The total volume of ozone that can be destroyed when all of the chlorine from 17.0 g of CF3Cl goes through 10 cycles of these reactions, measured at a pressure of 22.0 mmHg and a temperature of 230 K, is calculated using the Ideal Gas Law equation (PV=nRT) and stoichiometry.
First, we need to find the moles of CF3Cl and the moles of ozone it can destroy.
Molar mass of CF3Cl = (12.01) + 3(19.00) + 35.45 = 137.46 g/mol
Moles of CF3Cl = 17.0 g / 137.46 g/mol ≈ 0.1236 mol
Since one chlorine atom can destroy one ozone molecule in each cycle, 10 cycles can destroy 10 times the amount:
Moles of ozone destroyed = 0.1236 mol * 10 = 1.236 mol
Now, we can use the Ideal Gas Law equation to find the volume:
V = nRT/P
Where:
V = volume of ozone (in liters)
n = moles of ozone (1.236 mol)
R = ideal gas constant (0.0821 L atm / mol K)
T = temperature (230 K)
P = pressure (converted to atm: 22.0 mmHg * (1 atm / 760 mmHg) ≈ 0.02895 atm)
V = (1.236 mol) * (0.0821 L atm / mol K) * (230 K) / 0.02895 atm ≈ 778.32 L
So, the total volume of ozone that can be destroyed under the given conditions is approximately 778.32 liters.
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what are some enthalpy changes involved in ionic crystal formation?
Explanation:
In the formation of an ionic crystal, several enthalpy changes are involved. These include:
Lattice energy: The energy released when gaseous ions come together to form a solid ionic compound.
Ionization energy: The energy required to remove an electron from an atom or ion in the gas phase.
Electron affinity: The energy released when an electron is added to an atom or ion in the gas phase.
Hydration energy: The energy released when an ion is surrounded by water molecules in solution.
Heat of solution: The energy absorbed or released when a solute dissolves in a solvent.
Overall, the formation of an ionic crystal involves a complex interplay of these different enthalpy changes. The strength of the forces holding the ions together in the crystal lattice depends on the balance between these different energy contributions.
Convert a anthracite coal price of$90/ton to$/MMBtu. Heat content of anthracite coal is 15,000 Btu/pound.$15.52/MMBtu\$3/MMBtu \$90.00/MMBtu 3.86/MMBtu
The coal cost of $90/ton with an intensity content of 7000 BTU for every pound is D: $6.42/MMBtu.
The recipe to compute MMBtu from tons is as per the following -
Cost per mmbtu = cost per ton × 500/BTU per pound
Keep the qualities in the equation to find the cost per MMBtu
Cost per mmbtu = (90×500)/7000
Performing augmentation in the numerator on Right Hand Side of the situation
Cost per mmbtu = 45000/7000
Performing division on Right Hand Side of the situation to find the cost per MMBtu for coal
Cost per mmbtu = $6.42/mmbtu
Accordingly, the right choice is D: $6.42/MMBtu.
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Describe the method of separateing salt and water from their solutions
Answer:
Water and salt can be separated through the process of distillation or evaporation. The water is boiled till it evaporates into vapor and leaves salt behind as a solid. The boiling point of water is lower compared to the boiling point of salt.
Explanation:
The method of separating salt and water from their solutions is called evaporation or condensation
Here are the steps:
1. Pour the saltwater solution into a heat-resistant container, such as a glass or metal beaker.
2. Place the container on a heat source, such as a hot plate or stove.
3. Heat the solution until the water begins to evaporate. The salt will remain in the container as the water turns into steam.
4. Once all the water has evaporated, turn off the heat source and allow the container to cool.
5. As the steam cools, it will condense back into liquid form, leaving the salt behind.
6. Carefully remove the salt from the container using a utensil, such as a spatula or a spoon.
7. Discard the remaining water, or save it for other uses.
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consider combustion of coal in pure oxygen (oxycombustion) and in air. the percent theoretical oxidizer in each case is 100%. which case will have a higher adiabatic flame temperature?
The adiabatic flame temperature is the temperature of the flame when no heat is lost to the surroundings during combustion. In pure oxygen (oxycombustion), the combustion process involves the reaction of coal with pure oxygen.
This process provides a higher concentration of oxygen, leading to higher combustion temperatures compared to combustion in air. In contrast, air contains only 21% oxygen, and the combustion process is less efficient due to the presence of nitrogen, which acts as a heat sink.
Therefore, combustion in pure oxygen will have a higher adiabatic flame temperature than combustion in air. This higher temperature can be advantageous in certain industrial processes that require high temperatures, such as steel production, glass manufacturing, and chemical synthesis. However, pure oxygen is expensive to produce, so the cost of oxycombustion may be higher than combustion in air.
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select all of the compounds from the following list that are strong acids in aqueous solution. a. HF b. H2SO4 c. HBr d. H2CO3.
The compounds HF, [tex]H_2SO_4[/tex], and HBr are strong acids in aqueous solution.
Strong acids are molecules that can easily donate protons to water molecules in aqueous solution. This dissociation of protons from the acid molecules creates a solution that is highly acidic, often with a pH of less than 7.Hydrofluoric acid (HF), sulfuric acid ([tex]H_2SO_4[/tex]), and hydrobromic acid (HBr) are all strong acids in aqueous solution. This is because the conjugate bases of these acids are generally much less stable than the acids themselves, which makes them more likely to dissociate and donate protons in water.The higher the difference in stability, the more likely it is that the acid will dissociate in water and the stronger the acid will be.
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3 screenshots! Please help
1. The volume of the 12.0 g of methane, CH₄ is 16.8 L
2. The new celsius temperature of the gas is -153.8 °C
3i. The partial pressure for CO₂ is 0.575 atm
3ii. The partial pressure for O₂ is 0.2875 atm
3iii. The partial pressure for water is 0.2875 atm
1. How do i determine the volume of the gas?First, we shall obtain the mole of the gas. This shown below:
Mass of methane, CH₄ (m) = 12 gramsMolar mass of methane, CH₄ (M) = 16 g/molMole of methane, CH₄ =?Mole = mass / molar mass
Mole of methane, CH₄ = 12 / 16
Mole of methane, CH₄ = 0.75 mole
Finally, we shall determine the volume of the methane, CH₄
Mole of methane, CH₄ = 0.75 moleVolume of methane, CH₄ =?From ideal gas equation,
1 mole of methane, CH₄ = 22.4 L
Therefore,
0.75 mole of methane, CH₄ = 0.75 × 22.4
0.75 mole of methane, CH₄ = 16.8 L
Thus, the volume of methane, CH₄ is 16.8 L
2. How do i determine the new temperature?The new temperature of the gas can be obtained as follow:
Initial temperature (T₁) = 25 °C = 25 + 273 = 298 KInitial volume (V₁) = 10 LNew volume (V₂) = 4 LNew temperature (T₂) =?Charles' law equation is given as follow:
V₁ / T₁ = V₂ / T₂
Inputting the variables, we have
10 / 298 = 4 / T₂
Cross multiply
10 × T₂ = 298 × 4
Divide both side by 10
T₂ = (298 × 4) / 10
T₂ = 119.2 K
Subtract 273 to obtain answer in °C
T₂ = 119.2 - 273 K
T₂ = -153.8 °C
Thus, the new temperature is -153.8 °C
3. How do i determine the partial pressure?i. Partial pressure for CO₂ can be obtained as follow:
Percentage of CO₂ = 50%Total percentage = 100%Total pressure = 1.15 atmPartial pressure of CO₂ =?Partial pressure of CO₂ = (percentage of CO₂ / total percent) × total pressure
Partial pressure of CO₂ = (50 / 100) × 1.15
Partial pressure of CO₂ = 0.575 atm
ii. Partial pressure for O₂ can be obtained as follow:
Percentage of O₂ = 25%Total percentage = 100%Total pressure = 1.15 atmPartial pressure of O₂ =?Partial pressure of O₂ = (percentage of O₂ / total percent) × total pressure
Partial pressure of CO₂ = (25 / 100) × 1.15
Partial pressure of O₂ = 0.2875 atm
iii. Partial pressure for water can be obtained as follow:
Partial pressure of CO₂ = 0.575 atmPartial pressure of O₂ = 0.2875 atmTotal pressure = 1.15 atmPartial pressure of water =?Total pressure = Partial pressure of CO₂ + partial pressure of O₂ + partial pressure of water
1.15 = 0.575 + 0.2875 + partial pressure of water
1.15 = 0.8625 + partial pressure of water
Collect like terms
Partial pressure of water = 1.15 - 0.8625
Partial pressure of water = 0.2875 atm
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A grease fire started on the stove, it was then covered completely with a fire blanket so that the fire goes out. Identify the limiting reactant in this situation.
A.the grease
B.the blanket
C.the fire
D.oxygen
Oxygen, abbreviated O2, is the limiting reactant in this scenario. Limiting Reactor: The fire equation is O2 + Fuel = CO2 + H2O
How fire is exhausted?When a pile of leaves is set on fire and the fire is covered with a fire blanket to put it out, the blanket restricts the amount of oxygen the fire can access, which lowers the amount of oxygen present and lowers the amount of CO2 and H2O that can be created.
How can limiting reagents be discovered?By dividing the volume of each solution by its molarity, you can get the number of moles of each reactant. By dividing the number of moles of each reactant by its stoichiometric coefficient in the balanced chemical equation, you may determine which reactant is the limiting one.
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determine the empirical formula and/or molecular formula of a compound from percent composition or mass data
The empirical formula of the compound is: CH4.
To determine the empirical formula and/or molecular formula of a compound from percent composition or mass data, follow the steps below:
Empirical Formula:
Step 1: Calculate the mass of each element present in the compound.Step 2: Divide the mass of each element by its atomic weight.Step 3: Calculate the mole ratio by dividing each element's mole value by the smallest mole value.Step 4: Write the empirical formula by multiplying each subscript by the smallest integer that will produce whole numbers.Molecular Formula:
Step 1: Calculate the empirical formula mass by adding the atomic masses of all atoms in the empirical formula.Step 2: Calculate the mass of the empirical formula and divide the molecular mass of the compound by the empirical formula mass.Step 3: Multiply each subscript of the empirical formula by the result of step 2 to get the molecular formula.Example: What is the empirical formula of a compound that contains 14.3 g of carbon and 4.8 g of hydrogen?
Step 1: Calculate the mass of each element present in the compound. C = 14.3 gH = 4.8 gStep 2: Divide the mass of each element by its atomic weight. C = 14.3 g / 12.01 g/mol = 1.19 molTo know more about "Empirical formula" & "Molecular formula" refer here:
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Silver Acetate is a sparingly soluble salt with Ksp= 1.9*10^-3. Consider a saturated solution in equilibrium with the solid salt. Compare the effects on the solubility of adding the acid HNO3 or the base NH3.
Answer: When HNO3 is added to a saturated solution of silver acetate, it will react with the acetate anions to form nitric acid and acetic acid. This will shift the equilibrium of the solubility reaction to the right, according to Le Chatelier's principle, resulting in an increase in the solubility of silver acetate.
AgC2H3O2(s) ⇌ Ag+(aq) + C2H3O2-(aq)
Adding NH3 to the saturated solution of silver acetate will react with the silver ions to form the complex ion Ag(NH3)2+. This will remove the silver ions from the solution, thus decreasing the concentration of Ag+ in the solution. According to Le Chatelier's principle, the equilibrium of the solubility reaction will shift to the left to compensate for the decrease in Ag+, resulting in a decrease in the solubility of silver acetate.
Ag+(aq) + 2NH3(aq) ⇌ Ag(NH3)2+(aq)
Therefore, the addition of HNO3 will increase the solubility of silver acetate, while the addition of NH3 will decrease the solubility of silver acetate.
Explanation:
Under forward biasing, what processes occur in the quasi-neutral regions adjacent to the depletion region edges?
1.Drift and diffusion
2.Diffusion and recombination
3.Generation and diffusion
4.generation and drift
Under forward biasing, the processes that occur in the quasi-neutral regions adjacent to the depletion region edges are drift and diffusion.
What is forward biasing?
Forward biasing is the method of turning on a diode by providing a voltage that enables current to flow through the diode.
Quasi-neutral region
Quasi-neutral regions are the areas of a p-n junction diode where there is a substantial concentration of charge carriers on either side of the junction.
The density of charge carriers varies gradually in this area. As a result, the electrons and holes are mutually neutralized, and the region becomes electrically neutral.
In a p-n junction diode, there are two types of regions: the p-type region, which is dominated by holes, and the n-type region, which is dominated by electrons.
When the diode is forward-biased, the negative terminal is connected to the N-region, and the positive terminal is connected to the P-region.
This causes an electric field to develop that pushes the electrons toward the P-region and the holes toward the N-region.
When the applied voltage causes the minority carriers to be pushed across the junction into the opposite region, the carriers cross the depletion area, which is the space-charge region. In a diode, the area on either side of the junction, which is free of any charge carriers, is known as the depletion area or region.
The quasi-neutral regions adjacent to the depletion region edges experience drift and diffusion under forward biasing.
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when 14.5g of SO2 reacts with 21g of O2 ,what will be the theoretical yeild of the reaction of the actual is 12g
ans:We have to find theoretical yield and percentage yield of the reaction.
Solution : 14.5 g of SO2 reaches with 21 g of O2. and actual yield is 12g.
first we see chemical reaction is SO2 and O2,
2SO2 + O2 ⇒2SO3
we see, 2 moles of SO2 react with 1 mole of O2.
molecular weight of SO2 = 32 + 2 × 16 = 64 g
molecular weight of O2 = 32g
∴ 2 × 64 = 128g of SO2 reacts with 32g of O2.
∴ 14.5g of SO2 reacts with 32/128 × 14.5 = 3.625 g but given O2 is 21g
so, SO2 is limiting reagent.
hence, reaction prefers SO2 to produce SO3
2 moles of SO2 give 2 moles of SO3
∴ 128g of SO2 gives 2 × (32 + 3 × 16) = 160g of SO3
⇒14.5 g of SO2 gives 160/128 × 14.5 g = 18.125 g
so theoretical yield = 18.125 g
but actual yield = 12g
so, percentage yield = actual yield/theoretical yield × 100
= 12/18.125 × 100
= 66.207 %
when running the ldh assay using the lactate stock solution, what is the lactate concentration in the cuvette? why do you need to know this value? (hint: this is an important question!)
Lactate concentration in the cuvette for LDH assay can not be determined as this value would need to be specified in the experimental setup. The value should be known to assess lactate dehydrogenase activity.
The lactate concentration in the cuvette can be calculated using the Beer-Lambert law, which relates the absorbance of a sample to its concentration. The equation is A = εlc, where A is the absorbance, ε is the molar absorptivity coefficient, l is the path length of the cuvette (usually 1 cm), and c is the concentration in moles per liter.
Knowing the lactate concentration in the cuvette is important because it allows us to determine the activity of lactate dehydrogenase (LDH), the enzyme being assayed. LDH catalyzes the conversion of lactate to pyruvate, and the rate of this reaction depends on the concentration of lactate. By measuring the change in absorbance over time, we can calculate the initial rate of the reaction and use this information to determine the activity of LDH.
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The temperature of a given volume of water changes as heat is added at a consistent pace, as shown by the water heating curve. The temperature of the water does not vary throughout a phase shift, creating a plateau on the graph.
What does chemistry's heating process entail?When a substance is heated to a material-specific phase-change temperature, the phase transition from solid to liquid occurs immediately.
How does one heat water using a formula?Water has a specific heat capacity of 4.18 J/g/°C. The amount of heat, or Q, is what we want to know. To do this, we would apply the formula Q = m•C•T. Knowing the m and C allows for the calculation of the T.
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Who thought that, if left unchecked, a population would outgrow its food source?
Reverend Thomas Robert Malthus initially put forth the Malthusian hypothesis of population growth in 1798, which predicts that an unrestrained population would surpass its food supply.
What is stated by the Malthusian theory of population growth?According to the hypothesis, sickness, starvation, war, and other calamities will eventually ensue when the food supply cannot keep up with the increase in the human population. Malthus established the Statistical Society of London and was a well-known statistician and political economist.
Does the Malthusian theory contend that there will be an imbalance between population and food production?Thomas Robert Malthus famously prophesied in 1798 that if human population expansion outpaced food production, short-term advances in living standards would inevitably be undermined and pull living standards back towards subsistence.
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when calculating the ph of very dilute solutions, simply taking the negative log of the concentration of substance put into solution is likely to give incorrect results if the concentration is less than what?
To calculate the pH of very dilute solutions, simply taking the negative log of the concentration of substance put into solution is likely to give incorrect results if the concentration is less than [tex]10^-^7M[/tex].
The calculation of pH of very dilute solutions is likely to give incorrect results because when we take the negative logarithm of the hydrogen ion concentration in a solution, we should have a minimum of [tex]10^-^7M[/tex] hydrogen ion concentration to calculate the pH with. This is because pure water dissociates into [tex]10^-^7M[/tex] hydrogen and hydroxide ions.
For any solution with a pH of 7 or greater, the hydrogen ion concentration is lower than [tex]10^-^7M[/tex] . If we try to calculate the pH of a very dilute solution with hydrogen ion concentration less than [tex]10^-^7M[/tex], then the pH value will be outside the range of 0 to 14, which is not possible.
Hence, this will give incorrect results. Therefore, it is necessary to use alternative methods such as diluting the solution with a solvent or using indicators.
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From your knowledge of the dehydration of tertiary alcohols, which olefin should predominate in the product of the dehydration of 2-methyl-2-butanol, and why?
2-methyl-2-butene
Explanation:
From my knowledge of the dehydration of tertiary alcohols, the olefin that should predominate in the product of the dehydration of 2-methyl-2-butanol is 2-methyl-2-butene. This is because of the following reasons:
1. Dehydration of alcohols is an elimination reaction that follows the E1 mechanism.
2. In the E1 mechanism, the reaction rate depends on the stability of the carbocation formed.
3. Tertiary carbocations are more stable than secondary or primary carbocations due to hyperconjugation and inductive effects.
4. In the dehydration of 2-methyl-2-butanol, a tertiary carbocation is formed as an intermediate.
5. The carbocation can lose a proton to form an alkene.
6. Since the tertiary carbocation is more stable, it will form the more substituted alkene, which is 2-methyl-2-butene, due to Zaitsev's rule.
7. Zaitsev's rule states that the major product in an elimination reaction is the more substituted alkene, resulting from the removal of the least substituted proton.
So, 2-methyl-2-butene should predominate in the product of the dehydration of 2-methyl-2-butanol due to the stability of the tertiary carbocation and Zaitsev's rule.
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How do the unique characteristics of water determine its interactions with chemical and biological systems? How is water unique in chemical and biological systems?
A vital component of both chemical and biological processes, water is a wonderful substance. Its special characteristics result from the organisation of its molecules and the interactions they have with one another and with other molecules.
Water's ability to generate hydrogen bonds is one of its most significant characteristics. The negative oxygen atom of one water molecule interacts electrostatically with the positive hydrogen atom of another, forming hydrogen bonds. Water has a high surface tension as a result of these connections, which also enable it to form droplets and adhere to surfaces. For the structure and stability of biomolecules like proteins and nucleic acids in biological systems, hydrogen bonding are essential.The solvent water is likewise quite good. Many different polar and ionic chemicals can be dissolved by it because of its polar nature. The cytoplasm of cells and other biological fluids like blood contain it since it is a necessary component.
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C3H8 + 4 O2 ➞ 3 CO2 + 5 H2O
How many moles of CO2 are produced from the combustion of 6.40 mol C3H8 ?
Answer: 19.2 mols
Explanation:
3*6.40 mol so 19.2 mols are produced. This is because the ratio of C3H8 to CO2 is 1 to 3 so there are three times as many moles of CO2 as C3H8.
Can someone please answer these I need help
Answer:
(1) 80.64 Liters
(2) [tex]6.29 \times 10^{-4} Liters[/tex]
(3) 2.61 grams
(4) 0.714 g/L
(5) 0.19624 kilograms
Explanation:
It's known that:
one mole of any gas at STP (1 atm, 273K ) = 22.4 Liter
number of moles of any gas at STP = [tex]\frac{V}{22.4} = \frac{Particles}{N_A}[/tex] , Where V is Volume, NA is Avogadro's number, Particles: number of Particles
Volume of gas at STP = Moles × 22.4L
density = [tex]\frac{Molar-Mass}{Volume}[/tex]
(1)
Given That:
3.6 moles of CO2
Then:
Volume = 3.6 × 22.4 = 80.64 Liters
(2)
Moles of O2= [tex]\frac{1.69 \times 10^{19}}{6.022 \times 10^{23}} = 2.81 \times 10^{-5} moles[/tex]
Volume of O2= 22.4 × 2.81 × 10^-5 = [tex]6.29 \times 10^{-4} Liters[/tex]
(3)
Number of moles of He = [tex]\frac{14.6}{22.4} = 0.65 moles[/tex]
mass of He (molar mass = 4 g/mol) = 0.65 × 4 = 2.61 grams
(4)
The molar mass of CH4 = 12 + 4 = 16 g/mol
assuming that we have, at STP, one mole of Methane "CH4"
So, the volume = 22.4 L
Hence, The density = [tex]\frac{16}{22.4} = 0.714 g/L[/tex]
(5)
Number of moles of [tex]C_3H_8[/tex] = [tex]\frac{100}{22.4} = 4.46 moles[/tex]
molar mass of [tex]C_3H_8[/tex] = 3(12) + 8 = 44 g/mol
mass of [tex]C_3H_8[/tex] = 44 × 4.46 = 196.24 grams = 0.19624 kilograms
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Does the haloform test proceed more rapidly as more of the protons are substituted
The haloform test does not proceed more quickly as more of the protons are replaced.
This is because the haloform test is not influenced by the presence of protons. The haloform reaction is a well-known test for carbonyl compounds that react with hypochlorite (NaClO) in the presence of a base (OH) to produce haloforms. The haloform reaction is a typical aldehydic and ketonic carbonyl group reaction that yields a haloform (e.g., CHX3, where X is halogen) and a carboxylate. The haloform reaction proceeds with a carbonyl group as the starting material. The alpha hydrogen on the carbonyl group is removed by base and oxidized by hypochlorite to form the haloform.
When the reaction occurs, three alpha hydrogen atoms are replaced by halogen atoms, resulting in the formation of haloform. The presence of protons in a molecule does not speed up the reaction rate of the haloform reaction. The haloform test reaction rate is influenced by the concentration of NaOH (a base) and hypochlorite (NaClO). As a result, the haloform test does not proceed more quickly as more protons are replaced.
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how much heat does it take to increase the temperature of 2.90 moles of a diatomic ideal gas by an amount 25.0 k if the gas is held at constant volume? the gas molecules can translate and rotate but not vibrate. express your answer using three significant figures.
The heat does it take to increase the temperature of 2.90 moles of a diatomic gas by an amount 25.0 K if the gas is held at the constant volume is 1506.9 J.
The number of moles of the gas = 2.90 moles
The change in the temperature of the gas ΔT = 25 K
For the constant volume process , the expression is as :
Q = n CΔT
For the diatomic ideal gas , the specific heat capacity at the constant volume is : C = 5/2 R
Q = 2.90 × 5/2 × 8.314 × 25
Q = 1506.9 J
Thus, the heat need it take to increase the temperature is 1506.9 J.
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An element, M, has the electron distribution 2 + 8 + 18+ 3.
(a) Which group in the Periodic Table is element M likely to be in?
Electrons distribution in shells:
First shell - 2 electrons
Second shell - 8 electrons
Third shell - 18 electrons
Fourth (valence shell) - 3 electrons
Explanation:
The group number of an element can be found by finding its number of valence shell electrons.
According to the electrons distribution in shells, the valence shell has 3 electrons
Hence element M will be in the third group of the periodic table
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lime is used in farming to reduce the acidity of the soil. the chemical name for lime is calcium oxide. when water in the soil reacts with lime, what base is formed?
The chemical reaction of lime (calcium oxide) with water in the soil produces calcium hydroxide, a base. This reaction occurs when water molecules interact with the calcium oxide molecules, forming calcium hydroxide. The equation for this reaction is CaO + H₂O → Ca(OH)₂
Calcium oxide is produced by heating limestone to a high temperature. When calcium oxide is mixed with water, calcium hydroxide is produced. It is also called slaked lime.
Calcium hydroxide, a base, helps to reduce the acidity of the soil. It can do this because it has a pH greater than 7. The reaction between lime and water helps to neutralize the soil pH by releasing hydroxide ions which bond with hydrogen ions in the soil, causing the acidity to decrease. This is especially beneficial for plants, as acidic soil can stunt their growth.
Calcium hydroxide is used in a variety of applications, including the production of cement.
Overall, when water reacts with lime (calcium oxide) in the soil, calcium hydroxide is formed. This base helps to reduce the acidity of the soil, making it more suitable for plant growth.
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if you were asked to dissolve a solid into an aqueous solution, how could you speed this process up? how could you slow it down? listed below are a number of possible ways to alter the rate of this process. place them in the proper category. if you need help, think about putting sugar in your tea. items: add the solute in large chunks. add the solute slowly. increase the atmospheric pressure. stir or agitate the solution.
The answer is it will take longer to dissolve the solute in the solution. Add the solute slowly. Stir or agitate the solution. Increase the atmospheric pressure. Add the solute in large chunks. If a solute is added slowly, it will take longer to dissolve in the solution.
Stirring or agitating the solution will improve the rate at which the solute dissolves in the solution because it helps to break up the solute particles into smaller pieces, which increases the solute's contact with the solvent. Increasing the atmospheric pressure has the potential to improve the rate of dissolving a solid in a solution. The atmospheric pressure is the weight of the air over the surface of the solution. The higher the pressure, the more gas molecules are present in the atmosphere, and the more they will be compressed against the surface of the solution. The rate of dissolving of a solid in a solution can be slowed down by adding the solute in large chunks. As a result, it will take longer to dissolve the solute in the solution.
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the buoyant force acting on the Lucia before the torpedo attack
The buoyant force acting on the Lucia before the torpedo attack was the upward force on the submarine due to the water it displaces when submerged.
This force is determined by the submarine's volume and the density of the water it is submerged in. This force essentially counteracts the downward force of gravity, allowing the Lucia to remain at a constant depth underwater.The buoyant force acting on the Lucia before the torpedo attack was the force of the water pushing up on the hull of the ship, which counteracted the force of gravity pulling it down. This buoyancy kept the ship afloat, allowing it to remain afloat even when it was loaded with cargo and crew.
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complete question:Describe the buoyant force acting on the Lucia before the torpedo attack.
when carbonyl compounds are reduced with a reagent such as lialh4 or nabh4 and a new stereogenic center is formed, what will the composition of the product mixture be?
When carbonyl compounds are reduced with a reagent such as LiAlH₄ or NaBH₄ and new stereogenic center is formed, chemical change will lead to form products that form a racemic mixture of two enantiomers with alcohol as its composition.
A Chemical change is defined as a change which occurs when a substance combines with another substance to form a new substance as product. Also, when a substance decomposes to give new substances it is also considered as a chemical change.
The reduction of an unsymmetrical ketone with the reducing agents LiAlH4 or NaBH4 gives a pair of stereoisomers. This is because the hydride ion can attack from either face of a planar carbonyl group. And , If no other chiral center is present, then the product is a racemic mixture of two enantiomers. The carbonyl group is converted to alcohol in the end product of such reactions.
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What is the pure substance that cannot be broken down into simpler substances?
A pure substance that cannot be broken down into simpler substances is water.
A pure substance is a substance made up of one type of atom or molecule that cannot be broken down into simpler substances. This means that the substance has a fixed chemical composition that does not vary from sample to sample. Examples of pure substances include water, carbon dioxide, and salt.
The pure substance that cannot be broken down into simpler substances is called an element. An element is a substance that is made up of only one type of atom. Examples of elements include hydrogen, oxygen, and iron. Each element has a unique set of chemical and physical properties that distinguish it from other elements.
Elements are organized into the periodic table based on their atomic structure and properties. Elements can combine to form compounds, which are made up of two or more different elements chemically bonded together. Compounds can be broken down into their constituent elements by chemical means, but elements cannot be broken down into simpler substances.
Therefore, elements are considered pure substances that cannot be broken down any further.
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Question 25b please.
Will give branliest!!!
25 (b) 106 g of Na2CO3 is needed to produce 22.4 dm³ of CO2 at STP in this reaction.
What is meant by molar volume?Volume occupied by one mole of a substance at a given temperature and pressure is known as molar volume.
Balanced equation shows that 1 mole of Na2CO3 produces 1 mole of CO2. Therefore, the number of moles of CO2 produced in 22.4 dm^3 of gas at STP is:
n = V/VM = 22.4/22.4 = 1 mol
So we need 1 mole of Na2CO3 to produce this amount of CO2.
Molar mass of Na2CO3 is:
2Na + C + 3O = (2x23) + 12 + (3x16) = 106 g/mol
Therefore, mass of Na2CO3 needed is:
As mass = n x molar mass = 1 mol x 106 g/mol = 106 g
So, 106 g of Na2CO3 is needed to produce 22.4 dm³ of CO2 at STP in this reaction.
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What purpose does the sulfuric acid play in the Fischer esterification reaction?What is the purpose of the Dean-Stark trap?
In the Fischer esterification reaction, sulfuric acid acts as a catalyst that facilitates the reaction between a carboxylic acid and an alcohol to form an ester. The sulfuric acid protonates the carboxylic acid, making it more reactive towards the alcohol.
The acid also facilitates the removal of water from the reaction mixture, which drives the equilibrium towards the formation of the ester. This results in a higher yield of the ester product. The Dean-Stark trap is a piece of equipment used in the Fischer esterification reaction to remove water from the reaction mixture. It is a special type of condenser that collects the water formed during the reaction and allows it to separate from the organic layer.
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