A cheetah running initially at a velocity of 20 m/s accelerates
uniformly at 3.0 m/s. The velocity of the cheetah will be
m/s after 4.0 seconds.

Answers

Answer 1

Answer: I think it’s 32 m/s

Explanation: Vi=20 m/s

Vf=?

a=3.0 m/s^2

t= 4s

Vf= Vi + at

Vf= 20 m/s + (3 m/s^2)(4s)

Vf= 20 m/s + 12m/s

Vf= 32m/s

Answer 2

If A cheetah running initially at a velocity of 20 m/s accelerates

uniformly at 3.0 m/s2. The velocity of the cheetah after 4.0 seconds will be 32 m/s.

To find the velocity of the cheetah after some time we can use the formula:

v = u + at

where:

v = final velocity

u = initial velocity

a = acceleration

t = time

Given:

Initial velocity (u) = 20 m/s

Acceleration (a) = 3.0 m/s²

Time (t) = 4.0 seconds

now we can put values in eq.

v = 20 m/s + (3.0 m/s²) * 4.0 s

v = 20 m/s + 12 m/s

v = 32 m/s

so the answer is 32 m/s.

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Related Questions

6tyhfdytythftyhyhfytfyht

Answers

what? may you explain what the problem is? also may you mark this brainiest for free pls? :)

Answer:

Six is the only number that is both the sum and the product of three consecutive positive numbers.

Explanation:

What is the correct answer and try to explain if can.​

Answers

Answer:

C. Electrical

Explanation:

C because the lamp is plugged into a "Electrical" outlet meaning it uses electrical energy to produce light 'pls can i have brainliest i need it for my goal'

An object is known to have balanced forces on it. Which of the following would be a true statement?

Answers

If an object has a balanced force on it, there is a possibility that the object may be in a position i.e. there is no change in speed and direction of the body.

If the forces acting on an object is balanced, it means that the net force acting on the body is zero.

According to Newton's law of motion, an object will continue in a state of motion in a straight line unless acted upon by an external force.

This external force might be a balanced or unbalanced force. Hence if an object has a balanced force on it, there is a possibility that the object may be in a position i.e. there is no change in speed and direction of the body.

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what are the magnifications of the objective lenses

Answers

Answer:

Objective Lenses: Usually you find 3 or 4 objective lenses on a microscope. They almost always consist of 4x, 10x, 40x and 100x powers, when coupled with a 10x (most common) eyepiece lens, total magnification is 40x (4x times 10x) 100x, 400x and 1000x

Explanation:

Objective lenses come in various magnification powers, with the most common being 4x, 10x, 40x, and 100x, also known as scanning, low power, high power and typically oil immersion objectives, respectively

An airplane flies with a velocity of 750. kilometers
per hour, 30.0° south of east. What is the
magnitude of the eastward component of the
plane's velocity?
A. 866 km/h
B. 650. km/h
D. 375 km/h
C. 433 km/h

Answers

B. 650 km/h is the correct answer

The magnitude of velocity in east direction will be 650 N approximately.

What is velocity ?

velocity is given by the change in distance by the object with respect to change in time. It is a vector quantity and having S.I unit as m/s.

Here it is given that magnitude of velocity is 750 N and making an angle of 30 degree with x axis in counterclockwise direction as shown in figure below :

Now resolving and writing magnitude of velocity V in x and y direction respectively :

[tex]\begin{aligned}Vcos\theta&= 750 cos30^{o}=650 \:m/s\\Vsin\theta&= 750sin30^{o}= 375 m/s\end{aligned}[/tex]

It should be noted that [tex]vsin\theta[/tex] is acting in negative y direction.

Therefore, the magnitude of velocity in east direction is 650 m/s

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Use the picture to answer the question.
Name at least three physical properties of the bowling
ball.
1

Answers

Answer:

I need the picture to amswer the question thay's why it says " "

How can you return a negatively or positively charged object back to its neutral state?

Answers

[tex]\huge\fbox\orange{A} \huge\fbox\red{N}\huge\fbox\blue{S}\huge\fbox\green{W}\huge\fbox\gray{E}\huge\fbox\purple{R}[/tex]

[tex]\huge\underline\mathtt\colorbox{cyan}{For Positively Charged:}[/tex]

By gaining electrons from the ground, the object will have a balance of charge and therefore be neutral. Grounding is the grounding of a positively charged object and involves the transfer of electrons from the ground into the object.

[tex]\huge\underline\mathtt\colorbox{red}{For Negatively Charged:}[/tex]

If it is to have its charge removed, then it will have to lose its excess electrons. Once the excess electrons are removed from the object, there will be equal numbers of protons and electrons within the object and it will have a balance of charge.

Apply Newton’s second law to calculate the frictional force needed to hold a 15 g pen in your fingers and keep it from falling

Answers

Answer:

0.1962N.

Explanation:

Weight is a force, so we use newtons second law which states F=ma. So the weight of a watermelon on earth is 2kg x 9.81m/s², which is 19.62N (newtons). On the moon it weighs 2 x 1.63 which is 3.26N.

The weight of the pen is 0.02 x 9.81, which is 0.1962N. If the pen is not to fall the frictional force needs to be equal to this force,

so the answer is 0.1962N.

(Hope this helps can I pls have brainlist (crown)☺️)

a constant current flows in the conductor with a magnitude of 1.6 mA. Calculate the charge and number of electrons transferred through the straight cross-section of the conductor in 1 hour.

Answers

Current=1.6mA=1.6×10^{-3}A=0.0016A=ITime=1h=3600s=tCharge=Q

[tex]\\ \sf\longmapsto I=\dfrac{Q}{t}[/tex]

[tex]\\ \sf\longmapsto Q=It[/tex]

[tex]\\ \sf\longmapsto Q=0.0016(3600)[/tex]

[tex]\\ \sf\longmapsto Q=5.76C[/tex]

Based on the table, what is the advantage for using 16-inch spacing compared to 24-
inch spacing?
A. At a given load, the 16-inch spacing can support a smaller span
B. At a given load, the 16-inch spacing can support a larger span
C. At a given load, the 16-inch spacing requires less construction time
D. At a given load, the 16-inch spacing requires less construction costs

Answers

The advantage for using 16-inch spacing is that ; ( B ) At a given load, the 16-inch spacing can support a larger span

The spacing along a span in construction engineering is determined by the amount and mass of load the span will either carry or support during and after construction.

A smaller span spacing can support a given load more efficiently than a larger span spacing because when the spacing is smaller it can support a larger span better than a larger span spacing.

Hence we can conclude that the advantage for using 16-inch spacing is that At a given load, the 16-inch spacing can support a larger span.

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Help me pleaseee

in what way does the tools, equipment and paraphernalia help us in our lives
Help me pleaseee :( today is our last day pleaseee (Please dont answer if you dont know). ​

Answers

Answer:

They can help us in our daily lives

Explanation:

I knew that they can also be a help to others specially in other ways such as to help us to facilitate our work in home

Using the Position vs. time Graph below, showing the motion of two cyclists (Cyclist A and Cyclist B) answer the following question.Do the two cyclists have the same velocity at t = 3 seconds?

Answers

Using the information depicted on the distance - time graph, the slope of the graph is could be used to infer the velocity of each cyclist. Hence, cyclist A and B do not have the same velocity at 3 seconds.

The steepness of slope on the distance - time graph gives the velocity of the cyclist. At time, t = 0 ; the cyclist A has a greater slope than cyclist B. Hence, the velocity of the cyclists is different.

Therefore, the cyclists do not have the same velocity at time, t = 3 seconds.

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1.) 450 cm =____m

2.) 24 miles =____cm

3.) 16.7 gallons =____liters

Answers

Answer:

450cm = 4.5m

24miles = 3862430 cm (3.9×10⁶cm)

16.7 gallons = 63.216 liters (approx.)

Explanation:

brainliest plz

the emission of electrons from metals that have absorbed photons is called the

Answers

Answer:

The answer to your question is the Photoelectric effect.

Explanation:

Problem 4:
A body fell vertically from the top of a tower. It covered 123.1 m in the final two seconds
before hitting the ground. Determine the height of the tower rounding your answer to the
nearest two decimal places. Let the acceleration due to gravity g=9.8 m/s2.

Answers

Answer:

v2^2 - v1^2 = 2 g s        fundamental formula

v2 = v1 + 2 g    = v1 + 19.8         increase in velocity in 2 sec

v1^2 + 39.6 v1 + 392 - v1^2 = 2 * 9.8 * 123.1 = 2412.76

v1 = (2412.76 - 392) / 39.6 = 51.03

v2 = 51.03 + 19.6 = 70.63

T = 70.63 / .8 = 7.207 sec     time to fall height of tower

S = 1/2 g T^2 = 4.9 * 7.207^2 = 254.5 m

(Note  v2^2 - v1^2 = 70.63^2 - 51.03^2 = 2385 m

2385 / (2 * 9.8) = 122 m (close to 123.1    as was given

jane pushed a box with 15 N force (an action) what force does the box have on Jane? which law is this?

Answers

Answer:

This is Newton’s third law (forces due to friction). There would be 15N being pushed back at Jane.

Explanation:

Newton’s third law states that for every action there is an equal and opposite reaction. So if Jane pushed with a force of 15N, 15N would be pushed back at her. Hope this helps! :)

I need help asap please
Will give BRAINLIST for correct answers only
Thank you

A force of 225 N at an angle of 30 degrees to the horizontal displacement. The component of the force that will cause work to be done is?

Answers

Answer:

225cos30

Explanation:

Force in the direction of the work done

225cos30
~~~~~~~~~~~~~

Find out fastest to slowest will give brainlesa

Answers

Answer:

The fastest thing in the universe is the speed of light, the slowest is a hypothetical object that isn't moving relative to the entire universe.

Fastest -Universe slowest- hypothetical object

When a 12 newton horizontal force is applied to a box on a horizontal
table top, the box remains at rest. The force of static friction acting on
the box is .....

Answers

The force of static friction acting on  the box is greater than the applied horizontal force.

Force is known to be the reason for motion according to Newton's first law of motion. An object will move when it has been acted upon by an external force.

In this case, a box lying on a table has been acted upon by an external force of  12 newton but the box remains at rest. This simply means that the applied force is less than the force of static friction acting on  the box.

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In a salt solution, salt is a solute. why​

Answers

Answer: Because it can dissolve in water

Explanation: Logic

A plant dying after being exposed to poison represents a physical change.
True or false. (No links please.) Correct answers only..

Answers

Answer:

False is the correct answer.

It is considered more of a chemical change because all of the cells inside the plant decompose (change chemicaly)

Answer:

False

Explanation:

saw this on another brainly question, it's because a flower that becomes a poisonous flower would be a chemical change. If it were to mix with the poison it would just become something new entirely.

P1= 100 kPa
V1= 5 L
T1= 300 degrees Kelvin
P2=100 kPa
V2= ? L
T2= 350 degrees Kelvin

Answers

Explanation:

using Charles law; since the pressure is constant

V1/T1 = V2/T2

5/300 = V2/350

cross multiply

V2 X 300 = 5 X 350

V2 = 1750/300

V2 = 5.833L

A object was fired at 17ms at 40 degree angle horizontal , if object traveled 29meters how long was it in the air

Answers

First you need to find the initial x component which is 13.02. After that you plug it into the 3rd formula on the AP physics formula sheet. Then rearrange it into the quadratic formula and solve for time. The answer should be 4.1 seconds.

por favor ayuda que ejercicio debo hacer para enflacar en una semana xd

Answers

Answer:

Un excelente ejercicio para perder barriga rápidamente es correr, ya que el cuerpo gasta una mayor cantidad de calorías en un corto período de tiempo, en tan sólo 30 minutos corriendo se queman unas 300 calorías.

...

Qué ejercicios realizar

Correr. ...

Clase aeróbica. ...

Saltar cuerda. ...

Bicicleta. ...

Caminar rápido. ...

Natación.

Explanation:

dame coronita por favor

a car travels at a uniform speed of 30 km per hour for 30 mins and then at a uniform speed of 60 km per hour for the next 30 minutes calculate the average speed of a car ​

Answers

The car is travelling at 2km/hour

Vector A has a magnitude of 8.0 m and points 30 degrees north of east; vector B has a magnitude of 6.0 m and points 30 degrees west of north; and vector C has a magnitude of 5.0 m and points 30 degrees west of south. The resultant vector A + B + C is given by:

A) 2.1 m at an angle 66 degrees east of north.
B) 5.9 m at an angle 74 degrees north of east.
C) 2.7 m at an angle 74 degrees north of east.
D) 5.1 m at an angle 74 degrees north of east.
E) 4.8 m at an angle 74 degrees east of north.

Answers

D I believe it is hope it woke

The resultant vector A + B + C is approximately 5.1 m at an angle 74 degrees north of east.

To find the resultant vector A + B + C, we need to break down each vector into its horizontal (x) and vertical (y) components, and then add them together.

Given:

Vector A: magnitude = 8.0 m, angle = 30 degrees north of east

Vector B: magnitude = 6.0 m, angle = 30 degrees west of north

Vector C: magnitude = 5.0 m, angle = 30 degrees west of south

Let's calculate the x and y components for each vector:

For Vector A:

A_x = 8.0 m × cos(30°)

A_x = 8.0 m × 0.866

A_x ≈ 6.928 m

A_y = 8.0 m × sin(30°)

A_y = 8.0 m ×0.5

A_y = 4.0 m

For Vector B:

B_x = 6.0 m × sin(30°)

B_x = 6.0 m × 0.5

B_x = 3.0 m

B_y = 6.0 m × cos(30°)

B_y = 6.0 m × 0.866

B_y ≈ 5.196 m

For Vector C:

C_x = 5.0 m × sin(30°)

C_x = 5.0 m ×0.5

C_x = 2.5 m

C_y = 5.0 m × cos(30°)

C_y = 5.0 m × 0.866

C_y ≈ 4.33 m

Now, let's add up the x and y components:

Resultant x component = A_x + B_x + C_x

Resultant x component = 6.928 m + 3.0 m + 2.5 m

Resultant x component ≈ 12.428 m

Resultant y component = A_y + B_y + C_y

Resultant y component = 4.0 m + 5.196 m + 4.33 m

Resultant y component ≈ 13.526 m

Finally, we can find the magnitude and angle of the resultant vector:

Resultant magnitude = sqrt((Resultant x component)² + (Resultant y component)²)

Resultant magnitude = sqrt((12.428 m)^2 + (13.526 m)^2)

Resultant magnitude ≈ 18.015 m

Resultant angle = arctan(Resultant y component / Resultant x component)

Resultant angle = arctan(13.526 m / 12.428 m)

Resultant angle ≈ 48.413°

Considering the answer choices provided:

A) 2.1 m at an angle 66 degrees east of north.

B) 5.9 m at an angle 74 degrees north of east.

C) 2.7 m at an angle 74 degrees north of east.

D) 5.1 m at an angle 74 degrees north of east.

E) 4.8 m at an angle 74 degrees east of north.

The closest match to our calculated result is:

D) 5.1 m at an angle 74 degrees north of east.

Therefore, the resultant vector A + B + C is approximately 5.1 m at an angle 74 degrees north of east.

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A 250 g sample of water with an initial temp of 98.8 c loses 7500 joules of heat. What is the final temperature of the water?

Answers

The final temperature of the water is 106.0 °C

From the question,

We are to determine the final temperature of water.

From the formula

Q =mcΔT

Where Q is the quantity of heat

m is the mass of substance

c is the specific heat capacity of substance

and ΔT is the change in temperature

Also,

ΔT = T₂ - T₁

Where T₂ is the final temperature

and T₁ is the initial temperature

Then, the formula can be written as

Q =mc(T₂ - T₁)

From the question

Q = 7500 J

m = 250 g

T₁ = 98.8 °C

Putting the parameters into the formula, we get

7500 = 250 × 4.184 (T₂ - 98.8)

(NOTE: specific heat capacity of water, c,= 4.184 J/g °C)

7500 = 1046 (T₂ - 98.8)

7500 = 1046T₂ - 103344.8

Then,

1046T₂ = 7500 + 103344.8

1046T₂ = 110844.8

∴ T₂ = 110844.8 ÷ 1046

T₂ = 105.9701 °C

T₂ ≅ 106.0 °C

Hence, the final temperature of the water is 106.0 °C.

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A shopper walks westward 5.4 meters and then eastward 7.8 meters

Answers

Answer:

13.2 meters

Explanation:

(5.4) + (7.8)

A spanner is used to undo a nut. The spanner has already turned 30° from the horizontal. A vertical force of 50 N is applied 0.3 m from the centre of the nut. Calculate the turning effect of the force, please show the calculation thank you :)

Answers

Answer:

19.4Nm..............

in each of five scenarios, a 1 kg mass is attached to the end of a massless stick by a massless string. each stick is motionless. rank the torques acting on each stick due to the tension in the attached string. take the axis of rotation in each case to be the end of the stick opposite the string.

Answers

Answer:

C=A>B>E>D

Explanation:

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