What was the initial speed of a car if its speed is 40 m/s after 5 seconds of
accelerating at 4 m/s27
A. 10 m/s
B. 60 m/s
C. 20 m/s
D. 25 m/s
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Answers

Answer 1
We use the formula:
V= u + at

V- final velocity. U- intial velocity. A- acceleration. T- time

Note: velocity is speed in this question

Fill in values:
V= u + at
40= u + 4 x 5
40= u + 20
40 - 20 = u
u = 20m/s
Answer 2

Answer:

[tex]\boxed {\boxed {\sf C. \ 20 \ m/s }}[/tex]

Explanation:

We are asked to find the initial speed of a car.

We are given the final speed, the time, and the acceleration, so we will use the following kinematic equation:

[tex]v_f=v_i+at[/tex]

We know the final speed is 40 meters per second, the acceleration is 4 meters per second squared, and the time is 5 seconds.

[tex]v_f[/tex]= 40 m/s t= 5 s a= 4 m/s²

Substitute the values into the formula.

[tex]40 \ m/s = v_i+(4 \ m/s^2 * 5 \ s)[/tex]

Multiply inside the parentheses.

[tex]40 \ m/s =v_i+ 20 \ m/s[/tex]

We are solving for the initial speed, so we must isolate the variable [tex]v_i[/tex].  

20 meters per second is being added to [tex]v_i[/tex]. The inverse operation of addition is subtraction. Subtract 20 m/s from both sides of the equation.

[tex]40 \ m/s - 20 \ m/s = v_i + 20 \ m/s - 20 \ m/s[/tex]

[tex]40 \ m/s - 20 m/ s = v_i[/tex]

[tex]20 \ m/s=v_i[/tex]

The initial speed of the car is 20 meters per second and choice C is correct.


Related Questions

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Answer:

No, false.

Explanation:

You may use it to power a light bulb if you desired. The reason it isn't is because it's inconsistent not predictable.

The static electricity light our homes. This statement is false.

What is static electricity?

When two objects are rubbed, they get charged by friction present into it. Object can also be charged by induction.

The charge gets accumulated on them, due to which spark occurs.

This spark cannot light our homes. As, this has very less magnitude and no continuous flow. There is no complete circuit to get the continuous flow of electricity.

Thus, static electricity can't light our homes.

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Sharing thoughts on a peer's story is similar to... a.being a teacher b.listening to a lesson c.editing a story d.a collaborative discussion

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Answer:

D

Explanation:

when sharing ideas, you are being collaborative

please help me
7. If microsecound = 0.5, how much force must be applied to a spring (spring constant of 0.8 N/m) which is attached to a block of wood (mass = 4.0 kg) in order to just begin to move the block?​

Answers

Answer:

Explanation:

Your question is quite confusing, particularly the information about microsecond = 0.5.

I'm going to ASSUME that you mean coefficient of static friction μs = 0.5

unfortunately typing a subscript "s" is very difficult and probably leads to such confusion.

I will also ASSUME that the block, and spring, and force vector are all horizontal.

If the force is slowly increased until the block slips, the spring will compress until the force on each end equals the maximum static friction force. As we are not concerned with the compression distance, only the force, we can ignore the spring constant information and simply find the maximum available static friction force.

F = μN

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Gravity will apply a different amount of force to objects with different mass. The force of gravity can also be called
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Answers

Answer:

E.Mass

Explanation:

Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.

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Answers

Answer:

Atoms.

Explanation:

The fundamental structure obstructs that make matter are called molecules. What are the various particles found in iotas? (Reply: electrons, protons and neutrons) Where are they found? (Reply: Protons and neutrons are found in the core, and electrons are found in shells around the outside of the core.)

Really hope this helps! :D

Explanation:

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(Answer: electrons, protons, neutrons) Where are they? (Answer: Protons and neutrons are in the nucleus, and electrons are in the shell around the nucleus.)

HELP HELP!


Which of the following surfaces would have the lowest amount of friction?

a. Glass
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d. Ice

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what are the statements

Can you show us a picture please

David drives and slows to a stop when he sees a stop sign. A graph of his velocity over time is shown below.
Velocity
20-
P6
15+
As:
10+
MY
5+
Time (s)
Col
t
5
10
15
20
MY
Pro
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Pro

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Answer:

-2.0

Explanation:

Compare and contarst the difference between saturated and unsaturated solutions and supersaturated

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Answer:

Unsaturated Solution: Less amount of salt in water, clear solution, no precipitation. Saturated Solution: The maximum amount of salt is dissolved in water, Colour of the solution slightly changes, but no precipitation. Supersaturated Solution: More salt is dissolved in water, Cloudy solution, precipitation is visible

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« non eatables »

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Which theory of emotion explains the startle response

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Answer:

In the present study, the startle blink reflex is used as a measure of emotion regulation to effective picture stimuli. Based on the aphasic theory of emotion, it is hypothesized that the startle response will be largest in magnitude in the presence of negative emotional stimuli (Varanasi, Spence, & Lang, 1988).

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Answers

Answer:

Soldering is a technique or a process to bond metals with the help of solder. Solder is a metal alloy with a low melting point and is often regarded as the base metal for soldering. The piece or structure that is being bonded together does not get hot enough to melt and this is where solder (base metal) comes into play and creates the connection.

Explanation:

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Pls mark brainliest :3

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Give him brainly ;) he deserves it

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Answers

Answer:

4. pressure is defined as force per unit area

Pressure is defined by force per unit area.

WHAT IS PRESSURE:Pressure refers to the force applied to a substance per unit area.

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Answers

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Answers

They bounce off each other, conserving energy and momentum.

This is considered an elastic collision because they bounce off each other, conserving energy only.

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Answer:

Explanation:

Testing answer please do not delete

the diffrence in potential betwen two points that represents the work involved or the energy relesed in the transfe of a unit quantity of electicity from one point to the other

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Answers

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(neutral)

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(electrons)

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Show your workikkkkkkkk

Answers

Answer:

Explanation:

F = ma

Assuming the 20° is angle θ measured to the horizontal

mgsinθ - μmgcosθ = ma

g(sinθ - μcosθ) = a

at constant velocity, a = 0

g(sinθ - μcosθ) = 0

   sinθ - μcosθ = 0

                 sinθ = μcosθ

μ = sinθ/cosθ

μ = tanθ

μ = tan20

μ = 0.3639702342...

μ = 0.36

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b

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- The rocket now has a thruster that malfunctions and is now pushing the rocket in the wrong direction. What is the new net force on the rocket if it is now accelerating at 12mls²​

Answers

From your previous question

Mass=30kg

Acceleration=12m/s^2

[tex]\\ \sf\longmapsto F=ma[/tex]

[tex]\\ \sf\longmapsto F=30(12)[/tex]

[tex]\\ \sf\longmapsto F=360N[/tex]

Given,

Acceleration = 12 m/s²

According to your previous question you posted,

Mass = 30 KG

Solution:

We know that the formula of force according to the Newton's second law is:

[tex]\longmapsto \sf \red{f = m \times a}[/tex]

[tex]\sf \longmapsto \ 30 \times 12[/tex]

[tex]\sf \longmapsto \: \boxed {\sf \blue3 \red60}[/tex]

Answer:

[tex]\sf \boxed{ \bf \: force = 360\: N}[/tex]

the hanging
mass would need to be

Answers

Answer:

what do you need help with I can try to help you

Two spherically symmetric planets with no atmosphere have the same average density, but planet B has twice the radius of planet A. A small satellite of mass mA has period TA when it orbits planet A in a circular orbit that is just above the surface of the planet. A small satellite of mass mB has period TB when it orbits planet B in a circular orbit that is just above the surface of the planet.

Answers

A period of a satellite is the time taken by the satellite to travel round a

body.

The comparison between the periods  [tex]T_B[/tex], and [tex]T_A[/tex] is [tex]\underline {T_B = \dfrac{\sqrt{2} }{4 } \cdot T_A}[/tex]

Reason:

The period, T, of a satellite is given as follows;

[tex]T = 2 \cdot \pi \cdot \sqrt{\dfrac{r^3}{G \cdot M} }[/tex]

Volume of the planet A = [tex]\dfrac{4}{3} \cdot \pi \cdot r^3[/tex]

Mass of planet A, [tex]m_A[/tex] = [tex]\dfrac{4}{3} \cdot \pi \cdot r^3 \times \rho[/tex]

Volume of the planet B = [tex]\dfrac{4}{3} \cdot \pi \cdot (2 \cdot r)^3 = \dfrac{32}{3} \cdot \pi \cdot r^3[/tex]

Mass of planet B, [tex]m_B[/tex] = [tex]\dfrac{32}{3} \cdot \pi \cdot r^3 \times \rho[/tex]

Period of the satellite on planet A, [tex]T_A[/tex], is given as follows;

[tex]T_A = 2 \cdot \pi \cdot \sqrt{\dfrac{r^3}{G \times \dfrac{4}{3} \cdot \pi \cdot r^3 \times \rho} } = 2 \cdot \pi \cdot \sqrt{\dfrac{1}{G \times \dfrac{4}{3} \cdot \pi \times \rho} }[/tex]

Period of the satellite on planet B, [tex]T_B[/tex], is given as follows;

[tex]T_B = 2 \cdot \pi \cdot \sqrt{\dfrac{r^3}{G \times \dfrac{32}{3} \cdot \pi \cdot r^3 \times \rho} } = 2 \cdot \pi \cdot \sqrt{\dfrac{1}{G \times \dfrac{32}{3} \cdot \pi \times \rho} }[/tex]

Therefore, get;

[tex]\dfrac{T_A}{T_B} = \dfrac{ 2 \cdot \pi \cdot \sqrt{\dfrac{3}{G \times 4 \cdot \pi \times \rho} }}{ 2 \cdot \pi \cdot \sqrt{\dfrac{3}{G \times 32 \cdot \pi \times \rho} }} = \sqrt{\dfrac{32}{4} } = \sqrt{8} = 2 \cdot \sqrt{2}[/tex]

Therefore, [tex]T_A[/tex] = (2·√2)·[tex]T_B[/tex]

[tex]T_B = \dfrac{T_A}{2 \cdot \sqrt{2} } = \dfrac{\sqrt{2} \cdot T_A}{4 }[/tex]

The comparison between [tex]T_A[/tex] and  [tex]T_B[/tex] is therefore;

[tex]\underline {T_B = \dfrac{\sqrt{2} }{4 } \cdot T_A}[/tex]

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