Which of the following groups listed below is a subset of the whole numbers?

Rational Numbers

Real Numbers

Natural Numbers

Irrational Numbers

Integers

The pairs of cities that will not put Jenny back under budget if she drops them are:

a. Moscow and Chelyabinsk

b. Izhevsk and Nizhny Novgorod

To determine which pair of cities Jenny can drop without going over budget, we need to find the total cost of each pair and see if it exceeds her budget of rub 33,000.

a. Moscow and Chelyabinsk:

Total cost = 5,485 + 5,217 = 10,702 rubles

This pair of cities is over budget, so Jenny cannot drop any other cities if she wants to visit both Moscow and Chelyabinsk.

b. Izhevsk and Nizhny Novgorod:

Total cost = 4,721 + 6,920 = 11,641 rubles

This pair of cities is over budget, so Jenny cannot drop any other cities if she wants to visit both Izhevsk and Nizhny Novgorod.

c. Novosibirsk and Saint Petersburg:

Total cost = 4,870 + 5,960 = 10,830 rubles

This pair of cities is under budget, so Jenny can drop this pair without going over budget.

d. Yaroslavl and Tolyatti:

Total cost = 4,901 + 5,598 = 10,499 rubles

This pair of cities is under budget, so Jenny can drop this pair without going over budget.

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The probability of rolling two fair six-sided dice and getting a sum of 4 or higher is 11/12

To calculate the probability of rolling two fair six-sided dice and getting a sum of 4 or higher, we first need to calculate the total number of possible outcomes.

The number of possible outcomes when rolling two dice is 6 × 6 = 36, since each die has 6 possible outcomes.

Now, let's find the number of outcomes that result in a sum of 4 or higher. We can do this by listing all the possible outcomes:

Sum of 4: (1, 3), (2, 2), (3, 1) = 3 outcomes

Sum of 5: (1, 4), (2, 3), (3, 2), (4, 1) = 4 outcomes

Sum of 6: (1, 5), (2, 4), (3, 3), (4, 2), (5, 1) = 5 outcomes

Sum of 7: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1) = 6 outcomes

Sum of 8: (2, 6), (3, 5), (4, 4), (5, 3), (6, 2) = 5 outcomes

Sum of 9: (3, 6), (4, 5), (5, 4), (6, 3) = 4 outcomes

Sum of 10: (4, 6), (5, 5), (6, 4) = 3 outcomes

Sum of 11: (5, 6), (6, 5) = 2 outcomes

Sum of 12: (6, 6) = 1 outcome

Therefore, the number of outcomes that result in a sum of 4 or higher is 3 + 4 + 5 + 6 + 5 + 4 + 3 + 2 + 1 = 33.

Therefore, the probability of rolling two fair six-sided dice and getting a sum of 4 or higher is 33/36 = 11/12.

To find the probability of getting a sum of 44 or higher, we need to subtract the probability of getting a sum of 43 or lower from 1:

Sum of 2: (1, 1) = 1 outcome

Sum of 3: (1, 2), (2, 1) = 2 outcomes

Sum of 4: (1, 3), (2, 2), (3, 1) = 3 outcomes

Sum of 5: (1, 4), (2, 3), (3, 2), (4, 1) = 4 outcomes

Sum of 6: (1, 5), (2, 4), (3, 3), (4, 2), (5, 1) = 5 outcomes

Sum of 7: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1) = 6 outcomes

Sum of 8: (2, 6), (3, 5), (4, 4), (5, 3), (6, 2) = 5 outcomes

Sum of 9: (3, 6), (4, 5), (5, 4), (6, 3) = 4 outcomes

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The length should be less than or equal to 6 meters in order to have a plot with the maximum area allowed (45 square meters) when the width is 7.5 meters.

To find the length that will give a plot with the maximum area allowed, we can use the formula for the area of a rectangle:

Area = Length × Width

The width is given as 7.5 meters, and the area should not exceed 45 square meters.

Let's denote the length as L.

We want to maximize the area, so we need to find the value of L that satisfies the condition Area ≤ 45 and gives the largest possible area.

Substituting the given values into the area formula, we have:

Area = L × 7.5

Since the area should not exceed 45 square meters, we can write the inequality:

L × 7.5 ≤ 45

To find the maximum value of L, we can divide both sides of the inequality by 7.5:

L ≤ 45 / 7.5

Simplifying the right side:

L ≤ 6

Therefore, the length should be less than or equal to 6 meters in order to have a plot with the maximum area allowed (45 square meters) when the width is 7.5 meters.

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The height of the right octagonal prism is approximately 10.75 cm.

The given information states that the base of the prism is a regular octagon with each side measuring 2.3 cm, and the area of the base is 25.76 cm². Additionally, the surface area of the prism is 223.56 cm².

First, let's calculate the area of the eight lateral faces. We can do this by subtracting the base's area from the total surface area:

223.56 cm² (total surface area) - 25.76 cm² (base area) = 197.8 cm² (lateral area)

Now, we know that the lateral area is the sum of the areas of all eight rectangular faces. Each rectangle has a base of 2.3 cm (the same as the sides of the octagonal base) and a height equal to the height of the prism (h). Since there are eight faces, the combined area of these rectangles is 8 x 2.3 x h:

8 x 2.3 x h = 197.8 cm²

18.4 x h = 197.8 cm²

To find the height of the prism (h), we can divide both sides of the equation by 18.4:

h = 197.8 cm² / 18.4

h ≈ 10.75 cm

So, the height of the right octagonal prism is approximately 10.75 cm.

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The amount of cashews needed to be mixed with the peanuts so that the mixture will produce the same revenue as selling the nuts separately is 10 pounds.

To solve this problem, we need to use the equation:

$3(20) + 6x = 4(20 + x)$

where x is the number of pounds of cashews needed.

First, we simplify the equation by multiplying:

$60 + 6x = 80 + 4x$

Then we isolate x by subtracting 4x from both sides and subtracting 60 from both sides:

$2x = 20$

Finally, we solve for x by dividing both sides by 2:

$x = 10$

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Using the Perpendicular Bisector Theorem, the distance from third base to home plate is 90 feet. This means that all the bases are equidistant from home plate, which is a fundamental property of a baseball diamond.

To find the distance from third base to home plate, we need to use the Perpendicular Bisector Theorem, which states that if a point lies on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment.

First, we draw a baseball diamond with points A, B, C, and D labeled as described in the problem.

Next, we draw the line segment that joins first base (B) and third base (D), and we construct the perpendicular bisector of this segment by drawing a line through the midpoint of BD and perpendicular to BD. Let's label the point where the perpendicular bisector intersects the line that connects home plate (A) and second base (C) as E.

Since E lies on the perpendicular bisector of BD, it is equidistant from B and D. We know that first base (B) is 90 feet from home plate (A), so the distance from home plate to E must also be 90 feet. Therefore, the distance from third base (D) to home plate (A) is also 90 feet.

In conclusion, using the Perpendicular Bisector Theorem, we determined that the distance from third base to home plate is 90 feet.

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The 98% confidence interval for the mean amount of money spent per month on home maintenance by all homeowners is $58.06 to $65.94.

To construct a confidence interval for the mean amount of money spent per month on home maintenance by all homeowners, we can use the formula:

CI = [tex]\bar{X}[/tex] ± Zα/2 * (σ/√n)

where [tex]\bar{X}[/tex] is the sample mean, Zα/2 is the critical value from the standard normal distribution corresponding to the desired confidence level, σ is the population standard deviation, and n is the sample size.

In this case, we have:

[tex]\bar{X}[/tex] = $62 (the sample mean)

α = 0.02 (since we want a 98% confidence interval, which means α/2 = 0.01)

Zα/2 = 2.33 (from the standard normal distribution table)

σ = $13 (the population standard deviation)

n = 61 (the sample size)

Substituting these values into the formula, we get:

CI = $62 ± 2.33 * ($13/√61)

Simplifying this expression, we get:

CI = $62 ± $3.94

Therefore, the 98% confidence interval for the mean amount of money spent per month on home maintenance by all homeowners is $58.06 to $65.94.

This means that we can be 98% confident that the true population mean falls within this range. In other words, if we were to repeat the survey many times and construct confidence intervals in the same way, about 98% of the intervals would contain the true population mean.

It's important to note that this assumes that the sample is representative of the population, and that the population standard deviation is known. If these assumptions are not met, then the confidence interval may not be accurate.

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you got $45 for 6hours.

one hour=$7.5

two hours=$15

three hours=$7.5*3

calculation=$45/6

The answer is A. 1. We can use L'Hopital's rule to evaluate the limit:

limit x→9√(f(x))-3/√(x)-3 = limit x→9 (f(x)-9)/(x-9) / (√(f(x))-3)/(√(x)-3)

Now, we know that f(9) = 9 and f'(9) = 4, so we can use the definition of the derivative to write:

f(x) - f(9) = f'(9)(x-9) + o(x-9)

where o(x-9) represents a term that goes to 0 faster than x-9 as x approaches 9. Plugging this into the numerator, we get:

f(x) - 9 = 4(x-9) + o(x-9)

Plugging this into the denominator, we get:

√(f(x)) - 3 = √(4(x-9) + o(x-9)) = 2√(x-9) + o(1)

√(x) - 3 = √(x-9) + o(1)

Therefore, the limit becomes:

limit x→9 (4(x-9) + o(x-9))/(√(x-9) + o(1)) / (2√(x-9) + o(1))/(√(x-9) + o(1))

Simplifying this expression, we get:

limit x→9 2(4(x-9) + o(x-9))/(√(x-9) + o(1))^2

limit x→9 8 + 2o(1)/(x-9)

As x approaches 9, the o(1) term goes to 0, so the limit becomes:

8 + 2*0/0 = 8

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Answer:

Step-by-step explanation:

The length of the hypotenuse is approximately 4.95 cm.

We have,

Since triangle ABC is a 45-45-90 triangle, we know that the measure of angle B is also 45 degrees.

Therefore, we can use the 45-45-90 Triangle Theorem, which states that in a 45-45-90 triangle,

the length of the hypotenuse is √2 times the length of either leg.

In this case,

We know that leg a = 3.5 cm, so we can find the length of the hypotenuse c using the formula:

c = a√2

Substituting the value of a, we get:

c = 3.5√2 ≈ 4.95 cm

Therefore,

The length of the hypotenuse is approximately 4.95 cm.

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complete question:

The triangle above has the following measures. mzC = 45° a = 3.5 cm Use the 45-45-90 Triangle Theorem to find the length of the hypotenuse. Include correct units. Show all your work.​

21. in the figure, provided line n and line m are parallel the values of x and y are

x = 7

y = 24

21. When line m and line n are parallel then using corresponding angle theorem we have that:

7y - 23 + 8x - 21 = 180

7y - 8x = 180 + 23 - 21

7x - 8x = 182

Also

8x - 21 + 23x - 16 = 180

8x + 23x = 180 + 21 + 16

31x = 217

x = 217 / 31

x = 7

using vertical angle theorem we have:

7y - 23 = 23x - 16

plugging in the value of x

7y - 23 = 23 * 7 - 16

7y - 23 = 145

7y = 145 + 23

7y = 168

y = 24

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The quotient of the expression (5.04×10^12)÷(6.3×10^9) written in scientific notation is 8 × 10^2.

To divide two numbers written in scientific notation, we can divide their coefficients (the decimal parts) and subtract their exponents. So, we have:

(5.04 × 10^12) ÷ (6.3 × 10^9) = (5.04 ÷ 6.3) × 10^(12-9) = 0.8 × 10^3

Since 0.8 is less than 1, we can write this number in scientific notation by moving the decimal point one place to the right and subtracting 1 from the exponent:

0.8 × 10^3 = 8 × 10^2

Therefore, the quotient of the expression (5.04×10^12)÷(6.3×10^9) written in scientific notation is 8 × 10^2.

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There are 20 different ways the students can be chosen for the positions of editor-in-chief and assistant editor-in-chief.

There are 5 students in the newspaper staff, and two positions to fill i.e. editor-in-chief and assistant editor-in-chief. We need to find the number of different ways the students can be chosen for these positions.

To solve this problem, we can use the formula for permutation

We know the formula for Permutation is

[tex]P(n,r)=\frac{n!}{(n-r)!}[/tex]

Here, n=5 and r=2

So, P(5,2) = 5!/(5-2)!

= 5!/3!

= 120/6

= 20

Therefore, there are 20 different ways the students can be chosen for the positions of editor-in-chief and assistant editor-in-chief.

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the repeating decimal 0.216 can be written as the geometric series: 0.216 = 216/990.

To write the repeating decimal 0.216 as a geometric series, we first need to express it in the form of a sum of a geometric series.

The decimal 0.216 repeats every three digits, so we can break it down as follows:

0.216 = 0.2 + 0.01 + 0.006 + 0.0002 + 0.00001 + 0.000006 + ...

Now, we can write this as a sum of a geometric series with the first term (a) and the common ratio (r):

a = 0.2
r = 0.01 (because each term is 1/100 of the previous term)

Thus, the geometric series for the repeating decimal 0.216 is:

0.216 = 0.2 + 0.2(0.01) + 0.2(0.01)^2 + 0.2(0.01)^3 + ...

The formula for the sum of an infinite geometric series is S = a / (1 - r), where S is the sum, a is the first term, and r is the common ratio.

Using the values for a and r, we can find the sum of the series:

S = 0.2 / (1 - 0.01) = 0.2 / 0.99 = 216/990.

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To find the center of a circle when the circumference is not given, you still find it.

1. Determine the coordinates of at least three non-collinear points on the circle. Non-collinear points are points that do not lie on a straight line.
2. Using these points, create two line segments that are chords of the circle. A chord is a line segment connecting two points on the circle.
3. Find the midpoints of each chord. The midpoint formula is given as: Midpoint (M) = ((x1 + x2) / 2, (y1 + y2) / 2).
4. Calculate the slope of each chord using the slope formula: Slope (m) = (y2 - y1) / (x2 - x1).
5. Calculate the slope of the perpendicular bisectors of each chord. Since these lines are perpendicular to the chords, their slopes are the negative reciprocal of the chord slopes: m_perpendicular = -1 / m_chord.
6. Write the equation of each perpendicular bisector using the point-slope formula: y - y_midpoint = m_perpendicular * (x - x_midpoint).
7. Solve the system of equations formed by the two perpendicular bisectors. The solution is the coordinates of the center of the circle.

By following these steps, you can find the center of the circle even when the circumference is not given.

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The equation of the ellipse with center (1, -3), and a semi major axis of 4, and a semi minor axis of 3 is; (x - 1)²/4² + (y + 3)²/3²

The standard form equation of an ellipse can be presented as follows;

(x - h)²/a² + (y - k)²/b² = 1

Where;

(h, k) = The coordinates of the center of the ellipse.

The length of the semi major axis = a

Length of the semi minor axis = b

The center of the specified ellipse is; (h, k) = (1, -3)

The semi major axis = 4

The length of the semi minor axis = 3

The equation of the ellipse is therefore;

(x - 1)²/4² + (y - (-3))²/3² = 1

(x - 1)²/4² + (y + 3)²/3² = 1

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The Pythagorean Theorem with regards to the relationships between the lengths of the sides of a right triangle indicates that we get;

2. x = 51

3. x = 50

4. x = 82

8. x = 2·√(77)

9. x = √(39)

10. x = 2·√(19)

11. x = 2·√(154)

12. x = 3·√3

13. x = 6·√(13)

16. A right triangle

17. A right triangle

18. The triangle is not a right triangle

19. An obtuse triangle

20. An obtuse triangle

The Pythagorean Theorem states that the square of the length of the hypotenuse side of a right triangle is equivalent to the sum of the squares of the lengths of the other two sides.  

2. x² = 45² + 24² = 2601

x = √(2601) = 51

3. x² = 30² + 40² = 2500

x = √(2500) = 50

x = 50

4. x² = 80² + 18² = 6724

x = √(6724) = 82

x = 82

8. According to the Pythagorean Theorem, in the right triangle we get;

x² = 18² - 4² = 308

x = 2·√(77)

9. x² = 8² - 5² = 39

x = √(39)

10. x² = 20² - 18²

x² = 76

x = √(76) = 2·√(19)

x = 2·√(19)

11. x² = 25² - 3² = 616

x = √(616) = 2·√(154)

x = 2·√(154)

12. x² = 6² - 3² = 27

x = √(27)

x = 3·√3

13. x² = 22² - 4² = 468

x = √(468) = 6·√(13)

x = 6·√(13)

16. A triangle is a right triangle if the square of the side that is the longest is equivalent to the square of the other two sides, therefore;

17² = 289

15² + 8² = 289

Therefore, the triangle is a right triangle

17. 45² = 2025

27² + 36² = 2025

Therefore, the triangle is a right triangle

18. 11² = 121

9² + 4² = 97

Therefore, the triangle is not a right triangle

19. 6² = 36

4² + 3² = 25

The square of the side that is longest is larger than the sum of the squares of the other two sides, which indicates that the angle facing the longest side is lar1ger than 90°, and the triangle is an obtuse triangle.

20. 16² = 256

9² + 11² = 202

16² > 9² + 11²; Therefore, the triangle is an obtuse triangle

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In ΔPQR, the length of QR is approximately 4.1 feet to the nearest tenth of a foot.

In ΔPQR, given that ∠R=90°, ∠P=26°, and PQ=8.5 feet, you want to find the length of QR to the nearest tenth of a foot.

Step 1: Since ∠R is a right angle (90°), we can use trigonometric ratios to find QR. First, let's find ∠Q. We know that the sum of angles in a triangle is 180°, so ∠Q = 180° - (∠P + ∠R) = 180° - (26° + 90°) = 64°.

Step 2: Now that we have all the angles, we can use the sine formula to find QR. We'll use the sine of ∠P (26°) and the given side PQ (8.5 feet) as our reference. The sine formula is:

QR = (PQ * sin(∠P)) / sin(∠Q)

Step 3: Plug in the known values:

QR = (8.5 * sin(26°)) / sin(64°)

Step 4: Calculate the sine values and the division:

QR = (8.5 * 0.4384) / 0.8988 ≈ 4.1326

Step 5: Round the answer to the nearest tenth of a foot:

QR ≈ 4.1 feet

In ΔPQR, the length of QR is approximately 4.1 feet to the nearest tenth of a foot.

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To find the percentage of students who collected between 49 and 98 kilograms of newspapers, we need to first count the number of students whose collection falls within this range. We can do this by sorting the data and counting the number of values that fall within this range.

Sorting the data, we get:

15, 23, 35, 45, 45, 49, 55, 56, 57, 60, 64, 75, 76, 87, 88, 90, 98, 100, 101, 105, 120, 122

We can see that there are 17 students whose collection falls within the range of 49 to 98 kilograms.

To find the percentage of students, we can divide the number of students whose collection falls within this range by the total number of students and then multiply by 100. The total number of students is the sum of the number of values in the two sets, which is 22 + 22 = 44.

Therefore, the percentage of students who collected between 49 and 98 kilograms of newspapers is:

17/44 * 100% ≈ 38.6%

So approximately 38.6% of the students collected between 49 and 98 kilograms of newspapers.

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Answer:148

Step-by-step explanation:

Assuming he only bought milk, fish and chicken.
220+132=352
500-352=148

The range of values that represent the middle 95% of the data is from 20.18 to 47.82 or (20.18, 47.82).

A measurable speculation test is a strategy for factual deduction used to conclude whether the information within reach adequately support a specific speculation. We can make probabilistic statements about the parameters of the population thanks to hypothesis testing.

The middle 95% of a normal distribution is located within 1.96 standard deviations from the mean in both directions.

Therefore, the lower limit is:

34 - 1.96(7) = 20.18

And the upper limit is:

34 + 1.96(7) = 47.82

So the range of values that represent the middle 95% of the data is from 20.18 to 47.82 or (20.18, 47.82).

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The customer can choose from 21 different gifts if they want to order only 1 item, 138 different gifts if they want to order 2 items of different kinds, and 280 different gifts if they want to order 3 items of different kinds.

To find the different number of gifts, we use the fundamental counting principle, which states that the total number of ways to choose a sequence of items is equal to the product of the number of choices available for each item.

⇒ If a customer wants to order only 1 item, they can choose from:

10 varieties of "greeting-cards"

4 types of "fruit-baskets"

7 flower arrangements

So, total number of different gifts that can be created is: 10 + 4 + 7 = 21.

⇒ If a customer wants to order 2 items of different kinds, they can choose from:

10 varieties of greeting-cards and 4 types of fruit baskets :

(10 × 4 = 40 choices)

10 varieties of greeting cards and 7 flower arrangements :

(10 × 7 = 70 choices)

4 types of fruit-baskets and 7 flower arrangements :

(4 × 7 = 28 choices)

So, number of different gifts that can be created is: 40 + 70 + 28 = 138.

⇒ If a customer wants to order 3 items of different kinds, they can choose from:

10 varieties of greeting cards, 4 types of fruit baskets, and 7 flower arrangements (10 × 4 × 7 = 280 choices),

So, the total number of different gifts that can be created is : 280.

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Answer: (4)

Step-by-step explanation:

Two lines E and F are same.

5x + 5y = 40

x + y = 8

Deviding both hands of E by 5,

we get F's equation.

So every single point on the line x+y=8

represents the solution of the given system.

The final result is  ∫ sin²(x)- cos²(x)/cos(x) dx = -3cos²(x)/2 + 2ln|cos(x)| + C.

To solve the indefinite integral ∫ sin²(x)- cos²(x)/cos(x) dx, we need to use trigonometric identities to simplify the integrand.

First, we use the identity sin²(x) + cos²(x) = 1 to write:

sin²(x) - cos²(x) = sin²(x) + cos²(x) - 2cos²(x) = 2sin²(x) - cos²(x)

Next, we use the identity sin²(x) = 1 - cos²(x) to write:

2sin²(x) - cos²(x) = 2(1-cos²(x)) - cos²(x) = 2 - 3cos²(x)

Substituting this into the original integral, we get:

∫ sin²(x)- cos²(x)/cos(x) dx = ∫ (2 - 3cos²(x))/cos(x) dx

Now, we use the substitution u = cos(x) and du/dx = -sin(x) dx to transform the integral into a simpler form:

∫ (2 - 3cos²(x))/cos(x) dx = ∫ (2 - 3u²)/u (-du/sin(x))

= -∫ (3u² - 2)/u du

= -3∫ u du + 2∫ du/u

= -3u²/2 + 2ln|u| + C

= -3cos²(x)/2 + 2ln|cos(x)| + C

where C is the constant of integration.

Substituting back u = cos(x), we obtain the final result

∫ sin²(x)- cos²(x)/cos(x) dx = -3cos²(x)/2 + 2ln|cos(x)| + C

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The coordinates of triangle X'Y'Z' is X'(-2,-2), Y'(-3,4), Z'(1,2).

What are the coordinates of the triangle?

The triangle's vertices have the coordinates (x1,y1), (x2,y2), and (x3,y3). The line that connects the first two is split in the ratio l:k, and the line that runs from the division point to the opposing angular point is divided in the ratio m:k+l.

Here, we have

Given: Triangle XYZ has coordinates X(-2,2), Y(-3,-4). And Z(1,-2).

The triangle is reflected across the x-axis and we have to find the coordinates of triangle X'Y'Z'.

X(-2,2), Y(-3,-4) and Z(1,-2).

While reflecting any points across the x-axis with coordinates as (x, y) becomes, (x, -y). i.e. sign of y-coordinate changes.

The rule is (x, y) → (x, -y)

After applying the rule, we get

X(-2,2) ⇒ X'(-2,-2)

Y(-3,-4) ⇒ Y'(-3,4)

Z(1,-2) ⇒ Z'(1,2)

Hence, the coordinates of triangle X'Y'Z' is X'(-2,-2), Y'(-3,4), Z'(1,2).

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The length of the diagonal is c = √269 feet.

To get the length of the diagonal of a rectangular patio, we can use the Pythagorean theorem, which states that for a right triangle with legs of length a and b, and hypotenuse of length c, a² + b² = c². In this case, the legs of the right triangle are the length and width of the rectangular patio, which are 10 feet and 13 feet, respectively. Let's use a and b to represent these lengths.
a = 10 feet
b = 13 feet
We want to find the length of the diagonal, which is the hypotenuse of the right triangle. Let's use c to represent this length.
a² + b² = c²
10² + 13² = c²
100 + 169 = c²
269 = c²
Now we need to find the square root of 269 to get the length of the diagonal.
c = √269
c ≈ 16.4 feet
So the length of the diagonal of the rectangular patio is approximately 16.4 feet. We can also find the ratio of the length, width, and diagonal of the rectangular patio.
length:width = 10:13
width:length = 13:10
length:diagonal = 10:√269
width:diagonal = 13:√269
diagonal:length = √269:10
diagonal:width = √269:13

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The total number of possible lock combination using the 40 possible numbers for making lock of 3 numbers is equal to 64,000.

Possible number used for lock combination are 40.

Range is 0 - 39.

Total number chosen for lock combination is equal to 3.

Since there are 40 possible numbers to choose from for each of the three positions on the combination lock.

The total number of possible combinations is equal to ,

40 x 40 x 40

= 40^3

= 64,000

Therefore, there are 64,000 possible lock combinations when choosing 3 numbers out of 40 possible numbers, assuming repeated numbers are allowed.

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Cash outflows and decreases in cash are reported as negative amounts in the operating activities section of the statement of cash flows for Peach Computer using the indirect method.

The operating activities section of the statement of cash flows for Peach Computer using the indirect method would include the following cash inflows and outflows:

Cash inflows:

Cash outflows:

Any decrease in cash would be represented as negative amounts in this section.

It's important to note that the specific amounts and details would vary based on Peach Computer's individual financial transactions and operations. The operating activities section provides a summary of the cash inflows and outflows directly related to the company's core business operations during the specified period.

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