A rocket moves straight upward, starting from rest with an acceleration of +29.4 m/sec2 . It runs out of fuel after 4 seconds and continue to rise, reaching a maximum height before falling back to Earth. a) Find the rocket's velocity and height at the moment fuel ends. b) Find the maximum this rocket can reach. c) Find the velocity the instant before the rocket crashes on the ground.

Answers

Answer 1

Answer:

(a). The rocket's velocity is 117.6 m/s.

(b). The rocket can reach at maximum height is 940.8 m.

(c). The velocity the instant before the rocket crashes on the ground is 135.7 m/s.

Explanation:

Given that,

Acceleration = 29.4 m/s²

Time = 4 sec

(a). We need to calculate the rocket's velocity

Using equation of motion

[tex]v=u+at[/tex]

Put the value into the formula

[tex]v=0+29.4\times4[/tex]

[tex]v=117.6\ m/s[/tex]

We need to calculate the maximum height at the moment fuel ends

For the value of x₁

Using equation of motion

[tex]x_{1}=ut+\dfrac{1}{2}at^2[/tex]

Put the value into the formula

[tex]x_{1}=0+\dfrac{1}{2}\times29.4\times4^2[/tex]

[tex]x_{1}=235.2\ m[/tex]

We need to calculate the value of x₂

Using equation of motion

[tex]v^2=u^2-2gx_{2}[/tex]

Put the value into the formula

[tex]0=u^2-2gx_{2}[/tex]

[tex]x_{2}=\dfrac{u^2}{2g}[/tex]

Put the value in to the formula

[tex]x_{2}=\dfrac{117.6^2}{2\times9.8}[/tex]

[tex]x_{2}=705.6\ m[/tex]

(b). We need to calculate the maximum this rocket can reach

Using formula for height

[tex]H=x_{1}+x_{2}[/tex]

Put the value into the formula

[tex]H=235.2+705.6[/tex]

[tex]H=940.8\ m[/tex]

(c). We need to calculate the velocity the instant before the rocket crashes on the ground

Using equation of motion

[tex]v^2=u^2+2gh[/tex]

Put the value into the formula

[tex]v=\sqrt{2\times9.8\times940.8}[/tex]

[tex]v=135.7\ m/s[/tex]

Hence, (a). The rocket's velocity is 117.6 m/s.

(b). The rocket can reach at maximum height is 940.8 m.

(c). The velocity the instant before the rocket crashes on the ground is 135.7 m/s.


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Answer:

1

2

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4

Explained:

All the statement are correct about surface tension of water. Due to this force, water surface exhibit peculiar properties  compared to the bulk of the system.

What is surface tension ?

Surface tension is the potential for liquid surfaces that are at rest to condense into the smallest surface area. Razor blades and insects, which have a density greater than that of water, may float on the surface of the water without even getting partially buried because to surface tension.

Surface tension at liquid-air contacts originates from the liquid molecules' stronger attraction to one another owing to cohesion than to the air molecules due to adhesion.

Surface tension is the result of water molecules pulling inward with a strong attractive force. The attractive force brings the molecules on the surface of the water close together makes attractive force causes the molecules to be drawn toward the water molecules beneath the surface.

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Answer:

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Explanation:

Answer:

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Explanation:

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Answers

Answer:

vx = 65 yd/3 sec  = 21.7 yd/sec  since horizontal speed is constant

vy = g t = (32 / 3) yd/sec^2 * 1.5 sec = 16 yd/sec   where 32/3 is the acceleration due to gravity in yds / sec^2  and 1.5 is the time to travel each way in the vertical direction

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You can check using the range formula:

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Answers

Answer:

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Answer:

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Explanation:

Hi there !

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Answers

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