Answer:
D is correct.(1s22s22p63s2)
A zinc chloride solution is prepared by dissolving 0.316 g of anhydrous zinc chloride in 100.0 mL of H2O.
What mass of zinc chloride is present in 19.97 mL of that solution.
A zinc chloride solution is prepared by dissolving 0.316 g of anhydrous zinc chloride in 100.0 mL of [tex]H_2O[/tex] . The mass of zinc chloride present in 19.97 mL of the solution is 0.316 g.
We can use the formula:
C1V1 = C2V2
where C1 is the concentration of the original solution, V1 is the volume of the original solution, C2 is the concentration of the final solution, and V2 is the volume of the final solution.
First, let's calculate the concentration of the original solution:
concentration = (0.316 g) / (100.0 mL) = 0.00316 g/mL
Now, we can use the formula to find the mass of zinc chloride in 19.97 mL of the solution:
C1V1 = C2V2
0.00316 g/mL x 100.0 mL = C2 x 19.97 mL
C2 = (0.00316 g/mL x 100.0 mL) / 19.97 mL
C2 = 0.01583 g/mL
So the concentration of zinc chloride in the final solution is 0.01583 g/mL.
Now we can use this concentration to calculate the mass of zinc chloride in 19.97 mL of the solution:
mass = concentration x volume
mass = 0.01583 g/mL x 19.97 mL
mass = 0.316 g
Therefore, there are 0.316 g of zinc chloride present in 19.97 mL of the solution.
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Nitrogen dioxide gas and liquid water react to form aqueous nitric acid and nitrogen monoxide gas. Suppose you have 5.0 mol of NO2 and 11.0 mol of H2O in a reactor.
Calculate the largest amount of HNO3 that could be produced. Round your answer to the nearest 0.1 mol
First, we need to write the balanced chemical equation for the reaction:
2 NO2(g) + H2O(l) → HNO3(aq) + NO(g)
From the equation, we can see that 2 moles of NO2 react with 1 mole of H2O to produce 1 mole of HNO3 and 1 mole of NO. Therefore, we need to determine which reactant is limiting and calculate the amount of HNO3 that can be produced based on that.
To do this, we can use the mole ratio of NO2 to H2O:
5.0 mol NO2 × (1 mol H2O / 2 mol NO2) = 2.5 mol H2O
Since we have 11.0 mol of H2O, it is not limiting and we will use up all of the NO2.
Therefore, we can calculate the amount of HNO3 that can be produced from 5.0 mol of NO2:
5.0 mol NO2 × (1 mol HNO3 / 2 mol NO2) = 2.5 mol HNO3
Therefore, the largest amount of HNO3 that could be produced is 2.5 mol, rounded to the nearest 0.1 mol.
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Н
HOH
14
Н-С-С-С-Н
I
ННН
List the number of each atom in the formulas above:
H
НН Н
Н-С-С-С-О-Н
LI
НН Н
DONE
Н Н
H
Н-С-С-О-С-Н
II
Н Н
H
Answer:
Explanation:
It seems like you’re trying to count the number of atoms in some chemical formulas. Here’s the list of the number of each atom in the formulas you provided:
Formula 1: Н - 1 Formula 2: H - 1, O - 1 Formula 3: Н - 14 Formula 4: Н - 2, C - 3 Formula 5: I - 1 Formula 6: Н - 3 Formula 7: H - 2 Formula 8: Н - 2, C - 3, O - 1 Formula 9: Li - 1 Formula 10: Н - 2 Formula 11: Н - 2 Formula 12: H - 1 Formula 13: Н - 2, C - 2, O - 1 Formula 14: II
Which of the following represents an exothermic reaction?
Question 5 options:
CH4(g) + 2O2(g) → CO2(g) + 2H2O(g) + energy
2H2O(l) + energy → 2H2(g) + O2(g)
6CO2(g) + 6H2O(l) + energy → C6H12O6(aq) + 6O2(g)
Answer:
exothermic reaction is: Reactants → Products + Energy.
Explanation:
Note: ΔH represents the change in energy. If the energy produced in an exothermic reaction is released as heat, it results in a rise in temperature.
A sample of gas is contained in a 245 mL flask at a temperature of 23.5°C. The gas pressure is 37.8 mm Hg. The gas is moved to a new flask, which is then immersed in ice water, and which has a volume of 54 mL. What is the pressure of the gas in the smaller flask at the new temperature?
The pressure of the gas in the smaller flask at the new temperature is approximately 168.5 mm Hg.
To solve this problem, we can use the combined gas law equation, which relates the initial and final states of a gas sample undergoing changes in pressure, volume, and temperature. The equation is:
[tex]P_1V_1/T_1 = P_2V_2/T_2[/tex]
where [tex]P_1[/tex] and [tex]P_2[/tex] are the initial pressure and final pressure, [tex]V_1[/tex] and [tex]V_2[/tex] are the initial and final volumes, and [tex]T_1[/tex] and [tex]T_2[/tex] are the initial and final temperatures in Kelvin.
[tex]V_1[/tex] = 245 mL
[tex]T_1[/tex] = 23.5°C + 273.15 = 296.65 K
[tex]P_1[/tex] = 37.8 mm Hg
[tex]V_2[/tex] = 54 mL
[tex]T_2[/tex] = 0°C (ice water) + 273.15 = 273.15 K
We need to find [tex]P_2[/tex] . Plug the given values into the equation and solve for [tex]P_2[/tex] :
(37.8 mm Hg * 245 mL) / 296.65 K = (P2 * 54 mL) / 273.15 K
Rearrange the equation to isolate [tex]P_2[/tex] :
[tex]P_2[/tex] = (37.8 mm Hg * 245 mL * 273.15 K) / (296.65 K * 54 mL)
[tex]P_2[/tex] ≈ 168.5 mm Hg
So, the pressure of the gas is approximately 168.5 mm Hg in the smaller flask at the new temperature.
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Question
How many moles of Na₂S₂O3 are needed to dissolve 0.65 mol of AgBr in a solution volume of
1.0 L, if Ksp for AgBris 3.3 x 10-13 and K for the complex ion [Ag(S₂03)2] is 4.7 × 10¹3?
Remember to use correct significant figures in your answer (round your answer to the nearest
tenth). Do not include units in your response.
The precipitation of an ionic substance from solution occurs when the ionic product exceeds the value of its solubility product at that temperature. Here the moles of Na₂S₂O₃ needed is
The solubility product of a sparingly soluble salt is defined as the product of the molar concentrations of its ions in a saturated solution of it at a given temperature.
Here the concentration of Ag⁺ ions = √Ksp = √3.3 × 10⁻¹³ = 1.81 × 10⁻¹³.
Moles of Ag⁺ ions: (1.82 x 10⁻¹³ M) x 1.0 L = 1.82 x 10⁻¹³ mol Ag⁺
Use the stoichiometry of the reaction to find the moles of Na₂S₂O₃ needed: 1 mol Na₂S₂O₃ / 2 mol Ag⁺ = 0.5 mol Na₂S₂O₃/mol Ag⁺
Moles of Na₂S₂O₃ required: 0.5 mol Na₂S₂O₃/mol Ag⁺ x 1.82 x 10⁻¹³ mol Ag⁺ = 9.1 x 10⁻¹⁴ mol Na₂S₂O₃
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After some salt was added to it, a 45.4 g solution in a coffee-cup calorimeter increased in temperature from 23.0 oC to 31.5 oC. The specific heat constant (c) for the solution is 1 cal/g oC. The q of the reaction is ______ cal
The amount of heat absorbed during the reaction is 385.9 cal.
How to calculate heat in calorimetry?Calorimetry is the science of measuring the heat absorbed or evolved during the course of a chemical reaction or change of state.
The amount of heat in a reaction can be calculated as follows;
Q = mc∆T
Where;
Q = quantity of heat absorbedm = mass of substancec = specific heat capacity∆T = change in temperatureQ = 45.4 × 1 × {31.5 - 23)
Q = 45.4 × 8.5
Q = 385.9 cal
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Suppose 135 g of NO3- flows into a swamp each day. What volume of N2 would be produced each day at 17.0°C and 1.00 atm if the denitrification process were complete?
____ L of N2
Suppose 135 g of NO3- flows into a swamp each day. What volume of CO2 would be produced each day at 17.0°C and 1.00 atm?
____ L of CO2
Suppose the gas mixture produced by the decomposition reaction is trapped in a container at 17.0°C; what is the density of the mixture assuming Ptotal = 1.00 atm?
____ g/L
The volume of N2 produced each day is approximately 24.56 L.
How to find the volume of N2First, let's find the number of moles of NO3- that flow into the swamp each day:
NO3- molar mass = 14.01 (N) + 3 * 16.00 (O) = 62.01 g/mol
135 g / 62.01 g/mol ≈ 2.177 moles of NO3-
In the denitrification process, NO3- is reduced to N2 gas. The balanced equation for denitrification is:
2NO3- → N2 + 3O2
From the stoichiometry of the reaction, we can see that 2 moles of NO3- produce 1 mole of N2. Therefore, the moles of N2 produced each day can be calculated as follows:
moles of N2 = 2.177 moles of NO3- / 2 ≈ 1.0885 moles of N2
Now we can use the ideal gas law equation to find the volume of N2 produced:
PV = nRT
where:
P = Pressure (1.00 atm)
V = Volume (in Liters)
n = Moles of N2 (1.0885 moles)
R = Ideal gas constant (0.0821 Latm/molK)
T = Temperature (17.0°C or 290.15 K)
Solving for the volume of N2:
V = nRT / P
V = (1.0885 moles) * (0.0821 Latm/molK) * (290.15 K) / (1.00 atm)
V ≈ 24.56 L
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Which of the following is an example of an environmental impact of
agriculture?
O high use of gold, copper, and silver
O high use of rock supplies
O high use of mineral resources
O high use of water
Ne
Answer:
B
self explanatory
Explanation:
A sample of an ideal gas has a volume of 3.75 L
at 10.60 ∘C
and 1.80 atm.
What is the volume of the gas at 23.20 ∘C
and 0.990 atm?
The volume of the gas at 23.20∘C and 0.990 atm is 7.12L.
How to calculate volume?The volume of a gas can be calculated using the combined gas law equation as follows;
PaVa/Ta = PbVb/Tb
Where;
Pa, Va and Ta = initial pressure, volume and temperature respectively Pb, Vb and Tb = final pressure, volume and temperature respectivelyAccording to this question, a sample of an ideal gas initially has a volume of 3.75 L at 10.60 ∘C and 1.80 atm. The resulting volume can be calculated as follows;
1.8 × 3.75/283.6 = 0.990 × Vb/296.2
0.0238 × 296.2 = 0.990Vb
Vb = 7.0498 ÷ 0.990
Vb = 7.12L
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What is the main reason plants grow fruit?
A
to provide delicious food for humans and other animals
B
to stop animals from spreading seeds
C
to encourage bees to pollinate
D
to keep seeds safe and make them easier to spread
Answer:
D
Explanation:
to keep seeds safe and make them easier to spread
Answer:
D. to keep seeds safe and make them easier to spread
Explanation:
The main reason plants grow fruit is to aid in the protection and spreading of seeds. The fruit protects the seeds and also helps to spread them. Many fruits are good to eat and attract small animals, such as birds and squirrels, who like to feed on them. The seeds pass through them unharmed and then get spread through their droppings. So, the correct answer would be D.
* For all 3 trials find the moles of KHC8H4O4 using the grams of KHC8H4O4. Show all work!
* Use the mole ratio from question 1 to find the moles of NaOH used. Remember, in a 1:1 ratio if we use 1 mole of KHC8H4O4, then we use 1 mole of NaOH. Record the moles of NaOH used in each trial below.
Trial 1 ________________
Trial 2 ________________
Trial 3 ________________
At equivalence point, the reaction is seen to consume approximately 0.0024973 moles of KHP and then 0.0024973 moles of NaOH
How to calculate the mole ratio?The primary aim in this problem is to standardize a solution of the sodium hydroxide, NaOH, with the aid of potassium hydrogen phthalate, KHP.
The beginning point in this problem is the balanced chemical equation with respect to this neutralization reaction
KHP (aq] + NaOH(aq] → KNaP(aq] + H₂O(l]
The important thing that we are going to observe is that there is a ratio of 1:1 mole ratio between the two reactants. This suggests to us that the equivalence point can be attained by getting equal number of moles of KHP and of NaOH to react with each other.
We will begin with 0.5100 g of KHP. To obtain the molar amount of acid utilized for the experiment, we will make use of its molar mass of 0.5100g⋅
molar mass of KHP
1 mole KHP 204.22g = 0.0024973 moles KHP
Thus, at equivalence point, the reaction is seen to consume approximately 0.0024973 moles of KHP and then 0.0024973 moles of NaOH, due to the fact that it's what the 1:1 mole ratio suggests to us.
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7. What is the reason that methemoglobinemia was isolated to Troublesome Creek area of KY? (In other
words why was the disorder only prevalent in KY; why didn't other states see cases like this?)
Methemoglobinemia was caused by contaminated well water and a genetic predisposition in the population of Troublesome Creek, KY.
Methemoglobinemia was detached to the Problematic Rivulet area of KY in view of the novel blend of ecological variables and hereditary inclination in the populace. The issue was brought about by the utilization of well water polluted with elevated degrees of nitrate and nitrite, which can cause the arrangement of methemoglobin in the blood. The populace in this space was to a great extent slipped from a little gathering of trailblazers who settled there during the 1800s, which might have added to a higher pervasiveness of the hereditary characteristic that inclines people toward the issue. The particular mix of hereditary defenselessness and ecological openness in this populace probably prompted the secluded flare-up of methemoglobinemia around here.
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What mass of oxygen would be released by the thermal decomposition of 918.7 grams of Mercury (II) Oxide?
HgO --> Hg + O2
Answer:
Explanation:
[tex]\frac{918.7 g}{1} *\frac{1}{216.59m } = 4.241 mol[/tex] To start off the mol of HgO must be found.
After that the molar ratio between HgO and O must be found but in this case its 1:1
[tex]4.241 mol HgO*\frac{1 molO}{1molHgO} = 4.241 mol O[/tex] the mols of HgO is put on the bottom to cancel out with the other one leaving just mols of oxygen. Finally to find g of oxygen it must be multiplied by its molar mass.
[tex]\frac{4.241 molO}{1} * \frac{15.999 g}{mol} = 67.85 g[/tex] Oxygen
You react 0.017 mol of solid metal with HCl in a coffee cup calorimeter (reaction shown below). The calorimeter has 100 mL of water in it, and the temperature of the water increases by 3.81°C. The calorimeter has a heat capacity of 40.4 J/°C. What is the enthalpy of the reaction in terms of kJ per mol of the metal (your answer should be NEGATIVE, remember to convert from J to kJ, specific heat capacity of water is 4.184 J/g-°C)?
M(s) + 2 HCl (aq) MCl2 (aq) + H2 (g)
M = metal
The enthalpy of the reaction is -94.1308 kJ/mol of the metal.
First, we need to calculate the amount of heat absorbed by the water in the calorimeter. We can use the formula:
q = m × C × ΔT
where q is the amount of heat absorbed by the water, m is the mass of the water, C is the specific heat capacity of water, and ΔT is the temperature change of the water.
q = 100 g × 4.184 J/g-°C × 3.81°C = 1601.304 J
Next, we need to calculate the amount of heat released by the reaction. We can use the formula:
q = n × ΔH
where q is the amount of heat released, n is the number of moles of the metal, and ΔH is the enthalpy change of the reaction.
We know that 0.017 moles of metal reacted, and we can assume that all the heat released by the reaction was absorbed by the water in the calorimeter.
Therefore:
q = n × ΔH
1601.304 J = 0.017 mol × ΔH
ΔH = 1601.304 J / 0.017 mol = 94130.8235 J/mol
Finally, we need to convert the answer from joules to kilojoules:
ΔH = 94130.8235 J/mol / 1000 J/kJ = -94.1308 kJ/mol
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Chemistry balance equation
At equilibrium, the value of K = 0.00659 for the reaction: N₂ (g) + 3 H₂ (g) ← → 2 NH₃ (g). Calculate [N₂] when [NH₃] = 0.000123 M and [H₂] = 0.0275 M
The concentration of the ammonia from the calculation is [tex]1.1 * 10^-15[/tex]M.
What is the equilibrium constant?The ratio of the concentrations of products to reactants in chemical equilibrium, for a given chemical reaction at a given temperature, is described by the equilibrium constant, abbreviated as Kc or Keq.
We can see that;
[tex]Keq = [NH_{3} ]^2/[N_{2} ] [ H_{2}]^3\\Keq[N_{2} ] [ H_{2}]^3 = [NH_{3}]^2\\\\N_{2} ] = [NH_{3}]^2/Keq[ H_{2}]^3[/tex]
=[tex](0.000123 )^2/ 0.00659 * (0.0275)^3= 1.1 * 10^-15 M[/tex]
Thus we would have the nitrogen concentration as [tex]1.1 * 10^-15[/tex] M
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A container of hellum has 4.3 moles of gas in a container with a volume of 3.9 liters and a pressure of 201.6kPa at 298K. A container of xenon has a volume of 3.9 liters
and a pressure of 201.6kPa at 298K. How many moles of xenon gas is present?
The ideal gas law states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin. Rearranging the equation, we get:
n = PV/RT
For the container of helium:
n = (201.6 kPa) x (3.9 L) / [(8.31 J/mol*K) x (298 K)] = 0.0688 mol
Now, using the same equation for the container of xenon:
n = (201.6 kPa) x (3.9 L) / [(8.31 J/mol*K) x (298 K)] = 0.0688 mol
Therefore, there are also 0.0688 moles of xenon gas present in the container.
If an atom loses an electron, what will its resulting charge be?
Answer:
If an atom loses or gains electrons, it will become a positively or negatively charged particle, called an ion. The loss of one or more electrons results in more protons than electrons and an overall positively charged ion, called a cation.
Hope it helped! :)
arrange the following electrons, represented by their quantum numbers, in increasing order of energy (lowest written first)
(1,0,0,-1/2); (3,1,1,1/2); (2,1,0,-1/2); (2,1,0,-1/2); (3,2,0,-1/2)
The electrons can be arranged in increasing order of energy as follows: (1,0,0,-1/2) < (2,1,0,-1/2) < (2,1,0,-1/2) < (3,1,1,1/2) < (3,2,0,-1/2).
The energy of an electron is determined by its principal quantum number (n), azimuthal quantum number (l), magnetic quantum number (m), and spin quantum number (s). The electrons can be arranged in increasing order of energy by comparing their quantum numbers.
Starting with the lowest energy electron, we have the electron with quantum numbers (1,0,0,-1/2). This electron has the lowest principal quantum number, indicating that it occupies the lowest energy level.
It also has an azimuthal quantum number of zero, which corresponds to the s subshell, and a negative spin quantum number, indicating that its spin is aligned opposite to the magnetic field.
Next, we have the two electrons with quantum numbers (2,1,0,-1/2). These electrons have the same principal quantum number, indicating that they occupy the same energy level.
They both have an azimuthal quantum number of one, which corresponds to the p subshell, and a negative spin quantum number.
Following these electrons, we have the electron with quantum numbers (3,1,1,1/2). This electron has a higher principal quantum number than the previous electrons, indicating that it occupies a higher energy level.
It has an azimuthal quantum number of one, which corresponds to the p subshell, and a positive spin quantum number.
Finally, we have the electron with quantum numbers (3,2,0,-1/2). This electron has the highest azimuthal quantum number of all the electrons, indicating that it occupies the d subshell. It also has a negative spin quantum number.
Therefore, the electrons can be arranged in increasing order of energy as follows: (1,0,0,-1/2) < (2,1,0,-1/2) < (2,1,0,-1/2) < (3,1,1,1/2) < (3,2,0,-1/2).
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Pleae answer 2a and 2b
A chemical interaction between an acid and a base is known as an acid-base reaction.
Thus, These are known as acid-base theories, such as the Brnsted-Lowry acid-base theory, and they offer alternative conceptions of the reaction mechanisms and their application in solving related problems.
When examining acid-base reactions for gaseous or liquid species, or when the acid or basic character may be less obvious, their significance becomes clear.
The relative potency of the conjugated acid-base pair in the salt controls the pH of its solutions when weak acids and bases react. The resulting salt or its solution can be basic, neutral, or acidic. A strong acid and a weak base can combine to generate an acid salt.
Thus, A chemical interaction between an acid and a base is known as an acid-base reaction.
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Calculate the amount of energy (in kJ) required to increase the temperature of 255 g of water from 25.2 C to 90.5 C. Specific heat of water is 4.184J/g C.
Answer:
70.91 kJ
Explanation:
The amount of energy (in kJ) required to increase the temperature of 255 g of water from 25.2 C to 90.5 C can be calculated using the formula:
Q = m * c * ΔT
Where Q is the amount of energy, m is the mass of the substance, c is the specific heat, and ΔT is the change in temperature.
Substituting the given values:
m = 255 g
c = 4.184 J/g C
ΔT = (90.5 - 25.2) C = 65.3 C
Q = 255 g * 4.184 J/g C * 65.3 C
Q = 70905.564 J
Q = 70.91 kJ (rounded to two decimal places)
Therefore, the amount of energy required to increase the temperature of 255 g of water from 25.2 C to 90.5 C is 70.91 kJ.
A balloon vendor at a street fair is using a tank of helium to fill her balloons. The tank has a volume of 109.0 L and a pressure of 107.0 atm at 25.0 °C. After a while she notices that the valve has not been closed properly. The pressure had dropped to 97.0 atm. (The tank is still at 25.0 °C.) How many moles of gas has she lost?
The number of mole of the gas lost, given that the pressure had dropped to 97.0 atm is 44.5 moles
How do i determine the number of mole lost?First, we shall determine the initial mole of the gas. Details below:
Initial volume (V₁) = 109.0 LInitial temperature (T₁) = 25 °C = 25 + 273 = 298 KInitial pressure (P₁) = 107.0 atmGas constant (R) = 0.0821 atm.L/mol KInitial mole (n₁) =?P₁V₁ = n₁RT₁
107 × 109 = n₁ × 0.0821 × 298
Divide both sides by (0.0821 × 298)
n₁ = (107 × 109) / (0.0821 × 298)
n₁ = 476.7 mole
Next, w shall determine the final mole of the gas. Details below
Final volume (V₂) = 109.0 LFinal temperature (T₂) = 25 °C = 25 + 273 = 298 KFinal pressure (P₂) = 97.0 atmGas constant (R) = 0.0821 atm.L/mol KFinal mole (n₂) =?P₂V₂ = n₂RT₂
97 × 109 = n₂ × 0.0821 × 298
Divide both sides by (0.0821 × 298)
n₂ = (97 × 109) / (0.0821 × 298)
n₂ = 432.2 mole
Finally, we shall determine the mole of the gas that was lost. Details below:
Initial mole (n₁) = 476.7 molesFinal mole (n₂) = 432.2 molesMole lost =?Mole lost = n₁ - n₂
Mole lost = 476.7 - 432.2
Mole of gas lost = 44.5 moles
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which one have least PH
a. CH3CH2COOH
b. CH2CLCH2COOH
c. CH3CHCL2COOH
d. CH3CH2CH2COOH
CH₃CHCl₂COOH is 2,2-dichloropropanoic acid, with the least pH, option (c) is correct.
pH is a measure of the acidity or basicity of a solution. A lower pH indicates a higher acidity. Acidity is due to the presence of hydrogen ions (H⁺) in a solution. The more the concentration of H⁺, the lower the pH. CH₃CH₂COOH is propanoic acid, which has a pH of around 4.9.
CH₂ClCH₂COOH is 2-chloropropanoic acid, which has a pH of around 2.8 due to the electron-withdrawing effect of the chlorine atom. CH₃CH₂CH₂COOH is butanoic acid, which has a pH of around 4.8. Thus, CH₃CHCl₂COOH is 2,2-dichloropropanoic acid, which has the least pH among the given options, around 1.5 due to the presence of two electron-withdrawing chlorine atoms, option (c) is correct.
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A 1.5 M solution of HCl has 145 g of HCl dissolved, what is the volume of the solution?
The volume of the 1.5M solution of HCl solution that has 145g of mass is 2.65L.
How to calculate volume?The volume of a solution can be calculated by dividing the number of moles by its molar concentration as follows;
Volume = no of moles ÷ molarity
According to this question, a 1.5M solution of HCl has 145g of mass. The number of moles can be calculated as follows:
no of moles = 145g ÷ 36.5g/mol = 3.973 moles
volume of HCl solution = 3.973mol ÷ 1.5M
volume of HCl = 2.65L
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After writing the correct formulas for the reactants and products, the equation is balanced by a. adjusting subscripts to the formula(s). b. adjusting coefficients to the smallest whole-number ratio. c. changing the products formed. d. making the number of reactants equal to the number of products.
After writing the correct formulas for the reactants and products, the equation is balanced by adjusting coefficients to the smallest whole-number ratio. The correct answer is option b.
Adjusting the coefficients to the smallest whole-number ratio is the process of balancing a chemical equation. Balancing the equation means that the number of atoms of each element on the reactant side must equal the number of atoms of each element on the product side.
The coefficients in front of the formulas of the reactants and products are used to balance the equation. By adjusting the coefficients, you can make sure that the number of atoms of each element is balanced on both sides of the equation. Therefore option b is correct
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100 POINTS PLEASE HELP!!! 1. Explain how you would determine the enthalpy of reaction for the hypothetical reaction A2X4(l) + X2(g) → 2AX3(g) using the following information. You do not need to calculate an answer. Respond to the prompt with a minimum response length of 50 words.
To determine the enthalpy of reaction for the given reaction, use Hess's Law, which states that the total enthalpy change of a reaction is independent of the pathway between the initial and final states.
How to determine the enthalpy of reaction?Break the given reaction into a series of steps for which the enthalpy changes are known or can be measured experimentally.
Add the enthalpy changes of each step to determine the overall enthalpy change for the reaction.
For example, determine the enthalpy of formation for A₂X₄(l), X₂(g), and AX₃(g) and use them to calculate the enthalpy of reaction for the given equation.
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What is the pH of a solution that has a H+ concentration of 1.9x10-6?
The pH of the solution is 5.72, which is slightly acidic.
pH is a measure of the acidity or basicity of a solution. It is defined as the negative logarithm of the hydrogen ion concentration (H+) in a solution. The pH scale ranges from 0 to 14, where a pH of 7 is neutral, pH below 7 is acidic, and pH above 7 is basic. The formula to calculate pH is pH = -log[H+], where [H+] represents the concentration of hydrogen ions in moles per liter.
Given the H+ concentration of 1.9x10-6, we can calculate the pH of the solution as follows:
pH = -log(1.9x10-6) = 5.72
It is important to note that pH is an important factor in various chemical and biological processes. It can affect the solubility of certain substances, enzymatic activity, and the growth and survival of living organisms. Maintaining the appropriate pH is crucial for the proper functioning of these processes.
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A pH of 5 is considered to be neutral
Answer:
No,a pH of 5 is slightly acidic,not neutral. A pH of 7 is considered neutral
A bag of potato chips is sealed in a factory near seal level. The atmospheric pressure is 99.82 kPa. What is the difference in Pa between the pressure in the bag and the atmospheric pressure?
The difference in Pa between the pressure in the bag and the atmospheric pressure is 1.505 kPa.
How to obtain the difference in pressureTo obtain the difference in pressure, we first need to know the atmospheric pressure near sea level. This is 760 mm Hg. When we convert this to pascals, we will have, 101.32472 kPa.
Now, the difference in pressure will be obtained by subtracting the atmospheric pressure in the bag from the atmospheric pressure near sea level and this is:
101.32472 kPa - 99.82 kPa
= 1.505 kPa.
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please provide explanation!! thank you in advance!!
The molarity of the product is 0.00368 M. Option B
What is the reaction equilibrium?When the rates of the forward and reverse reactions in a chemical reaction are equal and the concentrations of reactants and products are stable over time, this condition is referred to as reaction equilibrium.
The equilibrium constant is a measure of the relative concentrations of reactants and products at equilibrium.
[tex]Keq = [H_{2} O] [CO]/[H_{2}] [CO_{2} ]\\0.106 = x^2/(0.0113)^2\\x = \sqrt{} 0.106 (0.0113)^2\\x = 0.00368 M[/tex]
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