A student has a 2.97 L
bottle that contains a mixture of O2
, N2
, and CO2
with a total pressure of 5.68 bar
at 298 K
. She knows that the mixture contains 0.225 mol N2
and that the partial pressure of CO2
is 0.309 bar
. Calculate the partial pressure of O2
.

Answers

Answer 1
To calculate the partial pressure of O2, we can use the ideal gas law equation:

PV = nRT

where:
P = pressure
V = volume = 2.97 L
n = number of moles
R = gas constant = 0.08314 L bar K^-1 mol^-1
T = temperature = 298 K

We can start by calculating the total number of moles of gas in the bottle:

n_total = PV/RT

n_total = (5.68 bar)(2.97 L)/(0.08314 L bar K^-1 mol^-1)(298 K)

n_total = 0.725 mol

We know that the mixture contains 0.225 mol N2, so we can calculate the number of moles of the other gases:

n_other = n_total - n_N2

n_other = 0.725 mol - 0.225 mol

n_other = 0.500 mol

We also know that the partial pressure of CO2 is 0.309 bar, so we can calculate the number of moles of CO2:

n_CO2 = P_CO2 V/RT

n_CO2 = (0.309 bar)(2.97 L)/(0.08314 L bar K^-1 mol^-1)(298 K)

n_CO2 = 0.0112 mol

Now we can use the mole fractions of O2 and N2 to calculate the partial pressure of O2:

X_O2 = n_O2/n_other

X_N2 = n_N2/n_other

We know that the mole fraction of N2 is 0.225/0.500 = 0.450, so:

X_N2 = 0.450

Therefore:

X_O2 = 1 - X_N2

X_O2 = 1 - 0.450

X_O2 = 0.550

Now we can use the ideal gas law to calculate the partial pressure of O2:

P_O2 = n_O2 RT/V

P_O2 = X_O2 n_other RT/V

P_O2 = (0.550)(0.500 mol)(0.08314 L bar K^-1 mol^-1)(298 K)/(2.97 L)

P_O2 = 0.876 bar

Therefore, the partial pressure of O2 in the mixture is 0.876 bar.

Related Questions

2. A slice of chocolate cake contains 560 Calories. a. Determine the number of calories found in the slice of cake. b. Determine the number of joules of energy for the slice of cake. c. Determine the number of kilojoules of energy for the slice of cake. 3. Determine the number of calories in 1.5 kilojoules of energy.
SHIW WORK​

Answers

b. To determine the number of joules of energy for the slice of cake, we need to convert the calories to joules using the conversion factor 1 calorie = 4.184 joules:

Number of joules = 560 calories * 4.184 joules/calorie = 2343.04 joules

Therefore, the slice of cake contains 2343.04 joules of energy.

c. To determine the number of kilojoules of energy for the slice of cake, we can divide the number of joules by 1000:

Number of kilojoules = 2343.04 joules / 1000 = 2.34304 kilojoules

Therefore, the slice of cake contains 2.34304 kilojoules of energy.

To determine the number of calories in 1.5 kilojoules of energy, we need to convert kilojoules to calories using the conversion factor 1 kilojoule = 1000 calories:

Number of calories = 1.5 kilojoules * 1000 calories/kilojoule = 1500 calories

Therefore, 1.5 kilojoules of energy contains 1500 calories.

Explanation:

Answer:

2. a. 560 Calories, b. 2343.04 J, c. 2.34304 kJ

3. 358.508604 Cal

Explanation:

2.

a. The number of calories found in the slice of chocolate cake is 56012.

b. To determine the number of joules of energy for the slice of cake, we can use the conversion factor that 1 calorie is equal to 4.184 joules3. Therefore, the number of joules in the slice of cake is:

560 Cal ⋅ 4.184 J/ 1 Cal = 2343.04J

c. To determine the number of kilojoules of energy for the slice of cake, we can use the conversion factor that 1 kilojoule is equal to 1000 joules4. Therefore, the number of kilojoules in the slice of cake is:

2343.04 J ⋅ 1 kJ/1000 J = 2.34304 kJ

3. To determine the number of calories in 1.5 kilojoules of energy, we can use the conversion factor that 1 kilojoule is equal to 239.005736 calories1. Therefore, the number of calories in 1.5 kilojoules of energy is:

1.5 kJ ⋅ 239.005736 Cal / 1 kJ = 358.508604 Cal

what is the volume and letters of a solution that contains 0.50 moles of NaOH dissolved in enough distilled water to make 3.0 mm of NaOH solution​
what is the molarity of a solution that contains 60.0 G of caoh dissolved in 150 mm solution​​

Answers

1. To find the volume and units of a solution that contains 0.50 moles of NaOH dissolved in enough distilled water to make 3.0 M NaOH solution:

We first need to use the formula:

moles = concentration (in moles/L) x volume (in L)

Rearranging the formula to solve for volume, we get:

volume = moles / concentration

Substituting the given values, we get:

volume = 0.50 moles / 3.0 M = 0.17 L

Since the volume is given in liters, the units of the solution are L. Therefore, the solution contains 0.50 moles of NaOH dissolved in 0.17 L of distilled water, which makes a 3.0 M NaOH solution.

2. To find the molarity of a solution that contains 60.0 g of Ca(OH)2 dissolved in 150 mL of solution:

We first need to convert the mass of Ca(OH)2 to moles using the molar mass:

molar mass of Ca(OH)2 = 40.08 g/mol + 2 x 16.00 g/mol + 2 x 1.01 g/mol = 74.10 g/mol

moles of Ca(OH)2 = 60.0 g / 74.10 g/mol = 0.810 moles

Next, we need to convert the volume of the solution from milliliters to liters:

volume of solution = 150 mL / 1000 mL/L = 0.150 L

Finally, we can use the formula:

molarity = moles / volume

Substituting the given values, we get:

molarity = 0.810 moles / 0.150 L = 5.4 M

Therefore, the molarity of the solution is 5.4 M.

All redox reactions form ionic bonds. True or False

Answers

Answer:

true

Explanation:

True your welcome byee

A silver block, initially at 55.1∘C
, is submerged into 100.0 g
of water at 25.0∘C
in an insulated container. The final temperature of the mixture upon reaching thermal equilibrium is 27.9∘C
. The specific heat capacities for water and silver are Cs,water=4.18J/(g⋅∘C)
and Cs,silver=0.235J/(g⋅∘C)
.

Answers

The mass of the silver block, given that it was initially at 55.1 °C  and is submerged into 100.0 g of water at 25.0°C is 189.8 g

How do i determine the mass of the silver?

We'll begin our calculation by obtaining the heat absorbed by the water. Details below:

Mass of water (M) = 100 gInitial temperature (T₁) = 25 °CFinal temperature (T₂) = 27.9 °CChange in temperature (ΔT) = 27.9 - 25 = 2.9 °CSpecific heat capacity of water (C) = 4.184 J/gºC Heat absorbed by water (Q) =?

Q = MCΔT

Q = 100 × 4.184 × 2.9

Q = 1213.36 J

Finally, we shall determine the mass of the silver block. Details below:

Heat absorbed by water (Q) = 6108.64 JHeat released by silver block (Q) = -1213.36 JInitial temperature of silver block (T₁) = 55.1 °CFinal temperature of silver block  (T₂) = 27.9 °CChange in temperature (ΔT) = 27.9 - 55.1 = -27.2 °C Specific heat capacity of silver (C) = 0.235 J/gºC Mass of silver block (M) =?

Q = MCΔT

-1213.36 = M × 0.235 × -27.2

-1213.36 = M × -6.392

Divide both sides by -6.392

M = -1213.36 / -6.392

M = 189.8 g

Thus, we can conclude that the mass of the silver block is 189.8 g

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Complete question:

A silver block, initially at 55.1∘C, is submerged into 100.0 g of water at 25.0∘C in an insulated container. The final temperature of the mixture upon reaching thermal equilibrium is 27.9∘C. The specific heat capacities for water and silver are Cs,water = 4.18J/(g⋅∘C) and Cs, silver = 0.235J/(g⋅∘C). What is the mass of the silver block?

100 grams of 4 degree celsius water is heated until its temperature is 37 degrees celsius. If the specific heat of water is 4.18 J/g degrees celsius, calculate the amount of heat energy needed to cause this rise in temperature.

Answers

To calculate the amount of heat energy needed to cause the rise in temperature, you can use the formula:
Q = mcΔT

Where Q represents the heat energy, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.
Given:
m = 100 grams
c = 4.18 J/g°C
Initial temperature (T1) = 4°C
Final temperature (T2) = 37°C
First, find the change in temperature (ΔT):
ΔT = T2 - T1 = 37°C - 4°C = 33°C
Now, plug the values into the formula:
Q = (100 g) × (4.18 J/g°C) × (33°C)
Q = 13794 J

So, the amount of heat energy needed to cause this rise in temperature is 13,794 Joules.

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what is the most basic level of organization that can perform functions like converting food into energy

Answers

Answer: Cells

Explanation:

Dimensional analysis with shapes

Answers

The surface area of the rectangular prism is 0.034 square meters.

For a rectangular prism with length l, width w, and height h, the surface area is:

Surface area = 2lw + 2lh + 2wh

Substituting the given values, we get:

Surface area = 2(10 cm x 5 cm) + 2(10 cm x 8 cm) + 2(5 cm x 8 cm)

Surface area = 100 cm² + 160 cm² + 80 cm² = 340 cm²

We can use dimensional analysis. So the conversion factor is:

1 m² / 10,000 cm²

Multiplying the surface area by this conversion factor, we get:

Surface area = 340 cm² x (1 m² / 10,000 cm²)

Surface area = 0.034 m²

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--The complete Question is, What is the surface area of a rectangular prism that has a length of 10 cm, a width of 5 cm, and a height of 8 cm? Use dimensional analysis to convert the answer to square meters--

The reactant concentration in a zero-order reaction was 6.00×10−2 M
after 175 s
and 3.50×10−2 M
after 315 s
. What is the rate constant for this reaction?

Answers

In a zero-order reaction, the rate of the reaction is independent of the concentration of the reactant. Therefore, the rate of the reaction is constant over time. We can use the following equation to determine the rate constant (k) for a zero-order reaction:

Rate = k

The units of k for a zero-order reaction are M/s.

To determine the rate constant for this reaction, we can use the two given concentrations and times:

Rate = (6.00×10^-2 M - 3.50×10^-2 M) / (315 s - 175 s)
Rate = 2.5×10^-3 M/s

Since the rate of a zero-order reaction is constant, we can set the rate equal to the rate constant:

k = Rate = 2.5×10^-3 M/s

Therefore, the rate constant for this zero-order reaction is 2.5×10^-3 M/s.

A solution that is neutral has a pH of:
0
14
10
1
7

Answers

7 is the correct answer

Classify each into the concepts of HEAT and TEMPERATURE ​

Answers

Answer:

Heat HeatHeatTemperatureTemperatureHeat

A 10 g piece of metal at 50°C absorbs 900 G of energy after which the temperature of the metal is 350°C what is the specific heat of the metal

Answers

A 10 g piece of metal at 50°C absorbs 900 G of energy after which the temperature of the metal is 350°C. 0.35J/g°C is the specific heat of the metal.

The amount of heat needed to raise a substance's temperature by one degree Celsius in one gramme, also known as specific heat. Typically, calories and joules per gramme per degree Celsius are used as the measurement units of specific heat.

For instance, water has a specific heat of 1 calorie per gramme per degree Celsius. The notion of specific heat was developed by the Scottish scientist Joseph Black in the 18th century as a result of his discovery that equal masses of different substances required varying quantities.

q = m×c×ΔT

900= 10×c×( 350-50)

c=0.35J/g°C

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Which of the following is the most basic level of organization that can perform functions like converting food into energy?

Answers

The most basic level of organization that can perform functions like converting food into energy is the cell.

The most basic level of organization that can perform functions like converting food into energy is the cell. Cells are the fundamental units of life and are capable of various functions, including metabolism, which involves converting food into energy through processes such as cellular respiration.

Cells can be found in all living organisms, from single-celled bacteria to complex multicellular organisms like plants and animals. Within a cell, various organelles such as mitochondria, which are responsible for energy production, carry out specialized functions to support the overall cellular function. Therefore, the cell is the smallest and most basic level of organization that is capable of performing functions like converting food into energy.

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What is the pH of the solution formed when 12.50 mL of 1.05 M KOH is added to 50.0 mL of 0.225 M HBr?

A. 0.65
B. 1.52
C. 12.48
D. 13.35

Answers

Answer: D

Explanation:

When 12.50 mL of 1.05 M KOH is added to 50.0 mL of 0.225 M HBr, the resulting solution has a pH of 13.35.

Here’s how to calculate it:

First, we need to determine the number of moles of KOH and HBr in the solution:

moles of KOH = (12.50 mL) * (1.05 mol/L) * (1 L/1000 mL) = 0.013125 mol moles of HBr = (50.0 mL) * (0.225 mol/L) * (1 L/1000 mL) = 0.01125 mol

KOH is a strong base and HBr is a strong acid, so they will react completely to form water and a salt (KBr):

KOH + HBr -> KBr + H2O

The number of moles of KOH is greater than the number of moles of HBr, so there will be an excess of KOH in the solution after the reaction is complete:

moles of excess KOH = moles of KOH - moles of HBr = 0.013125 mol - 0.01125 mol = 0.001875 mol

The total volume of the solution is the sum of the volumes of KOH and HBr:

total volume = 12.50 mL + 50.0 mL = 62.5 mL

The concentration of excess OH- ions in the solution is:

[OH-] = moles of excess KOH / total volume = 0.001875 mol / (62.5 mL * (1 L/1000 mL)) = 0.03 M

The pOH of the solution can be calculated using the formula pOH = -log[OH-]:

pOH = -log(0.03) = 1.52

The pH can be calculated using the formula pH + pOH = 14:

pH = 14 - pOH = 14 - 1.52 = 13.35

So the correct answer is D. 13.35.

The density of a test gas is to be determined experimentally at 289.2 K using an apparatus constructed of a 4.050 L glass bulb volume that is attached to a vacuum pump. The mass of the evacuated bulb is 22.513 g. After it is filled with the test gas to a pressure of 0.0250 atm, the mass increases to 22.651 g. Assume the gas behaves ideally.
What is the density of the gas? How many moles of gas are in the bulb? What is the apparent molar mass of the gas?

Answers

The density of the gas is  0.0340 g/L, moles of gas in the bulb is 0.00124 mol and apparent molar mass is 111.3 g/mol.

How to calculate density, moles and molar mass?

To determine the density of the gas, use the ideal gas law:

PV = nRT

where P = pressure, V = volume, n = number of moles, R = gas constant, and T = temperature.

Since the volume and temperature are constant:

(P/n) = constant

Therefore, the density (ρ) of the gas is given by:

ρ = (m-m₀)/V = (Δm)/V

where m = mass of the bulb filled with the gas, m₀ = mass of the evacuated bulb, and Δm = m - m₀ is the mass of the gas.

Substituting the given values:

Δm = 22.651 g - 22.513 g = 0.138 g

V = 4.050 L

ρ = 0.138 g / 4.050 L = 0.0340 g/L

To find the number of moles of gas in the bulb, use the equation:

n = PV/RT

Substituting the given values:

n = (0.0250 atm)(4.050 L) / (0.0821 L·atm/mol·K)(289.2 K) = 0.00124 mol

Finally, to find the apparent molar mass of the gas, use the equation:

M = m/n

where M = molar mass of the gas and m = mass of the gas.

Substituting the given values:

M = 0.138 g / 0.00124 mol = 111.3 g/mol

Therefore, the density of the gas is 0.0340 g/L, there are 0.00124 mol of gas in the bulb, and the apparent molar mass of the gas is 111.3 g/mol.

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When calcium metal is placed in water, hydrogen gas is produced. Determine the mass of H2 produced at 25 C and 0.967 atm when 525 mL of the gas is collected over water. Consider vapour pressure of water be 0.0313 atm.

Answers

The mass of hydrogen gas produced, given that 525 mL of the gas was collected over water is 0.04 grams

How do i determine the mass of hydrogen gas produced?

First, we shall determine the mole of the dry hydrogen gas collected. Details below:

Vapour pressure = 0.0313 atmPressure of wet gas = 0.967 atmPressure of dry gas (P) = 0.967 - 0.0313 = 0.9357 atmTemperature (T) = 25 °C = 25 + 273 = 298 KVolume of gas (V) = 525 mL = 525 / 1000 = 0.525 LGas constant (R) = 0.0821 atm.L/mol KNumber of mole (n) =?

PV = nRT

0.9357 × 0.525 = n × 0.0821 × 298

Divide both sides by (0.0821 × 298)

n = (0.9357 × 0.525) / (0.0821 × 298)

n = 0.02 mole

Finally, we shall determine the mass of the hydrogen gas produced. Details below:

Molar mass of hydrogen gas, H₂ = 2 g/mol Mole of hydrogen gas, H₂ = 0.02 moleMass of hydrogen gas, H₂ = ?

Mole = mass / molar mass

0.02 = Mass of H₂ / 2

Cross multiply

Mass of H₂ = 0.02 × 2

Mass of hydrogen gas, H₂ = 0.04 grams

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Chemistry Table balance A+B→C
Table 1 attached

Answers

The reaction A + B → C has the following rate expression is 197.62 [A][B] M/s

How to determine rate expression?

Using the experimental data to determine the order of the reaction with respect to A and B, assume that the rate of the reaction is given by:

rate = [tex]k[A]^x[B]^y[/tex]

where k =  rate constant and

x and y = orders of the reaction with respect to A and B, respectively.

Compare the rates of the reaction in trials 1 and 2 while keeping the concentration of A constant:

rate1/rate2 = [tex]\frac{k[A]^x[B]^y}{k[A]^x[B]^y} = \frac{[B]^y}{[B]^y} = 1[/tex]

Conclude that the reaction is first-order with respect to B.

Similarly, compare the rates of the reaction in trials 1 and 3 while keeping the concentration of B constant:

rate1/rate3 =[tex]\frac{k[A]^x[B]^y}{k[A]^x[B]^y} = \frac{[A]^x}{[A]^x} = 1[/tex]

Therefore, the reaction is first-order with respect to A.

The rate expression for the reaction A + B → C is:

rate = k[A][B]

Using any of the experimental trials to determine the value of the rate constant k, use trial 1:

rate1 =[tex]k[A]^1[B]^1[/tex]

k = [tex]\frac{rate1}{[A]^1[B]^1}[/tex] = (3.30 E-3)/(0.012 M x 0.014 M) = 197.62 M⁻² s⁻¹

Therefore, the rate expression for the reaction A + B → C is:

rate = 197.62 [A][B] M/s

In this case, the units of k are M⁻¹ s⁻¹ because the reaction is first-order with respect to both A and B.

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Compared to chemical reactions, most nuclear reactions result in the
OA. formation of new compounds
OB. formation of new elements
O C. formation of new bonds
OD. loss of valence electrons

Answers

Answer:

OB. formation of new elements.

Nuclear reactions involve changes in the nucleus of an atom, such as the splitting of a nucleus or the combining of two nuclei. These reactions can result in the formation of new elements, as the number of protons in the nucleus determines the element. In contrast, chemical reactions involve the rearrangement of electrons between atoms to form new compounds, but do not involve changes to the nucleus.

What volume will 5.00 mol of an ideal gas occupy at 25 C and 153 kPa of pressure?

Answers

79.8L is the volume for 5.00 mol of an ideal gas occupy at 25 C and 153 kPa of pressure.

A measurement of three-dimensional space is volume. It is frequently expressed quantitatively using SI-derived units, like the cubic metre or litre, or different imperial or US-standard units, including the gallon, quart and cubic inch. Volume and length (cubed) have a symbiotic relationship. A container's capacity is typically thought of as being represented by its volume.

P×V = n×R×T    

153000×V = 5×0.082×298

V= 79.8L

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Thoroughly explain fusion and fission, using a specific example, including a model of what is happening

The element i (Si-32)

Answers

Fusion and fission are two types of nuclear reactions that involve changes in the atomic nucleus of an atom.

Fusion is the process of combining two light atomic nuclei to form a heavier nucleus. This process releases a large amount of energy in the form of heat and light. Fusion occurs under high temperatures and pressures, similar to those found in the core of a star. A specific example of fusion is the fusion of two hydrogen nuclei to form helium, which is the process that powers the sun. In this reaction, the two hydrogen nuclei (protons) combine to form a helium nucleus, which consists of two protons and two neutrons. This process releases a large amount of energy in the form of gamma rays and other high-energy particles.

Fission, on the other hand, is the process of splitting a heavy atomic nucleus into two or more smaller nuclei. This process also releases a large amount of energy in the form of heat and radiation. Fission is used in nuclear power plants to generate electricity. A specific example of fission is the splitting of a uranium-235 nucleus into two smaller nuclei, such as krypton-92 and barium-141, and several neutrons. This reaction also releases a large amount of energy in the form of gamma rays and other high-energy particles.

In the case of the element Si-32, fusion and fission reactions can occur. For example, Si-32 can undergo fusion with hydrogen to form a heavier element, such as sulfur or argon. On the other hand, Si-32 can also undergo fission, where it can split into smaller nuclei, such as magnesium and calcium. The specific details of these reactions, including the amount of energy released and the products formed, depend on the specific conditions and the reactants involved.

Please help anyone !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

The volume of ammonia needed to react completely with 30 Liters of NO at STP is 45 L.

What is the volume of ammonia required in the reaction?

The volume of ammonia needed to react completely with 30 Liters of NO at STP is calculated as follows;

4NH₃  + 6NO    →   5N₂   +  6H₂O

From the reaction given above, we can see that;

4 moles of ammonia ------------> 6 moles of NO

ratio = 4 : 6

The volume of ammonia required is calculated as;

4 -------------- > 6

30 L -----------> ?

? = (30 L x 6 ) / 4

? = 45 L

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5. A sample of unknown metal has a mass of 135 grams. As the sample cools from 100.5 °C to 35.5 °C, it releases 7500 joules of energy. What is the specific heat of the sample?
please show work ​

Answers

The sample of the unknown metal has the mass of the 135 grams. The sample cools from the 100.5 °C to the 35.5 °C, and it releases the 7500 joules of the energy. The specific heat of the sample is 0.854 J/g °C.

Th mass of the metal = 135 g

The initial temperature = 100.5 °C

The final temperature = 35.5 °C

The heat energy releases = - 7500 J

The heat energy is expressed as :

Q = mc ΔT

Where,

The m is mass of the metal = 135 g

The c is the specific heat capacity = ?

The Q is heat energy releases = - 7500 J

The ΔT is the change in the temperature = final temperature - initial temperature.

The ΔT is the change in the temperature = 35.5 - 100.5

The ΔT is the change in the temperature =  - 65 °C

The specific heat capacity, c = Q / m ΔT

The specific heat capacity, c = - 7500 / 135 × - 65

The specific heat capacity, c = 0.854 J/g °C

The specific heat capacity of metal is 0.854 J/g °C.

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Which of these would be the least dense?Marble
Feather
Coin
Phone

Answers

The feather is the least thick of the bunch. This is due to the fact that density is defined as mass per unit volume.

A feather has a relatively low mass compared to its volume, due to its porous and lightweight nature. Marble, coin, and phone all have substantially higher densities than a feather since they are constructed of denser materials such as stone, metal, and plastic/electronics.

As a result, when the density of these things is compared, the feather is the least dense.

Because it has a significantly smaller mass than the other objects listed, the feather would be the least dense. Because density is defined as mass per unit volume, an object with a lower mass and the same or greater volume has a lower density.

The stone, coin, and phone all have greater masses and thus higher densities than the feather. However, because density varies based on the exact material used, the relative densities of these things may change if they are made of different materials.

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Which of the following statements confirms the law of conservation of energy?

Answers

Statement that shows that the total energy of a system remains constant and is conserved would confirm the law of conservation of energy.

What is law of conservation?

The law of conservation of energy states that energy cannot be created or destroyed, only transformed from one form to another. Therefore, any statement that shows that the total energy of a system remains constant and is conserved would confirm the law of conservation of energy.

Here are some examples of statements that confirm the law of conservation of energy:

The total energy of a closed system, such as a roller coaster, remains constant as the coaster moves from one point to another. Even though the potential energy of the coaster decreases as it goes downhill and the kinetic energy increases, the total energy of the coaster (potential plus kinetic) remains constant.

When a pendulum swings back and forth, the potential energy is converted into kinetic energy and back again, but the total energy of the pendulum remains constant.

In a chemical reaction, the total energy of the reactants is equal to the total energy of the products. Although energy can be released or absorbed during the reaction, the total energy of the system is conserved.

When a ball is thrown into the air, it gains potential energy as it rises and loses potential energy as it falls back down. However, the total energy of the ball (potential plus kinetic) remains constant, neglecting air resistance.

All of these statements confirm the law of conservation of energy by showing that the total energy of a system is conserved over time.

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Complete question is: "The total energy of a system remains constant and is conserved" statement would confirm the law of conservation of energy.

How many moles are in 28g of CO2?

Answers

Answer:

0.636 moles of CO2

Explanation:

The molar mass of CO2 is 44.01 g/mol (12.01 g/mol for one carbon atom and 2 x 16.00 g/mol for two oxygen atoms). To find the number of moles in 28g of CO2, you can divide the mass by the molar mass: 28g / 44.01 g/mol = 0.636 moles of CO2.

VITAMIN C IN FRUIT JUICE

Why might it be difficult to use this method to determine the amount of Vitamin C in other fruit juices such as cranberry, blackcurrant, or pomegranate juice?

Answers

The method for determining the sum of Vitamin C in fruit juice ordinarily includes adding an indicator (such as DCPIP) to the juice test and titrating the test with a standard arrangement of ascorbic corrosive until the marker changes colour.

In any case, there are a few variables that seem to make this strategy troublesome to utilize for other natural product juices such as cranberry, blackcurrant, or pomegranate juice:

Interference with the indicator: A few natural product juices may contain compounds that are meddled with the marker and anticipate it from changing colour indeed when all the Vitamin C has been titrated. This may lead to wrong comes about.Presence of other reducing agents: Natural product juices may contain other diminishing operators other than Vitamin C, such as fructose or glucose, which can moreover respond with the marker and create wrong positive comes about.Differences in Vitamin C substance: Diverse natural products contain distinctive sums of Vitamin C, and the sum of Vitamin C in a specific juice can change depending on variables such as the readiness of the fruit and the handling strategy utilized. This will make it troublesome to compare the Vitamin C substance of diverse natural product juices utilizing the same strategy.Differences in pH: The pH of natural product juices can moreover change, and this could influence the solidness of Vitamin C and the precision of the titration strategy. 

In this manner, whereas the strategy for deciding the sum of Vitamin C in natural product juice can be a valuable apparatus, it may not be appropriate for all sorts of natural product juices and may have to be be adjusted or adjusted to account for these variables. 

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Chemical equation for the formation of carbonic acid from the reaction of water with carbon dioxide

Answers

Answer: H2O + CO2 --> H2CO3

Explanation:

Water and Carbon Dioxide react to form Carbonic Acid

H2O + CO2 --> H2CO3

Lab: Limiting Reactant and Percent Yield
Step 7: Determine the Limiting Reactant (Trial 2)
Analysis: aluminum
there is no aluminum left
yes
Convert Mass:
2.50g=.019
.25g=.0093
The limiting reactants is/are aluminum.
Are these answers correct?
Yes they are I did the lab.

Answers

The given answer statement  "there is no aluminum left" and " limiting reactants is aluminum" are correct.

In the analysis of Trial 2, it was found that there was no aluminum left after the reaction had taken place. This indicates that all of the aluminum had reacted with the copper (II) chloride and that it was the limiting reactant in the reaction.

To confirm this, the mass of each reactant was converted to moles using their respective molar masses. It was found that the aluminum had a smaller number of moles than the copper (II) chloride, indicating that it would be used up first and thus be the limiting reactant.

Therefore, the limiting reactant in Trial 2 was aluminum.

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The nuclear reaction entails the breakdown of an element and the subsequent release of radioactive particles. This process can occur naturally or be produced purposefully. As a result, the reaction equation is balanced. The radon element is transmuted into polonium and an alpha particle in the provided question. Since an alpha particle was emitted, the equation is balanced.

Answers

The alpha decay of radon is shown by;

222/86Rn ----> 218/84Po + 4/2He

What is the alpha decay of radon?

Radon undergoes alpha decay by emitting an alpha particle, which consists of two protons and two neutrons.

Let us note that when there is an alpha decay, the parent nucleus would loose a helium nucleus and the daughter nucleus would less than than the parent in mass by four units and less than the parent in charge by 2 units and this would satisfy the mass and charge balance of the equation. The decay equation is; 222/86Rn ----> 218/84Po + 4/2He

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Missing parts;

Use the equation to complete the activity.

219 86Rn → 215 84Po + a

The nuclear equation shows the transmutation of a form of radon into polonium and an alpha particle. In one to two sentences, explain whether or not the reaction is balanced.

d. Given this law, 4 of 4.
Select Choice
of hydrogen (H2) is produced in the following reaction.

Zn + 2HCl → ZnCl2 + H2
65 g 72 g 135 g ?

Answers

Mass of reactants = mass of products
65 + 72 = 135 + m
m = 2 g

The mass of hydrogen produced in the reaction is 2g.

What is Mole?

The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.

A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.

Given,

Mass of Zn = 65g

Mass of HCl = 72g

Moles of Zn = mass / molar mass

= 65 / 65 = 1 mole

Moles of HCl = 72 / 36.5

= 1.97 moles

Since moles of Zn is lesser, therefore it is the limiting reagent.

From the reaction, 1 mole of Zn gives 1 mole of hydrogen

Moles of hydrogen = 1 mole

mass of hydrogen = moles × molar mass

= 1 × 2 = 2g

Therefore, the mass of hydrogen produced in the reaction is 2g.

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The total pressure of gas collected over water is 725.0 mmHg and the temperature is 18.0 C what is the pressure of hydrogen gas formed in mmHg

Answers

The pressure of hydrogen gas formed is 709.5 mmHg.

Partial pressure is the pressure exerted by a single gas component in a mixture of gases, assuming all other gases are held constant.

In this case, the hydrogen gas is formed by a chemical reaction.

To calculate the partial pressure of hydrogen gas, we need to subtract the vapor pressure of water from the total pressure of the gas collected.

The vapor pressure of water at 18.0 °C is 15.5 mmHg.

Therefore, the partial pressure of hydrogen gas can be calculated as:

Partial pressure of hydrogen gas = Total pressure - Vapor pressure of water

Partial pressure of hydrogen gas = 725.0 mmHg - 15.5 mmHg = 709.5 mmHg

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