What is the correct formula for finding the 6th power of a complex number in polar form?

Answer:

Step-by-step explanation:

Can we get the Answer's to see. Thanks.

Answer:

i dont know that well but i do know 1 meter is roughly 2ft, so id say about 25.5 inches

0.01 inch is the  length of a meter stick.

To find the length of a meter stick in inches, we can use the conversion factor:

1 meter = 100 centimeters

1 inch = 2.54 centimeters

We can set up the proportion:

1 meter / 100 centimeters = x inches / 1 inch

Cross-multiplying:

1 meter × 1 inch = 100 centimeters × x inches

x = (1 meter × 1 inch) / (100 centimeters)

x = 1 inch / 100

x = 0.01 inch

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You're a square !!!1!!!!!!!!11

9514 1404 393

Answer:

  76

Step-by-step explanation:

For some common difference d, the terms of the progression are ...

  k = 3 +d

  w = k +d = 3 +2d

  18 = w +d = 3 +3d

Solving for d, we get ...

  15 = 3d . . . . subtract 3

  5 = d . . . . . . divide by 3

Now, we can find ...

  3k +4w = 3(3 +d) +4(3 +2d) = 9 +3d +12 +8d = 21 +11d

  3k +4w = 21 +11(5) . . . . substitute for d

  3k +4w = 76

Answer:

see below

Step-by-step explanation:

Part A

We can shift f(x) to the left or shift it up

Part B

f(x+k) for a shift to the left

f(x) + k for a shift up

Part C

Looking at shifting f(x) to g(x) by going left, we are shifting 6 units to the left

f(x+6) will shift f(x) 6 units to the left

g(x) = f(x+6)

We can all shift f(x) up, we can shift up 18 units

f(x) +18 will shift the function up 18 units

g(x) = f(x) +18

Step-by-step explanation:

1. 3cm, 5cm, 7cm

2. 7cm, 7cm, 12cm

Answer:

5^6

Step-by-step explanation:

This is because the exponent is how many numbers are in the multiplication equation, in this case, five. Because there are six five's being multiplied together, our exponent is six.

The total distance of the race is D = 96 miles

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Substituting the values in the equation , we get

Let's denote the total distance of the race as "d" miles.

According to the given information, Mark ran half the distance and swam a quarter of the distance. This can be expressed as:

Distance Mark ran = d/2 miles

Distance Mark swam = d/4 miles

After Mark's quick break, he was just starting to bike the remaining 24 miles. Since he has already completed running and swimming, the total distance he has covered at that point is:

And this distance is equal to 24 miles, as given in the problem:

d/2 + d/4 + 24 = d

On simplifying the equation , we get

( 3/4 )d + 24 = d

Subtracting ( 3/4 )d on both sides , we get

( 1/4 )d = 24

Multiply by 4 on both sides , we get

d = 96 miles

Hence , the total distance of the race, denoted by "d", is 96 miles

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Answer:

703.7168 ft²

Step-by-step explanation:

Use the sector area formula, a = 1/2r²θ

If the diameter is 32 feet, then the radius is 16 feet.

Plug in the radius and angle measure into the formula, and solve:

a = 1/2r²θ

a = 1/2(16)²(7[tex]\pi[/tex]/4)

a = 703.7168

So, the area of the sector is 703.7168 ft²

Answer: (10,5) and (0,5)

Step-by-step explanation:

Answer:

plz mark me as brainlist

Step-by-step explanation:

b)JK and KL

Answer:

JK AND KL

Step-by-step explanation:

Answer:  40 lb of Type A

Step-by-step explanation:3 pounds of Type B and 1 pound of Type A will give 4 pounds of mix at a cost of ...  3($4.65) +($5.95) = $19.90Then $796 is the cost equivalent of 796/19.90 = 40 times that 4-lb mix. Since each instance of that 4-lb mix has 1 lb of Type A, $796 worth of blend has 40 lb of Type A coffee._____Additional commentIf you'd like to do this using a variable, you can let 'a' represent the amount of Type A coffee used. Then (3a) is the amount of Type B, and the total cost is ...  5.95a +4.65(3a) = 796  19.90a = 796 . . . . . . . . simplify  a = 796/19.90 = 40 . . . as above___There will be 120 lb of Type B coffee in that amount of blend.

The amount of Type A coffee that were used is 40 pounds.

Word problems in Algebra can be solved by correctly identifying the parameters given and the one(s) meant to be solved with the appropriate use of arithmetic operations.

From the given information;

For this month, the equation can be expressed as:

Thus;

Therefore, we can conclude that the amount of pounds of type A coffee that were used is 40 pounds.

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Answer:

x=8

Step-by-step explanation:

4 ^(1/2x) = 256

Rewriting 256 as a power of 4

4 ^(1/2x) = 4^4

Since the bases are the same, the exponents are the same

1/2x = 4

Multiply each side by 2

1/2x *2 = 4*2

x=8

Answer:

» B. 3- (+22) and C. 3 + (-22)

» A. 3- (-22) and E. 22 + 3

» D. 22 - 3 and H. 22 +(-3)

Step-by-step explanation:

[tex].[/tex]

Answer:

3 - (+22)

3 + (-22)

-22 + 3

Step-by-step explanation:

Answer:

(c)

Step-by-step explanation:

for the volume of a box all three dimensions must be multiplied with each other to create a cubic result.

3x²y × 4y²z × 5z²x

we need to combine the elements belonging to each other = that can be combined for simplification :

the constants, the x, the y and the z.

3×4×5 = 60

x²×x = x³

y×y² = y³

z×z² = z³

so, in total, that multiplication result is

60x³y³z³

therefore, (c) is the right answer

Answer:

volume of a retagular box whose adjacent egged 3x²y , 4y²z and 5z²x respectively is

( C ) 60x³y³z³

Step-by-step explanation:

hope it's help

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# FIRST MASTER

# PHILIPPINES

Answer:

The area is 7.5 square units

Answer:

-5,-4,-3,-2,-1,0,1,2,3,4,5

-5 देखि+5सम्म 11 पुर्ण सङ्ख्याहरु छन्

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Answer:

a=50

b=130

c=130

Step-by-step explanation:

2a-50=a(vertically opposite angles)

a=50

a+c=180(angles on straight line)

50+c=180

c=180-50=130

b=c(vertically opposite angles)

b=130

9514 1404 393

Answer:

  56th batch

Step-by-step explanation:

The least common multiple of 8 and 28 is 8·7 = 56. Tom and Larry will both test the 56th batch.

__

There are a couple of ways to find the least common multiple (LCM) of a pair of numbers.

1. Factor them and use the highest power of the unique factors.

  8 = 2³

  28 = 2²×7

Unique factors are 2 and 7. Their highest powers are 3 and 1, so the LCM is ...

  (2³)(7) = 56

__

2. Divide the product by the greatest common divisor (GCD). Here, both numbers are divisible by 4:

  8 = 4·2

  28 = 4·7

So, the LCM is 8×28/4 = 56.

Answer:

Step-by-step explanation:

8=2x2x2

28=2x2x7

lcm of 8,28= 56

Answer:

R = 6S/T

Step-by-step explanation:

R ∝ S/ T

》R = kS/ T

》k = RT/ S

If R = 8 when S = 4 and T = 3

then, k = (8 × 3)/ 4

k = 6

∴ R = (6 × S)/ T

Answer:

perfect square

Step-by-step explanation:

A perfect square is a number multiplied by itself:

16 = 4^2 = 4 * 4

9514 1404 393

Answer:

  a) see attached

  b) Each successive figure has one more tile at the end of each leg.

  c) 201, the number of tiles is 2n+1 for figure n.

Step-by-step explanation:

a) The attachment shows the next two figures

__

b) The pattern adds one more tile at the end of each leg than the previous figure had. This rule matches the figures shown.

__

c) The rule found in part B means that Figure N will have 2N+1 tiles, the N tiles in each leg plus the one where the legs meet.

Figure 100 will have 2(100) +1 = 201 tiles

Answer:

Step-by-step explanation:

152

Answer:13

Step-by-step explanation:

Answer:

640 dm

Step-by-step explanation:

200+40+400=640dm

Given

[tex]\vec v = f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k[/tex]

the curl of [tex]\vec v[/tex] is

[tex]\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k[/tex]

[tex]\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k[/tex]

[tex]\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k[/tex]