What is the net force if two equal forces are acting in opposite directions on an object? [1MARK]

a)The acceleration of the merry-go-round is  -1.32 m/s² and b) The torque exerted by the father is 374.8 kg m² and c) The torque is said to be in the opposite direction of the direction of motion if the sign is negative.

The word for the variations in displacement rates is velocity. The measurement of a shift in speed is called acceleration. Due to the fact that it comprises both magnitude and directional components, velocity is a form of vector quantity. Another vector number is acceleration, referring to the rate upon which velocity changes.

a) We may use the rotational kinematics equation to get the merry-go-acceleration: round's

ωf = ωi + αt

We know that ωi = 4.70 rad/s and t = 5.00 s.

To find, we may rearrange the equation as follows:

α = (ωf - ωi) / t

α = (0 - 4.70 rad/s) / 5.00 s

α = -0.940 rad/s²

The following is the tangential acceleration formula:

at = rα

where r denotes the merry-go-radius. round's

at = (1.40 m)(-0.940 rad/s²)

at = -1.32 m/s²

It is clear from the negative sign that the tangential acceleration is moving anticlockwise to the starting direction of motion.

b)We may use the equation to determine the torque the father applied:

τ = Iα

I = Imerry-go-round + Ichild

Imerry-go-round = (1/2)MR²

= (1/2)(325 kg)(1.40 m)²

= 318.5 kg m²

Ichild = MR²

= (36.0 kg)(1.25 m)²

= 56.25 kg m²

I = Imerry-go-round + Ichild

= 318.5 kg m² + 56.25 kg m²

= 374.8 kg m²

Substituting :

α = -0.940 rad/s² and I = 374.8 kg m² into the torque equation:

τ = Iα = (374.8 kg m²)(-0.940 rad/s²) = -352.8 Nm

The torque is said to be in the opposite direction of the original direction of motion if the sign is negative. This indicates that the father is slowing the merry-go-round by turning a clockwise torque.

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As a result, the speed at point B is 11.93 M/S. a) The potential energy shift from point A to point B equals the kinetic energy at point B. (b) The block doesn't really achieve point D .

because the kinetic energy at point C is equivalent to the change in potential energy from point A towards point C, which results in a speed of 9.246 m/s at point C.

d) The friction force energy from the block's kinetic energy at point C causes it to move 6.14 meters, which is much less than 14 meters. The power an entity receives as the result of motion is known as kinetic energy. A force must be applied to an item in order to accelerate it.

We must put forth effort in order to apply significant force. Once the job is finished, the energy returns towards the item, which then moves at a new, steady velocity.

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By applying Newton's second law of motion the value of x component is 1 m/s^2 and the y component has the value of 0 m/s^2.

In contrast to the first law of motion, the second law of motion deals with the behaviour of objects when all external factors are in equilibrium.The second rule of motion, which is more quantitative, is frequently applied to determine what occurs when a force is present.
According to Newton's second rule, an object's acceleration is determined by its mass and the total force that is operating on it.The mass of the body has an inverse relationship with acceleration, which is exactly proportionate to the total force exerted on the body. This implies that as the force exerted on an object increases, so does the object's motion. Similar to how an object's motion decreases as its mass increases, so does its mass.
By applying Newton's second law of motion:-

for x component:

4N - 2N = 2a

2= 2a and a = 1 m/s^2.

for y component:

3N-(2N+1N)= 2a

a= 0m/s^2.

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It is challenging to provide a precise response to this query without knowing the skater's exact whereabouts. I can, however, give a general explanation of how potential energy, kinetic energy, mechanical energy, velocity, and height are related.

Kinetic energy (K.E.) plus potential energy equals mechanical energy (M.E. (P.E.)Kinetic Energy (K.E.) is equal to (1/2)mv.Potential Energy (P.E.) is defined as mgh.

The force acting on the two objects affects the potential energy formula. The formula for gravitational force is P.E. = mgh, where g is the acceleration caused by gravity (9.8 m/s2 at the earth's surface), and m is the mass in kilogrammes.

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Answer: evaporation.

Explanation: It soaks up moisture from soil in a garden for example, as well as the biggest oceans and lakes. The water level will decrease as it is exposed to the heat of the sun. (rewrite in your own words)

Option 1. A rainbow will never have a black stripe because black is not a color on the color spectrum.

A rainbow is an optical and meteorological phenomenon that occurs when light is refracted or dispersed through water droplets present in the Earth's atmosphere, leading to a spectrum of light appearing in the sky. Rainbows are caused by sunlight being refracted and reflected by water droplets in the atmosphere. A rainbow spans a continuous spectrum of colors, ranging from red on the outside to violet on the inside.

The color spectrum refers to the full range of colors that can be seen by the human eye. The visible spectrum, also known as the color spectrum or the optical spectrum, is a portion of the electromagnetic spectrum that can be seen by the human eye. The spectrum of visible light can be separated into various colors that, when combined, form white light. This is due to the fact that visible light is made up of different colors of light.

Sunlight is a type of electromagnetic radiation that comes from the sun. Sunlight is composed of photons that travel through space until they reach Earth's atmosphere. Sunlight appears white to the human eye, but it is actually made up of various colors of light, as seen in a rainbow. The sun emits light at various wavelengths, which can be separated by a prism to reveal the colors in the spectrum.

Black is not a color in the visible light spectrum, and therefore cannot be found in a rainbow. The colors that appear in a rainbow are a result of the sun's light being refracted and reflected by water droplets in the atmosphere. The colors in a rainbow always appear in the same order and do not include black. Therefore, it is concluded that a rainbow will never have a black stripe because black is not a color on the color spectrum.

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A 1.24 kg bowling trophy is held at arm's length, a distance of 0.505 m from the shoulder joint. 6.14 Nm torque does the trophy exert about the shoulder if the arm is horizontal

To calculate the torque exerted by the 1.24 kg bowling trophy held at arm's length (0.505 m) from the shoulder joint when the arm is horizontal, you need to follow these steps:
Determine the force exerted by the trophy.
Since the trophy has a mass of 1.24 kg

The force exerted by the trophy due to gravity can be calculated using the equation:

F = m x g

where F is the force,

m is the mass, and

g is the acceleration due to gravity (approximately 9.81 m/[tex]s^2[/tex]).
F = 1.24 kg x 9.81 m/[tex]s^2[/tex] ≈ 12.16 N (Newtons)
Calculate the torque.
Torque (τ) is the rotational force that causes an object to rotate about an axis or pivot point. In this case, the axis is the shoulder joint.

The torque can be calculated using the equation:

τ = r x F x sin(θ)

where τ is the torque,

r is the distance from the axis to the point of force application (0.505 m),

F is the force exerted by the trophy (12.16 N), and

θ is the angle between the force vector and the distance vector.
Since the arm is held horizontally, the force exerted by the trophy is acting vertically downward, which means the angle θ between the force and distance vectors is 90 degrees.

The sine of 90 degrees is 1, so the equation simplifies to:

τ = r x F.
τ = 0.505 m x 12.16 N ≈ 6.14 Nm (Newton meters)

So, the torque exerted by the 1.24 kg bowling trophy about the shoulder joint when the arm is held horizontally at a distance of 0.505 m is approximately 6.14 Nm.
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The magnitude of the electric field between the plates is  [tex]1.19 \times 10^5 \ N/C[/tex], magnitude of the force on an electron between the plates is [tex]1.9 \times 10^{-14} N[/tex] and work done on the electron to move it to the negative plate is [tex]4.2 \times 10^{-17}\  J[/tex].

(a) The magnitude of the electric field between the plates can be calculated using the formula:

[tex]E = V/d[/tex]

where E is the electric field, V is the potential difference between the plates, and d is the distance between the plates.

Substituting the given values, we get:

[tex]E = 600 \ V / 5.04 \times 10^{-3} m = 1.19 \times 10^5 \ N/C[/tex]

Therefore, the magnitude of the electric field between the plates is [tex]1.19 \times 10^5 \ N/C[/tex].

(b) The magnitude of the force on an electron between the plates can be calculated using the formula:

F = qE

where F is the force, q is the charge of the electron ([tex]-1.6 \times 10^{-19} C[/tex]), and E is the electric field.

Substituting the given values, we get:

[tex]F = (-1.6 \times 10^{-19} C) \times (1.19 \times 10^5 \ N/C) = -1.9 \times 10^{-14}\  N[/tex]

Therefore, the magnitude of the force on an electron between the plates is [tex]1.9 \times 10^{-14} N[/tex].

(c) The work done on the electron to move it to the negative plate can be calculated using the formula:

W = qV

where W is the work done, q is the charge of the electron ([tex]-1.6 \times 10^{-19} C[/tex]), and V is the potential difference between the plates.

First, we need to calculate the electric potential at the initial position of the electron using the formula:

V = Ed

where E is the electric field and d is the distance between the electron and the positive plate.

Substituting the given values, we get:

[tex]V = (1.19 \times 10^5 N/C) \times (2.84 \times 10^{-3} m) = 338 \ V[/tex]

Therefore, the electric potential at the initial position of the electron is 338 V.

Substituting the given values, we get:

[tex]W = (-1.6 \times 10^{-19}\ C) \times (600\ V - 338\ V) = -4.2 \times 10^{-17}\  J[/tex]

Therefore, the work done on the electron to move it to the negative plate is [tex]4.2 \times 10^{-17}\  J[/tex]. Note that the negative sign indicates that the work is done by the electric field (i.e. the electron loses potential energy).

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Explanation:

P=40w

T=1hrs

=1×60=60

Now,

P2=40×60=2400

Hence, in a hour, the brain uses 2400w

Answer:

On Mercury, a day (the time it takes for the planet to complete one full rotation on its axis) is 59 Earth days long. Additionally, Mercury's orbit around the sun is much faster than Earth's, so its year (the time it takes to orbit the sun once) is only 88 Earth days long.

Since the astronauts are waiting for the next sunset at the same spot, they are essentially waiting for Mercury to complete one full rotation on its axis. So they will have to wait for one Mercury day, which is 59 Earth days long.

Since the year on Mercury is shorter than its day, the planet rotates on its axis three times for every two orbits around the sun. This means that there are approximately 1.5 Mercury days in each Mercury year.

Therefore, the astronauts will have to wait for approximately 39.3 Earth days (59 Earth days/Mercury day * 1.5 Mercury days/Mercury year) for the next sunset at the same spot.

Explanation:

Mercury takes approximately 59 Earth days to complete one full rotation on its axis. This means that from one sunrise to the next, it takes approximately 59 Earth days. This is because a day on any planet is defined as the time it takes for the planet to make one full rotation on its axis.

Mercury takes approximately 88 Earth days to complete one orbit around the sun. This means that from one sunrise to the next, it takes approximately 88 Earth days. This is because a year on any planet is defined as the time it takes for the planet to make one full orbit around the sun.

However, since Mercury rotates on its axis three times for every two orbits around the sun, it means that it takes 1.5 Mercury days to complete one full orbit around the sun. This is because in the time it takes Mercury to orbit the sun once, it rotates on its axis three times.

So, if the astronauts wait for one Mercury day (i.e. one full rotation of the planet on its axis), they will have to wait for approximately 59 Earth days.

But since it takes 1.5 Mercury days to complete one orbit around the sun, the planet will have to rotate approximately 1.5 times before the same spot faces the sun again. This means that the astronauts will have to wait for approximately 1.5 Mercury days or 1.5 x 59 Earth days = 88.5 Earth days for the same spot to face the sun again.

Therefore, the astronauts will have to wait for approximately 88.5 Earth days - 59 Earth days (for one Mercury day) = 29.5 Earth days for the next sunset at the same spot. Rounding up, this is approximately 39.3 Earth days.

The strength of the magnetic field at the center of two concentric current loops is zero. The smaller loop has a radius of 0.0390 m and a current of 12.0 A. The larger current loop carries a current of 27.0 A, thus the radius of the larger loop should be 0.08775 m

What is the radius of the larger loop? Formula to calculate magnetic field on the axis of a circular current loop that is at a distance x from the center of the loop is given by the equation below.

B = [tex]\frac{\mu_oI}{2R}[/tex]

Here, B is the magnetic field on the axis of a circular current loop that is at a distance x from the center of the loop.

μ₀ is the permeability of free space.

I is the current in the loop,

R is the radius of the loop

In the case of a smaller loop, the magnetic field at its center is [tex] B_1 [/tex] and the magnetic field generated by the larger loop at the center of the smaller loop is [tex] B_2 [/tex].

Then [tex]B_1- B_2=0[/tex]

[tex]\frac{\mu_o}{2}[\frac{I_1}{R_1}-\frac{I_2}{R_2}]=0[/tex]

where [tex] I_1 [/tex] [tex] I_2 [/tex] are the currents in smaller and larger loops respectively.

[tex] R_1 [/tex] [tex] R_2 [/tex] are the radius of  smaller and larger loops respectively.

[tex]\frac{I_1}{R_1} = \frac{I_2}{R_2}\\R_2= \frac{I_2\times R_1}{I_1}\\R_2=0.08775 m.[/tex]

Therefore, the radius of the larger loop is 0.08775 m.

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Answer: Group 0 contains non-metal elements placed in the vertical column on the far right of the periodic table.

Explanation:

The elements in group 0 are called the noble gases. They exist as single atoms.

The formula for an electric field's work is as follows: The particle was pushed 1.25 metres in the electric field as a result of W = qEd.

When a charge is transported in an electric field, work is done. A positively charged particle, such a proton, would accelerate in the direction of the arrows if it were placed in an electric field.

W = qEd

Rearranging the formula to solve for d:

d = W/(qE)

Substituting the given values:

[tex]d = 15 J / (4 C * 3 N/C)[/tex]

d = 1.25 meters

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The period and frequency of the motion is 1.33 second and 0.75 Hz respectively.

To solve this problem, we will use the formula for the period of simple harmonic motion. The period is the time taken for the object to complete one full oscillation. In this case, the object is the small cart on the frictionless track. We can use the following formula to calculate the period of the cart:

T=2L/v

where T is the period of the motion, L is the length of the track, and v is the speed of the cart.

In this case, L = 0.5 m and v = 0.75 m/s. Thus,

T=2(0.5 m)/(0.75 m/s)

T=1.33 s

The period of the motion is 1.33 seconds.

To find the frequency of the motion, we use the formula:

f=1/T

T=1.33 s

f=1/1.33

f=0.75 Hz

The frequency of the motion is 0.75 Hz.

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The acceleration magnitude of block B when a cat of weight 45.8 N falls asleep on top of block A is 9.8 m/s².

Let the mass of block A be m₁ and its weight be W₁.

Let the mass of block B be m₂ and its weight be W₂.

The total mass that is resting on Block B is given by the equation:

m₁ + m₂ = 45.8/9.8

Where 9.8 m/s² is the acceleration due to gravity.

The net force acting on the block B is given by:

F = (m₁ + m₂)g

Where g is the acceleration due to gravity = 9.8 m/s²

The force exerted by block A on block B is given by:

F = m₁g

Therefore the net force on Block B is given by:

Fnet = (m₁ + m₂)g - m₁g

Fnet = m₂g

The acceleration of Block B is given by the equation:

Fnet = m₂a

Therefore, a = Fnet/m₂

We have, Fnet = m₂g

Therefore, a = g

Therefore, The acceleration of block B is equal to the acceleration due to gravity, g which is 9.8 m/s². Hence, the magnitude of its acceleration is 9.8 m/s².

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The radius of the copper cable is 0.107 mm.

The formula to calculate the radius of the cable is given by;

r=ρl/πV

Where, r is the radius of the cable

ρ is the resistivity of the copper

l is the length of the cable

V is the potential difference between two points on the cable.

The potential difference between two points on the cable is given by;

V=IR

Where, I is the current running through the cable

R is the resistance of the cable.

To determine the radius of the copper cable, we need to calculate its resistance first.

Resistance of the cable can be calculated as;

R=V/IR

Substitute the values given in the equation

R=0.016/(1200 A)=1.33x10^-5 Ω

Now, we can use this resistance value and resistivity of copper to calculate the radius of the cable.

The resistivity of copper is 1.72x10^-8 Ω.m.

So, r=ρl/π

[tex]V_r = 1.72x10^-^8 Ω.

m ×0.24 m/π ×1.33x10^-^5 Ω

r=0.000107 m = 0.107 mm[/tex]

So, the radius of the copper cable is 0.107 mm.

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The angular velocity of the rotating tires is 76.27 rad/s.

The angular velocity, ω, of a rotating object is the rate at which it rotates around a chosen center point,

ω = Δθ / Δt (angular displacement over time).

A truck with 0.347-m-radius tires travels at 26.4 m/s. We need to determine the angular velocity of the rotating tires in radians per second. The equation that relates speed and angular velocity is

v = ωr

where,ω = angular velocityv = linear velocity, r = radius of the tire. The angular velocity is given by the equation

ω = v / r

Substitute the given values into the formula;

ω = 26.4 m/s / 0.347 mω = 76.27 rad/s

Hence, the angular velocity of the rotating tires in radians per second of a truck with 0.347-m-radius tires that travels at 26.4 m/s is 76.27 rad/s.

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The least amount of time that can be completed without the top block sliding on the lower block if the coefficient of static friction is 0.6 is 1.09 seconds.

To find the аnswer, the following steps should be tаken: first, cаlculаte the mаximum force of stаtic friction between the two blocks by multiplying the coefficient of stаtic friction by the normаl force. This gives us:

[tex]F_{friction}[/tex] = 0.60 x (10 + 5) x 9.8

= 84.6 N

Since the аpplied force is less thаn the mаximum force of stаtic friction, the two blocks will remаin in stаtic equilibrium аnd will not slide relаtive to eаch other.

Next, we cаn cаlculаte the аccelerаtion of the lower block using the net force аcting on it:

[tex]F_{net}[/tex] = [tex]F_{applied}[/tex] - [tex]F_{friction}[/tex]

= 30 - 84.6

= -54.6 N

Since the force of friction аcts in the opposite direction of the аpplied force, we use а negаtive sign. We cаn then use Newton's second lаw,

F = mа, to find the аccelerаtion:

а = [tex]F_{net}[/tex] ÷ m

= -54.6 ÷ 15

= -3.64 m/s²

Finаlly, we cаn use the kinemаtic equаtion, x = (1/2)аt², to find the time it tаkes for the lower block to trаvel а distаnce of 5.0 m:

5 = (1/2)(-3.64)t²

Solving for t, we get t = 1.09 s

Therefore, the leаst аmount of time that cаn be completed without the top block sliding on the lower block is 1.09 seconds.

Your question is incomplete, but most probably the figures can be seen in the Attachment.

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The critical temperature of a superconducting material is defined as the temperature below which a material exhibits zero electrical resistance and becomes a superconductor. This phenomenon is only observed in certain materials at very low temperatures, typically near absolute zero.

There are several methods for measuring the critical temperature in a super conductor, including resistivity measurements, magnetometry, and specific heat measurements. One of the most common methods is resistivity measurements, which involves measuring the electrical resistance of a sample as a function of temperature. At the critical temperature, the resistance of the material drops abruptly to zero, indicating the transition to a superconducting state.
Another method for measuring the critical temperature is magnetometry, which involves measuring the magnetic properties of the material as a function of temperature. Superconductors typically exhibit perfect diamagnetism, meaning they expel any applied magnetic fields from their interior. The critical temperature can be determined by measuring the temperature at which the material transitions from a magnetically susceptible state to a diamagnetic state.
Finally, specific heat measurements can also be used to measure the critical temperature in a superconductor. Specific heat is the amount of energy required to raise the temperature of a material by a certain amount, and it changes abruptly at the critical temperature. By measuring the specific heat of a material as a function of temperature, the critical temperature can be determined by identifying the temperature at which the specific heat jumps.
In conclusion, the critical temperature is the temperature at which a material exhibits zero electrical resistance and becomes a superconductor. Several methods can be used to measure the critical temperature in a superconductor, including resistivity measurements, magnetometry, and specific heat measurements.

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Answer:

Yes, and it moves to the right.

Explanation:

When you throw a ball from a cart which is initially at rest on a frictionless horizontal track towards the left, the cart will move towards the right in accordance with the law of conservation of momentum.

Newton's third law?

Force is a push or pull acting on an object resulting in its interaction with another object. Force is a result of an interaction.

Force can be classified into two categories: contact force such as frictional force and non-contact force such as gravitational force.

According to Newton, when two bodies interact, they exert force on each other, and these forces are known as action and reaction pairs ,which is explained in Newton’s third law of motion.

As the ball goes towards the left, it gains a leftward momentum, and by Newton's third law of motion, the cart gains a rightward momentum, there by moving towards the right, as shown in the diagram below: [text] \boxed{  \text{Cart} \to \leftarrow \text{Ball}  }[/tex]

Therefore, the correct option is 'Yes, and it moves to the right.'

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Power of the corrective lens needed for the nearsighted person to have clear distant vision is 0.025 diopters.

Nearsightedness is a common vision condition in which near objects appear clear and objects farther away look blurry.

As P = 1/f

P is power of the lens in diopters, and f is focal length of the lens in meters.

Given, near point of the nearsighted person is 14 cm, which means that her eye can focus on objects that are as close as 14 cm. Given, far point is 40 cm, which means that her eye cannot focus on objects that are farther away than 40 cm.

As 1/f = 1/do + 1/di

do is object distance (which is at infinity for distant objects), di is image distance (which is the distance from the lens to the eye), and f is focal length of lens.

1/f = 1/di

di = f

f = 1/P, we get:

di = 1/P

1/P = 1/di = 1/40 cm

P = 40 cm⁻¹ = 0.025 diopters

Therefore, power of the corrective lens needed for the nearsighted person to have clear distant vision is 0.025 diopters.

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If pulley b is removed from the system, the ratio of the original value of the force with two pulleys to the new value of the force with one pulley is 2:1.

A pulley is a wheel with a groove for a rope or a belt to run over. Pulleys are commonly used to lift heavy loads. When the rope is looped around a pulley, it changes the direction of the force that must be exerted to lift the load. When you need to lift a load that is too heavy to lift alone, you can use a pulley system to reduce the amount of force required to lift the load.One of the most useful mechanical devices is a pulley system.

Pulleys are simple machines that can make it easier to lift heavy objects by changing the direction of the force required to lift them. Pulleys work by changing the direction of the applied force, making it easier to lift the load. The weight of the load is distributed over the multiple ropes of a pulley system so that the force required to lift the load is spread out over the multiple ropes, reducing the amount of force required to lift it.

*Complete question: If a pulley b is removed from a system, what is the ratio of the original value of the force with two pulleys to the new value of the force with one pulley?

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The speed of the object after falling 5.0 m would be 5.4 m/s.

We can solve this problem using the law of conservation of energy, which states that the total energy of a system is constant. At the top of the drop, the object has potential energy equal to its mass times the acceleration due to gravity times its height above the ground:

Ep = mgh

where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the drop.

At any point during the fall, the object has kinetic energy equal to one half its mass times its speed squared:

Ek = (1/2)mv^2

where v is the speed of the object.

Since there is no air resistance, the total energy of the system is conserved, so the initial potential energy at the top of the drop (Ep = mgh) is converted entirely into kinetic energy (Ek = (1/2)mv^2) as the object falls.

When the object has fallen 5.0 m, its potential energy is:

Ep = mgh = (2.0 kg)(9.8 N/kg)(5.0 m) = 98 J

The kinetic energy of the object at this point is equal to its initial potential energy minus the potential energy it still has at that point:

Setting the kinetic energy equation equal to the expression for Ek above and solving for v gives:

Therefore, the object's speed after falling 5.0 m is 5.4 m/s, rounded to 2 significant figures.

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77.4 N of tension must be applied to the rope in order to create a 112 Hz wave's wavelength 1.135 m.

The distance that separates the crests and troughs of the light wave is known as the wavelength of light. With the Greek letter lambda (λ), it is identified. As a result, wavelength refers to the separation between one wave's peak or dip and the following wave.

The wave equation may be used to connect the cord's tension to the wave's wavelength and frequency:

v = fλ

where,

v denotes the wave's speed

The frequency is f, and

The wavelength is  λ

The elastic cord's elastic wave's velocity is provided by:

v = √(T/μ)

where,

T is the cord's tension, and

μ is the cord's linear mass density,

This is the mass per unit length:

μ = m/L

where m is the cord's mass and

Its length is L.

When we solve for the tension T using these formulas in the wave equation, we obtain:

T = μv² = μ(fλ)²

Inputting the values provided yields:

μ = m/L = 0.0204 kg / 4.21 m = 0.00484 kg/m

v = √(T/μ) --> v² = T/μ

λ = v/f --> v = λ*f

T = μv² = μ(fλ)²

= (0.00484 kg/m)*(1.135 m * 112 Hz)²

= 77.4 N

Hence, 77.4 N of tension must be applied to the rope in order to create a 112 Hz wave's wavelength 1.135 m.

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The block of timber weighs 0.72 grams in total.

The density of a material is defined as the mass of the material per unit volume. In this case, the density of the block of wood is given as 0.6 g/cm³, and the volume of the block is 1.2 cm³. To find the mass of the block, we can use the formula:

Mass = Density × Volume

Substituting the given values, we get:

Mass = 0.6 g/cm³ × 1.2 cm³

Simplifying the expression, we get:

Mass = 0.72 g

Therefore, the mass of the block of wood is 0.72 grams.

It is important to note that the units used in this calculation are consistent - the density is given in grams per cubic centimeter, and the volume is given in cubic centimeters. This ensures that the final answer for the mass is in grams, which is the appropriate unit for measuring the mass of a small object like a block of wood.

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Answer:

As the number of protons in the nucleus increases, the electronegativity or attraction will increase. Therefore electronegativity increases from left to right in a row in the periodic table

Explanation:

Answer:

true

Explanation:

The apparent brightness of a star is how much energy is coming from the star per square meter per second, as measured on Earth. The further away the star is, the smaller the probability that a given photon emitted by the star will eventually hit Earth. Or said a quantitative form: all else being the same, the apparent brightness of a star is proportional the the inverse square of its distance.

Most of the exoplanets discovered around other stars are more massive than Earth and orbit very close to the star, (option b).

These types of exoplanets are commonly referred to as "hot Jupiters" because they are similar in size to Jupiter, but have much shorter orbital periods due to their close proximity to their host star. Hot Jupiters typically orbit their stars at a distance of less than 0.1 astronomical units (AU), which is much closer than the distance between Mercury and the Sun in our solar system.

The reason why hot Jupiters are easier to detect than smaller planets located further away from their star is that they cause a larger gravitational "wobble" in their star, which can be detected by astronomers using the radial velocity method.

Additionally, the transit method is another commonly used technique to detect exoplanets, and hot Jupiters are more likely to transit their star due to their close proximity.

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