Your friend makes a stem-and-leaf plot of the data. 51, 25, 47, 42, 55, 26, 50, 44, 55 Student work is shown. A stem and leaf plot. A vertical line separates each stem from its first leaf. The first row has a stem of 2 and leaves 5 and 6. The second row has a stem of 4 and leaves 2, 4, and 7. The third row has a stem of 5 and leaves 0, 1, 5, and 5. The key shows 4 vertical bar 2 is equal to 42. Is your friend correct? Responses yes yes no no Question 2 Explain your reasoning.

The estimated surface area of the bead is 52π square millimeters.

To estimate the  face area of the blob, we need to find the  face area of the sphere and abate the  face area of the spherical hole.   The  face area of a sphere is given by the formula   A =  4πr2   where r is the compass of the sphere.

 The radius of the sphere is: r = 8 mm / 2 = 4 mm.

The surface area of the sphere is: S_sphere = 4π[tex]r^{2}[/tex] = [tex]4π(4 mm)^{2}[/tex] =64 [tex]mm^{2}[/tex]

The radius of the cylinder is: r = 2 mm / 2 = 1 mm.

The height of the cylinder is: h = 8 mm - 2 mm = 6 mm.

The surface area of the cylinder is: S_cylinder = 2πrh = 2π(1 mm)(6 mm) = 12π [tex]mm^{2}[/tex]

The estimated surface area of the bead is: S_bead = S_sphere - S_cylinder = 64π [tex]mm^{2}[/tex] - 12π [tex]mm^{2}[/tex] = 52π [tex]mm^{2}[/tex]

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To find the critical numbers of h(x) = sin^2(x) + cos(x) in 0 < x < 2π steps are first to find the derivative h'(x), set h'(x) equal to zero and solve for x and check if solutions are within the given interval. The critical numbers are x = π, π/3, and 5π/3.

To find the critical numbers of the function h(x) = sin^2(x) + cos(x) in the interval 0 < x < 2π, we will follow these steps:

Find the derivative of the function, Set the derivative equal to zero and solve for x, Set h'(x) equal to zero and solve for x, Check if the solutions are within the given interval.
1: Differentiate h(x) with respect to x.
h'(x) = d(sin^2(x) + cos(x))/dx
Using chain rule, we get:
h'(x) = 2sin(x)cos(x) - sin(x)
2: Set h'(x) equal to zero and solve for x.
0 = 2sin(x)cos(x) - sin(x)
Factor out sin(x):
0 = sin(x)(2cos(x) - 1)
So, either sin(x) = 0 or 2cos(x) - 1 = 0.
3: Solve for x and check if the solutions are within the interval 0 < x < 2π.
For sin(x) = 0, x = π (since 0 < π < 2π).
For 2cos(x) - 1 = 0, cos(x) = 1/2.
x = π/3 and 5π/3 (since 0 < π/3 < 2π and 0 < 5π/3 < 2π).
Therefore, the critical numbers of the function h(x) = sin^2(x) + cos(x) in the interval 0 < x < 2π are x = π, π/3, and 5π/3.

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Answer:

609 pages

Hope this helps!

Step-by-step explanation:

9 books = 5481 pages

1 book = ? pages

9 books ÷ 9 = 1 book  so  5481 pages ÷ 9 = 609 pages

1 book has 609 pages.

Walter can stay within his budget by dropping Fes (option ii).

Walter's original itinerary includes trips to Marrakech, Fes, Kenitra, and Oujda, which will cost him a total of 478 + 478 + 778 + 683 = MAD 2,417. This exceeds his budget of MAD 2,500.

Option i suggests replacing Kenitra with Tangier and Oujda with Casablanca, which will cost a total of 610 + 466 + 610 + 466 = MAD 2,152. However, this still exceeds Walter's budget.

Option iii suggests replacing Marrakech with Casablanca, which will cost a total of 965 + 466 + 778 + 683 = MAD 2,892, which is over Walter's budget.

Therefore, the only option that allows Walter to stay within his budget is to drop Fes from his itinerary, which will cost a total of 478 + 778 + 683 = MAD 1,939. This is well within his budget of MAD 2,500. So optio 2 is correct.

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Now let's check if f(x) = g(h(x)):
gh(x)) = g(x + 1) = (x + 1)² + 1 = x² + 2x + 1 + 1 - 1 = x² + 2x + 1
The formulas for g(x) and h(x), which are g(x) = x² + 1 and h(x) = x + 1, such that their composition yields:

f(x) = g(h(x)) = x² + 2x + 1.

In both cases, we use the composition of functions f(x) = g(h(x)) to relate the functions g(x), h(x), and their inverses. These formulas allow us to find the other function given one of the functions in the composition.
Suppose we have the function f(x) = g(h(x)). Here, we have three functions: f(x), g(x), and h(x). We're given one of these functions and asked to find the formulas for the other two functions so that their composition results in f(x).

To find a formula for one of the functions in the composition f(x) = g(h(x)), we can substitute the other function into it and simplify.
(1) If we want to find a formula for g(x) given f(x) = g(h(x)), we can substitute h(x) for x in g(x), which gives us g(h(x)). This means that g(x) = f(h^{-1}(x)), where h^{-1}(x) is the inverse function of h(x).
(2) If we want to find a formula for h(x) given f(x) = g(h(x)), we can substitute g(x) for f(x) and solve for h(x). This gives us h(x) = g^{-1}(f(x)), where g^{-1}(x) is the inverse function of g(x).

Given: f(x) = x² + 2x + 1
We need to find the formulas for g(x) and h(x) such that f(x) = g(h(x)).
One possible choice for g(x) could be g(x) = x² + 1. Now we need to find the function h(x) such that when we compose g(h(x)), it results in f(x) = x² + 2x + 1.

To do this, we can see that g(x) has x² + 1, and f(x) has x² + 2x + 1. We need to add a term '2x' in the composition. Therefore, we can choose h(x) = x + 1.
Now, let's check if f(x) = g(h(x)):
g(h(x)) = g(x + 1) = (x + 1)² + 1 = x² + 2x + 1 + 1 - 1 = x² + 2x + 1

Thus, we have successfully found the formulas for g(x) and h(x), which are g(x) = x² + 1 and h(x) = x + 1, such that their composition yields f(x) = g(h(x)) = x² + 2x + 1.

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In factorization the needed observations and steps before you can factor a difference of two squares are binomial, two positive/negative, prime, multiply factors, and look for a GCF.

Finding the factors of a given number or statement is the process of factorization. Factorization is the process of taking a larger number or expression and turning it into a product of smaller numbers or expressions, or factors. The factors may be polynomials, integers, or other mathematical constructs.

Therefore, the needed observations and steps before you can factor a difference between two squares are:

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The turbocharged model is moving 41.25 ft/sec faster than the model with the standard engine at the end of the 11-second test run.

We need to find how much faster the turbo-charged model is moving than the model with the standard engine at the end of an 11-second test run at full throttle.

To find the final velocity of each model at the end of 11 seconds, we need to integrate their respective acceleration functions with respect to time from 0 to 11 seconds:

For the standard engine model:

v(t) = ∫(5 + 0.8t) dt = 5t + [tex]0.4t^2[/tex]

v(11) = 5(11) +[tex]0.4(11)^2[/tex] = 72.4 ft/sec

For the turbo-charged model:

v(t) = ∫(5 + 1.2t + 0.03[tex]t^2[/tex]) dt = 5t +[tex]0.6t^2 + 0.01t^3[/tex]

v(11) = 5(11) + [tex]0.6(11)^2 + 0.01(11)^3[/tex]= 113.65 ft/sec

The difference in final velocity between the two models is:

[tex]v_{turbo} - v_{standard[/tex] = 113.65 - 72.4 = 41.25 ft/sec

Therefore, the turbo-charged model is moving 41.25 ft/sec faster than the model with the standard engine at the end of the 11-second test run.

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The estimated mean interest rate for 60-month fixed-rate auto loans at lending institutions in the urban area is 3.59% (the calculated mean from the given data).

To calculate the estimated mean interest rate, we need to find the average of the interest rates provided by the 12 lending institutions. The given data is as follows:

3.25%, 3.50%, 3.75%, 3.25%, 3.80%, 3.90%, 3.95%, 3.75%, 3.40%, 3.50%, 3.60%, 3.65%

The mean is calculated by adding up all the interest rates and then dividing by the total number of rates. Therefore,

Mean = (3.25 + 3.50 + 3.75 + 3.25 + 3.80 + 3.90 + 3.95 + 3.75 + 3.40 + 3.50 + 3.60 + 3.65)/12

Mean = 3.59%

Hence, the estimated mean interest rate for 60-month fixed-rate auto loans at lending institutions in the urban area is 3.59%.

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This is an example of an experiment. In an experiment, researchers manipulate the independent variable (in this case, the presence or absence of an electrical impulse) to determine its effect on the dependent variable (the number of repetitions the subjects can lift a weight).

The researcher randomly assigned subjects to either receive the electrical impulse or not, which is a key feature of experimental design.

By doing so, the researcher can ensure that any differences observed between the two groups are due to the manipulation of the independent variable, rather than any pre-existing differences between the groups.

In contrast, an observational study merely observes existing characteristics or behaviors of a population, without any manipulation or control of variables.

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Answer:  Note that we used the table of general integration formulas to recognize that the integral of csc(x) dx is -       ln|csc(x) + cot(x)| + C.

Explanation:

To evaluate the indefinite integral of csc(x) cot(x) dx, we can use substitution.

Let u = cot(x), then du/dx = -csc^2(x) and dx = -du/csc^2(x).

Substituting these values in the integral, we get:  

∫ csc(x) cot(x) dx = ∫ -du/u = -ln|u| + C

Now substituting back u = cot(x),

we get: ∫ csc(x) cot(x) dx = -ln|cot(x)| + C

This is the final answer.

Note that we used the table of general integration formulas to recognize that the integral of csc(x) dx is -ln|csc(x) + cot(x)| + C. We then used the substitution technique and the general integration formula for ln|u| to arrive at the final answer.

(A). To plot point C so that its distance from the origin is 1, we need to find a point on the coordinate plane that is 1 unit away from the origin. One such point is (1, 0), which is located on the positive x-axis.

(B). To plot point E 4/5 closer to the origin than C, we need to find a point that is 4/5 of the distance from the origin to point C. Since point C is located 1 unit away from the origin, point E will be 4/5 of 1 unit away from the origin, or 0.8 units away.

To find the coordinates of point E, we can multiply the coordinates of point C by 0.8. If point C is (1, 0), then point E is (0.8, 0).

(C). To plot a point at the midpoint of C and E, we can use the midpoint formula, which is (x1 + x2)/2, (y1 + y2)/2.

The coordinates of point C are (1, 0) and the coordinates of point E are (0.8, 0), so the coordinates of point H are ((1 + 0.8)/2, (0 + 0)/2), or (0.9, 0). We can label this point H.

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The finance charge for a $7000 two year loan with a 6.75% APR is $945.

To determine the finance charge for a $7000 two year loan with a 6.75% APR, we need to use the following formula:

Finance charge = (Amount borrowed × Annual percentage rate) × Time period

Given that, the amount borrowed is $7000, the annual percentage rate (APR) is 6.75%, and the time period is two years.

First, we need to convert the APR to a decimal by dividing it by 100:

APR = 6.75%

APR = 6.75/100

APR = 0.0675

Now we can plug in the values into the formula:

Finance charge = (Amount borrowed × Annual percentage rate) × Time period

Finance charge = ( $7000 × 0.0675) x 2

Finance charge = $945

Therefore, the finance charge  is $945.

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The number of zeros are in the product of the number 50 and 6000 is 50 x 6000 = 300,000 are five.

Integers, natural numbers, fractions, real numbers, complex numbers, and quaternions are examples of typical special instances where it is possible to define the product of two numbers or the multiplication of two numbers.

A product is the outcome of multiplication in mathematics, or an expression that specifies the elements (numbers or variables) to be multiplied.

The commutative law of multiplication states that the result is independent of the order in which real or complex numbers are multiplied. The result of a multiplication of matrices or the elements of other associative algebras typically depends on the order of the components. For instance, matrix multiplication and multiplication in general in other algebras are non-commutative operations.

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The particular solution for f(x) is:

f(x) = (2/3)x³/² - (17/8)x + 2

We will integrate the given differential equation twice and use the initial conditions to find the constants of integration.

Given: f"(x) = 0.25x⁻³/²

Integrating once, we get:

f'(x) = ∫(0.25x⁻³/²) dx = 0.5x¹/² + C₁

where C₁ is the constant of integration.

Using the initial condition f'(4) = -1/8, we can solve for C₁:

f'(4) = 0.5(4)¹/² + C₁ = 2 + C₁ = -1/8

C₁ = -1/8 - 2 = -17/8

So,

f'(x) = 0.5x¹/² - 17/8

Integrating again, we get:

f(x) = ∫(0.5x¹/² - 17/8) dx = (2/3)x³/² - (17/8)x + C₂

where C₂ is the second constant of integration.

Using the initial condition f(0) = 2, we can solve for C₂:

f(0) = (2/3)(0)³/² - (17/8)(0) + C₂ = 2

C₂ = 2

So, the particular solution for f(x) is:

f(x) = (2/3)x³/² - (17/8)x + 2

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The experimental probability of the computer generating a 1 is D. 40 %.

First, add up the outcomes to see the total number of times the integers were generated ;

= 36 + 11 + 13 + 12 + 18

= 90

The number of times 1 was generated was 36.

The experimental probability is therefore;

= number of times 1 was generated / total number of outcomes

= 36 / 90

= 0. 4

= 40 %

Therefore, the experimental probability of the computer generating a 1 is 40 %.

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Your answer: a. $525

The "12 months is the same as cash" plan means that if you pay off the laptop within 12 months, you won't be charged any interest.

Since you plan to pay off the laptop in 11 months, which is within the 12-month period, you will not be assessed the 15.5 percent APR.

Therefore, you only need to pay the original cost of the laptop, which is $525.
To summarize, as long as you pay the full amount within the specified 12-month period, you avoid the additional interest charges. In this case, you will pay the laptop off in 11 months, so your total payment will be $525.

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Answer:

x = -10 (zeros), vertex = infinity..?

Step-by-step explanation:

The graph is a straight line, not a parabola. I would assume the vertex would be infinity, and the zeros would be x = -10.

a. To find the inverse function of f(x), we need to interchange the roles of x and y and solve for y. So, we have:

y = 1x - 3
x = 1y - 3
x + 3 = y
Therefore, the inverse function of f(x) is f^-1(x) = x + 3.
The domain of f^-1(x) is the range of f(x). Since f(x) = 1x - 3 is a linear function, its domain is all real numbers. Therefore, the range of f(x) is also all real numbers. In interval notation, we can write this as (-inf, inf).

The range of f^-1(x) is the domain of f(x). As we determined in part b, the domain of f(x) is all real numbers. Therefore, the range of f^-1(x) is also all real numbers. In interval notation, we can write this as (-inf, inf).
Hi! I'd be happy to help you with your question.
a. To find the inverse function of f(x) = 1x - 3, you can follow these steps:
1. Replace f(x) with y: y = 1x - 3
2. Swap x and y: x = 1y - 3
3. Solve for y: y = x + 3
So, the inverse function f^(-1)(x) = x + 3.
The domain of f^(-1) refers to the set of all possible x-values. Since the inverse function is a linear function with no restrictions, the domain of f^(-1) is all real numbers. In interval notation, this is written as (-∞, ∞).

c. The range of f^(-1) refers to the set of all possible y-values (output). Again, since it's a linear function with no restrictions, the range of f^(-1) is also all real numbers. In interval notation, this is written as (-∞, ∞).

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The fully expanded expression using logarithm properties is:

[tex]In(8x^2 - 72x + 112) = 2.079 + In(x - 2) + In(x –-7)[/tex]

To expand the given expression[tex]In(8x^2 - 72x + 112)[/tex], we can use the following logarithmic properties:

Product Rule: [tex]logb (xy) = logb x + logb y[/tex]

Quotient Rule: [tex]logb (x/y) = logb x - logb y[/tex]

Power Rule:[tex]logb (x^a) = a logb x[/tex]

We can first factor out a common factor of 8 from the expression inside the logarithm:

[tex]In(8x^2 - 72x + 112) = In[8(x^2 - 9x + 14)][/tex]

Using the distributive property, we can expand the expression inside the logarithm:

[tex]In[8(x^2 - 9x + 14)] = In(8) + In(x^2 - 9x + 14)[/tex]

Now, we need to expand the second logarithm. We notice that the expression inside the logarithm can be factored as follows:

[tex]x^2 - 9x + 14 = (x - 2)(x - 7)[/tex]

Using the product rule, we can write:

[tex]In(x^2 - 9x + 14) = In[(x - 2)(x - 7)][/tex]

[tex]= In(x - 2) + In(x - 7)[/tex]

Putting all the pieces together, we get:

[tex]In(8x^2 - 72x + 112) = In(8) + In(x^2 - 9x + 14)[/tex]

[tex]= In(8) + In(x -2) + In(x - 7)[/tex]

Finally, we can simplify the numerical expression In(8) by using the fact that ln(e) = 1:

[tex]In(8) = ln(8)/ln(e) = 2.079/1 = 2.079[/tex]

So the fully expanded expression using logarithm properties is:

[tex]In(8x^2 - 72x + 112) = 2.079 + In(x - 2) + In(x -7)[/tex]

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The rate of the boat in still water is 5 miles per hour and rate of the boat in current is 3 miles per hour.

Let us represent the rate of boat in still water hence and rate of boat in current be y. Also, we know that speed = distance/time. Hence, keep the values in formula -

Converting mixed fraction to fraction, time = 3/2 hour

Time = 1.5 hour

1.5 (x + y) = 12 : equation 1

Divide the equation 1 by 3

0.5 (x + y) = 4 : equation 2

6 (x - y) = 12 : equation 3

Divide the equation 3 by 6

(x - y) = 2

x = 2 + y : equation 4

Keep the value of x from equation 4 in equation 2

0.5 (2 + y + y) = 4

1 + y = 4

y = 4 - 1

y = 3 miles/ hour

Keep the value y in equation 4 to get x

x = 2 + 3

x = 5 miles per hour

The rate in still water and current is 5 and 3 miles per hour.

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The complete question is-

It takes a boat 1 (1/2) hr to go 12 mi downstream, and 6 hr to return. Find the rate of the boat in still water and the rate of the current.

The equation of the plotted absolute value function graph is

y = |x - 1| - 1

The equation of the graph which is a graph of absolute value function is solved using transformation

The parents equation or original equation is

y = |x|

Then a shift 1 unit to the right direction is gotten by

y = |x - 1|

The second transformation is a downward shift of 1 unit, this results to the equation of the form

y = |x - 1| - 1

The graph is potted and attached

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The area of the first triangle is 0 square feet.

To find the area of the first triangle with the given side lengths of 1 ft, 3 ft, and 4 ft, you can use Heron's formula.

Calculate the semi-perimeter (s) of the triangle:
s = (a + b + c) / 2
where a, b, and c are the side lengths of the triangle.
s = (1 + 3 + 4) / 2 = 8 / 2 = 4 ft

Apply Heron's formula to find the area (A) of the triangle:
A = √(s * (s - a) * (s - b) * (s - c))
A = √(4 * (4 - 1) * (4 - 3) * (4 - 4))
A = √(4 * 3 * 1 * 0)
A = √0 = 0

The area of the first triangle is 0 square feet. This means that the given side lengths do not form a valid triangle, as two sides' lengths (1 ft and 3 ft) do not add up to be greater than the length of the third side (4 ft).

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The first 10 iterations of Newton's method for f(x) = 2 sin x + 3x + 3, with initial approximation x₀ = 15, are approximately 8.156, 6.099, 5.091, 4.941, 4.929, 4.929, 4.929, 4.929, 4.929, 4.929

The first 10 iterations of Newton's method for the given function and initial approximation

x₁ = x₀ - f(x₀)/f'(x₀) = 15 - (2sin(15) + 45) / (2cos(15) + 3) ≈ 8.156

x₂ = x₁ - f(x₁)/f'(x₁) ≈ 6.099

x₃ = x₂ - f(x₂)/f'(x₂) ≈ 5.091

x₄ = x₃ - f(x₃)/f'(x₃) ≈ 4.941

x₅ = x₄ - f(x₄)/f'(x₄) ≈ 4.929

x₆ = x₅ - f(x₅)/f'(x₅) ≈ 4.929

x₇ = x₆ - f(x₆)/f'(x₆) ≈ 4.929

x₈ = x₇ - f(x₇)/f'(x₇) ≈ 4.929

x₉ = x₈ - f(x₈)/f'(x₈) ≈ 4.929

x₁₀ = x₉ - f(x₉)/f'(x₉) ≈ 4.929

Therefore, the first 10 iterations are 8.156, 6.099, 5.091, 4.941, 4.929, 4.929, 4.929, 4.929, 4.929, 4.929

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1. Chelsea Menken's debt-to-income ratio is 35.7%.

2. Her debt situation is concerning because she accumulated significant student loan debt and credit card debt.

The debt-to-income ratio means percentage of gross monthly income that goes to paying your monthly debt payments

Her total monthly debt payments is:

= $385 (Student loans) + $240 (Credit card) + $1,100 (Rent)

= $1,725.

Her total monthly income after taxes is:

= $58,000 / 12 months

= $4,833.33 per month.

The debt-to-income ratio will be:

= Total monthly debt payments / Monthly income after taxes

= $1,725 / $4,833.33

= 0.357

= 35.7%.

Her debt situation is concerning, so, it important for to develop a plan to pay off the debts in order to avoid accruing more interest and damaging her credit score.

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The equation is P = [tex]25cos(0.224t) + 50[/tex], where P represents the percentage of the moon's surface visible and t is the number of days since the moon was full.

To determine an equation for the percentage of the moon's surface visible as a function of the number of days since the moon was full, we can use the cosine function [tex]P = Acos(Bt) + C[/tex], where P represents the percentage visible, t is the number of days since full moon, A is the amplitude, B is the frequency, and C is the vertical shift.

Given that the maximum percentage visible is 50%, we know that C = 50. The period of the function is 28 days, so we can calculate B using the formula B = 2π/period = 0.224. The amplitude A can be calculated as half of the maximum percentage visible, or A = 25.

Therefore, the equation for the percentage of the moon's surface visible as a function of the number of days since full moon is P = 25cos(0.224t) + 50.

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It's arithmetic and the common difference should be -4.

Arithmetic = Adding/Subtracting

Geometric = Multiplying/Dividing

The sequence is a steady decline of subtracting 4.

Ishaan's current age is 84.

Let Ishaan's current age be I and Christopher's current age be C.

Given, I = 2C ...........(1) (Ishaan is twice the age of Christopher)

35 years ago, I - 35 = 7(C - 35) (Ishaan was 7 times the age of Christopher 35 years ago)

Simplifying the above equation, we get:

I - 35 = 7C - 245

I = 7C - 210 ...........(2)

Substituting equation (1) in equation (2), we get:

2C = 7C - 210

5C = 210

C = 42

Therefore, Christopher's current age is 42.

Substituting C = 42 in equation (1), we get:

I = 2C = 2(42) = 84

Therefore, Ishaan's current age is 84.

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The question is translated to English as

Ishaan is twice the age of Christopher. 35 years ago Ishaan was 7 times the age of Christopher. How old is Ishaan now?

Step-by-step explanation:

we only need to calculate directly the work hours needed for 10 child bikes and 12 adult bikes.

as a child bikes needs 4 hours to build and 4 hours to test, for 10 child bikes that means 10×4 = 40 hours to build and 40 hours to test

an adult bike needs 6 hours to build and 4 his to test.

so, for 12 bikes that are 12×6 = 72 hours to build and 12×4 = 48 hours to test.

together that means we need

40 + 72 = 112 hours to build

40 + 48 = 88 hours to test

the limits of the company are 120 build hours and 100 test hours per week.

as 112 < 120 and 88 < 100, yes, the company can build 10 child bikes and 12 adult bikes in one week.

in fact, with that they still have 8 work hours (120 - 112) and 12 test hours (100 - 88) left and could therefore build either 2 additional child bikes (8 build hours, 8 test hours) or one additional adult bike (6 build hours, 4 test hours).

They have total of 70 dolls together.

Let the initial number of dolls Jack had be 5x and the number Peter had be 2x.

After Jack gave Peter 15 dolls, their amounts became equal. So, we can write the equation: 5x - 15 = 2x + 15

Now, solve the equation for x: 5x - 2x = 15 + 15, which simplifies to 3x = 30

Divide both sides by 3: x = 10

Now, find the initial number of dolls they had: Jack had 5x = 5(10) = 50 dolls, and Peter had 2x = 2(10) = 20 dolls.

After Jack gave Peter 15 dolls, both had 35 dolls (50 - 15 = 35, and 20 + 15 = 35).

So, together they have 35 + 35 = 70 dolls.

To learn more about number:  https://brainly.com/question/20400557

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Let's represent the width of the rectangular course as $w$. Then the length of the rectangular course can be represented as $2w$, since the ratio of the length to the width is given as 2:1.

We know that the total length of the course is 2.4 kilometers, so we can write an equation:

$\sf\implies\:2w + 2(2w) = 2.4$

Simplifying the equation:

$\sf\implies\:6w = 2.4$

$\sf\implies\:w = \frac{2.4}{6}$

$\bigstar\implies\sf{\textbf{\boxed{w = 0.4}}}$

Therefore, the width of the course is 0.4 kilometers.

The length of the course is $\sf\:2w = 2(0.4)=$

${\boxed{\sf{0.8 kilometers.}}}$

Hence, the length of the course is 0.8 kilometers and the width of the course is 0.4 kilometers.

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[tex]\begin{align}\colorbox{black}{\textcolor{white}{\underline{\underline{\sf{Please\: mark\: as\: brillinest !}}}}}\end{align}[/tex]

[tex]\textcolor{lime}{\small\textit{If you have any further questions, feel free to ask!}}[/tex]

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