A stick is resting on a concrete step with 1/7 of its total length hanging over the edge. A single ladybug lands on the end of the stick hanging over the edge, and the stick begins to tip. A moment later, a second, identical ladybug lands on the other end of the stick, which results in the stick coming momentarily to rest at theta = 67.3 degrees with respect to the horizontal, as shown in the figure. If the mass of each bug is 3.09


times the mass of the stick and the stick is 11.5 cm long, what is the magnitude of the angular acceleration of the stick at the instant shown? Use =9.81 m/s2.

Answer:

i hope this is what you are looking for

The total current supplied to the trailer when the taillights and running lights are on is the sum of the current drawn by the running lights and the current drawn by the taillights.

The current drawn by the running lights is:

I1 = 4 * 0.5 A = 2 A

The current drawn by the taillights is:

I2 = 2 * 1.2 A = 2.4 A

Therefore, the total current supplied to the trailer when the taillights and running lights are on is:

I = I1 + I2 = 2 A + 2.4 A = 4.4 A

Therefore, the current supplied to the trailer when the taillights and running lights are on is 4.4 A.

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Answer:

The first mechanical means for transmitting real-time stock market data from exchange floors to brokers and investors across the country.

Explanation:

boat is heading due east at speed v when passengers onboard

spot a dolphin swimming due north away from them, relative

to their moving boat (c) heading north of east at a speed greater than v

The motion of the dolphin relative to a stationary observer floating in the water depends on the velocity of the boat and the velocity of the dolphin relative to the water.

Since the boat is heading due east and the dolphin is swimming due north relative to the moving boat, the dolphin's velocity relative to the boat is due north. Let's call the magnitude of this velocity "d".

The boat's velocity relative to the water is also due east and has a magnitude of "v".

Using the Pythagorean theorem, the magnitude of the dolphin's velocity relative to the stationary observer is:

sqrt([tex]d^2 + v^2)[/tex]

The direction of the dolphin's velocity relative to the stationary observer can be found using trigonometry. The angle between the dolphin's velocity relative to the boat and the boat's velocity relative to the water is 90 degrees, so the tangent of the angle between the dolphin's velocity and the velocity of the boat is d/v.

If we draw a right triangle with sides d, v, and sqrt([tex]d^2 + v^2[/tex]), the angle between the dolphin's velocity and the velocity of the boat is the angle opposite the side d. Using trigonometry, we find that this angle is:

[tex]tan^-1(d/v)[/tex]

The direction of the dolphin's velocity relative to the stationary observer is then 90 degrees plus this angle, since the dolphin's velocity is heading north relative to the boat.

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The potential difference across the each bulb and the current entering each bulb.

Each bulb in a straightforward parallel circuit receives the entire battery power. This is explains why the parallel circuit's lights will shine stronger than the series circuit's. The parallel circuit also has the benefit of maintaining an electricity even if one loop is disconnected.

The same brightness is produced when two identical bulbs are linked in parallel as it is when they are connected in a series, which is why.

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Approximately 3.16 x 10¹² machines at a distance of 5 m are needed to exceed 115 dB at a distance of 5 m.

Decibel (dB) is a unit of measurement that is used to express the relative intensity of sound or the ratio of two power quantities. It is a logarithmic unit that compares the power level of a sound to a reference level.

The decibel scale is logarithmic because the human ear perceives changes in sound intensity logarithmically. Therefore, the use of the decibel scale allows us to express a wide range of sound intensities using a more manageable numerical range.

a) To calculate the volume in decibels, we can use the given formula:

L = 10 lg(I/I0)

First, let's calculate the intensity of the noise:

1 kW = 1000 W

0.01% of 1000 W = 0.01 x 1000 W = 10 W

Area of a sphere with a radius of 5 m = 4πr² = 4π(5 m)² = 314.16 m²

Therefore, the intensity of the noise at a distance of 5 m from the machine is:

I = 10 W / 314.16 m² = 0.0318 W/m²

Now we can use the formula to calculate the volume:

L = 10 lg(I/I0) = 10 lg(0.0318 W/m² / 10⁻¹⁶ W/cm²) = 105 dB

Therefore, the volume of the noise at a distance of 5 m from the machine is 105 dB.

b) To calculate the number of machines needed to exceed 115 dB, we can use the formula in reverse:

L = 10 lg(I/I0)

115 dB = 10 lg(I/I0)

11.5 = lg(I/I0)

I/I0 = 10¹¹°⁵

Now we can calculate the total intensity needed at a distance of 5 m from the machines:

I_total = 10¹¹°⁵ W/m²

For one machine, the intensity of the noise at a distance of 5 m is:

I_machine = 10 W / 314.16 m² = 0.0318 W/m²

So the number of machines needed is:

N = I_total / I_machine = 10¹¹°⁵/ 0.0318 = 3.16 x 10¹²

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a) The number of excess electrons on the sphere is 1.97 x 10^10 electrons.

b) There are 0.0000857 excess electrons per lead atom.

a) The elementary charge of a single electron is -1.6 x 10^-19 C. To find the number of excess electrons on the sphere, we can divide the total charge by the charge of a single electron:

-3.15 x 10^-9 C / (-1.6 x 10^-19 C/electron) = 1.97 x 10^10 electrons

b) To find the number of excess electrons per lead atom, we need to first find the number of lead atoms in the sphere. We can use the molar mass of lead and the mass of the sphere to find the number of moles of lead:

7.90 g / 207 g/mol = 0.0382 mol

Next, we can use Avogadro's number to find the number of lead atoms:

0.0382 mol x (6.02 x 10^23 atoms/mol) = 2.30 x 10^22 atoms

Finally, we can divide the number of excess electrons by the number of lead atoms:

1.97 x 10^10 electrons / 2.30 x 10^22 atoms ≈ 0.0000857 excess electrons per lead atom.

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The space station would complete one revolution in about 2.2 minutes.

It's exciting to consider the use of artificial gravity inside a spacecraft. Many believe it would be a smart way to maintain humans' health on lengthy missions, preventing bone and muscle loss over the roughly 18 months it would take to fly to and from Mars in weightlessness.

The period of rotation T can be calculated using the formula T = 2π/ω, where ω is the angular velocity. Since the artificial gravity is equal to 1g, we can use the formula g = ω²r, where r is the radius of the cylinder. When we solve for, we obtain = sqrt(g/r).

Substituting the given values, we get ω = sqrt(9.81 m/s² / (2135/2 m)) = 0.0477 rad/s.

Using the formula for T, we get T = 2π/ω = 131.9 seconds, or approximately 2.2 minutes.

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Answer:

People are familiar with F = M a in rectilinear motion

Γ = I α is the corresponding relation in rotational motion.

Also, Γ = R X F gives the direction of the torque

When the wheel is turned over the direction of R is reversed since if it was pointing to the right the lever arm on which the force was acting is now pointing to the left. The gravitational force is still pointing downward  so the direction of Γ has been reversed and the gravitational force is still in the downwards direction  and there is a reversal in the torque acting on the wheel.

One can also think of the wheel having bendable spokes. A force that would turn the wheel and bend the spokes in one direction would have the opposite effect when the wheel was turned over. (A force forcing the spokes backwards would still force the spokes backwards when the wheel is turned over but now the wheel is rotating in the opposite direction)

3,1 The value of the "change in velocity per second" for the putty ball is 256 m/s².

3.2 The putty ball's mass has no effect on its acceleration, but it does have an effect on its weight and momentum.

4 The experiment can be repeated several times to ensure the reliability of the results.

3.1 The "change in velocity per second" for the putty ball can be calculated using the formula:

change in velocity = (final velocity - initial velocity) / time

In this case, the putty ball A is released from rest, so its initial velocity is zero. Its final velocity can be calculated using the equation of motion:

distance = 0.5 x acceleration x time²

where distance is the height of the building, and time is the time it takes for the ball to fall to the ground. We are given that the distance is h and the time is 2 minutes or 120 seconds. Using these values, we can solve for the acceleration:

h = 0.5 × a × t²

a = 2h / t²

Substituting h = XZ = 2.0 m and t = 0.125 s:

a = 2 x 2.0 / (0.125)² = 256 m/s²

Now, calculate the change in velocity per second:

change in velocity = (final velocity - initial velocity) / time

= (acceleration x time) / time

= acceleration

= 256 m/s²

Therefore, the value of the "change in velocity per second" for the putty ball is 256 m/s².

3.2 The acceleration of putty ball B will be equal to the acceleration of putty ball A. This is because the acceleration of an object is determined only by the force acting on it and its mass, according to Newton's second law of motion (F = ma). In this case, both putty balls are subject to the same gravitational force and experience the same air resistance (which is negligible), so their acceleration will be the same. The mass of the putty ball does not affect its acceleration, but it does affect its weight and momentum.

4 To ensure the reliability of the results, the experiment can be repeated multiple times, and the results can be compared and analyzed for consistency. The experiment can also be performed under controlled conditions, such as in a vacuum, to eliminate the effects of air resistance. The equipment used in the experiment should be calibrated and properly maintained to ensure accurate measurements. The experimenter should also take care to minimize sources of error, such as parallax error when reading the height of the building, and record all measurements and observations accurately.

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The change in momentum of the ball is -1.215 kg m/s. This is known as the law of conservation of momentum, which states that the total momentum of an isolated system remains constant if no external forces act upon it.

What is Momentum?

Momentum is a physics concept that describes the quantity of motion an object has. It is defined as the product of an object's mass and velocity. The formula for momentum is p = mv, where p is momentum, m is mass, and v is velocity. Momentum is a vector quantity, meaning it has both magnitude and direction. In the absence of external forces, the total momentum of a system is conserved.

a. The initial momentum of the ball can be calculated using the formula:

p = mv

where p is the momentum, m is the mass, and v is the velocity.

p = (0.045 kg) (27 m/s) = 1.215 kg m/s

Therefore, the initial momentum of the ball is 1.215 kg m/s.

b. The final momentum of the ball can also be calculated using the formula:

p = mv

Assuming the ball comes to a stop after being hit, the final velocity will be 0 m/s. So we get:

p = (0.045 kg) (0 m/s) = 0

Therefore, the final momentum of the ball is 0 kg m/s.

c. The change in momentum of the ball can be calculated using the formula:

Δp = pf - pi

where Δp is the change in momentum, pf is the final momentum, and pi is the initial momentum.

Δp = 0 - 1.215 kg m/s = -1.215 kg m/s

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Answer:

Explanation:

The force of gravity acting on the block can be resolved into two components, one parallel to the incline and one perpendicular to the incline. The perpendicular component is balanced by the normal force of the incline, and the parallel component is opposed by the force of friction. The force of friction is given by:

F_friction = coefficient_of_friction * F_norm

where F_norm is the normal force of the incline. The normal force is equal in magnitude and opposite in direction to the perpendicular component of the force of gravity, which is:

F_perpendicular = m * g * cos(theta)

where m is the mass of the block, g is the acceleration due to gravity, and theta is the angle of inclination.

The parallel component of the force of gravity is:

F_parallel = m * g * sin(theta)

The net force acting on the block is:

F_net = F_parallel - F_friction

Using Newton's second law, F = m * a, we can solve for the acceleration of the block:

a = F_net / m

Substituting the expressions for F_parallel and F_friction, we get:

a = [m * g * sin(theta) - coefficient_of_friction * m * g * cos(theta)] / m

Simplifying, we get:

a = g * [sin(theta) - coefficient_of_friction * cos(theta)]

Substituting the given values, we get:

a = 9.8 m/s^2 * [sin(36°) - 0.55 * cos(36°)] = 6.43 m/s^2

Therefore, the acceleration of the block is 6.43 m/s^2.

Answer: The length of track required is 500 m.

Explanation: Determine the object's original velocity by dividing the time it took for the object to travel a given distance by the total distance. In the equation V = d/t, V is the velocity, d is the distance, and t is the time.

Brainliest? <33

Answer:

E = h ν     energy of wave of frequency ν

ν = c / λ      frequency of wave in terms of wavelength

E = h c / λ

Since λ = 6.4E-11 is the shortest wavelength this corresponds to the highest potential needed

E = 6.63E-34 * 3.00E8 / 6.4E-11 = 3.11E-15 joules

V = E / q = 3.11E-15 / 1.6E-19 = 19,400 volts

Note (E above is energy required and not the electric field)

Answer:

The magnitude of the total vertical force exerted by the ground on the rear wheels of the truck is 62271.86 N

Explanation:

To find the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck, we need to consider the static equilibrium condition of the truck.

The weight of the truck and its contents acts downwards through its center of gravity (cg) and the normal force exerted by the ground acts upwards. The normal force is distributed between the front and rear axles of the truck according to the position of the cg.

Let F_R be the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck.

Then, from the static equilibrium condition:

Sum of vertical forces = 0

F_R + (8010 kg)(9.81 m/s^2) - F_F = 0

where F_F is the magnitude of the total vertical force exerted by the ground on the front wheels of the truck.

The distance between the cg and the rear axle is given as 0.63(2.3 m) = 1.449 m.

The distance between the cg and the front axle is therefore (2.3 m - 1.449 m) = 0.851 m.

We can assume that the weight is evenly distributed between the four wheels of the truck. Therefore, the weight supported by each wheel is:

(8010 kg)(9.81 m/s^2)/4 = 19653.45 N

Using moments about the rear axle, we get:

F_F(0.851 m) - F_R(1.449 m) = 0

Solving these two equations simultaneously, we get:

F_R = 62271.86 N

Therefore, the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck is 62271.86 N.

The magnitude of the total vertical force exerted by the ground on the rear wheels of the truck is approximately 62,203 N.

Static equilibrium refers to the state of an object at rest when the net force acting on it is zero. In other words, when an object is in static equilibrium, it is not accelerating in any direction and all forces acting on it are balanced.

The principle of static equilibrium states that the sum of all forces acting on an object in static equilibrium is zero, and the sum of all torques (rotational forces) acting on the object is also zero. This principle can be applied to solve problems involving the forces and torques acting on objects at rest.

Static equilibrium is important in many areas of physics and engineering, including structural analysis, civil engineering, and mechanical engineering. Understanding static equilibrium is essential for designing structures and machines that can support loads without collapsing or breaking, and for analyzing the stability of systems in various applications.

Here in the Question,

To find the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck, we need to analyze the forces acting on the truck and apply the principle of static equilibrium, which states that the sum of all forces acting on an object in static equilibrium is zero.

The forces acting on the truck are the weight of the truck and its contents and the reaction forces from the ground acting on each of the four wheels. The weight of the truck and its contents can be represented as a single force acting vertically downwards at the center of gravity (cg) of the truck.

Since the truck is at rest on a horizontal road, the reaction forces from the ground acting on the wheels must balance the weight of the truck and its contents in both the horizontal and vertical directions. The horizontal components of the reaction forces cancel each other out, since the truck is at rest and not moving in the horizontal direction.

To find the vertical forces, we can first find the weight of the truck and its contents:

w = m*g

where w is weight, m is mass, and g is the acceleration due to gravity (9.81 m/s^2).

Substituting the given values, we get:

w = 8010 kg * 9.81 m/s^2 = 78,419.1 N

Next, we can find the position of the center of gravity (cg) relative to the front and rear axles of the truck:

d = L * (m1 - m2) / m

where d is the distance from the cg to the rear axle, L is the distance between the front and rear axles (2.3 m), m1 is the mass of the truck and contents behind the cg, m2 is the mass of the truck and contents in front of the cg, and m is the total mass of the truck and contents.

Substituting the given values, we get:

d = 2.3 m * (8010 kg * 0.63 - 8010 kg * 0.37) / 8010 kg = 0.743 m

Now, we can find the magnitudes of the vertical forces acting on the rear and front wheels of the truck using the principle of static equilibrium. Since the truck is not moving vertically, the sum of the vertical forces acting on it must be zero. Therefore:

Frear + Ffront = w

where Frear is the vertical force exerted by the ground on the rear wheels, Ffront is the vertical force exerted by the ground on the front wheels, and w is the weight of the truck and its contents.

The rear wheels support the weight of the truck and its contents, as well as a portion of the weight shifted forward of the rear axle due to the position of the cg. The front wheels support only a portion of the weight shifted backward of the front axle. To find the magnitudes of the vertical forces, we can use the following equations:

Frear = (m1/m)*w

Ffront = (m2/m)*w

where m1 is the mass of the truck and contents behind the cg, m2 is the mass of the truck and contents in front of the cg, and m is the total mass of the truck and contents.

Substituting the given values and using the value of d found earlier, we get:

Frear = (8010 kg * 0.63 / 8010 kg)*78,419.1 N = 62,202.7 N

Ffront = (8010 kg * 0.37 / 8010 kg)*78,419.1 N = 36,216.4 N

The magnitude of the total vertical force exerted by the ground on the rear wheels of the truck is:

Frear = 62,202.7 N ≈ 62,203 N

Therefore, the magnitude of the total vertical force exerted by the ground on the rear wheels of the truck is approximately 62,203 N.

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The skydiver is accelerating upward with an upward orientation with an acceleration of 0.556 m/s².

The pace at which a speed changes over time is called acceleration. In other words, it is a measurement of how quickly an object's velocity alters. It is a vector quantity with a direction and magnitude.

Finding the net force affecting the skydiver can be our first step. The vector sum of all forces acting on the skydiver is known as the net force. Weight and drag force are the two forces at play here as they affect the skydiver.

The skydiver's weight is determined by:

Weight= mass x acceleration due to gravity

Weight: 82.0 kg x 9.81 m/s² (acceleration due to gravity)

Weight= 804.42 N

The skydiver is under the following net force:

net force = weight - drag force

850 N - 804.42 N = Net force

45.58 N of net force (upwards)

The skydiver will accelerate upwards since the net force is upward. The magnitude of the acceleration can be determined by applying Newton's second law of motion:

Net force is calculated as follows:

Net force = mass x acceleration

45.58 N = 82.0 kg x acceleration

Acceleration = 0.556 m/s².

As a result, the skydiver is accelerating upward with an upward orientation with an acceleration of 0.556 m/s².

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As 500 kg of supplies are added to the truck, the gravitational force between the two vehicles rises from 1.27 106 N to 1.33 106 N.

As a result, when the space between the objects is cut in half, the gravitational force multiplies by four.

The Newton's Law of Universal Gravitation can be used to compute the gravitational force between the two vehicles: F = G * (m1 * m2) / d²

Plugging in the values given in the problem, we get:

F = 6.6743 × 10⁻¹¹ * ((3,650 kg) * (9,850 kg)) / (25.0 m)²

F = 1.27 × 10⁻⁶ N

As a result, there is 1.27 106 N of gravitational force between the two vehicles.

The separation between the two vehicles stays constant. Hence, after entering the updated values, we obtain:

F = 6.6743 × 10⁻¹¹ * ((3,650 kg) * (10,350 kg)) / (25.0 m)²

F = 1.33 × 10⁻⁶ N

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As an electron moves towards the positive plate in a uniform electric field between two parallel plates, the distance between the electron and the positive plate decreases, force causing the electric field between them to increase. Hence, the correct option is (2).

In the given diagram, there is a uniform electric field between two parallel plates, with the positive plate on the left and the negative plate on the right. When an electron is placed between the plates and moves towards the positive plate, it experiences a force due to the electric field. The direction of this force is opposite to the direction of the electric field and is given by F = qE, where F is the force, q is the charge of the electron, and E is the electric field. As the electron moves towards the positive plate, the distance between the electron and the positive plate decreases, which means that the electric field between them increases. Therefore, the force acting on the electron also increases according to F = qE. Hence, the correct option is (2) increases.

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The disk must have traveled a distance of 4.52 meters before coming to a stop.

We can use the equation for the distance traveled by an object under constant acceleration:

d = (v_f^2 - v_i^2) / (2 * a)

The acceleration of the disk is determined by the force of friction, which is given by:

F_friction = friction_coefficient * F_normal

We can find the weight of the disk by using the formula:

F_gravity = m * g

Let's assume the mass of the disk is 0.5 kg. Then:

F_gravity = 0.5 kg * 9.8 m/s^2 = 4.9 N

So the normal force on the disk is also 4.9 N.

Now we can find the force of friction:

F_friction = 0.34 * 4.9 N = 1.67 N

The acceleration of the disk is given by:

a = F_friction / m = 1.67 N / 0.5 kg = 3.34 m/s^2

Plugging this into the equation for distance, we get:

d = (0 - (5.6 m/s)^2) / (2 * (-3.34 m/s^2)) = 4.52 m

Therefore, the disk travels 4.52 meters before coming to a stop, which is less than the length of the court (14.3 m).

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A.The linear acceleration of block A is [tex]a = -3.42 m/s^2[/tex]

B.The linear acceleration of block B is [tex]a = 3.42 m/s^2[/tex]

C.The angular acceleration of the wheel c  is [tex]a= -31.09 rad/s^2[/tex]

D. The tension in the left side is T = -210.83 N

E.The tension in the right side is T = -58.75 N

A. The linear acceleration of block A can be calculated using the equation for the acceleration of an Atwood's machine:

[tex]a =\frac{ (m2 - m1)g}{ (m1 + m2)}[/tex]

Substituting the given values, the linear acceleration of block A is:

[tex]a =\frac{ (2.00 kg - 5.50 kg) 9.81 m/s^2 }{ (5.50 kg + 2.00 kg)}\\a = -3.42 m/s^2[/tex]

B. The linear acceleration of block B can be calculated using the same equation:

[tex]a =\frac{ (m2 - m1)g}{ (m1 + m2)}[/tex]

Substituting the given values, the linear acceleration of block B is:

[tex]a = \frac{(2.00 kg - 5.50 kg) 9.81 m/s^2 }{ (5.50 kg + 2.00 kg)}\\a = 3.42 m/s^2[/tex]

C. The angular acceleration of the wheel can be calculated using the equation:

[tex]a = \frac{a}{r}[/tex]

where α is the angular acceleration, a is the linear acceleration and r is the radius of the wheel.

Substituting the given values and the value for the linear acceleration of block A, the angular acceleration of the wheel is:

[tex]a = \frac{-3.42 m/s2 }{ 0.110 m}[/tex]

[tex]a= -31.09 rad/s^2[/tex]

D. The tension in the left side of the cord can be calculated using the equation:

T = m1a + m1rα

Substituting the given values, the tension in the left side of the cord is:

T = 5.50 kg (-3.42 m/s2) + 5.50 kg (0.110 m) (-31.09 rad/s2)

T = -210.83 N

E. The tension in the right side of the cord can be calculated using the equation:

T = m2a + m2rα

Substituting the given values, the tension in the right side of the cord is:

T = 2.00 kg (3.42 m/s2) + 2.00 kg (0.110 m) (-31.09 rad/s2)

T = -58.75 N

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Answer:

This is an isolated system

Explanation:

By the definition

"Isolated system is a type of system on which no external force acts on"

In the above diagram, the surroundings are not applying any force on the enclosed system

Hence it is an Isolated system (Option 1)

Hope you understand

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Answer:

A

Explanation:

The bacteria exists as organic matter

Answer:

a) is probably the answer

The minimum force required to move the book and paper system is 0.0098 times the mass of the book.

To determine the minimum force required to move the book and paper system, we need to consider the forces acting on the system. There are two forces acting on the paper: the force of friction and the applied force P. The force of friction is equal to the coefficient of friction times the normal force, which is the weight of the paper. The weight of the paper is 0.1Mg, where g is the acceleration due to gravity.

Ffriction = μN = μ(0.1Mg) = 0.01Mg

To move the paper, the applied force P must be greater than or equal to the force of friction. Therefore:

P ≥ Ffriction

P ≥ 0.01Mg

Substituting the weight of the paper, we get:

P ≥ 0.01M(9.8 m/s²)(0.1) = 0.0098M

Therefore, the minimum force required to move the book and paper system is 0.0098 times the mass of the book.

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Answer:

Weight of object = .98 N

Buoyant force equals weight of water displaced = .10 N

Weight of object - weight of water displaced = .98 - .10 = .88 N

Density = Weight of object / Weight of equivalent weight of water

ρ = .98 / .10 = 9.8         specific gravity of object

Since the density of water = 1 g / cm^3

the density of the object is 9.8 g / cm^3      (9800 kg/m^3)

Answer:

Magnetic shielding is the process of reducing the magnetic field in a given space by using a material that can redirect or absorb the magnetic field. Some materials are better magnetic shields than others because of their magnetic properties and their ability to interact with magnetic fields.

Materials that are highly permeable to magnetic fields, such as iron, nickel, and cobalt, are excellent magnetic shields. These materials have a high magnetic susceptibility, which means that they can easily become magnetized in the presence of a magnetic field. When a magnetic field is applied to these materials, the magnetic domains within the material align with the external field, creating a magnetic shield that redirects the field away from the protected space.

Other materials, such as copper and aluminum, are not as effective as magnetic shields because they have low magnetic permeability and low magnetic susceptibility. These materials do not easily become magnetized in the presence of a magnetic field, and therefore cannot redirect or absorb the field as effectively as highly permeable materials.

In summary, the effectiveness of a material as a magnetic shield depends on its magnetic properties, including its permeability and susceptibility. Materials that are highly permeable and susceptible to magnetic fields, such as iron, nickel, and cobalt, are better magnetic shields than materials with low permeability and susceptibility, such as copper and aluminum.

Answer:

Current is inversely related to resistance.

Explanation:

Based on the given information, we can conclude that the relationship between current and resistance is inverse. This is because the graph is a downward curve, indicating that as resistance increases, current decreases, and vice versa.

In other words, when resistance is high, the flow of current is low, and when resistance is low, the flow of current is high. This inverse relationship between current and resistance is known as Ohm's Law, which states that the current flowing through a conductor is directly proportional to the voltage and inversely proportional to the resistance of the conductor.

Therefore, the best answer choice that describes the relationship between the two variables is:

Current is inversely related to resistance.

Answer:

B. Current is inversely related to resistance.

Explanation:

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