The velocity of gas molecules in the gas phase and the temperature of the gas has: a direct relationship.
When gas molecules move they have kinetic energy, which is responsible for the velocity of gas molecules in the gas phase. The velocity of gas molecules depends on the temperature of the gas. As the temperature of the gas increases, the velocity of the gas molecules increases too.
The velocity of the gas molecules also depends on the mass of the gas molecules, temperature, and pressure of the gas. In other words, the velocity of gas molecules in the gas phase is directly proportional to the temperature of the gas. This relationship is known as the Kinetic Theory of Gases.
This theory states that the higher the temperature of a gas, the faster its molecules move. This is due to the increase in the kinetic energy of the gas molecules. When the temperature of the gas is increased, the kinetic energy of the molecules also increases.
This increase in kinetic energy causes the gas molecules to move faster, which results in an increase in the velocity of gas molecules in the gas phase. When the temperature of the gas is decreased, the kinetic energy of the molecules decreases, which results in a decrease in the velocity of gas molecules in the gas phase.
Therefore, the velocity of gas molecules in the gas phase is directly proportional to the temperature of the gas.
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a steady current was passed through molten s n s o 4 until 5.51 g of metallic tin was produced. calculate the coulombs of electricity used.
The coulombs of electricity used will be 9,650 C.
To calculate the coulombs of electricity used in this experiment, you must first determine the number of moles of SnSO4 that were reacted.
5.51 g of metallic tin produced indicates that 0.100 moles of SnSO4 were reacted.
Now, coulombs of electricity can be determined using the equation Q = I x t, where I is the current, and t is the time.
Using the information provided, we can determine that the coulombs of electricity used in this experiment is equal to (I x t) = (steady current x time until 5.51 g of metallic tin was produced).
The coulombs of electricity used in this experiment can also be determined by considering the Faraday’s constant, which states that the amount of electricity needed to completely react one mole of a substance is equal to 96,500 coulombs.
Since the reaction involves 0.100 moles of SnSO4, the amount of electricity used is equal to 0.100 moles x 96,500 coulombs, which is equal to 9,650 coulombs.
To summarize, the amount of coulombs of electricity used in this experiment is 9,650 coulombs, and this can be determined using the equation Q = I x t, or by considering the Faraday’s constant. This amount of coulombs of electricity was used until 5.51 g of metallic tin was produced.
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the most common end product of the chemical weathering of feldspar is clay minerals. pyroxene. amphibole. calcite.
The most common end product of the chemical weathering of feldspar is clay minerals.
Chemical weathering refers to the decomposition of rocks or minerals due to chemical reactions, water, or atmospheric gases.
The surface area of rocks or minerals is increased as they become more weathered, making them more susceptible to erosion. Clay minerals are the most common end product of the chemical weathering of feldspar.
This is because feldspar minerals are extremely reactive to acidic solutions in the environment, and they can easily become hydrolyzed.
Hydrolysis of feldspar:During hydrolysis, feldspar reacts with water to form clay minerals, silica, and soluble salts.
The hydrolysis reaction:KAlSi3O8 + 2H2O → Al2Si2O5(OH)4 + 4SiO2 + K+ + 2H+ + 2OH-Albite,
which is a type of feldspar, reacts with water to create kaolinite clay minerals, which is the most common end product of the reaction.
This reaction results in an increase in volume, which causes the rock to crack and disintegrate.
The reaction also produces silica, potassium, and aluminum ions, which can be transported by water to other locations.
Chemical weathering of feldspar has a significant impact on soil formation and the availability of nutrients in the environment.
The most common end product of the chemical weathering of feldspar is clay minerals, which plays a vital role in soil structure and plant growth.
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what is the molarity of the solution formed by dissolving 10.0g of ca(no3)2 in 250 ml aqueous solution
Answer: The molarity of the solution formed by dissolving 10.0g of Ca(NO3)2 in 250 mL of aqueous solution is
0.244 M.
The molarity of the solution formed by dissolving 10.0g of Ca(NO3)2 in 250 mL of aqueous solution can be calculated using the following equation: Molarity (M) = (moles of solute / liters of solution).
In this case, we have 10.0 g of Ca(NO3)2, so we first need to convert it to moles. To do this, we multiply the grams of Ca(NO3)2 by its molar mass, which is 164.08 g/mol: 10.0 g × (1 mol/164.08 g) = 0.061 mol.
We also have 250 mL of aqueous solution, which is equivalent to 0.25 L. Plugging these values into the equation above gives us: M = (0.061 mol/0.25 L) = 0.244 M.
Therefore, the molarity of the solution formed by dissolving 10.0g of Ca(NO3)2 in 250 mL of aqueous solution is 0.244 M.
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how many moles of oh- are in 55.85 ml of 0.350 m naoh? do not include units and place answers in 3 sig figs. be sure to include any zeros before the decimal and do not put answer in scientific notation.
The number of moles of OH- in 55.85 mL of 0.350 M NaOH is 0.01976 moles.
This can be calculated using the following equation:
the number of moles of OH- in 55.85 mL of 0.350 M NaOH is 0.01976 moles with 3 significant figures.
To determine the number of moles of OH⁻ present in 55.85 mL of 0.350 M NaOH, we use the formula;
Molarity = Moles of solute ÷ Volume of solution in L
It can be simplified to:
Molarity = Moles of solute ÷ (Volume of solution in mL ÷ 1000)Moles of solute = Molarity × (Volume of solution in mL ÷ 1000)
Thus, the number of moles of OH⁻ present in 55.85 mL of 0.350 M NaOH is given by;
Moles of OH⁻ = 0.350 M × (55.85 mL ÷ 1000) = 0.0196 moles
Therefore, there are 0.0196 moles of OH⁻ present in 55.85 mL of 0.350 M NaOH.
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•••••PLEASE HELP!Determine the maximum amount of NaNO that was produced during the experiment. Explain how you determined this amount.
The maximum amount of NaNO₃ that can be produced during the experiment is 9 moles
How do i determine the maximum amount of NaNO₃ produced?First, we shall obtain the limiting reactant. Details below:
Al(NO₃)₃ + 3NaCl -> 3NaNO₃ + AlCl₃
From the balanced equation above,
1 mole of Al(NO₃)₃ reacted with 3 moles of NaCl
Therefore,
4 moles of Al(NO₃)₃ will react with = 4 × 3 = 12 moles of NaCl
Thus, we can see that a higher amount of NaCl is needed to react with 4 moles of Al(NO₃)₃. Therefore, NaCl is the limiting reactant.
Finally, we can determine the maximum amount of NaNO₃ produced. Details below:
From the balanced equation above,
3 moles of NaCl reacted to produce 3 mole of NaNO₃
Therefore,
9 moles of NaCl will also react to produce 9 moles of NaNO₃
Thus, the maximum amount of NaNO₃ produced is 9 moles
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what is the major reason that physical properties do not differ much from one gaseous substance to another
One of the major reasons that physical properties do not differ much from one gaseous substance to another is that gases have weak intermolecular forces between their particles.
The physical properties of a substance are those characteristics that can be measured or observed without causing any change in the substance's identity or composition.
The physical properties of gases include their volume, mass, pressure, temperature, and density.
Boyle's law, Charles's law, and Avogadro's law are three important gas laws that help to describe the physical behavior of gases.
Boyle's law describes the relationship between volume and pressure at a constant temperature.
Charles's law describes the relationship between volume and temperature at a constant pressure.
Avogadro's law describes the relationship between volume and the number of particles at a constant temperature and pressure.
Gases can expand or contract based on the conditions under which they are being held. Gases are highly compressible, and they fill any container that they are placed in.
Because gases have weak intermolecular forces, they can move about freely and do not have a fixed shape.
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which type of equilibrium is more likely to omit substances from the equilibrium constant expression? select the correct answer below: homogeneous equilibria heterogeneous equilibria a and b are equally likely there is no correlation
The correct answer for the type of equilibrium that is more likely to omit substances from the equilibrium constant expression is option a) heterogeneous equilibria.
Heterogeneous equilibria are equilibria in which reactants and products exist in two or more phases, such as gas and liquid, or liquid and solid. The equilibrium constant for these types of equilibria does not include any of the substances in the other phase.
For example, if a reaction is occurring in a liquid solution, but some of the reactants and products are gases, then the equilibrium constant will only include the substances that are in the liquid phase.
In contrast, homogeneous equilibria involve all reactants and products in the same phase, such as a gas or a liquid. As a result, the equilibrium constant expression will include all of the substances.
Therefore, heterogeneous equilibria are more likely to omit substances from the equilibrium constant expression.
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what nacl nacl concentration results when 279 ml 279 ml of a 0.840 m 0.840 m nacl nacl solution is mixed with 442 ml 442 ml of a 0.220 m 0.220 m nacl nacl solution?
The final NaCl concentration when 279 ml of a 0.840 m NaCl solution is mixed with 442 ml of a 0.220 m NaCl solution is 0.46 m NaCl.
To calculate this, the formula for mixing two solutions of different concentrations is:
C₁V₁ + C₂V₂ = CfVf,
where C₁ and C₂ are the concentrations of each solution, V₁ and V₂ are the volumes of each solution, and Cf and Vf are the final concentration and volume, respectively.
Using the formula, we can calculate the final NaCl concentration to be 0.476 m by solving for Cf.
Cf = (C₁V₁ + C₂V₂) / Vf
Cf = ((0.840 m × 279 ml) + (0.220 m × 442 ml)) / (279 ml + 442 ml)
Cf = 0.476 m NaCl.
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calculate the enthalpy change when 100. g of ice at 0.0 oc is heated to liquid water at 50.0oc. (the heat of fusion for water is 333 j/g.)
The enthalpy change when 100. g of ice at 0.0°C is heated to liquid water at 50.0°C is equal to 333J/g x 100g = 33300 J.
This is because the heat of fusion of water is 333J/g and it takes 33300J of energy to melt 100g of ice at 0.0°C.
The process of melting the ice can be broken down into two steps. First, the ice needs to be heated from 0.0°C to its melting point (0.0°C).
This requires energy to overcome the intermolecular forces that are keeping the ice solid, but no heat is absorbed or released. Second, the ice needs to be heated from its melting point to 50.0°C.
This is when the heat of fusion is released and 333J of energy is absorbed for every gram of ice melted. Therefore, 333J/g x 100g = 33300J of energy must be supplied to the system for the ice to melt and reach 50.0°C.
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half of the estuarine area has waters falling below a certain do concentration level, and the other half has levels above that level. what is that level, in mg/l?
Half of the estuarine area has waters falling below a certain DO concentration level, and the other half has levels above that level. The level of DO concentration is 2.0 mg/L.
This is because the minimum level of dissolved oxygen in estuaries is 2.0 mg/L, below which the fish and other aquatic life will suffer from hypoxia or low oxygen levels, which may lead to fish kills and other negative impacts on the estuarine ecosystem. The division of estuarine waters into hypoxic and non-hypoxic zones at 2.0 mg/L has been a useful and widely used tool in estuarine ecology, water quality monitoring, and ecosystem management. This level is also used as a regulatory limit in many countries to protect aquatic life and to ensure the estuarine ecosystem's health and sustainability.
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the unit cell for perovskite is shown. this is a mineral containing calcium, titanium, and oxide ions. the titanium is the grey sphere, the calcium ions are black spheres, and the oxide ions are white spheres. what is the empirical formula of the salt.
The empirical formula of the salt is CaTiO3. The perovskite mineral has a unit cell that consists of calcium, titanium, and oxide ions. The grey sphere in the unit cell represents titanium while the black spheres represent calcium ions and the white spheres represent oxide ions.The empirical formula of a salt is the simplest whole number ratio of the atoms in a
compound. The perovskite mineral contains one calcium ion, one titanium ion, and three oxide ions in its unit cell. Therefore, the empirical formula of the salt can be calculated by dividing the number of each ion by the greatest
common factor of the ions. In this case, the greatest common factor is one, which means the empirical formula is the same as the molecular formula.CaTiO3 is the molecular formula of the perovskite mineral and it is also the empirical
formula since the ratio of the atoms in the compound is already in its simplest whole number form.
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Enter your answer in the provided box. Calculate the maximum wavelength of light (in nm) required to ionize a single potassium atom. The first ionization energy of K is 419 kJ/mol.
The maximum wavelength of light required to ionize a single potassium atom is 283.6 nm.
What is Wavelength?
Wavelength is the distance between two consecutive points in a wave that are in phase with each other. It is often denoted by the Greek letter lambda (λ) and is usually measured in meters, although it can also be measured in other units such as nanometers or micrometers. Wavelength is a fundamental characteristic of waves and is related to other wave properties such as frequency and wave speed.
To calculate the maximum wavelength of light required to ionize a single potassium atom, we can use the formula:
λ = hc/E
where λ is the maximum wavelength, h is Planck's constant , c is the speed of light , and E is the first ionization energy of potassium in joules.
First, we need to convert the first ionization energy of K from kJ/mol to joules per atom:
419 kJ/mol / (6.022 x[tex]10^{23}[/tex] atoms/mol) = 6.973 x [tex]10^{-19}[/tex] J/atom
Now we can plug in the values and solve for λ:
λ = (6.626 x[tex]10^{34}[/tex]J s) x (2.998 x [tex]10^{8}[/tex] m/s) / (6.973 x [tex]10^{-19}[/tex] J/atom)
λ = 283.6 nm
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compare the processes that occur when methanol (ch3oh), hydrogen chloride (hcl), and sodium hydroxide (naoh) dissolve in water. write equations and prepare sketches showing the form in which each of these compounds is present in its respective solution.
The processes that occur are:
Methanol (CH3OH) Dissolution: CH3OH + H2O → CH3OH2+ + OH−
Hydrogen Chloride (HCl) Dissolution: HCl + H2O → H3O+ + Cl−
Sodium Hydroxide (NaOH) Dissolution: NaOH + H2O → Na+ + OH−
Methanol (CH3OH), hydrogen chloride (HCl) and sodium hydroxide (NaOH) all dissolve in water. When these compounds dissolve in water, different processes occur.
When methanol dissolves in water, it forms an ionic bond, where the positive hydrogen atoms of the methanol molecule interact with the negative oxygen atoms of the water molecule.
This process is known as hydrogen bonding, and is represented in the following equation: CH3OH + H2O → CH3OH2+ + OH−.
When hydrogen chloride dissolves in water, it undergoes hydrolysis, where the HCl molecule separates into a hydrogen ion (H+) and chloride ion (Cl-). This is represented in the following equation: HCl + H2O → H3O+ + Cl−.
Lastly, when sodium hydroxide dissolves in water, it forms an ionic bond, where the NaOH molecule separates into a sodium ion (Na+) and hydroxide ion (OH-).
This is represented in the following equation: NaOH + H2O → Na+ + OH−.
In summary, methanol undergoes hydrogen bonding, hydrogen chloride undergoes hydrolysis, and sodium hydroxide forms an ionic bond when dissolved in water.
The chemical equations and sketches for each process are included below:
Methanol (CH3OH) Dissolution: CH3OH + H2O → CH3OH2+ + OH−
Hydrogen Chloride (HCl) Dissolution: HCl + H2O → H3O+ + Cl−
Sodium Hydroxide (NaOH) Dissolution: NaOH + H2O → Na+ + OH−
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A large forest of trees was recently cut down. Which of the following effects, relating only to photosynthesis, is most likely to occur in this area as a result?
a An decrease in carbon dioxide in the air
b An increase in sunlight
c A decrease in oxygen in the air
d An increase in glucose (sugar) in the area
Answer:
c.no is a correct answer
calculate the percent recovery from the acetanilide recrystallization. show calculation with units and correct significant digits. was this recrystallization successful at purifying the acetanilide? use your written observations of the physical appearance of the acetanilide (before and after recrystallization) and the melting point range of the purified acetanilide as evidence.
The percent recovery of acetanilide recrystallization is: 75.5%,
the physical appearance of the purified acetanilide was: white, fine-grained crystals
and the melting point range of the purified acetanilide was: 114.6-116.9 °C
Explanation:
The percent recovery of acetanilide recrystallization is as follows: Initial weight of acetanilide = 2.245 g
Weight of filter paper = 0.343 g
Weight of filter paper + purified acetanilide = 2.633 g
Weight of purified acetanilide = (2.633 - 0.343) g = 2.290 g
Percent recovery = (Weight of purified acetanilide / Initial weight of acetanilide) × 100= (2.290 / 3.032) × 100 = 75.5%
Since the percent recovery is greater than 60%, we can say that the acetanilide recrystallization was successful at purifying the acetanilide.
The physical appearance of the purified acetanilide was white, fine-grained crystals, and the melting point range of the purified acetanilide was 114.6-116.9 °C. Both the physical appearance and melting point range confirm that the acetanilide was purified through the recrystallization process.
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Nuclear fission occurs when a neutron strikes the nucleus of a uranium-235 atom. The illustration models the chain reaction that can result. Which statement describes how a chain reaction results from the nuclear fission of uranium-235? A. It produces an enormous amount of energy in the form of heat. B. It takes enormous amounts of heat to get the reaction started. C. It produces neutrons that strike other nuclei and cause more fission. D. It uses a type of nuclear fuel that has a very short half-life.
The statement that describes how a chain reaction results from the nuclear fission of uranium-235 is: It produces neutrons that strike other nuclei and cause more fission.
Option C.
What happens when a neutron strikes a nucleus?When a neutron strikes the nucleus of a uranium-235 atom, the nucleus splits into two smaller nuclei and releases two or three neutrons.
These neutrons can then go on to strike other uranium-235 nuclei, causing them to undergo fission and releasing more neutrons. This process continues in a chain reaction, producing a large amount of energy in the form of heat.
However, in order to sustain the chain reaction, there must be enough uranium-235 present and the neutrons must be slowed down to increase the probability of their striking other nuclei.
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0.1mol of a substance has a mass of 4g. Calculate the mass of 1 mol
Answer:
The mass of 1 mole of substance is 40 g
Molar Mass is defined as the mass in grams of one mole of a substance. The units of molar mass are grams per mole (g/mol).
This can be found by dividing the mass present by the number of moles. Mathematically, the units: grams ÷ moles = g/mol.
Hence, Molar mass (M) = mass (m) ÷ moles (n).
Therefore, M = m/n = 4/0.1 = 40 g/mol
how many grams of glucose (c6h12o6 ) would you need to prepare 1.25 l of 4% (by mass) glucose solution? assume that the percentage by mass is the number of grams per 100 ml of solution.
To prepare 1.25 L of 4% (by mass) glucose solution, the amount of glucose (C6H12O6) needed is approximately 50 grams.
Glucose is a monosaccharide with the molecular formula C6H12O6. It is also known as dextrose, grape sugar, or blood sugar. Glucose is produced by photosynthesis in green plants and is the main source of energy for the cells of the human body. Glucose is a carbohydrate with a chemical structure similar to other sugars.
A 4% (by mass) glucose solution is a solution that contains 4 grams of glucose in 100 ml of water. It is also known as a 4% weight/volume (w/v) solution. This solution is often used in medical settings to treat hypoglycemia, or low blood sugar levels.
To calculate the amount of glucose (C6H12O6) needed to prepare a 4% (by mass) glucose solution:
Step 1: Convert the volume of the solution to milliliters.1.25 L x 1000 mL/L = 1250 mL
Step 2: Calculate the mass of glucose needed to make a 4% (by mass) solution.4 g glucose/100 mL solution x 1250 mL solution = 50 g glucose
Therefore, approximately 50 grams of glucose (C6H12O6) would be needed to prepare 1.25 L of a 4% (by mass) glucose solution.
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hydration occurs when mineralsgroup of answer choicesare dissolved into water.are turned into rust.absorb water and expand.are removed by frost.
Hydration occurs when minerals are dissolved in water. This means that minerals absorb water and expand. Hence, the correct answer is dissolved into water.
Hydration is the procedure of blending an element with water. It's a chemical reaction that takes place between a chemical compound and water molecules, which helps to break down and dissolve the substance being hydrated.
The hydration process in chemistry entails taking a substance and breaking it down into its component parts. This occurs when a compound or molecule takes in water, which results in the separation of the bonds between the atoms or ions.
The newly-formed ions interact with the water molecules, resulting in a new, hydrated compound.
Hydration can also occur naturally in the body. This is why it is essential to drink enough water throughout the day to remain hydrated. Therefore the correct answer is dissolved into water.
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g which of the following is an important organic solvent? a. acetone b. menthone c. phenol d. citral
An organic solvent is a liquid that has the ability to dissolve, extract, or suspend another substance to make a solution. An important organic solvent is acetone. The correct option is A.
What is an organic solvent?An organic solvent is a liquid that has the ability to dissolve, extract, or suspend another substance to make a solution. Organic solvents are essential in a variety of industries, including pharmaceuticals, agriculture, paints, coatings, cleaning, and printing, among others.
They are used in the formulation of many products that we use in our daily lives. For example, in the paint and coatings industry, organic solvents are used to dissolve and disperse the ingredients of the paint, which then evaporates, leaving behind a solid coating.
Among the options given, acetone is the most important organic solvent. It is a colorless, flammable liquid that has a distinctive sweet odor.
Acetone is a versatile solvent that is used in a wide range of industries, including the production of chemicals, plastics, and fibers. It is also used as a solvent in paint, ink, and varnish, and it is used as a cleaning agent in a variety of applications.
Additionally, acetone is used in the manufacture of pharmaceuticals and cosmetics. It is also used as a fuel additive and a solvent in the production of biodiesel.
Among the other options given, menthone, phenol, and citral are not organic solvents. Menthone is a terpenoid that is used in the flavor and fragrance industry.
Phenol is an aromatic compound that is used as an antiseptic and disinfectant. Citral is a fragrance compound that is used in the production of perfumes and other fragrances.
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what are the main reasons that gases deviate from ideal behavior?
The main reasons that gases deviate from ideal behavior are due to two factors: intermolecular forces and the volume of gas particles.
1. Intermolecular forces: In an ideal gas, it is assumed that there are no attractive or repulsive forces between the gas particles. However, in real gases, intermolecular forces do exist. These forces can cause gas particles to attract or repel each other, resulting in deviations from ideal behavior.
2. Volume of gas particles: Ideal gas laws assume that gas particles have no volume, meaning they are considered point masses. In reality, gas particles have a finite volume, which becomes significant at high pressures and low temperatures. This can also lead to deviations from ideal gas behavior.
In summary, gases deviate from ideal behavior mainly due to the presence of intermolecular forces and the volume of gas particles.
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When adding the measurements 42. 1014 g + 190. 5 g, the answer has Significant figures
When adding the measurements 42. 1014 g + 190. 5 g, we get 7 significant figures. Those 7 significant figures are 2, 3, 2, 6, 0, 1 and 4.
Significant figures can be defined as the number of digits in a value which is often a measurement which contribute to the degree of accuracy of the value. We can start counting all the significant figures by starting the first non-zero digit. Significant figures of a number in positional notation are defined as digits in the number that are reliable and necessary to indicate the quantity of something. All zeros that occur between any two non zero digits are significant figures. Significant figures are known as the digits of a number which are meaningful in the terms of accuracy or in the term of precision. That involves any non-zero digits. When we are adding the measurements 42. 1014 g + 190. 5 g, the predicted 7 significant figures as it appears between the two non zero digits.
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The complete question is,
When adding the measurements 42. 1014 g + 190. 5 g, the answer has ----------Significant figures.
what volume of a soft drink that is 10.5% sucrose (c12h22o11) by mass contains 78.5 g of sucrose? the density of the solution is 1.04 g/ml.
The volume of the soft drink that is 10.5% sucrose by mass is 718.86 mL.
To find the volume of a soft drink that contains 78.5 g of sucrose (C₁₂H₂O₁₁) with 10.5% sucrose by mass, we can start by calculating the total mass of the solution. This can be calculated using the following equation:
total mass = 78.5 g / 0.105 = 747.619 g
The 10.5% sucrose by mass means that for every 100 g of the soft drink, 10.5 g is sucrose.
As the density of the solution is 1.04 g/mL, the volume of the solution is calculated by dividing the mass of solution by the density of the solution.
V = 747.619 g / 1.04 g/mL = 718.86 mL
Therefore, the volume of the soft drink is 718.86 mL.
It is important to note that the calculation used in this example assumes that the sucrose (C₁₂H₂O₁₁) is the only solute in the solution. If there are other solutes present in the solution, then the calculation needs to be adjusted accordingly.
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15. why is it important to take both the polarity of the bonds and the shape of the molecule into consideration when determining the polarity of the molecule?
The polarity of a molecule is determined by both the type of bonds and the shape of the molecule. Polar bonds result in a molecule being polar, while non-polar bonds result in a molecule being non-polar. The shape of the molecule can also affect the polarity of the molecule. Molecules that are symmetrical are non-polar, while those that are asymmetrical are polar.
Polar bonds occur when two atoms share electrons unequally, leading to a permanent dipole moment. These molecules are said to be polar. On the other hand, non-polar molecules occur when the atoms involved in the bond share electrons equally, resulting in a non-polar molecule.
The shape of the molecule also plays a role in determining the polarity of the molecule. If the shape of the molecule is symmetrical, with an equal distribution of electrons, then it is considered non-polar.
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given 7.00 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100 % yield?
Answer:
The reaction between butanoic acid and ethanol produces ethyl butyrate and water, and the balanced chemical equation is:
Butanoic acid + Ethanol → Ethyl butyrate + Water
The molar mass of butanoic acid is 88.1 g/mol, and the molar mass of ethanol is 46.1 g/mol. The molar mass of ethyl butyrate is 116.2 g/mol.
To determine the amount of ethyl butyrate produced, we need to use stoichiometry and the given mass of butanoic acid to find the number of moles of butanoic acid, and then use the mole ratio to find the number of moles (and mass) of ethyl butyrate produced.
Calculate the number of moles of butanoic acid:
moles of butanoic acid = mass/molar mass = 7.00 g / 88.1 g/mol = 0.0795 mol
Use the mole ratio to find the number of moles of ethyl butyrate produced:
From the balanced equation, we see that 1 mole of butanoic acid reacts with 1 mole of ethanol to produce 1 mole of ethyl butyrate.
So, the number of moles of ethyl butyrate produced = 0.0795 mol (since we assume a 100% yield)
Calculate the mass of ethyl butyrate produced:
mass of ethyl butyrate = moles x molar mass = 0.0795 mol x 116.2 g/mol = 9.23 g
Therefore, 9.23 grams of ethyl butyrate would be synthesized if 7.00 grams of butanoic acid were reacted with excess ethanol, assuming a complete 100% yield.
if 3.43 mol 3.43 mol of an ideal gas has a pressure of 2.17 atm 2.17 atm and a volume of 68.83 l, 68.83 l, what is the temperature of the sample in degrees celsius?
The temperature of the sample in degrees Celsius is 257.5 °C.
The temperature of the sample can be calculated using the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature.
In this case, P = 2.17 atm, V = 68.83 L, n = 3.43 mol, and R = 0.08206 L atm mol-1 K-1.
Rearranging the equation will give us the equation for the temperature, T.
T = PV/nR
Pugging in the values, we get:
T = (2.17 atm)(68.83 L) / (3.43 mol)(0.08206 L atm/mol K)
T = 530.65 K
Converting Kelvin to degree Celcius, we have:
T = 530.65 - 273.15 = 257.5 °C
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explain why the diborane solution is added drop-wise to a vial cooled in an ice bath over a period of 5 minutes.
The diborane solution is added drop-wise to a vial cooled in an ice bath over a period of 5 minutes to control the exothermic reaction that occurs between diborane and methanol.
Diborane (B2H6) is a colorless gas that burns in air and is toxic, it is a boron hydride and is a good reducing agent due to its tendency to release hydrogen gas. Diborane reacts vigorously with water and alcohols and is, therefore, used as a reagent in organic chemistry for hydroboration reactions.
An ice bath is a type of temperature-controlled bath used in science and engineering experiments, it is used to keep a reaction mixture cool while it is being stirred or shaken. An ice bath is prepared by adding ice to a container, such as a bucket or a beaker, and adding water to cover the ice. The reaction mixture is then placed in a smaller container, such as a vial, and placed inside the ice bath. The reaction mixture is cooled by the ice bath and is protected from overheating.
Diborane reacts vigorously with methanol, which is a common solvent used in organic chemistry. The reaction is exothermic and can produce a large amount of heat. To prevent the reaction from overheating and causing a fire or explosion, diborane solution is added drop-wise to a vial cooled in an ice bath over a period of 5 minutes. The slow addition of diborane solution and the use of an ice bath help to control the reaction and prevent it from becoming too hot.
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How many reaction schemes involving the alkene should you have in the "Reactions" section of your Pre-lab notebook?
4
1
3
2
In the "Reactions" section of your Pre-lab notebook, you should have two reaction schemes involving the alkene. The correct answer is option d.
The Pre-lab notebook is a collection of worksheets and pre-lab assignments that students must finish before lab. This may include preparing solutions, making graphs, filling out data tables, or writing lab reports.A pre-lab notebook is a place where students may record and evaluate their work before and during a laboratory session. It is a document that is kept by the student and used to help them comprehend the material that is presented to them.
The Pre-lab notebook is divided into three sections: the Procedures section, the Data section, and the Reactions section. An alkene is a hydrocarbon that contains a carbon-carbon double bond. Alkenes are typically unsaturated and highly reactive. Alkenes are used in a variety of industries, including the production of plastics, synthetic rubbers, and fibers. Alkenes are also used as solvents in many applications.
They are known for their ability to react with a variety of other compounds. This will ensure you cover a range of possible reactions and provide a comprehensive understanding of the alkene's behavior in different situations.
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How many grams of chlorine gas can be liberated from the decomposition of 169. 0 g. Of AuCl3
169.0 g of [tex]AuCl _{3}[/tex] can liberate 118.4 g of [tex]Cl_{2}[/tex] gas upon decomposition. The molar mass of [tex]AuCl _{3}[/tex] is 303.33 g/mol, which means that 1 mole of [tex]AuCl _{3}[/tex]contains 3 moles of chlorine (3 atoms of chlorine).
To determine the moles of [tex]AuCl _{3}[/tex]in 169.0 g, we divide the mass by the molar mass:
169.0 g / 303.33 g/mol = 0.557 moles of [tex]AuCl _{3}[/tex]
Since each mole of [tex]AuCl _{3}[/tex] produces 3 moles of chlorine, the total moles of chlorine that can be liberated from the decomposition of 0.557 moles of [tex]AuCl _{3}[/tex]is:
0.557 moles x 3 = 1.671 moles of [tex]Cl_{2}[/tex]
Finally, we use the molar mass of chlorine ([tex]Cl_{2}[/tex]), which is 70.90 g/mol, to convert the moles of [tex]Cl_{2}[/tex]to grams:
1.671 moles x 70.90 g/mol = 118.4 g of [tex]Cl_{2}[/tex]
Therefore, 169.0 g of [tex]AuCl _{3}[/tex]can liberate 118.4 g of [tex]Cl_{2}[/tex]gas upon decomposition.
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you can purchase nitric acid in a concentrated form that is 70.3% by mass and has a density of 1.41 g/ml. describe exactly how you would prepare 1.15 l of 0.100 m from the concentrated solution.
Answer: To prepare 1.15 L of 0.100 M Nitric Acid from a 70.3% by mass concentrated solution with a density of 1.41 g/ml, you must use 2.765 g of the concentrated solution.
In order to prepare 1.15 L of 0.100 M Nitric Acid from a 70.3% by mass concentrated solution with a density of 1.41 g/ml, you need to first calculate the moles of Nitric Acid present in the 1.15 L of the solution. To do this, multiply the density of the solution (1.41 g/ml) by the volume of the solution (1.15 L) to obtain the mass of the solution (1.615 g). Then, divide the mass of the solution (1.615 g) by the molar mass of Nitric Acid (63.01 g/mol) to obtain the number of moles present in the solution (0.02547 moles).
Next, you must determine the volume of the concentrated solution required to obtain 0.100 M of Nitric Acid in 1.15 L of the solution. To do this, divide the number of moles of Nitric Acid required in the solution (0.100 moles) by the number of moles of Nitric Acid present in the 1.15 L solution (0.02547 moles) to obtain the volume of the concentrated solution needed (3.933 L).
Finally, you can calculate the amount of the concentrated solution required to make the desired 1.15 L of 0.100 M Nitric Acid solution. To do this, multiply the volume of the concentrated solution required (3.933 L) by the mass percentage of the concentrated solution (70.3%) to obtain the mass of the concentrated solution needed (2.765 g).
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