A helium balloon can carry a load of 750 N. The envelope of the balloon has a mass of 1.5 kg. a) What is the volume of the balloon? b) Assume that the balloon has twice the volume calculated in part (a). What initial acceleration would the balloon experience when carrying a 900N load? c) To what height does the balloon rise at most (assuming that the balloon volume remains constant)?

Answer: Both static and kinetic coefficients of friction depend on the pair of surfaces in contact. Their values are determined experimentally. For a given pair of surfaces, the coefficient of static friction is larger than the kinetic friction. The coefficient of friction depends on the materials used.

Explanation:

the coefficient of static friction is larger than the kinetic friction.

Answer:

The coefficient of kinetic friction and the coefficient of static friction are both affected by the area of contact between two surfaces in contact. The following is a detailed explanation of how the values of these coefficients are affected by the area of contact.

The coefficient of kinetic friction is defined as the ratio of the force required to maintain a constant velocity between two surfaces in contact to the normal force pressing them together. It is a measure of the resistance to motion between two surfaces in contact. The coefficient of kinetic friction is affected by several factors, including the nature of the surfaces in contact, their roughness, and their temperature. However, the area of contact between two surfaces also plays a crucial role in determining the coefficient of kinetic friction.

The larger the area of contact between two surfaces, the greater the frictional force acting between them. This is because a larger area of contact means that there are more points of interaction between the two surfaces, which leads to a greater number of intermolecular forces acting between them. As a result, it becomes more difficult to maintain a constant velocity between two surfaces with a larger area of contact, and hence, the coefficient of kinetic friction increases.

On the other hand, the coefficient of static friction is defined as the ratio of the maximum force required to initiate motion between two surfaces in contact to the normal force pressing them together. It is a measure of the resistance to motion when an object is at rest on a surface. Like the coefficient of kinetic friction, it is also affected by several factors including surface roughness and temperature. However, unlike the coefficient of kinetic friction, it is not affected significantly by changes in area of contact.

This is because when an object is at rest on a surface, it does not matter how much area it covers on that surface. The maximum force required to initiate motion remains constant regardless of whether an object has a small or large area in contact with another surface. Therefore, changes in area of contact do not significantly affect the coefficient of static friction.

The cyclist will be moving with a velocity of 6.12m/s when she reaches the end of the patch which is 290cm long.

Given the speed of cyclist initially (u) = 5m/s

The length of rough horizontal patch of the road (s) = 290cm = 2.9m

The coefficient of kinetic friction of road with her tyres (μ) = 0.220

The frictional force acting on the cyclist f = μN = ma where a is the acceleration acting on the cyclist.

Then f = 0.220 * N

0.220 * m * g = m * a

a = 2.156m/s^2

From Newtons laws of motion we know that :

[tex]v^2 - u^2 = 2as[/tex] where v is the final velocity such that:

[tex]v^2 - (5)^2 = 2 * 2.156 * 2.9[/tex]

[tex]v^2 = 12.5048 + 25 = 37.5048[/tex]

[tex]v = \sqrt{37.5048} = 6.12m/s[/tex]

Hence the final velocity of the cyclist is 6.12m/s

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The value of C₂ is approximately 9.53 microfarads.

Using the conservation of charge, we can say that the total charge on the two capacitors before and after they are connected is the same.

The initial charge on the first capacitor, Q₁, can be calculated as:

Q₁ = C₁ * V

where V is the voltage of the battery (125 V).

When the two capacitors are connected in series, they have the same charge, so the charge on each capacitor is Q = Q₁ = C₁ * V.

The final voltage on each capacitor can be calculated using the formula for capacitors in series:

1/Ceq = 1/C1 + 1/C2

where Ceq is the equivalent capacitance of the two capacitors.

The final voltage on each capacitor is given as 15 V, so we can write:

Q = Ceq * Vf

where Vf is the final voltage on each capacitor (15 V).

Substituting Q = C₁ * V into the above equation and solving for C₂, we get:

C₂ = (C₁ * Vf) / (V - Vf)

Substituting the given values, we get:

C₂ = (7.7 × 10^-6 F × 15 V) / (125 V - 15 V) ≈ 9.53 × 10^-6 F

Therefore, the value of C₂ is approximately 9.53 microfarads.

What is capacitor?

A capacitor is an electrical component that stores electric charge and energy in an electric field between two conductive plates. It consists of two parallel conductive plates separated by an insulating material called a dielectric. When a voltage is applied to the capacitor, it charges up by accumulating electric charges on the two plates, with one plate becoming positively charged and the other negatively charged.

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Answer:

4618.9N

Explanation:

We need to start of by calculating the Gravitational Force (acceleration) of the Earth (IF it was the same size as the moon) which is showed as follows:

[tex]g = \frac{GM}{r^2}[/tex] where g is the gravitational acceleration, G is the gravitational constant (6.673 × [tex]10^{-11}[/tex] Nm^2kg^-2), M is the mass of the planet, r is the radius of the planet.

Substituting the values as given in the question,

[tex]g = \frac{6.673 * 10^{-11} * 4 * 10^{24}}{(1.7*1000 * 1000)^2}\\\\= \frac{26.69200 * 10^{13}}{2890000000000}\\\\\\= 92.3598615917 N/kg[/tex]

Hence, the gravitational force is 92.4N/kg (or m/s^2).

Considering this,

50 * 92.4 = 4618.89N ≈ 4618.9N

Hope this helps and be sure to mark this as brainliest! :)

The density of water being approximately 1000 kg/m³ and acceleration due to gravity being approximately 9.8 m/s², the depth is calculated to be approximately 10.2 meters, while assuming Atmospheric pressure at sea level.

The pressure at any point in a fluid (like water) is given by:

pressure = density x gravity x depth

where density is the density of the fluid, gravity is the acceleration due to gravity, and depth is the depth of the point below the surface.

At sea level, the atmospheric pressure is 10⁵ N/m². This means that the pressure at any point below sea level in water will be higher than 10⁵ N/m².

To find the depth at which the pressure is equal to 10⁵ N/m², we can rearrange the above equation as:

depth = pressure / (density x gravity)

The density of water is approximately 1000 kg/m³, and the acceleration due to gravity is approximately 9.8 m/s². Substituting these values and the given pressure of 10⁵ N/m², we get:

depth = 10⁵ N/m² / (1000 kg/m³ x 9.8 m/s²)

depth = 10.2 meters

Therefore, the depth at which the pressure is equal to atmospheric pressure at sea level (10⁵ N/m²) in water is approximately 10.2 meters.

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The graph of the resistors and the colors of the resistors are presented as follows;

Q1. a) Line A represents R₁, B represents R₃, and C represents R₂

b) The line of the equivalent  will be lower than C

c) Brown, green, black and gold

The resistance of a resistor is; R = V/I

V = The voltage across the resistor, and I is the current through the resistor.

Q1. R₁ = 3.13 kΩ, R₂ = 0.52 kΩ, and R₃ = 1.59 kΩ

a) The potential difference, or voltage V = I·R, where;

I = The current

R = The value of the resistor

The slope is therefore, directly proportional to the resistance of the resistor. Therefore, the resistor that the line A in Figure 1 (b) in the question represents is the highest value resistor, which is R₁ = 3.13 kΩ

The resistor that the line B represents is R₃ = 1.59 kΩ

The resistor that the line C represents is R₂ = 0.52 kΩ

b) The value of Requiv can be found as follows;

1/Requiv = 1/R₁ + 1/R₂ + 1/R₃

Therefore;

1/Requiv = 1/3.13 + 1/0.52 + 1/1.59

Therefore; Requiv ≈ 0.348 Ω

Therefore, the line in Figure 1 (b) representing Requiv will be lower than the line C

c) The obtain the four colors of resistor R₃, we need to calculate its value in ohms. Using the values R₃ = 1.36 kΩ and R₃ = 1.61 kΩ, the average value of R₃ can be calculated as follows;

(R₃₁ + R₃₂)/2 = (1.36 + 1.61)/2 = 1.485

The average value of R₃ is therefore, 1.485 kΩ

The colors of R₃ are therefore; brown, green, black, and gold, where, the first two bands represent the significant digits of the resistance value, the third band represent the multiplier, and the fourth band represent the tolerance value.

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Answer:

the magnitude of the electric field at a point inside the sphere, 0.110 m below the surface, is 7.31 × 10^5 N/C.

Explanation:

To find the magnitude of the electric field at a point inside the sphere, we can use Gauss's law, which states that the electric flux through any closed surface is proportional to the charge enclosed by that surface. We will assume that the metal sphere is a conductor and has a uniform charge density.

First, we need to find the charge enclosed by a spherical surface with radius 0.110 m, centered at the center of the metal sphere. Since the sphere has a uniform charge density, we can find the charge enclosed by this surface as:

Qenc = (4/3)πr^3ρ = (4/3)π(0.110)^3σ,

where ρ is the charge density of the metal and σ is the surface charge density, which is equal to the net charge divided by the surface area of the sphere:

σ = Qnet / (4πr^2) = 0.270 nC / (4π(0.440)^2) = 4.994 × 10^-5 C/m^2.

Therefore, the charge enclosed by the spherical surface is:

Qenc = (4/3)π(0.110)^3(4.994 × 10^-5) = 1.472 × 10^-8 C.

The electric flux through this surface is proportional to the charge enclosed, so we can use Gauss's law to find the electric field at the point inside the sphere:

ΦE = E(4πr^2) = kQenc,

where k is Coulomb's constant.

Solving for E, we get:

E = kQenc / (4πr^2) = (9 × 10^9 N·m^2/C^2)(1.472 × 10^-8 C) / (4π(0.110)^2 m^2) = 7.31 × 10^5 N/C.

Therefore, the magnitude of the electric field at a point inside the sphere, 0.110 m below the surface, is 7.31 × 10^5 N/C

Kohlberg's three levels of moral development are pre-conventional, conventional, and post-conventional.

Pre-conventional level > Conventional level > Post-conventional level

The pre-conventional level is focused on self-interest and avoiding punishment, while the post-conventional level is based on abstract principles and individual conscience.

It is possible for someone to move backwards in Kohlberg's levels of moral development, especially if they experience a traumatic event or significant life changes that challenge their moral beliefs. However, it is also possible for someone to move forward in their moral development with the right support and experiences.

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Please, for the sake of clarity on the solution to the question on calculating the potential V(r) of the metal sphere, let's go ahead with the step by step explanation as shown below.

To calculate the potential V(r) at a distance r from the center of the spheres, we need to consider two cases:

In this case, the point is inside the inner sphere and the potential is simply the potential due to the inner sphere, which can be calculated using the formula:

V_inner(r) = k * q / ra

where k is the Coulomb constant (k = 1/4πε0) and ε0 is the electric constant.

In this case, the point is between the two spheres and the potential is the sum of the potentials due to the inner and outer spheres. The potential due to the outer sphere can be calculated using the same formula as above:

V_outer(r) = - k * q / rb

Note that the negative sign indicates that the potential due to the outer sphere is negative since it has a negative charge.

Therefore, the total potential at this point is:

V(r) = V_inner(r) + V_outer(r)

= k * q / ra - k * q / rb

In this case, the point is outside both spheres and the potential is simply due to the outer sphere, which is:

V_outer(r) = - k * q / r

So the total potential at this point is:

V(r) = V_outer(r)

= - k * q / r

Therefore, the potential V(r) as a function of the distance r from the center of the spheres is:

V(r) = { k * q / ra - k * q / rb if ra < r < rb

{ - k * q / r if r > rb

where k is the Coulomb constant, q is the charge on the inner sphere, ra is the radius of the inner sphere, and rb is the radius of the outer spherical shell. Note that we have taken the potential to be zero when the distance r from the center of the spheres is infinite.

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soo helpful

Explanation:

this is so helpful thank you so much

The time interval between the student clapping his hands and hearing the first echo is 0.2 seconds. The time interval between the student clapping his hands and hearing the third echo is 0.6 seconds.

The question is based on echoes and involves the calculation of time taken to hear an echo. To calculate this, we can consider the echo reaching the student as a journey of sound, first going towards the building, and then reflecting back. Therefore, the total distance covered by the sound is twice the distance between the student and the building.

So, if the distance is 33m, the total distance covered is 66m. As the speed of sound is given as 330m/s, the time taken for the first echo = Distance / Speed = 66m / 330m/s = 0.2 seconds.

To hear the third echo, the same journey must be repeated three times. So, the time for the third echo would be 3 * 0.2s = 0.6 seconds.

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Answer:2.5 N of force was required by marco

Explanation: Given

                       work done=48J

                        displacement =19m

                         W=force*displacement

                         force=W/d

                         force=2.5 N

Here the work done is given and the force due to which displacement is also given ,From the formulea work done= force* displacment. We have calculated the answer.

The minimum radius hump you can use for the semi-circular hump is 11.25 m.

The minimum radius loop you can use for the vertical loop is 16.7 m.

For the rollercoaster ride, use the following equations for the centripetal acceleration:

At the top of the hump:

a = v² / r

At the bottom of the loop:

a = (v² + g × h) / r

where v is the velocity of the rollercoaster, r is the radius of the curve, g is the acceleration due to gravity, and h is the height of the curve.

To satisfy the safety regulations:

a_top ← 1.85g

a_bottom ← 5.45g

Rearrange the equations to solve for the minimum radius required for each curve:

For the hump:

a_top = v² / r

r_top = v² / a_top

r_top = (12.5 m/s)² / (1.85 × 9.8 m/s²)

r_top = 11.25 m

Therefore, the minimum radius for the hump is 11.25 m.

For the loop:

a_bottom = (v² + g × h) / r

r_bottom = (v² + g × h) / a_bottom

r_bottom = (12.5 m/s)² + 9.8 m/s² × 37.1 m / (5.45 × 9.8 m/s²)

r_bottom = 16.7 m

Therefore, the minimum radius for the loop is 16.7 m.

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The flow of electrons (charged particles) between positive and negative sources is what generates electrical energy.

Electrical energy is a form of energy that results from the movement of charged particles, such as electrons, through a conductor. This movement of charged particles creates an electric current, which can be harnessed to power devices and machines.

Electrical energy is a versatile form of energy that is used for a wide range of purposes, from lighting and heating to transportation and communication.

It is also a clean and efficient form of energy, which has led to its increased use in recent years as a more sustainable alternative to fossil fuels. The unit of measurement for electrical energy is the joule (J) or the watt-hour (Wh).

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Answer:

I mean 25 kg of course.

Explanation:

If you filled the bucket it is 25 liters. The density of water is about 1 kg/liter so about 1 kg

The change in the electrical potential from the point A to the point B is -840 V

The change in electrical potential, also known as the potential difference or voltage, refers to the difference in electrical potential energy per unit of electric charge between two points in an electrical circuit or between two electrodes of a cell.

Electric potential energy is a measure of the potential for an electric field to do work on an electric charge, and is usually measured in units of volts (V). The greater the potential difference between two points, the greater the amount of work that can be done by moving electric charge from one point to the other.

We have that;

ΔV = Kq (1/ra - 1/rb)

9.0 * 10^9 * 2 * 10^-9(1/0.05 - 1/0.015)

-840 V

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5.42 * a large foucault pendulum such as hangs in many science museums can swing for many hours before it damps out. taking the decay time to be about 8 hours and the length to be 30 meters. The quality factor Q of the large Foucault pendulum is approximately 51,988.

To find the quality factor (Q) of the large Foucault pendulum, we can use the formula:
Q = 2 * π * (Energy stored in the pendulum) / (Energy lost per oscillation)
First, we need to find the period of oscillation (T) of the pendulum using the formula:
T = 2 * π * √(L / g)
where L is the length of the pendulum (30 meters) and g is the acceleration due to gravity (approximately 9.81 m/s²).
T = 2 * π * √(30 / 9.81) ≈ 3.48 seconds
Next, we need to find the number of oscillations (n) in the decay time (8 hours):
n = (8 hours * 3600 seconds/hour) / T
n ≈ (28800 seconds) / 3.48 seconds ≈ 8276 oscillations
Now, we can calculate the energy lost per oscillation:
Energy lost per oscillation = (Energy stored in the pendulum) / (n * decay time)
Since the energy stored in the pendulum and the energy lost per oscillation are proportional, we can use the proportionality constant as the quality factor Q:
Q = 2 * π * (Energy stored in the pendulum) / (Energy lost per oscillation)
Q = 2 * π * n
Q ≈ 2 * π * 8276 ≈ 51988
Therefore, the quality factor Q of the large Foucault pendulum is approximately 51,988.

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Answer:

B. potential mechanical energy to kinetic mechanical energy

Explanation:

The energy of a child on a swing transforms from potential energy to kinetic energy as they swing from the highest point to the lowest point.

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To keep the seesaw in balance, Marcel should position Gilles approximately 0.828 meters to the right of the pivot.

Force Moments Gilles' clockwise moment on the right side of the pivot and Jacques' counterclockwise moment on the left must be equal for the seesaw to be balanced. The child's weight divided by the distance from the pivot yields the moment (M):

                             M = w × L1 = W × L

where w is the weight of Gilles.

Rearranging this equation, we get:

                    L1 = (W × L) / w

Substituting the given values, we get:

L1 = (72.0 N × 0.80 m) / w

We are unable to solve for L1 because we do not know Gilles's weight. However, we can calculate the weight w required to balance the seesaw using an equation:

                                      W × L = w × L1

Substituting the given values, we get:

72.0 N × 0.80 m = w × L1

Solving for w, we get:

w = (72.0 N × 0.80 m) / L1

Now we can replace this expression for w into the other equation for L1, giving:

L1 = (W × L) / [(72.0 N × 0.80 m) / L1]

Simplifying, we get:

L1² = (W × L × L1) / (72.0 N × 0.80 m)

L1² = (W × L) / (72.0 N × 0.80 m)

replacing the given values and solving, we get:

L1 = √[(72.0 N × 0.80 m) / (76.8 N)]

L1 ≈ 0.828 m

To balance the seesaw, Marcel ought to position Gilles approximately 0.828 meters to the right of the pivot.

A big balance is like a seesaw. The fulcrum of a balance is in the middle, like a lever. A lever can lift a weight at the other end when a force, such as the weight of a person sitting on it, is applied to one end. Due to inequalities in the forces, the seesaw is out of balance. The hurdler has lost contact with the ground and has moved upwards. The pull of the earth is off balance. She slows down and changes direction as a result, bringing her back to earth.

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F = K ( | q1 × q2 | ) / r² is the formula you need

convert the value of the charge to the SI system by multiplying with 10^-6

so the task probably gives you coulombs constant but im gonna assume it's K= 9 × 10⁹ Nm²/C² because thats the common way to use it

so we have

F = 9 × 10⁹ ( 7 × 10^-6 × 2 × 10^-6)/ 0.02²

F = 315 N

so i guess the answer is B because your task must give you K=9. something × 10⁹

hope this helps, sorry if i dont make sense

Answer B is correct because the net electrostatic force on q2 is 314.65 N to the left.

In light of the fact that both the charge q1 and the other charge q2 are equal to zero. According to the equation, one charge is positive and the other is negative. Both charges are of similar size. This indicates that the two supplied charges on the system will add up to a total charge of zero.

[tex]F = k * |q1| * |q2| / r^2[/tex]

[tex]F = 9 x 10^9 * 7 x 10^-6 * 2 x 10^-6 / (0.02)^2[/tex]

[tex]F ≈ 314.65 N to the left[/tex]

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The force applied by pressing down on the left side is referred to as the input force. The force that the rope or pulley applies to the box when it is hoisted is known as the output force.

The pulley system employs the tension force applied to one side of the rope to redirect the force in a different direction.

A pulley is a straightforward device that consists of a rope or cable looped around a wheel that has been grooved, as seen below. By pulling on the rope's one end, you operate a pulley. Your pull's force is the input force. The output force pulls up on the object you want to move at the other end of the rope.

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Answer:

0.14442 N

Explanation:

To find the magnitude and direction of the force needed to cause equilibrium in the system, we can use vector addition.

First, we need to convert the forces given in polar coordinates (direction and magnitude) to Cartesian coordinates (x and y components):

Force A: (60 grams) cos(60°) = 30 grams in the x direction, (60 grams) sin(60°) = 51.96 grams in the y direction.

Force B: (100 grams) cos(142°) = -36.07 grams in the x direction, (100 grams) sin(142°) = 94.78 grams in the y direction.

Force C: (130 grams) cos(255°) = -109.57 grams in the x direction, (130 grams) sin(255°) = -62.79 grams in the y direction.

Next, we can add up the x and y components of the three forces to find the net force acting on the system:

Net force in x direction = 30 grams - 36.07 grams - 109.57 grams = -115.64 grams

Net force in y direction = 51.96 grams + 94.78 grams - 62.79 grams = 83.95 grams

Since the system is in equilibrium, the net force in both the x and y directions must be zero. Therefore, we can set up the following equations:

-115.64 grams + F_Dx = 0

83.95 grams + F_Dy = 0

Solving for F_Dx and F_Dy, we get:

F_Dx = 115.64 grams

F_Dy = -83.95 grams

The magnitude of Force D can be found using the Pythagorean theorem:

|F_D| = sqrt(F_Dx^2 + F_Dy^2) = sqrt((115.64 grams)^2 + (-83.95 grams)^2) = 144.42 grams

To convert this to Newtons, we can divide by the conversion factor of 1000 grams per Newton:

|F_D| = 144.42 grams / (1000 grams per Newton) = 0.14442 Newtons

Finally, the direction of Force D can be found using the inverse tangent function:

theta = atan(F_Dy / F_Dx) = atan(-83.95 grams / 115.64 grams) = -37.21 degrees

Therefore, Force D needs to be 144.42 grams (0.14442 Newtons) in magnitude and 37.21 degrees in direction to cause equilibrium in the system.

The measure of the amount of water vapor in the atmosphere is called humidity.

Humidity refers to the amount of water vapor present in the air, and it can be expressed in a variety of ways, such as absolute humidity (the actual amount of water vapor per unit volume of air), relative humidity (the amount of water vapor present as a percentage of the maximum amount the air can hold at a given temperature), or specific humidity (the mass of water vapor per unit mass of air). Humidity plays an important role in weather and climate, as it can affect temperature, cloud formation, precipitation, and other atmospheric phenomena.

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The change of the potential energy of gravitation, ΔPEg, is ΔPEg = expresses the notion, with h being the rise in height with g the acceleration caused by gravity.

A doubling in height will lead to a doubling in gravitational potential energy since an object's gravitational potential energy is directly proportionate to its height above the zero point. Its gravitational potential energy will triple with a tripling of height.

Potential energy changes are identical to kinetic energy changes by definition. As the object is at rest, its initial KE is 0. As a result, the ultimate Kinetic Energy is the same as the KE change.

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Name: Bubble Blitz

Goals and Playthrough: Bubble Blitz is a fast-paced game in which players race against time to pop as many bubbles as possible. The game's objective is to pop as many bubbles as possible to score as many points as possible.

Scoring: One point is awarded for popping each bubble. The player with the highest score wins the game at the end.

Required equipment: A large open area and either a bubble machine or a container filled with soapy water are required for Bubble Blitz.

The number of team members: You can play Bubble Blitz by yourself or in teams of two or more.

Abilities required: To pop the bubbles as they appear in Bubble Blitz, players must have strong hand-eye coordination and quick reflexes.

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The length of weighted rod under the surface when the rod floated in brine density is 7.2cm

Given the length of weighted rod under water(L1) = 6cm

The density of water (d1) = [tex]1000kg.m^3[/tex]

The density of brine (d2) = [tex]1200kg.m^3[/tex]

Let the length of rod floated in brine under surface = L2

We know that the density of a material will increase as its length increases. This is because the mass of the material increases with length, while the volume of the material remains constant.

length under water/length under surface = density of water/density of brine

L1/L2 = d1/d2

Then [tex]6 * 10^{-2}/L2 = 1000kg.m^3/1200kg.m^3[/tex]

L2 = 7.2cm

Hence, the length of rod under surface in brine = 7.2cm

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The mechanic will have to apply a force of 73.575 N to lift the vehicle using the hydraulic Jack.

To calculate the force the mechanic will have to apply, we first need to determine the pressure exerted by the weight of the vehicle on the surface area.

Pressure is defined as force per unit area, so we can use the formula:

Pressure = Force / Area

The weight of the vehicle is 1500kg, which is equivalent to a force of:

Force = mass x gravity

where;

Force = 1500 kg x 9.81 m/s²

Force = 14,715 N

The pressure exerted by the weight of the vehicle on the surface area of 10m² is:

Pressure = Force / Area

Pressure = 14,715 N / 10 m²

Pressure = 1471.5 Pa

Now we can calculate the force the mechanic will have to apply to the surface area of 0.05m² using the same formula:

Pressure = Force / Area

We know the pressure and the area, so we can rearrange the formula to solve for the force:

Force = Pressure x Area

Force = 1471.5 Pa x 0.05 m²

Force = 73.575 N

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Explanation:

To find the net work done on the particle to cause it to move to the right at 38 m/s, we need to use the work-energy theorem, which states that the net work done on an object is equal to its change in kinetic energy:

Net work = ΔK = 1/2 * m * (vf^2 - vi^2)

where m is the mass of the particle, vi is its initial velocity (to the left), and vf is its final velocity (to the right).

Substituting the given values, we get:

Net work = 1/2 * 0.059 kg * (38 m/s)^2 - 1/2 * 0.059 kg * (27 m/s)^2

Net work = 46.4657 J - 22.6545 J

Net work = 23.8112 J

Therefore, the net work done on the particle to cause it to move to the right at 38 m/s is 23.8112 Joules.