We need a volume of 60.4 ml of 11.7 M HCl to make a 500.0 ml solution with a pH of 3.20.
To calculate the required volume of 11.7 M HCl to make a 500.0 ml solution with a pH of 3.20, we need to use the Henderson-Hasselbalch equation, which relates the pH of a solution to its pKa and the ratio of the concentrations of the conjugate base and acid.
Using the Henderson-Hasselbalch equation:
pH = pKa + log([A⁻] ÷ [HA])
where [A-] / [HA] is the ratio of the concentration of the conjugate base (Cl⁻) to the concentration of the acid (H⁺).
Rearranging the equation, we can solve for [H⁺]:
[H⁺] = [tex]10^{(pH - pKa)}[/tex]
[H⁺] = [tex]10^{(3.20 - (-1))}[/tex]
= [tex]10^{-3.20} + mol/L[/tex]
Since the concentration of HCl is equal to the concentration of [H⁺] in solution, we can calculate the moles of HCl required to make the solution:
moles of HCl = concentration of HCl × volume of solution
moles of HCl = [tex](10^{-3.20})[/tex] × (0.5 L)
= 7.08 × 10⁻⁴ mol
Finally, we can calculate the required volume of 11.7 M HCl:
volume of HCl = moles of HCl ÷ concentration of HCl
volume of HCl = (7.08 × 10⁻⁴ mol) ÷ (11.7 mol/L)
= 0.0604 L
= 60.4 ml
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If 450 ml of water are added to 550 ml of a 0.75 m k2so4 solution, what will the molarity of the diluted solution be?
To determine the molarity of the diluted solution, we need to use the equation:
M1V1 = M2V2
where M1 is the initial molarity of the solution, V1 is the initial volume of the solution, M2 is the final molarity of the solution, and V2 is the final volume of the solution.
In this case, the initial solution is a 0.75 M K2SO4 solution with a volume of 550 mL, and water is added to make a final volume of 450 mL. We can write:
M1 = 0.75 M
V1 = 550 mL
V2 = 450 mL
We can solve for M2:
M1V1 = M2V2
0.75 M × 550 mL = M2 × 450 mL
M2 = (0.75 M × 550 mL) / 450 mL
M2 = 0.92 M
Therefore, the molarity of the diluted solution is 0.92 M.
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Consider the following reaction: 2fe3+(aq) + 2hg(l) + 2cl−(aq) → 2fe2+(aq) + hg2cl2(s). which species loses electrons?
In the reaction 2Fe3+(aq) + 2Hg(l) + 2Cl−(aq) → 2Fe2+(aq) + Hg2Cl2(s), the species that loses electrons is Hg(l).
Here, mercury (Hg) undergoes oxidation, changing from Hg(l) to Hg2Cl2(s), and in the process, it loses electrons to form a bond with Cl− ions.
Hg(0) → Hg(+1) + 1 e-
And Iron undergoes reduction, Fe3+ (aq) accepts one electron to become Fe2+ (aq).
Fe(+3) + 1 e- → Fe(+2)
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Alanine is also a_____amino acid and would have similar _____of leucine.
Thus, enzyme activity should be maintained because the ____ should not undergo major change.
Protein structure
protein function
interaction to those
polar acidic
polar basic
function to that
nonpolar
Alanine is also a non-polar amino acid and would have similar Protein structure of leucine. Thus, enzyme activity should be maintained because the polar basic should not undergo major change.
Alanine is an amino acid this is used to make proteins. It is used to interrupt down tryptophan and nutrition B-6. It is a supply of power for muscular tissues and the principal frightened gadget. It strengthens the immune gadget and allows the frame use sugars. Alanine is a nonacidic α-amino acid. Its aspect chain (a methyl group) is neither acidic (it isn't greater acidic than water) nor basic (it does now no longer have a nitrogen atom lone pair that isn't delocalized via way of means of resonance).
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If you started with 20. 0 g of a radioisotope and waited for 3 half-lives to pass, then how much would remain? 1. 25g
5. 00g
10. 0g
2. 50g
Answer: The answer is 2.50g.
I hope this helps and have a great day!
If earth had no atmosphere, its longwave radiation emission would be lost quickly to space making the planet approximately 33 K cooler. Calculate the rate of radiation emitted E and the wavelength of maximum radiation emission for earth at 255 K.
The Earth is emitting the most longwave radiation at a wavelength of approximately 11.4 micrometers.
Longwave radiation emission, also known as infrared radiation, is the process by which the Earth releases heat into space. This radiation is absorbed by greenhouse gases in the atmosphere, which then trap the heat and prevent it from escaping back into space.
If the Earth had no atmosphere, this longwave radiation emission would be lost quickly to space, resulting in a much cooler planet.
To calculate the rate of radiation emitted (E) by the Earth at a temperature of 255 K, we can use the Stefan-Boltzmann Law, which states that E = σT⁴, where σ is the Stefan-Boltzmann constant (5.67 x 10⁻⁸ W/m²K⁴) and T is the temperature in Kelvin. Plugging in the values, we get:
E = 5.67 x 10⁻⁸ x (255)⁴
E = 3.8 x 10⁸ W/m²
This means that the Earth is emitting 3.8 x 10⁸ watts of longwave radiation per square meter at a temperature of 255 K.
The wavelength of maximum radiation emission can be determined using Wien's Law, which states that the wavelength of maximum emission (λmax) is equal to the constant of proportionality (b) divided by the temperature in Kelvin. The value of b is approximately equal to 2.898 x 10⁻³ mK.
Plugging in the values, we get:
λmax = b/T
λmax = 2.898 x 10⁻³ / 255
λmax = 1.14 x 10⁻⁵ meters
This means that the Earth is emitting the most longwave radiation at a wavelength of approximately 11.4 micrometers.
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What is mean by region of postive slope on the heating curve of water
When we talk about a heating curve of water, we are referring to a graph that shows the temperature of water as it is heated.
The x-axis of the graph represents the amount of heat energy being added to the water, while the y-axis represents the temperature of the water.
The region of positive slope on the heating curve of water refers to the portion of the graph where the temperature of the water is increasing as more heat energy is added. This region starts at the melting point of ice (0°C) and extends all the way to the boiling point of water (100°C) at standard atmospheric pressure.
During this region, the heat energy being added to the water is being used to break the intermolecular bonds between the water molecules and increase their kinetic energy, resulting in an increase in temperature. As the temperature increases, the water transitions from a solid (ice) to a liquid, and finally to a gas (steam).
It is important to note that the slope of the heating curve during the region of positive slope is positive, which means that the temperature is increasing at a steady rate. This region is significant because it represents the phase changes of water, which have important implications for a variety of fields, including chemistry, physics, and engineering.
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Certain amounts of the hypothetical substances A2 and B are mixed in a 3. 00 liter container at 300. K. When equilibrium is established for the reaction the following amounts are present: 0. 200 mol of A2, 0. 400 mol of B, 0. 200 mol of D, and 0. 100 mol of E. What is Kp, the equilibrium constant in terms of partial pressures, for this reaction
Without knowing the balanced chemical equation for the reaction involving A2, B, D, and E, it is not possible to determine the equilibrium constant Kp.
The equilibrium constant Kp is specific to a particular chemical reaction at a given temperature, and is determined by the stoichiometry of the reaction and the relative partial pressures of the reactants and products at equilibrium.
Therefore, to calculate Kp, we need to know the balanced chemical equation for the reaction involving A2, B, D, and E, as well as the partial pressures of the gases at equilibrium.
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A rigid container of N2 has a pressure at 378 kPa at a temperature of 413 K. What is the new pressure at 273 K?
The new pressure at 273 K, given that the initial pressure was 378 KPa, is 249.9 KPa
How do i determine the new presssure?The following parameters were obtained from the question:
Initial pressure (P₁) = 378 KPaInitial temperature (T₁) = 413 KNew temperature (T₂) = 273 KNew pressure (P₂) = ?The new pressure of the gas at 273 K can be obtained as shown below:
P₁ / T₁ = P₂/ T₂
378 / 413 = P₂ / 273
Cross multiply
413 × P₂ = 378 × 273
413 × P₂ = 103194
Divide both sides by 413
P₂ = 103194 / 413
P₂ = 249.9 KPa
Thus, from the above calculation, we can conclude the new pressure at 273 K is 249.9 KPa
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Help what’s the answer?
The theoretical yield of iron(II) oxide is 4.67 grams.
The percent yield of the reaction is 64.85%.
How to calculate theoretical and percent yield?To find the theoretical yield of iron(II) oxide, calculate the amount of iron(II) oxide that would be produced if all of the iron reacted with oxygen:
Molar mass of Fe = 55.85 g/mol
Molar mass of FeO = 71.85 g/mol
From the balanced equation, 1 mole of iron reacts with 1 mole of oxygen to produce 1 mole of iron(II) oxide. So, set up a proportion to find the theoretical yield:
3.59 g Fe × (1 mol Fe / 55.85 g) × (1 mol FeO / 1 mol Fe) × (71.85 g FeO / 1 mol FeO) = 4.67 g FeO (rounded to two decimal places)
Therefore, the theoretical yield of iron(II) oxide is 4.67 grams.
To find the percent yield, we use the following formula:
Percent yield = (actual yield / theoretical yield) x 100%
The actual yield is given as 3.03 grams. Plugging in the values:
Percent yield = (3.03 g / 4.67 g) x 100% = 64.85% (rounded to two decimal places)
Therefore, the percent yield of the reaction is 64.85%.
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Image transcribed:
Use the References to access important values if needed for this question.
For the following reaction, 3.59 grams of iron are mixed with excess oxygen gas. The reaction yields 3.03 grams of iron(II) oxide.
iron (s) + oxygen (g)- →iron(II) oxide (s)
What is the theoretical yield of iron(II) oxide ? ______ grams
What is the percent yield for this reaction? ________ %
an aqueous magnesium chloride solution is made by dissolving 7.39 7.39 moles of mgcl2 mgcl 2 in sufficient water so that the final volume of the solution is 3.10 l 3.10 l . calculate the molarity of the mgcl2 mgcl 2 solution.
The molarity of the magnesium chloride solution is 2.38 M. This means that there are 2.38 moles of magnesium chloride per liter of solution.
The molarity is defined as the number of moles of the solute per liter of the solution. In this problem, we are given the moles of magnesium chloride (7.39 moles) and the final volume of the solution (3.10 L). We can use the formula Molarity = moles of solute / volume of solution to calculate the molarity of the magnesium chloride solution.
First, we divide the moles of magnesium chloride by the volume of the solution in liters:
[tex]Molarity = 7.39 moles / 3.10 L[/tex]
[tex]Molarity = 2.38 M[/tex]
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A 75.0 ml volume of 0.200 m nh3 (kb = 1.8 * 10^-5) is titration with 0.500 m hno3. calculate the ph after the addition of 19.0 ml of hno3
The pH after the addition of 19.0 ml of 0.500 M HNO₃ to a 75.0 ml volume of 0.200 M NH₃ (Kb = 1.8 * 10⁻⁵) is 9.11.
1. Calculate moles of NH₃ and HNO₃: moles NH₃ = 75.0 ml * 0.200 mol/L = 15.0 mmol, moles HNO₃ = 19.0 ml * 0.500 mol/L = 9.5 mmol
2. Find moles of NH₃ remaining: 15.0 mmol - 9.5 mmol = 5.5 mmol
3. Calculate new concentrations: [NH₃] = 5.5 mmol / (75.0 ml + 19.0 ml) = 0.055 mol/L, [NH₄⁺] = 9.5 mmol / (75.0 ml + 19.0 ml) = 0.095 mol/L
4. Apply the Henderson-Hasselbalch equation: pH = pKa + log([NH₃]/[NH₄⁺])
5. Find pKa from Kb: pKa = 14 - log(Kb) = 14 - log(1.8 * 10⁻⁵) = 9.74
6. Calculate pH: pH = 9.74 + log(0.055/0.095) = 9.11
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The 3p subshell in the ground state of atomic silicon contains ________ electrons.
The 3p subshell in the ground state of atomic silicon contains 3 electrons.
In the ground state of atomic silicon, the electronic configuration is 1s²2s²2p⁶3s²3p².
The 3p subshell can accommodate a total of six electrons, as there are three orbitals in the subshell: 3px, 3py, and 3pz. The first two electrons in the 3p subshell will occupy the 3px and 3py orbitals singly, as required by Hund's rule, while the remaining four electrons will pair up in the 3pz orbital.
Therefore, the 3p subshell in the ground state of atomic silicon contains four electrons.
It's worth noting that the electronic configuration of an atom can be determined by using the periodic table and the rules of electron configuration.
Silicon, which has an atomic number of 14, has two electrons in the 1s orbital, two electrons in the 2s orbital, six electrons in the 2p orbital, two electrons in the 3s orbital, and four electrons in the 3p orbital.
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Question 1 (2 points)
2. 5 L of a gas is heated from 200 K to 300 K. What is the final volume of the gas?
The final volume of the gas is 3.75 L. This result can be explained by the fact that as the temperature of the gas increased, the kinetic energy of its particles also increased, causing them to move faster and occupy a larger volume.
According to the ideal gas law, PV = nRT, the volume of a gas is directly proportional to its temperature.
Therefore, if the temperature of a gas is increased while its pressure and amount remain constant, its volume will also increase.
In this case, the initial volume of the gas is 2.5 L and its temperature is increased from 200 K to 300 K. To find the final volume of the gas, we can use the following equation:
V2 = (T2/T1) x V1
where V1 is the initial volume of the gas, T1 is the initial temperature of the gas, T2 is the final temperature of the gas, and V2 is the final volume of the gas. Plugging in the values, we get:
V2 = (300 K/200 K) x 2.5 L
V2 = 3.75 L
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Help what’s the answer?
This problem can be solved using Boyle's Law, which posits that the pressure of any given gas will be inversely proportional to its volume when temperature is kept as a constant.
What will be the final volume of the given methane gas ?Mathematically Boyle's Law can be expressed as:
P₁V₁ = P₂V₂
where P₁ and V₁ are the initial pressure and volume, respectively, and P₂ and V₂ are the final pressure and volume, respectively.
We are given that:
P₁ = 1.15 atm
V₁ = 640 mL
T = 23.9 °C (which is 297.05 K, using the Kelvin temperature scale)
We need to find V₂ when P₂ = 1.43 atm.
Using Boyle's Law, we can set up the following equation:
P₁V₁ = P₂V₂
(1.15 atm)(640 mL) = (1.43 atm)(V₂)
Solving for V₂:
V₂ = (1.15 atm)(640 mL) / (1.43 atm)
V₂ = 514.69 mL
Therefore, the final volume of the methane gas is 514.69 mL when compressed at constant temperature until its pressure is 1.43 atm.
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A student has a sample of copper (I) sulfate hydrate. If the hydrate has a mass of 20 grams and the anhydrous salt has a mass of 12 grams, what is the percent of water in the sample? %
Student has a sample of copper (I) sulfate hydrate, then the percent of water in the sample is 40%.
What is meant by a hydrate?In chemistry, a hydrate is a compound that contains water molecules that are chemically bound to the atoms or ions of the compound.
Mass of the anhydrous salt is given as 12 grams.
So, mass of water = total mass - mass of anhydrous salt
mass of water = 20 g - 12 g
mass of water = 8 g
Now, % water = (mass of water ÷ total mass) × 100
% water = (8 g ÷ 20 g) × 100
% water = 40%
Therefore, the percent of water in the sample is 40%.
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What volume of 16. 2 M NH3 is required to prepare 350. 0 mL of 0. 200 M NH3
4.3 mL of 16.2 M [tex]NH3[/tex]is required to prepare 350.0 mL of 0.200 M [tex]NH3[/tex]
The molarity equation is:
Molarity (M) = moles of solute / liters of solution
We can rearrange this equation to solve for the number of moles of solute:
moles of solute = Molarity (M) x liters of solution
We can use this equation to determine the number of moles of [tex]NH3[/tex]required to prepare the 350.0 mL of 0.200 M [tex]NH3[/tex] solution:
moles of [tex]NH3[/tex] = (0.200 M) x (0.350 L) = 0.070 moles [tex]NH3[/tex]
Now, we need to determine the volume of 16.2 M [tex]NH3[/tex]required to obtain 0.070 moles of [tex]NH3[/tex]. We can use the following equation:
moles of solute = Molarity (M) x liters of solution
Rearranging the equation to solve for the volume of solution, we get:
liters of solution = moles of solute / Molarity (M)
Plugging in the values, we get:
liters of solution = 0.070 moles / 16.2 M[tex]NH3[/tex] = 0.0043 L
Converting this to milliliters, we get:
volume of 16.2 M [tex]NH3[/tex] = 0.0043 L x 1000 mL/L = 4.3 mL
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What set of coefficients will balance the chemical equation below:
___H2SO4 (aq) + ___NH4OH (aq) ---> ___H2O (l) + ___(NH4)2SO4 (aq)
A. 2,2,1,2
B. 1,2,2,1
C. 1,1,2,2
D. 1,3,2,1
The set of coefficients that will balance the chemical equation are: B.) 1, 2, 2, 1
What is meant by chemical reaction?Chemical reactions are processes that cause one set of chemical elements to change into another set of chemical elements. During chemical reaction, atoms are rearranged, bonds between atoms are broken and formed and then new compounds or molecules are produced.
Chemical reactions can be represented using the chemical equations, that show reactants and products.
The balanced chemical equation for the given reaction is: H₂SO₄ (aq) + 2NH₄OH (aq) ---> 2H₂O (l) + (NH₄)2SO₄ (aq)
Therefore, the set of coefficients that will balance the chemical equation are: 1, 2, 2, 1.
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The Goodyear Blimp has a volume of 5. 74 x 10e6 L. If it was also filled with hydrogen, how many moles of hydrogen would fit into the blimp?
The mass of helium present in the blimp is 644 kg.
To calculate the mass of helium present in the blimp, we can use the ideal gas law:
PV = nRT
where:
We can rearrange this equation to solve for the number of moles of gas:
n = PV/RT
Substituting the given values, we get:
n = (1.2 atm) x [tex](5.74 * 10^6 L)[/tex]/ [(0.08206 L·atm/K·mol) x (25°C + 273.15)]
n = 1.61 x [tex]10^5[/tex] moles of helium
Now, to calculate the mass of helium present in the blimp, we can use the molar mass of helium:
mass = n x molar mass
mass = (1.61 x [tex]10^5 mol[/tex]) x (4.00 g/mol)
mass = 644 kg
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--The complete Question is, If the Goodyear Blimp is filled with helium gas at a pressure of 1.2 atm and a temperature of 25°C, what is the mass of helium present in the blimp? (Assume ideal gas behavior and a molar mass of 4.00 g/mol for helium.) --
A gas occupying 3. 05 liters at STP is warmed to 85. 0°C. It
now occupies 9. 85 liters. What is the pressure of the gas?
The pressure of the gas can be calculated using the combined gas law equation. The pressure of the gas at STP is 1 atm. Therefore, the pressure of the gas at 85.0°C is 0.289 atm.
Given that a gas occupies 3.05 L at STP, we can assume that the gas is at a pressure of 1 atm and a temperature of 273 K. We can use the ideal gas law to find the number of moles of gas in the container at STP:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
Rearranging the equation to solve for n, we get:
n = PV/RT
Substituting in the values for P, V, R, and T, we get:
n = (1 atm)(3.05 L)/(0.0821 L·atm/mol·K)(273 K)
n = 0.125 mol
Now, we know that the volume of the gas has increased to 9.85 L and the temperature has increased to 85°C. We need to find the new pressure of the gas.
First, we need to convert the temperature to Kelvin:
85°C + 273 = 358 K
Next, we can use the combined gas law to find the new pressure of the gas:
P1V1/T1 = P2V2/T2
Substituting in the values we know:
(1 atm)(3.05 L)/(273 K) = P2(9.85 L)/(358 K)
Solving for P2, we get:
P2 = (1 atm)(3.05 L)/(273 K)(9.85 L/358 K)
P2 = 0.289 atm
Therefore, the pressure of the gas at the new volume and temperature is 0.289 atm.
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What is the density of ammonia (in g/L) at 646 torr and 10°C? *
Molar Mass of Ammonia = 17. 04
R = ((0. 0821 atm*L)/(mol*k)
To find the density of ammonia (NH3) at 646 torr and 10°C, we need to use the Ideal gas law equation:
PV = nRT
Where R is the gas constant, n is the number of moles, P is pressure, V is volume, and T is temperature in Kelvin.
We must first change the pressure from torr to atm:
646 torr = 0.852 atm
The temperature is then changed from Celsius to Kelvin:
10°C + 273.15 = 283.15 K
Now, we can rearrange the ideal gas law equation to solve for density (d):
d = (PM) / (RT)
M is the ammonia's molar mass.
With the supplied values and constants, we obtain:
d = (0.852 atm)(17.04 g/mol) / ((0.0821 atm*L)/(mol*K))(283.15 K)
d = 0.736 g/L
Therefore, the density of ammonia at 646 torr and 10°C is 0.736 g/L.
What do you mean by density of ammonia?
The density of ammonia refers to the mass of ammonia gas per unit volume. The standard temperature and pressure (STP), which is defined as a temperature of 0 degrees Celsius (273.15 Kelvin) and a pressure of 1 atmosphere (101.325 kilopascals or 760 millimeters of mercury), is used to measure the density of ammonia, a colorless gas that is lighter than air.
At STP, the density of ammonia gas is approximately 0.771 grams per liter (g/L) or 0.771 kilograms per cubic meter (kg/m3). However, the density of ammonia can vary depending on the temperature, pressure, and other factors such as the presence of impurities or moisture.
The density of ammonia is an important property in many applications, particularly in the chemical industry. It is used to calculate the amount of ammonia needed for a particular reaction or process, and can also be used to determine the mass or volume of ammonia gas in a storage tank or container.
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A) What volume of concentrated nitric acid (15.8 M) is needed to prepare 5.0 L of a 2.5 M solution?
WILLLL GIVE BRAINLIEST!!!
Answer:
0.79 L of concentrated nitric acid is needed to prepare 5.0 L of a 2.5 M solution.
Explanation:
We can use the formula:[tex]M_1V_1 = M_2V_2[/tex]where [tex]M_1[/tex] is the concentration of the concentrated nitric acid, [tex]V_1[/tex] is the volume of concentrated nitric acid needed, [tex]M_2[/tex] is the desired concentration of the final solution, and [tex]V_2[/tex] is the final volume of the solution.Plugging in the given values, we get:[tex](15.8 \text{ M})(V_1) = (2.5 \text{ M})(5.0 \text{ L})[/tex]Solving for [tex]V_1[/tex], we get:[tex]V_1 = \frac{(2.5 \text{ M})(5.0 \text{ L})}{15.8 \text{ M}} \approx 0.79 \text{ L}[/tex]Therefore, approximately 0.79 L of concentrated nitric acid is needed to prepare 5.0 L of a 2.5 M solution.
Answer:
0.79 L
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How many total electrons are transferred during the reaction of the oxidation of chromium
metal according to the following reaction?
4Cr(s) + 302(g)
-->
2Cr2O3(s)
O4 electrons
6 electrons
8 electrons
O2 electrons
In the reaction of the oxidation of chromium, 4 chromium atoms each lose 3 electrons to become positively charged ions, and 3 oxygen molecules each gain 4 electrons to become negatively charged ions. This means that a total of 12 electrons are transferred in the oxidation of chromium.
The oxidation of chromium can be broken down into two half-reactions:
1) The oxidation of chromium:
4Cr(s) --> 4Cr³⁺(aq) + 12e-
In this half-reaction, each
chromium atom loses 3 electrons to become a positively charged ion (Cr³⁺), and a total of 12 electrons are
transferred
.
2) The reduction of oxygen:
3O₂(g) + 12e- --> 6O²⁻(aq)
In this half-reaction, each oxygen molecule gains 4 electrons to become a negatively charged ion (O²⁻), and a total of 12 electrons are transferred.
Therefore, the total number of electrons transferred during the reaction of the oxidation of chromium is 12. It is important to note that this reaction involves the transfer of O₂ electrons, not O₄ electrons.
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Calculate the specific heat in J/(g·ºC) of an unknown substance if a 2. 50-g sample releases 12. 0 cal as its temperature changes from 25. 0ºC to 20. 0ºC. ________J/(g·°C)
The specific heat in J/(g·ºC) of an unknown substance if a 2. 50-g sample releases 12. 0 cal as its temperature changes from 25. 0ºC to 20. 0ºC. 2.02 J/(g·ºC).
The specific heat of the unknown substance can be calculated using the formula:
q = m x c x ΔT
where q is the heat released, m is the mass of the substance, c is the specific heat, and ΔT is the change in temperature.
First, we need to convert the given heat release from calories to joules:
12.0 cal x 4.184 J/cal = 50.208 J
Next, we can plug in the given values and solve for c:
50.208 J = 2.50 g x c x (25.0°C - 20.0°C)
c = 2.02 J/(g·°C)
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A 4 L sample of gas at 30 degrees celcius and 1 atm is changed to 0 degrees celcius and 800torr. What is its new volume?
A 4 L sample of gas at 30 degrees celcius and 1 atm is changed to 0 degrees celcius and 800torr. 4.51 L is its new volume.
To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas.
[tex]P1V1/T1 = P2V2/T2[/tex]
where P1, V1, and T1 are the initial conditions, and P2, V2, and T2 are the final conditions.
Substituting the given values, we get:
[tex]\left(\frac{{1 , \text{atm} \cdot 4 , \text{L}}}{{303 , \text{K}}}\right) = \left(\frac{{0.8 , \text{atm} \cdot V2}}{{273 , \text{K}}}\right)[/tex]
Solving for V2, we get:
[tex]V2 = \frac{{1 , \text{atm} \cdot 4 , \text{L} \cdot 273 , \text{K}}}{{303 , \text{K} \cdot 0.8 , \text{atm}}} = 4.51 , \text{L}[/tex]
Therefore, the new volume of the gas is 4.51 L when the temperature is changed from 30 degrees Celsius to 0 degrees Celsius and the pressure is changed from 1 atm to 800 torr.
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The volume of a sample of gas is 2. 8 L when the pressure is 749. 5 mm Hg and the temperature is 31. 2 C. What is the new temperature in degrees Celsius if the volume increases to 4. 3 L and the pressure increases to 776. 2 mm Hg?
a 120 C
b 280 C
c 480 C
d 210 C
The volume of a sample of gas is 2.8 L when the pressure is 749.5 mm Hg and the temperature is 31. 2°C. (c) 480°C is the new temperature in degrees Celsius if the volume increases to 4. 3 L and the pressure increases to 776.2 mm Hg
Using the combined gas law:
(P1V1) / (T1) = (P2V2) / (T2)
Where:
P1 = 749.5 mm Hg
V1 = 2.8 L
T1 = 31.2 + 273.15 = 304.35 K (temperature converted to Kelvin)
P2 = 776.2 mm Hg
V2 = 4.3 L
T2 = ?
Solving for T2:
T2 = (P2V2T1) / (P1V1)
T2 = (776.2 mmHg * 4.3 L * 304.35 K) / (749.5 mmHg * 2.8 L)
T2 ≈ 758 K
Converting T2 back to Celsius:
T2 = 758 K - 273.15 = 484.85°C ≈ 480°C
Therefore, the new temperature is approximately 480°C.
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I need help!
Describe the bonding in water molecule using VBT. Show the overlap of hybridized orbitals leading to the formation of H2O molecule. Account for the bond angle 104. 5°.
Answer:
In Valence Bond Theory (VBT), the water molecule is formed by overlapping of two hydrogen 1s orbitals with two hybridized oxygen orbitals. The oxygen atom in the water molecule has two unpaired electrons in two 2p orbitals and two paired electrons in two 2s orbitals. It hybridizes the 2s and 2p orbitals to form four hybridized sp3 orbitals. These four sp3 hybridized orbitals point towards the corners of a tetrahedron.
The two hybridized orbitals of oxygen containing unpaired electrons overlap with the 1s orbitals of two hydrogen atoms. This overlapping results in the formation of two O-H sigma (σ) bonds. The two remaining hybridized orbitals containing the paired electrons do not participate in bond formation.
The bond angle in the water molecule is 104.5°, which is less than the tetrahedral angle (109.5°) because the two lone pairs of electrons on the oxygen atom exert greater repulsion than the two bonding pairs. This causes the bonding pairs to be pushed closer together, resulting in a smaller bond angle.
what would earth be like if vascular plants never developed
If the vascular plants never developed, the Earth would be drastically different. Vascular plants are responsible for much of the oxygen production on our planet, so the atmosphere would contain significantly less oxygen. Additionally, without the root systems of vascular plants, soil erosion would be much more prevalent and the landscape would likely be more barren.
The evolution of many animals, including insects and birds, would have been impacted as well, as many of these species rely on vascular plants for food and shelter. Overall, the absence of vascular plants would have a profound effect on the ecology and biodiversity of our planet.
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QUESTION 6
Write the electron configuration of the following ions. Use the equation editing tool for neatness. It is symbolized with fx.
B a to the power of 2 plus end exponent C a to the power of 2 plus end exponent C u to the power of 2 plus end exponent L i to the power of plus K to the power of plus N a to the power of plus S r to the power of 2 plus end exponent
Electronic configuration of Ba²⁺ is 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶; Ca²⁺ is 1s²2s²2p⁶3s²3p⁶; Li⁺ is 1s²; K⁺ is 1s²2s²2p⁶3s²3p⁶; Na⁺ is 1s²2s²2p⁶; Sr²⁺is 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶.
Electronic configuration of the elements present in the periodic table is defined as the designation of atoms on the basis of the electrons present in their shells and subshells. The electrons entering in the same valence shell are grouped together which shows similarity in case of physical and chemical properties. Atoms tend to lose electron and attain stable positive charge so as to attain their nearest noble gas configuration.
Electronic configuration of
Ba²⁺ = 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶
Ca²⁺= 1s²2s²2p⁶3s²3p⁶
Li⁺=1s²
K⁺ = 1s²2s²2p⁶3s²3p⁶
Na⁺ = 1s²2s²2p⁶
Sr²⁺= 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶
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Chemical equilibrium is a dynamic process. What does this mean?
1. Nothing is changing.
2. There are multiple reactants and products involved in the chemical reaction.
3. It appears as though nothing is happening, but there is constant change occurring.
4.The reaction has reached completion and stopped reacting.
Answer: 3. It appears as though nothing is happening, but there is constant change occurring.
Explanation:
equilibrium is the state when the changes cancel each other, and the net change is 0.
think of it like a stalemate in tug of war; both people are pulling, but you wont see anything change, because their forces are equal and in opposite direction :)
All else being equal, a reaction with a higher activation energy compared to one with a lower activation energy will:.
All else being equal, a reaction with a higher activation energy will have a slower reaction rate compared to one with a lower activation energy.
Activation energy refers to the minimum amount of energy required for a chemical reaction to occur. The higher the activation energy, the more energy is required to initiate the reaction, and thus the slower the reaction rate.
This is because a higher activation energy means that fewer reactant molecules will have enough energy to overcome the energy barrier and form products. Therefore, reactions with higher activation energies require more energy input to proceed and will typically have a slower reaction rate than those with lower activation energies.
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