What is the balanced equation of KOH + HCl -> KCl + H2O

Gay-Lussac's Law-

[tex] \:\:\:\:\:\:\star\longrightarrow \underline{\sf \boxed{\sf \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}}}[/tex]

[tex] \:\:\:\:\:\:\star\longrightarrow \sf \underline{P_2=\dfrac{P_1 \:T_2}{T_1}}[/tex]

Where-

As per question, we are given -

Now that we are given all the required values, so we can put them into the formula and solve for P₂:-

[tex] \:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf P_2=\dfrac{P_1 \:T_2}{T_1}\\[/tex]

[tex] \:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf P_2=\dfrac{6.8\times 211}{539}\\[/tex]

[tex]\:\:\:\:\:\: \:\:\:\:\:\:\longrightarrow \sf P_2 = \dfrac{1434.8}{539}\\[/tex]

[tex] \:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf P_2 = 2.661966.........\\[/tex]

[tex]\:\:\:\:\:\: \:\:\:\:\:\:\longrightarrow \sf\underline{ P_2 = 2.7 \:KPa}\\[/tex]

Therefore, If the temperature decreases to 211K, then the new pressure will become 2.7 KPa.

The cold pack is designed to address the problem of pain and swelling due to injury or inflammation.

A cold pack, also known as a cold compress, is a medical device designed to provide cold therapy to a specific area of the body. It typically consists of a gel-filled plastic bag or pouch that is placed in the freezer for a period of time to lower its temperature.

When applied to the affected area, the cold temperature helps to reduce blood flow, which in turn reduces inflammation, swelling, and pain. Cold packs are commonly used to treat minor injuries such as sprains, strains, and bruises, as well as to alleviate pain and swelling associated with chronic conditions like arthritis.

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The heat that is going to be released in the reaction can be obtained as 930.3 kJ.

The heat of reaction, also known as the enthalpy change of a reaction, is the amount of heat energy that is released or absorbed during a chemical reaction. It is denoted by the symbol ΔH and has units of joules per mole (J/mol) or kilojoules per mole (kJ/mol).

Number of moles of butane = 41.06g/58 g/mol = 0.7 moles

If 2 mole release 2658 kJ

0.7 moles will release 0.7 * 2658/2

= 930.3 kJ

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The partial pressure of IBr after equilibrium is reached is:

P_IBr = 0.029 - x = 0.0265 atm.

What is Equilibrium?

In chemistry, equilibrium refers to a state in which the rates of the forward and reverse reactions are equal, resulting in a stable concentration of products and reactants. In other words, equilibrium occurs when the concentrations of reactants and products remain constant over time. The concept of equilibrium is important in many areas of chemistry, including chemical reactions, acid-base equilibria, and solubility equilibria.

We can start by setting up an ICE table:

2IBr(g) I2(g) Br2(g)

Initial 0.029 atm 0 atm 0 atm

Change -x +x +x

Equil. 0.029-x x x

The equilibrium constant expression for the reaction is:

Kp = (P_I2 * P_Br2) / P_IBr^2

At equilibrium, the partial pressures are:

P_I2 = P_Br2 = x

P_IBr = 0.029 - x

Substituting these expressions into the equilibrium constant expression gives:

8.5×10^-3 = (x * x) / (0.029 - x)^2

Solving for x gives:

x = 0.0025 atm

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AnswerTherefore, you left approximately 1.202 x 10^23 molecules of CaCO3 on the concrete after drawing with a 25g chalk piece outside for 5 minutes.

Explanation:

To solve this problem, we need to use the concept of conservation of mass, which states that matter cannot be created or destroyed, only transformed from one form to another. Therefore, the total mass of the chalk before and after drawing must be equal.

The mass of the chalk before drawing is 25 g. After drawing for 5 minutes, the mass of the chalk is 5 g. Therefore, the mass of chalk that was used for drawing is:

25 g - 5 g = 20 g

Next, we need to convert the mass of the chalk used to the number of molecules. The molar mass of CaCO3 is 100.09 g/mol, which means that one mole of CaCO3 contains 6.022 x 10^23 molecules.

To calculate the number of molecules of chalk used for drawing, we can use the following steps:

Calculate the number of moles of CaCO3 used:

20 g / 100.09 g/mol = 0.1998 mol

Calculate the number of molecules of CaCO3 used:

0.1998 mol x 6.022 x 10^23 molecules/mol = 1.202 x 10^23 molecules

The IUPAC name of the given compound is 1-bromo-3-ethylpentane.

IUPAC (International Union of Pure and Applied Chemistry) naming is a system used to give standardized names to chemical compounds. The steps involved in doing IUPAC naming are as follows:

1. Identify the longest carbon chain: The parent chain is the longest continuous chain of carbon atoms in the molecule.

2. Number the carbon atoms: The carbon atoms in the parent chain are numbered starting from the end nearest to the substituent, and the substituents are given numbers based on the carbon to which they are attached.

3. Identify and name the substituents: Substituents are groups of atoms that replace hydrogen atoms on the parent chain. They are named according to their functional groups.

4. Write the name: The name of the compound is written by listing the names of the substituents in alphabetical order, along with their position on the parent chain.

5. Add prefixes and suffixes: Prefixes are added to indicate the number of substituents on the parent chain, and suffixes are added to indicate the functional group present.

6. Check the name: The final step is to check the name for accuracy and consistency with IUPAC rules.

It's important to note that the naming of complex organic compounds can involve additional rules and naming conventions beyond these basic steps.

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Hurricane = Rapid

Volcanic eruption = Rapid

Regrowth after volcanic eruption = Gradual

Flooding = Rapid

Seasonal changes = Gradual

Oceans increasing temperature = Gradual

Global warming = Gradual

Fire = Rapid

Answer:

rapid

rapid

gradual

rapid

gradual

gradual

gradual

rapid

Explanation:

One mole of glucose burns to produce several gases. [tex]6600kJ[/tex] of power. Another way to put it is that the burning of glucose releases  [tex]6600KJ/mol[/tex]  thermal energy.

A chemical reaction between two or more substances, typically containing oxygen, is called combustion. It results in the production of light and heat in the form of a flame.

The correct chemical formula for the burning of glucose

[tex]C6H12O6 + 6O2 \rightarrow  6CO2 + 6H2O[/tex]

We can determine the change in enthalpy for this reaction by using the values provided for the enthalpies of formation of the reactants and products:

Reactants:

[tex]C_6H_1_2O_6[/tex] : not given

[tex]O2: -498 kJ/mol \times 6 = -2988 kJ/mol[/tex]

Products:

[tex]CO_2[/tex]: not given

[tex]H2O -1598 kJ/mol \times 6 = -9588 kJ/mol[/tex]

[tex]\Delta H = (\epsilon products) - (\epsilon reactants)[/tex]

[tex]\Delta H = (-9588 kJ/mol + 0) - (0 + -2988 kJ/mol)[/tex]

[tex]\Delta H = -6600 kJ/mol[/tex]

Therefore, One mole of glucose burns to produce several gases. [tex]6600kJ[/tex] of power. Another way to put it is that the burning of glucose releases  [tex]6600KJ/mol[/tex]  thermal energy.

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Al, Cu, and Zn, Al are the metals in equations 1 and 2, respectively. Since aluminium is ranked higher on the activity series than copper, it can substitute for copper in chemical reactions.

Metal and Water Reaction: An Introduction Because of the intense interactions that certain metals have with water, such potassium and sodium, they will ignite if left outside.

Magnesium is therefore the most reactive of the listed metals, and as a result, its pace of reaction will be the quickest (to react with steam). Magnesium does not react with cold water, whereas metals with strong reactivity like potassium (K), sodium (Na), and calcium (Ca) do.

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The mass of chlorine in 25kg of [tex]CFCl_3[/tex] is 6,435g where mass is a measure of the amount of matter in an object. It is measured in kilograms (kg) or grams (g).

The mass of [tex]CFCl_3[/tex] = 25kg

The molecular weight of [tex]CFCl_3[/tex] (also known as Freon-11) is = 137.37 g/mol.

It means one mole of [tex]CFCl_3[/tex] = 137.37 g.

Since chlorine is an element, one mole of chlorine is equal to its atomic weight, which is 35.45 g/mol.

Therefore, number of moles 25 kg of [tex]CFCl_3[/tex] contains =

(25 kg) / (137.37 g/mol) = 182.4 mol of [tex]CFCl_3[/tex].

To calculate the mass of chlorine in 25 kg of [tex]CFCl_3[/tex], we need to multiply the number of moles of chlorine by its atomic weight.

The mass of chlorine in 25 kg of [tex]CFCl_3[/tex] is = 182.4 mol * 35.45 g/mol = 6,435 g of chlorine.

Hence, the mass of chlorine in 25 kg of [tex]CFCl_3[/tex] is 6,435 g.

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the normality of the solution that results when 4.0g of Al(NO₃)₃ (MW = 213.0) is dissolved in enough water to give 250mL of solution the molarity of the solution is 0.0751 M.

To calculate the normality and molarity of the solution, we need to know the number of moles of Al(NO₃)₃ in the solution.

The number of moles can be calculated as:

moles = mass / molar mass

where mass is the mass of Al(NO₃)₃ and molar mass is the molecular weight of Al(NO₃)₃

Substituting the given values, we get:

moles = 4.0 g / 213.0 g/mol = 0.01878 mol

The volume of the solution is given as 250 mL, which is equivalent to 0.25 L.

The normality of the solution is defined as the number of equivalents of solute per liter of solution. For Al(NO₃)₃, each mole of the compound produces 3 moles of ions, so the number of equivalents of Al(NO₃)₃ is:

equivalents = moles x 3

Substituting the value of moles, we get:

equivalents = 0.01878 mol x 3 = 0.05634 eq

The normality can now be calculated as:

normality = equivalents / volume

Substituting the given values, we get:

normality = 0.05634 eq / 0.25 L = 0.225 N

Therefore, the normality of the solution is 0.225 N.

The molarity of the solution is defined as the number of moles of solute per liter of solution. The number of moles of Al(NO₃)₃ in 250 mL of solution is the same as the number of moles in 1 L of solution, which is 0.01878 mol. Therefore, the molarity of the solution is:

molarity = moles / volume

Substituting the given values, we get:

molarity = 0.01878 mol / 0.25 L = 0.0751 M

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Answer:

Activation Energy

Explanation:

Activation energy is the minimum amount of energy that reactant molecules must possess in order to undergo a chemical reaction. as it is necessary to break the bonds of between the molecules of the reactants.


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The food chain that produces elements like the crust, tomato sauce, cheese, and meat on a pizza begins with the energy that plants absorb from the sun through photosynthesis.

Green plants, algae, and some microorganisms transform solar energy into chemical energy in the form of organic compounds like carbohydrates through a process called photosynthesis. Light energy is absorbed by pigments, chiefly chlorophyll, which is present in the chloroplasts of plant cells, during photosynthesis. Next, using this energy, glucose (a form of sugar) and oxygen are produced from carbon dioxide and water.

By photosynthesis, plants use the sun's energy to create carbohydrates (like glucose). Following the consumption of these carbohydrates by herbivores, predators subsequently consume these carbs, and so on.

When it comes to a pizza, the wheat used to form the crust was probably grown in a field where it employed photosynthesis to take in energy from the sun. Like with other vegetables used as toppings, the tomatoes used to prepare the sauce were probably also grown in a field. Pizza's cheese is formed from milk, which comes from cows who eat grass and other plants that have undergone photosynthesis to receive solar energy. Last but not least, any meat added as a garnish originated from creatures that also ate vegetables for fuel.

In a sense, the sun's energy, which plants use to produce food, including the components in a pizza, is eventually harnessed by photosynthesis.

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1.02 mol of carbon monoxide gas will occupy a volume of approximately 22.8 liters at STP.

At STP (standard temperature and pressure), the temperature is 273.15 K (0°C) and the pressure is 1 atmosphere (atm). The molar volume of a gas at STP is 22.4 L/mol.

Using the ideal gas law, we can calculate the volume of 1.02 mol of carbon monoxide gas at STP: PV = nRT

where:

P = pressure = 1 atm

V = volume (unknown)

n = moles = 1.02 mol

R = gas constant = 0.0821 L·atm/(mol·K)

T = temperature = 273.15 K

V = (nRT)/P

putting the values,

V = (1.02 mol)(0.0821 L·atm/(mol·K))(273.15 K) / (1 atm)

V = 22.4 L/mol

V = 22.8 L

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Answer:

23205 J or 2.37 × 10⁴ J or 23.7 kJ

Explanation:

The amount of heat required to change the temperature of a substance can be calculated using the formula: q = mcΔT, where q is the heat added, m is the mass of the substance, c is its specific heat capacity, and ΔT is the change in temperature.

The specific heat capacity of iron is 0.44 J/g K1. So, to raise the temperature of 235 g of iron from 25.0°C to 250.0°C (a change of 225°C), you would need to add:

q = (235 g) × (0.44 J/g K) × (225 K) = 23205 J

So you would need to add 23205 joules of heat to raise the temperature of 235 g of iron from 25.0°C to 250.0°C.

There are 5.85 grams of acetic acid (CH3CO2H) in the given solution.

To calculate the grams of solute in the given solution, we first need to calculate the number of moles of solute (acetic acid) present in the solution.

We know the volume of the solution (250 mL) and the molarity of the solution (0.39 M). We can use the following equation to calculate the number of moles of solute:

moles of solute = molarity × volume (in liters)

First, we need to convert the volume from milliliters to liters:

250 mL = 0.250 L

Now we can use the equation to calculate the number of moles of acetic acid:

moles of CH3CO2H = 0.39 M × 0.250 L = 0.0975 moles

Finally, we can use the molar mass of acetic acid to convert the number of moles to grams:

molar mass of CH3CO2H = 60.05 g/mol

grams of CH3CO2H = moles of CH3CO2H × molar mass of CH3CO2H

grams of CH3CO2H = 0.0975 moles × 60.05 g/mol = 5.85 g.

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Answer:

The base conjugate acid pair is NH3 and NH4+.

In order to convert the volume from 21.0 L to 41.0 L while maintaining the same pressure and particle number, the gas would need to be heated to a temperature of 580.49 K.

According to Boyle's law, the pressure and volume of a gas follow an inverse relationship when the gas's temperature and molecular composition are both constant.

This problem can be solved using the coupled gas law, which connects a gas's pressure, volume, and temperature:

(P1 V1) / T1 = (P2 V2) / T2

In this problem, we are given P1 = P2, V1 = 21.0 L, V2 = 41.0 L, and            T1 = 34°C. We want to find T2 in Kelvin.

First, we need to convert T1 from Celsius to Kelvin:

T1 = 34°C + 273.15

T1 = 307.15 K

Next, we can rearrange the combined gas law to solve for T2:

T2 = (P2 V2 T1) / (P1 V1)

Substituting the given values, we get:

T2 = (1 atm * 41.0 L * 307.15 K) / (1 atm * 21.0 L)

T2 = 580.49 K

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Restate original Claim here. This claim was supported by the claim because the evidence showed that acidic substances have a pH value less than 7 and cause the pH paper to turn a certain color.

What is pH?

pH is a measure of the acidity or basicity of a solution. It is defined as the negative logarithm of the concentration of hydrogen ions (H+) in a solution. pH values range from 0 to 14, where 0 is the most acidic, 7 is neutral, and 14 is the most basic. A change of one unit in pH represents a tenfold change in the concentration of hydrogen ions.

For example, from the evidence, fruit juices such as lemon juice have a pH value of around 2-3 and turn the pH paper a red color, which indicates acidity. Beverages such as coffee and soda also have a low pH value, around 4-5, and turn the pH paper a slightly red color. Cleaning products such as vinegar have a pH value of around 2-3 and turn the pH paper a red color as well.

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The molar entropy from the question that we have here is 85.1kJ/K.mol as shown.

The molar entropy of a substance can be calculated by dividing the total entropy of the substance by the number of moles present. The entropy of a substance can be determined experimentally by measuring its heat capacity or by analyzing its thermodynamic behavior under different conditions.

We know that;

Entropy = ΔH/T

= 1.6 * 10^4 * 10^3J/mol/187.95 K

= 85.1kJ/K.mol

For the bromide ion;

Rate = 5/1 * 2.7 * 10^-3 mol/s

= 1.35 * 10^-2 mol/s

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Answer:

1.525834 (1.53 when accounting for significant figures).

Explanation:

This problem relies on the Ideal Gas Law, PV = nRT, where P is pressure, V is volume, n is moles, R is a specific constant, and T is temperature. In this problem, we are solving for n, moles, so we would rewrite it as n = PV/RT. Since the units here are moles, liters, atmospheres, and kelvin, R would be the value in atmosphere liter per mole kelvin, or 0.0821. From here, you just enter the values in the fraction and calculate.

For the significant figures, I followed the measurement of 34.2 L, giving 3, although an argument could be made for 1 significant figure from 1 atm, I imagine your professor would want something more specific than 2.

Answer:

Green Bean Casserole is a classic.

The family recipe has passed down from one great-aunt to another.
Now it's causing gas and bloating across multiple generations of the family.

Explanation:

Answer:

Explanation:Two pre-requisite skills needed for students to learn the process of writing balanced chemical and ionic equations are:

1. Understanding of the periodic table and elements: Students must have a solid foundation in the periodic table, including recognizing elements by their symbols and understanding their properties, groups, and electron configurations.

2. Knowledge of chemical bonding and compound formation: Students should be familiar with the different types of chemical bonds (ionic, covalent, and metallic) and know how to construct chemical formulas for compounds based on their component elements and valence electrons.

Answer:

9 ans

Explanation:

cold 20 -11 =9 ans

summer 20-11=9 ans

Explanation:

To calculate the molarity of the vinegar solution, we first need to calculate the number of moles of acetic acid present in one liter of the solution.

Since the density of the solution is 1.01 g/mL, one liter of the solution will have a mass of 1.01 kg.

The mass of acetic acid in one liter of the solution can be calculated as follows:

mass of acetic acid = 5% × 1.01 kg = 0.0505 kg

The number of moles of acetic acid can be calculated using its molar mass:

moles of acetic acid = mass of acetic acid / molar mass of acetic acid

moles of acetic acid = 0.0505 kg / 60.052 g/mol

moles of acetic acid = 0.000841 mol

Therefore, the molarity of the vinegar solution is:

molarity = moles of acetic acid / volume of solution in liters

molarity = 0.000841 mol / 1 L

molarity = 0.000841 M

So, the molarity of a 5% vinegar solution is approximately 0.000841 M.

Answer: 2 L or 2000 mL

Explanation:

A 1 molar (1 M) solution is equal to 1 mole of the solute dissolved in 1 L of solution.

For HCl (mw 36.5) 1 mole = 36.5 g

1 molar (1 M) = 1 mole/1 liter (or 36.5 g/L)

So

0,5 M = 1 mole/x

(x is the volume we are solving for)

Multiply both sides by x and you get

0.5x=1

Now multiple both sides by 2

X=2

So it’s 2L volume

Answer:

catalysts do not shift the equilibrium position of a chemical reaction because they do not affect the free energy difference between reactants and products

Explanation:

To understand this better, let's consider an example. The Haber process is used to produce ammonia from nitrogen and hydrogen gas:

N2(g) + 3H2(g) ⇌ 2NH3(g)

This reaction is exothermic, meaning that it releases heat. According to Le Chatelier's principle, adding heat to an exothermic reaction will shift the equilibrium position towards the reactants (N2 and H2). Conversely, removing heat from the system will shift the equilibrium position towards the products (NH3).

Now, let's say we add a catalyst to this reaction. The catalyst will speed up both the forward and reverse reactions equally, without affecting their relative rates. This means that although the reaction will reach equilibrium faster with a catalyst present, it will still reach the same equilibrium position as it would without a catalyst.

1. (a) Consider the following table .

which of the element :

a) is a halogen?

Ans. Element J is halogen.

b) is most likely to be attracted by a magnet?

Ans. Element Y is most likely to be attracted by a magnet.

c) belongs to group I.

Ans. Element X belongs to group 1.

d) would readily form an ion with a double negative charge?

Ans. Element R would readily form an ion with a double negative charge.

e) what type of bond would exist between J and X when they combine?

Ans. Ionic bond would exist between J and X when they combine.

f) how many neutrons are there in Q?

Ans. Atomic number of Q = 13

Mass Number = 27.

Number of neutrons = Mass Number - Atomic number

Number of neutrons = 27 - 13.

Hence, There are 14 neutrons in Element Q.

g) write the formula of the compound formed when R combines with X.

Ans. When R combines with X it forms X₂R.

h) state the element which exist as a diatomic molecule

Ans. Element J exist as a diatomic molecule.

I) select the element which belongs to the d- block of the periodic table

Ans. Element Y belongs to the d- block of the periodic table.

J) write the electronic configuration of the element Y

Ans. Electronic configuration of the element Y is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d⁵ or [Ar] 4s¹ 3d⁵.