The speed of the car after the collision is determined as 0.2 m/s.
What is the speed of the car after the collision?The speed of the car after the collision is calculated by applying the principle of conservation of linear momentum as follows;
m1u1 + m2u2 = v(m1 + m2)
where;
m1 and m2 are the masses of the carsu1 and u2 are the initial velocity of the carsv is the final velocity of the cars after the collision20000(3) - 40000(1.2) = v (20000 + 40000)
12,000 = 60,000v
v = 12,0000 / 60,000
v = 0.2 m/s
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Imagine a child swinging back and forth on a swing. Their energy transform from ____ as they swing from the highest point to the lowest point
O A. potential mechanical energy to light energy
• B. potential mechanical energy to kinetic mechanical energy
O c. kinetic mechanical energy to potential mechanical energy.
O D. kinetic mechanical energy to elastic energy
The delivery track is at rest on a horizontal road .It has four wheels and the distance between it's front and rear axle is 2.3 m .Workers have loaded the truck in such a way that it;s center of gravity(cg) is only slightly (0.63) forward of the rear axle.The total mass of the truck and its contents is 8010 kg.Finf the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck.
Answer:
The magnitude of the total vertical force exerted by the ground on the rear wheels of the truck is 62271.86 N
Explanation:
To find the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck, we need to consider the static equilibrium condition of the truck.
The weight of the truck and its contents acts downwards through its center of gravity (cg) and the normal force exerted by the ground acts upwards. The normal force is distributed between the front and rear axles of the truck according to the position of the cg.
Let F_R be the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck.
Then, from the static equilibrium condition:
Sum of vertical forces = 0
F_R + (8010 kg)(9.81 m/s^2) - F_F = 0
where F_F is the magnitude of the total vertical force exerted by the ground on the front wheels of the truck.
The distance between the cg and the rear axle is given as 0.63(2.3 m) = 1.449 m.
The distance between the cg and the front axle is therefore (2.3 m - 1.449 m) = 0.851 m.
We can assume that the weight is evenly distributed between the four wheels of the truck. Therefore, the weight supported by each wheel is:
(8010 kg)(9.81 m/s^2)/4 = 19653.45 N
Using moments about the rear axle, we get:
F_F(0.851 m) - F_R(1.449 m) = 0
Solving these two equations simultaneously, we get:
F_R = 62271.86 N
Therefore, the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck is 62271.86 N.
The magnitude of the total vertical force exerted by the ground on the rear wheels of the truck is approximately 62,203 N.
What is static equilibrium?Static equilibrium refers to the state of an object at rest when the net force acting on it is zero. In other words, when an object is in static equilibrium, it is not accelerating in any direction and all forces acting on it are balanced.
The principle of static equilibrium states that the sum of all forces acting on an object in static equilibrium is zero, and the sum of all torques (rotational forces) acting on the object is also zero. This principle can be applied to solve problems involving the forces and torques acting on objects at rest.
Static equilibrium is important in many areas of physics and engineering, including structural analysis, civil engineering, and mechanical engineering. Understanding static equilibrium is essential for designing structures and machines that can support loads without collapsing or breaking, and for analyzing the stability of systems in various applications.
Here in the Question,
To find the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck, we need to analyze the forces acting on the truck and apply the principle of static equilibrium, which states that the sum of all forces acting on an object in static equilibrium is zero.
The forces acting on the truck are the weight of the truck and its contents and the reaction forces from the ground acting on each of the four wheels. The weight of the truck and its contents can be represented as a single force acting vertically downwards at the center of gravity (cg) of the truck.
Since the truck is at rest on a horizontal road, the reaction forces from the ground acting on the wheels must balance the weight of the truck and its contents in both the horizontal and vertical directions. The horizontal components of the reaction forces cancel each other out, since the truck is at rest and not moving in the horizontal direction.
To find the vertical forces, we can first find the weight of the truck and its contents:
w = m*g
where w is weight, m is mass, and g is the acceleration due to gravity (9.81 m/s^2).
Substituting the given values, we get:
w = 8010 kg * 9.81 m/s^2 = 78,419.1 N
Next, we can find the position of the center of gravity (cg) relative to the front and rear axles of the truck:
d = L * (m1 - m2) / m
where d is the distance from the cg to the rear axle, L is the distance between the front and rear axles (2.3 m), m1 is the mass of the truck and contents behind the cg, m2 is the mass of the truck and contents in front of the cg, and m is the total mass of the truck and contents.
Substituting the given values, we get:
d = 2.3 m * (8010 kg * 0.63 - 8010 kg * 0.37) / 8010 kg = 0.743 m
Now, we can find the magnitudes of the vertical forces acting on the rear and front wheels of the truck using the principle of static equilibrium. Since the truck is not moving vertically, the sum of the vertical forces acting on it must be zero. Therefore:
Frear + Ffront = w
where Frear is the vertical force exerted by the ground on the rear wheels, Ffront is the vertical force exerted by the ground on the front wheels, and w is the weight of the truck and its contents.
The rear wheels support the weight of the truck and its contents, as well as a portion of the weight shifted forward of the rear axle due to the position of the cg. The front wheels support only a portion of the weight shifted backward of the front axle. To find the magnitudes of the vertical forces, we can use the following equations:
Frear = (m1/m)*w
Ffront = (m2/m)*w
where m1 is the mass of the truck and contents behind the cg, m2 is the mass of the truck and contents in front of the cg, and m is the total mass of the truck and contents.
Substituting the given values and using the value of d found earlier, we get:
Frear = (8010 kg * 0.63 / 8010 kg)*78,419.1 N = 62,202.7 N
Ffront = (8010 kg * 0.37 / 8010 kg)*78,419.1 N = 36,216.4 N
The magnitude of the total vertical force exerted by the ground on the rear wheels of the truck is:
Frear = 62,202.7 N ≈ 62,203 N
Therefore, the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck is approximately 62,203 N.
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A student is using two circuits to investigate power consumption. She connects two identical light bulbs in series in one circuit and in parallel in the second circuit. What should she measure to calculate which configuration uses more power?
Responses
A The resistance of the bulbs and the potential difference of the battery.The resistance of the bulbs and the potential difference of the battery.
B The current flowing into each bulb and the potential difference across each bulb.The current flowing into each bulb and the potential difference across each bulb.
C The current flowing out of the battery and the resistance of each bulb.The current flowing out of the battery and the resistance of each bulb.
D The potential difference of the battery and the resistance of the battery.
The potential difference across the each bulb and the current entering each bulb.
What occurs if you connect two light bulbs in series?Each bulb in a straightforward parallel circuit receives the entire battery power. This is explains why the parallel circuit's lights will shine stronger than the series circuit's. The parallel circuit also has the benefit of maintaining an electricity even if one loop is disconnected.
When are two identical bulbs linked in both series and parallel?The same brightness is produced when two identical bulbs are linked in parallel as it is when they are connected in a series, which is why.
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The figure below (Figure 1) illustrates an Atwood's machine. Let the masses of blocks A
and B be 5.50 kg and 2.00 kg, respectively, the moment of inertia of the wheel about its axis be 0.400 kg⋅m2 and the radius of the wheel be 0.110 m.
A. Find the linear acceleration of block A if there is no slipping between the cord and the surface of the wheel.
B. Find the linear acceleration of block B if there is no slipping between the cord and the surface of the wheel.
C. Find the angular acceleration of the wheel C if there is no slipping between the cord and the surface of the wheel.
D. Find the tension in left side of the cord if there is no slipping between the cord and the surface of the wheel.
E. Find the tension in right side of the cord if there is no slipping between the cord and the surface of the wheel.
A.The linear acceleration of block A is [tex]a = -3.42 m/s^2[/tex]
B.The linear acceleration of block B is [tex]a = 3.42 m/s^2[/tex]
C.The angular acceleration of the wheel c is [tex]a= -31.09 rad/s^2[/tex]
D. The tension in the left side is T = -210.83 N
E.The tension in the right side is T = -58.75 N
A. The linear acceleration of block A can be calculated using the equation for the acceleration of an Atwood's machine:
[tex]a =\frac{ (m2 - m1)g}{ (m1 + m2)}[/tex]
Substituting the given values, the linear acceleration of block A is:
[tex]a =\frac{ (2.00 kg - 5.50 kg) 9.81 m/s^2 }{ (5.50 kg + 2.00 kg)}\\a = -3.42 m/s^2[/tex]
B. The linear acceleration of block B can be calculated using the same equation:
[tex]a =\frac{ (m2 - m1)g}{ (m1 + m2)}[/tex]
Substituting the given values, the linear acceleration of block B is:
[tex]a = \frac{(2.00 kg - 5.50 kg) 9.81 m/s^2 }{ (5.50 kg + 2.00 kg)}\\a = 3.42 m/s^2[/tex]
C. The angular acceleration of the wheel can be calculated using the equation:
[tex]a = \frac{a}{r}[/tex]
where α is the angular acceleration, a is the linear acceleration and r is the radius of the wheel.
Substituting the given values and the value for the linear acceleration of block A, the angular acceleration of the wheel is:
[tex]a = \frac{-3.42 m/s2 }{ 0.110 m}[/tex]
[tex]a= -31.09 rad/s^2[/tex]
D. The tension in the left side of the cord can be calculated using the equation:
T = m1a + m1rα
Substituting the given values, the tension in the left side of the cord is:
T = 5.50 kg (-3.42 m/s2) + 5.50 kg (0.110 m) (-31.09 rad/s2)
T = -210.83 N
E. The tension in the right side of the cord can be calculated using the equation:
T = m2a + m2rα
Substituting the given values, the tension in the right side of the cord is:
T = 2.00 kg (3.42 m/s2) + 2.00 kg (0.110 m) (-31.09 rad/s2)
T = -58.75 N
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Can you answer this question?
a) The multimeter in figure 2(a) is set up to measure DC voltage. The setting is indicated by the V with a straight line above it, which stands for "DC voltage".
b) The multimeter in figure 2(a) reads 25.6 V (volts).
c) The multimeter in figure 2(b) is set up to measure DC current. The setting is indicated by the A with a straight line above it, which stands for "DC current".
d) The multimeter in figure 2(b) reads 0.40 A (amperes).
What is multimeter?
A multimeter is an electronic instrument that is used to measure electrical parameters such as voltage, current, and resistance. Multimeters can measure AC and DC voltage, AC and DC current, resistance, continuity, capacitance, and frequency.
What is DC volage?
DC voltage refers to the level or strength of a direct current (DC) electrical signal. Direct current is a type of electrical current that flows in one direction only and does not alternate in polarity. DC voltage can be measured using a multimeter or other voltage measurement instrument, and is typically expressed in volts (V). DC voltage is commonly used in many electronic devices and systems, such as batteries, power supplies, and DC motors.
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URGENT PLEASE HELP 100 POINTS AND BRAINLIEST!
Physics Essay
Pick one of the sources of energy and write an essay on why you think that source of
energy is better than the rest.
Discuss why the other sources of energy are not as beneficial as the one you chose. (This
step will be important for the debate).
You can write the essay by hand or type it. If you choose to type the essay it should be 12
pt font and double spaced.
There is no page limit, however you should have at least 3 paragraphs and you should
provide enough details that I can recognize why you chose that source of energy and
what the benefits of using that source of energy are. Also remember you need to have
some sort of counter argument on why other types of energy are not as beneficial as the
one that you chose.
Do not plagiarize your essay. If you plagiarize you WILL get a 0.
Make sure to cite any sources that you use to write this paper.
Solar energy is an increasingly popular form of energy that is quickly becoming more efficient and cost effective than other sources of energy.
What is energy?Energy is the capacity of a physical system to do work. It is a property of objects which can be transferred to other objects or converted into different forms, but cannot be created or destroyed. Energy can take the form of kinetic, potential, thermal, electrical, chemical, nuclear, or other various forms.
Solar energy is an abundant, renewable source of energy that can be used to power homes, businesses, and other applications without harming the environment. Solar energy is produced when energy from the sun is captured and converted into electricity. This electricity can be used to power everyday appliances and other activities.
Solar energy has many advantages over other forms of energy. For starters, it is a clean form of energy that does not create any air or water pollution. Additionally, solar energy does not require any finite resources, such as coal or oil, to produce. This means that solar energy is an inexhaustible source of energy and is able to provide an unlimited amount of power. Solar energy is also very cost effective compared to other sources of energy. Solar installations require a significant upfront cost, but the savings in energy costs can be significant.
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The velocity of a train is 112 km/h north. What length of track is required?
Answer: The length of track required is 500 m.
Explanation: Determine the object's original velocity by dividing the time it took for the object to travel a given distance by the total distance. In the equation V = d/t, V is the velocity, d is the distance, and t is the time.
Brainliest? <33
Two vehicles, a 3,650-kg car and a 9,850-kg truck, are parked in a lot 25.0 meters apart.
Calculate the gravitational force between these two vehicles.
500 kilograms of supplies are added to the truck. Explain whether the gravitational force increases, decreases, or stays the same between the two vehicles.
Remember to identify all data (givens and unknowns), list equations used, show all your work, include units and the proper number of significant digits, and write explanation in complete sentences
As 500 kg of supplies are added to the truck, the gravitational force between the two vehicles rises from 1.27 106 N to 1.33 106 N.
Does the gravitational force between two objects grow or decrease as their distance decreases?As a result, when the space between the objects is cut in half, the gravitational force multiplies by four.
The Newton's Law of Universal Gravitation can be used to compute the gravitational force between the two vehicles: F = G * (m1 * m2) / d²
Plugging in the values given in the problem, we get:
F = 6.6743 × 10⁻¹¹ * ((3,650 kg) * (9,850 kg)) / (25.0 m)²
F = 1.27 × 10⁻⁶ N
As a result, there is 1.27 106 N of gravitational force between the two vehicles.
The separation between the two vehicles stays constant. Hence, after entering the updated values, we obtain:
F = 6.6743 × 10⁻¹¹ * ((3,650 kg) * (10,350 kg)) / (25.0 m)²
F = 1.33 × 10⁻⁶ N
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What type of system is represented by the image below?
Group of answer choices
Isolated system
Semi-open system
Closed system
Open system
Answer:
This is an isolated system
Explanation:
By the definition
"Isolated system is a type of system on which no external force acts on"
In the above diagram, the surroundings are not applying any force on the enclosed system
Hence it is an Isolated system (Option 1)
Hope you understand
Please mark the brainliest :)
Question 1
A stone of 8 kg mass falls from the top
of an 80 m-high building. Find the
kinetic energy of the stone when it
reaches the ground.
Points 2
R
Re
be
ce
as
To determine the stone's kinetic energy when it touches the ground, we can use the law of conservation of energy. The stone is initially at rest 80 metres above the ground, and its potential energy is provided by: PEi = mg
What energy does a body of mass 5 kg possess when it is put 10 metres above the ground?(ii) For free fall, the body's overall energy supply remains constant at any given moment. It is the same as adding P.E. and K.E.
What is the energy that an item with a mass of 10 kg has at a height of 6 metres?The energy held by the 10 kg item at 6 inches in height. m above ground is 588 J.
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Consider a tall building located on the Earth's equator. As the Earth rotates, a person on the top floor of the building moves faster than someone on the ground with respect to an inertial reference frame because the person on the ground is closer to the Earth's axis. Consequently, if an object is dropped from the top floor to the ground a distance h below, it lands east of the point vertically below where it was dropped.
(a)
How far to the east will the object land? Express your answer in terms of h, g, and the angular speed
The object will land a distance of ωR√(2h/g) east of the point vertically below where it was dropped.
What is rotation of earth?
The rotation of the Earth causes the object to have an eastward velocity component, which causes it to land to the east of the point vertically below where it was dropped.
To determine how far to the east the object will land, we need to consider the following:
The eastward velocity component of the object due to the Earth's rotation.The time it takes for the object to fall from the top of the building to the ground.The distance the object moves eastward during that time due to its eastward velocity component.Let's assume that the building is located exactly on the equator, so its distance from the Earth's axis is equal to the radius of the Earth, R. The angular speed of the Earth's rotation is given by the symbol omega, which is approximately equal to 7.27 x 10⁻⁵ radians per second.
First, let's find the eastward velocity component of the object due to the Earth's rotation. This can be calculated using the formula:
v = ω * R * cos(latitude)
where;
latitude is the latitude of the location (in this case, 0 degrees for the equator).Since cos(0) = 1, the formula simplifies to:
v = ωR
Next, let's find the time it takes for the object to fall from the top of the building to the ground. This can be calculated using the formula:
t = √(2h/g)
where;
h is the height of the building and g is the acceleration due to gravity, which is approximately 9.81 m/s²Finally, let's find the distance the object moves eastward during that time due to its eastward velocity component.
This can be calculated using the formula:
d = vt
Substituting the formulas for v and t, we get:
d = ωR√(2h/g)
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When a parachute opens, the air exerts a large drag
force on it. This upward force is initially greater than
the weight of the sky diver and, therefore, slows him down. The mass of the sky diver is 82.0 kg and the drag force has a magnitude of 850 N. What are the
magnitude and direction of his acceleration?
The skydiver is accelerating upward with an upward orientation with an acceleration of 0.556 m/s².
What is acceleration?The pace at which a speed changes over time is called acceleration. In other words, it is a measurement of how quickly an object's velocity alters. It is a vector quantity with a direction and magnitude.
Finding the net force affecting the skydiver can be our first step. The vector sum of all forces acting on the skydiver is known as the net force. Weight and drag force are the two forces at play here as they affect the skydiver.
The skydiver's weight is determined by:
Weight= mass x acceleration due to gravity
Weight: 82.0 kg x 9.81 m/s² (acceleration due to gravity)
Weight= 804.42 N
The skydiver is under the following net force:
net force = weight - drag force
850 N - 804.42 N = Net force
45.58 N of net force (upwards)
The skydiver will accelerate upwards since the net force is upward. The magnitude of the acceleration can be determined by applying Newton's second law of motion:
Net force is calculated as follows:
Net force = mass x acceleration
45.58 N = 82.0 kg x acceleration
Acceleration = 0.556 m/s².
As a result, the skydiver is accelerating upward with an upward orientation with an acceleration of 0.556 m/s².
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A 18.0 kg block slides down an inclined plane (angle of inclination is 36 degrees). If the coefficient of kinematic friction is 0.55, what is the acceleration of the block? Consider g = 9.8 m/s². Express your answer correct to 2 decimal places. Add the appropriate unit(s).
Answer:
Explanation:
The force of gravity acting on the block can be resolved into two components, one parallel to the incline and one perpendicular to the incline. The perpendicular component is balanced by the normal force of the incline, and the parallel component is opposed by the force of friction. The force of friction is given by:
F_friction = coefficient_of_friction * F_norm
where F_norm is the normal force of the incline. The normal force is equal in magnitude and opposite in direction to the perpendicular component of the force of gravity, which is:
F_perpendicular = m * g * cos(theta)
where m is the mass of the block, g is the acceleration due to gravity, and theta is the angle of inclination.
The parallel component of the force of gravity is:
F_parallel = m * g * sin(theta)
The net force acting on the block is:
F_net = F_parallel - F_friction
Using Newton's second law, F = m * a, we can solve for the acceleration of the block:
a = F_net / m
Substituting the expressions for F_parallel and F_friction, we get:
a = [m * g * sin(theta) - coefficient_of_friction * m * g * cos(theta)] / m
Simplifying, we get:
a = g * [sin(theta) - coefficient_of_friction * cos(theta)]
Substituting the given values, we get:
a = 9.8 m/s^2 * [sin(36°) - 0.55 * cos(36°)] = 6.43 m/s^2
Therefore, the acceleration of the block is 6.43 m/s^2.
The characteristic spectral lines for the molybdenum element occur at lamda= 6.4 x 10^-11m and lamda= 7.5 x 10^-11m. What is the minimum potential difference needed to accelerate electrons in an x-ray tube to produce both of these lines
Answer:
E = h ν energy of wave of frequency ν
ν = c / λ frequency of wave in terms of wavelength
E = h c / λ
Since λ = 6.4E-11 is the shortest wavelength this corresponds to the highest potential needed
E = 6.63E-34 * 3.00E8 / 6.4E-11 = 3.11E-15 joules
V = E / q = 3.11E-15 / 1.6E-19 = 19,400 volts
Note (E above is energy required and not the electric field)
Find the Equivalent Resistance for the circuit.
The equivalent resistance of the circuit is 5.65 k
What is equivalent resistance?Equivalent resistance of an electric circuit is the equivalent sum of all the resistances in the circuit whether in series or in parallel.
Now, in the circuilt above, we can see that we have two resistances 1.1 k and 4.55 k. We also note that the resistances are in series.
For resistors in series, to find their equivalent resistance, we add them together.
So, the equivalent reistance R = R' + R" where R' = 1.1k and R" = 4.55 k
So, substituting the values of the variables into the equation, we have that
R = R' + R"
= 1.1 k + 4.55 k
= 5.65 k
So, the equivalent resistance is 5.65 k
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12.11 the rate law of a reaction can only be determ ined from experiment. two experiemntal procedures for determining rate laws were outline din chapter 12. what are the two procedures and how are thye used to detemrine the rate laws
The two experimental procedures for determining rate laws are the method of initial rates and the graphical method.
The two experimental procedures for determining rate laws are the method of initial rates and the graphical method.
Method of Initial Rates: This method involves measuring the initial rates of reaction under different initial concentrations of reactants while keeping all other conditions constant. The rate law can be determined by comparing the initial rates with the initial concentrations of the reactants.
Graphical Method: In this method, the concentration of the reactants is plotted against time. The rate law can be determined by analyzing the slope of the resulting curves.
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Hot air moves into a valley, causing a hot day. Which method of heat transfer is this an example of?
Group of answer choices
Radiation
Kinetic energy
Conduction
Convection
How much force is needed to accelerate a 70kg table at a rate of 4 m/s
Answer:
F = 280 NExplanation:
To determine the force needed to accelerate a 70 kg table at a rate of 4 m/s², we can use Newton's second law of motion, which states that force (F) is equal to mass (m) times acceleration (a).
So, we can calculate the force (F) required using the following formula:
F = m x awhere F is the force in Newtons (N), m is the mass in kilograms (kg), and a is the acceleration in meters per second squared (m/s²).
Plugging in the given values, we get:
F = 70 kg x 4 m/s²F = 280 NTherefore, the force needed to accelerate a 70 kg table at a rate of 4 m/s² is 280 Newtons.In the classroom demonstration illustrated in V Figure 8.30, a person on a rotating stool holds a rotating bicycle wheel by handles attached to the wheel. When the wheel is held horizontally, she rotates one way (clock-wise as viewed from above). When the wheel is turned over, she rotates in the opposite direction. Explain why this occurs. [Hint: Consider angular momentum vectors.]
Answer:
People are familiar with F = M a in rectilinear motion
Γ = I α is the corresponding relation in rotational motion.
Also, Γ = R X F gives the direction of the torque
When the wheel is turned over the direction of R is reversed since if it was pointing to the right the lever arm on which the force was acting is now pointing to the left. The gravitational force is still pointing downward so the direction of Γ has been reversed and the gravitational force is still in the downwards direction and there is a reversal in the torque acting on the wheel.
One can also think of the wheel having bendable spokes. A force that would turn the wheel and bend the spokes in one direction would have the opposite effect when the wheel was turned over. (A force forcing the spokes backwards would still force the spokes backwards when the wheel is turned over but now the wheel is rotating in the opposite direction)
Consider the heaviest box of 68 kg
that you can push at constant speed across a level floor, where the coefficient of kinetic friction is 0.30, and estimate the maximum horizontal force that you can apply to the box. A box sits on a ramp that is inclined at an angle of 60.0 ∘
above the horizontal. The coefficient of kinetic friction between the box and the ramp is 0.30. If you apply the same magnitude force, now parallel to the ramp, that you applied to the box on the floor, what is the heaviest box that you can push up the ramp at constant speed? (In both cases assume you can give enough extra push to get the box started moving.)
The heaviest box that you can push up the ramp at constant speed is 114kg where the coefficient of kinetic friction is 0.30.
Given the mass of heaviest box (m) = 68kg
The coefficient of kinetic friction of floor is (k1) = 0.30
The angle of inclination of ramp (θ) = 60°
The coefficient of kinetic friction between the box and ramp is(k2) = 0.30
The speed to push box on floor is constant = F
In the first case, the maximum horizontal force that can be applied to the box is equal to the coefficient of kinetic friction multiplied by the weight of the box.
F1 = k1 * m = 68 * 0.30 = 20.4 N.
In the second case, the maximum force that can be applied to the box is equal to the coefficient of kinetic friction multiplied by the normal force that the ramp exerts on the box.
The maximum force on ramp is (F2) = 0.30 x 68 x cos 60.0 = 34.2 N.
Thus it means that you can push a heavier box up the ramp at constant speed than you can across the level floor.
The maximum weight of the box that can be pushed up the ramp at constant speed is (M) = F2/k2 = 34.2 N / 0.30 = 114 kg.
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in the unit vector notation, what is the net torque about the origin on a flea located at coordinates (0, -4.0m, 5.0m) qhwn forces F1=(3.0N)k^ and F2= (-2.0N)j^ act on the flea>=>
Answer:
i hope this is what you are looking for
If proteins contain mutations, the proteins often do not maintain the proper shape and are unable to perform their functions. Properly functioning proteins are essential to maintaining healthy organisms.
Which statement describes the overall consequence of proteins containing mutations like those described in the passage?
Excess electrons are placed on a small lead sphere with a mass of 7.90 g
so that its net charge is −3.15×10−9 C
.
a) Find the number of excess electrons on the sphere.
b) How many excess electrons are there per lead atom? The atomic number of lead is 82, and its molar mass is 207g/mol.
a) The number of excess electrons on the sphere is 1.97 x 10^10 electrons.
b) There are 0.0000857 excess electrons per lead atom.
Electrostatic problema) The elementary charge of a single electron is -1.6 x 10^-19 C. To find the number of excess electrons on the sphere, we can divide the total charge by the charge of a single electron:
-3.15 x 10^-9 C / (-1.6 x 10^-19 C/electron) = 1.97 x 10^10 electrons
b) To find the number of excess electrons per lead atom, we need to first find the number of lead atoms in the sphere. We can use the molar mass of lead and the mass of the sphere to find the number of moles of lead:
7.90 g / 207 g/mol = 0.0382 mol
Next, we can use Avogadro's number to find the number of lead atoms:
0.0382 mol x (6.02 x 10^23 atoms/mol) = 2.30 x 10^22 atoms
Finally, we can divide the number of excess electrons by the number of lead atoms:
1.97 x 10^10 electrons / 2.30 x 10^22 atoms ≈ 0.0000857 excess electrons per lead atom.
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As an electron that is placed between the plates below moves toward the positive plate, the force acting on it.
As an electron moves towards the positive plate in a uniform electric field between two parallel plates, the distance between the electron and the positive plate decreases, force causing the electric field between them to increase. Hence, the correct option is (2).
In the given diagram, there is a uniform electric field between two parallel plates, with the positive plate on the left and the negative plate on the right. When an electron is placed between the plates and moves towards the positive plate, it experiences a force due to the electric field. The direction of this force is opposite to the direction of the electric field and is given by F = qE, where F is the force, q is the charge of the electron, and E is the electric field. As the electron moves towards the positive plate, the distance between the electron and the positive plate decreases, which means that the electric field between them increases. Therefore, the force acting on the electron also increases according to F = qE. Hence, the correct option is (2) increases.
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Artificial gravity is a must for any space station if humans are to live there for an extended length of time. Without artificial gravity, human growth is stunted and biological functions break down.
An effective way to create artificial gravity is through the use of a rotating enclosed cylinder, as shown in the figure. Humans walk on the inside of the outer edge of the cylinder, which has a diameter of =2135 m that is large enough such that its curvature is not readily noticeable to the inhabitants. (The space station in the figure is not drawn to scale.)
Once the space station is rotating at the necessary angular speed to create an artificial gravity of 1, how many minutes would it take the space station to make one revolution?
The space station would complete one revolution in about 2.2 minutes.
Why would astronauts require artificial gravity to maintain normalcy during lengthy space missions?It's exciting to consider the use of artificial gravity inside a spacecraft. Many believe it would be a smart way to maintain humans' health on lengthy missions, preventing bone and muscle loss over the roughly 18 months it would take to fly to and from Mars in weightlessness.
The period of rotation T can be calculated using the formula T = 2π/ω, where ω is the angular velocity. Since the artificial gravity is equal to 1g, we can use the formula g = ω²r, where r is the radius of the cylinder. When we solve for, we obtain = sqrt(g/r).
Substituting the given values, we get ω = sqrt(9.81 m/s² / (2135/2 m)) = 0.0477 rad/s.
Using the formula for T, we get T = 2π/ω = 131.9 seconds, or approximately 2.2 minutes.
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a. Whats the initial momentum of the ball.
b. what is the final momentum after the ball was hit ?
c. what is the change in momentum of the ball ?
The change in momentum of the ball is -1.215 kg m/s. This is known as the law of conservation of momentum, which states that the total momentum of an isolated system remains constant if no external forces act upon it.
What is Momentum?
Momentum is a physics concept that describes the quantity of motion an object has. It is defined as the product of an object's mass and velocity. The formula for momentum is p = mv, where p is momentum, m is mass, and v is velocity. Momentum is a vector quantity, meaning it has both magnitude and direction. In the absence of external forces, the total momentum of a system is conserved.
a. The initial momentum of the ball can be calculated using the formula:
p = mv
where p is the momentum, m is the mass, and v is the velocity.
p = (0.045 kg) (27 m/s) = 1.215 kg m/s
Therefore, the initial momentum of the ball is 1.215 kg m/s.
b. The final momentum of the ball can also be calculated using the formula:
p = mv
Assuming the ball comes to a stop after being hit, the final velocity will be 0 m/s. So we get:
p = (0.045 kg) (0 m/s) = 0
Therefore, the final momentum of the ball is 0 kg m/s.
c. The change in momentum of the ball can be calculated using the formula:
Δp = pf - pi
where Δp is the change in momentum, pf is the final momentum, and pi is the initial momentum.
Δp = 0 - 1.215 kg m/s = -1.215 kg m/s
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If soil did not have bacteria in it, then?
A: plants would probably not have enough nitrogen.
B: we probably could not digest our food.
C: plants would probably never die.
D: we could not eat yogurt.
Answer:
A
Explanation:
The bacteria exists as organic matter
Answer:
a) is probably the answer
A shuffleboard disk is accelerated to a speed of 5.6 m/s and released. If the coefficient of kinetic friction between the disk and the concrete court is 0.34, how far does the disk go
before it comes to a stop? The courts are 14.3 m long.
The disk must have traveled a distance of 4.52 meters before coming to a stop.
Coefficient of FrictionWe can use the equation for the distance traveled by an object under constant acceleration:
d = (v_f^2 - v_i^2) / (2 * a)
where d is the distance traveled, v_f is the final velocity (in this case, zero), v_i is the initial velocity (in this case, 5.6 m/s), and a is the acceleration.The acceleration of the disk is determined by the force of friction, which is given by:
F_friction = friction_coefficient * F_normal
where F_normal is the normal force, which is equal to the weight of the disk, and the friction coefficient is given as 0.34.We can find the weight of the disk by using the formula:
F_gravity = m * g
where F_gravity is the force of gravity, m is the mass of the disk, and g is the acceleration due to gravity (taken as 9.8 m/s^2).Let's assume the mass of the disk is 0.5 kg. Then:
F_gravity = 0.5 kg * 9.8 m/s^2 = 4.9 N
So the normal force on the disk is also 4.9 N.
Now we can find the force of friction:
F_friction = 0.34 * 4.9 N = 1.67 N
The acceleration of the disk is given by:
a = F_friction / m = 1.67 N / 0.5 kg = 3.34 m/s^2
Plugging this into the equation for distance, we get:
d = (0 - (5.6 m/s)^2) / (2 * (-3.34 m/s^2)) = 4.52 m
Therefore, the disk travels 4.52 meters before coming to a stop, which is less than the length of the court (14.3 m).
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Place these events in order to demonstrate the steps in how sound travels.
You kick a stone and it starts to roll.
In turn, those air molecules set more air molecules in motion.
As the stone starts to move, it stirs up air molecules around it.
The first air molecules to move shake up the other air molecules around them.
Pls help me
Answer:
(1) you kick the stone
(2) air molecules are set in motion
(3) the first molecules set other molecules in motion
(4) these moving molecules set other molecules in motion
In an old-fashioned camera, the light sensitive film is placed 2.8 cm behind the camera lens, so that it gives a magnification of 1.2 × 103. The image of a tree on the film is 2.3 cm high. How tall was the real tree?
The height of the real tree is 1.92 × 10^-3 cm.
We can use the magnification formula to solve this problem. The magnification formula relates the size of the object to the size of its image and is given by: magnification = size of image/size of the object
In this case, the magnification is given as 1.2 × 10^3, the size of the image is 2.3 cm, and we want to find the size of the object, which is the height of the tree. So we can rearrange the formula to solve for the size of the object: the size of the object = size of the image/magnification
Substituting the given values, we get:
size of object = 2.3 cm / 1.2 × 10^3 = 1.92 × 10^-3 cm
So the height of the real tree is 1.92 × 10^-3 cm.
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