when sodium chloride dissolves in water, how do the water molecules orient around the ions? question 6 options: a) the oxygen atoms point toward the sodium ions, and the hydrogen atoms point toward the chloride ions. b) the hydrogen atoms point toward both the sodium and the chloride ions. c) the oxygen atoms point toward both the sodium ions and the chloride ions. d) the hydrogen atoms point toward the sodium ions, and the oxygen atoms point toward the chloride ions. e) water molecules are randomly oriented around the ions.

If the H2SO4 formula is understood, the name can be written according to the naming guidelines for acids.

Industrially, sulfuric acid is created when water reacts with sulphur trioxide (see sulphur oxide), which is created chemically by combining oxygen and sulphur dioxide, either through the contact process or the chamber process.

In the process of converting ethanol to ethane, H2SO4 serves as a dehydrating agent. It aids in removing water molecule (more particularly , the -OH group from one carbon and -H from the other carbon) in the following reaction: CH3CH2OH.

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The questions that should be asked before writing the name for H₂SO₄ are options 2, 3, and 5.

These questions are relevant because they provide important clues about the compound's naming conventions and help determine the correct name for H₂SO₄. The suffix "-ic" is commonly used for naming the anions of many acids. The suffixes "-ate" and "-ite" are commonly used for naming the anions of many compounds, including acids.

Hydrogen can act as a cation in some compounds, including acids. Recognizing hydrogen's role as a cation helps determine the appropriate naming conventions for the compound.

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Your question is incomplete, most probably the full question is this:

Which question should be asked prior to writing the name for H₂SO₄? Select all that apply.

Linus pauling

1. In 1913, Niels Bohr proposed a theory for the hydrogen atom, based on quantum theory that some physical quantities only take discrete values. Electrons move around a nucleus, but only in prescribed orbits, and If electrons jump to a lower-energy orbit, the difference is sent out as radiation

3. J.J. Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons. Thomson proposed the plum pudding model of the atom, which had negatively-charged electrons embedded within a positively-charged "soup."

4. Ernest Rutherford found that the atom is mostly empty space, with nearly all of its mass concentrated in a tiny central nucleus. The nucleus is positively charged and surrounded at a great distance by the negatively charged electron

5. In 1932, Chadwick made a fundamental discovery in the domain of nuclear science: he proved the existence of neutrons – elementary particles devoid of any electrical charge.

Linus pauling was the only scientist not related to the development of the atomic theory.

During the 1930s Linus Pauling was among the pioneers who used quantum mechanics to understand and describe chemical bonding–that is, the way atoms join together to form molecules.

53 mg of lead can be dissolved per litre of water. Option e is correct.

The solubility product constant, Ksp, of PbSO4 is given by the expression below:

Ksp= [Pb2+][SO42-]

If S is the solubility of PbSO4 in Molarity, then the quantity of lead ions that can dissolve from the salt into the solution is given as

S × MW (where MW is the molecular weight of PbSO4)

MW of PbSO4 = (1 x 207.2) + (1 x 32.06)+ (15.99 x 4) = 303.22 g/mol

S =√Ksp = √1.6 × 10-8= 1.26 × 10-4

So the number of milligrams of lead (II) that can dissolve per liter of water is

1.26 × 10^-4  M/L  × 303.22 g/mol = 0.352 g/L= 35.2 mg/L≈ 35 mg/L

The correct answer is (e) 53 mg/L.

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We need to add 5.61 ml of a 2.67 M stock solution dye to a 50 ml volumetric flask before filling the flask to the calibration mark.

This can be found using the formula of concentration and volume for dilution of solutions which is C1V1=C2V2.

Steps for finding the ml of a 2.67 M stock solution that should be added to a 50 ml volumetric flask before filling the flask to the calibration mark:

C1= is the initial concentration of the solution

V1 = is the initial volume of the solution

C2 = is the final concentration of the solution

V2 = is the final volume of the solution

Now, let's substitute the given values into the formula

Stock concentration : 2.67 M = C1

Final concentration : 0.30 M = C2

Final Volume : 50 ml = V2

Let V1 is the stock solution required

Therefore, 2.67 M * V1 = 0.30 M * 50 ml

2.67 M * V1 = 15 ml

V1 = 5.61 ml

Therefore, we need to add 5.61 ml of a 2.67 M stock solution to a 50 ml volumetric flask before filling the flask to the calibration mark to prepare a 0.30 M solution of food dye.

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There are approximately 6.02 x 10²³ atoms in 58.7 g of nickel.

The molar mass of nickel (Ni) is 58.69 g/mol.

Using the formula:

number of moles = mass / molar mass

we can calculate the number of moles of nickel in 58.7 g:

number of moles = 58.7 g / 58.69 g/mol

number of moles = 1.0006 mol

Since one mole of any substance contains Avogadro's number of atoms (6.022 x 10²³), we can calculate the number of atoms of nickel in 1.0006 mol:

number of atoms = 1.0006 mol x 6.022 x 10²³ atoms/mol

number of atoms = 6.025 x 10²³ atoms

Therefore, there are approximately 6.025 x 10²³ atoms in 58.7 g of nickel

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Answer:

To solve stoichiometry problems like these, we need to use balanced chemical equations and convert the given quantities into moles using their respective molar masses. Then, we can use the mole ratios from the balanced equation to find the moles of the unknown substance, and convert back to grams if necessary.

Fe₂O3 + 2Al → 2Fe + Al₂O3

How many grams of Al are needed to completely react with 135 g Fe₂O3?

First, we need to find the moles of Fe₂O3 in 135 g:

molar mass of Fe₂O3 = 2(55.85 g/mol) + 3(16.00 g/mol) = 159.70 g/mol

moles of Fe₂O3 = 135 g / 159.70 g/mol = 0.8459 mol

According to the balanced equation, 2 moles of Al react with 1 mole of Fe₂O3:

moles of Al = 2 × moles of Fe₂O3 = 2 × 0.8459 mol = 1.6918 mol

Finally, we can convert the moles of Al to grams using its molar mass:

molar mass of Al = 26.98 g/mol

mass of Al = moles of Al × molar mass of Al = 1.6918 mol × 26.98 g/mol ≈ 45.66 g

Therefore, 45.66 grams of Al are needed to completely react with 135 g Fe₂O3.

How many grams of Al₂O3 can form when 23.6 g Al react with excess Fe₂O3?

First, we need to find the moles of Al in 23.6 g:

moles of Al = 23.6 g / 26.98 g/mol ≈ 0.874 mol

According to the balanced equation, 2 moles of Al react with 1 mole of Al₂O3:

moles of Al₂O3 = 0.5 × moles of Al = 0.5 × 0.874 mol = 0.437 mol

Finally, we can convert the moles of Al₂O3 to grams using its molar mass:

molar mass of Al₂O3 = 101.96 g/mol

mass of Al₂O3 = moles of Al₂O3 × molar mass of Al₂O3 = 0.437 mol × 101.96 g/mol ≈ 44.64 g

Therefore, 44.64 grams of Al₂O3 can form when 23.6 g Al react with excess Fe₂O3.

How many grams of Fe₂O3 react with excess Al to make 475 g Fe?

First, we need to convert the given mass of Fe to moles:

molar mass of Fe = 55.85 g/mol

moles of Fe = 475 g / 55.85 g/mol ≈ 8.504 mol

According to the balanced equation, 2 moles of Al react with 1 mole of Fe:

moles of Al = 0.5 × moles of Fe = 0.5 × 8.504 mol = 4.252 mol

Since Al is in excess, it will not be completely consumed by the reaction. However, we can use the moles of Al to find the moles of Fe₂O3 needed:

moles of Fe₂O3 = 0.5 × moles of Al = 0.5 × 4.252 mol = 2.126 mol

Finally, we can convert

Explanation:

A proposed structure for the molecule with the molecular formula [tex]C_{9}H_{12}[/tex] , given the spectroscopic data, is 1-methyl-3-propylbenzene.

To propose a structure for a molecule with the molecular formula [tex]C_{9}H_{12}[/tex] and corresponding to the given spectroscopic data, we can follow these steps:

1. Analyze the 1H NMR data:
  - d 6.78 (s, 1H) indicates a single hydrogen on an aromatic or unsaturated carbon.
  - d 2.26 (s, 3H) suggests a methyl group (-CH3).

2. Analyze the 13C NMR data:
  - d 137.7 (no peak in DEPT-135 or DEPT-90) corresponds to a quaternary carbon (no hydrogens attached).
  - d 127.0 (up peaks in both DEPT-135 and DEPT-90) indicates a carbon with one hydrogen attached.
  - d 21.2 (up peak in DEPT-135, no peak in DEPT-90) signifies a methyl carbon.

3. Combine the information:
  - From the 1H NMR, we have one aromatic/unsaturated hydrogen and one methyl group.
  - From the 13C NMR, we have one quaternary carbon, one carbon with a single hydrogen, and one methyl carbon.

4. Propose a structure:
  - The molecule has nine carbons, so it could be an aromatic compound with a six-carbon ring (benzene-like) and three additional carbons.
  - The quaternary carbon could be part of the aromatic ring, and the carbon with a single hydrogen could be connected to the ring and the methyl group.
  - Based on this information, a possible structure is 1-methyl-3-propylbenzene.

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Net ionic equation for the reaction that occurs between aqueous solutions of potassium phosphate and aluminum chloride is Al3+(aq.) + PO43–(aq.) → AlPO4(s). So, option (b) is correct.

The net ionic equation is defined as the chemical equation that shows only those elements, compounds, and ions that are directly involved in the chemical reaction. Aqueous potassium phosphate reacts with aqueous aluminum chloride to form aqueous potassium chloride and solid aluminum phosphate. The balanced equation of the reaction between aqueous aluminum chloride and potassium phosphate to form aqueous potassium chloride and solid aluminum phosphate is,

K3PO4(aq.) + AlCl3(aq.) ---> 3 KCL (aq.) + AlPO4(s)

Net ionic equations must be balanced by both mass and charge that means we have to ensure that there are equal masses of each element on the product and reactant sides. Balancing the equation by charge means making sure that the overall charge is the same on both sides of the equation. Balancing the molecular equation properly the net ionic equation will end up being balanced by both mass and charge of the equation.

Al3+(aq.) + PO43–(aq.) → AlPO4(s)

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The equilibrium expression for the reaction 2Na₂O (s) ⇌ 4Na (l) + O₂ (g) is K = [Na]⁴[O₂].

The equilibrium expression expresses the ratio of the concentrations of the products to the concentrations of the reactants at equilibrium. In this case, the balanced chemical equation for the reaction is 2Na₂O (s) ⇌ 4Na (l) + O₂ (g).

The equilibrium constant (K) is defined as the product of the concentrations of the products, each raised to the power of its stoichiometric coefficient, divided by the product of the concentrations of the reactants, each raised to the power of its stoichiometric coefficient. Based on the balanced equation, the equilibrium expression can be written as K = [Na]⁴[O₂].

It is important to note that the concentrations used in the equilibrium expression are always in the units of molarity (mol/L). Also, the equilibrium constant is temperature-dependent, meaning that it can change with changes in temperature, but remains constant at a particular temperature.

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The compound least soluble in water would be Option C, CH3CH2CH2CH2CH2CH2NH2. When an ionic compound is added to water, it splits into cations and anions, which are surrounded by water molecules. When a solute dissolves in a solvent, the solvent's molecules surround the solute's molecules.

The solubility of compounds varies widely depending on their chemical structure. A compound with polar bonds is typically more soluble in polar solvents like water, while a compound with nonpolar bonds is typically more soluble in nonpolar solvents like oil.

Here are the options and their solubility characteristics:

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The mass of hydrogen reacted with 4.1 moles of ammonia ([tex]NH_3[/tex]) is 24.6g in the given reaction.

Given the number of moles of ammonia ([tex]NH_3[/tex]) = 4.1

The reaction is as follows: [tex]3H_2 + N_2 -- > 2NH_3[/tex]

From the equation we can see that for 3 moles of hydrogen ([tex]H_2[/tex]) 2 moles of ammonia ([tex]NH_3[/tex]) is produced.

mass of hydrogen reacted = number of moles x molar mass of [tex]H_2[/tex]

mass of hydrogen reacted = 3 * 2 = 6g

mass of [tex]NH_3[/tex] used up = moles x molar of [tex]NH_3[/tex]

mass of ammonia = 2 * 17 = 34g

So for 6g of [tex]H_2[/tex], 34g of ammonia ([tex]NH_3[/tex]) is used.

mass of ammonia reacted with 4.1moles = 4.1 * 34 = 139.4g

Then for 139.4g of [tex]NH_3[/tex] amount of hydrogen needed = 139.4 * 6/34 = 24.6g

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Based on the calculations, n-pentane has a larger δt value than 1-butanol.

Intermolecular forces refer to the forces between molecules. In this case, the strength of the intermolecular forces in the two molecules is different, resulting in different δt values. n-pentane is a nonpolar molecule with only van der Waals forces between molecules. These forces are weak compared to the intermolecular forces present in 1-butanol.1-butanol is a polar molecule with intermolecular hydrogen bonds between molecules.

Hydrogen bonds are strong intermolecular forces that increase the boiling point of the molecule. The larger the intermolecular forces, the larger the δt value will be. Since n-pentane only has weak van der Waals forces, it has a smaller δt value than 1-butanol, which has stronger intermolecular hydrogen bonds.

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The polystyrene molecule with a molecular mass of 18,000 g/mol has approximately 173 monomer units.

A polystyrene molecule has a molar mass of 18,000 g/mol.

To calculate the number of monomer units (the degree of polymerization) for this molecule, we need to use the formula for calculating the degree of polymerization:

Degree of polymerization = (Molar mass of polymer) / (Molar mass of monomer)

For polystyrene, the monomer is styrene, which has a molar mass of 104 g/mol.

Using the above formula, we get:

Degree of polymerization = 18,000 g/mol ÷ 104 g/mol= 173.08

Therefore, the number of monomer units (the degree of polymerization) for this polystyrene molecule is approximately 173.

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Option B, the surface area of the solvent, does not affect the rate of dissolving a solid in a liquid. The rate of dissolving a solid in a liquid is affected by several factors, including temperature, the surface area of the solute, and agitation.

Increasing the temperature of the solvent typically increases the rate of dissolving because it increases the kinetic energy of the solvent molecules, allowing them to interact more effectively with the solute. Increasing the surface area of the solute by breaking it into smaller pieces also increases the rate of dissolving because it provides more surface area for the solvent to interact with. Agitation, such as stirring or shaking, increases the rate of dissolving by keeping fresh solvent in contact with the solute.

However, the surface area of the solvent itself does not affect the rate of dissolving a solid in a liquid because it is the solute that is dissolving into the solvent, not the other way around. Therefore, the surface area of the solvent is not a factor that affects the rate of dissolving.

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Rewriting the above question in a clearly manner,

"If the size of a radioactive sample is doubled, what happens to the activity of the sample in Becquerel (Bq)? Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer.

The activity of the sample ________.

The number of ________ per second ________ to the number of ________ gram(s)."

ANSWER: The activity of the sample increases.

The number of decays per second doubles to the number of atoms/gram.

Radioactive decay is the process of spontaneous decay of a nucleus into another nucleus.
In a radioactive decay, the parent nuclide disintegrates into a different daughter nuclide while emitting an alpha particle, beta particle, or gamma rays.

When radioactive decay occurs, radiation is emitted as particles or electromagnetic radiation. The amount of radioactive substance in a sample, as well as the radioactive isotopes present in it, determine the activity of a radioactive sample. This is the rate at which radiation is emitted by the sample.

In a nuclear reaction, the activity of a radioactive substance is expressed in Becquerel (Bq). This is the amount of radioactive substance that decays in one second. One Bq equals one radioactive decay per second.

In summary, if the size of a radioactive sample is doubled, the activity of the sample in Bq is also doubled.

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Answer: 68.5826%

Explanation:

Answer:249.68 g/mol

Explanation:

Answer: Fruits contain seeds and develop from the ovaries of flowering plants. The first step in making fruits is pollination. Fruit trees and plants produce flowers. Then, bees, bats, birds, and even the wind spread pollen from one flower to another.

Answer:

Fruits contain seeds and develop from the ovaries of flowering plants. The first step in making fruits is pollination. Fruit trees and plants produce flowers. Then, bees, bats, birds, and even the wind spread pollen from one flower to another.

Explanation:

The volume of the gas drops from 12.3 L to 8.20 L as the pressure rises from 40.0 mmHg to 60.0 mmHg.

To solve this problem, we can use Boyle's law, which states that the pressure and volume of a gas are inversely proportional when the temperature and the number of particles are constant. Mathematically, Boyle's law can be expressed as P₁V₁ = P₂V₂, where P₁ and V₁ are the initial pressure and volume, and P₂ and V₂ are the final pressure and volume.

Using this formula, we can calculate the final volume of the gas when the pressure is increased from 40.0 mmHg to 60.0 mmHg:

P₁V₁ = P₂V₂

(40.0 mmHg)(12.3 L) = (60.0 mmHg)(V₂)

Simplifying the equation, we get:

V₂ = (40.0 mmHg)(12.3 L) / (60.0 mmHg) = 8.20 L

Therefore, when the pressure is increased from 40.0 mmHg to 60.0 mmHg, the volume of the gas decreases from 12.3 L to 8.20 L, assuming the temperature and the number of particles remain constant.

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Molecules will move from an area of higher concentration to an area of lower concentration in order to establish equilibrium through passive transport. This is due to diffusion, which is the process in which molecules spread out from areas of high concentration to areas of low concentration.

The way molecules move to establish equilibrium using passive transport is from high concentration to low concentration. Passive transport is the movement of molecules across the cell membrane without requiring the expenditure of energy.Passive transport includes diffusion, osmosis, and facilitated diffusion. Diffusion is the movement of molecules from an area of high concentration to an area of low concentration.

Osmosis is the diffusion of water molecules across a selectively permeable membrane. Facilitated diffusion is the movement of molecules across the cell membrane with the aid of carrier proteins or channel proteins.Passive transport ensures that the molecules are transported in the correct direction for equilibrium to be reached. Equilibrium is reached when there is no net movement of molecules across the cell membrane.

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The density of materials is influenced by the arrangement of their molecules and how well they can pack together. HDPE and LDPE have the same chemical composition, but their densities differ due to differences in their molecular structure.

HDPE has a more linear structure with fewer branches, while LDPE has a more branched structure with more branches. This branching reduces the ability of LDPE molecules to pack together as tightly as HDPE molecules, leading to a lower density for LDPE.

The density of a material can also influence its properties. HDPE, with its higher density, is generally stronger and more rigid than LDPE. It is also less flexible than LDPE, which can bend and deform more easily due to the branching in its molecular structure. LDPE, on the other hand, has better impact resistance than HDPE, meaning it can absorb more energy before breaking.

In addition, HDPE is more resistant to chemicals and has better temperature resistance than LDPE. However, LDPE is more resistant to stress cracking and is more easily processed due to its lower melting point.

In summary, the density of a material is influenced by its molecular structure and packing ability, which can in turn affect its strength, flexibility, and other material properties. HDPE and LDPE, despite having the same chemical composition, have different densities and properties due to differences in their molecular structures.

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When 259 ml of a 0.860 M NaCl solution is mixed with 552 ml of a 0.350 M NaCl solution, the concentration of NaCl will be 0.496 M.

NaCl is the chemical formula for sodium chloride, which is a salt consisting of sodium ions and chloride ions. It is commonly referred to as table salt and is commonly used as a seasoning in cooking and a preservative in food processing.

Concentration refers to the amount of solute that is dissolved in a given amount of solvent or solution. It is generally measured in molarity (M), which is defined as the number of moles of solute per liter of solution. The equation for calculating molarity is as follows:

Steps to find out the NaCl concentration:

Given that 259 ml of a 0.860 M NaCl solution is mixed with 552 ml of a 0.350 M NaCl solution.

First, find the moles of NaCl in the first solution (259 ml of 0.860 M NaCl).

0.860 M means there are 0.860 moles of NaCl for every liter of solution.

In 259 ml (0.259 L) of this solution, there will be:

moles of NaCl = 0.860 M × 0.259 L = 0.22294 mol NaCl

Next, find the moles of NaCl in the second solution (552 ml of 0.350 M NaCl).

0.350 M means there are 0.350 moles of NaCl for every liter of solution.

In 552 ml (0.552 L) of this solution, there will be:

moles of NaCl = 0.350 M × 0.552 L = 0.1932 mol NaCl

Total moles of NaCl in the final solution = 0.22294 mol + 0.1932 mol = 0.41614 mol NaCl

Finally, calculate the molarity of the final solution (which is the concentration of NaCl):

Molarity = moles of NaCl / liters of solutionThe total volume of the final solution is 259 ml + 552 ml = 811 ml or 0.811 L.

Molarity = 0.41614 mol / 0.811 L = 0.513 M NaCl

Therefore, when 259 ml of a 0.860 M NaCl solution is mixed with 552 ml of a 0.350 M NaCl solution, the concentration of NaCl will be 0.496 M.

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A fuel cell is an electrochemical device that converts chemical energy from a fuel (such as hydrogen) and an oxidizing agent (such as oxygen) into electrical energy, water, and heat.

What is Fuel?

Fuel is a material that is burned or processed to release energy in the form of heat or to produce work. Common examples of fuel include coal, natural gas, gasoline, diesel, and wood. The energy contained within the fuel is released through a chemical reaction, usually with oxygen, to produce heat, light, or other forms of energy. Fuel is used to power a wide range of machinery and devices, including vehicles, power plants, and heating systems.

The reactants (fuel and oxidizing agent) are supplied to the cell, where they undergo a chemical reaction in the presence of a catalyst, producing electricity and the byproduct water.

According to the law of conservation of mass, mass cannot be created or destroyed in a chemical reaction. In the case of a fuel cell, the mass of the reactants (fuel and oxidizing agent) is equal to the mass of the products (water) plus the mass of the electricity produced

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1.Balance: NaCl(s) → NaCl(aq)

2.This is a physical change because only the state of the substance changes from solid to aqueous, without any chemical reaction taking place.

The law of conservation of mass states that in a closed system, the total mass of the system remains constant, regardless of any physical or chemical changes that take place.

3.Balanced equation: Na₂CO₃(aq) + CaCl₂(aq) → 2NaCl(aq) + CaCO₃(s). The state of the products are NaCl(aq) and CaCO₃(s).

4.This is a chemical change because a chemical reaction takes place, resulting in the formation of new substances with different properties.

5.When a new product is formed in a chemical reaction, the reacting atoms rearrange their bonds to form new molecules. Bonds between atoms are broken and new bonds are formed, resulting in the formation of new molecules with different properties. The conservation of atoms is maintained as the number of atoms of each element in the reactants must be equal to the number of atoms of each element in the products.

6.Balanced equation: Na₂CO₃(aq) + 2HC₂H₃O₂(aq) → 2NaC₂H₃O₂(aq) + H₂O(l) + CO₂(g). The state of the products are NaC₂H₃O₂(aq), H₂O(l), and CO₂(g).

7. In each experiment, the mass was conserved because the total mass of the reactants was equal to the total mass of the products. Therefore, mass was neither created nor destroyed during the reactions.

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Answer:

Only one, so option c

Explanation:

Because monoprotic as it says, had only one proton to lose giving it only one pka for example Hydrochloric Acid (H-Cl). unlike a diprotic acid which would have two pkas like carbonic acid for example (H2CO3).

Answer:

To answer this question, we first need to write the balanced chemical equation for the reaction between sodium carbonate and calcium chloride:

Na2CO3 + CaCl2 → 2NaCl + CaCO3

From the equation, we see that 1 mole of sodium carbonate reacts with 1 mole of calcium chloride to produce 1 mole of calcium carbonate and 2 moles of sodium chloride.

Therefore, since we have an excess amount of calcium chloride, we can assume that all 5.32 moles of sodium carbonate react completely to produce 10.64 moles of sodium chloride.

So the answer is: 10.64 moles of salt (sodium chloride) are produced.

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Sodium chloride is the strongest electrolyte among the following examples. Hence, option C is correct.

Generally, strong electrolytes are defined as those electrolytes which completely ionizes into an aqueous solution.

Generally, strong acids and strong bases are considered to be strong electrolytes. Basically, sodium chloride (NaCl) is a salt which is formed from HCl, a strong acid, and a strong base, Sodium hydroxide (NaOH). Since it completely ionizes into Sodium ion (Na⁺) and Cl⁻ ion in solution, it is generally considered to be a strong electrolyte.

NaCl (aq) → Na⁺ (aq) + Cl⁻ (aq)

Hence, sodium chloride is strongest base. Option C is correct.

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When a solution containing strontium ions ([tex]Sr^{2+}[/tex]) is added to the Bunsen burner flame, it changes the color to red. Therefore, the answer is option A, red.

A Bunsen burner is a laboratory equipment that produces a single open gas flame, which is used for heating, sterilization, and combustion reactions. A Bunsen burner produces a clean blue flame when it is set to the right mixture of air and gas.

The color of a Bunsen burner flame is determined by the temperature of the flame and the chemicals being burned. The addition of chemicals to a Bunsen burner flame can cause it to change color.

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The correct order of the reaction and  proper units are:

The units for the rate constant (k) is depend on the order  reaction. For the zero order reaction,  units of the k are the concentration/time, and which is the usually expressed as the moles per liter per second that is mol/L s or the  per second (s⁻¹).

For the first order reaction, the units for the k is mol per second (mols⁻¹) and the second order reaction has the unit for the rate constant is M⁻² s⁻¹. The third order reaction has the unit for the rate constant is M⁻¹ s⁻¹.

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