The total distance described by the rubber ball before it comes to rest is 100 meters.
At the first drop, the ball falls from a height of 50 meters, and then rebounds to a height of 25 meters. So, the distance covered in the first drop and rebound is 50 + 25 = 75 meters.
At the second drop, the ball falls from a height of 25 meters and rebounds to a height of 12.5 meters. So, the distance covered in the second drop and rebound is 25 + 12.5 = 37.5 meters.
At the third drop, the ball falls from a height of 12.5 meters and rebounds to a height of 6.25 meters. So, the distance covered in the third drop and rebound is 12.5 + 6.25 = 18.75 meters.
This process repeats until the height of the rebound is less than 0.01 meters, at which point we consider the ball to have come to rest.
The total distance covered by the ball is the sum of all the distances covered during each drop and rebound, which is:
75 + 37.5 + 18.75 + 9.375 + 4.6875 + 2.34375 + ...
This is a geometric series with first term 75 and common ratio 1/2. Using the formula for the sum of an infinite geometric series, we get:
total distance = 75 / (1 - 1/2) = 100 meters.
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A very long, uniformly charged cylinder has radius R and linear charge density λ.
- A) Find the cylinder's electric field strength outside the cylinder, r≥R. Give your answer as a multiple of λ/ε0.
- B) Find the cylinder's electric field strength inside the cylinder, r≤R. Give your answer as a multiple of λ/ε0.
Express your answers in terms of some or all of the variables R, r, and the constant π.
A very long, uniformly charged cylinder has radius R and linear charge density λ. The cylinder's electric field strength outside the cylinder (r≥R) is given by E = λ/(2πε0r) (where ε0 is the permittivity of free space) and inside the cylinder (r≤R) is given by E = λr/(2πε0R²).
Given:
Radius of the cylinder, RLinear charge density, λTo find:
Electric field strength outside the cylinder (r≥R)Electric field strength inside the cylinder (r≤R)Electric field strength outside the cylinder (r≥R)The cylinder is very long, so it can be considered an infinitely long cylinder. Thus, the electric field lines are perpendicular to the cylindrical surface of radius R and the magnitude of the electric field E is given by Gauss's law.
Using Gauss's law for the cylindrical surface, we get:
E2πrl = λ/ε0
Where,
l is the length of the cylinder.Rearranging this equation, we get:
E = λ/(2πε0r)
Electric field strength inside the cylinder (r≤R)
Using Gauss's law for a cylindrical surface of radius r (r ≤ R) inside the cylinder, we get:
E(2πrl) = λr/ε0R²
Rearranging this equation, we get:
E = λr/(2πε0R²)
Hence, the electric field strength outside the cylinder (r≥R) is given by E = λ/(2πε0r) and inside the cylinder (r≤R) is given by E = λr/(2πε0R²).
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a car of mass 1147 kg (including the driver) turns to the right on a circular arc on flat pavement. if the distance around the quarter circle is 43.6 m and the speed was 13.6 m/s, find the centripetal acceleration and the static friction force on the car tires.
The centripetal acceleration of the car tires is 17.01 m/s². The static friction force on the car tires is 11242.6 μs N
Given,
Mass of car (m) = 1147 kg
Distance around quarter circle (s) = 43.6 m
Speed (v) = 13.6 m/s
The centripetal acceleration is given as
a = v²/r
Where,
v is the velocity of the object around the circle
r is the radius of the circle
Static friction force on the car tires is given by
Ff = μs x N
Where,
μs is the coefficient of static friction
N is the normal force on the object
Steps to calculate Centripetal acceleration
a = v²/rr = s/π = 43.6 m/4 = 10.9 mv = 13.6 m/sa = v²/r = (13.6 m/s)² / 10.9 m= 17.01 m/s²
Therefore, centripetal acceleration is 17.01 m/s².
Steps to calculate the Static Friction force on the car tires
f = μs x N
The normal force N can be calculated by N = mg
where g is the acceleration due to gravity = 9.8 m/s²N = mg = 1147 kg x 9.8 m/s²= 11,242.6 N
Static friction force on the car tires is given by,
Ff = μs x N= μs x (1147 kg x 9.8 m/s²)= 11242.6 μs N
The formula for calculating static friction force on the car tires is
Ff = μs x N.
The normal force N can be determined as follows:
N = mg,
where g is the acceleration due to gravity = 9.8 m/s²N = mg = 1147 kg x 9.8 m/s²= 11,242.6 N
The static friction force on the car tires is:
Ff = μs x N= μs x (1147 kg x 9.8 m/s²)= 11242.6 μs N
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-How did Carver's work impact the lives of farmers in
the South? Describe two ways.
George Washington Carver, an agricultural scientist, had a significant impact on the lives of farmers in the Southern United States. Here are two ways that his work influenced their lives:
Crop Diversification: Carver encouraged farmers to diversify their crops and move away from their dependence on cotton.
Soil Conservation: Carver was a strong advocate for soil conservation and introduced farming practices that helped to conserve soil. He recommended practices such as crop rotation, using cover crops, and adding organic matter to the soil to improve its quality.
Thus, this way, Carver's work impact the lives of farmers in the South.
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if the ground on a machine is live (hot) and causes an electrical shock, what does this likely mean?
If the ground on a machine is live (hot) and causes an electrical shock, this likely means that there is a fault in the electrical system, such as broken insulation or a short circuit.
A machine's electrical system is malfunctioning if the ground is live and generates an electrical shock. The machine's ground is meant to offer a secure route for electrical current to flow to earth in the event that there is an electrical system malfunction. An electrical conductor is said to be "live" if it is carrying an electrical current. A live ground indicates a hole in the electrical system's insulation that allows electrical current to pass to the ground, posing a serious safety risk. To reduce the risk of electrical shock or electrocution to anybody coming into touch with the equipment, immediate action should be made to shut it down and rectify the problem before future usage.
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What would be a good addition to your community to promote physical activities for people with disabilities?
More pedestrian lights at roadways
Buses equipped with spaces for wheelchairs
More disabled parking spaces at the coffee shops
Accessibility ramps for going into and out of the pool
Most individuals can live an active life through walking, including those with impairments who can move around through the use of assistance equipment. wheelchair-accessible bus vehicles
Why is accessibility crucial for those who are disabled?It is acceptable to claim that everyone in society, including those with disability, benefit from accessibility. Enhancing accessibility results in a higher quality of life, as well as more independence and social integration. Also, it promotes improved health and has a variety of cost-saving benefits.
What are a few wheelchair-accessible examples?While "wheelchair accessible" is a common way to characterise a facility or amenity that helps persons with disabilities, accessibility may also refer to Braille sign, wheelchair access, elevators, sounds at pedestrian crossings, pathway contours, web designing, and other things.
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write a statement (your hypothesis) about what you think will happen in the parallel circuit when you remove one resistor (led). support your answer with reasoning.
My hypothesis is that when one resistor (LED) is removed from a parallel circuit, the overall resistance of the circuit will decrease.
This is because parallel circuits have multiple paths for current to flow through, and removing one resistor (LED) reduces the number of paths and increases the current flow through the remaining resistors.
What happens when one resistor is removed from a parallel circuit?When you remove one resistor from a parallel circuit, the current through the other resistors will increase because there are fewer resistors for the current to flow through. This means that the overall resistance of the circuit decreases when you remove one resistor. This is because parallel circuits have multiple paths for current to flow through.
Removing one resistor reduces the number of paths and increases the current flow through the remaining resistors. A parallel circuit is a circuit in which the components are connected in such a way that the voltage is the same across each component.
In contrast, a series circuit is a circuit in which the components are connected in a series, so the same current flows through each component.
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at what height above the surface of the earth would a satellite be orbiting if it was travelling at 7200 m/s?
At 7200 m/s, a satellite would be orbiting at an altitude of approximately 28,800 km above the surface of the Earth.
A satellite is a celestial body that orbits around a planet. Satellites have various forms, including the natural moon or an artificial man-made object that orbits a planet, the Sun, or any other astronomical body.
Satellites are classified based on their usage, location, and orbit. Weather forecasting, GPS, communication, military intelligence, remote sensing, and scientific experiments are just a few of the applications in that satellites are utilized.
The formula to calculate the height of a satellite above the earth is as follows:
[tex]R = [ (G*M*T^2) / 4\pi^2 ] ^(\frac{1}{3} ) - R_E[/tex]
Where R = height of the satellite above the earth's surface.
G = universal gravitational constant, M = mass of the Earth, T = orbital period of satellite, [tex]R_E[/tex] = radius of the earth.
The radius of the earth is 6400 km. In meters, this would be 6,400,000 m.
Therefore, the orbital period of the satellite is,
[tex]T = (2*\pi *r) / v[/tex]
Where r = radius of the orbit, v = velocity of the satellite.
[tex]T = (2*\pi *R_E) / v[/tex]
[tex]T= (2*\pi *6,400,000) / 7200[/tex]
[tex]T= 2,206.43 \ s[/tex]
Now, calculate the height of the satellite:
[tex]R = [ (G*M*T^2) / 4\pi ^2 ] ^(\frac{1}{3} - R_E[/tex]
Substituting known values in the above equation
[tex]R= [ (6.67 * 10^(-11) * 5.97 * 10^(24) * (2,206.43)^2) / (4 * \pi ^2) ] ^(\frac{1}{3} ) - 6,400,000[/tex]
[tex]R = 28,800\ km[/tex]
Thus, the satellite would be orbiting at a height of 28,800 km above the surface of the earth if it was traveling at the speed of 7200 m/s.
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define wavelength and amplitude. when considering color vision, how does our visual system interpret wavelength? amplitude? provide examples to illustrate your answer.
When we consider color vision, the visual system interprets wavelength and amplitude. The definition of wavelength and amplitude is given below.
Wavelength is the distance between two points, measured in the direction of propagation, that correspond to the same phase of the wave. Its symbol is λ. The distance traveled by one full cycle of the wave is its wavelength.
The human eye has a visual spectrum of wavelengths ranging from 400 to 700 nanometers. Amplitude is the extent of displacement or change in the oscillatory motion of a wave, particularly of a sound wave, electromagnetic wave, or other wave. Its symbol is A. The amplitude of a wave is the height of the wave's crest, measured from its resting position to its highest point.Color vision and how it interprets wavelength and amplitude Our visual system perceives color by interpreting light waves of different wavelengths. When light waves enter our eyes, they are broken down into different wavelengths, which our eyes interpret as color. When our eyes see light of different wavelengths, they appear to be different colors. The shorter the wavelength, the bluer the light appears, and the longer the wavelength, the redder it appears.
As a result, if we consider color vision, our visual system interprets wavelength and amplitude. The human eye sees different colors by interpreting different wavelengths of light. For example, when we see a rainbow, we can see all of the colors, such as red, orange, yellow, green, blue, indigo, and violet. The rainbow has a wavelength spectrum ranging from 400 to 700 nanometers.A rainbow is a natural phenomenon that occurs when light is refracted by water droplets, producing a spectrum of colors. Another instance of color vision is a sunset. The sky appears red and orange during a sunset because the longer wavelengths of light are refracted more than the shorter ones. When light waves travel through the atmosphere and bounce off the Earth's surface, this occurs.
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A thin uniform rod of mass M and length L is bent at its center so that the two segments are now perpendicular to each other.A) Find its moment of inertia about an axis perpendicular to its plane and passing through the point where the two segments meet.B) Find its moment of inertia about an axis perpendicular to its plane and passing through the midpoint of the line connecting its two ends.
A thin uniform rod of mass M and length L is bent at its center so that the two segments are now perpendicular to each other.
A) To find the moment of inertia about an axis perpendicular to its plane and passing through the point where the two segments meet, we can use the parallel axis theorem. The moment of inertia of a thin rod of length L and mass M can be found to be:
I = mL^2 /12
Now, we need to add the distance between the axis of rotation and the centre of mass. The distance between the two points is L/2. Thus, the moment of inertia is:
I = mL^2/12 + mL^2/4 = mL^2/3
B) To find the moment of inertia about an axis perpendicular to its plane and passing through the midpoint of the line connecting its two ends, we can use the perpendicular axis theorem. The moment of inertia of the rod can be found to be:
I = mL^2/3
Since the distance between the axis of rotation and the Centre of mass is 0, the moment of inertia remains the same.
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a 2.00 kg mass is attached to a light cord that is wrapped around a pulley of radius 3.80 cm, which turns with negligible friction. the mass falls at a constant acceleration of 2.40 m/s2. find the moment of inertia of the pulley.
The moment of inertia of the pulley when a 2.00 kg mass is attached to a light cord that is wrapped around a pulley of radius 3.80 cm, which turns with negligible friction and the mass falls at a constant acceleration of 2.40 [tex]m/s^2[/tex] is 4.5472[tex]kgm^2[/tex].
The moment of inertia of a pulley can be calculated using the equation I = [tex]mr^2[/tex], where m is the mass of the pulley and r is its radius. In this example, the mass of the pulley is 2.00 kg and its radius is 3.80 cm. So, the moment of inertia is:
I = [tex](2.00 kg)(3.80 cm)^2[/tex]
= 4.5472 [tex]kgm^2[/tex]
To understand why this equation works, it helps to consider the concept of rotational inertia. Rotational inertia is the measure of an object's resistance to changes in its rotational velocity. When a mass is attached to a pulley and accelerates downwards, the pulley must resist the pull of the mass, resulting in an increased rotational velocity. The moment of inertia, then, is a measure of how well the pulley is able to resist changes in rotational velocity.
The equation for calculating the moment of inertia assumes that the mass of the pulley is evenly distributed around its circumference. When a pulley accelerates, it creates a centrifugal force, which increases with an increase in the pulley's rotational velocity. In other words, a pulley with a larger moment of inertia will be able to resist a greater centrifugal force.
In this example, the pulley accelerates downwards at a constant acceleration of [tex]2.40 m/s^2[/tex]. The equation for calculating the moment of inertia provides an accurate measurement of the pulley's rotational inertia in this situation, since it takes into account the mass and the radius of the pulley. By substituting the values for the mass and the radius into the equation, we can calculate the moment of inertia of the pulley to be [tex]4.5472 kgm^2[/tex].
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A student is investigating the effect of the size of the current flowing on the strength of an electromagnet
What are the Independant and dependant variables in her investigation?
What is a practical way she could measure the strength of the magnetic field produced by the electromagnet?
What instruments should she use to measure the size of the electric current?
What are the units of the electric current?
Who ever answers this I will give 45 points :)
Answer:
Independent Variable: The size of the current flowing through the wire.
Dependent Variable: The strength of the electromagnetic field produced by the wire.
A practical way to measure the strength of the magnetic field would be to use a compass to determine the direction of the magnetic field lines. As the strength of the magnetic field increases, the compass needle will deflect more from its original position.
To measure the size of the electric current, she could use an ammeter. An ammeter is a device that connects in series with the wire and measures electric current in amperes (A).
The units of electric current are amperes (A), named after André-Marie Ampère, a French physicist who is one of the founders of electrodynamics.
I hope this helps!
One of the most practical way to measure the strength of the magnetic field would be to use a compass to determine the direction of the magnetic field lines. As the strength of the magnetic field increases, the compass needle will deflect more from its original position.
What instruments should she use to measure the size of the electric current?In order to measure the size of the electric current, she could use an ammeter. An ammeter means a device that connects in series with the wire and measures electric current in amperes (A).
What are the units of the electric current?The units of electric current are amperes (A), named after André-Marie Ampère, a French physicist who is one of the founders of electrodynamics.
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What will this wave look like when it reflects across a free boundary?
The amplitude of the reflected wave is opposite to the amplitude of the original wave.
When a wave reflects across a free boundary, it undergoes a change in direction and amplitude. The reflected wave looks like the original wave, but it's inverted. It means that the reflected wave's crest becomes a trough, and the trough becomes a crest.What is a wave?A wave is a disturbance that travels through space and time, carrying energy without carrying matter along with it. The movement of energy through a body of water, such as the ocean, is a typical example of a wave.A free boundary refers to a boundary that is not restricted. An example of a free boundary is a reflecting surface. When waves reflect off of a free boundary, they bounce back in the opposite direction. The angle of reflection equals the angle of incidence.The wave looks similar to the original wave, but it is inverted or flipped. The crest of the original wave becomes the trough of the reflected wave, and the trough becomes the crest.
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a current of 6.09 a in a solenoid of length 14.8 cm creates a 0.203 t magnetic field at the center of the solenoid. how many turns does this solenoid contain?
The solenoid contains approximately 259 turns.
The magnetic field produced by a solenoid is directly proportional to the current passing through it and the number of turns in the solenoid. The formula for the magnetic field produced by a solenoid is given as B = μ₀nI, where B is the magnetic field, μ₀ is the permeability of free space, n is the number of turns per unit length, and I is the current passing through the solenoid.
We are given that the current passing through the solenoid is 6.09 A, the length of the solenoid is 14.8 cm, and the magnetic field produced at the center of the solenoid is 0.203 T. We can use these values to calculate the number of turns in the solenoid as follows:
B = μ₀nI
n = B/(μ₀I)
Substituting the given values, we get:
n = (0.203 T)/(4π×10⁻⁷ T·m/A × 6.09 A × 0.148 m)
n ≈ 259 turns
Therefore, the solenoid contains approximately 259 turns.
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1. How does the speed of coastal erosion compare to other types of erosion?
A fundamental frequency
The lowest frequency that a vibrating object or system can produce is referred to as a fundamental frequency. As the first harmonic frequency, it has another name.
How are fundamental frequencies determined?The vocal folds' fundamental frequency reflects their rate of vibration. It can be measured in cycles per second or hertz (Hz). Male conversational fundamental frequencies often vary from 100 to 150 Hz, while female fundamental frequencies typically range from 180 to 250 Hz.
Explain about the fundamental frequency?It is the frequency at which the object or system naturally tends to vibrate when set into motion. The fundamental frequency is also known as the first harmonic frequency, and it is the primary pitch of a sound wave. In musical instruments, the fundamental frequency determines the perceived pitch or note of the sound, while the overtones or harmonics (which are integer multiples of the fundamental frequency) contribute to the timbre or quality of the sound.
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Complete question;- What is a fundamental frequency?
need help asap pleasee
Answer:
Hello! Our answer is C: it shows negative acceleration :)
Explanation:
Small tip: Always draw a car when you are working with these type of questions. Now imagine: A car is moving in the positive way, goes smae speed for a bit, and slows down. Then it stops at 30 mins. Then it starts moving in the opposite direction. So, our answer is c :)
Good luck!
what would happen to shadows if you were to move the sun farther away from the earth and moon? and what would happen if you moved it closer?
If you were to move the sun farther away from the earth and moon, shadows would become sharper and more defined. This is because the light rays from the sun would be more parallel, resulting in less scattering and more direct illumination. The shadows would also be longer because the light source is farther away.
If you were to move the sun closer to the earth and moon, shadows would become less defined and more diffuse. This is because the light rays would be less parallel, resulting in more scattering and less direct illumination. The shadows would also be shorter because the light source is closer.
Answer:
If the sun were moved farther away from the Earth and Moon, the shadows would become sharper and darker because the Sun's light would be more direct and less scattered. This would result in more defined shadows with less ambient light to soften their edges.
On the other hand, if the Sun were moved closer to the Earth and Moon, the shadows would become less defined and lighter because the Sun's light would be less direct and more scattered. This would result in less defined shadows with more ambient light to soften their edges.
However, it's important to note that the position of the sun is not the only factor affecting shadows. Other factors include the size and shape of the object casting the shadow, the position of the observer, and the angle of incidence of the light source.
a 0.24 kg blob of clay is thrown at a wall with an initial horizontal velocity of 16 m/s if the clay comes to a stop in what is the average horizontal force on the clay due to the wall?
The average horizontal force on the clay due to the wall, given that the clay is thrown at the wall with an initial horizontal velocity of 16 m/s is 42 N
How do i determine the average horizontal force?To obtain the average horizontal force, we shall begin by calculating the deceleration of the blob of clay. Details below:
Initial velocity (u) = 16 m/sFinal velocity (v) = 0 m/sTime (t) = 91 ms = 91×10⁻³ sDeceleration of blob of clay (a) =?a = (v - u) / t
a = (0 - 16) / 91×10⁻³
a = -16 / 91×10⁻³
a = -175.8 m/s²
Finally, we shall determine the average horizontal force on the clay due to the wall. This is illustrated below:
Mass of blob of clay (m) = 0.24 KgDeceleration of blob of clay (a) = -175.8 m/s²Average horizontal force (F) =?Force = mass × deceleration
Average horizontal force = 0.24 × -175.8
Average horizontal force = -42 N
Note: The negative sign indicates that the force is in opposite direction to the motion of the clay.
Thus, the average horizontal force is 42 N
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complete question
A 0.24 kg blob of clay is thrown at a wall with an initial velocity of 16 m/s. If the clay comes to a stop in 91 ms, what is the average force experienced by the clay?
If it takes 726 watts of power to move a mass 36 meters in 14 seconds, then what is the magnitude of the object’s mass?
A. 12. 1 kg
B. 20. 2 kg
C. 28. 8 kg
D. 282 kg
Answer: mass=28.8kg
Power , p =726 watt
displacement, d =36m
time ,t =14s
g=9.8m/s^2
p= (work)/t
p=(mg*d)/t
726=(m*9.8*36)/14
m= 28.8kg
Explanation: when a force causes displacement of the body , work is said to be done on the body. Power is the rate of doing work. Hence here power was applied on a body of certain mass which caused the given displacement of the body in given time.
the b) part please...
Tyres have a tread pattern to improve traction and provide better handling on a variety of road surfaces, including wet and slippery conditions.
Why do tyres use a tread pattern ?The tread pattern on tyres is designed to provide a number of benefits for drivers. One of the main reasons for the tread pattern is to improve traction, particularly on wet or slippery surfaces.
The pattern provides channels or grooves that help to channel water away from the surface of the tyre, reducing the risk of hydroplaning and improving grip on wet roads. This can be particularly important in areas with frequent rainfall or snow. The tread pattern also helps to improve handling on a variety of road surfaces.
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the strongest region of a magnet can be found at ______.
Answer:
Africa
Explanation:
7. How much time would it take a bowling ball dropped from a helicopter to reach a speed of 55 m/sec?
How far will the ball have fallen in that time?
Answer:
Approximately [tex]5.61\; {\rm s}[/tex].
Approximately [tex]154\; {\rm m}[/tex].
(Assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex], air resistance on the ball is negligible, and that the helicopter was initially stationary.)
Explanation:
Under the assumptions, acceleration of the ball during the fall would be constantly [tex]a = g = 9.81\; {\rm m\cdot s^{-2}}[/tex].
Let [tex]u[/tex] denote the initial velocity of the ball; [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex] since it is assumed that the helicopter was initially stationary.Let [tex]v[/tex] denote the final velocity of the ball; [tex]v = 55\; {\rm m\cdot s^{-1}}[/tex].Apply the SUVAT equation [tex]t = (v - u) / a[/tex] to find the time it takes for the velocity of the ball to change from [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex] to [tex]v = 55\; {\rm m\cdot s^{-1}}[/tex]:
[tex]\begin{aligned}t &= \frac{v - u}{a} \\ &= \frac{55 - 0}{9.81}\; {\rm s} \\ &\approx 5.61\; {\rm s}\end{aligned}[/tex].
Apply the SUVAT equation [tex]x = (v^{2} - u^{2}) / (2\, a)[/tex] to find the displacement [tex]x[/tex] of the ball as its velocity change from [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex] to [tex]v = 55\; {\rm m\cdot s^{-1}}[/tex]:
[tex]\begin{aligned}x &= \frac{v^{2} - u^{2}}{2\, a} \\ &= \dfrac{55^{2} - 0^{2}}{2\, (9.81)}\; {\rm m} \\ &\approx 154\; {\rm m}\end{aligned}[/tex].
a formula that relatively accurately predicts the orbital distances of the first eight major bodies in the solar system and then somewhat predicts the next several is known as
The formula that relatively accurately predicts the orbital distances of the first eight major bodies in the solar system and then somewhat predicts the next several is known as the Titius-Bode law.
Titius-Bode law is a generalization, or rule of thumb, that appears to describe the orbital distances of the planets of the Solar System. The sequence is 0, 3, 6, 12, 24, 48, 96, and 192. The seventh number, 384, is used as a substitute for Jupiter's real mean distance from the Sun, which is 483.6 million miles.The distance from the Sun to the planets in our Solar System follows a regular pattern known as the Titius-Bode law, which predicts the distance of the planet to the Sun based on its position in the sequence.
The Titius-Bode law is named after two eighteenth-century German astronomers, Johann Daniel Titius and Johann Elert Bode. It was initially proposed in 1766 by Titius as an empirical hypothesis, with little explanation of why it should work, and was later refined by Bode in 1778 into a formula, which became known as Bode's law or the Titius-Bode law.
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if there were two telescopes with the same diameter, but one is a visible light telescope and the other a radio telescope, how would the resolution of the images from each telescope compare? the wavelength of visible light is several hundred nanometers (1 nanometer
The resolution of the images produced by the visible light telescope will be higher than that of the radio telescope, due to the difference in wavelength.
When there were two telescopes with the same diameter, but one is a visible light telescope and the other a radio telescope, the resolution of the images from each telescope would be different. The wavelength of visible light is several hundred nanometers (1 nanometer = 10−9 meters), while the wavelength of radio waves is much longer, typically on the order of meters or centimeters.
Hence, we can compare the resolution of visible light and radio telescopes. This means that the visible light telescope will be able to resolve more details, since it can detect smaller details due to its smaller wavelength.
Radio telescopes have a lower resolution compared to visible light telescopes because of their longer wavelength. The resolution of an optical telescope is limited by the size of its aperture. The smaller the aperture, the more diffracted the image. As the aperture size grows, the resolving power of the instrument improves.
The same is not true of radio telescopes because their wavelength is so much longer than visible light. The aperture size of a radio telescope would have to be several kilometers in diameter to achieve the same resolution as a visible light telescope of the same size. This is why radio telescopes are usually much larger than optical telescopes.
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when a falling merteoiud is at a distance above the earth's surface of 3 times the earth's radius what is it acelartion due to earths gravitation
At a distance above the Earth's surface of 3 times the Earth's radius, the acceleration due to Earth's gravity is approximately 1.23 m/s².
Distance above the Earth's surface of 3 times the Earth's radius, the distance from the center of the Earth is:
d = 4 * R
where R is the radius of the Earth.
The acceleration due to gravity at this distance can be calculated using the formula:
a = G * M / d²
where G is the gravitational constant,
M is the mass of the Earth, and
d is the distance from the center of the Earth.
Substituting the values, we get:
a = G * M / (4*R)²
where G = 6.67 × 10⁻¹¹ Nm²/kg² and M = 5.97 × 10²⁴ kg.
Substituting these values, we get:
a = 1.23 m/s²
Therefore, the acceleration due to Earth's gravity at a distance above the Earth's surface of 3 times the Earth's radius is approximately 1.23 m/s².
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The drawing shows a hot air balloon. The mass of the balloon is 3000kg. 34000N
What is the weight? What is the resultant force on the balloon?
Answer:
Weight =29400N
Resultant force = 4600N upwards
Explanation:
The weight of an object is calculated using the formula:
[tex]W = mg[/tex]
where W = weight (N), m = mass (kg) and g = gravitational field strength (N/kg).
Since the hot air balloon has a mass of 3000kg and the field strength of the Earth is 9.8N/kg, the weight of the balloon is:
[tex]3000kg\times 9.8N/kg = 29400N[/tex]
The second part of your question asks about the resultant force of the hot-air balloon. This can be calculated by subtracting the smaller magnitude of force from the larger magnitude. This means the resultant force is:
[tex]34000N-29400N = 4600N[/tex]
Therefore, the hot-air balloon has a resultant force of 4600N upwards.
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a person who weighs 550 n empties her lungs as much as possible and is then completely immersed in water (of density 1000 kg/m3) while suspended from a harness. her apparent weight is now 21.2 n. what is her density?
The density of the person is 480.24 kg/m³.
Given,
Mass of the person = m = 550 N
Apparent weight =[tex]F_ a_p_p_a_r_e_n_t[/tex] = 21.2 N
Density of water = р = 1000 kg/m³
We need to find the density of the person.
The formula for the apparent weight of an object when it is immersed in a liquid is given as:
[tex]F_ apparent[/tex][tex]= (m[/tex]р[tex]V)_g[/tex]...…(1)
Where m is the mass of the object, ρ is the density of the liquid, V is the volume of the object and g is the acceleration due to gravity.
Let V be the volume of the person. Then, the weight of the person in air = mg And, the weight of the person in water = [tex]F_ a_p_p_a_r_e_n_t[/tex] = 21.2 N
We know that, Weight of the person in air - Weight of the person in water = Buoyant force = Weight of water displaced by the person[tex]mg - F_ a_p_p_a_r_e_n_t[/tex]
550 - 21.2 = р[tex]V_g[/tex]
528.8 = р[tex]V_g[/tex].......(2)
Dividing both sides of equation (1) and (2), we get:
[tex]F_ a_p_p_a_r_e_n_t[/tex][tex]/m - mg/m[/tex] = [tex](m -[/tex] р[tex]V)_g/m[/tex] = р[tex]V_g/m[/tex]
[tex]F_ a_p_p_a_r_e_n_t[/tex][tex]/m - g =[/tex] р/[tex]V_g[/tex][tex]/m - g[/tex]
[tex]F_ a_p_p_a_r_e_n_t[/tex][tex]m - g =[/tex] р/[tex]V_g[/tex][tex]/m[/tex]
21.2/550 - 9.81 = рVg/550 - 9.81Vg/550 = (21.2/550 - 9.81)/(р).........(3)
We know that, Density = mass/volume => р= m/V => V = m/р
Substituting V in equation (3), we get:
Vg/550 = (21.2/550 - 9.81)/m/рg
V = m/р = (21.2/550 - 9.81)/(1000*9.81)≈ 0.0113 m³
Substituting the value of V in equation (2), we get:528.8 = р(0.0113) (9.81)р = 480.24 kg/m³
Therefore, the density of the person is 480.24 kg/m³.
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measurement of the speed of sound using the flash and report method
The flash and report method is a simple and common technique used to measure the speed of sound. In this method, an observer measures the time between seeing a flash, such as from a gunshot or a firecracker, and hearing the corresponding sound. The observer is usually at a known distance from the source of the flash and sound.
To perform the experiment, the observer stands at a fixed distance away from the source of the flash and sound. When the flash is seen, they start a stopwatch or use any other timing device. Once they hear the sound, they stop the timer and note the time difference between the flash and the sound. This time difference is the time it takes for the sound to travel from the source to the observer.
The speed of sound can then be calculated using the formula: speed of sound = distance / time taken. The distance between the observer and the source is divided by the time difference recorded to find the speed of sound in the medium (usually air).
It is essential to ensure that the distance between the source and the observer is accurate and that the observer's reaction time is considered when measuring the time difference. External factors such as temperature, humidity, and altitude also affect the speed of sound and should be taken into account.
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The probable question may be:
Discuss the measurement of the speed of sound using the flash and report method?
a talented musician can produce a number of overtones on this natural horn. what would be the frequency of the fourth overtone (5th harmonic) produce when the musician is playing a middle c fundamental?
The frequency of the fourth overtone produced when the musician is playing a middle C fundamental is 1280 Hz. Therefore, the correct option is D.
A natural horn (trumpet with no valves) is similar to a pipe open at both ends. A musician plans to create a fundamental frequency of 256 Hz (middle C) using the horn. A talented musician can produce a number of overtones on this natural horn.
To solve this question, you need to know that the frequency of the fundamental frequency in a pipe open at both ends is given by;
f = (n * v) / (2L)
where, f is the fundamental frequency, n is an integer, v is the speed of sound, and L is the length of the pipe.
Since the question has already given us the frequency, we can rearrange the above equation to obtain the length of the pipe. Therefore,
L = (n * v) / (2f).
Since we are dealing with the fourth overtone, we know that n = 5.
Therefore, the frequency of the fourth overtone is given by;
f4 = 5f = 5 * 256 Hz = 1280 Hz
Hence, the frequency of the fourth overtone produced when the musician is playing a middle C fundamental is 1280 Hz (option D).
Note: The question is incomplete. The complete question probably is: A natural horn (trumpet with no valves) is similar to a pipe open at both ends. A musician plans to create a fundamental frequency of 256 Hz (middle C) using the horn. A talented musician can produce a number of overtones on this natural horn. What would be the frequency of the fourth overtone produce when the musician is playing a middle C fundamental? A) 512 Hz B) 768 Hz C) 1024 Hz D) 1280 Hz E) 1536 Hz
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increasing the kilovoltage on the control panel, with all other exposure factors remaining the same, will result in a film that is: group of answer choices a. overexposed and darker b. underexposed and lighter c. normal exposure and diagnositc d. increasing the kvp does not affect the quality of the film
Increasing the kilovoltage on the control panel, with all other exposure factors remaining the same, will result in a film that is: "Underexposed and lighter." The correct option is b.
If we increase the kilovoltage on the control panel with all other exposure factors remaining the same, it will result in a film that is underexposed and lighter. The increase in kVp leads to the increase in the penetrating ability of the x-ray beam. It, therefore, increases the number of x-ray photons that reach the film and allows more of the scattered radiation to reach the film.
The underexposure leads to lightening of the image on the film. In addition to this, the increased kilovoltage reduces the contrast of the image. It is due to the fact that the overall density of the image is decreased due to underexposure.
In conclusion, an increase in kVp on the control panel leads to an increase in the number of x-ray photons that reach the film, thereby lightening the image on the film. Also, the image will be underexposed because an increased kilovoltage reduces the contrast of the image. Here, the correct option is b. underexposed and lighter.
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