x^2 =−8x−7 solve by rewriting the square

Answer:

Raul is 15 years old.

Step-by-step explanation:

The number of years from the start of the Great Depression to Nixon's election is six years less than three times Raul's age: 3r-6

If then Nixon's first election happened 39 years after the Great Depression, then: 3r-6=39

3r-6=39    Add six to both sides so the 6 on the left side gets canceled out (positive and negative cancel each other out) so the equation will now look like this: 3r=45

Then divide 3 on both sides (multiplication and division also cancel each other out), then the equation looks like this: r=15

And so, Raul is 15 years old.

Answer:

Step-by-step explanation: ??? There is no picture

Answer:

the method of exact differential equations:

We need to check if this differential equation is exact. To do that, we check if the partial derivative of the first term with respect to y is equal to the partial derivative of the second term with respect to x:

∂/∂y(x(x-y)) = x(-1) = -x

∂/∂x(y^2) = 0

Since these partial derivatives are not equal, the differential equation is not exact. We can try to make it exact by multiplying the entire equation by a suitable integrating factor.

Let's find the integrating factor (IF) by taking the partial derivative of the IF with respect to y and equating it to the partial derivative of the second term with respect to x:

∂/∂y(IF) = -y^2/(x(x-y)^2)

∂/∂x(y^2) = 0

From the first equation, we can see that an integrating factor of IF = x(x-y)^2 should make the equation exact. Multiplying the entire equation by this integrating factor, we get:

x(x-y)^2dy + y^2x(x-y)dx = 0

Now, we just need to find a function φ(x,y) such that:

∂φ/∂x = x(x-y)^2dy

∂φ/∂y = y^2x(x-y)dx

Integrating the first equation with respect to x, we get:

φ(x,y) = ∫x(x-y)^2dy + f(x)

φ(x,y) = -1/3(x-y)^3x + f(x)

Now, we differentiate this equation with respect to x and equate it to the second equation:

∂φ/∂x = -(x-y)^3 + f'(x)

∂φ/∂y = y^2(x-y)^3

Comparing the two, we can see that f'(x) = 0, which means that f(x) is a constant. We can choose this constant to be zero without loss of generality.

Therefore, the solution to the differential equation is given by:

-1/3(x-y)^3x + C = 0

where C is an arbitrary constant.

Answer:

about like 4-5

Step-by-step explanation:

its 4 or 5

The correct answers for the equation of parabola with  (3,5) are:

A. True

B. False

C. True

D. True

E. True

Using the vertex form equation of the parabola with vertex (h, k) and p = 2,

[tex](y-4)^{2}[/tex] = 8(x - 3)

[tex]y^{2}-10y+25[/tex] = 8x - 24

[tex]y^{2}-10y+49[/tex] = 8x

A. (-1, 5): Substitute x = -1 and y = 5 into the equation:

25 - 10(5) + 49 = 8(-1)

-16 = -16

This is true, so the point (-1, 5) is on the parabola.

B. (3, 3): Substitute x = 3 and y = 3 into the equation:

9 - 10(3) + 49 = 8(3)

-8 = 8

This is false, so the point (3, 3) is not on the parabola.

C. (5, 5): Substitute x = 5 and y = 5 into the equation:

25 - 10(5) + 49 = 8(5)

9 = 9

This is true, so the point (5, 5) is on the parabola.

D. (7, 5): Substitute x = 7 and y = 5 into the equation:

25 - 10(5) + 49 = 8(7)

25 = 25

This is true, so the point (7, 5) is on the parabola.

E. (3, 9): Substitute x = 3 and y = 9 into the equation:

81 - 10(9) + 49 = 8(3)

1 = 1

This is true, so the point (3, 9) is on the parabola.

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Answer:√x

Step-by-step explanation:

I am assuming the equation says [tex]f^{-1}(x)=x^{2}[/tex]

What you do is put x instead of [tex]f^{-1}(x)[/tex] and y² instead of x²

So x = y²

Rearrange for y

y = √x

Replace y with f(x)

f(x) = √x

In conclusion, the probability of selecting a Democrat or a business major is 11/15.

How to solve?

To find the probability of selecting a Democrat or a business major, we need to add the probabilities of selecting a Democrat and selecting a business major, and then subtract the probability of selecting a student who is both a Democrat and a business major (since we would be double counting this student).

So, let's calculate each of these probabilities:

Probability of selecting a Democrat: There are 40 Democrats out of 60 students, so the probability of selecting a Democrat is 40/60 = 2/3.

Probability of selecting a business major: There are 10 business majors out of 60 students, so the probability of selecting a business major is 10/60 = 1/6.

Probability of selecting a student who is both a Democrat and a business major: We know that there are 4 business majors who are also Democrats, so the probability of selecting one of these students is 4/60 = 1/15.

Now we can calculate the probability of selecting a Democrat or a business major:

P(Democrat or business major) = P(Democrat) + P(business major) - P(Democrat and business major)

= 2/3 + 1/6 - 1/15

= 11/15

Therefore, the probability of selecting a Democrat or a business major is 11/15.

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Answer: Please provide further information for help so I can assist you.

Answer:☠️☠️☠️☠️do ur hw lil bro u actually need to learn this fr fr dont let me catch u slippin on foenem

Step-by-step explanation:

b. 650 because in the directions it says for groups of more than ( > ) 8 people they charge a FIXED fee of 650 so it's not 75 times 9 which would have been 675

Step-by-step explanation:

C(n) = {

75n, if n <= 8

650, if n > 8 and n <= 12

}

This function states that for groups of 8 people or fewer, the total cost is 75n, while for groups of 9 to 12 people, the total cost is a fixed $650.

b. To determine the total cost of a 1-hour private guided tour with 9 people, we can simply plug n = 9 into the equation we derived in part a:

C(9) = {

75*9, if 9 <= 8

650, if 9 > 8 and 9 <= 12

}

Since 9 is greater than 8 but less than or equal to 12, we use the second case:

C(9) = 650

Therefore, the total cost of a 1-hour private guided tour with 9 people is $650.

ChatGPT

Answer:

Step-by-step explanation:

Let's say the two numbers are x and y.

From the first statement "twice the difference between two numbers is 44", we can set up the equation:

2(x-y) = 44

Simplifying this equation, we get:

x - y = 22 (dividing both sides by 2)

From the second statement "three times their sum is 96", we can set up the equation:

3(x+y) = 96

Simplifying this equation, we get:

x + y = 32 (dividing both sides by 3)

Now we have two equations:

x - y = 22

x + y = 32

We can solve for x and y by adding the two equations together:

2x = 54

x = 27

Substituting x = 27 in either of the two equations, we get:

y = 5

Therefore, the two numbers are 27 and 5.

x = 27;

y = 5.

Say "x" is the first number.

Say "y" is the second number.

First statement: "twice the difference between two numbers is 44".

Difference of the numbers:[tex]x-y[/tex]

Twice the difference: [tex]2(x-y)[/tex]

Twice the difference between two numbers is 44: [tex]2(x-y)=44[/tex]

Second statement: "three times their sum is 96".

Sum of the numbers: [tex](x+y)[/tex]

3 times the sum: [tex]3(x+y)[/tex]

3 times the sum is 96: [tex]3(x+y)=96[/tex]

Use the distributive property of multiplication to simplify each equation as follows (check this property in the attached image).

[tex]2(x-y)=44\\ \\2x-2y=44[/tex]

[tex]3(x+y)=96\\ \\3x+3y=96[/tex]

Let's solve the second equation for "x".

[tex]3x+3y-3y=96-3y\\ \\3x=96-3y\\ \\x=\frac{96-3y}{3} \\ \\x=\frac{96}{3} -\frac{3y}{3} \\ \\x=32-y[/tex]

[tex]2((32-y)-y)=44\\ \\2(32-y-y)=44\\ \\2(32-2y)=44\\ \\(2)(32)+(2)(-2y)=44\\ \\64+(-4y)=44\\ \\64-4y=44\\ \\-4y=44-64\\ \\-4y=-20\\ \\y=\frac{-20}{-4} \\ \\y=5[/tex]

Use any equation to find a value for "x" by substituting "y" by "5" and solving for "x".

[tex]3(x+(5))=96\\ \\3(x+5)=96\\ \\3x+15=96\\ \\3x=96-15\\ \\3x=81\\ \\x=\frac{81}{3} \\ \\x=27[/tex]

To see if the answers are correct, plug in the values of "x" and "y" on each formula and see if they return the correct values (44 and 96).

[tex]2(x-y)=44\\ \\2((27)-(5))=44\\ \\2(22)=44\\ \\44=44[/tex]

Correct.

[tex]3((27)+(5))=96\\ \\3(32)=96\\ \\96=96[/tex]

Correct.

The numbers returned the correct values when evaluated in both opf the equation. Therefore, they are the correct answers.

x = 27;

y = 5.

See the graphic solution to this problem in the second attached image.

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Answer:

19, 993

Step-by-step explanation:

35, 617

15, 624

19, 993

Answer:

Step-by-step explanation:

20,047 using simple subtraction

From the given answer choices, the equation that shows work being calculated with the correct unit is C. 113J = (17.4N) x (6.51m)

In physics, work is defined as the amount of energy transferred by a force when it causes an object to move over a certain distance. Work is a scalar quantity and is expressed in units of joules (J) or foot-pounds (ft-lbs).

Mathematically, work (W) is given by the product of the force (F) applied on an object and the displacement (d) of the object in the direction of the force, as expressed in the formula:

W = F * d * cos(theta)

where theta is the angle between the force vector and the displacement vector.

Thus, the correct units which are Joules, metres and Newton are used.

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Answer:

Step-by-step explanation:

So, we have an equation relating the volume of the prism to the dimensions of the base. However, we still need more information to solve for x. Then x is 2.5 xyxx

Height generally refers to the distance from the base of an object, such as a person or a building, to the highest point of that object. In the case of a person, height is typically measured in feet and inches or centimeters and is a measurement of how tall someone is from the top of their head to the soles of their feet. In the case of a building or structure, height is typically measured in meters or feet and is a measurement of how tall the structure is from its base to its highest point, such as its roof or antenna. Height can also refer to the vertical distance between two points, such as the height of a mountain or the height of a wave in the ocean.

by the question.

Volume = base area x height

Since the bases of the prism are right triangles, we can calculate their area using the formula:

base area = 1/2 x base x height

where base is the length of the base of the triangle and height is the height of the triangle.

Let's assume that the length of the base of each right triangle is x, and that the height of each right triangle is y. Then we can write:

base area = 1/2 x y

The total volume of the prism is given as So. Therefore, we can write:

So = base area x height

Substituting the expression for base area and the given value for height, we get:

So = 1/2 x y x 5

Simplifying this equation, we get:

So = 2.5 x y x x

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Answer:

Each apple is worth $0.12

Step-by-step explanation:

Total of 12 apples ÷ Quantity of Apples = Cost of each apple

1.44 ÷ 12 = 0.12

Answer:

The tangent line is:  y = 8x - 58

The tangent point is at  (7, -2)

===================================================

Explanation:

One of the definitions of derivatives is

[tex]\displaystyle f'(a) = \lim_{x\to a} \frac{f(x)-f(a)}{x-a}[/tex]

where f ' (a) represents the derivative evaluated at x = a.

The value of f ' (a) will get us the slope of the tangent at x = a.

The idea is that x is getting closer and closer to 'a'. In doing so, the secant lines slowly approach the tangent line.

Keep in mind that x will never reach 'a' itself (if it did, then we'd have a division by zero error).

---------------

The given limit we have is

[tex]\displaystyle \lim_{x\to 7} \frac{f(x)+2}{x-7} = 8[/tex]

and that is equivalent to

[tex]\displaystyle \lim_{x\to 7} \frac{f(x)-(-2)}{x-7} = 8[/tex]

and also equivalent to

[tex]\displaystyle \lim_{x\to 7} \frac{f(x)-f(7)}{x-7} = 8[/tex]

Compare that to the template I mentioned at the top to see that

Therefore, we can say the tangent slope is 8 and the tangent touches the f(x) curve at (x,y) = (a, f(a)) = (7,f(7)) = (7,-2)

---------------

[tex]m = 8 = \text{slope}\\\\(x_1,y_1) = (7,-2) = \text{tangent point}\\\\[/tex]

Let's use that info to determine the equation of the tangent line.

I'll use point-slope form to isolate y.

[tex]y-y_1 = m(x-x_1)\\\\y-(-2) = 8(x-7)\\\\y+2 = 8x-56\\\\y = 8x-56-2\\\\y = 8x-58\\\\[/tex]

That's the equation of the tangent line to the point (7,-2).

Answer:

6 quarts

Step-by-step explanation:

2 pints = 1 quart

4 cups = 1 quart

• 5 pints of orange juice

5 pints = 5/2 =>2.5 quarts

• 6 cups of grape juice

6 cups = 6/4 => 1.5 quarts

• 8 cups of apple juice

8 cups = 2 quarts

2.5 + 1.5 + 2 = 6 quarts

The angles of the given Rhombus are:

The above are arrived at using the qualities of a Rhombus and the theorem of alternate angles.

A rhombus is a quadrilateral with certain properties that distinguish it from other types of quadrilaterals. The key properties of a rhombus are:

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The area of the given figures is 1) 4 sq. units; 2) 16 sq units; 3) 6 sq units.

Define area and perimeter.

The distance around a closed figure is its perimeter, while the area is the portion of the surface that it occupies. The size of a plane or the space it encloses is expressed in square meters.

1. In this figure, the longest side has 4 units and the smallest one has 1 unit.

   Area of the rectangular figure(A) = 4 * 1 = 4 sq units

   Perimeter(P) = 4 + 1 + 4 + 1 = 10 units.

2. In this figure, the longest side has 4 units and the smallest one has 4 units.

   Area of the rectangular figure(A) = 4 * 4 = 16 sq units

   Perimeter(P) = 4 + 4 + 4 + 4 = 16 units.

3. In this figure, the longest side has 4 units, 3 units, then 2 units the smallest one has 1 unit.

   Area of the rectangular figures combinely (A) = 4 * 1 + 2 * 1= 6 sq units

   Perimeter(P) = 4 + 3 + 2 + 2 + 1 = 12 units.

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Lines I and P can be considered parallel if they have the same slope, and ABC and CEF can be considered similar if they have the same size, but not necessarily the same shape.

Angle is a two-dimensional figure formed by two rays, called the sides of the angle, sharing a common endpoint, called the vertex of the angle. An angle is measured in degrees, which are represented by the symbol °. The size of an angle is determined by the amount of rotation between the two rays, with the vertex being the point of rotation. Angles can be described as acute, obtuse, right, reflex, straight and full.

A) The slope of line I is equal to the slope of line P. - True. If two lines have the same slope, they are parallel.

B) ABC is congruent to CEF - False. Congruent shapes have the same size and same shape. ABC and CEF are not necessarily the same size or shape.

C) Lines I and P are parallel - True. If two lines have the same slope, they are parallel.

D) ABC is similar to CEF - True. Similar shapes have the same size, but not necessarily the same shape.

E) Sin (A) = Sin (C) - False. The sine of an angle is only equal to the sine of another angle if they are the same angle.

F) Sin (B) = cos (F) - False. The sine of an angle is not equal to the cosine of another angle.

In conclusion, lines I and P can be considered parallel if they have the same slope, and ABC and CEF can be considered similar if they have the same size, but not necessarily the same shape. However, the sine of an angle is only equal to the sine of another angle if they are the same angle, and the sine of an angle is not equal to the cosine of another angle.

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The answer is no. As the p-value is more than 0.01, evidence does not support Annie's claim that the chances of getting married for this group is greater than 3.4%.

It assumes that the observed result is due to chance and there is not any difference between specified populations.

To determine this, we must calculate the p-value.

The number of successes in the sample is 20 and the number of observations is 407.

The sample proportion = 0.049. (20/407)

The hypothesis is that the percentage of women who got married is greater than 3.4%.

The null hypothesis is that the percentage is 3.4%.

We can use the z-test statistic to test this hypothesis.

The z-test statistic is calculated as:

z = (0.049-0.034)/(√(0.034(1-0.034)/407))

= 1.66.

The p-value is calculated as:

p-value = Φ/(1.66)

= 0.97.

This is more than 0.01 ,so we can not reject the null hypothesis.

This evidence does not support Annie's claim that the chances of getting married for this group is greater than 3.4%.

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[tex]\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{59\% of 640}}{\left( \cfrac{59}{100} \right)640}\implies 377.6[/tex]

Answer:

377.6

Step-by-step explanation:

640÷10=64 to find 10%

64×5=320 to find 50%

640÷100=6.4 to find 1%

6.4×9=57.6 to find 9%

320+57.6=377.6

answer: 377.6

Answer:

The range of the stock prices is from $10.82 to $33.17. To find the upper quartile, we need to find the value of the stock price that is greater than 75% of the data.

The distance between the minimum value and the maximum value is:

$33.17 - $10.82 = $22.35

To find the upper quartile, we need to find the value that is three-quarters of the distance above the minimum value:

$10.82 + 0.75($22.35) = $26.69

Therefore, the upper quartile of the stock price is $26.69.

To find the value above which the stock price is higher 25% of the time, we need to find the value that is 75% of the distance above the minimum value:

$10.82 + 0.25($22.35) = $15.62

Therefore, 25% of the time, the stock price is above $15.62.

To find the upper quartile, we need to first find the median of the stock prices, which is the value that divides the distribution into two equal parts. The midpoint of the distribution is:

Midpoint = (10.82 + 33.17) / 2 = 22.995

Now, we can find the upper quartile, which is the median of the upper half of the distribution. The upper half of the distribution ranges from the midpoint to the highest value of 33.17. Therefore, we calculate the median of this range as follows:

Upper quartile = (22.995 + 33.17) / 2 = 28.0825

So, the upper quartile of the stock prices is $28.08.

To find the value above which the stock is priced 25% of the time, we need to find the 75th percentile of the distribution. Since the distribution is uniform, we can use the formula for the percentile as follows:

Percentile rank = (percentile / 100) = (value - minimum) / (maximum - minimum)

Solving for the value, we get:

value = minimum + percentile rank x (maximum - minimum)

For the 75th percentile, we have:

value = 10.82 + 0.75 x (33.17 - 10.82) = 28.49

Therefore, the stock is priced above $28.49 on 25% of all days.

The quadratic equation is:

y = (149/1,800)*(x + 1)² + 2

Remember that if the parabola has a vertex (h, k) and a leading coefficient a can be written as:

y = a*(x - h)² + k

Here we know that the vertex is (-1, 2), then we will get the following equation:

y = a*(x + 1)² + 2

And we know it passes through (-14, - 153/8), then we will get:

-153/8 = a*(14 + 1)² + 2

-153/8 = a*225 + 2

a = (153/8 - 2)/225 =

a = 149/1,800

The quadratic is:

y = (149/1,800)*(x + 1)² + 2

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a) the journey took 11 hours and 50 minutes.

b)the average speed of the bus was 70.95 km/hour.

c) the cost of fuel for the journey was K240.08.

Distance is the measure of how far apart two objects or points are from each other. It is a scalar quantity, which means it only has magnitude and no direction. Distance is usually measured in units such as meters (m), kilometers (km), feet (ft), miles (mi), or any other appropriate unit of length.

a) convert the times to a 24-hour format to perform the calculation.

07:00 in 24-hour format is 07:00, and 18:50 in 24-hour format is 18:50.

The journey duration is:

18:50 - 07:00 = 11 hours and 50 minutes

Therefore, the journey took 11 hours and 50 minutes.

b) The average speed of the bus can be found by dividing the distance traveled by the time taken:

Average speed = Distance ÷ Time

= 840 km ÷ 11.83 hours (converted from 11 hours and 50 minutes)

= 70.95 km/hour

Therefore, the average speed of the bus was 70.95 km/hour.

c) The fuel consumption rate is 1 liter per 20 km. Therefore, the bus consumed 840 km / 20 = 42 liters of diesel fuel for the journey.

The cost of fuel can be calculated by multiplying the fuel quantity by the cost per liter:

Cost of fuel = Fuel quantity x Cost per liter

= 42 liters x K5.74/liter

= K240.08 (rounded to two decimal places)

Therefore, the cost of fuel for the journey was K240.08.

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The pressure exerted (in N/m²) by the box on the shelf given that the bottom of the box has an area of 0.30 m² and weighs 60 N, is 200 N/m²

Pressure is defined a force per unit area. Mathematically, it is written as

Pressure (P) = force (F) / area (A)

P = F / A

With the above formular, we can obtain the pressure exerted by the box as follow:

Pressure exerted (P) = Weight of box (W) / Area of box (A)

Pressure exerted = 60 / 0.30

Pressure exerted = 200 N/m²

Thus, we can conclude that the pressure exerted is 200 N/m²

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Complete question:

The area of the bottom of a tiffin box is 0.30 sq. m and weight is 60 N, Calculate the pressure exerted by the box on the shelf in N/sq. m *​

Answer:

3/20

Step-by-step explanation:

To find the product of 2/8 and 3/5, we simply multiply the numerators and the denominators:

(2/8) x (3/5) = (2 x 3) / (8 x 5) = 6/40

We can simplify this fraction by dividing both the numerator and denominator by their greatest common factor, which is 2:

6/40 = (6 ÷ 2) / (40 ÷ 2) = 3/20

Therefore, the product of 2/8 and 3/5 is 3/20.

Answer:

x = 26

Step-by-step explanation:

the 3 angles lie on the straight line DAC and sum to 180° , that is

4x - 8 + 34 + 76 - x = 180

3x + 102 = 180 ( subtract 102 from both sides )

3x = 78 ( divide both sides by 3 )

x = 26