This function is not differentiable at all points in [tex]R^2[/tex]. To see this, consider the points on the x-axis, where y = 0. At these points, the function is not differentiable because it has a sharp corner.
To show that the function f(x, y) = |y| is differentiable at (0, 0), we need to show that there exists a linear transformation L such that:
[tex]lim (h,k) - > (0,0) [f(0+h,0+k) - f(0,0) - L(h,k)] / \sqrt{(h^2 + k^2)} = 0[/tex]
where f(0,0) = 0 since |0| = 0.
We have:
f(0+h,0+k) - f(0,0) = |k|
Now we need to find L(h,k), which is a linear transformation of (h,k) that approximates f(0+h,0+k) - f(0,0) near (0,0). We can take:
L(h,k) = 0
Since L is a constant function, it is a linear transformation. Also, we have:
f(0+h,0+k) - f(0,0) - L(h,k) = |k|
So we have:
[tex]lim (h,k) - > (0,0) [f(0+h,0+k) - f(0,0) - L(h,k)] / \sqrt{(h^2 + k^2) } = lim (h,k) - > (0,0) |k| / \sqrt{(h^2 + k^2)}[/tex]
Using the squeeze theorem, we can show that this limit is equal to 0, since[tex]|k| < = \sqrt{(h^2 + k^2)}[/tex] for all (h,k) and[tex]lim (h,k) - > (0,0)\sqrt{ (h^2 + k^2) } = 0.[/tex]
Therefore, f(x, y) = |y| is differentiable at (0,0).
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how much money do winners go home with from the television quiz show jeopardy? to determine an answer, a random sample of winners was drawn and the amount of money each won was recorded and listed below. estimate with 98% confidence the mean winning's for all the show's players. 256592886121164159762297615479276802828316105181371690216879240102008815149
The mean winnings for all of the show's contestants can be estimated with 92% certainty. 35014.48385 is the lower bound, while 40669.38281 is the upper bound.
Lower Bound = [tex]X - t(\alpha/2) * s / \sqrt{(n)[/tex]
Upper Bound = [tex]X + t(\alpha/2) * s / \sqrt{(n)[/tex]
where
[tex]\alpha/2 = (1 - confidence\: level)/2 = 0.04 \\ X = sample\: mean = 37841.93333 \\ t(\alpha/2) = critical\: t \:for \:the\: confidence\: interval = 1.887496145 \\ s = sample\: standard\: deviation = 5801.688541 n = sample\: size = 15 \\ df = n - 1 = 14[/tex]
Thus,
Lower bound = 35014.48385
Upper bound = 40669.38281
A lower bound refers to the smallest possible value or limit that a given quantity or parameter can take. In various fields of mathematics and computer science, lower bounds are used to establish limits on the performance of algorithms, the complexity of computational problems, and the amount of resources required to solve a problem. This information can be useful in developing more efficient algorithms or determining the practicality of a given approach.
Lower bounds are useful for understanding the fundamental limits of a system or process. By establishing a lower bound, researchers and practitioners can better understand the potential of a given technology or approach, and can work to optimize it within the constraints imposed by the lower bound.
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Complete Question:-
How much money do winners go home with from the television quiz show Jeopardy? To determine an answer, a random sample of winners was drawn and the amount of money each won was recorded and listed below. Estimate with 92% confidence the mean winning's for all the show's players.
30692 43231 48269 28592 28453
36309 45318 36362 42871 39592
35456 40775 36466 36287 38956
Lower confidence level (LCL) = ?
Upper confidence level (UCL) = ?
solve the equation
(2\3)to the power of X=16\81
3. (3 points) For ordinary differential equation
X =1- ƛx³6
with ƛ > 0, compute the update Ax= x(t+h) - x(t) using
⚫ Euler's method
⚫ the implicit Euler method
⚫ the midpoint method.
The following are the updates for the given ordinary differential equation using Euler's method, the implicit Euler method, and the midpoint method.
To compute the update Ax for the given ordinary differential equation using Euler's method, we first need to discretize the time domain. Let t0 be the initial time and tn = t0 + nh be the time after n steps of size h. Then, using Euler's method, we have:
xn+1 = xn + hf(xn, tn)
where f(xn, tn) = 1 - ƛxn³/6. Therefore,
Ax = xn+1 - xn = h(1 - ƛxn³/6)
Using the implicit Euler method, we have:
xn+1 = xn + hf(xn+1, tn+1)
where f(xn+1, tn+1) = 1 - ƛxn+1³/6. Solving for xn+1, we get:
xn+1 = (xn + h)/[1 + ƛh/6(xn+1)²]
which is a nonlinear equation that needs to be solved iteratively at each step. Therefore, the update Ax becomes:
Ax = xn+1 - xn
Using the midpoint method, we have:
xn+1 = xn + hf(xn+½h, tn+½h)
where f(xn+½h, tn+½h) = 1 - ƛ(xn+½h)³/6. Therefore,
xn+1 = xn + h(1 - ƛxn³/6 + 3ƛx²n h/4)
and the update Ax becomes:
Ax = xn+1 - xn = h(1 - ƛxn³/6 + 3ƛx²n h/4)
These are the updates for the given ordinary differential equation using Euler's method, the implicit Euler method, and the midpoint method.
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a machine in a manufacturing plant has on the average two breakdowns per month. find the probability that during the next three months it has (a) at least five breakdowns, (b) at most eight breakdowns, (c) more than five breakdowns.
The probability that during the next three months it has;
(a) at least five breakdowns is 0.036.(b) at most eight breakdowns is 0.00085.(c) more than five breakdowns is 0.012.Probability refers to potential. A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1. Mathematics has included probability to forecast the likelihood of certain events.
The degree to which something is likely to happen is basically what probability means. You will understand the potential outcomes for a random experiment using this fundamental theory of probability, which is also applied to the probability distribution.
The plant has on the average two breakdowns per month,
so the Poisson distribution is,
[tex]P(X=k) = \frac{e^{-\lambda} \lambda^k}{k!}[/tex]
where,
X is the random variable representing the number of events
λ is the average rate at which the events occur
k is the number of events that occur
a) at least five breakdowns
[tex]P(X=k) = \frac{e^{-\lambda} \lambda^k}{k!}[/tex]
P(X =5) = [tex]\frac{e^{-2} 2^5}{5!}[/tex]
= 0.036
Thus, probability that at least five breakdowns in three months is 0.036.
b) at most eight breakdowns
[tex]P(X=k) = \frac{e^{-\lambda} \lambda^k}{k!}[/tex]
[tex]P(X=8) = \frac{e^{-2} 2^8}{8!}[/tex]
= 0.00085.
Therefore, probability of at most eight breakdowns is 0.00085.
c) more than five breakdowns.
[tex]P(X=k) = \frac{e^{-\lambda} \lambda^k}{k!}[/tex]
P(X = 6) = [tex]\frac{e^{-2} 2^6}{6!}[/tex]
=0.012
Therefore, probability of more than five breakdowns is 0.012.
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Complete the sentence.
The focus so far has been on similar triangles, but there are also theorems that deal with similar
The focus so far has been on similar triangles, but there are also theorems that deal with similar polygon
Completing the sentenceTheorems of similar triangles are important properties that hold true for any pair of similar triangles. Some of the most commonly used theorems are:
AA Similarity Theorem: If two angles of one triangle are congruent to two angles of another triangle, then the triangles are similar.
SSS Similarity Theorem: If the three sides of one triangle are proportional to the three corresponding sides of another triangle, then the triangles are similar.
SAS Similarity Theorem: If two sides of one triangle are proportional to two sides of another triangle and the included angles are congruent, then the triangles are similar.
These theorems are also applicable to similar polygons
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The focus so far has been on similar triangles, but there are also theorems that deal with similar polygons.
HELP PLEASE BRAINLIEST + POINTS
Answer:
CD = 34 units--------------------------
Since CD is diameter, therefore the angle CAD opposite to it is a right angle.
We are given the lengths of two legs, AD = 16 and AC = 30.
Use Pythagorean theorem to find the length of the hypotenuse CD:
CD² = AD² + AC²CD² = 16² + 30²CD² = 1156CD = √1156CD = 34Find the sum of first seven terms of 5+11+17......
Step-by-step explanation:
d = a2 - a1
d = 11 - 5
d = 6
[tex]Sn \: = \frac{n}{2} (2a1 + (n - 1)d) \\ S7 = \frac{7}{2} (2 \times 11 + (7 - 1)6) \\ S7 = \frac{7}{2} (22 + 36) \\ S7 = \frac{7}{2} \times 58 \\ S7 = 7 \times 29 \\ S7 = 203[/tex]
#CMIIWPls help me find the exponent
Answer:
1.6 × 10^4
Step-by-step explanation:
(My question has a part A and part B)
The salesperson earns a 5%
commission on the first $5000
she has in sales. • The salesperson earns a 7. 5%
commission on the amount of her sales that are greater than.
Part A
This month the salesperson had $1,375
in sales. What amount of commission, in dollars, did she earn?
A) The total commission she earned is $475
B) Total sales for commission of $1375 is $20000
How to calculate the amount of commission?A) Total Commission = Commission 1+ Commission 2
Where:
Commission 1 = 5% of first $5000
Commission 2 = 7.5% of the amount left after $5000 is subtracted
thus
Commission 1 = $5000 * 0.05 = $250
Commission 2= $3000 * 0.075 = $225
Commission total = $250 + $225 = $475
The total commission she earned is $475
B) Total sales = Sales with 5% commission + Sales with 7.5% commission
Sales with 5% commission = $5000
Commission At 7.5% = Total commission -Commission with 5% = $1375 - $250
Sales * 0.075 = $1125
Sales with 7.5% commission = $15000
Total sales = $5000+$15000
Total sales = $20000
Total sales for commission of $1375 is $20000
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Complete question is:
A salesperson earns commission on the sales that she makes each month. The salesperson earns a 5% commission on the first $5,000 she has in sales.
The salesperson earns a 7.5% commission on the amount on her sales that are greater than $5,000.
Part A:
This month the salesperson had $8,000 in sales. What amount of commission, in dollars, did she earn?
Part B:
The salesperson earned $1,375 in commission, last month. How much money, in dollars, did she have in sales last month?
A bag contains 4 white, 3 blue, and 5 red marbles. Find the probability of choosing a red marble, then a white marble if the marbles were replaced.
The probability of choosing a red marble, then a white marble is 5/36
Finding the probability of choosing a red marble, then a white marbleFrom the question, we have the following parameters that can be used in our computation:
A bag contains 4 white, 3 blue, and 5 red marbles
If the marbles were replaced, then we have
P(Red) = 5/12
P(White) = 4/12
So, we have
The probability of choosing a red marble, then a white marble is
P = 5/12 * 4/12
Evaluate
P = 5/36
Hence, the probability of choosing a red marble, then a white marble is 5/36
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Nicole has 28 nickels and dimes that amount to $1. 85 how many of each coin does she have
Answer:
Nicole has 9 dimes and 19 nickels.
Which correctly compares the numbers? 158,364 > 158,379 > 158,397 158,364 > 158,379 > 158,397 518,317 > 518,246 > 518,197 518,317 > 518,246 > 518,197 290,061 > 289,937 > 290,324 290,061 > 289,937 > 290,324 678,200 > 678,194 > 678,227
The correct comparison of the numbers is:
678,200 > 678,194 > 678,227
Therefore, the answer is the last option, "678,200 > 678,194 > 678,227".
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If f(x) = 3(5") + x and g(x) = 3cos(x), what is (f9)'()? O (3(5*) In(5) + 1)(3cos(x)) + (3(5") + x)(sin(x)) O (3(5") In(5) + 1)(3sin(x)) O (3(5") In(5) + 1)(-3sin(x)) O (3(5) In(5) + 1)(3cos(x)) + (3(5") + x)(-3sin(x))
The derivative of (f∘g)(x) can be found using the chain rule, which states that the derivative of (f∘g)(x) is (f'(g(x)))(g'(x)).
In this case, (f∘g)(x) = f(g(x)) = 3(5^x) + 3cos(x), so we need to find f'(g(x)) and g'(x) and then multiply them together. The derivative of f(x) is f'(x) = 15^x * ln(5) + 1, so the derivative of f(g(x)) with respect to g(x) is f'(g(x)) = 15^(g(x)) * ln(5) + 1. The derivative of g(x) is g'(x) = -3sin(x). Therefore, using the chain rule, we have:(f∘g)'(x) = f'(g(x)) * g'(x) = (15^(g(x)) * ln(5) + 1) * (-3sin(x))Substituting g(x) = 3cos(x), we get:(f∘g)'(x) = (15^(3cos(x)) * ln(5) + 1) * (-3sin(x))So the correct answer is: (3(5^3cos(x)) ln(5) + 1) * (-3sin(x))
For more similar questions on topic a) The intervals for which f(x) = -5.5sin(x) + 5.5cos(x) is concave up and concave down on [0,2π] can be found by analyzing the second derivative of the function. Taking the second derivative of f(x), we get:
f''(x) = -5.5cos(x) - 5.5sin(x)
To find the intervals of concavity, we need to determine where f''(x) is positive and negative.
When f''(x) > 0, the function is concave up. When f''(x) < 0, the function is concave down.
Setting f''(x) = 0, we get:
-5.5cos(x) - 5.5sin(x) = 0
Simplifying, we get:
cos(x) + sin(x) = 0
Solving for x, we get:
x = 3π/4, 7π/4
These are the possible points of inflection for the function.
Using test intervals, we can determine the intervals of concavity:
When 0 ≤ x < 3π/4 or 7π/4 < x ≤ 2π, f''(x) < 0, so f(x) is concave down.
When 3π/4 < x < 7π/4, f''(x) > 0, so f(x) is concave up.
b) The possible points of inflection for f(x) on [0,2π] are x = 3π/4 and x = 7π/4. To find the coordinates of these points, we can substitute each value of x into the original function f(x):
f(3π/4) = -5.5sin(3π/4) + 5.5cos(3π/4) = 5.5√2 - 5.5√2/2 = 5.5√2/2
So the coordinates of the point of inflection at x = 3π/4 are (3π/4, 5.5√2/2).
Similarly, we can find the coordinates of the point of inflection at x = 7π/4:
f(7π/4) = -5.5sin(7π/4) + 5.5cos(7π/4) = -5.5√2 - 5.5√2/2 = -5.5(3/2)√2
So the coordinates of the point of inflection at x = 7π/4 are (7π/4, -5.5(3/2)√2).
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Find the divergence of vector fields at all points where they are defined.
div ( (2x^2 - sin(x2)) i + 5] - (sin(X2)) k)
The divergence of the given vector field at all points where it's defined is div [tex]F = 4x - 2x × cos(x^2).[/tex]
To find the divergence of the given vector field at all points where it's defined, we will use the following terms:
divergence, vector field, and partial derivatives.
The given vector field is[tex]F = (2x^2 - sin(x^2)) i + 5j - sin(x^2) k.[/tex]
To find the divergence of F (div F), we need to take the partial derivatives of each component with respect to their
respective variables and then sum them up. So, div [tex]F = (∂(2x^2 - sin(x^2))/∂x) + (∂5/∂y) + (∂(-sin(x^2))/∂z)[/tex].
Find the partial derivative of the first component with respect to x:
[tex]∂(2x^2 - sin(x^2))/∂x = 4x - 2x × cos(x^2)[/tex] (applying chain rule).
Find the partial derivative of the second component with respect to y:
∂5/∂y = 0 (since 5 is a constant).
Find the partial derivative of the third component with respect to z:
[tex]∂(-sin(x^2))/∂z = 0[/tex] (since there is no z variable in the component).
Sum up the partial derivatives:
[tex]div F = (4x - 2x × cos(x^2)) + 0 + 0 = 4x - 2x × cos(x^2).[/tex]
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Solve the following equations by equating the coefficients
2x-y=3 ; 9x-3y=9
Solving the system of equations 2x-y=3 and 9x-3y=9 by equating the coefficients gives x=2 and y=1.
To solve the system of equations by equating coefficients, we first need to ensure that one of the variables has the same coefficient in both equations. In this case, we can multiply the first equation by 3 to get 6x-3y=9.
Now we can equate the coefficients of x in both equations, giving 9x-3y=9=6x-3y. Simplifying this equation, we get 3x=3, or x=1. Substituting this value of x into either equation gives y=2x-3=2(1)-3=-1. Therefore, the solution to the system of equations is x=2 and y=1.
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Hunter needs 10 ounces of a snack mix that is made up of seeds and dried fruit. the
seeds cost $1.50 per ounce and dried fruit costs $2.50 per ounce. hunter has $22
to spend and plans to spend it all.
let x = the amount of seeds
let y = the amount of dried fruit
part 1: create a system of equations to represent the scenario. (2 points)
part 2: solve your system using any method. write your answer as an ordered pair. (2
points)
Hunter needs 3 ounces of seeds and 7 ounces of dried fruit, which will cost him $22 in total. The system of equations is 1.5x + 2.5y = 22 and x + y = 10. The solution is (x,y) = (3,7).
The total amount of snack mix required is 10 ounces. So, the sum of the amount of seeds and dried fruit should be 10.
x + y = 10 ---(Equation 1)
The cost of seeds is $1.50 per ounce and the cost of dried fruit is $2.50 per ounce. The total cost of snack mix should be $22.
1.50x + 2.50y = 22 ---(Equation 2)
To solve the system, we can use substitution method. Solving Equation 1 for y, we get
y = 10 - x
Substituting this value of y in Equation 2, we get
1.5x + 2.5(10 - x) = 22
Simplifying and solving for x, we get
1.5x + 25 - 2.5x = 22
-x = -3
x = 3
So, Hunter needs 3 ounces of seeds and 7 ounces of dried fruit to make 10 ounces of snack mix with a total cost of $22.
The ordered pair is (3, 7).
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BRANLYIST IF YOU ASWER ALL 5 RIGHT
1. How many students chose walking as their preferred method of transportation?
A 6
B 3
C 9
D none of these
2. How many total students participated in the survey?
A 10
B 20
C 15
D none of these
3. What percentage of the total students chose skateboarding?
A 10%
B 20%
C 30%
D none of these
4. What percentage of the boys chose walking?
A 30%
B 45%
C 25%
D none of these
5. What percentage of the students who chose biking were girls?
A 30%
B 37. 5%
C 45%
D none of these
1. The number of students choosing walking as their preferred method of transportation is 9. Therefore, the correct option is C.
2. The total students participated in the survey are 20. Therefore, the correct option is B.
3. The percentage of the total students choosing skateboarding is 10%. Therefore, the correct option is A.
4. The percentage of the boys choosing walking is 30%. Therefore, the correct option is A.
5. The percentage of the students who chose biking were girls is 37.5%. Therefore, the correct option is B.
1. The number of students who chose walking as their preferred method of transportation based on the information provided is 9. The total number of students who chose walking is given as 9 (3 boys + 6 girls). Hence the correct answer is option C.
2. The total students who participated in the survey based on the information provided are 20. The total number of students is given as 20 (10 boys + 10 girls). Hence the correct answer is option B.
3. The percentage of the total students who chose skateboarding based on the information provided is 10%. 3 students chose skateboarding out of 20 total students, so the percentage is (3/20) * 100% = 10%. Hence the correct answer is option A.
4. The percentage of the boys who chose walking based on the information provided is 30%. 3 boys chose walking out of 10 total boys, so the percentage is (3/10) * 100% = 30%. Hence the correct answer is option A.
5. The percentage of the students who chose biking were girls based on the information provided is 37.5%. 3 girls chose biking out of 8 total students who chose biking, so the percentage is (3/8) * 100% = 37.5%. Hence the correct answer is option B.
Note: The question is incomplete. The complete question probably is: Given the following data:
Activity Boys Girls Total
Walk 3 6 9
Bike 5 3 8
Skateboard 2 1 3
Total 10 10 20
1. How many students chose walking as their preferred method of transportation? A. 6 B. 3 C. 9 D. none of these. 2. How many total students participated in the survey? A. 10 B. 20 C. 15 D. none of these 3. What percentage of the total students chose skateboarding? A. 10% B. 20% C. 30% D. none of these. 4. What percentage of the boys chose walking? A. 30% B. 45% C. 25% D. none of these. 5. What percentage of the students who chose biking were girls? A. 30% B. 37. 5% C. 45% D. none of these.
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Consider the histogram shown in the figure.
Which best describes the histogram?
Skewed left
Skewed right
symmetric
Vertical
Thank you!!!
It is kinda hard but just try it
Answer:
we 1st can get the weight of rat by
1 rat and 1 cat + 1 dog and rat = 30
2 rat + 1 cat + 1 dog = 30
Then 1 rat and cat measure 24 so
2 rat + 24 =30
2 rat + 24 =30 1 rat = 3 kg
2 rat + 24 =30 1 rat = 3 kg 1 cat + 1 rat = 10
2 rat + 24 =30 1 rat = 3 kg 1 cat + 1 rat = 101 cat + 3kg = 10
2 rat + 24 =30 1 rat = 3 kg 1 cat + 1 rat = 101 cat + 3kg = 101 cat = 7kg and
2 rat + 24 =30 1 rat = 3 kg 1 cat + 1 rat = 101 cat + 3kg = 101 cat = 7kg and 1 dog + 1 rat = 20 kg
2 rat + 24 =30 1 rat = 3 kg 1 cat + 1 rat = 101 cat + 3kg = 101 cat = 7kg and 1 dog + 1 rat = 20 kg 1 dog + 3kg = 20 kg
2 rat + 24 =30 1 rat = 3 kg 1 cat + 1 rat = 101 cat + 3kg = 101 cat = 7kg and 1 dog + 1 rat = 20 kg 1 dog + 3kg = 20 kg 1 dog = 17kg
so we get the weight of each now we r going to sum them 1 rat + 1 cat + 1 dog = x
1 rat + 1 cat + 1 dog = x 3 kg + 7 kg + 17 kg = x
1 rat + 1 cat + 1 dog = x 3 kg + 7 kg + 17 kg = x 27 kg = x ..... is the mass of 3 of them
Research on the major types of businesses in your province. Based from the data you have gathered, create 1 revenue problem involving quadratic functions.
The top industries are agriculture, mining, tourism, and manufacturing.
The quadratic equations are as given.A manufacturing company in my fiefdom produces and sells ceramic pots.
The company has fixed costs of$ 10,000 per month and variable costs of$ 5 per pot. The company's profit is given by the quadratic function R( x) = -0.2 x2 50x, where x is the number of pots produced and vended in a month.
What's the maximum profit that the company can induce in a month: To break this problem, we can use the formula for chancing the maximum value of a quadratic function, which is given by x = - b/ 2a. In this case, the measure of the x2 term is-0.2, and the measure of the x term is 50. Plugging these values into the formula, we get x = -50/( 2 *(-0.2)) = 125 Hence we obtain the quadratic equation.
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The mean number of sit-ups
done by a group of students is
46 with a standard deviation
of 7. If Rylee's Z-score was
1. 8, how many sit ups did she
do?
Rylee did approximately 58.6 sit-ups.
We are given that the mean number of sit-ups is 46 and the standard deviation is 7. We are also given that Rylee's Z-score was 1.8, we can use the formula for Z-score to find how many sit-ups she did.
The formula for Z-score is [tex]Z = \frac{X-\mu}{\sigma}[/tex]
Z = Z-score
μ = mean
σ = standard deviation
X = ?
Substituting these values into the formula
1.8 = (X - 46)/7
1.8 × 7 = X - 46
X - 46 = 12.6
X = 12.6 + 46
X = 58.6
Therefore, Rylee did approximately 58.6 sit-ups.
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Your parents decide that they will help you out the first two months you are at college
by helping you buy groceries for your meals, but they won't cover the cost of you going
out to eat at restaurants or fast food.
for the first month you submit your receipts, 13 are for fast food and four for kroger, and
totaled $487. the second month you submit receipts for six fast food meals and two for
kroger, and totaled $232. the receipts do not list the per-item price.
a. write the two equations for the cost of buying groceries and meals. (4 points)
• 13f + 4k = 487
• 65+2k = 232
i
b. what were the average costs of one fast food meal and of one trip to kroger?
show your work and justify your thinking. (6 points)
a. The two equations for the cost of buying groceries and meals are 13f + 4k = 487 and 65+2k = 232
b. The average costs of one fast food meal and of one trip to kroger is $77.33
To calculate the average cost, we divide the total cost by the number of meals or trips. For example, in the first month, the total cost of fast food meals and grocery trips was $487, and there were 13 fast food meals and 4 grocery trips. Therefore, the average cost of a fast food meal can be calculated by dividing the total cost of fast food meals ($487) by the number of fast food meals (13):
Average cost of a fast food meal = $487 / 13 = $37.46
Similarly, we can calculate the average cost of a grocery trip in the first month by dividing the total cost of grocery trips ($487 - total cost of fast food meals) by the number of grocery trips (4):
Average cost of a grocery trip = ($487 - $37.46 x 13) / 4 = $89.38
Using the same method, we can calculate the average cost of a fast food meal and a grocery trip in the second month. In the second month, the total cost of fast food meals and grocery trips was $232, and there were 6 fast food meals and 2 grocery trips. Therefore, the average cost of a fast food meal is:
Average cost of a fast food meal = $232 / 6 = $38.67
And the average cost of a grocery trip is:
Average cost of a grocery trip = ($232 - $38.67 x 6) / 2 = $77.33
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For thousands of years, gold has been considered one of the Earth's most precious metals. One hundred percent pure gold is 24-karat gold, which is too soft to be made into jewelry. Most gold jewelry is 14-karat gold, approximately 58% gold. If 18 karat-gold is 75% gold and 12-karat gold, how much of each should be used to make a 14-karat gold bracelet weighing 500 grams
The solution is: 14 karat gold is 58.3333...% gold
We have given that;
75% gold and 50% gold and we need to make 200 grams of 58.3333...% gold.
Since, A percentage is a number or ratio that can be expressed as a fraction of 100. A percentage is a number or ratio expressed as a fraction of 100. It is often denoted using the percent sign, "%", although the abbreviations "pct.", "pct" and sometimes "pc" are also used. A percentage is a dimensionless number; it has no unit of measurement.
Here, we have,
A) x + y = 200
B) .75x + .50y = ( (14/24) * 200)
We multiply equation B) by -1.3333... and get
B) -x -.6666...y = -155.5555... then adding A)
A) x + y = 200 we get
.3333...y = 44.4444...
y = 133.3333... grams 12 karat gold
x = 66.6666... grams 18 karat gold
Double-Checking the answer
133.3333... * .5 = 66.6666...
66.6666 * .75 = 50.0000...
Hence, Concentration of final solution = (66.6666... + 50) / 200 = 58.3333...% which is 14 karat gold
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Find the indicated probability using the two/way table: p(drive to school | senior)
The probability that a senior drives to school is 0.3 or 30%.
To find the indicated probability using the two-way table, we need to locate the row for "senior" and the column for "drive to school" and then find the corresponding cell.
Let's assume that the two-way table shows the number of students who either drive or take the bus to school based on their grade level. We are interested in finding the probability that a student drives to school given that they are a senior.
So, we locate the row for "senior" and the column for "drive to school". Let's say that the cell in the intersection of these two is labeled "30". This means that there are 30 seniors who drive to school.
Next, we need to find the total number of seniors in the sample. Let's say that the total number of seniors in the sample is 100.
To find the probability that a senior drives to school, we divide the number of seniors who drive to school by the total number of seniors in the sample:
P(drive to school | senior) = 30/100 = 0.3 or 30%
Therefore, the probability that a senior drives to school is 0.3 or 30%.
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If P = (1,1), Find:
Rx=5 (P)
([?], []
The coordinate of the image point is (9,1).
There are eight types of rules for the transformation of a point. When the takes place across a line, then the point (x,y) is changed to the point (y,x).
Given that the rule for the transformation of a point P(1,1) is [tex]R_{x=5} (P)[/tex], which defines the reflection of a point about a line, that is parallel to the y-axis. The line [tex]x=5[/tex] is like a mirror. So, the distance between the line and the image point is equal to the distance between the line and the original point.
Using the point-line distance formula, the distance between the line [tex]x=5[/tex] and a point (1,1) is given by [tex]|5-1|=4[/tex].
Similarly, by the above statement, the distance between the line [tex]x=5[/tex] and the image point will also be 4.
Therefore, the coordinate of the image point is (9,1).
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The complete question is -
If P = (1,1), then find the reflection [tex]R_{x=5} (P)[/tex].
A quadrilateral has a total area of 36. 18 square inches. One of the sides measures 6. 7 inches. How long is the other side? inches
(do not include any words in the answer blank)
The length of the other side of the quadrilateral is 10.67 inches.
The other side of the quadrilateral measures 10.67 inches. This can be found by using the formula for the area of a quadrilateral, which is (1/2) x diagonal x height. We know the total area and one side length, so we can solve for the height. The height is 10.67 inches, which is the length of the other side.
To find the length of the other side of the quadrilateral, we need to use the formula for the area of a quadrilateral, which is (1/2) x diagonal x height.
We know the total area of the quadrilateral is 36.18 square inches, and we can assume that the side given (6.7 inches) is one of the diagonals. We can solve for the height, which represents the length of the other side.
Using algebra, we can rearrange the formula to solve for the height:
Area = (1/2) x diagonal x height
36.18 = (1/2) x 6.7 x height
Multiplying both sides by 2:
72.36 = 6.7 x height
Dividing both sides by 6.7:
height = 10.67 inches
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PLEASE HELP!!!!!!! Line M is represented by the following equation: x + y = −1 What is most likely the equation for line P so the set of equations has infinitely many solutions? (4 points) Question 5 options: 1) 2x + 2y = 2 2) 2x + 2y = 4 3) 2x + 2y = −2 4) x − y = 1
The equation for line P such that the system has an infinite number of solutions is given as follows:
3) 2x + 2y = -2.
How to obtain the equation?The first equation for the system of equations is given as follows:
x + y = -1.
A system of equations has an infinite number of solutions when the two equations are multiples.
Multiplying the equation by 2, we have that:
2x + 2y = -2.
Meaning that equation 3 is correct.
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Create trig ratios for sin, cos, and tan
Sin(z) = 4/5, Cos(z) = 3/5, tan(z) = 4/3
We know that
sin(z) = perpendicular/hypotenuse
cos(z) = base/hypotenuse
tan(z) = perpendicular/base
Now putting we get,
Sin(z) = 4/5
Cos(z) = 3/5
tan(z) = 4/3
(n+3)!/(n+1)! please help immediately
Answer:
(n + 3)(n + 2) or n² + 5n + 6------------------
The factorial of a non-negative integer n, denoted by n!, is the product of all positive integers less than or equal to n:
n! = n × (n - 2) × (n - 3) × ... × 2 × 1As per above mentioned definition we see that:
(n + 3)! = (n + 3) × (n + 2) × (n + 1)!Hence the quotient of (n + 3)! and (n + 1)! is:
(n + 3)(n + 2) or n² + 5n + 6Prove that triangle FGH is right-angled at F
Triangle FGH is a right triangle because (HG)²= (FG)²+ (FH)²
What are similar triangles?Similar triangles are triangles that have the same shape, but their sizes may vary. The ratio of corresponding sides of similar triangles are equal.
Therefore;
6/5 = 3.6/FH
represent FH by x
6/5 = 3.6/x
6x = 5 × 3.6
6x = 18
divide both sides by 6
x = 18/6 = 3
Since FH is 3, this means that the sides of triangle FGH are Pythagorean triple, hence FGH is a right triangle.
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