Answer:
6s
Explanation:
Barium is in group 2 of the s block and is in period 6.
Barium belongs to the s block's period 6 and group 2. Barium is an alkaline earth metal with two valence electrons and a (+2) oxidation state found in Periodic Table Group 2.
How are the valence electrons located?Valence electrons are electrons in an atom's outermost shell, or energy level. For example, oxygen has six valence electrons, two of which are in the 2s subshell and four of which are in the 2p subshell. For neutral atoms, the number of valence electrons is the same as the number of the atom's main group. The column of a periodic table element can be used to determine its main group number. Carbon, for example, belongs to group 4 and has four valence electrons, which are the outermost (valence) shell electrons of an atom that can be shared or transferred to another element.To learn more about valence electrons refer to:
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A 100-gram sample of material requires 1220 calories of heat energy to raise its temperature from 20 0C to 80 0C. What is the specific heat capacity of the material?
Taking into account the definition of calorimetry, sensible heat and latent heat, the specific heat capacity of the material is 0.203 [tex]\frac{calories}{gC}[/tex].
CalorimetryCalorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
The amount of heat a body receives or transmits is determined by:
Q = c× m× ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
Specific heat capacity of the materialIn this case, you know:
Q= 1220 caloriesc= ?m= 100 gΔT=Tfinal - Tinitial= 80 C - 20 C= 60 CReplacing in the definition of amount of heat:
1220 calories= c× 100 g× 60 C
Solving:
c= 1220 calories÷ (100 g× 60 C)
c= 0.203 [tex]\frac{calories}{gC}[/tex]
Finally, the specific heat capacity of the material is 0.203 [tex]\frac{calories}{gC}[/tex].
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What mass of kool-aid is needed to make a 0.5-M solution from 100 mL?
Answer:
but purely citric acid synthetic Acid whose moller mass is equal to 192 g per mole. Okay, so here we have Modernity is even McGarity is equal to 0.5 M and we have volume, so Volume is equal to 200 mililiters is equal to 0.1 liter Okay, so they are asking to calculate the mass of what u have Okay. So first of all, if we want to calculate the mass of then we have to calculate the number of moles. So maturity is equal to the number of moles per volume in liters . So you mean zero point sorry from this one number of moles is equal to So N is equal to m multiplied very weak. So that is equal to 0.1 and 0.5. So that is equal to 0.05 moles. Okay, now the mask is equal to the mass of cool eh is equal to the number of Okay. Number of 0.5 and it is multiplied by 92 g per mole. Then it is equal to 9.6 g. So this is the mass of a present. A 0.500 ml
An electric motor in a bike has a voltage of 24 V and produces 240 W of power. How much current does it draw?]
Answer:
Electrical energy is the product of power multiplied by the length of time it was consumed. So if we know how much power, in Watts is being consumed and the time, in seconds for which it is used, we can find the total energy used in watt-seconds. In other words, Energy = power x time and Power = voltage x current.
The amount of current the electric motor having a power of 240 W Will draw from the 24 V supply is 10 A
What is power?This is defined as the rate in which energy is consumed. Electrical power is expressed mathematically as:
Power (P) = voltage (V) × current (I)
P = IV
How to determine the currentFrom the question given above, the following data were obtained:
Voltage (V) = 24 V
Power (P) = 240 W
Current (I) = ?
P = IV
240 = I × 24
Divide both sides by 24
I = 240 / 24
I = 10 A
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Mercury-203 undergoes beta minus decay. the subscript in the nuclide notation, hg, is . 203 ? hg →? the element symbol produced is . it has a mass number and an atomic number . 203 80 hg → 203 81 ti ?
When Mercury-203 undergoes beta minus decay, the nucleus that is formed is 203/81Tl.
What is beta emission?A parent nucleus is said to undergo beta emission when only when an electron is lost to form the daughter nucleus. This would make the atomic number of the daughter nucelus to increase by 1.
Hence, when Mercury-203 undergoes beta minus decay, the nucleus that is formed is 203/81Tl.
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Answer:
Mercury-203 undergoes beta minus decay. The subscript in the nuclide notation, Hg, is ____80______
The element symbol produced is __TI__ . It has a mass number __203__ and an atomic number ___81____
80
Explanation:
What kind of property is melting point? an atomic property , , , an atomic property , , a physical property , a physical property , , an acidic property , an acidic property , , a chemical property
Answer:
physical property has a melting point
disadvantages of hard water
Answer:
Here are some disadvantages
Explanation:
Hard water does not pose a health threat.
Hard water can contribute to dry skin and hair.
Hard water is unfit for washing as it is difficult to form lather with soap.
Trimming of kettles will take place due to the formation of magnesium and carbonates of calcium.
The Taste/Smell
Lather
Dishwashing Ability
Clothes-Washing Ability
Staining
Limescale Buildup
Corrosion
Shaila is collecting data to calculate the density of a piece of wood. First, she
places the wood on a triple beam balance; its mass is 63.85 g. Then, she fills a
graduated cylinder with 50.0 mL of water. She places the wood in
graduated cylinder with the water and notes that the water level rises to 125.0
mL. Calculate the density of the wood given that D = m/V. i need some1 to explain this
Answer:
Explanation:
Remark
You have 2 facts that you got from the experiment. The first is that the mass of the wood is 63.85 grams and the volume can be calculated.
From there, the desity can be found.
Givens
m = 63.85 grams
vo = 50 mL
vf = 125 mL
Solution
Volume = vf - vo
Volume = 125 mL - 50 ml. This gives you the amount of water that has been moved aside (called displaced)
volume = 75 mL
D = 63.85 grams/ 75 mL
D = 0.851 grams / mL
Some woods actually do have a density less than 1 which is the density of water. These woods float.
Find the concentration of 0.75 mol.dm-³ AgNO3
The mass concentration of the 0.75 mol.dm-³ AgNO3 solution is 127.5 g/dm³.
What is concentration?Concentration is the amount of a solute present ina a given volume of solution.
Concentration of solutions can either be expressed as:
molar concentration Mass concentration Percentage concentrationThe concentration of 0.75 mol.dm-³ AgNO3 is a molar concentration.
The concentration can be converted to mass. concentration as follows:
Mass concentration = molar concentration × molar massmolar mass of AgNO3 = 170 g/mol
Mass concentration = 0.75 × 170 = 127.5 g/dm³.
Therefore, the mass concentration of the AgNO3 solution is 127.5 g/dm³.
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Equation Given : Al^(3+) + Na3PO4 ==> 3Na^+ + AlPO4
Given that 61µg of aluminum phosphate precipitate formed, calculate the micromoles of aluminum ions in 50 mL of river water. (1µg = 1 x 10^(-6)g)
1 mols of Aluminium ion forms 1 mol aluminium phosphate
Molar mass of AlPO_4
27+31+16(4)58+48106uMoles of AlPO_4
61µg/1060.000061/1065.75×10^{-7}57.5µmolMoles of Al3+=57.5µmol
What is the mass of oxygen in 25. 0 grams of potassium permanganate kmno4.
Answer: The mass of oxygen in 25.0 grams of potassium permanganate, KMnO4 is 10.13 grams. molar mass of KMnO₄ = 39 + 55 + 16(4).
Explanation:hope this helps ^^ have a good day xlXCherryColaXlx..(pls mark me brainliest)
To determine the mass of oxygen in 25.0 grams of potassium permanganate (KMnO4), we need to consider the molar mass and the ratio of oxygen atoms in the compound.
What is molar mass ?Molar mass is a term used in chemistry to denote the mass of one mole of a substance. It is expressed in grams per mole (g/mol). Molar mass is calculated by summing up the atomic masses of all the atoms in a molecule, as indicated by its chemical formula.
The molar mass of potassium permanganate (KMnO4) can be calculated as follows:
Molar mass of K = 39.10 g/mol
Molar mass of Mn = 54.94 g/mol
Molar mass of O = 16.00 g/mol (since there are 4 oxygen atoms in KMnO4)
Molar mass of KMnO4 = (39.10 g/mol) + (54.94 g/mol) + (4 * 16.00 g/mol)
= 39.10 g/mol + 54.94 g/mol + 64.00 g/mol
= 158.04 g/mol
Now, we can calculate the mass of oxygen in 25.0 grams of KMnO4 using the molar mass and the molar ratio:
Mass of oxygen = (Molar mass of O / Molar mass of KMnO4) * Mass of KMnO4
= (4 * 16.00 g/mol / 158.04 g/mol) * 25.0 g
= (64.00 g / 158.04 g) * 25.0 g
= 0.4052 * 25.0 g
= 10.13 g (rounded to two decimal places)
Therefore, the mass of oxygen in 25.0 grams of potassium permanganate (KMnO4) is approximately 10.13 grams.
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A solution is prepared by dissolving 17. 1 g of sucrose (C12H220,1) in 275 g of H2O.
a. What is the molar mass of sucrose?
b. What is the molality of that solution?
Answer:
If you know the formula to use you should have no trouble getting the answers.
molality = mols/kg solvent.
mols sucrose = g/molar mass
kg solvent = 0.275 kg.
How many moles of chlorine gas at 120.0 °C and 33.3 ATM would occupy a vessel of 25.5 L?
Temperature (T) = 120°C
= (120+273) K
= 393 K
Pressure (P) = 33.3 atm
Volume (V) = 25.5 L
Gas Constant (R) = PV/T
= (1*22.4)/273
= 0.082 atm.L/K.mol
Law= PV = nRT
= (33.3*25.5)
= (n*0.082*393)
= 849.15
= 32.226n
= 26.349n
= 26.3 mol Cl₂
therefore, the number of moles are 26.3 mol Cl₂.
PV = nRT
P = 33.3 atm
V = 25.5 L
n = ? mol
R = 0.08206 L•atm/K•mol
T = 120.0 °C + 273.15 = 393.15 K
Solve for moles:
n = PV/RT
n = (33.3 atm × 25.5 L)/(0.08206 L•atm/K•mol × 393.15 K)
= 26.3 mol Cl₂
Fill In the
476 nm = 4.76 x 10^? Cm
Recall that 1 nm 1 x 10 m and 1 cm = 1 x 10-2 m. You will want to memorize the metric conversion factors and those covered in this lesson!
Answer:
I gotthe answer
Explanation:
The explanation is This
Now writing the value in sentific term
It would look like
[tex]4.76 \times {10}^{2} \times {10}^{ - 9} [/tex]
[tex]4.76 \times {10}^{2 - 9} [/tex]
4.76
[tex]4.76 \times {10}^{ - 7} [/tex]
Now in centimeter
[tex]4.76 \times {10}^{ - 5} [/tex]
PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE
Which best explains the relationship between evaporation and temperature?
A liquid evaporates slower at lower temperatures because the molecules are more spread apart and are not pushed as easily from the liquid’s surface.
A liquid evaporates faster at lower temperatures because the attractions are decreased and more particles can escape the surface of the liquid.
A liquid evaporates slower at higher temperatures because the vapor pressure of the liquid is higher, so fewer molecules can escape the surface.
A liquid evaporates faster at higher temperatures because more particles have a higher speed and can overcome attractions in the liquid.
Answer:
A liquid evaporated slow at higher temperature bz the vapour pressure of the is higher so few molecule can escape the surface
Answer:
The correct answer is D. A liquid evaporates faster at higher temperatures because more particles have a higher speed and can overcome attractions in the liquid.
Explanation:
I just got it right on Edge.
Hope this helped!
Brainliest would be greatly appreciated :D
explain volume and pressure at constant temperature of a gas using the kinetic molecular
Answer:
If the temperature is increased, the average speed and kinetic energy of the gas molecules increase. If the volume is held constant, the increased speed of the gas molecules results in more frequent and more forceful collisions with the walls of the container, therefore increasing the pressure
Explanation:
hope this helps
When you calculate the Ksp of calcium fluoride, CaF2, and the concentration of the F- ion is 4.2 x 10-4M, what is the concentration of the Ca2 ion
Calculate its molar solubility in a saturated aqueous solution that is also 0.050 M in fluoride ion, F-. Ksp = (x)(2x + 0.05)2. 2x = 4.210 4
What is the molar concentration of HBr if 25 mL of the acid is titrated 15.3 mL of 0.5 M KOH?
Round answer to 2 decimal places.
When determining the cell potential for a hypothetical galvanic cell containing two different materials, how do we determine which substances comprise the anode and which comprise the cathode
To determine the substance that comprises the anode and the cathode in a galvanic cell is by determing ;
The material with the larger (more positive) standard reduction potential that will be the cathode.
Characteristics of a galvanic cellIn a galvanic cell, oxidation which leads to the loss of elctrons occurs at the anode, while reduction ( addition of elctrons ) occurs at the cathode. therefore the materials with a more positive standard reduction potential will be the cathode of the galvanic cell.
Hence we can conclude that The material with the larger (more positive) standard reduction potential will be the cathode.
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what is kind of property is denisty?
Answer:
INTENSIVE PROPERTY OF MATTER
Explanation:
DENSITY IS AN INTENSIVE PROPERTY OF MATTER THAT ILLUSTRATES HOW MUCH MASS A SUBSTANCE HAS IN A GIVEN AMOUNT OF VALUE,
My cousin cant figure this out and neither me so maybe yall can help?
Answer:
I believe the Answer is B
Which group of compounds tastes bitter and are usually slippery when placed in water?.
Answer:
Bases
Explanation:
Soap is a common example of a base. They taste bitter (try tasting soap or shampoo) and are slippery (that is why a wet bar of soap flies out of your hands)
3 grams of Aluminum was heated from 20 °C to 662 °C while absorbing
1728 I of heat. What is the specific heat of Aluminum?
The specific heat capacity of Aluminum of mass 3 grams that was heated from 20 °C to 662 °C while absorbing 1728 J of heat is 12.5 J/g°C.
What is specific heat capacity?The specific heat capacity of a substance can be calculated using the following formula:
Q = m × c × ∆T
Where;
Q = quantity of heat absorbed or releasedm = mass of substancec = specific heat capacity∆T = change in temperatureAccording to this question, 3 grams of Aluminum was heated from 20 °C to 66.2 °C while absorbing 1728 J of heat.
1728 = 3 × c × (66.2 - 20)
1728 = 138.6c
c = 1728 ÷ 138.6
c = 12.5 J/g°C
Therefore, the specific heat capacity of Aluminum of mass 3 grams that was heated from 20 °C to 662 °C while absorbing 1728 J of heat is 12.5 J/g°C.
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PLEASE HELP: You have been given 0.507 moles of cesium fluoride (CsF), determine the mass in grams of cesium fluoride that you have.
Answer:
C because 77.0 CsF
Explanation:
That is the correct answer because I have that homework and i got it right
Determine the number of moles of water that could be produce
from 10.0 mols of hydrogen gas and 6.0 mols of oxygen gas.
If 10.0L of hydrogen gas, and 6.0L of oxygen gas were used in
problem 1, how many liters of water vapor would be produced?
PLEASE HELP <3
From the mole ratio of the gases, 10 moles of hydrogen will produce 10 moles of water, and if 10.0 L of hydrogen and 6.0 L of oxygen were used, 10.0 L of water will be produced.
What is the mole ratio of reactants in the formation of water?The mole ratio of the reactants in the formation of water can be shown from the equation below:
[tex]2H_2 + O_2 \rightarrow 2H_2O[/tex]
Mole ratio of hydrogen to oxygen is 2:1
10 moles of hydrogen will require 5 moles of oxygen, therefore hydrogen is the limiting reactant.
10 moles of hydrogen will produce 10 moles of water.
1 mole of a gas has a volume of 22.4 L.
If 10.0 L of hydrogen and 6.0 L of oxygen were used, 10.0 L of water will be produced.
Therefore, the volume ratio of gas equals mole ratio of gas.
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Classify the following type of stoichiometry problem: How many cubic centimeters of oxygen are produced from decomposing 5.00 mL of steam? (Sec.9.3)
(a) mass–mass problem
(b) mass–volume problem
(c) volume–volume problem
(d) mole–mole problem
(e) none of the above
Answer:
volume problem
Explanation:
cubic usually means volume
How would the graph below change if a catalyst were added to the reaction?
2
Potential Energy
3
Reaction Progress
A. Part 1 would be higher, and part 2 would be lower.
B. Parts 1, 2, and 3 would be lower.
C. Part 2 would be lower, and parts 1 and 3 would be unchanged.
D. Parts 1 and 3 would be higher, and part 2 would be unchanged.
In an energy profile diagram, part 2 the initiation or activation energy is lowered and parts 1 and 3 would be unchanged; option C.
What is the effect of addition of a catalyst to reaction?A catalyst is a substance which alters the rate of a chemical reaction but is not chemically altered in the reaction.
Addition of a catalyst to a reaction lowers the activation energy of that reaction.
Thus, in an energy profile diagram, part 2 the initiation or activation energy is lowered and parts 1 and 3 would be unchanged.
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In an energy profile diagram, in part 2 the initiation or activation energy is lowered and parts 1 and 3 would be unchanged. Hence, option C is correct.
What is the effect of the addition of a catalyst to the reaction?The addition of a catalyst provides an alternate pathway/mechanism with a lower energy of activation, thus speeding up the reaction.
Catalysts typically speed up a reaction by reducing the activation energy or changing the reaction mechanism.
Thus, in an energy profile diagram, in part 2 the initiation or activation energy is lowered and parts 1 and 3 would be unchanged.
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student A correctly describes a chemical equilibrium is “reactant favored” and student B also correctly describes the same equilibrium as “product favored”. Can this happen? If so how?
ANSWER ASAP!!
What is the name of bird W?
Answer:
woodpecker it's easy lil lol
How might the ability of magnets to attract or repel other magnets relate to
the floating rings?
Answer:
Using magnets to repel each other is one way to try to achieve a frictionless bearing. In practice, it can be difficult to remove all friction. While a pair of magnets will repel each other, they are not stable in this condition. One magnet won't simply float forever above another magnet.
Explanation:
Strong nuclear forces inside the atomic nucleus tend to ____ .
a. cause nuclear decay
b. hold the nucleus together
c. make the nucleus unstable
d. push the nucleus apart
Answer: a. cause nuclear decay
Explanation: