What mass of carbon dioxide is produced from the complete combustion of 8.40x10-3g of methane?

A sample lab report that measures pH levels is given below:

Introduction:

In this experiment, we measured the pH levels of various substances using a pH meter. The pH meter measures the acidity or basicity of a substance on a scale of 0 to 14, with 0 being extremely acidic, 7 being neutral, and 14 being extremely basic.

Materials:

pH meter

Distilled water

Hydrochloric acid (HCl)

Sodium hydroxide (NaOH)

Vinegar

Lemon juice

Baking soda

Tap water

Procedure:

Calibrated the pH meter according to the manufacturer's instructions using distilled water.

Prepared five test solutions in beakers:

50 mL of 0.1 M HCl

50 mL of 0.1 M NaOH

50 mL of vinegar

50 mL of lemon juice

50 mL of baking soda

Rinsed the pH meter probe with distilled water and then dipped it into each test solution, making sure that the probe did not touch the bottom or sides of the beaker.

Recorded the pH measurement for each solution and compared it to the expected pH range based on the known properties of the substances.

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Answer:

I have attached my interpretation of the pH measuring lab.  All I ask is that you at least change some of the answers, please  

Explanation:

The ball will sink because its weight is greater than the amount of water it displaces. Since their weight is less than the amount of water they displace, objects made of aluminium foil like a boat, paper and cups will float on water.

Whether an item will float or sink in another material depends on its density. If an object's density is lower than the liquid it is placed in, it will float. If an object is heavier than the liquid it is immersed in, it will sink.

While individuals may create their goods or aluminium foils with the aluminium, beating the metal to form aluminium foil is a physical change.

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The mass of butane needed to produce 67.5 g of carbon dioxide is 22.27 g.

The balanced chemical equation for the combustion of butane (C4H10) is:

2 C4H10 + 13 O2 → 8 CO2 + 10 H2O

This equation shows that 2 moles of butane react with 13 moles of oxygen to produce 8 moles of carbon dioxide. The molar mass of butane is 58.12 g/mol, and the molar mass of carbon dioxide is 44.01 g/mol.

To calculate the mass of butane needed to produce 67.5 g of carbon dioxide, we can use the following steps:

Calculate the number of moles of carbon dioxide produced:

67.5 g CO2 x (1 mol CO2 / 44.01 g CO2) = 1.534 mol CO2

Use the mole ratio from the balanced chemical equation to find the number of moles of butane needed:

1.534 mol CO2 x (2 mol C4H10 / 8 mol CO2) = 0.3835 mol C4H10

Calculate the mass of butane needed:

0.3835 mol C4H10 x 58.12 g/mol = 22.27 g C4H10

Therefore, the mass of butane needed to produce 67.5 g of carbon dioxide is 22.27 g.

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we need to mix 3.68 g of Na2HPO4 and 2.89 g of NaH2PO4 to prepare 1.00 L of a buffer with a total phosphate concentration of 0.0500 M and a pH of 7.45.

pH = pKa + log([base]/[acid])

Substituting the values:

7.45 = 7.20 + log([Na2HPO4]/[NaH2PO4])

0.25 = log([Na2HPO4]/[NaH2PO4])

Antilog(0.25) = [Na2HPO4]/[NaH2PO4]

1.78 = [Na2HPO4]/[NaH2PO4]

Let x be the amount of Na2HPO4 in moles and y be the amount of NaH2PO4 in moles.

Then:

x + y = 0.0500 (total moles of phosphate)

141.96x + 119.98y = (0.0500)(141.96 + 119.98) (total mass of phosphate)

Solving these equations simultaneously, we get:

x = 0.0259 mol

y = 0.0241 mol

Mass of Na2HPO4 = 0.0259 mol × 141.96 g/mol = 3.68 g

Mass of NaH2PO4 = 0.0241 mol × 119.98 g/mol = 2.89 g

Concentration in chemistry refers to the amount of a substance dissolved in a given volume of a solvent. It is a fundamental concept in chemistry and is used to describe the strength of a solution. The concentration of a solution is usually expressed in terms of the amount of solute present per unit volume of the solution. There are several ways to express concentration, including molarity, molality, mole fraction, and percent by mass or volume.

Molarity is the most commonly used unit of concentration and is defined as the number of moles of solute per liter of solution.  The concentration of a solution plays an important role in determining its properties and behavior. For example, a highly concentrated solution of salt will have a higher boiling point and lower freezing point than a dilute solution. Concentration also affects the rate of chemical reactions, as higher concentrations of reactants typically result in faster reaction rates.

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Answer:

At STP (standard temperature and pressure), the conditions are:

Temperature (T) = 273.15 K

Pressure (P) = 1 atm = 101.3 kPa

Volume (V) = 22.4 L (for one mole of gas)

So, for a gas at STP with a volume of 5 L, we can use the following formula to calculate the number of moles present:

n = V / Vm

where:

n = number of moles

V = volume of gas (in liters)

Vm = molar volume of gas at STP (22.4 L/mol)

Plugging in the values, we get:

n = 5 L / 22.4 L/mol

n = 0.2232 mol (rounded to four significant figures)

Therefore, there are approximately 0.2232 moles of the gas present.

(Please could you kindly mark my answer as brainliest you could also follow me so that you could easily reach out to me for any other questions)

Answer:

204.8 K

Explanation:

(P1 * V1)/T1 = (P2 * V2)/T2

"If the pressure remains constant" means

you can cancel the pressure part of the equation

T2 = (V2 * T1)/(V1)

T2 = (2.64 L * 453 K)/(5.82 L)

T2 = 204.8 K

chatgpt

A sample of xenon gas occupies a volume of 5.82 L at 453 K. If the pressure remains constant, the temperature that will make this same xenon gas sample have a volume of 2.64 L is 220K.

The combined gas law is the law of of gaseous state which is made by combination of Boyle's law, Charle's law, Avogadro's law and Gay Lussac's law.

It is a mathematical expression that relates Pressure, Volume and Temperature.

(P1 × V1)÷T1 = (P2 × V2)÷T2

We can also use the following relation-

PV = nRT

At constant pressure,

V1÷T1 = V2÷T2

This is Charles's law.

V1 = 5.82L

T1 = 453K

V2 = 2.64L

T2 = ?

T2 = 220K

Therefore, A sample of xenon gas occupies a volume of 5.82 L at 453 K. If the pressure remains constant, the temperature that will make this same xenon gas sample have a volume of 2.64 L is 220K.

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The percent of C in Ca(C2H3O2)2 is 27.28%.

The formula mass of Ca(C2H3O2)2 is 158.17 g/mol.

The percent of H in Ca(C2H3O2)2 is 2.54% and the percent of O is 54.50%.

To find the percent of C in Ca(C2H3O2)2, we first need to calculate the molar mass of the compound:

Molar mass of Ca(C2H3O2)2 = (1 × 40.08) + (2 × (2 × 12.01 + 3 × 1.01 + 2 × 16.00)) = 2 × 158.17 = 316.34 g/mol

Now we can calculate the percent of C:

Mass of C in Ca(C2H3O2)2 = 2 × (2 × 12.01) = 48.04 g/mol

Percent of C in Ca(C2H3O2)2 = (48.04 g/mol ÷ 316.34 g/mol) × 100% = 15.19%

Therefore, the percent of C in Ca(C2H3O2)2 is 15.19%, rounded to the hundredths place.

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Assuming the volume of the tire remains constant, we can use the ideal gas law to determine the pressure of the tire at the higher temperature:

P1/T1 = P2/T2

where P1 is the initial pressure, T1 is the initial temperature, P2 is the final pressure (what we're trying to find), and T2 is the final temperature.

Converting the temperatures to Kelvin (as the ideal gas law requires temperatures in Kelvin), we have:

P1/T1 = P2/T2

P1 = 2.25 atm

T1 = 20 + 273.15 = 293.15 K

T2 = 45 + 273.15 = 318.15 K

Solving for P2, we get:

P2 = P1(T2/T1)

P2 = 2.25 atm (318.15 K / 293.15 K)

P2 = 2.44 atm (rounded to two significant figures)

Therefore, the pressure in your tires at 45°C would be approximately 2.44 atm.

The mass of the water that is going to be produced from the balanced reaction equation is 84 g.

Stoichiometry is the branch of chemistry that deals with the quantitative relationship between the reactants and products in a chemical reaction. It involves the calculation of the amounts of reactants needed to produce a certain amount of product, or the amount of product produced from a given amount of reactants.

Number of moles of Fe = 195.9 g/56 g/mol

= 3.5 moles

If 3 moles of Fe is produced when 4 moles of water is produced

3.5 moles of Fe is produced when 3.5 * 4/3

= 4.7 moles

Now we have that the mas of water is;

4.7 moles * 18 g/mol

= 84 g

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When 50.0 mL of distilled water is added to 100.0 mL of a saturated solution of copper (I) chloride (KSP = 1.72x10-7) with some solid present, the answer becomes diluted.

When 50.0 mL of distilled water is added to 100.0 mL of a saturated solution of copper (I) chloride (KSP = 1.72x10-7) with some solid present, the [Cu+] will decrease because the answer is now less concentrated. The solid in the beaker will remain the same because the solution is still saturated.

The first beaker will expand when heat is applied because it will absorb the heat. Therefore the water level will first decrease due to the beaker's increased volume. Water will eventually warm up and expand as its temperature rises. Water level will consequently rise later.

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Esterification is a chemical reaction between an alcohol and a carboxylic acid that results in the formation of an ester and a molecule of water.

Esterification  is an important class of organic reactions and is widely used in the synthesis of flavors, fragrances, and plastics. In this report, we will explore the fundamental principles and practical applications of esterification.

The experimental procedure involves the reaction between methanol and acetic acid to form methyl acetate and water. The reaction was carried out in a round-bottom flask equipped with a condenser and a thermometer. The reactants were mixed in stoichiometric amounts, and a small amount of sulfuric acid was added as a catalyst. The flask was heated using a hot plate and maintained at a constant temperature of 60°C.

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The amount of energy for the reaction using Hess's Law is -459.82 kJ/mol.

Based on the calculation, the formation is exothermic.

To use Hess' Law, we need to rearrange and multiply the given chemical equations to get the desired equation:

2 Mg + 2 HCl → 2 MgCl₂ + H₂ (multiply Equation 1 by 2)

2 MgO + 4 HCl → 2 MgCl2 + 2 H₂O (multiply Equation 2 by 2)

2 H₂ + O₂ → 2 H₂O (multiply Equation 3 by 2)

2 Mg + O₂ + 4 HCl → 2 MgCl₂ + 2 H₂O (add the above equations)

The enthalpy change of the desired equation can be calculated as follows:

AH = [AH₁ × 2] + [AH₂ × 2] + [AH₃ × (-2)]

AH = [(Answer to #5 -1) × 2] + [(-125 kJ/mol) × 2] + [(-285.82 kJ/mol) × (-2)]

AH = [-457.82 - 2] kJ/mol

AH = -459.82 kJ/mol

Since the value of AH is negative, the formation of MgO is exothermic. This means that energy is released during the formation of MgO.

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Because it demonstrated how the atoms of copper and silver were changed by oxidation and reduction, the experiment achieved its goal. The presence of a specific halogen in a presumed halogenoalkane can be determined using silver nitrate solution.

Calculating the products and reactants of a chemical process is what we mean by stoichiometry. Numbers are essentially its main focus. When using balanced formulas to determine the proportions of reactants and products, stoichiometry is a key concept in chemistry.

The study of quantifiable correlations found in chemical equations and reactions is known as stoichiometry. The terms stoicheion, which means element, and metron, which means measure, are the origins of the name.

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The symbol of the ion is U 2+

U represents the element uranium, and

the superscript 2+ indicates that charge

The atomic number (Z) of an element represents the number of protons found in the nucleus of an atom. In a neutral atom, the number of electrons is equal to the number of protons. However, in an ion, the number of electrons can differ from the number of protons.

To find the symbol for an ion with 87 electrons and a Z of 89, we need to determine the charge on the ion. The charge on an ion is equal to the difference between the number of protons and the number of electrons. In this case, we have:

charge = Z - number of electrons

charge = 89 - 87

charge = +2

Therefore, the ion has a charge of +2. The symbol for this ion can be written as follows:

U 2+

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The pH of the solution is equal to the pKa of the acid when the concentrations of the conjugate acid and base are equal.

The Henderson-Hasselbalch equation is given by:

pH = pKa + log([A-]/[HA])

Where:

pH = the pH of the solution

pKa = the acid dissociation constant of the acid

[A-] = the concentration of the conjugate base

[HA] = the concentration of the acid

When the concentrations of the conjugate acid and base are equal, [A-] = [HA], and the Henderson-Hasselbalch equation can be simplified to:

pH = pKa + log(1)

log(1) = 0, so:

pH = pKa

Therefore, when the concentrations of the conjugate acid and base are equal, the pH of the solution is equal to the pKa of the acid. This can be used to determine the acid dissociation constant (Ka) of the acid by measuring the pH of the solution when the concentrations of the conjugate acid and base are equal.

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0.21 moles of S[tex]O_{2[/tex] can be produced by reacting 8 grams of C[tex]S_{2[/tex]

What is Moles?

Mole is a unit of measurement used in chemistry to express the amount of a substance. It is defined as the amount of a substance that contains the same number of entities (such as atoms, molecules, or ions) as there are atoms in 12 grams of carbon-12. This number is known as Avogadro's number

To calculate the number of moles of S[tex]O_{2[/tex] produced, we need to use the balanced chemical equation to determine the mole ratio between C[tex]S_{2[/tex]and S[tex]O_{2[/tex].

The balanced chemical equation is:

C[tex]S_{2[/tex] + 3[tex]O_{2[/tex]→ C[tex]O_{2[/tex] + 2S[tex]O_{2[/tex]

The molar mass of C[tex]S_{2[/tex] is 76.14 g/mol.

First, we need to calculate the number of moles of C[tex]S_{2[/tex] present in 8 grams:

moles of C[tex]S_{2[/tex] = mass / molar mass

moles of C[tex]S_{2[/tex] = 8 g / 76.14 g/mol

moles of C[tex]S_{2[/tex] = 0.105 moles

From the balanced equation, we see that the mole ratio between C[tex]S_{2[/tex]and S[tex]O_{2[/tex] is 1:2. This means that for every 1 mole of C[tex]S_{2[/tex] that reacts, 2 moles of S[tex]O_{2[/tex] are produced.

Therefore, the number of moles of S[tex]O_{2[/tex] produced can be calculated as:

moles of S[tex]O_{2[/tex] = moles of C[tex]S_{2[/tex] × 2

moles of S[tex]O_{2[/tex] = 0.105 moles × 2

moles of S[tex]O_{2[/tex] = 0.21 moles

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Answer:

human error , random error .

Answer:

Explanation:

We can use to convert the given number of atoms of nickel to moles.

1 mole of any element contains 6.022 x 10^23 atoms of the element

So, the number of moles of nickel can be calculated as:

moles of Ni = (number of atoms

moles of Ni = 3.88 x 10^23 / 6.022 x 10^23

moles of Ni = 0.644

Therefore, the answer is option B: 0.644 moles Ni.

Answer: Na2CO3 + 2 HNO3 → 2 NaNO3 + H2O + CO2

Explanation:

The level of acidity or alkalinity of aqueous solutions can be conveniently expressed using the pH scale, also known as the pOH scale.

"The negative of the logarithm of the molar hydronium-ion concentration" is how pH is defined. The pH formula is written as. P H equals l o g [H 3 0 +] You can alternatively write the pH Formula as. l o g [H +] = p H

The pH of a solution is equal to the solution's hydrogen ion concentration divided by its negative logarithm to base 10:

   pH = -log₁₀[H⁺]

     pOH = -log₁₀[OH⁻]

For any aqueous solution, the sum of the pH and pOH is 14. That is;

                    pH + pOH = 14

Now solving for [OH⁻]:

              HNO₃ + H₂O → H₃O⁺ + NO₃⁻

   Since pH + pOH = 14

              pOH = 14 - pH = 14 -3.75 = 10.25

 since pOH = -log₁₀[OH⁻]

             10.25 = -log₁₀(OH⁻)

             [OH⁻] = inverse log₁₀(-pOH)

             [OH⁻] = inverse log₁₀(-10.25) = 5.62 x 10⁻¹¹moldm⁻³

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Answer:

[OH− ] = 5.62

n = -11

pOH = 10.25

Explanation:

I did it not too long ago

The ideal gas law can be used to solve this issue:

PV = nRT

where R is the universal gas constant, n is the number of moles, P is the gas's pressure, V is its volume, and T is its temperature.

The following expression can be used to link the starting and final volumes and moles under the assumption that the gas's pressure and temperature don't change:

V1 / n1 = V2 / n2

where V1 and n1 represent the volume and number of moles at the beginning, and V2 and n2 represent the volume and number of moles at the end.

Inputting the specified values results in:

15 L/n2 = 3 L / 3 mol

When we simplify and account for n2, we obtain:

n2 = 3 mol (15 L / 3 L)

n2 = 15

As a result, 15 mol of the gas are present when the volume is changed to 15 L.

Using the equation V = nV m, where V is the volume in liters, n is the amount of gas in moles, and V m is the molar gas volume in liters per mole, is another technique to determine the solution. We may substitute the volume and molar gas volume from the question into this equation.

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The pH of the buffer after the addition of 0.020 mol of NaOH is 4.83.

Henderson-Hasselbalch equation: pH = pKa + log([A^-]/[HA]),

[CH3COOH] = 0.300 mol/1.00 L = 0.300 M

[CH3COO^-] = 0.300 mol/1.00 L = 0.300 M

CH3COOH + NaOH → CH3COO^- + H2O

[CH3COOH] = (0.300 mol - 0.020 mol)/1.00 L = 0.280 M

CH3COO^-] = (0.300 mol + 0.020 mol)/1.00 L = 0.320 M

pH = pKa + log([CH3COO^-]/[CH3COOH])

pH = 4.74 + log(0.320/0.280)

pH = 4.83

The pH of a solution can be measured using a pH meter or pH paper, which changes color based on the pH of the solution. It is a dimensionless quantity that indicates the concentration of hydrogen ions (H+) in a solution. pH stands for "power of hydrogen" and is defined as the negative logarithm of the hydrogen ion concentration. A pH of 7 is considered neutral, pH values below 7 indicate acidity, and pH values above 7 indicate alkalinity.

pH is an important parameter in many chemical and biological processes, as it can affect the behavior and properties of molecules and ions in solution. Maintaining the correct pH in biological systems is critical for many physiological processes, and pH control is important in many industrial processes as well.

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According to the Heisenberg Uncertainty Principle, we can only know one of two things at once: either the speed (momentum) or the position.

The uncertainty principle can also be explained in terms of a particle's momentum and position. The momentum of a particle is calculated by dividing its mass by its speed.

Heisenberg's Uncertainty Principle states that there is some uncertainty when measuring a particle's variable. a term frequently used to describe the position and momentum of a particle.

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The final molarity of the acetate anion in the solution is 0.06148 M.

The balanced chemical equation for the reaction between lead(II) acetate and ammonium sulfate is:

[tex]Pb(CH_3COO)_2 + (NH_4)_2SO_4 -- > PbSO_4 + 2NH_4CH_3COO[/tex]

So, if we dissolve 1 mole of Pb(CH₃COO)₂, it will produce 2 moles of acetate anion.

Moles of Pb(CH₃COO)₂ = (mass of Pb(CH₃COO)₂) / (molar mass of Pb(CH₃COO)₂)

Assuming the mass of Pb(CH₃COO)₂ is given, let's say it is 5 g, then:

Moles of Pb(CH₃COO)₂ = (5 g) / (Pb(CH₃COO)₂ molar mass)

The molar mass of Pb(CH₃COO)₂ is:

207.2 g/mol (molar mass of Pb) + 2(16.00 g/mol) + 2(12.01 g/mol) = 325.27 g/mol

Substituting the values, we get:

Moles of Pb(CH₃COO)₂ = (5 g) / (325.27 g/mol) = 0.01537 mol

Since 1 mole of Pb(CH3COO)₂ produces 2 moles of acetate anion, the total number of moles of acetate anion in the solution is:

Moles of acetate anion = 2 x 0.01537 mol = 0.03074 mol

We can calculate the final molarity of the acetate anion in the solution:

Molarity of acetate anion = Moles of acetate anion / Volume of solution

Molarity of acetate anion = 0.03074 mol / 0.5 L = 0.06148 M

The final molarity of the acetate anion in the solution is 0.06148 M.

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The reaction between C2H4 (ethylene) and H2O (water) to form CH3CH2OH (ethanol) is a type of hydration reaction. For this reaction to occur, two conditions need to be met:

The presence of a suitable catalyst: The reaction is catalyzed by an acid catalyst, such as phosphoric acid (H3PO4). The acid catalyst helps to break the double bond in C2H4 and promotes the addition of water to form ethanol.

The reaction requires high pressure and temperature to proceed. The typical reaction conditions involve a temperature range of 300-400 °C and a pressure range of 60-70 atm. These conditions are necessary to overcome the high activation energy of the reaction and promote the formation of the desired product, ethanol.

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HBr has a dipole moment of 7.95debye and an interatomic spacing of 1.94 x 10-om.

HBr (a polar covalent molecule) has a dipole moment () of 0.851D (debye) and a percentage ionic character of 12.6%.

The size of the charge multiplied by the distance between the centres of the positive and negative charges yields a dipole moment. The Greek character " is used to represent it. It is measured in Debye units ('D'). 1 D = 3.33564 10-30 C.m, where C signifies Coulomb and m a metre.

It's 1018 statcoulomb-centimeters. Traditionally, the debye moment was defined as the dipole moment produced by two charges of opposing sign but equal magnitude of 1010 statcoulomb.

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The minimum mass of hydrochloric acid that could be left over by the chemical reaction is 18.23 g.

Moles in chemistry is a unit of measurement for the amount of a substance. It is equal to the number of atoms or molecules in a given mass of a substance, and is represented by the symbol ‘mol’. The molar mass of a substance is the mass of one mole of that substance, expressed in grams. It is important for calculating the amount of energy or reactants needed for a reaction. Moles can also be used to measure the concentration of a solution.

The minimum mass of hydrochloric acid that could be left over by this chemical reaction can be calculated using the following equation:

Moles of HCl = Mass HCl / Molar Mass HCl

Moles of NaOH = Mass NaOH / Molar Mass NaOH

Moles of HCl must equal moles of NaOH in the reaction, so:

Moles HCl = Moles NaOH

Mass HCl / Molar Mass HCl = Mass NaOH / Molar Mass NaOH

Rearranging for mass HCl:

Mass HCl = Molar Mass HCl x Mass NaOH / Molar Mass NaOH

Given:

Mass HCl = 28.8 g
Molar Mass HCl = 36.46 g/mol
Mass NaOH = 20.0 g
Molar Mass NaOH = 40.0 g/mol

Substituting values:

Mass HCl = 36.46 g/mol x 20.0 g / 40.0 g/mol

Mass HCl = 18.23 g

Therefore, the minimum mass of hydrochloric acid that could be left over by the chemical reaction is 18.23 g.

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Answer:

Explanation:

The balanced chemical equation for the reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) is:

HCl(aq) + NaOH(s) → NaCl(aq) + H2O(l)

From the balanced equation, we can see that one mole of hydrochloric acid reacts with one mole of sodium hydroxide to produce one mole of sodium chloride and one mole of water.

First, we need to determine which reactant is limiting, i.e., which reactant is completely consumed in the reaction. To do this, we need to compare the number of moles of each reactant, using their respective molar masses:

Molar mass of HCl = 1.008 g/mol (atomic weight of hydrogen) + 35.45 g/mol (atomic weight of chlorine) = 36.46 g/mol

Molar mass of NaOH = 22.99 g/mol (atomic weight of sodium) + 16.00 g/mol (atomic weight of oxygen) + 1.008 g/mol (atomic weight of hydrogen) = 39.99 g/mol

Number of moles of HCl = mass / molar mass = 30.0 g / 36.46 g/mol ≈ 0.823 mol

Number of moles of NaOH = mass / molar mass = 14.3 g / 39.99 g/mol ≈ 0.358 mol

Since the stoichiometric ratio between HCl and NaOH is 1:1, NaOH is the limiting reactant because it has fewer moles than HCl.

Therefore, we can calculate the maximum mass of NaCl that can be produced by the reaction using the number of moles of NaOH:

Number of moles of NaCl produced = number of moles of NaOH used in the reaction = 0.358 mol

Mass of NaCl produced = number of moles of NaCl produced x molar mass of NaCl

Molar mass of NaCl = 22.99 g/mol (atomic weight of sodium) + 35.45 g/mol (atomic weight of chlorine) = 58.44 g/mol

Mass of NaCl produced = 0.358 mol x 58.44 g/mol = 20.9 g

Therefore, the maximum mass of NaCl that can be produced by the reaction is approximately 20.9 g