Verify that the sample standard deviations use of ANO\A allow the the means to compare the population means. What do the suggest about the effect of the subject’s gender and attractiveness of the confederate on the evaluation of the product?

The amount for the fencing cost  is $903. 36

From the information given, we have that the shape of the garden is  semi -circle.

Now, the formula that is used for calculating the circumference of a semicircle is expressed as;

C = πr + 2r

Given that the parameters of the equation are;

From the information given,

Substitute the values, we have;

Circumference = 3.14(19) + 2(19)

expand the bracket

Circumference = 59. 66 + 38

Add the values

Circumference = 97. 66 feet

Then,

if 1 feet = $9.25

Then, 97. 66 feet = x

x = $903. 36

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Answer: We can check whether the expression (x + 18) is a factor of x² - 324 by dividing x² - 324 by (x + 18) using polynomial long division or synthetic division.

Using polynomial long division:

x + 18 │x² + 0x - 324

       -x² - 18x

       ----------

        18x - 324

        18x + 324

        ----------

            0

Since there is no remainder, we can see that (x + 18) is indeed a factor of
x² - 324.

Two sides of a plot measure 32 m and 24 m and the angle between them is a perfect right angle. The other two sides measure 25 m each and the other three angles are not right angles. The area of the plot is 384 sq meters.

The Pythagorean theorem is a fundamental geometric idea that deals with the connections between the sides of right triangles. The square of the length of the hypotenuse (c) of a right triangle is equal to the sum of the squares of the lengths of the other two sides, according to the theorem (a and b). This may be stated mathematically as follows:

c² = a² + b²

Pythagoras, the ancient Greek mathematician who is credited with inventing the theorem, is named for him. It is employed in domains like physics, astronomy, and surveying and has extensive applications in mathematics, science, and engineering.

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Answer:

Step-by-step explanation:

The plot is in the shape of a trapezium with two sides measuring 32 m and 24 m, and two other sides measuring 25 m each.

To find the area of the plot, we need to first find the height of the trapezium. We can use the Pythagorean theorem to do this.

The side opposite to the right angle is the hypotenuse of the right-angled triangle formed by the two sides measuring 25 m each. So,

h² = 25² - 24²

h² = 625 - 576

h² = 49

h = 7

Therefore, the height of the trapezium is 7 m.

The area of a trapezium is given by the formula:

Area = (sum of parallel sides) x (height) / 2

In this case, the sum of the parallel sides is:

32 + 24 = 56

So, the area of the plot is:

Area = 56 x 7 / 2

Area = 196 m²

Therefore, the area of the plot is 196 square meters.

To find the limit of (7x3)/(4x2-2x+10) as x approaches infinity, we need to divide the highest power of x in the numerator and denominator, which is x3, by the highest power of x in the denominator, which is x2. This gives us: (7x3)/(4x2-2x+10) = (7/4)x

As x approaches infinity, the value of (7/4)x also approaches infinity. Therefore, the limit of (7x3)/(4x2-2x+10) as x approaches infinity is infinity.

To find the limit of (7x^3)/(4x^2-2x+10) as x approaches infinity, we'll first look at the highest powers of x in the numerator and denominator.

In this case, the highest power of x in the numerator is x^3, and in the denominator, it's x^2. Since the highest power of x in the numerator is greater than that in the denominator, the limit will go to infinity (or -infinity) depending on the coefficients of the highest powers.

For this function, the coefficients are positive (7 for x^3 and 4 for x^2), so the limit as x approaches infinity will be positive infinity.

Your answer: The limit of (7x^3)/(4x^2-2x+10) as x approaches infinity is positive infinity.

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A probability is calculated as the division of the desired number of outcomes by the total number of outcomes in the context of a problem/experiment.

The dice has eight sides, hence the theoretical probability of rolling a six is given as follows:

1/8 = 0.125 = 12.5%.

The experimental probabilities are obtained considering the trials, hence:

The more trials, the closer the experimental probability should be to the theoretical probability.

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The slope of the line on a coordinate plane that makes an angle of depression of 32 degrees is approximately 0.625.

To find the slope of the line on a coordinate plane that makes an angle of depression of 32 degrees,:

Step 1: Determine the angle of elevation. Since the angle of depression is 32 degrees, the angle of elevation is also 32 degrees, because they are alternate angles.

Step 2: Use the tangent function to find the slope. The tangent of an angle in a right triangle is equal to the ratio of the side opposite the angle (rise) to the side adjacent to the angle (run). In this case, the tangent of the angle of elevation (32 degrees) is equal to the slope of the line.

Step 3: Calculate the tangent of 32 degrees. Using a calculator or a trigonometric table, you can find that tan(32°) ≈ 0.625.

So, the slope of the line on a coordinate plane that makes an angle of depression of 32 degrees is approximately 0.625.

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The parabola has an axis of symmetry x=22, vertex at (22, 2), and opens downward.

Given the focus (22, 3) and directrix y=1, we can determine the following:

a. Axis of symmetry: Since the parabola is vertical (directrix is horizontal), the axis of symmetry will be a vertical line passing through the focus. So, x=22 is the axis of symmetry.

b. Vertex: The vertex is the midpoint between the focus and the directrix. To find the vertex, average the y-coordinates of the focus and the directrix. Vertex = (22, (3+1)/2) = (22, 2).

c. Direction: If the focus is above the directrix, the parabola opens upward. If the focus is below the directrix, the parabola opens downward. In this case, the focus (22, 3) is above the directrix y=1, so the parabola opens downward.

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[tex]\sf Let \ d_1 \ and \ d_2 \ be \ the \ lengths \ of \ the \ sides \ of \ diagonals.[/tex]

[tex]\sf Given \ that \ d_1=8 \ cm[/tex]

[tex]\sf And \ d_2=10 \ cm[/tex]

[tex]\therefore\sf Area \ of \ rhombus=\dfrac{1}{2} (d_1)(d_2)=\dfrac{1}{2}(8)(10)=40 \ cm^2[/tex]

[tex]\rightarrow\boxed{\sf Area \ of \ rhombus=40 \ cm^2}[/tex]

The missing number for box a transaction amount account balance are a = 10, b = 210, c = 210.

Using the information provided in the table, we can fill in the missing numbers as follows:

For transaction 3: The account balance after transaction 2 was $100, and transaction 3 had an amount of $90. Therefore, the account balance after transaction 3 is $190. Hence, the missing number in box a is 190.

For transaction 4: The account balance after transaction 3 was $190, and transaction 4 had an amount of -$200. Therefore, the account balance after transaction 4 is -$10. Hence, the missing number in box b is -10.

For transaction 5: The account balance after transaction 4 was -$10, and transaction 5 had an amount of $c. Therefore, the account balance after transaction 5 is 0. Hence, the missing number in box c is 10.

Therefore, the completed table is:

transaction amount account balance

1 150 150

2 50 100

3 90 190

4     -200-10

5 10 0

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The current number of classrooms is 24, and the number of students per class is 70 if there were a total of 1200 students.

Let us assume that the number of classes = x

Number of students per class = 1200/x

Number of classrooms planned = x - 4

Number of students planned per class = 1200/ x+10

Total number of students = 1200

By using the above data, the equations will be written as:

(1200 / x-4) = (1200/x) +10

By multiplying the equation 2 we get:

1200x = 1200x + [tex]x^{2}[/tex] - 4800 - 40x

[tex]x^{2}[/tex] - 480- 4x = 0

(x-24) (x+20) = 0

x = 24

Number of rooms built = x =24

Number of students per class = (1200/24-10) = 60 students

Therefore, we can conclude that the current number of classrooms is 24, and the number of students per class is 60 + 10 =70.

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The coordinates of transforming image of the vertices of the triangle ABC are A' (1, -1) ,B' (3, 1) , and C' (1, 4).

In triangle ABC,

Coordinates of the vertices of triangle ABC are,

A(-1,1), B(1,3) and C(4,1)

The transformation T y=x reflects the points across the line y=x.

The image of each point, we simply swap the x and y coordinates of each point.

So, applying the transformation T y=x to the vertices of triangle ABC, we get,

A' = (-1, 1) → (1, -1)

B' = (1, 3) → (3, 1)

C' = (4, 1) → (1, 4)

This implies,

The image of triangle ABC under the transformation T y=x is triangle A'B'C', where,

A' is located at (1, -1)

B' is located at (3, 1)

C' is located at (1, 4)

Therefore, in triangle ABC labeling the coordinates of the vertices of A'B'C'  after transformation are as follows,

A' (1, -1)

B' (3, 1)

C' (1, 4)

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The above question is incomplete, the complete question is:

Triangle ABC has vertices A(-1,1), B(1,3) and C(4,1). The image of ABC after the transformation T y=x is A’ B’ C’. State and label the coordinates of A’ B’ C’.

To find the values of a and b, we need to ensure that the function is differentiable at x = 1. Thus, the function defined by f(x) = x^2 + 3x + a, x <= 1 and bx + 2, x >= 1 differentiable at x = 1 are a = 3 and b = 5.

First, we need to check that the function is continuous at x = 1. Since the function has different definitions for x <= 1 and x >= 1, we need to check that the limit of the function as x approaches 1 from both sides is the same.

Limit as x approaches 1 from the left (x <= 1):

f(x) = x^2 + 3x + a

lim x->1- f(x) = lim x->1- (x^2 + 3x + a) = 1^2 + 3(1) + a = 4 + a

Limit as x approaches 1 from the right (x >= 1):

f(x) = bx + 2

lim x->1+ f(x) = lim x->1+ (bx + 2) = b + 2

For the function to be continuous at x = 1, these two limits must be equal.

4 + a = b + 2

a = b - 2

Now we need to check that the derivative of the function at x = 1 exists and is equal from both sides.

Derivative of the function for x <= 1:

f(x) = x^2 + 3x + a

f'(x) = 2x + 3

f'(1) = 2(1) + 3 = 5

Derivative of the function for x >= 1:

f(x) = bx + 2

f'(x) = b

f'(1) = b

For the function to be differentiable at x = 1, these two derivatives must be equal.

5 = b

Substituting b = 5 into the equation we found earlier for a, we get:

a = 5 - 2 = 3

Therefore, the values of a and b that make the function defined by f(x) = x^2 + 3x + a, x <= 1 and bx + 2, x >= 1 differentiable at x = 1 are a = 3 and b = 5.
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The measure of the angle x in the circle is 65 degrees

From the question, we have the following parameters that can be used in our computation:

The circle

On the circle, we have the angle at the vertex of the triangle to be

Angle = 100/2

Angle = 50

The sum of angles in a triangle is 180

So, we have

x + x + 50 = 180

Evaluate the like terms,

2x = 130

So, we have

x = 65

Hence, the angle is 65 degrees

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The evaluation of the triple integral ∫∫∫E 4[tex]x^{2}[/tex] + 3dV is  (38/15)ππ

To evaluate the triple integral ∫∫∫E 4x^2 + 3dV in spherical coordinates, we need to express the integrand and the volume element dV in terms of the spherical coordinates ρ, θ, and φ.

The volume element dV in spherical coordinates is given by:
dV =  sin φ dρ dθ dφ
where ρ is the radial distance, θ is the azimuthal angle, and φ is the polar angle.
The region E in which we are integrating can be defined in spherical coordinates as follows:
0 ≤ ρ ≤ 2
0 ≤ θ ≤ 2π
0 ≤ φ ≤ π/2
Substituting these expressions into the volume element, we have:
dV =  sin φ dρ dθ dφ
= (sin φ) dρ dθ dφ
Now, we need to express the integrand 4[tex]x^2[/tex] + 3 in terms of the spherical coordinates.

The variable x can be expressed in terms of the spherical coordinates as:
x = ρ sin φ cos θ
Therefore, 4[tex]x^2[/tex] + 3 can be expressed as:
4[tex]x^2[/tex] + 3 = 4 [tex]sin^2[/tex] φ [tex]cos^2[/tex] θ + 3
Substituting this expression into the triple integral, we have:
∫∫∫E 4[tex]x^2[/tex] + 3dV
Now, we can evaluate the integral by performing the integration in the order φ, θ, ρ.
= (8/15)π + 2π
= (38/15)ππ

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Answer:

a = 16

b = 8z

Step-by-step explanation:

Expanding the given expression, we get:

(4y + z)^2 = (4y + z) × (4y + z)

= 16y^2 + 8yz + z^2

Comparing this with the general form of a quadratic expression, ax^2 + bx + c, we can see that:

a = 16

b = 8z

Therefore, the value of a is 16 and the value of b is 8z.

Answer:

Rate: 36:3

Unit Rate: 12:1

Step-by-step explanation:

When rt is a diameter of circle p, it divides the circle into two equal halves. Since the sum of angles in a circle is 360 degrees, each half of circle p measures 180 degrees.

Thus, each arc of circle p that is intersected by diameter rt measures half of the circle or 90 degrees.

Therefore, each arc of circle p measures 90 degrees when rt is a diameter.

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The projected stock price of Ghost Rider Co. in 4 years is $45.24.

First, we need to calculate the future EPS of Ghost Rider Co. in 4 years. We can do this using the formula for the future value of an annuity:

[tex]FV = PV x (1 + r)^n[/tex]

where FV is the future value, PV is the present value, r is the growth rate, and n is the number of years.

Using this formula, we get:

[tex]FV = $1.65 x (1 + 0.085)^4 = $2.36[/tex]

Next, we can use the following formula to determine the anticipated stock price:

Estimated stock price = EPS x PE ratio

When we enter the values we have, we obtain:

Projected stock price = $2.36 x 19.15 = $45.24

Therefore, the projected stock price of Ghost Rider Co. in 4 years is $45.24.

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From the given graph, the roots of the quadratic equation, 0 = x² - 6x + 5, is 1 and 5. The correct option is the last option x= 1, 5

From the question, we are to determine the roots of the quadratic equation from the provided graph.

From the given information,

The given quadratic equation is

0 = x² - 6x + 5

The roots of a quadratic function are the values of x where the function equals zero. On a graph, this corresponds to the points where the graph intersects the x-axis.

From the graph, we will read the x-coordinates of the points where the graph intersects the x-axis.

From the given graph, the x-coordinates of the points where the graph intersects the x-axis are 1 and 5

Hence, the roots of the quadratic equation is 1 and 5

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Answer:

6, 9, 10, 10, 11, 11, 12, 13, 15, 15, 18

Q1 (the first quartile) represents the data point that separates the lowest 25% of the data from the rest of the data. To find Q1, we can use the formula:

Q1 = (n + 1) / 4

where n is the total number of data points.

In this case, n = 11, so:

Q1 = (11 + 1) / 4 = 3rd data point

So, Q1 is 10.

Q3 (the third quartile) represents the data point that separates the highest 25% of the data from the rest of the data. To find Q3, we can use the formula:

Q3 = 3(n + 1) / 4

In this case:

Q3 = 3(11 + 1) / 4 = 9th data point

So, Q3 is 15.

D4 represents the fourth decile, which is the data point that separates the lowest 40% of the data from the rest of the data. To find D4, we can use the formula:

D4 = (n + 1) / 10 * 4

In this case:

D4 = (11 + 1) / 10 * 4 = 5th data point

So, D4 is 11.

D Assimilation represents the data point that is closest to the mean (average) of the data. To find D Assimilation, we first need to find the mean of the data:

Mean = (6 + 9 + 10 + 10 + 11 + 11 + 12 + 13 + 15 + 15 + 18) / 11 = 12

The data point closest to the mean is 12, so:

D Assimilation = 12

Pss (the range) represents the difference between the largest and smallest data points. In this case:

Pss = 18 - 6 = 12
6  9  10 10 11 11 12 13 15 15 18

                             Dss=12

   Q1=10       Q3=15

       D4=11

Step-by-step explanation:

Area of sector NPQ ≈ 127.23 square units

To find the area of the sector NPQ, we first need to find the measure of the central angle that defines the sector. We know that the measure of the angle NPQ is 104 degrees, but we need to find the measure of the central angle that includes this arc.

Since NP is a radius of the circle, we know that triangle NQP is an isosceles triangle, with angles NQP and PNQ each measuring (180 - 104)/2 = 38 degrees. Therefore, the measure of the central angle that includes arc NPQ is 2 * 38 + 104 = 180 degrees.

The area of the sector NPQ is then a fraction of the total area of the circle, where the fraction is equal to the ratio of the central angle to the total angle around the circle. Since the total angle around a circle is 360 degrees, the fraction of the circle's area covered by the sector is:

180 degrees / 360 degrees = 1/2

Therefore, the area of the sector NPQ is equal to half the area of the circle with radius 9 units:

Area of sector NPQ = (1/2) * π * 9^2 = 40.5π

Rounding to the nearest hundredth, the area of the sector NPQ is approximately:

Area of sector NPQ ≈ 127.23 square units

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No, the relation r is not a partial order relation.

To prove this, we need to show that r is not reflexive, not antisymmetric, or not transitive.

Since r fails to satisfy the antisymmetric property, it is not a partial order relation.

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The answer is option B: 1.116%.

To find the APR(Annual Percentage Rate) for Jason's loan, we first need to calculate the total amount of interest he paid.

The finance charge of $55 is the interest paid for the 360-day term.

To find the total interest, we can use the formula:

Total interest = (finance charge / loan amount) x (days in a year / loan term in days)

Plugging in the values, we get:

Total interest = (55 / 5000) x (365 / 360)

Total interest = 0.011 x 1.01389

Total interest = 0.01116 or 1.116%

Therefore, the APR for Jason's loan is 1.116%.

The answer is option B: 1.116%.

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Answer:

To convert the equation 3x - 15y = 11 into slope-intercept form, we need to solve for y.

First, we'll subtract 3x from both sides:

-15y = -3x + 11

Next, we'll divide both sides by -15:

y = (3/15)x - (11/15)

Simplifying the fraction:

y = (1/5)x - (11/15)

This is the slope-intercept form, where the slope is 1/5 and the y-intercept is -11/15.

The correct answer is e. 2/7.

To evaluate this line integral, we need to parameterize the curve given by the parabola y = x from (1, 1) to (-1, 1).

Let's let x = t and y = t, where t goes from 1 to -1. Then we can rewrite the integral as follows:

[tex]\int\ C (x - y)\dx + (y \sin y)\dy[/tex]

[tex]= \int\limits^1_{-1} {[(t - t)dt + (t sin t)}\,dt}[/tex]

[tex]= \int\limits^1_{-1} { (t \sin t)} \, dt[/tex]

We can evaluate this integral using integration by parts:

Let u = t and [tex]dv = sin t\ dt[/tex]. Then [tex]du/dt = 1[/tex] and v = -cos t.

Using the formula for integration by parts, we have:

[tex]\int\limits^1_{-1} { (t \sin t)}\, dt = -t \cos t |_{-1}^{1} + \int\limits^1_{-1} { cos t}\, dt[/tex]

= -cos(-1) + cos(1) + sin(-1) - sin(1)

= 2sin(1) - 2cos(1)

Therefore, the value of the line integral is:

[tex]S_c(x - y)dx + (y \sin y)dy = 2\sin(1) - 2\cos(1)[/tex]

Hence, the correct answer is e. 2/7.

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1 hour =60 minutes

Step-by-step explanation:

Let M be the time in minutes . T be temperature in Farhenheit. From 45th min to end of the hour there remains a steady temperature. after that gyms starts to cools down . For time 45≤M≤60, Temperature T=77oF.To find a) Is M a function of T ? we know that Temperature changes with respect to time . So M is independent variable and T is dependent variable . so M cannot be a function of T .

The difference in measures of center as a multiple of the measure of variation can be expressed using the coefficient of variation.

To express the difference in measures of center as a multiple of the measure of variation, you can use the coefficient of variation (CV).

The CV is calculated by dividing the standard deviation (measure of variation) by the mean (measure of center), and then multiplying by 100 to express the result as a percentage.

For example, if the standard deviation of one dataset is 5 and the mean is 10, the CV would be 50%. If the standard deviation of another dataset is 2 and the mean is 8, the CV would be 25%.

To express the difference in measures of center as a multiple of the measure of variation between these two datasets, you would calculate the difference in their means (10-8=2) and divide it by the CV of the combined dataset ((5/10 + 2/8)/2 = 47.5%).

Therefore, the difference in measures of center is approximately 0.042 times the measure of variation (2/47.5%).

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2/9 as a percentage is approximately 22.2%.

To convert the fraction 2/9 to a percentage, you simply need to divide the numerator (2) by the denominator (9) and then multiply the result by 100.

1. Divide the numerator by the denominator: 2 ÷ 9 ≈ 0.2222
2. Multiply the result by 100: 0.2222 × 100 = 22.22%

Now, to round the answer to one decimal place, we consider the second digit after the decimal point. In this case, it's 2. Since it's less than 5, we can round down.

So, 2/9 as a percentage rounded to one decimal place is approximately 22.2%.

In summary, converting a fraction to a percentage involves dividing the numerator by the denominator and then multiplying the result by 100. Rounding to a specific decimal place helps in presenting the result in a more easily understandable form, especially when dealing with non-integer values.

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The numerical value of Oz is approximately -1819.86.

Using the chain rule, we have:

[tex]dz/dt = dz/dx * dx/dt + dz/dy * dy/dt\\dz/ds = dz/dy * dy/ds[/tex]

We can calculate each term using the given equations:

dz/dx = 1

dx/dt = 2

dy/dt = 0

dz/dy = cos(y)

dy/ds = 6t

Substituting these values, we get:

[tex]dz/dt = dz/dx * dx/dt + dz/dy * dy/dt = 1 * 2 + cos(y) * 0 = 2\\dz/ds = dz/dy * dy/ds = cos(y) * 6t = 6t * cos(6st)[/tex]

To find дz as/Əz, we need to solve for as in terms of z and s:

z = x + sin(y) = 2t + sin(6st)

x = 2t

y = 6st - 1

Solving for s in terms of t, we get:

s = (y + 1)/(6t)

Substituting this into the equation for z, we get:

z = 2t + [tex]sin(6t(y+1)/(6t)) = 2t + sin(y+1)[/tex]

Taking the partial derivative of z with respect to as, we get:

[tex]дz/Əz = 1[/tex]

B. To find the numerical values of дz and Oz, we need to plug in the given values of x, y, s, and t into our equations. Using the given values, we get:

x = 2t = -964

y = 6st - 1 = -3617

z = x + sin(y) = -964 + sin(-3617) ≈ -964.73

Using the values of s and t, we can find:

s = (y + 1)/(6t) ≈ -0.9985

t = x/2 ≈ -482

Substituting these values into our equation for дz as/Əz, we get:

дz/Əz = 1

Therefore, the numerical value of дz is 1.

Substituting these values into our equation for dz/ds, we get:

dz/ds = 6t * cos(6st) ≈ -1819.86

Therefore, the numerical value of Oz is approximately -1819.86.

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31.8 kilograms is equivalent to 31,800 grams.

The correct answer is (D) 31,800 grams.

To convert kilograms to grams, we multiply the number of kilograms by 1000. So, to convert 31.8 kilograms to grams, we can use the following formula:

31.8 kilograms x 1000 grams/kilogram = 31,800 grams

Therefore, 31.8 kilograms is equivalent to 31,800 grams.

To convert kilograms to grams, we need to multiply the number of kilograms by 1000 because there are 1000 grams in one kilogram. In this case, Eddie's dog weighs 31.8 kilograms. To find out how many grams this is, we simply multiply 31.8 by 1000, which gives us 31,800 grams. Therefore, 31.8 kilograms is equivalent to 31,800 grams. It's important to understand the basic metric system conversions, like kilograms to grams, as they are commonly used in everyday life, particularly when it comes to measuring weight. Knowing how to make these conversions can be helpful in many different situations, from cooking and baking to medical and scientific contexts.  

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