The potential difference, acting over a distance of 2.5 cm is 1.4*10^-12V.
What are the effects of distance on potential difference?The potential actually grows as you get farther away from the charge, becoming less negative as you get closer to it and eventually reaching zero. The potential for both positive and negative charges is zero at infinite distances from the charge.
Exactly what is potential energy?The energy that a body has because of its location or deformation is known as potential energy. Both the body's bulk and the height to which it is lifted play a role.
Given:
Distance (d) = 2.5cm = 0.025 m
For an electron,
[tex]m= 9.109*10^-31kg[/tex]
[tex]q=1.602*10^-19C[/tex]
We isolate the electric field:
[tex]E=\frac{mg}{q}[/tex]
[tex]g=9.8 m/s^2[/tex]
[tex]E=\frac{(9.109*10^-31kg)(9.8m/s^2)}{1.602*`10^-19C}[/tex]
[tex]E=5.5723*10^-11V/m[/tex]
Electric potential,
[tex]E=\frac{V}{d}[/tex]
[tex]V=Ed[/tex]
[tex]V= (5.5723*10^-11V/m)(0.025m)[/tex]
[tex]V=1.4*10^-12V[/tex]
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The centripetal force on object M as it passes
through the rest position is approximately
Since the particle always moves in a circular motion in a direction perpendicular to the radial direction.
The work done by the centripetal force in a circular motion is therefore always zero since the dot product is always zero. A force known as the centripetal force acts on a particle when it is revolving around a specific axis or point. The circular path's center is where this force is directed. The ideal decision is (d) Therefore, the body's weight will be equal to the centripetal force when the angular acceleration reaches the same level as the acceleration caused by gravity. It should be noted that for the centripetal force to equal the weight, there must be a uniform circular motion.
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A voltage source provides ___________ required for electric current.
Someone help me with these questions
Answer:
Im not 100% sure so don't completly rely on these answer s
#1 is B
#2 ia B
#3 is A
#4 is A
#5 is A
and i think #6 is A
im 100% sure that 3 and 4 are A tho
Explanation:
What is the combined resistance of 5 ohms wire arranged in series with a parallel arrangement of 4 ohms and 6 ohms wires
Answer:
7.4 Ω
Explanation:
Let,
R1 = 5 Ω
R2 = 4 Ω
R3 = 6 Ω
R1 is connected series.
R2 and R3 are connected in parallel.
1 / Rp = 1 / R2 + 1 / R3
= 1 / 4 + 1 / 6
= 3 / 12 + 2 / 12
1 / Rp = 5 / 12
Rp = 12 / 5 = 2.4 Ω
Effective resistance
= R1 + Rp
= 5 + 2.4
= 7.4 Ω
Therefore, the combined resistance of 5 ohms wire arranged in series with a parallel arrangement of 4 ohms and 6 ohms wires is
7.4 Ω.
A 5 kg block is on a frictionless surface. A 15 n force is applied To the the block in a direction parallel to the surface. What is the acceleration of the block?
The acceleration is 3 [tex]m/s^2[/tex] when a block with a mass of 5 kg is pulled with a force of 15 n.
The block will experience a net external force of 15 N due to the frictionless surface it is kept in place on.
The block weighs 5 kg.
F = m × a
There is a net external force (F), mass (m), and acceleration acting on the object in this situation (a).
Using the appropriate values in place of F and m:
15 = 5 × a
15/5 = a
3=a
Taking 5 as a factor, we get 3 = a.
As a result, a 5-kilogram item is drawn over a friction less surface with an acceleration of 15 N is 3 m/s².
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Please help! The image produced by a concave mirror is ? .
Answer:
is a reflection.
The image is real light rays actually focus at the image location). As the object moves towards the mirror the image location moves further away from the mirror and the image size grows (but the image is still inverted). When the object is that the focal point, the image is at infinity.
Explanation:
To report the position of an object, first choose a reference point. Then, describe the of the object with respect to the reference point. Next, measure the from the reference point to the object.
We will understand the given concept through an example
The rat serves as your point of reference if you mentioned that the rabbit was to the left of it. You are expressing its position when you specify the distance and direction. The present separation and direction of an object from a reference point is its position.
When something moves with relation to a reference frame, like when a passenger gets off an airline or a lecturer gets up to leave, the object's position changes.the right in relation to a whiteboard. Displacement describes this shift in location.Every location helps you to achieve various location positions.Your position is defined by how you describe your place. The separation in the first illustration is one meter. The reference point helps to locate each and every point.To know more about reference point here
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A centripetal force of 250 N is exerted on a 2.2 kg discus as it rotates uniformly in a horizontal circle of radius 0.85 m. Calculate the speed of the discus in both m/s and rotations per minute?
Answer:
133m/s
Explanation:
b/c 250÷2.2÷0.85=133
I walked 45 m East then turned to the north and walked 30 m. What was the magnitude of my displacement?
The magnitude displacement vector's magnitude (or length), which is indicated by the arrow's length, measures the separation between the locations.
How can I determine how much movement there is?d = (((x2 - x1)2 + (scaling factor - y1)2)12 represents the displacement's magnitude. The displacement vector's size, or distance d, is its length. The guided line segment connecting P1 and P2 is the displacement vector's (d) direction. We refer to this straight line segment as a geometric or look of the scalar d.
What is a displacement example of what magnitude?When we talk about magnitude, we don't only imply the amount of a displacement; we also imply its orientation just a number with a unit As just an illustration, the professor might repeatedly pace back and forth, possibly
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In the video, Dr. Hewitt lifts a bowling ball on a rope to his teeth, then lets go, the ball swings away and returns. What happens the first time Dr. Hewitt lifts the bowling ball near his teeth and lets go?
answer choices
O The ball returns to Dr. Hewitt, stopping almost exactly at the point where it was released.
O The ball leaves Dr. Hewitt and returns to him, going past the point where it was released.
O The ball leaves Dr. Hewitt and returns to him, stopping short of the point where it was released.
Option 1 is correct choice, The ball returns to Dr. Hewitt, stopping almost exactly at the point where it was released.
Potential energy becomes kinetic energy when a stationary item begins to move. When an item in motion stops moving, its kinetic energy transforms into potential energy.
Here, the energy input from the push is transforming into kinetic energy, which would be later transformed into even more potential energy than the ball had at the beginning of the motion.
The component of swinging is called kinetic energy, and it is the speed at which the ball runs back and forth. The most powerful aspect of swinging is potential energy. The ball achieves more potential energy the higher you go on the swing, so When it comes back to Dr. Hewitt, the ball stops almost exactly where it started.
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Here's the screenshot
A car at rest with respect to a building can be in motion with respect to another observer. True/False. Please explain your answer
What is the magnitude of the passenger's acceleration as she passes through the lowest point in her circular motion
The magnitude of the passenger's acceleration as she passes through the lowest point in her circular motion is the centripetal acceleration.
This is given by the equation a = v^2 / r, where v is the velocity of the passenger and r is the radius of the circle. Therefore, the magnitude of the passenger's acceleration is equal to the square of her velocity divided by the radius of the circle.
For example, if the passenger is travelling at 10 m/s in a circle with a radius of 5 m, then her centripetal acceleration would be 10^2 / 5 = 20 m/s^2.
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If you pushed against the 3000 kg truck with a force of 1000 N for 5 s, how fast would the truck be moving?
Answer:
V = 1.67 m/s
Explanation:
Given the following data;
Force = 1000 N
Mass = 3000 kg
Time = 5 seconds
To find the speed of the truck;
First of all, we would find the acceleration
Force = mass * acceleration
1000 = 3000 * acceleration
Acceleration = 1000/3000
Acceleration = 0.333 m/s²
Using the first equation of motion, we would determine the speed;
V = u + at
Initial velocity is equal to zero because the truck starts from rest.
V = 0 + 0.333*5
V = 1.67 m/s
A person finds it easier to lift an anchor through the water than lift it into the boat through the air. Why?
Answer:
because underwater a force called buoyant force of upthrust applies in the objects in water in the upward direction
What is the reason why a yellow colored object looks white in a dimmed light or low intensity of light?
The reason why a yellow colored object looks white in a dimmed light or low intensity of light the colors wavelength have the colors more farther it means it's getting more dimmed.
The wavelengths of sound waves are similar to the size of objects around you, but the wavelength of light waves are much shorter. As a result, you can hear people talking in a room with an open door even though you can’t see them.
The amount of diffraction or bending of the wave depends on the size of the obstacle the wave encounters. If the size of the obstacle is much larger than the wavelength, very little diffraction occurs. Then there is a shadow behind the object where there are no waves.
As the wavelength increases compared with the size of the obstacle, the amount of diffraction increases. The amount of diffraction is greatest if the wavelength is much larger than the obstacle.
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A wagon wheel is a ring (hoop) of mass 77.1 kg and radius of 0.630 m. If it has 182 J of rotational KE, what is its angular velocity?
Answer:
3.44
Explanation:
Acellus said it was right. :) Just figure out the inertia first and plug it into the Rotational KE equation.
different between simple cell and dry cell
Answer:
Simple cell has liquid chemicals and it is difficult to carry from one place to another. Dry cell has no solution. So, it is easier to carry it from one place to another and there is no risk of spilling acid from the dry cell. So, dry cell is more useful than simple cell in our daily life.
PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST THIS IS A SCIENCE QUESTION
Fusion reactions in the sun change nuclear energy into
mechanical energy
chemical energy
electromagnetic energy
potential energy
Answer:
Electromagnetic energy
What is the position of the particle at time t 0?
The position of the particle is zero because the velocity is zero for the particle. The velocity of the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point.
Velocity is the rate of change of velocity. At any point on a trajectory, the magnitude of the velocity is given by the rate of change of velocity in both magnitude and direction. Velocity of the body that we can consider is the increasing value of the velocity of any object at a constant rate and that of we can calculate. Hence by the primary information that we have we can formerly consider that the velocity which is acting on the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point and the position of the particle is zero because the velocity is zero for the particle.
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light travels 300000 km/s,is it velocity or speed
Answer:
speed
Explanation:
Answer:
Velocity
Explanation:
Velocity is km/s
If researchers failed to take into account the effect of air resistance on the pitch, how would it impact their measurements of the efficiency of energy transfer from the arm to the baseball
The efficiency of energy transfer from the arm to the baseball would be lower than the actual efficiency, as there was a higher initial velocity at release.
In order to answer this question, we must look at the experimental design and assess how air resistance would affect the scientists' computations. The ball's velocity would be reduced as it moved from the mound to home plate, where the velocity was measured, due to air resistance.
Therefore, the measured velocity ought to be lower than the release velocity. As a result of the baseball's predicted energy being lower due to the lowered velocity, the efficiency of the energy transfer from the arm to the ball will also be lower.
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A cannonball is launched horizontally from the top of a 166 m
cliff with an original speed of 35.9 m/s.
Determine the horizontal displacement (in m) of the cannonball.
The horizontal displacement of the cannonball is 65.75 meter.
What is speed?Speed is characterized as the rate at which an object's position changes in any direction. The distance travelled in relation to the time it took to travel that distance is how speed is defined. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
original speed: u= 35.9 m/s.
acceleration due to gravity: g = 9.8 m/s².
Initial height of the cannonball = 166 m.
Hence, the horizontal displacement of the cannonball = u²/2g
= 35.9²/(2×9.8) meter
= 65.75 meter.
so, the displacement of the cannonball is 65.75 meter.
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At t = 0, a wheel rotating about a fixed axis at a constant angular acceleration of -0.40 rad/s2 has an angular velocity of 1.5 rad/s and an angular position of 2.3 rad. what is the angular position of the wheel at t = 2.0 s?
At t = 0, the wheel has an angular position of 2.3 rad and an angular velocity of 1.5 rad/s.
Since the wheel is rotating about a fixed axis at a constant angular acceleration of -0.40 rad/s2, we can use the equation for angular position to calculate the wheel's angular position at t = 2.0 s.
Angular position = initial angular position + (initial angular velocity × time) + (1/2 ×angular acceleration ×time²)
Angular position at t = 2.0 s = 2.3 rad + (1.5 rad/s × 2.0 s) + (1/2 ×-0.40 rad/s2 × (2.0 s)²)
Angular position at t = 2.0 s = 2.3 rad + 3.0 rad + -1.6 rad
Angular position at t = 2.0 s = 3.7 rad
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The upper and lower fixed points of a mercury thermometer corresponds to 9.00mV and 16.50mV on the thermocouple thermometer. The temperature of a warm iron giving a reading of 11.21mV to the nearest whole number is.
To find the temperature of the warm iron, we first need to convert the reading on the thermocouple thermometer to a temperature value. To do this, we will use the formula:
Temperature = (Reading - Lower Fixed Point) / (Upper Fixed Point - Lower Fixed Point) * (Upper Temperature - Lower Temperature) + Lower Temperature
In this case, the lower fixed point is 9.00mV and the upper fixed point is 16.50mV. We also know that the lower temperature is 0°C (the freezing point of water) and the upper temperature is 100°C (the boiling point of water). So, we can plug in these values:
Temperature = (11.21mV - 9.00mV) / (16.50mV - 9.00mV) * (100°C - 0°C) + 0°C
Simplifying, we get:
Temperature = (2.21mV / 7.50mV) * 100°C
And further simplifying, we get:
Temperature = 0.2907 x 100°C
So, the temperature of the warm iron is approximately 29.07°C to the nearest whole number.
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Una luz (con una longitud de onda de 600 nm y velocidad de la luz de c = 3 × 108 m⁄s), que proviene del aire incide en glicerina con un ángulo de 30°. Después de pasar por la glicerina, entra en diamante, después pasa por cuarzo y por último sale de nuevo al aire. Calcule el ángulo de refracción al pasar el rayo en cada medio, también calcule la velocidad de la luz en cada medio y la longitud de onda en cada medio
Answer:
a) angles 19.8º, 11.9º, 13.8, 20.4
b) speed 3 10⁸ m/s, 2,037 10⁸ m/s, v = 1.24 10⁸ m/s, v = 2.06 10⁸ m/s
c) wavelength 600 nm, 407.3 nm, 248.0 nm, 411.5 nm
Explanation:
For this exercise let's use the law of refraction
n₁ sin θ₁ = n₂ sin θ₂
where subscript 1 is for the middle of the incident ray and subscript 2 for the middle of the refracted ray
the refractive index is related to the speed of the lightning in the middle
n = c / v
When the ray enters a material medium, it is absorbed and re-emitted by the atoms in the medium, the frequency remains constant, it is a resonant system, but as the speed of light changes in the medium, the wavelength must change to keep the equation
in the void
c = λ f
in the material medium
v = λ f
[tex]\frac{c}{\lambda_o} = \frac{c}{\lambda_n}[/tex]
λₙ = [tex]\frac{v}{c} \ \lambda_o[/tex]
λₙ = λ₀ / n
we used these expressions to our case
1) medium incident air n₁ = 1 medium transmitted n₂ = 1.473
sin θ₂= [tex]\frac{n_1}{n_2}[/tex] sin θ₁
sin θ₂ = 1/1,473 sin 30
θ₂ = sin⁻¹ 0.3394
θ₂ = 19.8º
2) medium incident glycerin θ₁ = 19.8, medium transmitted diamond θ₂=2.419
sin θ₂ = 1.473/2.419 sin 19.8
θ₂ = sin⁻¹ 0.2067
θ₂ = 11.9º
3) half incident diamond θ₁ = 11.9º, half transmitted quartz n₂ = 1.458
sin θ₂= 2.419/1.458 sin 11.9
θ₂ = sin⁻¹ 0.3429
θ₂ = 13.8º
4) half incident quartz θ₁ = 13.8, medium transmitted air n₂ = 1
sin θ₂ = 1.458/1 sin 13.8
θ₂ = sin⁻¹ 0.3467
θ₂ = 20,4º
b) we look for the speed of lightning in each medium
air v = c = 3 10⁸ m / s
glycerin v = c / n
v = 3 108 / 1,473
v = 2,037 10⁸ m / s
diamond v = 3 108 / 2.419
v = 1.24 10⁸ m / s
quartz v = 3 108 / 1.458
v = 2.06 10⁸ m / s
c) the wavelength in each medium
air λₙ = λ₀/ n
λₙ = 600/1
λₙ 600 nm
glycerin
λₙ = 600 / 1,473
λₙ = 407.3 nm
Diamond
λₙ = 600 / 2.419
λₙ = 248.0 nm
quartz
λₙ = 600 / 1.458
λₙ = 411.5 nm
Which of the following would be potential impacts of global climate change on thermohaline circulation in the oceans?
A: slowing the rate of circulation
B: no effect of circulation
C: changing the direction of circulation
D: increasing the rate of circulation
The potential impacts of global climate change on thermohaline circulation in the oceans is increasing the rate of circulation. That is option D.
What is thermohaline circulation?The thermohaline circulation is defined as the process by which deep-ocean currents are driven by differences in the water's density, which is controlled by temperature (thermo) and salinity (haline).
When there is global climate change increased temperature of water masses would cause these currents to flow faster given the higher kinetic energy of the water molecules.
Therefore, there is increase in rate of circulation when there is global climate change.
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A car moving with an initial speed v collides with a stationary car that is one- half as massive. After the collision, the first car moves moves in the same direction as before with the speed v/3. a) Find the final speed of the second car b) What type of collision is it (elastic or inelastic)
The final speed of the second car is '2v' and the collision is elastic collision.
What exactly are elastic collisions?The elastic collision is one in which the system does not experience a net loss of kinetic energy as the result of a collision. In elastic collisions, momentum & kinetic energy are both conserved.
v′ = m1v1 + m2v2 /m1+m2
v ′ = m 1 v 1 + m 2 v 2/ m 1 + m 2
in which m1 is mass of body 1, v1 is its initial speed, m2 is mass of body 2, & v2 is the final speed at which the two objects will be moving after colliding.
m1v +0 = mv/3 +m/3v2
v2 = 2v
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The person in the figure below is pulling a heavy load. However, the load is resisting the forward motion. The figure can act as a model for what happens in electrical conductors, cells and batteries, and electrical devices in a circuit.
1. Write a paragraph that explains what you think each circuit component would represent in the model, and why.
2. How does the figure model resistance in a circuit?
The components of an electrical circuit represented by the model are as follows:
the man pulling the load represents the battery or cellthe cord used by the man to pull the load represents the conductors such as wiresthe load pulled by the man represents the resistance.The figure models resistance in a circuit because just as resistance in a circuit opposes the flow of current, the load resists the movement of the man.
What is an electrical circuit?An electrical circuit is a complete path that is provided for the flow of electric current.
Tue components of an electric circuit includes:
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A ramp is 12 meters long and I need to use it to raise up a box 4 meters. The box weighs 200 newtons. How much force are you going to need to exert to get the box up the ramp
The force required to raise the box up the ramp when the ramp is 12 meters long, the box is 4 meters and the box weighs 200 newtons is 653.33 N (7840/12)
How do you determine the force required to raise the box up the ramp?To determine the force required to raise the box up the ramp, we can use the work-energy principle.
Work = Change in PE
W = PEf - PEi
where
W = work done (Joules)
PEf = final gravitational potential energy (Joules)
PEi = initial gravitational potential energy (Joules)
The gravitational potential energy of an object is given by the formula:
PE = mgh
where
m = mass of the object (200 N)
g = acceleration due to gravity (9.8 m/s^2)
h = height (4 meters)
We can find the change in potential energy as follows:
PEf = mgh = 200 x 9.8 x 4 = 7840 J
PEi = mgh = 200 x 9.8 x 0 = 0 J
So, the change in potential energy is 7840 J.
Now we can calculate the work done as:
W = PEf - PEi = 7840 - 0 = 7840 J
The work done is equal to the force exerted on the object multiplied by the distance it is moved:
W = F x d
7840 = F x 12
So, the force required to raise the box up the ramp is 653.33 N (7840/12)
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