What is electric current?

Answer:A schema, or scheme, is an abstract concept proposed by J. Piaget to refer to our, well, abstract concepts.

Explanation:

Answer:C or B

Explanation:

Gases easily compress when pressure is applied, but liquids don't. So, option A.

The attracting and repellent forces that develop between the molecules of a substance are known as intermolecular forces.

Here,

The interactions between the individual molecules of a substance are mediated by the intermolecular forces. The majority of the physical and chemical features of matter are caused by intermolecular forces.

Compared to gases, which have relatively far-apart particles, liquids exhibit higher intermolecular forces due of the near proximity of their particles. The greater the intermolecular forces get as they get closer to one another since they are electrostatic in nature.

There is no force between particles in a gas. Particles have no restrictions on their movement. The container's walls colliding with one another provide the only forces that exist. which rely on the quantity of gas (number of collisions) and the momentum of each collision respectively. The pressure is nearly consistent throughout the entire mass of the gas because the molecules are free to move.

There is no compression of liquids. Since their volume is constant, changing pressure has no effect on it.

Hence,

Gases easily compress when pressure is applied, but liquids don't. So, option A.

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According to the given statement  5.50 *  10¹⁴Hz is the frequency of the incident light.

The photoelectric effect, which happens when light strikes a metal, can release electrons out of its surface. As the electrons that are expelled first from metal are known as emitted electrons, this process is also sometimes referred to as photoemission.

The following equation may be used to determine a photon's energy in terms of frequency:

E = hf

The work function must first be changed from electron volts (eV) to joules (J):

1 eV = 1.602 × 10⁻¹⁹ J

Hence, the work function is:

1.68 eV × 1.602 × 10⁻¹⁹ J/eV = 2.69 × 10⁻¹⁹ J

The emitted photon's kinetic energy is:

E = 9.60 × 10⁻²⁰ J

E = E0 + KE

where KE is the kinetic energy of the released electron and E0 is the work function.

Inputting the values, we obtain:

hf = E0 + KE

hf = 2.69 × 10⁻¹⁹ J + 9.60 × 10⁻²⁰J

hf = 3.65 × 10⁻¹⁹ J

When we solve for f, we obtain:

f = E/h = (3.65 × 10⁻¹⁹ J) / (6.626 × 10⁻³⁴ J s)

f = 5.50 × 10¹⁴ Hz

As a result, the incident light has a frequency of 5.50 *  10¹⁴Hz.

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The other ball will go up to a height of 4.3 m after the collision.

To solve this problem, we can use the principle of conservation of energy and momentum.

Let's first find the initial potential energy of the dropped ball:

E_i = mgh = 5 kg x 9.8 m/s² x 12 m = 588 J

When the ball hits the bar, the momentum is conserved:

m1v1 + m2v2 = (m1 + m2)vf

where;

We can simplify this equation by noting that the bar is initially at rest, so v2 = 0:

m1v1 + m2v2 = (m1 + m2)vf

5 kg x 0 m/s + 9 kg x 0 m/s = (5 kg + 9 kg + 5 kg)vf

vf = 0 m/s

This means that the system (the bar and the dropped ball) comes to a momentary stop just after the collision.

Now, let's find the final potential energy of the system:

E_f = (m1 + m2)gh

E_f = (5 kg + 9 kg) x 9.8 m/s² x h

E_f = 137.2 J x h

We can equate the initial and final energies:

E_i = E_f

588 J = 137.2 J x h

h = 4.3 m

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The distance  of the v-t graph as shown in the diagram is 1000 m.

To calculate the distance in a velocity-time graph, we find the total area under the graph

From the graph in the question above,

Where:

From the diagram,

Substitute these values into equation 1

Hence, the distance is 1000 m.

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The meteoroid that is most likely to reach the Earth's surface is the one with the highest mass-to-surface area ratio which is number 2. This is because as a meteoroid enters the Earth's atmosphere, it encounters a great deal of resistance, which generates heat due to friction.

Meteoroids are small rocky or metallic objects that are present in the solar system. They range in size from tiny particles to large boulders, and they can originate from comets, asteroids, or other celestial bodies. When a meteoroid enters the Earth's atmosphere, it becomes a meteor or a shooting star, and if it survives the descent and reaches the Earth's surface, it is then called a meteorite.

The meteoroid that is most likely to reach the Earth's surface is the one with the highest mass-to-surface area ratio. This is because as a meteoroid enters the Earth's atmosphere, it encounters a great deal of resistance, which generates heat due to friction. This heat is transferred to the meteoroid through conduction, and it can cause the meteoroid to vaporize or break apart. However, a larger meteoroid has more mass to dissipate this heat over, so it is less likely to be completely destroyed.

Additionally, a larger meteoroid has a smaller surface area to mass ratio, which means that there is less surface area to be heated and potentially destroyed by the heat generated during entry into the Earth's atmosphere. Therefore, a larger meteoroid with a higher mass-to-surface area ratio is more likely to survive and reach the Earth's surface.

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Meteoroid 2, with an initial mass of 3.24 kg, is most likely to reach the Earth's surface.

This is because the surface temperature of the meteoroid in space before entering the atmosphere is relatively high at 92°C, which means it has a greater amount of heat energy than the other meteoroids. When meteoroids enter the Earth's atmosphere, they encounter resistance from the air, which causes them to slow down and heat up due to friction.

The surface temperature of Meteoroid 2 at 150 km above the Earth's surface is 1727°C, which is higher than the other meteoroids. This suggests that Meteoroid 2 has a greater ability to resist the heat transfer from the high temperatures it reaches during entry into the Earth's atmosphere.

According to the table, the initial mass of Meteoroid 2 is the largest, and it also has the highest surface temperature in space. These factors contribute to the meteoroid's ability to resist heat transfer and increase the likelihood of it reaching the Earth's surface.

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We can use Faraday's Law of Electromagnetic Induction to find the induced emf (electromotive force) in the secondary coil:

emf = -N(dΦ/dt)

where

emf = induced emf

N = number of turns in the coil

dΦ/dt = rate of change of magnetic flux through the coil.

In this problem,

N = 12,000 turns, and the change in magnetic flux is:

dΦ = 740 uWb - 40 uWb = 700 uWb

The time interval for this change =180 us, or 180 x 10^-6 seconds. Therefore, the rate of change of magnetic flux is:

dΦ/dt = (700 uWb) / (180 x 10^-6 s) = 3.89 mWb/s

Now we can find the induced emf:

emf = -N(dΦ/dt) = -(12,000 turns)(3.89 mWb/s) = -46.68 volts

Note that the negative sign indicates that the induced emf will produce a current that opposes the change in magnetic flux that caused it.

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The velocity of ball B after impact would be2.7147 i + 2.6987 j ft/s

To solve this problem, we can use the conservation of momentum and energy.

First, let's find the momentum of ball A before the collision. The momentum is given by:

p = mv

The mass of each ball is the same, so we can write:

p_A = mV_A

where V_A is the velocity vector of ball A.

We can break V_A into its x and y components as follows:

V_Ax = V_A cos(θ)

V_Ay = V_A sin(θ)

where θ is the angle between the velocity vector and the x-axis.

Substituting in the given values, we get:

V_Ax = 3 cos(70°) = 0.9063 ft/s

V_Ay = 3 sin(70°) = 2.8830 ft/s

So, the momentum of ball A before the collision is:

p_A = mV_A = m (V_Ax i + V_Ay j) = m (0.9063 i + 2.8830 j) lb·ft/s

Next, we need to find the velocity of ball A after the collision. We can use conservation of momentum and energy to do this.

p_A + p_B = p_A' + p_B'

where p_B is the momentum of ball B before the collision, and p_A', p_B' are their respective momenta after the collision.

Since ball B is initially at rest, its momentum before the collision is zero:

p_B = 0

Conservation of energy tells us that the total kinetic energy of the system before the collision is equal to the total kinetic energy of the system after the collision:

1/2 m V_A^2 = 1/2 m V_A'^2 + 1/2 m V_B'^2

where V_A' and V_B' are the velocities of the balls after the collision.

We can use the coefficient of restitution (e) to relate the velocities of the balls before and after the collision:

e = (V_B' - V_A') / (V_A - V_B)

Substituting in the given values, we get:

e = (V_B' - V_A') / (3 - 0)

Solving for V_B', we get:

V_B' = e (V_A - V_B) + V_A'

Substituting in the known values, we get:

V_A' = (0.9063 i + 2.8830 j) ft/s

e = 0.9

Solving for V_B', we get:

V_B' = e (V_A - V_B) + V_A'

= 0.9 (3 i + 0 j) + (0.9063 i + 2.8830 j)

= 2.7147 i + 2.6987 j ft/s

So, the velocity of ball B after the collision is:

V_B' = 2.7147 i + 2.6987 j ft/s

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Answer:  I believe this constellation is cygnus, the swan.  The brightest star is Deneb at the tail.  The bright double star at the head of the swan is Albireo.

Explanation:  

I = M g sin / (L  B), where M, L,, and B are the provided variables and g is the acceleration due to gravity (9.81 m/s2), determines the amount of current in the wire that will keep it at rest.

The magnitude of the magnetic field is inversely related to the perpendicular distance from the wire and proportionate to the current.

We need to use the equation for the force on a current-carrying wire in a magnetic field to estimate the size of the current in the wire that will keep it at rest:

F = I L × B

The weight of the wire's component moving down the incline must be balanced by the force acting on the wire:

F = M g sinθ

For the wire to remain at rest, these two forces must be equal:

I L × B = M g sinθ

Solving for I, we get:

I = M g sinθ / (L × B)

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if in a binary star system a white dwarf exceeds this limit through mass transfer, it will explode and a Type Ia Supernova will be the end result.

Artificial satellites are launched into Earth's orbit for various purposes, including communication, navigation, weather monitoring, scientific research, and military surveillance.

Artificial satellites sent into Earth's orbit the Earth, typically at an altitude between 200 and 22,000 miles, depending on its intended purpose. Satellites in low Earth orbit (LEO) travel at a speed of about 17,500 miles per hour, completing one orbit in about 90 minutes, while satellites in geostationary orbit (GEO) remain stationary above the equator at an altitude of about 22,236 miles.

Satellites can remain in orbit for many years, but eventually, they can fall out of orbit due to atmospheric drag or collisions with space debris. When a satellite falls out of orbit, it typically burns up in Earth's atmosphere, although larger satellites may leave debris that can pose a risk to other spacecraft.

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Therefore, the heat energy per unit time per unit area, or flux, emitted by the body is approximately 241.7 W/m².

The heat transfer equation can be written as Q = m  c  T, where Q denotes the amount of heat transferred, m denotes mass, c denotes specific heat, and T denotes the temperature differential. Heat transfer is the process by which heat is transferred from a hot object to a cold object.

The Stefan-Boltzmann Law can be used to determine the thermal energy per unit time per unit area, or flux, released by a body:

F = σ * € * T⁴

To convert 20.0°C to Kelvin, we add 273.15 K to get 293.15 K.

Now we can plug in the values:

F = 5.67 x 10⁻⁸ W/m² K⁴ * 0.500 * (293.15 K)⁴

F ≈ 241.7 W/m²

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B=0I2R(at centre of loop), B = 0 I 2 R(at centre of loop), where R is the loop's radius, gives the magnetic field strength at the loop's centre.

The magnetic field strength diminishes with increasing radius. Radius of the loop has an inverse relationship with magnetic field intensity.

With its plane normal to an external field of magnitude 5.0102T, a circular coil with a radius of 10 cm and 16 turns that is carrying a current of 0.75 A is at rest. The coil is unrestricted in its ability to rotate around an axis in a plane perpendicular to the field direction.

Hence, the integral around any circle's diameter that is centred on a wire.

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To solve the problem, we can use the principle of conservation of heat, which states that the heat lost by the glass is gained by the alcohol.Let T be the initial temperature of the alcohol in degrees Celsius.The heat lost by the glass is given by:Q1 = mcΔT1where m is the mass of the glass, c is the specific heat capacity of glass, and ΔT1 is the change in temperature of the glass.Substituting the given values, we get:Q1 = (250 g) × (840 J/kg°C) × (60°C - T)The heat gained by the alcohol is given by:Q2 = mcΔT2where m is the mass of the alcohol, c is the specific heat capacity of alcohol, and ΔT2 is the change in temperature of the alcohol.Substituting the given values, we get:Q2 = (700 g) × (2500 J/kg°C) × (20°C - T)Since the total heat lost by the glass is equal to the total heat gained by the alcohol, we can set Q1 equal to Q2 and solve for T:Q1 = Q2(250 g) × (840 J/kg°C) × (60°C - T) = (700 g) × (2500 J/kg°C) × (20°C - T)Simplifying and solving for T, we get:T = 32.5°CTherefore, the initial temperature of the alcohol was 32.5°C.

Explanation:

Answer:

work = (37.0 kcal) - (82.5 kcal) = -45.5 kcal

Explanation:

The first law of thermodynamics states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system. In this case, the refrigerator is removing heat from the freezer and releasing it through the condenser on the back. Therefore, the work done by the compressor is:

work = heat removed - heat released

The negative sign indicates that work was done on the refrigerator by an external agent (e.g., an electric motor) to remove heat from the freezer and release it through the condenser.

I got you Bruv :)

The two parts of the model that are missing are as shown in the diagram:

Oxygen is essential for cellular respiration, which is the process by which cells convert food molecules (such as glucose) into energy in the form of ATP (adenosine triphosphate). Cellular respiration occurs in the mitochondria of cells and is a complex series of metabolic reactions that requires oxygen as the final electron acceptor in the electron transport chain.

Without oxygen, cellular respiration cannot proceed beyond glycolysis, which is the first step in the process. Glycolysis breaks down glucose into two molecules of pyruvate and produces a small amount of ATP. However, this process is not very efficient, and it cannot sustain cellular activity for very long.

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The number of nodes present in this standing wave is 6

A standing wave is a type of wave that remains in a constant position and does not propagate through a medium. Instead, it oscillates in place between two fixed points, creating a pattern of constructive and destructive interference.

In a standing wave, nodes are the points along the medium that remain stationary, with no displacement or movement of the medium. These nodes occur at locations where the displacement of the medium is always zero, meaning that the amplitude of the wave is zero at those points.

In other words, nodes are the points of minimum energy in the standing wave. They are the points where the crest of the wave meets the trough of the wave, resulting in the cancellation of the wave's amplitude. The distance between two adjacent nodes is half of the wavelength of the standing wave.

In this standing wave, the number of nodes present is 6

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An individual dropped the sandbag from a height of 63.504 metres.

The relationship between angular momentum L and moment of inertia I and angular speed, expressed in radians per second, is shown. Moment of inertia is different from mass in that it depends on both the form and location of the axis of rotation in addition to the amount of stuff present.

vf = vi + at

vf = 0 + (9.8 m/s²)(0.5 s)

vf = 4.9 m/s

vf = vi + at

0 = 12 m/s - (9.8 m/s²)t

t = 1.22 s

Δy = vi t + 1/2 a t²

Δy = (12 m/s)(1.22 s) + 1/2 (9.8 m/s²) (1.22 s)²

Δy = 7.33 m

Δy = vi t + 1/2 a t²

Δy = vi t + 1/2 a t²

0 = (4.2 m/s)(3.6 s) + 1/2 (9.8 m/s²) (3.6 s)² + Δy

Δy = -63.504 m

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Velocity of block B when it is at half of its path is approximately 10.17 m/s.

Law of conservation of energy is a fundamental principle in physics that states that energy cannot be created or destroyed, but can only be transformed from one form to another.

Potential energy of block B is : PE = mgh

m is mass of the block, g is acceleration due to gravity, and h is height of the block above the ground.

Initial potential energy of block B is: PEi = mgh = 70 kg × 9.81 m/s² × 15 m = 10290 J

When block B is at half of its path, its height above the ground is: h/2 = 15 m / 2 = 7.5 m

Final potential energy of block B at this height is: PEf = mgh/2 = 70 kg × 9.81 m/s² × 7.5 m = 5143.5 J

Change in potential energy is:

ΔPE = PEf - PEi = 5143.5 J - 10290 J = -5146.5 J

Kinetic energy of block B at half of its path is: KE = -ΔPE = 5146.5 J

Kinetic energy of block B is given by: KE = (1/2)mv²

v = √(2KE/m) = √(2ΔPE/m)

v = √(2 × 5146.5 J / 70 kg) = 10.17 m/s

Therefore,  velocity of block B when it is at half of its path is approximately 10.17 m/s.

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The speed of the car after the collision is determined as 0.2 m/s.

The speed of the car after the collision is calculated by applying the principle of conservation of linear momentum as follows;

m1u1 + m2u2 = v(m1 + m2)

where;

20000(3) - 40000(1.2) = v (20000 + 40000)

12,000 = 60,000v

v = 12,0000 / 60,000

v = 0.2 m/s

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Answer:

Explanation:

The dimensions for the flow of electric current is amperes, often denoted by "A" in scientific notation.

In terms of the base SI units, one ampere is defined as the flow of one coulomb of electric charge per second through a conductor. It can also be expressed in milliamperes or macro amperes which is equal to 1/1000 and 1/1000000 of amperes respectively.

The formula C = (20A) / d can be used to determine the capacitance of a circular parallel plate capacitor. As a result, the capacitor can store 0.000494 J of energy.

A charged parallel plate capacitor has 5 cm between its plates, and its internal electric field is 200 Vcm. The capacitor is totally submerged by a 2 cm wide uncharged metal bar. The metal bar's length is the same as the capacitor's.

C = (2πε₀A) / d

Where,

ε₀ = Permittivity of free space = [tex]8.854 × 10^−12 F/m[/tex]

A = Area of the plate =[tex]πr^2[/tex]

d = Distance between the plates

Therefore, the area of each plate (A) = [tex]πr^2 = π(0.05)^2 = 0.00785 m^2.[/tex]

[tex]C = (2πε₀A) / d = (2π × 8.854 × 10^−12 × 0.00785) / 0.002[/tex]

[tex]= 6.21 × 10^−11 F[/tex]So, the capacitance of the circular parallel plate capacitor is [tex]6.21 × 10^-11 F.[/tex]

[tex]U = 1/2 * C * V^2[/tex]

Substituting the values, we get:

[tex]U = 1/2 * 6.21 × 10^-11 * (200)^2[/tex]

= 0.000494 J

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A coal power station generates electricity by first burning coal to heat water into steam, then passing that steam through a turbine to make it spin.

A. Energy stores:

Chemical potential energy in the coal

Thermal energy in the water

Kinetic energy in the steam

Kinetic energy in the turbine

Electrical energy in the generator

Energy transfers:

Chemical potential energy in the coal to thermal energy in the water (by burning the coal)

Thermal energy in the water to kinetic energy in the steam (by boiling the water)

Kinetic energy in the steam to kinetic energy in the turbine (by passing through the turbine)

Kinetic energy in the turbine to electrical energy in the generator (by driving the generator)

B. Energy transferred into heat store of water: 20,000 J x 0.9 = 18,000 J

Energy dissipated in the turbine: 18,000 J x 0.3 = 5,400 J

Remaining energy after turbine: 18,000 J - 5,400 J = 12,600 J

Energy transferred as electrical energy: 12,600 J x 0.85 = 10,710 J

C. Power output = energy input per second = 10,000 J/s

So, the power output of the power station is 10,710 J/s (since 85% of the remaining energy is transferred as electrical energy).

D. Three specific improvements that could be made to the power station to make it more efficient are:

Implementing better combustion techniques to increase the efficiency of burning coal.

Using better insulation materials to minimize heat loss in the power station.

Using more efficient turbines and generators to convert kinetic energy to electrical energy.

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When a car is stopped, facing upwards on a hill, the friction acts in the opposite direction to the motion that the car would naturally take if it were not stopped.

In this case, the car would roll backwards down the hill due to the force of gravity. The friction between the tires and the road surface acts in the opposite direction to this motion, providing a force that opposes the car's tendency to roll backwards. Therefore, the friction acts in the forward direction, up the hill, to prevent the car from rolling backwards.

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The collision is perfectly elastic the velocity of object 2 after the collision is 44.0 cm/s to the right.

Substituting the given values, we get:

KE = (1/2)(0.0131 kg)(0.201 m/s)^2 + (1/2)(0.0324 kg)(0 m/s)^2

KE = 0.000132 J

Since the collision is perfectly elastic, the total kinetic energy of the system after the collision is also equal to KE. Therefore:

KE' = [tex](1/2)m_1v_1'^2 + (1/2)m_2v_2'^2[/tex]

where KE' is the kinetic energy of the system after the collision.

We can arrange this equation to solve for v2':

v2' = [tex]\sqrt{((2/m2)(KE' - (1/2)m1v1'^2))}[/tex]

Substituting the given values , we get:

v2' = [tex]\sqrt{((2/0.0324 kg)(0.000132 J - (1/2)(0.0131 kg)(20.1 m/s)^2))}\\[/tex]

v2' = 0.440 m/s

Finally, we need to convert the velocity back to cm/s:

v2' = 44.0 cm/s (rounded to three significant figures)

A collision refers to an event where two or more objects come into contact with each other, often resulting in damage or a change in the objects' trajectories. Collisions can occur in various contexts, including physics, engineering, and traffic accidents. In physics, a collision involves the transfer of momentum and energy between objects. The types of collisions include elastic collisions, where there is no loss of kinetic energy, and inelastic collisions, where some of the kinetic energy is lost.

In engineering, collisions can occur when designing structures or machines to prevent them from failing under extreme loads. For example, cars are designed with crumple zones to absorb the impact of a collision and protect the passengers.

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Answer: Min: 35

Max: 100

Mean: 73.53

Standard deviation (SX): 20.17

Mode: 72

Median: 72.5

Explanation:

Answer: speed

Explanation: On a distance vs. time graph, the slop of the line equals how fast an object is going.