Which of the following are true statements about a 30-60-90 triangle?
Check all that apply.
A. The hypotenuse is 3 times as long as the longer leg.
B. The hypotenuse is twice as long as the longer leg.
C. The longer leg is twice as long as the shorter leg.
D. The longer leg is 3 times as long as the shorter leg.
E. The hypotenuse is twice as long as the shorter leg.
F. The hypotenuse is 3 times as long as the shorter leg.

We need to sum at least one term to ensure that the remainder is less than[tex]10^{-6[/tex].

We know that the alternating series test states that if a series is alternating and its terms are decreasing in absolute value, then the series converges. We can see that the series ∑[infinity]k=1(−1)kk4 is an alternating series because the signs of the terms alternate, and the terms decrease in absolute value because [tex]k_4[/tex] > (k+1)4 for all k.

Now, we can use the remainder formula for an alternating series, which tells us that the remainder Rn of an alternating series ∑[infinity]k=1(−1)ka_k after n terms is less than or equal to the absolute value of the next term [tex]a_{n+1[/tex]:

|Rn| ≤ |[tex]a_{n+1[/tex]|

So, we want to find the smallest value of n such that |a_n+1| < 10^(-6). We have:

[tex]a_k = (-1)^k \times k^4[/tex]

[tex]a_{n+1} = (-1)^{(n+1)} \times(n+1)^4[/tex]

We want to find n such that:

[tex]|(n+1)^4| < 10^{(-6)[/tex]

Taking the fourth root of both sides, we get:

[tex]|n+1| < (10^(-6))^(1/4)[/tex]

|n+1| < 0.1

n+1 < 0.1 or -(n+1) < 0.1

n < 0.1 - 1 or n > -0.1 - 1

n < -0.9 or n > -1.1

Since n must be a positive integer, the smallest possible value of n that satisfies this inequality is n = 1. Therefore, we need to sum at least one term to ensure that the remainder is less than [tex]10^{(-6)[/tex].

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To calculate the total cost including tax for Noah's video game, we need to add the cost of the game to the sales tax.

Sales tax on Noah's game = 6.5% of $27.99 = $1.82

Total cost for Noah's game = $27.99 + $1.82 = $29.81

Similarly, for Matt's game:

Sales tax on Matt's game = 6.5% of $21.99 = $1.43

Total cost for Matt's game = $21.99 + $1.43 = $23.42

Therefore, Noah will have to pay $29.81 and Matt will have to pay $23.42 including tax.

Answer:

cos65°= x/11

cos65° × 11=x

4.65=x

Answer:

Step-by-step explanation:

You want to know suitable equations that can be solved for x given that AC=x, AB=11, and ∆ABC is a right triangle with angle A=25° and C=90°.

The mnemonic SOH CAH TOA reminds you that ...

  Sin = Opposite/Hypotenuse

  Cos = Adjacent/Hypotenuse

The side marked 11 is the hypotenuse, and the side marked x is adjacent to the 25° angle and opposite angle B. We can find the measure of angle B as the complement of angle A:

  ∠B = 90° -25° = 65°

The cosine relation is ...

  cos(A) = AC/AB

  cos(25°) = x/11

The sine relation is ...

  sin(B) = AC/AB

  sin(65°) = x/11

These are equations you can solve to find x.

The volume of the treasure chest is approximately 1.3153 [tex]m^{3}[/tex]

A three-dimensional object's volume is determined by the amount of space it occupies. It is a scalar quantity that can be expressed in cubic metres (m³), cubic feet (ft³), litres (L), gallon (gal), or any other volume unit.

Before dividing the value by the length of the treasure chest to determine its volume, the area of the treasure chest's bottom section must be determined.

A semicircle and a rectangle form the cross section. Let's calculate each of their areas separately, then add them all together:

Area of rectangle EY:

height   = 0.6m

breadth = 0.8m

area = height x breadth

       = 0.6 x 0.8  

       = 0.48[tex]m^{2}[/tex]

Area of a semicircle:

radius = half of the breadth

= 0.8 / 2

= 0.4m

area = 1/2 x [tex]\pi[/tex] x radius²  (since it's a semicircle)

= 1/2 x [tex]\pi[/tex] x [tex]0.4^{2}[/tex]

= 0.2513 [tex]m^{2}[/tex]

The total area of the crοss-sectiοn

=0.48 + 0.2513

= 0.7313[tex]m^{2}[/tex]

Nοw, we can find the volume οf the treasure chest by multiplying the crοss-sectiοnal area by its length:

volume = area x length

 = 0.7313[tex]m^{2}[/tex] x 1.8[tex]m[/tex]

 = 1.3153 [tex]m^{3[/tex]

Therefore, the volume of the treasure chest is apprοximately 1.3153[tex]m^{3}[/tex]

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Todd can afford to pay 390 per month for the next 7 years in order to purchase a new car. the interest rate is 6.8 percent compounded monthly. The value of the most Todd can afford to pay for a new car today is 24,708.07. The correct option is d. 24,708.07.

To calculate this, we can use the present value formula for a monthly compounded loan:

[tex]PV = PMT \times ((1 - (1 + r/n)^(-nt))/(r/n)),[/tex]

where PV is the present value or the amount that Todd can afford to pay for a new car today PMT is the monthly payment (390) n is the number of times the interest is compounded in a year (12 for monthly) r is the annual interest rate (6.8%) t is the total number of years (7)

Now, we can substitute the values and solve for PV:

[tex]PV = 390 \times ((1 - (1 + 0.068/12)^(-12\times7))/(0.068/12))

            = 24,708.07[/tex]

Therefore, Todd can afford to pay 24,708.07 for a new car today.

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last choice

x² needs to be represented

so you have to put a 0 there

6x³+ 0x² -4x +5

7x - 1

In the given any letter should get drawn 250 times and the letter is the experimental probability closest to the theoretical probability is N.

What is probability?

Probability is a way of calculating how likely something is to happen. It is difficult to provide a complete prediction for many events. Using it, we can only forecast the probability, or likelihood, of an event occurring. The probability might be between 0 and 1, where 0 denotes an impossibility and 1 denotes a certainty.

Theoretically, each letter should have the same probability of occurring since there are 15 of each. There are 5 letters that can be drawn, so there is a total of 75 balls, and each letter has a probability is ,

=> [tex]\frac{15}{75}= \frac{1}{5}[/tex] of being drawn.

This means one would expect a theoretical frequency of

=> [tex]\frac{1250}{5}= 250[/tex]

Hence  any given letter should get drawn 250 times and the letter is the experimental probability closest to the theoretical probability is N.

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The IBM computer can compute about 6 trillion (6 x 1012) multiplications per second

The IBM computer can perform around 6 trillion multiplications per second, making it one of the fastest computers in the world. Multiplication is a fundamental arithmetic operation that is used to calculate the total value when two or more numbers are combined.

Multiplication is used to calculate the total number of things when there are several equal groups. For example, 2 x 5 = 10 means that there are 10 items in two groups, each containing five items. The symbol "x" represents the multiplication operation.

The IBM computer can compute about 6 trillion (6 x 1012) multiplications per second. IBM's Summit computer, which is currently the world's most powerful computer, has a peak speed of 200 petaflops, or 200 quadrillion (2 x 1017) calculations per second. This makes it one of the fastest computers in the world.

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Answer:

Step-by-step explanation:

Step-by-step explanation:

We know that diagonals of a rhombus perpendicularly bisect each other.

Therefore

Let side of rhombus be 'a' , then

[tex] {a}^{2} =( \frac{d1}{2} )^{2} + ( \frac{d2}{2} ) + = \frac{12}{2}^{2} + ( \frac{6}{2}) ^{2} = 36 + 9 \\ \\ a ^{2} = 45 = a = \sqrt[3]{5} [/tex]

0.25

Explanation:

The easiest way to answer this question is to recognize that a uniform probability distribution is essentially a rectangle with an area equal to 1.

Now find the area of a portion of this rectangle.

[tex]\dfrac{51-5.05}{52-50} =\dfrac{0.5}{2} =0.25[/tex]

Answer: 47%

Step-by-step explanation:

When you divide 7 out of 15 you get .4666666. But rounding to the percent you get 47%.

Answer:

6 meters per second

Step-by-step explanation:

6 meters/ seconds

Step 1: Find the unit rate

total distance/total time

54/9

6 meters / seconds

Answer: 6 meters/ seconds

Answer: To solve this problem, first multiply 3.2 calories by 40 minutes to find the total number of calories she burns in one half:

3.2 calories/minute x 40 minutes = 128 calories

Erin burns 128 calories while playing flag football during one 40 minute half.

The probability that a card drawn randomly from a standard deck of 52 cards is a red queen = 0.038

We know that the formula for the probability of an event is given by,

P = number of favourable outcomes / total number of possible outcomes of an event

Let us assume that event A : drawing a red queen card

Here, sample space is a standard deck of 52 cards.

So, n(S) = 52

We know that there are 2 queens of red color (red heart and red diamond)

So, n(A) = 2

Using probability formula,

P(A) = n(A) / n(S)

P(A) = 2/52

P(A) =  0.038

Therefore, the required probability is 0.038

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By answering the presented questiοn, we may cοnclude that, the equatiοn lengths that are equal tο 6 feet 12 inches are: 7 ft and 2 yd 1 ft.

Thus, option b and d are correct.

In mathematics, an equatiοn is a claim that twο expressiοns are equivalent. Twο sides that are separated by the algebraic symbοl (=) make up an equatiοn. As an illustratiοn, the claim "2x + 3 = 9" makes the claim that the cοmbinatiοn "2x + 3" equals the integer "9".

Finding the value οr values οf the variable(s) necessary fοr the equatiοn tο be true is the gοal οf equatiοn sοlving. Equatiοns can include οne οr mοre parts and be straightfοrward οr cοmplex, regular οr nοnlinear. Fοr example, the variable x is raised tο the secοnd pοwer in the equatiοn "x² + 2x - 3 = 0." In many different branches οf mathematics, including algebra, calculus, and geοmetry, lines are used.

6 feet 12 inches can be simplified tο 7 feet.

Sο, the lengths that are equal tο 6 feet 12 inches are: 7 ft

Also 7 ft is equal to  2yd 1ft

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The two-column proofs of the segments are shown below

The proof is as follows

Statement                                                      Reason

ABCD and BCDE are parallelogram            Given

AG = BC                                                         Opposite sides of

                                                                       parallelogram            

ED = BC                                                         Opposite sides of

                                                                       parallelogram            

AG ≅ ED                                                         Substitution property (proved)

Proving that KLMN is a parallelogram

The proof is as follows

Statement                                                Reason

KL || NM  and ∠L ≅ ∠N                            Given

KN ≅ LM                                                   CPCTC

KL ≅ NM                                                   CPCTC

We've proved that the opposites sides are equal and parallel

So, KLMN is a parallelogram

Proving that STUV is a parallelogram

The proof is as follows

Statement                                                Reason

ST || VU  and W is midpoint of SU          Given

SW = UW                                                   Definition of midpoint

VW = TW                                                   Definition of midpoint

VU = ST                                                     CPCTC

VS = UT                                                     CPCTC

We've proved that the opposites sides are equal and parallel

So, STUV is a parallelogram

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First transformation: Reflection across the y-axis

Second transformation: Vertical translation down by 12 units.

A coordinate is a value that specifies the position of a point in a particular system or framework of reference. Coordinates are typically expressed as numerical values that describe the location of a point in relation to some predefined origin, axis, or set of reference points. The most common type of coordinate system is the Cartesian coordinate system, which uses two or three axes to describe points in a plane or in three-dimensional space, respectively. In this system, coordinates are typically expressed as ordered pairs (for two-dimensional points) or ordered triplets (for three-dimensional points), such as (x, y) or (x, y, z), where x, y, and z represent the distances along each axis from the origin. Other types of coordinate systems include polar coordinates, cylindrical coordinates, and spherical coordinates, which are used in various branches of mathematics and science to describe points in different contexts.

To find the two transformations, we can use the fact that applying multiple transformations to a figure is the same as applying a single transformation that is the composition of the individual transformations.

Let's start with the final vertices of the transformed figure: (-2,0), (2, 0), (2,-6), and (0,-2).

We can see that the first two vertices have the same x-coordinate and are located on the x-axis. This suggests a reflection across the y-axis, which would swap the x-coordinates of the vertices.

So, the first transformation is a reflection across the y-axis.

After this transformation, the transformed figure has vertices (-WXYZ).

Next, we need to find the second transformation that maps WXYZ to (-WXYZ) with the given final vertices.

We can see that the vertex (2,-6) has a lower y-coordinate than the other three vertices. This suggests a vertical translation that moves this vertex down to its final position.

To determine the amount of vertical translation, we can subtract the y-coordinate of the vertex in its initial position (6) from the y-coordinate of the vertex in its final position (-6), which gives a total downward movement of 12 units.

So, the second transformation is a vertical translation down by 12 units.

Therefore, the two transformations that Nelson applies to WXYZ are a reflection across the y-axis followed by a vertical translation down by 12 units.

First transformation: Reflection across the y-axis

Second transformation: Vertical translation down by 12 units.

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The οnly sοlutiοn is sinθ = 0, θ = kπ, where k is any integer.

Trigοnοmetric functiοns are mathematical functiοns that relate tο the angles and sides οf a right-angled triangle.  These functiοns can be used tο calculate the relatiοnships between the sides and angles οf a triangle.

1a) Using inverse tangent functiοn,

θ = tan^{-1}(-2/3) ≈ -0.93 + kπ οr 2.21 + kπ, where k is any integer.

1b) Using cοsine functiοn,

[tex]2cos^{2}\theta - 1 = 0[/tex]

[tex]cos^{2}\theta= 1/2[/tex]

cοsθ = ±√(1/2) = ±1/√2

Sο, θ = π/4 + kπ/2 οr 3π/4 + kπ/2, where k is any integer.

1c) Rearranging the equatiοn, we get

[tex]sin^{2}\theta - 6sin\theta- 7 = 0[/tex]

Using the quadratic fοrmula,

sinθ = [6 ± √(36 + 28)]/2 = 3 ± √19

Since -1 ≤ sinθ ≤ 1, the οnly sοlutiοn is

sinθ = 3 - √19

[tex]θ = sin^{(-1)(3 - \sqrt{19})} \approx 0.47 + 2k\pi[/tex] οr π - 0.47 + 2kπ, where k is any integer.

1d) Factοring οut sinθ frοm the equatiοn, we get

sinθ(cοsθ - 7) = 0

Sο, either sinθ = 0 οr cοsθ = 7. Since -1 ≤ sinθ, cοsθ ≤ 1, the οnly sοlutiοn is

cοsθ = 7 has nο real sοlutiοn, sο the οnly sοlutiοn is

sinθ = 0

θ = kπ, where k is any integer.

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Answer:

Step-by-step explanation: ???

Answer:

proofs attached to answer

Step-by-step explanation:

proofs attached to answer

Answer:

A **cone** and a **cylinder** each have 1 curved face.

The property that justifies that action - A. Action: Add 3 to both sides, D. Property: Addition property of equality.

The addition property of equality is a fundamental property of algebra which states that if the same value is added to both sides of an equation, the equality is still maintained. In other words, if a = b, then a + c = b + c for any value of c. This property is useful when we want to isolate a variable on one side of an equation, by adding or subtracting the same value from both sides until the variable is isolated.

To solve x - 3 = 12, we can use the addition property of equality, which says that if we add the same value to both sides of an equation, the two sides remain equal.

Starting with x - 3 = 12, we can add 3 to both sides to isolate the variable x:

x - 3 + 3 = 12 + 3

x = 15

Therefore, the solution to the equation x - 3 = 12 is x = 15.

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a) An absolute value equation that could be used to determine the maximum and minimum value of h, the height of the machine part, is: | h - 13.15 | ≤ 0.07

b) The minimum value the machine part could be is: 13.08 mm

c) The maximum value the machine part could be is: 13.22 mm

An absolute value equation that could be used to determine the maximum and minimum value of h, the height of the machine part, is

| h - 13.15 | ≤ 0.07

The minimum value the machine part could be is

13.15 - 0.07 = 13.08 mm

The maximum value the machine part could be is

13.15 + 0.07 = 13.22 mm

The absolute value equation represents the range of acceptable values for the height of the machine part, which is within 0.07 mm of the target height of 13.15 mm.

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The probability mass function (pmf) of the random variable x is:

Question 1: The chance a 1-km segment of railroad track contains a defect is 0.01. Assume the 1-km segments of track are independent. a. Compute the probability that exactly 125 km of track need to be tested before a defect is found. b. On average, how many 1-km segments of railroad track have to be tested before a defect is found?

Answer 1: a. The probability that exactly 125 km of track need to be tested before a defect is found is 0.000148. b. On average, 125.01 1-km segments of railroad track need to be tested before a defect is found.

Question 2: A geotechnical engineering company conducted a study that indicates there is a 20% chance a borehole in a certain neighborhood will find a layer of clay no more than 20 m deep. a. Compute the probability that the third layer of clay within 20 m is found on the seventh borehole drilled. b. Compute the mean and variance of the number of boreholes that must be drilled if the geotechnical engineering company wants to have three that find clay within 20 m.

Answer 2: a. The probability that the third layer of clay within 20 m is found on the seventh borehole drilled is 0.02. b. The mean and variance of the number of boreholes that must be drilled if the geotechnical engineering company wants to have three that find clay within 20 m are 15 and 75 respectively.

Question 3: Dam failures are rare and are estimated to occur on average once every five years. a. Compute the probability there will be at least one dam failure in the next 10 years. b. Draw a pmf that describes the random variable x.

Answer 3: a. The probability that there will be at least one dam failure in the next 10 years is 0.8187. b. The probability mass function (pmf) of the random variable x is:

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Rounding the amount to the nearest dollar, we get $10.00 as the estimated tip amount.

In general, "amount" refers to a quantity or a sum of something. The specific context in which the term is used determines the meaning of the word more precisely.

In financial contexts, "amount" typically refers to a sum of money or other financial value, such as the amount of a payment, a loan, or an investment. In accounting, the amount may refer to the total value of assets, liabilities, or equity.

In scientific contexts, "amount" may refer to the quantity or volume of a substance or material, such as the amount of water in a solution, the amount of gas in a container, or the amount of a drug in a patient's bloodstream.

In general usage, "amount" can refer to a quantity of something that can be measured, counted, or expressed numerically, such as the amount of time spent on a task, the amount of food consumed, or the amount of work completed

$10.00.

Rounding the bill amount to the nearest dollar, we get $48. The 20% tip on $48 is $9.60. Rounding this amount to the nearest dollar, we get $10.00 as the estimated tip amount.

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The total area that Leo plans to cover with gold leaf is 4*30.95 = 123.8 ft2. Leo plans to cover 61% of the area of the stand with gold leaf.

A right trapezoidal prism is a three-dimensional solid with two parallel trapezoidal bases and rectangular lateral sides. The trapezoidal prism's bases are not perpendicular to its lateral sides, but rather slanted. A right trapezoidal prism is referred to as "right" if its lateral edges are perpendicular to its bases.

(a) Area of trapezoid = (a + b)/2 * h = 40

9a + 9b = 80

a + b = 80/9

Now, let the height of the trapezoid be h1, and the length of the shorter side be h2. Then we have:

[tex]h1^2 = (9/2)^2 + h2^2[/tex]

h2 = [tex]\sqrt{(h1^2 - (9/2)^2)}[/tex]

Finally, we can find the perimeter P of the base by adding up the lengths of all four sides:

P = a + b + 2*[tex]\sqrt{((a-b)/2)^2 + h2^2)}[/tex]

Now we can find the length of roping needed:

Length of roping = 4P = 4(a + b + 2*[tex]\sqrt{((a-b)/2)^2 + h2^2}[/tex])

Substituting a + b = 80/9 and h2 from above, we get:

Length of roping = 4(80/9 + 2[tex]\sqrt{((a-b)/2)^2}[/tex] + [tex]\sqrt{(h1^2 - (9/2)^2))}[/tex]

Length of roping = (320/9) + 8[tex]\sqrt{((a-b)/2)^2}[/tex] + 4*[tex]\sqrt{(h1^2 - (9/2)^2)}[/tex]

Length of roping = 37.14 ft

Therefore, Leo purchases 37.14 feet of roping.

(b) The total surface area of the stand is 203.8 [tex]ft^2[/tex]. The area of both bases combined is 2*40 = 80 [tex]ft^2[/tex]. Therefore, the area of the sides of the stand is:

203.8 - 80 = 123.8 [tex]ft^2[/tex]

The stand has four side faces, so the area of one face is:

123.8 / 4 = 30.95 [tex]ft^2[/tex]

The total area that Leo plans to cover with gold leaf is the sum of the areas of all four side faces, which is:

4*30.95 = 123.8 [tex]ft^2[/tex]

Therefore, the percent of the area of the stand that will have gold leaf is:

(123.8 / 203.8) * 100 = 60.73%

Rounding to the nearest whole number, Leo plans to cover 61% of the area of the stand with gold leaf.

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the zeros of the quadratic equation are approximately:-x ≈ -0.53 and x ≈ 1.03

What is quadratic equation ?

In algebra, a quadratic equation is a polynomial equation of degree 2. It is an equation in which the highest power of the variable is 2. The general form of a quadratic equation is:

ax² + bx + c = 0

where a, b, and c are constants, and x is the variable.

Quadratic equations can have one, two, or zero real solutions, depending on the values of a, b, and c. The solutions of a quadratic equation can be found using the quadratic formula:

x = (-b ± sqrt(b² - 4ac)) / 2a

or by factoring the quadratic expression into two linear factors, and then solving for x. The quadratic formula works for all quadratic equations, while factoring can only be used for some quadratic equations that have integer roots.

To locate the zero of a quadratic equation given the values of x and y, we can set the equation equal to zero and solve for x. Since the given data consists of x and y values, we can use the method of interpolation to find the quadratic equation that passes through these points. To do this, we can use the formula for the quadratic function:

f(x) = ax² + bx + c

where a, b, and c are constants that we need to find. We can use the given data to form a system of three equations:

14 = a(-1)² + b(-1) + c

2 = a(0)² + b(0) + c

-3 = a(1)² + b(1) + c

Simplifying each equation, we get:

a - b + c = 14

c = 2

a + b + c = -3

Substituting c = 2 into the first and third equations, we get:

a - b + 2 = 14

a + b + 2 = -3

Solving for a and b, we get:

a = -8

b = -13

Therefore, the quadratic function that passes through the given points is:

f(x) = -8x² - 13x + 2

To find the zero of this quadratic equation, we can set it equal to zero and solve for x:

-8x² - 13x + 2 = 0

Using the quadratic formula, we get:

x = (-(-13) ± sqrt((-13)² - 4(-8)(2))) / (2(-8))

Simplifying, we get:

x = (13 ± sqrt(249)) / 16

Therefore, the zeros of the quadratic equation are approximately:

x ≈ -0.53 and x ≈ 1.03

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Answer:

you are correct but it may want it unrounded in which case it would be 21.6333076528

The total probability that red card from a deck of 52 cards and 4 on dice will come: P(R and 4) = 1/12.

A fundamental statistician's rule governing conditional and margin probabilities is the total probability rule, commonly known as the rule of total probability.

According to the rule, if the chance of a happening is unknown, its probability may be determined using the probabilities of numerous different occurrences that have already occurred.

For the given question:

Probability of drawing a red card say P(R) = 1/2.

Probability of throwing 4 on dice P(4) = 1/6.

Thus, total probability that red card and 4 on dice will come:

P(R and 4) = P(R)* P(4)

P(R and 4) = 1/2 * 1/6

P(R and 4) = 1/12

Thus,  total probability that red card from a deck of 52 cards and 4 on dice will come: P(R and 4) = 1/12.

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