7 pounds and cost $5.94

2.4k = 5.28

k= 2.2

2.7k = 5.94

k = 2.2

k > 1

The weight and total cost of bag of of lemons is directly proportional, so when weight of lemon increases, the cost of lemon also increases.

Therefore, there is a directly proportional relationship between the weight and total cost of bag of of lemons.

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Answer:

10

Step-by-step explanation:

Hope it helps! :D

Answer:

6

Step-by-step explanation:

1 1/2 divided by 1/4

1 2/4 divided by 1/4

6/4 divided by 1/4

How many times does 1/4 go into 6/4?

Answer:

The mean number of customers that will arrive in a five-minute period is 2.

Step-by-step explanation:

a. What is the mean or expected number of customers that will arrive in a five-minute period

For one minute, the mean is of 0.4 customers.

So, using proportions, for 5 minutes, the mean is of 5*0.4 = 2 customers.

The mean number of customers that will arrive in a five-minute period is 2.

Answer:

180 degrees counter-clockwise and 180 degrees clockwise

Step-by-step explanation:

The simplified expression is [tex]c^2 d^2 e^6 / b^8[/tex]

The given expression is [tex](a^0 b^-4 cde^3)^2[/tex]

We know that any number raised to the power of 0 is 1.

Therefore,[tex]a^0 = 1[/tex].

Also, any number raised to the power of -1 is its reciprocal.

Therefore, [tex]b^-4 = 1/b^4[/tex]

Simplifying the above expression we get

[tex](1*1/b^4 * cde^3)^2 = (cde^3/b^4)^2[/tex]

Now, we apply the rule that [tex](a^m * a^n) = a^(m+n)[/tex]

So, [tex](cde^3/b^4)^2 = c^2 d^2 e^6 / b^8)[/tex]

Hence the simplified expression is [tex]c^2 d^2 e^6 / b^8[/tex]

Please note, when an exponent is raised to another exponent, we can multiply the exponents, so [tex](a^m)^n = a^(m*n)[/tex]

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Answer:

The degrees of freedom for this problem are 21

Step-by-step explanation:

Degrees of freedom:

When testing an hypothesis involving two samples, the number of degrees of freedom is given by:

[tex]df = n_1 + n_2 - 2[/tex]

In which [tex]n_1[/tex] is the size of the first sample and [tex]n_2[/tex] is the sample of the second sample.

In this question:

Samples of 9 and 14, so [tex]n_1 = 9, n_2 = 14[/tex]

The degrees of freedom for this problem are

[tex]df = n_1 + n_2 - 2[/tex]

[tex]df = 9 + 14 - 2 = 21[/tex]

The degrees of freedom for this problem are 21

The required degree of freedom is 21.

Given that,

He randomly selects a sample of 9 lunch tickets from the city population resulting in a mean of $14.30 and a standard deviation of $3.40.

He randomly selects a sample of 14 lunch tickets from the suburban population resulting in a mean of $11.80 and a standard deviation $2.90.

He is using an alpha value of .10 to conduct this test.

We have to find,

The degrees of freedom for this problem are.

According to the question,

Degrees of freedom refers to the maximum number of logically independent values, which are values that have the freedom to vary, in the data sample.

Degrees of freedom are commonly discussed in relation to various forms of hypothesis testing in statistics, such as a chi-square.

When testing an hypothesis involving two samples, the number of degrees of freedom is given by,

[tex]Degree \ of \ freedom = n_1+n_2-2[/tex]

Where, [tex]n_1[/tex] is the size of the first sample and [tex]n_2[/tex] is the sample of the second sample.

[tex]n_1 = 9 \ and\ n_2 = 14[/tex]

Therefore,

[tex]Degree \ of \ freedom = 9+14-2\\\\Degree \ of \ freedom = 21[/tex]

Hence, The required degree of freedom is 21.

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Answer:

200 CENTIMETRES

Step-by-step explanation:

Answer:

I can't please the question is sooo hard but can you give steps

Respuesta:

23,5 milímetros

Explicación paso a paso:

Dado :

Diámetro del círculo = 47 mm

Radio del círculo = diámetro / 2

Por lo tanto, Radio = 47 mm / 2

Radio = 23,5 mm

Answer:

increase amount = 32× 4.4%

= 32 × 4.4 ÷ 100

= 32 × 44 ÷ 1000

= 1.408

32 increased by 4.4% = 32 + 1.408 = 33.408

Answer:

it is not factorable

Step-by-step explanation:

There are no factors of 24 that will make -4, so it is not factorable

Answer:

From the statements in the question, I and III is CORRECT

Step-by-step explanation:

First we take down the given data from the question for substitution;

Process mean = 16.9 ounces

Lower specification limit = 16.75 ounces

Upper specification limit = 17.05 ounces

Standard deviation = 0.04

Now, we get our Cpk;

Cpk = MINIMUM( (Upper specification limit - mean ) / 3 × Standard deviation), (mean - Lower specification limit) / 3 × Standard deviation) )

so we substitute

Cpk = MINIMUM(  ((17.05 ounces - 16.9 ounces) / 3 × 0.04 ounces ), (( 16.9 ounces - 16.75 ounces) / 3 × 0.04 ) )

Cpk = MINIMUM( 0.15 / 0.12 ), ( 0.15 / 0.12 )

Cpk = MINIMUM( 1.25, 1.25 )

Cpk = 1.25

Next the Cp;

Cp = ( Upper specification limit - Lower specification limit ) / ( 6 ×  standard deviation )

we substitute

Cp = ( 17.05 ounces - 16.75 ounces ) / ( 6 × 0.04 ounces )

Cp = 0.3 / 0.24

Cp = 1.25

Hence;

Cpk calculation is not less than Cp calculation.

Since Cp is greater than 1, the process is cable.

Since the actual process mean is also 16.90 ounces, then  the process is centered.

Therefore, From the statements in the question, I and III is CORRECT

The correct statement is "the Cp calculation indicates that the process is capable" and "the process is centered, so the Cp calculation should be used" and this can be determined by using the formula of Cpk and Cp.

GIven :

The formula of Cpk is given below:

[tex]\rm Cpk = minimum\left( \dfrac{Upper \;specification \;limit - mean}{ 3 \times Standard \;deviation)}, \dfrac{ mean - Lower\; specification\; limit} { 3 \times Standard \;deviation}\right )[/tex]

Now, substitute the known terms in the above formula.

[tex]\rm Cpk = minimum \left(\dfrac{17.05-16.9}{3\times 0.04},\dfrac{16.9-16.75}{3\times 0.04}\right)[/tex]

[tex]\rm Cpk = minimum \left(\dfrac{0.15}{0.12},\dfrac{0.15}{0.12}\right)[/tex]

Cpk = 1.25

Now, the formula of Cp is given below:

[tex]\rm Cp = \dfrac{Upper\; specification\; limit - Lower\; specification \;limit} { 6 \times standard \;deviation }[/tex]

Now, substitute the known terms in the above formula.

[tex]\rm Cp = \dfrac{17.05-16.75}{6\times 0.04}[/tex]

Cp = 1.25

So, the correct statement is "the Cp calculation indicates that the process is capable" and "the process is centered, so the Cp calculation should be used".

Therefore, the correct option is D) I and III.

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Answer: 441.32 currency units

Step-by-step explanation:

The CD changer costs 108 currency units and the Camera costs 364 currency units.

First add these up to find out the total price:

= 108 + 364

= 472 currency units

The sales tax is 6.5% and this needs to be deducted from the total to get the after-tax total:

= 472 * ( 1 - 6.5%)

= 441.32 currency units

Answer:

[tex]m = 10\sqrt 3[/tex]

[tex]n = 10[/tex]

Step-by-step explanation:

Required

Find m and n

Considering the given angle, we have:

[tex]\sin(60) = \frac{Opposite}{Hypotenuse}[/tex]

This gives:

[tex]\sin(60) = \frac{m}{20}[/tex]

Make m ths subject

[tex]m = 20 * \sin(60)[/tex]

[tex]\sin(60) =\frac{\sqrt 3}{2}[/tex]

So, we have:

[tex]m = 20 *\frac{\sqrt 3}{2}[/tex]

[tex]m = 10\sqrt 3[/tex]

Considering the given angle again, we have:

[tex]\cos(60) = \frac{Adjacent}{Hypotenuse}[/tex]

This gives:

[tex]\cos(60) = \frac{n}{20}[/tex]

Make n the subject

[tex]n = 20 * \cos(60)[/tex]

[tex]\sin(60) =\frac{1}{2}[/tex]

So, we have:

[tex]n = 20 *\frac{1}{2}[/tex]

[tex]n = 10[/tex]