Answer:
Newton's first law, also known as the law of inertia, states that an object will remain at rest or in motion at a constant velocity unless acted upon by an external force. In other words, an object will not change its velocity on its own, it will only do so if something else pushes or pulls on it. This law is a fundamental principle of classical mechanics, and it helps to explain the behavior of objects under various conditions.
Explanation:
Answer: Newton first law states that an object at rest tends to stay at rest. an object in motion tends to stay in motion in a straight line at a constant speed until another force acts on the object. It is also called the law of inertia
Explanation: Newton’s first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.
Hope this was helful
A smoke detector is an electronic fire-protection device that automatically senses the presence of smoke as a key indicator of fire and creates a loud sound as a warning. In 3-5 sentences, describe what is happening inside a photoelectric smoke detector as soon as smoke enters it
Answer:
Photoelectric-type alarms aim a light source into a sensing chamber at an angle away from the sensor. Smoke enters the chamber, reflecting light onto the light sensor; triggering the alarm.
Explanation:
nfpa.org is the website with theanswer
The first scientist misidentified the fossil as that of a big cat. What body structure did he use to make his observations?
Manipulation of equations:
mAvAi+mBvBi=mAvAf+mBvBf
Find mA
The value of mA is the equation of conservation of linear momentum is determined as mA = [ mB (vBi - vBf) ] / [ (vAf - vAi ) ].
What is the principle of conservation of linear momentum?
The principle of conservation of linear momentum states that in a closed or isolated system, the total momentum of the system is always conserved.
Mathematically, the formula for the principle of conservation of linear momentum is given as;
Pi = Pf
where;
Pi is the initial momentum of the systemPf is the final momentum of the systemmAvAi + mBvBi = mAvAf + mBvBf
where;
mA is the mass of the object AmB is the mass of the object BvAi is the initial velocity of object AvBi is the initial velocity of object BvAf is the final velocity of object AvBf is the final velocity of object BTo find the value of mA, we will make mA the subject of the formula as follow;
mAvAf - mAvAi = mBvBi - mBvBf
mA (vAf - vAi ) = mB (vBi - vBf)
mA = [ mB (vBi - vBf) ] / [ (vAf - vAi ) ]
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11. (2 pts) A photon with energy 44.8 eV is absorbed by a hydrogen atom in its ground state, knocking the
electron out. What is the speed of the electron as it leaves?
Answer: 3.3·10^6 m/s
Explanation: Ionization energy of H is 13.6 eV. So the kinetic energy of electron is 31,2 eV. Kinetic Energy of Electron is E = ½mv^2
1 eV = 1.60·10^-19 J and m = 9.1·10^-31 kg. Solving speed v = √( 2E / m)
v = √(2·31.2·1.60·10^-19 J /9.1·10^-31 kg) = 3.3·10^6 m/s
What was David Berkowitz best known for? How did arson play a role in his past?
As a well-known serial killer, David Berkowitz was infamous for starting fires and then reporting some of them to various fire officials. He started over 500 fires annually.
What David Berkowitz best known for?David Berkowitz, also known as Son of Sam, was apprehended on August 10, 1977 – 11 days after he committed his final murder—and later received six consecutive sentences of 25 years to life in prison.
Since the 18th century, arson has changed from a bad individual act to a powerful tool for group violence. The privatization of common land in England starting in 1750 restricted the access of peasants to resources like game and firewood.
Therefore, Son of Sam, also known as David Berkowitz, was apprehended by authorities after going on a homicidal rampage in New York City in the 1970s.
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a horizontal of 5 n is required to maintain a velocity of 2m/s for a block of 10kg
Complete Question:
A horizontal force of 5N is required to maintain a velocity of 2m/s for a block of 10kg mass sliding over a rough horizontal surface. The work done by this force in one minute is:
Answer:
Workdone = 600 Joules.
Explanation:
Given the following data;
Force = 5N
Velocity = 2 m/s
Time = 1 minute to seconds = 60 seconds.
Mass = 10 kg
To find the work done;
First of all, we would determine the distance covered by the block.
Distance = speed * time
Distance = 2 * 60
Distance = 120 seconds
Mathematically, workdone is given by the formula;
[tex] Workdone = force * distance[/tex]
Substituting into the formula, we have;
[tex] Workdone = 5 * 120 [/tex]
Workdone = 600 Joules.
Therefore, the work done by this force in one minute is 600 Joules.
7. The more friction that there is, the slower an object will move. *
true or false (science)
Answer:
*TrueThe force of friction opposes the motion of an object, causing moving objects to lose energy and slow down. When objects move through a fluid, such as air or water, the fluid exerts a frictional force on the moving object. The frictional force from a fluid is called a drag force.
The sum of the x components of vectors A and B in (Figure 1 ) is
-5
4
14
6
Vectors A and B are shown in a tip to tail arrangement. Vector A begins at the origin (0,0) and ends at the x y coordinate (9,3). Vector B begins at the tip of vector A and ends at the x y coordinate (4,6).
The resultant (x,y) coordinate of vector B is (- 5, 3) and that of A is (9,3). Then, the sum of x components of vector A and B is 4.
What are vectors ?Vectors are physical quantities having both magnitude and direction. For example force, velocity, displacement etc .are vector quantities. Coordinates are used to describe the position of these vectors.
The coordinates of tail of the vector A is (0, 0) and the head is (9,3)
Then the coordinate of A is (9 -0, 3-0) = (9,3)
Similarly, the tail coordinate of B is (9,3) and head is (4,6). The coordinates of B vector is (4-9, 6-3) = (-5, 3)
Now the sum of x components of A and B is = - 5 + 9 = 4.
Therefore, option b is correct.
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An object with a weigh of 170 N on Earth is brought to planet Oobla. Where it has a weight of 360 N. What is the gravitational field strength on Oobla
The gravitational field strength on Oobla is 20.75 m/s².
What is gravitational field strength?The gravitational field is the gravitational force exerted per unit mass on a small mass at a point in the field.
To calculate the gravitational field strength on Ooobla, we use the formula below
Formula:
W/g = W'/g'................. Equation 1Where:
W = Weight of the object on Earthg = Gravitational field strength on the Earthg' = Gravitational field strength on the OoblaW' = Weight of the object on OoblaFrom the question,
Given;
W = 170 Ng = 9.8 m/s²W' = 360 NSubstitute these values into equation 1 and solve for g'
170/9.8 = 360/g'g' = 360×9.8/170g' = 20.75 m/s²Hence, the gravitational field strength is 20.75 m/s².
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d. The mass of the boy is the same in all places because mass does not depend
on gravity.
True or False
(Science)
Explanation:
Remember, even if you weigh less because of a change in gravity's force on your body, your body's mass is still the same. As your body grows, you will have more mass, which also means you will weigh more. That's because when you're on the earth, the amount of gravity that pulls on you stays the same.Thank you for marking me Brainlist ☺️Answer:
true . it depends tho weight depends on gravity .
Two students are balancing on a 10m seesaw. The seesaw is designed so that each side of the seesaw is 5m long. The student on the left weighs 60kg and is sitting three meters away from the fulcrum at the center. The student on the right weighs 45kg. The seesaw is parallel to the ground. The mass of the board is evenly distributed so that its center of mass is over the fulcrum. What distance from the center should the student on the right be if they want the seesaw to stay parallel to the ground?
a. 4m
b. 5m
c. 2m
d. 3m
NO LINKS.
Answer:
B.5m
Explanation:
not sure if i'm right;)
A 600-nm-wavelength beam of light is incident on a soap film with air on both sides. The film has an index of refraction of 1.33. Determine the film's minimum thickness to make the reflected light enhanced in brightness
Answer:
the film's minimum thickness to make the reflected light enhanced in brightness is 112.8 nm
Explanation:
Given the data in the question;
wavelength λ = 600 nm
index of refraction = 1.33
so the film's minimum thickness to make the reflected light enhanced in brightness = ?
condition for maxima for reflected light is;
2nt = [ ( 2m + 1 )λ ] / 2
we solve for t
4nt = [ ( 2m + 1 )λ ]
t = [ ( 2m + 1 )λ ] / nt
Now, for minimum thickness m = 1
t = λ / 4n
so we substitute in our values;
t = 600 nm / ( 4 × 1.33 )
t = 600 nm / 5.32
t = 112.78195 ≈ 112.8 nm { one decimal place }
Therefore, the film's minimum thickness to make the reflected light enhanced in brightness is 112.8 nm
three laws of mechanics and
Answer:
In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
During a hard drive crash the read/write head scrapes against the disk with a coefficient of kinetic friction of µk and normal force of N. Assume that just before the head crash the disk is rotating at ω0 rad/s, and the distance of the head from the disk axis is r. You can ignore any friction at the bearing (rotational axis of the disk). Assume that the disk is uniform, and has radius R and mass M. What is the angular acceleration associated with the torque from the crashed disk head?
Answer:
α = [tex]\frac{2 \mu \ N}{m \ r}[/tex]
Explanation:
For this exercise we use Newton's equation for rotational motion
∑ τ = I α
the troque is
α = Fr .r
the moment of inertia of a cylinder is
I = ½ m r²
we substitute
fr r = (½ m r²) α
the expression friction is
fr = μ N
we substitute
μ N r = ½ m r² α
α = [tex]\frac{2 \mu \ N}{m \ r}[/tex]
PLEASE OMGGGG When describing image formation for plane mirrors, what is an important rule to remember about light rays?
A. The angle when it leaves is the same as the angle when it hits.
B. The angle is smaller in the medium that has the lower index of
refraction
C. The angle when it leaves is larger than the angle when it hits.
D. The angle is smaller in the medium that has the higher index of
refraction
Answer:
The angle when it leaves is the same as the angle when it hits.
Explanation:
think of it as a mirror, mirrors show exactly what you display.
Both formal and informal
Explanation:
is this a question????...
HELP When the forces are applied in the same direction, how do you determine net force?
Answer:
Explanation:
If two forces act on an object in the same direction, the net force is equal to the sum of the two forces.
The pressure of a sample of gas is measured as 49 torrent. Convert this to atmosphere
Answer:
P = 0.0644 atm
Explanation:
Given that,
The pressure of a sample of gas is measured as 49 torr.
We need to convert this temperature to atmosphere.
The relation between torr and atmosphere is as follow :
1 atm = 760 torr
1 torr = (1/760) atm
49 torr = (49/760) atm
= 0.0644 atm
Hence, the presssure of the sample of gas is equal to 0.0644 atm.
A rocket is launched from the surface of Earth with a speed v0 that will allow the rocket to escape the gravitational field of Earth. The same rocket is now launched from a different planet with the same mass as Earth and four times the radius of Earth. Which of the following is a correct expression for the escape speed from the surface of the new planet?
a. 0.5V.
b. 2V0
c. 0.25v.
d. 0.71V.
e. Vo
Answer:
option ( a ) is correct .
Explanation:
Escape velocity on the earth = √ ( 2 GM / R )
where G is universal gravitational constant , M is mass of the earth and R is radius .
V₀ = √ ( 2 GM / R )
escape velocity on the planet where mass is equal is earth's mass and radius is 4 times that of the earth
Radius of the planet = 4 R
escape velocity of planet = √ ( 2 GM / 4R )
= .5 x √ ( 2 GM / R )
= .5 V₀
option ( a ) is correct .
Directions: Unscramble each word. Then write each term on the line before its definition.
1. antstonc
2. desep
3. ticlovey
4. onlacietrace
5. emincedsplat
6. tomoni
7. cenferree nitop
8. spooniti
9. measure of change in velocity
10. distance an object moves in a unit of time
11. change of position
12. distance and direction from a reference point
13. not changing
14. speed of an object in a given direction
15. distance between the initial and final position
16. starting point used to describe the location of an object
Answer:
constantspeedvelocityaccelerationdisplacementmotionreference pointpositionExplanation:
Above is the unscrambled words. Hope this helps!
Determine the parallel and perpendicular components of the force of gravity for a 369 N object on a 28.4 degree incline
The parallel component of the force of gravity is the net force. The perpendicular component of the force of gravity is directed opposite the normal force and as such balances the normal force.
What is the perpendicular component of the force of gravity?In order to balance the normal force, the perpendicular component of gravity is pointed in the opposite direction. No other force can counteract the parallel component of the gravitational force.
What is the parallel component of the force of gravity?The presence of an imbalanced force will then cause the object to accelerate downward along the inclined plane. This acceleration is brought on by the parallel part of the gravitational force. The net force is a parallel part of the gravitational force.
Steps for Calculating the Force of Gravity on an Object Falling from an Inclined Plane: Determine the inclined plane's angle in the first step.Determine the object's mass on the inclined plane in step two.Determine and compute the gravitational force acting on the item.Determine and compute the parallel and perpendicular forces acting on the object.Formulas to Calculate the Force of Gravity on an Object Falling Down an Inclined Plane using Vocabularyincline plane: a wedged angle.Force of Gravitation the downward-moving gravitational force.Force that is parallel to the inclined plane's face is referred to as the perpendicular force.The force that is parallel to the inclined plane's face is known as the parallel force.Equation for Gravitational Force: The gravitational force is equal to the product of an object's mass and its gravitational acceleration.FGravity=m×g
where m is the object's mass and g is gravity's acceleration, which is 9.8 m/s2. In this case, the negative indicates that the force is downward-directed.
Equation for Perpendicular Force: The Perpendicular Force is equal to the gravitational force multiplied by the cosine of the angle of the inclined plane.FParallel=FGravity×Cos(Θ)
Equation for the Parallel Force: The Parallel Force is equal to the gravitational force multiplied by the sine of the inclined plane's angle.FParallel=FGravity×Sin(Θ)
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What is the meaning of anything
Answer:
everything
Explanation:
Used to refer to a thing, no matter what
Why was Silent Spring so influential at the time?
The book provided inspiration to those suffering from pesticide exposure.
It was the first book to bring awareness to global warming issues.
It was the first book that discussed the benefits of the Endangered Species Act.
It was the first time that the public was being made aware of the long-term impacts of pollution.
The reason that Silent Spring was so influential at the time is option D: It was the first time that the public was being made aware of the long-term impacts of pollution.
What is the book about?Silent Spring, a book written by Rachel Carson and published in 1962, was influential at the time because it was the first book to bring awareness to the negative impacts of pesticides on the environment and human health.
Therefore, The book provided evidence and detailed accounts of the harmful effects of pesticides on wildlife and ecosystems, and it argued that the widespread use of pesticides was unsustainable and could have long-term consequences for the environment and human health.
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A child's toy consists of a spherical object of mass 50 gg attached to a spring. One end of the spring is fixed to the side of the baby's crib so that when the baby pulls on the toy and lets go, the object oscillates horizontally with a simple harmonic motion. The amplitude of the oscillation is 6 cmcm and the maximum velocity achieved by the toy is 3.2 m/sm/s . What is the kinetic energy KKK of the toy when the spring is compressed 4.4 cmcm from its equilibrium position
Answer:
Explanation:
amplitude of oscillation A = .06 m .
maximum velocity = ω A where ω is angular frequency .
ω A = 3.2 m/s ( Given )
ω x .06 = 3.2
ω = 53.33 rad /s .
velocity when the displacement is x can be given by the expression
v² = ω²( A² - x² )
x = .04 m
v² = 53.33²( .06² - .04² )
= 2844.1( .0036 - .0016 )
= 5.688
kinetic energy = 1/2 m v²
= .5 x .050 x 5.688
= .1422 J .
=
On what basis is it considered that the universe is expanding?
There is strong evidence to support the idea that the universe is expanding. One of the main pieces of evidence for this is the observation of the cosmic microwave background radiation, which is a faint glow of microwave radiation that permeates the entire universe. This radiation is thought to be a residual heat left over from the Big Bang, the event that is believed to have marked the beginning of the universe.
The cosmic microwave background radiation has a very even temperature throughout the universe, but if the universe were not expanding, we would expect to see some regions that are slightly hotter or cooler than others due to differences in density. However, measurements of the cosmic microwave background radiation show that it has a very uniform temperature, which suggests that the universe must be expanding in order to even out any temperature differences that may have existed in the past.
Other evidence for the expansion of the universe includes the observation of supernovae in distant galaxies, which are explosions of massive stars that can be used to measure the distances to those galaxies. These measurements have shown that the most distant galaxies are moving away from us at a speed that is proportional to their distance, which is consistent with the expansion of the universe.
Hope This Helps You!
A woman of mass 55 kg stands on the rim of a frictionless merry-go-round of radius 2.0m and rotational inertia 1250 kg-m2 that is not moving. She throws a rock of mass 350g horizontally in a direction that is tangent to the outer edge of the merry-go-round. The speed of the rock, relative to the ground, is 2.0m/s. Afterward, what are (a) the angular speed of the merry-go-round and (b) the linear speed of the woman
Answer:
a) [tex]\omega=9.10*10^{-4}rad/sec[/tex]
b) [tex]V=1.8217*10^{-3}[/tex]
Explanation:
From the question we are told that:
Mass of woman [tex]M_w=55kg[/tex]
Radius of merry go round [tex]r=2.0m[/tex]
Rotational inertia [tex]i= 1250 kg-m2[/tex]
Mass of rock [tex]M_r=350g \approx 0.350kg[/tex]
Speed of rock [tex]V_r=2.0m/s[/tex]
Tangent angle to the outer edge [tex]\theta=1[/tex]
a)
Generally the equation for conservation of momentum is mathematically given by
[tex]M_r(ucos\theta)r=(I+M_wr^2)\omega[/tex]
[tex]0.350(2.0cos1)(2.0)=(1250+(55)(2.0)^2)\omega[/tex]
[tex]1.3998=1470\omega\\\omega=\frac{1.339}{1470}[/tex]
[tex]\omega=9.10*10^{-4}rad/sec[/tex]
b)
Generally the equation for linear speed V is mathematically given by
[tex]V=r\omega\\V=2.0*9.10*10^{-4}[/tex]
[tex]V=1.8217*10^{-3}[/tex]
A 1.0-kg cart and a 0.50-kg cart sit at different positions on a low-friction track. You push on the 1.0-kg cart with a constant 4.0-N force for 0.20 m. You then remove your hand, and the cart slides 0.35 m and strikes the 0.50-kg cart. What is the work done by you on the two-cart system? How far does the system's center of mass move while you are pushing the 1.0-kg cart? By what amount does your force change the kinetic energy of the system's center of mass?
Answer:
a)[tex]W=0.8J[/tex]
b) [tex]d_t=0.20m[/tex]
c) [tex]\triangle K.E=0.267J[/tex]
Explanation:
From the question we are told that:
Mass of cart 1 [tex]M_1=1.0kg[/tex]
Mass of cart 1 [tex]M_2=0.05kg[/tex]
Force on cart 1 [tex]F_1=4.0N[/tex]
Push Distance of cart 1 [tex]d_1=0.20m[/tex]
Slide Distance of cart 1 [tex]d_1'=0.35m[/tex]
a)
Generally the equation for work-done is mathematically given by
[tex]W=f*d\\W=4*0.20\\W=0.8J \\[/tex]
b)
The systems center of mass moved a net totally of (while being pushed)
Mass 1 =0.20m
Mass 2=0
Therefore
[tex]d_t=d_1+d_2[/tex]
[tex]d_t=0.20+0[/tex]
[tex]d_t=0.20m[/tex]
c)
Since work-done is equal to K.E energy of cart 1
Therefore
[tex]W=1/2mv^2[/tex]
[tex]V_1=\sqrt{\frac{W}{1/2m}}[/tex]
[tex]V_1=\sqrt{\frac{0.8}{1/2(1)}}[/tex]
[tex]V_1=1.264[/tex]
Therefore Kinetic energy before collision is
[tex]K.E_1=1/2mv^2[/tex]
[tex]K.E_1=1/2*1*1.264^2[/tex]
[tex]K.E_1=0.768[/tex]
Generally from the equation for conservation of momentum the Velocity of cart 2 is mathematically given by
[tex]v_2=\frac{m_1V_1}{m_1+m_2}[/tex]
[tex]v_2=\frac{1*1.264}{1+0.5}[/tex]
[tex]V_2=0.842m/s[/tex]
Therefore the final K.E is mathematically given by
[tex]K.E_2=(1/2)(m_1+m_2)V_2^2[/tex]
[tex]K.E_2=1/2*(1.5)(0.842)^2[/tex]
[tex]K.E_2=0.531J[/tex]
Generally the Change in K.E is mathematically given by
[tex]\triangle K.E=K.E_1-K.E_2[/tex]
[tex]\triangle K.E=0.798-0.531[/tex]
[tex]\triangle K.E=0.267J[/tex]
Therefore the will force change the kinetic energy of the system's center of mass by
[tex]\triangle K.E=0.267J[/tex]
(a) The work done by you when you push the cart at a constant force is 0.8 J.
(b) The distance moved by the center mass of the two cart system is 0.23 m.
(c) The change in kinetic energy of the system center of mass is 0.271 J.
Work done by you
The work done by you when you push the cart at a constant force is calculated as follows;
W = Fd
W = 4 x 0.2
W = 0.8 J
Distance moved by the center mass of the two cart systemlet the 0.5 kg mass be the reference mass at zero (0).Xcm = (m₁x₁ + m₂x₂)/(m₁ + m₂)
Xcm = (0.5(0) + 1(0.35)) / (1 + 0.5)
Xcm = (0.35)/(1.5)
Xcm = 0.23 m
Initial velocity of the 1.0 kg massF = ma
a = F/m
a = (4)/1 = 4 m/s²
v² = u² + 2as
v² = 0 + 2(4)(0.2)
v² = 1.6
v = √1.6
v = 1.265 m/s
Final velocity of the massesm₁u₁ + m₂u₂ = v(m₁ + m₂)
1(1.265) + 0 = v(1 + 0.5)
1.265 = 1.5v
v = 0.84 m/s
Change in kinetic energyK.E(initial) = ¹/₂m₁u₁² + ¹/₂m₂u₂²
K.E(initial) = ¹/₂(1)(1.265)² + ¹/₂(0.5)(0) = 0.8 J
K.E(final) = ¹/₂(m₁ + m₂)v²
K.E(final) = ¹/₂(1 + 0.5)(0.84)² = 0.529 J
Δ K.E = 0.8 J - 0.529 J = 0.271 J
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True or False question! ⬇⬇ Will give BRAINLIEST!
No matter the medium, light will always bend at the same angle when it passes from one medium to a different medium.
-True
-False
Answer:
Explanation:true
The system in the figure below, If atmospheric pressure is 101.3 KPa and the absolute pressure at the bottom of the tank is 231.3 KPa, what is the specific gravity of the olive oil?
If atmospheric pressure is 101.3 KPa and the absolute pressure at the bottom of the tank is 231.3 KPa, the specific gravity of the olive oil is 1.30
How do you calculate the gravity?To calculate the specific gravity, deduct the absolute pressure at the bottom of the tank (231.3 KPa) from the atmospheric pressure (101.3 KPa). This will give you a ratio of 130KPa, then divide it by the atmospheric pressure which is the specific gravity of olive oil.
Use the formula below:
specific gravity = absolute pressure - atmospheric pressure / atmospheric pressure
Specific gravity = (231.3 KPa - 101.3 KPa) / (101.3 KPa) = 1.30
Therefore, the specific gravity of the olive oil is 1.30.
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What is the atomic composition of methane
Answer:
As in chemical formula? It's CH4.