Answer:
Companies are turning to the world of sports to meet their promotional needs because sports have a large and passionate fan base, and sponsoring a team or athlete can help companies reach a wider audience and increase brand awareness. Here are 10 ideas for how companies might decide which team or individual athletes to use for their promotions:
Choose a team or athlete that aligns with the company’s values and brand image.
Consider the popularity and reach of the team or athlete, both locally and globally.
Look at the demographics of the team or athlete’s fan base to see if it matches the company’s target audience.
Evaluate the team or athlete’s performance and potential for future success.
Consider the cost of sponsorship and whether it fits within the company’s budget.
Look at the team or athlete’s social media presence and engagement with fans.
Consider any existing partnerships or sponsorships that the team or athlete may have.
Evaluate the potential for co-branded merchandise or promotional materials.
Consider the potential for cross-promotion with other sponsors or partners.
Look at the potential for long-term partnerships and opportunities for future collaboration.
Explanation:
assuming stp and a stoichiometric amount of nh3 and no in an expandable container originally at 15 L, what is the final volume if the reaction goes to completion? 4NH3 (g) + 6NO (g) —> 5N2 (g) + 6H2O (g)
Answer:
16.5 L
Explanation:
We are given the following factors (they are all essential):
4 moles NH3 gas (15 L initially)6 moles NO gasContainer volume = 15 L initially at STPGiven reaction:
4NH3 (g) + 6NO (g) -> 5N2 (g) + 6H2O (g)
Using the mole ratios from the balanced chemical equation:
For every 4 moles NH3, there will be 6 moles NO and they will react to produce:
5 moles N26 moles H2OInitial moles of gas:
4 moles NH36 moles NOTotal = 10 molesFinal moles of gas:
5 moles N26 moles H2OTotal = 11 molesBy Avogadro's law, volume is directly proportional to moles of gas at constant temperature and pressure.
Since we have 11 moles of gas after the reaction compared to 10 moles initially, the final volume will be:
(11 moles gas)(15 L initial)/(10 moles initial)
= 16.5 L
So in summary, the final volume of the gas mixture after the reaction goes to completion will be 16.5 L, assuming a constant temperature and pressure within the expandable container.
The general approach is to calculate the mole ratios and number of moles of gases before and after the reaction, then use proportionality to determine how the volume will change accordingly.