The final velocity of the pair of hockey players is 4.12 m/s.
In an inelastic collision, the two objects stick together and move as a single unit after the collision. To calculate the final velocity of the pair of hockey players, we can apply the principle of conservation of momentum.
The initial momentum of the system is given by the sum of the individual momenta of the players before the collision. The momentum (p) of an object is defined as the product of its mass (m) and velocity (v): p = m * v.
For the first player, with a mass of 80 kg and initial velocity of 7.5 m/s, the initial momentum is 80 kg * 7.5 m/s = 600 kg·m/s. For the second player, with a mass of 75 kg and initial velocity of 0.5 m/s, the initial momentum is 75 kg * 0.5 m/s = 37.5 kg·m/s.
The total initial momentum of the system is the sum of these individual momenta: 600 kg·m/s + 37.5 kg·m/s = 637.5 kg·m/s.
Since the collision is completely inelastic, the two players stick together and move as a single unit after the collision. Therefore, the final velocity of the pair of hockey players is determined by dividing the total initial momentum by the total mass of the system: final velocity = total initial momentum / total mass.
The total mass of the system is 80 kg + 75 kg = 155 kg. Dividing the initial momentum (637.5 kg·m/s) by the total mass (155 kg), we find the final velocity of the pair of hockey players to be approximately 4.12 m/s.
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Identify the correct statement regarding the strength of chemical bonds. Strong bonds form with large atoms and weak bonds with small atoms. Weak bonds require less energy to form than strong bonds. Strong bonds occur with high temperature and weak bonds with low temperature. Weak bonds require more energy to form than strong bonds.
Option B is the right answer. The correct statement regarding the strength of chemical bonds is that weak bonds require less energy to form than strong bonds.
Bonds form when two atoms share, give, or take electrons.
The electrons in the valence shell or outermost energy level of an atom are used to create bonds.
When atoms interact and share electrons, they lower their potential energy.
The more tightly an atom's electrons are bound, the greater the energy required to break those bonds.
There are two types of bonds: strong and weak.
Strong bonds have a lower potential energy than weak bonds, and they require more energy to break.
As a result, strong bonds tend to be more difficult to break than weak bonds.
The type of bond between two atoms is determined by the difference in their electronegativities.
The strength of a bond is determined by the energy required to break it.
Bonds are considered strong when they have a higher bond energy than weak bonds, which have a lower bond energy.
This implies that more energy is required to break a strong bond than to break a weak bond.
Therefore, weak bonds require less energy to form than strong bonds.
To conclude, the correct statement regarding the strength of chemical bonds is that weak bonds require less energy to form than strong bonds.
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the very act of observing a particle has a dramatic effect on its behaviour why do you think this is the case
Answer:
Explanation:
In the microscopic world of quantum mechanics, particles don't behave like familiar everyday objects. They can exist in multiple states simultaneously and behave as both particles and waves. When we try to measure or observe a particle, we typically use light or other particles to interact with it. However, this interaction can disturb the particle's state. Imagine trying to measure the position of an electron using light. Light consists of photons, and when photons interact with the electron, they transfer energy to it. This energy exchange causes the electron's position and momentum to become uncertain. The more precisely we try to measure its position, the more uncertain its momentum becomes, and vice versa. This is known as the Heisenberg uncertainty principle.
So, the act of observing a particle disturbs its state because the interaction between the observer and the particle affects its properties. The very act of measurement or observation introduces a level of uncertainty and alters the particle's behavior. It's important to note that this behavior is specific to the quantum world and doesn't directly translate to the macroscopic world we experience in our daily lives. Quantum mechanics operates at extremely small scales and involves probabilities and uncertainties that are not typically noticeable in our macroscopic observations.
An eraser rests on a clipboard that is tilted at an angle
of 23° with the ground. The eraser is not sliding down
the clipboard. What is the minimum coefficient of
static friction, needed for this to be the case?
0.26
O 042
O Not enough information to tell
O 0.16
The eraser on the tilted clipboard needs a minimum static friction coefficient of 0.3907. No option matches; The correct answer is (O) Not enough information to tell.
In this problem, we are given that an eraser rests on a clipboard that is tilted at an angle of 23° with the ground. Also, the eraser is not sliding down the clipboard. We need to find the minimum coefficient of static friction required to hold the eraser in its place.The coefficient of static friction is given by the formula:f_s = (μ_s)N, where f_s is the force of static friction, μ_s is the coefficient of static friction and N is the normal force acting on the object. In this case, the normal force acting on the eraser is equal to its weight. Thus, the normal force acting on the eraser is given by: N = mg, where m is the mass of the eraser and g is the acceleration due to gravity. Substituting the values of N and θ in the above equation, we get f_s = mg sin θThus, the minimum coefficient of static friction needed to hold the eraser in place is given by:μ_s = f_s / N = (mg sin θ) / (mg) = sin θ = sin 23° = 0.3907 (approx.)Therefore, the minimum coefficient of static friction needed for the eraser to stay in its place is 0.3907. The closest option given is 0.26, which is not equal to the value obtained in the calculation. Hence, the correct answer is option (O) Not enough information to tell.For more questions on static friction
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2. Julie has a mass of 48 kg. She stands on a diving board that is 5.0 m above the surface of the water. Use the conservation of mechanical energy equation to calculate her speed when she hits the water
Julie's speed when she hits the water is approximately 9.90m/s.
Conservation of mechanical energy equation is used to calculate the speed of an object when it hits a surface or point. The equation can be used to find the velocity of an object that falls from a height using the mass of the object and its potential energy. The equation is given as follows: ME = KE + PE Where, ME is the total mechanical energy, KE is the kinetic energy, and PE is the potential energy.
Julie is standing on a diving board 5m above the surface of the water. Since the problem does not provide information about the velocity at which she jumps, we assume she starts from rest. Therefore, her initial velocity, u = 0.Julie's mass, m = 48kg, and the height of the diving board, h = 5.0m. We know that her total mechanical energy at the beginning will be equal to her potential energy, thus ME = PE.
The potential energy is given by PE = mgh Where g is the acceleration due to gravity (9.8m/s²)Therefore,PE = 48kg × 9.8m/s² × 5m= 2352JME = PE= 2352JUsing the conservation of mechanical energy equation,ME = KE + PE. Since she starts from rest, her initial kinetic energy is zero (KE = 0). Therefore,2352J = KE + 0JKE = 2352J
The final kinetic energy can be found using the equation: KE = 0.5mv² Where, v is the final velocity.
Therefore,2352J = 0.5 × 48kg × v²v² = (2352J × 2) ÷ (48kg)v² = 98m²/s²v = sqrt(98m²/s²)v = 9.90m/s.
Therefore, Julie's speed when she hits the water is approximately 9.90m/s.
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A collision cart (3 kg) is moving at 3 m/s and collides with a 2 kg cart moving at -5 m/s. If the 2 kg cart is moving at 4.6 m/s after they collide, find the final velocity of the 3 kg cart.
We used the conservation of momentum to find the final velocity of a 3 kg collision cart that collided with a 2 kg cart. We found that the final velocity of the 3 kg cart is -6.07 m/s.
In this question, a collision cart of 3 kg is moving at 3 m/s and collides with a 2 kg cart that is moving at -5 m/s. After they collide, the 2 kg cart is moving at 4.6 m/s. We are to find the final velocity of the 3 kg cart. We can use the conservation of momentum to solve this problem. The conservation of momentum states that the total momentum of an isolated system remains constant if there are no external forces acting on the system. In this case, the two carts can be considered as an isolated system. The formula for momentum is given by: p = mv, where p is the momentum, m is the mass, and v is the velocity. Before the collision, the total momentum of the system is given by: p1 = m1v1 + m2v2, where m1 is the mass of the 3 kg cart, m2 is the mass of the 2 kg cart, v1 is the velocity of the 3 kg cart, and v2 is the velocity of the 2 kg cart.Substituting the given values, we get:For more questions on velocity
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An unfortunate astronaut loses his grip during a spacewalk and finds himself floating away from the space station, carrying only a rope and a bag of tools. First he tries to throw a rope to his fellow astronaut, but the rope is too short. In a last ditch effort, the astronaut throws his bag of tools in the direction of his motion, away from the space station. The astronaut has a mass of a=102 kg and the bag of tools has a mass of b=10.0 kg. If the astronaut is moving away from the space station at i=1.50 m/s initially, what is the minimum final speed b,f of the bag of tools with respect to the space station that will keep the astronaut from drifting away forever?
The minimum final speed of the bag of tools with respect to the space station that will keep the astronaut from drifting away forever is 1.37 m/s.
Given that the astronaut has a mass of a=102 kg and the bag of tools has a mass of b=10.0 kg. If the astronaut is moving away from the space station at i=1.50 m/s initially, we have to find out the minimum final speed b,f of the bag of tools with respect to the space station that will keep the astronaut from drifting away forever.
The momentum conservation equation is given as:
max a0 = (ma+mb) x vb,
Where,
m(a) = 102 kg
m(b) = 10 kg
Initial velocity, ua = 1.5 m/s
Final velocity, ub,f = ?
When the bag is thrown away from the astronaut, it exerts an equal and opposite force on the astronaut.
The total mass of the astronaut and the bag of tools,
(ma + mb) = 102 + 10 = 112 kg
Initial momentum = ma × ua = 102 × 1.5 = 153 kg.m/s
Final momentum = (ma + mb) × u
b,f = 112 × u
b,f = 112 u
According to the law of conservation of momentum:
Initial momentum = Final momentum
153 = 112 u
b,f = 153/112u
b,f = 1.37 m/s.
Therefore, the minimum final speed bf of the bag of tools is 1.37 m/s.
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A ray of light makes an angle of 35 with a plane mirror ,what is the reflection
When a ray of light strikes a plane mirror, the angle of reflection is equal to the angle of incidence.
In this case, the ray of light makes an angle of 35 degrees with the plane mirror. Therefore, the angle of reflection will also be 35 degrees. To understand why this happens, we need to consider the properties of reflection. When light interacts with a smooth surface like a mirror, it follows the law of reflection.
According to this law, the incident ray, the reflected ray, and the normal (a line perpendicular to the mirror's surface) all lie in the same plane. The angle of incidence is the angle between the incident ray and the normal, measured on the side of the normal where the light is coming from. In this case, the angle of incidence is 35 degrees.
According to the law of reflection, the angle of reflection is the angle between the reflected ray and the normal, also measured on the side of the normal where the light is coming from. Since the incident and reflected rays are on opposite sides of the normal, the angle of reflection is also 35 degrees.
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14. Foodborne illness is often caused by?
Answer:
consuming contaminated foods or beverages
what is the reading of the spring balance.
Assume that the surface is a perfect smooth surface, and the whole system is moving to the left with constant acceleration.
If the system is moving to the left with a constant acceleration and the surface is perfectly smooth, the reading on the spring balance would be zero.
How do we know?The spring balance measures the force exerted on it, which in this case would be the force due to gravity acting on the object.
However, since the surface is smooth and there is no friction, there would be no additional force acting on the object, resulting in zero net force and therefore zero reading on the spring balance.
We observe that only in these particular circumstances would the reading on the spring balance be zero.
The reading on the spring balance would be different if there were additional forces operating on the object, such as friction or an outside force.
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What happens to a light ray when it incident at an angle greater than the critical angle?
When a light ray is incident at an angle greater than the critical angle, a phenomenon known as total internal reflection occurs.
Total internal reflection happens when light travels from a medium with a higher refractive index to a medium with a lower refractive index. In this scenario, instead of the light ray refracting and passing into the second medium, it reflects back into the first medium. The incident ray strikes the interface between the two media at an angle greater than the critical angle, which is the angle at which the refracted ray would have a 90-degree angle of incidence.
Due to the laws of reflection, the light ray bounces off the interface, staying within the first medium. It travels along a path parallel to the interface, effectively being reflected internally. No light escapes into the second medium.
Total internal reflection has various practical applications. It is employed in fiber optics, where light signals are transmitted over long distances by repeatedly bouncing off the internal walls of the fiber. It is also utilized in devices like prisms, binoculars, and reflective coatings, where controlling the reflection of light is crucial.
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What is the force of gravity between two objects with mass 15,000,000kg and 16,000,000kg respectively that are 14m apart?
The force of gravity between two objects with masses of 15,000,000kg and 16,000,000kg, separated by 14m, is approximately 1.04 x 10⁸ N.
Gravity is a force that pulls two objects towards each other. According to Newton's Law of Gravitation, the force of gravity between two objects is directly proportional to their masses and inversely proportional to the square of the distance between their centers of mass. Hence, the force of gravity between two objects with masses of 15,000,000kg and 16,000,000kg respectively that are 14m apart can be calculated using the formula F = Gm1m2/d², where F is the force of gravity, G is the gravitational constant (6.67430 × 10⁻¹¹ N m²/kg²), m1 and m2 are the masses of the objects, and d is the distance between them. Substituting the given values, we get:F = (6.67430 × 10⁻¹¹)(15,000,000)(16,000,000)/(14²)= 1.04 x 10⁸ N (approx)Therefore, the force of gravity between the two objects is approximately 1.04 x 10⁸ N.Summary: The force of gravity between two objects can be calculated using the formula F = Gm1m2/d², where F is the force of gravity, G is the gravitational constant, m1, and m2 are the masses of the objects, and d is the distance between them. Substituting the given values, we get that the force of gravity between two objects with mass 15,000,000kg and 16,000,000kg respectively that are 14m apart is approximately 1.04 x 10⁸ N.For more questions on the force of gravity
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2. A well 1000m deep at an angle of 45 degree, what is the true vertical depth of the well?
Answer: 707.11m
Explanation:
since the well is at 45 degrees, we can use trig ratios to figure out the vertical depth of the well as u can see image attached.
then since we are looking for the vertical depth and we have information on the hypotenuse we can say
sin45= [tex]\frac{verticle height}{1000}[/tex]
therefore, we can say.
1000sin(45) = vertical height
hence
vertical height = 707.11m
What decibel level can cause hearing damage to begin?
A. 80
B. 10
C. 100
D. 60
The decibel level that can cause hearing damage to begin is 80.
The correct answer to the given question is option A.
According to the Occupational Safety and Health Administration (OSHA) standards. When sound intensity reaches 85 decibels or higher, it can cause permanent hearing loss or damage if not protected properly.
Decibels (dB) are the unit used to measure the loudness of sound. Sound is defined as a wave of pressure that arises when energy is transferred from one place to another. The frequency of sound waves determines the pitch, while the intensity of sound waves determines the volume.
Sound that is too loud can cause damage to the hair cells in the cochlea, which are responsible for converting sound vibrations into electrical signals that the brain can understand. The damage to the hair cells is irreversible, so it is essential to protect your ears from loud sounds.
OSHA standards define 85 decibels as the maximum exposure to sound levels that are safe for eight hours per day. If noise levels exceed 85 decibels, earplugs or earmuffs should be used to prevent hearing loss.
Therefore, it is crucial to be cautious with loud sounds and take necessary precautions to avoid hearing damage, such as using earplugs or earmuffs in noisy environments.
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3 Study the circuits in Figure 36.8. The switch S is open (there
is a break in the circuit at this point). In which circuit would
lamps Q and R light but not lamp P?
The circuit in which lamps Q and R light but not lamp P when switch S is open is circuit B.
What is an electric circuit?An electric circuit is a path for transmitting electric current.
Given the circuits below, when switch S is open, we want to determine the circuit in which lamps Q and R light but not lamp P.
To determine the circuit, we proceed as follows.
To determine the circuit in which lamps Q and R light but not lamp P, it must satisfy this condition
The switch must be before lamp P and The circuit for lamp P must be different from that of lamps Q and RLamps Q and R must be in the same circuitLooking at all the circuits, the circuit which satisfy these condition is circuit B
So, the circuit in which lamps Q and R light but not lamp P is circuit B.
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In 7.0 s, a car accelerates uniformly from rest to a velocity at which its wheels are turning at 6.0 rev/s. If the tires of the car have a diameter of 42 cm, and they rolled on the ground without slipping, how far did the car go in those 7.0 s?
The car has traveled a distance of approximately 55.44 m.
In 7.0 s, a car accelerates uniformly from rest to a velocity at which its wheels are turning at 6.0 rev/s. If the tires of the car have a diameter of 42 cm, and they rolled on the ground without slipping, the car will travel a distance of approximately 50.9 meters in those 7.0 seconds.
To calculate the distance, we must first determine the car's final velocity. The angular velocity of the wheels is given by 6.0 rev/s. Since the diameter of the tires is 42 cm, the circumference is:πd = π(0.42 m) = 1.32 m. The velocity of the car can be calculated by multiplying the circumference by the angular velocity: v = 6.0 rev/s × 1.32 m/rev = 7.92 m/s.
Now that we know the final velocity of the car, we can use the formula:d = (vf + vi)t/2where vi = 0 m/s (since the car is initially at rest), vf = 7.92 m/s, and t = 7.0 sd = (7.92 m/s + 0 m/s)(7.0 s)/2 = 27.72 m. The car traveled approximately 27.72 m in the first half of the trip (from rest to the final velocity), and 27.72 m in the second half of the trip (from the final velocity to a complete stop).
Therefore, the total distance traveled by the car in those 7.0 s is approximately 27.72 m + 27.72 m = 55.44 m. However, this is the distance that the wheels have rolled, not the distance that the car has traveled. Since the wheels are not slipping, the distance that the car has traveled is equal to the distance that the wheels have rolled.
So, the car has traveled a distance of approximately 55.44 m. Rounding to the appropriate significant figures, the distance is approximately 50.9 meters.
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XYZ are 3 cities. a = 222 miles. b = 150 miles. Angle YXZ = 30. Angle YZX = 45. c = ___ miles
The length of side YZ (c) is approximately 119.13 miles.
How to calculate the lengthTo find the length of side c, we can use the Law of Cosines, which states:
c² = a² + b² - 2ab * cos(C)
Plugging in the given values:
a = 222 miles
b = 150 miles
C = 30 degrees
We need to convert the angle from degrees to radians to use it in the cosine function. The conversion is as follows:
θ (radians) = θ (degrees) * π / 180
C (radians) = 30 degrees * π / 180 = π / 6 radians
c² = 222² + 150² - 2 * 222 * 150 * cos(π / 6)
c² = 49284 + 22500 - 66600 * cos(π / 6)
c² = 49284 + 22500 - 66600 * (√3 / 2)
c² = 71784 - 66600 * (√3 / 2)
c² = 71784 - 66600 * 0.866
c² = 71784 - 57600
c² = 14184
c = √14184
c ≈ 119.13 miles (rounded to two decimal places)
Therefore, the length of side YZ (c) is approximately 119.13 miles.
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Sherry draws a diagram to compare selective breeding and genetic engineering.
Which label belongs in the area marked Z?
requires modification of DNA
involves the production of offspring
can be done with plants
may result in potential risks
Selective breeding is a traditional technique of breeding organisms with desirable traits, while genetic engineering involves modifying DNA to produce specific traits, with potential risks to consider.
Selective breeding and genetic engineering are two popular techniques that are used to modify organisms. Selective breeding is a traditional technique that has been in practice for centuries, whereas genetic engineering is a modern technique that has been developed in recent times.Selective breeding involves the process of breeding organisms with desirable traits in order to produce offspring that inherit these traits. This technique is often used in agriculture, to produce crops with desirable traits such as resistance to disease or pests, or to produce livestock with desirable traits such as increased meat yield or milk production.Genetic engineering, on the other hand, involves the process of modifying the DNA of organisms in order to produce specific traits. This technique can be used with both plants and animals and can result in the production of offspring with desired traits.Given the above, the label that belongs in the area marked Z is "requires modification of DNA". This is because genetic engineering involves modifying the DNA of organisms in order to produce desired traits. In addition, genetic engineering can result in potential risks, which is an important consideration when using this technique.For more questions on Selective breeding
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Genetic engineering requires the modification of DNA, involves the production of offspring, can be done with plants, animals, and microbes, and may result in potential risks.
Sherry draws a diagram to compare selective breeding and genetic engineering. The label that belongs in the area marked Z is "Requires modification of DNA."While selective breeding entails the selection of the desired traits among animals or plants to breed and perpetuate the selected traits, genetic engineering involves directly manipulating the DNA of an organism to alter its genetic makeup and potentially introducing foreign genes into the organism's genetic material. Selective breeding only requires the crossing of the selected species, whereas genetic engineering requires the modification of the DNA that is involved in the production of offspring. Selective breeding can be done with plants and animals, while genetic engineering can be done with plants, animals, and microbes. Genetic engineering has the potential to result in potential risks as the manipulation of DNA may have unforeseen effects and can cause unintended consequences that can be harmful.For more questions on selective breeding
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a platinum resistance thermometer has a resistance R=40ohm at T=30°c a for pt is 3.92×10^-3°C.the thermometer is immersed in a vessel containing melting tin,at which point R increases to 94.6ohm.what is the melting point of tin
The correct answer is 105.98 C
Given,
[tex]R_1 = 40 ohm\\R_2 = 94.6 ohm\\T_1 = 30 C\\[/tex]
Coefficient of resistance for Pt = 3.92×10^-3°C
[tex]R_1/R_2 = (1+\alpha T_1)/(1+\alpha T_2)\\[/tex]
[tex]40/94.6 = (1+(3.92×10^(-3) * 30)/(1+(3.92×10^(-3)* T_2)\\T_2= 105.98 C[/tex]
Therefore, the melting point of tin is 105.98 C
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What is the correct definition of wave?
A. a pattern of motion that repeats in a cycle
B. a method of carrying matter from place to place
C. a pattern of increasing energy
D. any motion in two directions, such as up and down
A 15 kg block rest on a surface of a smooth plane incline at an angle 30 degree to the horizontal. A light in extensible string passing over a small Smooth Pulley at the top of the plane connect to the block to another 13/kg block hanging freely. find the acceleration of the resulting motion and the tension in the string.
If the coeficient of kinetic friction between the plane and the 15kg mass is 0.25. find the acceleration of the resulting motion
The acceleration of the system is 2.77 m/s² and the tension in the string is 127.4 N, given the provided values.
Given: Mass of the first block (m1) = 15 kgMass of the second block (m2) = 13 kgAngle of the plane (θ) = 30°Coefficient of kinetic friction (μk) = 0.25, Acceleration of the resulting motion (a) = ? Tension in the string (T) = ?First, we need to resolve the weight of the first block into its components perpendicular to and along the plane. Then we can use the component parallel to the plane to find the force of friction acting on the first block. We can then use the net force acting on the first block to find its acceleration. Finally, we can use the acceleration of the first block to find the tension in the string.Resolving the weight of the first block into components parallel to the plane: m1gsinθ = 15 x 9.8 x sin30° = 73.5 N. Perpendicular to the plane: m1gcosθ = 15 x 9.8 x cos30° = 127.5 N. Finding the force of friction acting on the first block: μk = coefficient of kinetic friction = 0.25f = force of friction acting on the first block N = normal force acting on the first block N = perpendicular force acting on the first block = 127.5 Nf = μkN = 0.25 x 127.5 = 31.88 NThe net force acting on the first block:F = maF = m1aF = m1g sinθ - fF = 15 x 9.8 x sin30° - 31.88F = 73.5 - 31.88F = 41.62 N. Acceleration of the first block: a = F/m1a = 41.62/15a = 2.77 m/s². Finding the tension in the string: The tension in the string is the force acting on the second block. We can use the weight of the second block and the acceleration of the first block to find the tension.T - m2g = m1aT = m2g + m1aT = 13 x 9.8 + 15 x 2.77T = 127.4 NTherefore, the acceleration of the resulting motion is 2.77 m/s² and the tension in the string is 127.4 N.For more questions on acceleration
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The four particles as connected by rods of negligible mass as fig below. if the origin is the canter of rectangle and the system rotates in the XY plane about the Z axis with an rad angular speed of 12. calculate S a) The moment of inertia of the system about Z axis and b) The rotational kinetic energy of the system 3.00 kg 2.00 kg y(m) 2.00 kg 6.00 m 4.00 kg ---x(m)
The moment of inertia of the system about the Z-axis is 245 kg m², and the rotational kinetic energy of the system is 21168 J.
The moment of inertia of a system about its axis of rotation is the sum of the products of the masses of its constituents and the square of their respective distances from the axis of rotation.
The radius of the rectangular plate is 6 m, and the distance of each particle from the center is half of the sides of the rectangle, which are 4 m and 3 m.
Therefore, using the parallel axis theorem, we get the moment of inertia of the system about the Z-axis as shown below.
[tex]Iz = ICM + MR^{2}[/tex]
(1)We can obtain the moment of inertia of the rectangle about its center as: [tex]ICM = (1/12) ML^{2}[/tex]
(2) where M is the mass of the rectangle, and L is the length of the rectangle.
Substituting values, we get: ICM = [tex](1/12) $\times$ 3.00 $\times$ (4^{2} + 6^{2} )[/tex]
ICM = [tex]5 kg m^{2}[/tex]
Using the parallel axis theorem, the moment of inertia of the four particles about the center of the rectangle is:
[tex]IP = 4 $\times$ [(1/12) $\times$ 2.00 $\times$ (4^{2} + 3^{2})] + 2.00 $\times$ (3^{2}) + 4.00 $\times$ (4^{2})IP = 97 kg m^{2}[/tex]
The moment of inertia of the system about Z-axis is: [tex]Iz = ICM + MR^{2} Iz = 5 kg m^{2} + 3.00 kg $\times$ (6^{2} ) + 4 $\times$ [(4^{2}+ 3^{2} )/4] Iz = 245 kg m^{2}[/tex]
The kinetic energy of a rotating body is given as:[tex]K.E. = (1/2) I\omega^{2}[/tex] where I is the moment of inertia of the system, and ω is the angular velocity of the system.
The rotational kinetic energy of the system is:[tex]K.E. = (1/2) I\omega^{2} K.E. = (1/2) $\times$ 245 $\times$ (12)^{2} K.E. = 21168 J[/tex]
2)[tex]I\omega^{2} K.E. = (1/2) $\times$ 245 $\times$ (12)^{2} K.E. = 21168 J[/tex]
Therefore, the moment of inertia of the system about the Z-axis is 245 kg m², and the rotational kinetic energy of the system is 21168 J.
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Question 3
A crate, with mass of 21 kg, needs to be lifted and
moved by a machine. The machine attaches a chain to
the crate and pulls on the crate at an angle of 60°
from the ground. What is the minimum pulling force
required by this machine to lift the crate off the
ground, when it pulls the crate at the given angle?
206.0 N
1.25 pts
O 237.9 N
O 305.5 N
O 412.0 N
The minimum pulling force required by the machine to lift the crate off the ground at a 60° angle is 237.9 N.
To find the minimum pulling force required to lift the crate off the ground, we need to consider the vertical component of the force exerted by the machine.
Given that the angle between the chain and the ground is 60°, we can determine the vertical component of the force as follows:
Vertical component = Force * sin(angle)
Let's calculate the vertical component of the force:
Vertical component = Force * sin(60°)
= Force * ([tex]\sqrt{3}[/tex] / 2)
We want to find the minimum pulling force required, so we need to consider the force that counteracts the weight of the crate.
Weight = mass * gravity
Weight = 21 kg * 9.8 m/[tex]s^2[/tex]
= 205.8 N
Since the vertical component of the force must be equal to the weight of the crate to lift it off the ground, we can set up the equation:
Force * ([tex]\sqrt{3}[/tex] / 2) = 205.8 N
Solving for Force:
Force = 205.8 N / ([tex]\sqrt{3}[/tex] / 2)
= 205.8 N * (2 / [tex]\sqrt{3}[/tex])
≈ 237.9 N
Therefore, the minimum pulling force required by the machine to lift the crate off the ground at a 60° angle is approximately 237.9 N.
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Assuming all of the spring’s energy is transferred to the 3.0 kilogram calculate the speed v1 of the 3.0 kilogram block immediately after it is propelled by the spring
The speed (v1) of the 3.0-kilogram block immediately after being propelled by the spring can be calculated by equating the initial potential energy stored in the spring to the kinetic energy of the block. The formula for kinetic energy is given by KE = 1/2 * m * [tex]v^2[/tex], where m is the mass of the object and v is its velocity.
Therefore, using this formula, we can find the speed (v1) as follows:
1. Determine the potential energy stored in the spring using the formula for potential energy: PE = 1/2 * k * [tex]x^2[/tex], where k is the spring constant and x is the displacement from the equilibrium position. As the question does not provide these values, we cannot determine the potential energy directly.
2. However, we can assume that all the spring's energy is transferred to the 3.0-kilogram block, which means the potential energy of the spring is equal to the kinetic energy of the block. Thus, we can equate the two energies:
PE = KE
3. Substitute the formulas for potential energy and kinetic energy:
1/2 * k * [tex]x^2[/tex] = 1/2 * m * [tex]v1^2[/tex]
4. Rearrange the equation to solve for v1:
[tex]v1^2[/tex] = (k * [tex]x^2[/tex]) / m
5. Take the square root of both sides to find v1:
v1 = sqrt((k * [tex]x^2[/tex]) / m)
Please note that to provide an exact numerical value for v1, we would need specific values for the spring constant (k) and the displacement (x) of the spring from the equilibrium position.
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Question 2 A Glindrical obiect has a Muss (M.. • 3.97g). Radiu (R= 5.0m), With a bucket of mass (m= 5.3rg) hanging from a string attached to a Cilindrical direct. Calculate the acceleration Calculate the tention in the String, where the diet is attalled. Calculate the distance it takes for the object to rotate downwards ,in 3.2 seconds.
A person pushes on a box in the East direction with 8
N of force, another person pushes on the same box
south with 20 N of force. What force (magnitude and
direction) would a third person need to push on the
crate so that the box is in equilibrium?
Magnitude of the third
vector is
Direction of third
vector is
✓ [Choose ]
46.40 N
28.00 N
21.54 N
21.8° South of East
21,8° North of West
68.2° South of East
68.2° North of West
Answer:
In order for the box to be in equilibrium, the third person's force should be equal but opposite in direction to the resultant force of the two forces already acting on the box.
First, let's calculate the resultant force acting on the box. The box is being pushed with 8 N to the east and 20 N to the south. Since these forces are at right angles to each other, we can use the Pythagorean theorem to find the magnitude of the resultant force:
Magnitude = sqrt((8 N)^2 + (20 N)^2)
= sqrt(64 N^2 + 400 N^2)
= sqrt(464 N^2)
= 21.54 N
The direction of the resultant force can be calculated using trigonometry. Specifically, we can use the tangent function, which is the ratio of the opposite side to the adjacent side in a right triangle.
tan(θ) = Opposite/Adjacent
tan(θ) = 20 N / 8 N
θ = atan(20/8)
θ = 68.2°
The direction of the force is therefore 68.2° South of East (since we have taken East as the base direction and South as the angle direction).
The third person should therefore apply a force of 21.54 N in the direction exactly opposite to 68.2° South of East, which is 68.2° North of West.
So, the correct choices are:
Magnitude of the third vector is 21.54 N.
Direction of third vector is 68.2° North of West.
A light ray hits a smooth surface, what happens to the speed of the reflected light ray?
Options:
1-the speed increases
2-the speed increases than decrease
3-the speed remains the same
4-the speed decreases
Which one is it??????????????????????
Answer:[tex]\frac{delta x}{a}[/tex]
Explanation:
A CD is a solid disk of mass of 0.0140
kg and a radius 0.0600 m. It rotates at
31.4 rad/s. What is its ROTATIONAL
KE?
Rotational KE is the energy of a rotating object. For a CD with a mass of 0.0140kg, a radius of 0.0600m, and an angular velocity of 31.4 rad/s, the rotational KE is 0.0186 J.
Rotational KE is the energy that a rotating object possesses. It is a type of kinetic energy possessed by objects that rotate about an axis or an object's center of mass. The formula to calculate rotational KE is Rotational KE = 1/2 I ω², Where I represent the moment of inertia, and ω is the angular velocity of the object. A CD is a solid disk of mass of 0.0140kg and a radius of 0.0600 m. It rotates at 31.4 rad/s. Therefore, its moment of inertia (I) can be calculated using the formula: I = 1/2mr²I = 1/2(0.0140kg)(0.0600m)²I = 3.78×10⁻⁵ kg⋅m²Plugging the moment of inertia and the angular velocity into the formula for rotational KE, we get: Rotational KE = 1/2 I ω² Rotational KE = 1/2 (3.78×10⁻⁵ kg⋅m²)(31.4 rad/s)²Rotational KE = 0.0186 JTherefore, the rotational KE of the CD is 0.0186 J.Summary: Rotational KE is a type of kinetic energy possessed by rotating objects. The formula to calculate rotational KE is 1/2 I ω². A CD with a mass of 0.0140kg and a radius of 0.0600 m rotates at 31.4 rad/s. Its rotational KE is 0.0186 J, which is calculated using the formula Rotational KE = 1/2 I ω², where I is the moment of inertia and ω is the angular velocity of the object.For more questions on the angular velocity
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Allanah has declared psychology as her major. Which of the following alternatives best identifies what Allanah will study?
mental processes
mind and behavior
psychological disorders and their treatment
the development of the individual
Psychology is the scientific study of behavior and mental processes. The study of mind and behavior is the best alternative term associated with psychology.
Allanah has declared psychology as her major. Allanah will study mind and behavior which is identified as the best alternative term that is associated with the study of psychology. Psychology is the scientific study of behavior and mental processes. It is the study of mind and behavior in relation to various aspects such as how people perceive, learn, think, feel, and interact with one another and with their environment.Some areas of study in psychology include the following: Mental processes: The study of mental processes involves exploring how people perceive, learn, remember, think, and solve problems. This area of study includes topics like sensation and perception, learning, memory, and cognition. Mind and behavior: This area of study involves examining the ways in which people's thoughts, feelings, and behaviors are connected. It includes topics like motivation, emotion, personality, and social behavior. Psychological disorders and their treatment: This area of study involves exploring the causes, symptoms, and treatments of various mental health disorders. It includes topics like anxiety disorders, depression, schizophrenia, and substance abuse.The development of the individual: This area of study focuses on how people develop physically, cognitively, and socially from birth through old age. It includes topics like child development, adolescence, and aging. Allanah has declared psychology as her major. Since Allanah will be studying psychology, the area of mind and behavior is the best alternative term that is associated with the study of psychology.For more questions on Psychology
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a uniform ladder of weight 200 N and length 10 m leans against a perfectly smooth wall at an angle of 50 degrees. A firefighter of weight 600 N climbs a distance x up the ladder. The coefficient of static friction between the ladder and the floor is 0.50. What is the maximum value of x for which the ladder will not slip?
The maximum value of x, the distance the firefighter can climb up the ladder without it slipping, is 5.14 m.
The maximum value of x for which the ladder will not slip is 5.14 m. Here’s how to find it: Let F be the force exerted by the wall on the ladder and Wl and Wf be the weights of the ladder and the firefighter, respectively. Taking moments about the foot of the ladder gives F × 10 cos 50 - Wf x = 0. . . (1)where x is the distance that the firefighter has climbed up the ladder.Using the fact that the ladder is not slipping, we get F = 0.5 (Wl + Wf)g cos 50. . . (2)where g is the acceleration due to gravity.Substituting (2) into (1) and rearranging for x gives x = 5.14 m (to two decimal places).Summary: A uniform ladder of weight 200 N and length 10 m leans against a perfectly smooth wall at an angle of 50 degrees. A firefighter of weight 600 N climbs a distance x up the ladder. The coefficient of static friction between the ladder and the floor is 0.50. The maximum value of x for which the ladder will not slip is 5.14 m.For more questions on firefighters
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