Water can dissolve many substances because-
-
it has a partial charge on each side of its molecules
it has a linear molecular shape
it has a nonpolar molecular structure
it has the molecular formula H₂O

Answer:

Explanation:

In the given reaction, carbon has a greater oxidation number in carbon dioxide (CO₂) than in carbon monoxide (CO). In CO₂, the oxidation number of carbon is +4, while in CO it is +2.

A potential problem associated with travel to another planet is : the extended time for humans to be in space.

It is highly likely that humans will travel to another planet, and Mars is currently considered the most viable option for human exploration. However, there are many potential problems associated with this endeavor, and one of the major issues is the extended time that humans would need to spend in space.

Traveling to Mars would take several months, and once there, astronauts would need to spend significant amount of time on planet before returning to Earth. This means that they would be exposed to high levels of radiation and would need to find ways to survive in harsh and unforgiving environment.

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A crucial trace mineral is chromium. Trivalent chromium, which is safe for people, and hexavalent chromium, which is toxic, are the two types.

Thus, Foods and dietary supplements both contain trivalent chromium. It might assist maintain normal blood sugar levels by enhancing the body's utilization of mineral.

Chromium is used by people to treat deficiencies. Additionally, it is used to treat bipolar disorder, diabetes, high cholesterol, and a variety of other conditions, but the majority of these uses are not well-supported by science.

Chromium by mouth doesn't help control blood sugar levels in people with prediabetes. Schizophrenia. Taking chromium by mouth doesn't affect weight or mental health in people with schizophrenia.

Thus, A crucial trace mineral is chromium. Trivalent chromium, which is safe for people, and hexavalent chromium, which is toxic, are the two types.

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The molecular formula of the strychnine, given that it is composed of 75.45% carbon, 6.59% hydrogen, 8.38% nitrogen, and the balance oxygen is C₂₁H₂₂N₂O₂

First, we shall obtain the empirical formula of compound. Details below:

Divide by their molar mass

C = 75.45 / 12 = 6.2875

H = 6.59 / 1 = 6.59

N = 8.38 / 14 = 0.5986

O = 9.58 / 16 = 0.59875

Divide by the smallest

C = 6.2875 / 0.5986 = 10.5

H = 6.59 / 0.5986 = 11

N = 0.5986 / 0.5986 = 1

O = 0.59875 / 0.5986 = 1

Multiply through by 2 to express in whole number

C = 10.5 × 2 = 21

H = 11 × 2 = 22

N = 1 × 2 = 2

O = 1 × 2 = 2

Thus, we can conclude that the empirical formula is C₂₁H₂₂N₂O₂

Now, we shall determine the molecular formula of strychnine. Details below

Molecular formula = empirical × n = mass number

[C₂₁H₂₂N₂O₂]n = 140.22

[(12×21) + (1×22) + (14×2) + (16×2)]n = 334

334n = 334

Divide both sides by 334

n = 334 / 334

n = 1

Molecular formula = [C₂₁H₂₂N₂O₂]n

Molecular formula = [C₂₁H₂₂N₂O₂]1

Molecular formula = C₂₁H₂₂N₂O₂

Thus, we can conclude that the molecular formula of strychnine is C₂₁H₂₂N₂O₂

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The centripetal acceleration experienced by the object can be calculated using the formula a = v^2/r, where v is the speed of the object and r is the radius of the circle. Substituting the given values, we get:

a = (50 cm/s)^2 / (250 cm)
a = 10 cm/s^2

Therefore, the centripetal acceleration experienced by the object is 10 cm/s^2.
To calculate the centripetal acceleration experienced by the object, you can use the formula:
Centripetal acceleration (a_c) = (velocity^2) / radius
Here, the velocity (v) is 50 cm/s and the radius (r) is 250 cm. Plugging in these values, we get:
a_c = (50^2) / 250 = 2500 / 250 = 10 cm/s²
So, the centripetal acceleration experienced by the object is 10 cm/s².

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The S-P difference (sec) is the time gap between the arrival of the S-wave and the arrival of the P-wave at a seismic station. The S-P discrepancy is depicted in the figure as 20 seconds.

The amplitude (mm) of a seismic wave is the largest displacement from its resting point. The amplitude of the waves is not depicted in the image and cannot be calculated based on the information provided.

Distance (km): Using the S-P time difference and the known velocity of seismic waves, the distance from the seismic station to the earthquake epicenter may be determined. Seismic wave velocity is determined by the type of wave and the features of the Earth's interior. The velocity of P-waves in the Earth's crust, for example, is around 6 km/s. We may compute the distance to the epicenter using this value and the S-P difference of 20 seconds as follows:

Distance = Speed x Time = 6 km/h x 20 seconds = 120 kilometres

As a result, the distance between the seismic station and the earthquake epicenter is about 120 km.

The magnitude of an earthquake (M) is a measurement of the energy generated by the earthquake based on the amplitude of the seismic waves and the distance to the epicenter. Magnitude is commonly measured on a logarithmic scale, with each whole number reflecting a factor of ten increase in energy release.

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At some constant temperature, the equilibrium constant for the reaction below is Kc = .76. An empty 1.00L flask is charged with 2.00 mol carbon tetrachloride and then allowed to reach equilibrium. CCl4(g) ⇌ C (s) + 2 Cl2(g)

a. To find the fraction of the reactant (CCl4) remaining at equilibrium, we can start by determining the initial concentration of CCl4:
Initial concentration of CCl4 = moles/volume = 2.00 mol / 1.00 L = 2.00 M

Let x be the change in concentration of CCl4 at equilibrium. Then, the equilibrium concentrations are:
[CCl4] = 2.00 - x
[Cl2] = 2x
The equilibrium constant expression is given by:
Kc = [Cl2]^2 / [CCl4]
Plugging in the given Kc value (0.76) and the equilibrium concentrations:
0.76 = (2x)^2 / (2.00 - x)

Now, you can solve for x. The fraction of the reactant remaining at equilibrium is (2.00 - x) / 2.00.

b. To find the molarity of chlorine gas (Cl2) at equilibrium, you can use the value of x obtained in part (a). The molarity of Cl2 is equal to 2x.

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First, we need to calculate the heat gained by the cold water and the heat lost by the hot water:

Qcold = mcΔT = (30 g)(4.184 J/g-°C)(1.93°C) = 242.06 J

Qhot = mcΔT = (70 g)(4.184 J/g-°C)(-1.93°C) = -546.53 J

Since energy is conserved, we can assume that the heat gained by the cold water and calorimeter is equal to the heat lost by the hot water:

Qcold + Qcalorimeter = Qhot

Qcalorimeter = Qhot - Qcold

Qcalorimeter = -546.53 J - 242.06 J = -788.59 J

Therefore, the heat capacity of the calorimeter can be calculated as:

Ccalorimeter = Qcalorimeter / ΔT

Ccalorimeter = (-788.59 J) / (1.93°C)

Ccalorimeter ≈ -408.4 J/°C

Note that the negative sign indicates that the calorimeter loses heat when the system gains heat, which is expected since the calorimeter is absorbing some of the heat from the hot water.

The volume of the carbon dioxide is produced at the 31.0 °C and the 0.995 atm is 119,786 L.

The number of moles of octane = 538 mol

The moles of carbon dioxide = 4888 mol

The temperature of the gas = 31.0 °C

The pressure of the gas = 0.995 atm

The volume of the gas = ?

The ideal gas equation is :

P V = n R T

Where,

The p is the pressure = 0.995 atm

The V is the volume = ?

The n is moles of gas = 4888 mol

The R is gas constant = 0.823 atm L / mol K

The T is temperature = 31 + 273 = 304 K

V = n R T / P

V = ( 4888 mol × 0.0823 × 304 ) / 0.995

V = 119,786 L

The volume is 119,786 L.

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The reaction rates for trial 1 is 8.22 x 10⁻² M⁻² s⁻¹ and 1.10 M⁻² s⁻¹ for trail 2 and 3

Keep the concentration of W constant while varying the concentrations of U and S while measuring the reaction rate in order to determine the reaction rate with regard to U and S.

Select trial 1 as the reference trial and calculate the reaction's rate constant (k) with respect to U and S, assuming that the concentration of W is constant throughout all three trials.

For trial 1:

[W] = 0.13 M

Rate = 4.72 x 10⁻⁴ M/s

For trial 2:

[W] = 0.13 M

Rate = 1.18 x 10⁻² M/s

From the equation rate = k[U][S], set up the following ratio of rates:

Rate2/Rate1 = (k[U]2[S]2)/(k[U]1[S]1)

Simplifying:

k = (Rate2/Rate1) x (1/[U]2) x (1/[S]2) x ([U]1) x ([S]1)

Substituting the values from trials 1 and 2:

k = (1.18 x 10⁻² M/s) / (4.72 x 10⁻⁴ M/s) x (1/0.65 M) x (1/1 M) x (0.13 M) x (1 M)

k = 8.22 x 10⁻²M⁻² s⁻¹

Similarly, for trial 3:

[W] = 0.13 M

Rate = 2.95 x 10⁻¹ M/s

Again, using trial 1 as the reference trial, figure out the reaction's rate constant (k) in relation to U and S:

k = (Rate3/Rate1) x (1/[U]3) x (1/[S]3) x ([U]1) x ([S]1)

k = (2.95 x 10⁻¹ M/s) / (4.72 x 10⁻⁴ M/s) x (1/3.25 M) x (1/1 M) x (0.13 M) x (1 M)

k = 1.10 M⁻² s⁻¹

Therefore, the equation states the reaction rate in relation to U and S is k = 8.22 x 10⁻² M⁻² s⁻¹ and 1.10 M⁻² s⁻¹ for trials 2 and 3, respectively.

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The average speed of a gas molecule is proportional to the square root of its temperature and inversely proportional to the square root of its molar mass. Therefore, we can use the following equation to find the average speed of a CO2 molecule at the same temperature:

v2/v1 = sqrt(M1/M2)

where v1 and v2 are the average speeds of the oxygen and CO2 molecules, respectively, M1 and M2 are the molar masses of oxygen and CO2, respectively.

The molar mass of oxygen (O2) is 32 g/mol, and the molar mass of CO2 is 44 g/mol.

We are given that the average speed of an oxygen molecule is 4.37 × 10^4 cm/s at 25°C. We can convert the temperature to Kelvin by adding 273.15 to get:

T = 25°C + 273.15 = 298.15 K

Now we can solve for v2:

v2 = v1 * sqrt(M1/M2)

v2 = 4.37 × 10^4 cm/s * sqrt(32 g/mol / 44 g/mol)

v2 = 3.67 × 10^4 cm/s

Therefore, the average speed of a CO2 molecule at the same temperature is 3.67 × 10^4 cm/s.

The mass of Na₃PO₄ formed during the reaction is 328 g.

The balanced chemical equation for the reaction is:

[tex]3NaOH + Na_3PO_4 - > 3Na_2PO_4 + H_2O[/tex]

From the equation, we can see that 3 moles of NaOH produce 1 mole of Na₃PO₄.

Given that 2.0 moles of Na₃PO₄ is produced, we can set up a proportion to find the amount of NaOH required:

3 mol NaOH / 1 mol Na₃PO₄ = x mol NaOH / 2.0 mol Na3PO4

Solving for x, we get:

x = (3 mol NaOH / 1 mol Na₃PO₄) × (2.0 mol Na₃PO₄ / 1) = 6.0 mol NaOH

So, 6.0 moles of NaOH are required to produce 2.0 moles of Na₃PO₄.

To find the mass of Na₃PO₄ produced, we can use its molar mass:

mass = moles × molar mass = 2.0 mol × 164 g/mol = 328 g

Therefore, the mass of Na₃PO₄ formed during the reaction is 328 g.

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Answer:

A. setting standards and governing the cleanliness of water used by Americans

Explanation:

The responsibilities of the Environmental Protection Agency (EPA) is to make sure that:

The mass of the platinum ring is 76.0 grams.

We need to know the molar mass of platinum and the number of platinum atoms in the ring.

The molar mass of platinum (Pt) is 195.08 g/mol.

The number of platinum atoms in the ring is 2.35×10^23.

Now we can use the following formula to calculate the mass of the ring:

mass = (number of atoms) x (atomic mass) / Avogadro's number

where Avogadro's number is 6.022 x 10^23 mol^-1.

Substituting the values:

mass = (2.35×10^23 atoms) x (195.08 g/mol) / (6.022 x 10^23 mol^-1)

mass = 76.0 g

Therefore, the mass of the platinum ring is 76.0 grams.

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Step-by-step Explanation:

8.51 moles is to 5.12 L  as  'x'  moles is to (13.3-5.12) L

8.51 moles / 5.12 L    =   x / ( 13.3-5.12)

x = 13.6 moles

Answer:

Data collection is the act of obtaining information from diverse sources, and data analytics is the process of processing that information to derive practical insights.

Explanation:

To calculate the concentration resulting from the dilution of 500.0 mL of 4.267 M to a volume of 1.85 L, we can use the equation:
M1V1 = M2V2
where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.

Plugging in the given values, we get:
4.267 M)(500.0 mL) = M2(1.85 L)
Simplifying this equation, we get:
M2 = (4.267 M)(500.0 mL) / (1.85 L)
M2 = 1.153 M
Therefore, the concentration resulting from the dilution is 1.153 M.
To calculate the concentration after dilution, you can use the dilution formula: C1V1 = C2V2, where C1 and V1 are the initial concentration and volume, and C2 and V2 are the final concentration and volume.
Given:
C1 = 4.267 M
V1 = 500.0 mL = 0.5 L (converted to liters)
V2 = 1.85 L
Now, find C2:

C2 = (C1 * V1) / V2
C2 = (4.267 M * 0.5 L) / 1.85 L
C2 ≈ 1.153 M
The concentration after dilution is approximately 1.153 M.

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To find the concentration resulting from the dilution, we can use the equation:
M1V1 = M2V2
where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.

Plugging in the given values, we get:
(4.267 M)(500.0 mL) = M2(1.85 L)
Simplifying and converting units, we get:
M2 = (4.267 M)(500.0 mL) / (1.85 L)
M2 = 1.16 M
Therefore, the concentration resulting from the dilution is 1.16 M.
To find the concentration after dilution, you can use the dilution formula:
C1V1 = C2V2
where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
Given:
C1 = 4.267 M
V1 = 500.0 mL (0.5 L)
V2 = 1.85 L
Rearrange the formula to solve for C2:
C2 = (C1V1) / V2
Now, plug in the given values:
C2 = (4.267 M * 0.5 L) / 1.85 L
C2 ≈ 1.154 M
So, the resulting concentration after dilution is approximately 1.154 M.

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According to the ideal gas law, a gas's pressure is inversely related to its volume and directly proportionate to its temperature. So, if a gas sample's volume is reduced, the gas sample's pressure must also increase.

As a result, in order to determine the pressure of the gas sample under the specified circumstances, we must first determine the ratio of the two volumes before multiplying the starting pressure of the sample by that ratio.

We may get the ratio of the two volumes using the ideal gas law as follows: V2/V1 = (100.0 mL/0.75 L) x (273 K/25oC) = 8.02 As a result, the gas sample's pressure at 25 oC with a volume of 100.0 mL is 8.02 times higher than the sample's original pressure.

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The mass of carbon dioxide formed when 24 kg of carbon is burnt completely in oxygen is 88 kg, and the heat released is 811.2 MJ.

What is Molar Mass?

Molar mass is the mass of one mole of a substance and is expressed in grams per mole (g/mol). It is calculated by adding up the atomic masses of all the atoms in a molecule or formula unit of a compound. The molar mass is used in stoichiometry calculations to convert between mass and moles of a substance.

The balanced equation for the combustion of carbon is:

C + O₂ → CO₂

From the equation, we can see that one mole of carbon reacts with one mole of oxygen to produce one mole of carbon dioxide. The molar mass of carbon dioxide is 12 + (2 × 16) = 44 g/mol.

First, let's find the number of moles of carbon in 24 kg:

n(C) = m/M = 24000 g / 12 g/mol = 2000 mol

Therefore, 2000 mol of CO₂ will be produced.

The mass of CO₂ produced can be calculated as:

m(CO₂) = n(CO₂) × M(CO₂) = 2000 mol × 44 g/mol = 88,000 g = 88 kg

Now, let's calculate the heat released during combustion:

Heat released = 33.8 MJ/kg × 24 kg = 811.2 MJ

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The oxidation number of the unknown chlorine in the compound is + 5

The oxidation number of an element in a compound is determined by a set of rules based on its position in the periodic table, as well as the charges of other atoms in the compound

We know that the oxidation number of the chlorine which we want to obtain would be designated as x and the total of the oxidation numbers of the elements in the compound is zero.

Thus we have that;

1 + x + 3(-2) = 0

1 + x - 6 = 0

-5 + x = 0

x = 5

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the balanced equation and there reactions are as follow:

K₂O + H₂O → 2KOH

The reaction between potassium oxide and water produces potassium hydroxide (KOH).

F₂ + 2NaBr → 2NaF + Br₂

The reaction between fluorine gas and sodium bromide produces sodium fluoride and bromine.

2Ba(CIO3)₂ → 2BaCl₂ + 3O₂

The decomposition of barium chlorate produces barium chloride and oxygen gas.

SrBr₂ + (NH₄)₂CO₃ → SrCO₃ + 2NH₄Br

The reaction between strontium bromide and ammonium carbonate produces strontium carbonate and ammonium bromide.

C₈H₁₈ + 12O₂ → 8CO₂ + 9H₂O

The combustion of octane with oxygen produces carbon dioxide and water.

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The final temperature of the copper and water after they come to thermal equilibrium is 109.8°C.

Temperature is a measure of the amount of thermal energy present in a substance or object. It is measured in degrees on a scale such as Fahrenheit, Celsius, or Kelvin. Temperature is important in determining the physical and chemical properties of a substance, such as its melting point, boiling point, and specific gravity. Temperature also affects the rate of a chemical reaction and the speed of diffusion.

The change in temperature of the copper can be calculated using the equation
ΔT = (Q/mc), where Q is the heat transferred, m is the mass of the copper, and c is the specific heat of copper.
Q = mcΔT = (192 g)(0.385 J/g °C)(100°C) = 74080 J
The heat transferred from the copper must equal the heat transferred to the water. Therefore,
(74080 J) = (0.85 L)(4.184 J/g°C)(ΔT)
ΔT = (74080 J)/[(0.85 L)(4.184 J/g°C)] = 109.8°C
The final temperature of the copper and water after they come to thermal equilibrium is 109.8°C.

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Answer:

3.566 mol

Explanation:

Since 60.05 is grams divided by mol to cancel out the grams to get only mols it must be divided by 16.84 g

[tex]\frac{60.05 g}{mol} *\frac{1 }{16.84g} =3.566[/tex] mols acetic acid

The triacylglycerol depicted may be converted to a saturated fat by adding two hydrogen atoms (H2) to each carbon-carbon double bond. Six hydrogen atoms (H2) are required to convert the three carbon-carbon double bonds in triacylglycerol into saturated fat.

This is so that the triacylglycerol may be converted to a saturated fat by using hydrogen molecules (H2) to saturate the double bonds.

Triacylglycerol's physical characteristics, such as its melting point, will similarly be altered by the addition of hydrogen molecules (H2), making it more solid at normal temperature.

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Before the chairs touch, the temperature of the bottom chair is lower than the temperature of the top chair, this is because the molecules in the bottom chair are in contact with a cooler surface.

After the chairs have been touching for a while, the heat will begin to transfer from the top chair to the bottom chair through a process called conduction. This will continue until the temperature of the two chairs equalizes, at which point there will be no more net heat transfer between them.

The final temperature of both chairs will be somewhere between the initial temperatures of the two chairs, and will depend on factors such as the thermal conductivity of the material, the size of the chairs, and the duration of the contact.

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Answer:

39.7

Explanation:

Therefore, the final temperature of the water is 39.7°C.

All of the equation-related claims are not entirely true. The appropriate chemical formula should be:

Fe(OH)3 + 3NH4Cl = FeCl3 + 3NH4OH

Because the total mass of the reactants and products are equal, as well as the number of each type of atom in each of the reactants and products, mass is conserved in this balanced equation. Depending on the stoichiometric coefficients in the balanced equation, there may or may not be an equal amount of molecules in the reactants and products.

Iron(III) hydroxide (Fe(OH)3) and ammonium chloride (NH4Cl) are the products of the chemical reaction between iron(III) chloride (FeCl3) and ammonium hydroxide (NH4OH).

The coefficients (the numbers in front of the chemical formulae) must be changed to make sure that the number of each type of atom is the same on both sides of the equation in order to ensure that the equation is balanced. The coefficients in this instance are:

Fe(OH)3 + 3NH4Cl = FeCl3 + 3NH4OH

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The problem requires the calculation of the volume of carbon dioxide produced at STP when 587 mol of octane combusts; ,therefore, the volume of CO₂ produced at 36.0 °C and 0.995 atm is approximately 124,700 L.

The ideal gas law is given by:

PV = nRT

P is the pressure in atm, V is the volume in L, n is the number of moles, R is the gas constant (0.0821 L·atm/mol·K), and T is the temperature in K.

587 mol octane × (16 mol CO₂/2 mol octane) = 4696 mol CO2

Next, one can use the ideal gas law to calculate the volume of CO₂ produced at 36.0 °C and 0.995 atm. Then one needs to convert the temperature to kelvin by adding 273.15:

T = 36.0 °C + 273.15 = 309.15 K

Substituting the values into the ideal gas law:

PV = nRT

V = nRT/P

V = (4696 mol)(0.0821 L·atm/mol·K)(309.15 K)/(0.995 atm)

V ≈ 124,700 L

Therefore, the volume of CO2 produced at 36.0 °C and 0.995 atm is approximately 124,700 L.

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The rate of appearance of NOBr at the given time is 9.80 × [tex]10^-^4[/tex] M/s which is the second option as the question asks to determine the rate of appearance of NOBr, which is a product of the given chemical reaction, at the given time when the rate of disappearance of Br₂ is known. 

For every 1 mole of Br₂ that disappears, 2 moles of NOBr appear. Thus, we can set up a proportion:

(2 mol NOBr / 1 mol Br₂) = (rate of appearance of NOBr / rate of disappearance of Br₂)

Substituting the given values,

(2 mol NOBr / 1 mol Br₂) = (rate of appearance of NOBr / 4.90 x  [tex]10^-^4[/tex] M/s)

Solving for the rate of appearance of NOBr,

rate of appearance of NOBr = (2 mol NOBr / 1 mol Br₂) x (4.90 x  [tex]10^-^4[/tex] M/s) = 9.80 ×  [tex]10^-^4[/tex]M/s

The rate of appearance of NOBr at the given time is 9.80 × [tex]10^-^4[/tex] M/s.

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