Alicia took a friend for a birthday dinner. The total bill for dinner was $44.79 (including tax and a tip). If Alicia paid a 21.6% tip, what was her bill before adding the tip?

(Round your answer to the nearest cent.)

Shawn's phone is 36 cubic cm larger than Ellie's phone.

To get difference in volume between the two phones, we must calculate  volume of each phone and subtract the volume of Ellie's phone from the volume of Shawn's phone.

The volume of a rectangular prism is: length*width* height. The height of both phones is 3/4 centimeters.

The volume of Ellie's phone is:

= length x width x height

= 12 cm x 6 cm x (3/4) cm

= 54 cubic centimeters

The volume of Shawn's phone is:

= length x width x height

= 15 cm x 8 cm x (3/4) cm

= 90 cubic centimeters

The difference in volume is:

= Volume of Shawn's phone - Volume of Ellie's phone

= 90 cubic centimeters - 54 cubic centimeters

= 36 cubic centimeters

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The [tex]f^{-1}[/tex] inverse of f  of each

1) (x + 1)/2

2) [tex]\sqrt{\frac{x+1}{4} } \\[/tex]

3) 3 - 4x

4) [tex](x+5)^{1/3}[/tex]

5) [tex]\sqrt{x + 4}[/tex]

1) function f(x) = 3x + 1

let f(x) = y

y = 3x + 1

y - 1 = 3x

(y - 1)/3 = x

x obtained is [tex]f^{-1}[/tex]

and y will be x

[tex]f^{-1}[/tex] = (x-1)/3

2) equation f(x) = 4x² - 1

let f(x) = y

y = 4x² - 1

y + 1  = 4x²

(y + 1 )/4 = x²

x = [tex]\sqrt{\frac{x + 1}{4} }[/tex]

x obtained is [tex]f^{-1}[/tex]

and y will be x

[tex]f^{-1}[/tex] =  [tex]\sqrt{\frac{x + 1}{4} }[/tex]

similarly,

3) f(x) = 3-x/4

y = 3-x/4

4y = 3 - x

x = 3 - 4x

[tex]f^{-1}[/tex] =  3- 4x

4) y = x³ - 5

y + 5 = x³

x = [tex](y + 5)^{1/3}[/tex]

[tex]f^{-1}[/tex] = [tex](x+5)^{1/3}[/tex]

5) y = x² - 4

y + 4 = x²

x = √y + 4

[tex]f^{-1} = \sqrt{x + 4}[/tex]

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The Surface area of the composite figure is calculated as approximately: 234 sq. cm

The surface area of the composite figure is the area surrounding the faces of the solid as a whole. Therefore, we have:

Surface area (SA) = Surface area of the square prism + surface area of the square pyramid - 2(area of base)

Area of base = area of square = 6 * 6 = 36 sq. cm.

Surface area of the square prism = 2a² + 4ah

a = 6 cm

h = 4 cm

Plug in the values:

Surface area of the square prism = 2(6²) + 4*6*4

= 72 + 96

= 168 sq. cm.

Surface area of the square pyramid = 2bs + b²

b = side length = 6 cm

s = slant height = √(8² + 3²) = 8.5 cm

Plug in the values:

Surface area of the square pyramid = 2 * 6 * 8.5 + 6² = 138 sq. cm.

Surface area of the composite figure = 168 + 138 - 2(36) = 234 sq. cm

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I: TRUE - A limit is a value that a function, pattern, or sum of a series approaches as the number of terms or input value increases.

II: TRUE - A limit can also be a value that a function approximates for a specific input value, especially when dealing with continuity or differentiability.

III: FALSE - Although a limit might seem like a value that is never quite achieved, it can be reached or even exceeded, depending on the function and its behavior.

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The answer is $11,092.63.

This could be calculated using the proportion. If the value of the car decreases by 15% each year, that means that after each year the value of the car is 85% of the value from the first year.

After 1st year:

$25,000 : 100% = x1 : 85%

x1 = $25,000 · 85% ÷ 100%

x1 = $21,250

After 2nd year:

$21,250 : 100% = x2 : 85%

x2 = $21,250 · 85% ÷ 100%

x2 = $18,062.5

After 3rd year:

$18,062.5 : 100% = x3 : 85%

x3 = $18,062.5 · 85% ÷ 100%

x3 = $15,353.12

After 4th year:

$15,353.12 : 100% = x4 : 85%

x4 = $15,353.12 · 85% ÷ 100%

x4 = $13,050.15

After 5th year:

$13,050.15 : 100% = x5 : 85%

x5 = $13,050.15 · 85% ÷ 100%

x5 = $11,092.63

Therefore, the value of the car 5 years after it is purchased is $11,092.63.

The area of a shape is calculated by calculating the amount of space on the shape

By definitinon, the area of a shape is the amount of space on the shape

using the above as a guide, we have the following:

There are several formulas to calculate area

The formula to use is dependent on the shape whose area is being calculated

This means that the area of trapezoid cannot be calculated using the area of parallelogram

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the equation for the curve C as n approaches infinity     is           y = x This is the equation of the diagonal line that passes through the points (0, 0) and (1, 1).

what is diagonal line ?

A diagonal line is a straight line that runs obliquely (at an angle) between two opposite corners of a geometric shape, such as a rectangle or a square. It is called "diagonal" because it connects two non-adjacent vertices of the shape, forming a diagonal across the interior of the shape.

In the given question,

As n increases, the process described in the question creates a set of line segments that connect the equally spaced points on the x-axis to the equally spaced points on the y-axis. The resulting curve is a piecewise linear function that converges to a continuous curve as n approaches infinity.

To derive an equation for this curve, we can start by considering the line segment connecting the first mark on the x-axis to the last mark on the y-axis. Let's call this point (0, 1) and the nth mark on the x-axis (1, 0). The slope of the line connecting these two points is given by:

m = (0 - 1) / (1 - nth mark) = (1 - nth mark)^(-1)

where the nth mark on the x-axis is given by:

nth mark = 1 - (1/n)

Substituting this expression for nth mark into the equation for m, we get:

m = (n/(n-1))

The y-intercept of the line is given by:

b = 1 - m = 1 - (n/(n-1)) = 1/(n-1)

Therefore, the equation for the line segment connecting the first mark on the x-axis to the last mark on the y-axis is:

y = (n/(n-1))x + 1/(n-1)

Similarly, the equation for the line segment connecting the second mark on the x-axis to the second last on the y-axis is:

y = (n/(n-2))x + 1/(n-2)

Continuing this process for all n line segments, we get:

y = (n/(n-k))x + 1/(n-k)

where k = 1, 2, ..., n.

To get the equation for the curve C, we need to take the limit as n approaches infinity. As n goes to infinity, the value of k becomes insignificant compared to n, and we can approximate the equation for the curve as:

y = x

Therefore, the equation for the curve C as n approaches infinity is:

y = x

This is the equation of the diagonal line that passes through the points (0, 0) and (1, 1).

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Answer:

Step-by-step explanation:

In a circle, the measure of an inscribed angle is equal to half the measure of its intercepted arc. In this case, the inscribed angle is ∠WVX and its intercepted arc is ⌢WX.

Since the length of ⌢WX is (9/2)π, its measure in degrees is (9/2)π * (180/π) = 810/2 = 405 degrees.

Therefore, the measure of ∠WVX is half the measure of its intercepted arc, which is 405/2 = 202.5 degrees.

48 labels can be made if the company has a total of 4521.6in² of paper available.

We can calculate the number of labels by finding the surface area of the side of the can.

The surface area of the side of the can is the circumference of the base times the height:

C = πd

C = 3.14 x 6

C = 18.84 in

Area = C x h

Area = 18.84 x 5

Area = 94.2 in²

Therefore, each label requires 94.2 in² of paper.

To find the number of labels that can be made, we divide the total amount of paper by the amount needed per label:

Number of labels = Total area of paper / Area per label

Number of labels = 4521.6 / 94.2

Number of labels = 48

Therefore, 48 labels can be made using a total of 4521.6in² of paper.

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The 99% confidence interval estimate of the population standard deviation is [12.54, 54.62] mi/h.

A confidence interval is the mean of your estimate plus and minus the variation in that estimate. This is the range of values you expect your estimate to fall between if you redo your test.

x = [64, 60, 56, 60, 52, 59, 58, 59, 70, 68]

s = 5.963

n = 10

CI = [(n-1)*s²/chi2_upper, (n-1)*s²/chi2 lower]

CI = [(9*5.963^m²)/19.022, (9*5.963²)/2.700]

CI = [12.54, 54.62]

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The solutions for -2x²+2x+1 are x = 1 + √(3)/2 and x = 1 - √(3)/2.

To use the quadratic formula to solve -2x²+2x+1, we first identify the coefficients a, b, and c of the quadratic equation in standard form: ax²+bx+c=0. In this case, a=-2, b=2, and c=1. We then plug these values into the quadratic formula

x = (-b ± √(b²-4ac)) / 2a

Substituting the values, we get

x = (-2 ± √(2²-4(-2)(1))) / 2(-2)

Simplifying the expression inside the square root

x = (-2 ± √(4+8)) / (-4)

x = (-2 ± √12) / (-4)

Simplifying the radical

x = (-2 ± 2√3) / (-4)

Reducing the fraction

x = (1 ± √3/2)

Therefore, the two solutions are x = (1 + √3/2) and x = (1 - √3/2).

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The solution to the inputs of the given function are:

a) f(0) = 13

b) f(2) = -1

c) f(-2) = 27

d) f(1) + f(-1) = 26

The set of input values of a function is referred to as the domain of the function. Then, the set of output values of the function is referred to as the range of the function. Thus, if we possess a set of ordered pairs, we can find the domain by listing all of the input values, which are the x-coordinates.

We are given the function:

f(x) = (-x)³ - x² - x + 13

a) f(0) = (-0)³ - (0)² - 0 + 13

f(0) = 13

b) f(2) = (-2)³ - (2)² - 2 + 13

f(2) = -1

c) f(-2) = (2)³ - (-2)² + 2 + 13

f(-2) = 27

d) f(1) = (-1)³ - (1)² - 1 + 13

f(1) = 10

f(-1) = (1)³ - (-1)² + 1 + 13

f(-1) = 16

f(1) + f(-1) = 10 + 16 = 26

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Answer:

what arecrosses on line 2

The equation of the line passing through the given points is y = 6x

Given that are the values of x and y coordinates we need to find the equation of the line using them,

So, considering the points (4, 24) and (5, 30),

We know that the equation of a line passing through points (x₁, y₁) and (x₂, y₂) is =

y-y₁ = y₂-y₁ / x₂-x₁ (x-x₁)

Here (x₁, y₁) and (x₂, y₂) are (4, 24) and (5, 30),

Therefore, the required equation is =

y-24 = 30-24/5-4 (x-4)

y-24 = 6(x-4)

y-24 = 6x-24

y = 6x

Hence, the equation of the line passing through the given points is y = 6x

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Therefore, the solutions of the equation -x² + x + 12 = 0 are x = -3 and x = 6.

In mathematics, an equation is a statement that shows the equality between two expressions, typically separated by an equal sign (=). An equation can contain one or more variables, which are symbols that represent unknown or varying values. The value of the variable(s) can be found by solving the equation.

Here,

The given equation is:

-x² + x + 12 = 0

To solve for x, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / 2a

where a, b, and c are the coefficients of the quadratic equation ax² + bx + c = 0.

In this case, we have:

a = -1, b = 1, and c = 12

Substituting these values into the quadratic formula, we get:

x= (-1 ± √(1² - 4(-1)(12))) / 2(-1)

x = (-1 ± √(1 + 48)) / (-2)

x = (-1 ± √(49)) / (-2)

x = (-1 ± 7) / (-2)

There are two solutions:

x = (-1 + 7) / (-2)

= -3

x = (-1 - 7) / (-2)

= 6

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Answer:

[tex]y = -x/5 -4.[/tex]

Step-by-step explanation:

To simplify the line x + 5y = 20 into y = mx + b form:

x + 5y = 20.

5y = -x + 20.

y = -x/5 + 4.

The line parallel to the line y = -x/5 + 4 will have the same slope of -1/5.

We get the equation:

y = -x/5 + b.

To find b, we plug in the point (5, -5).

-5 = -5/5 + b.

-5 = -1 + b.

b = -4.

[tex]y = -x/5 -4.[/tex]

Answer:

Step-by-step explanation:

1) Find the upper bound of the confidence interval:

Upper bound = sample mean + margin of error

= 172.6 + 4.8

= 177.4

2) Find the lower bound of the confidence interval:

Lower bound = sample mean - margin of error

= 172.6 - 4.8

= 167.8

3) Estimate the total number of text messages sent in a month:

Total number of text messages sent = (number of students in the population / number of students in the sample) x sample mean

        = (3000 / 250) x 172.6

        = 2071.2

Therefore, the estimated number of text messages sent in a month is 2071.2, with a 95% confidence interval between 167.8 and 177.4 text messages.

Answer:

----------------------------

Find lower bound:

Find upper bound:

Lower bound:

Upper bound:

The estimated number of text messages sent in a month for all 3000 high-school students in the city is:

Answer:

36 °

Step-by-step explanation:

The markings imply equal sides*

So both of the angles are 27° there

To find angle a we do 180 - (27+27) and obtain 126°

Then to find angle y, we do 180-angle a which is 180-126 and we get 54°

We now have reached the triangle where you're supposed to find x right?

So x is equal to 180 - both other angles, which is 180 - (90 and angle y) = 180- (90+54) = 180 - 144 = 36 which is your final answer

The result of the row 1 multiplication by 1/4 is determined as  [¹/₂  0 ].

The resultant of the row multiplication in the Matrice is calculated by applying the following method;

row 1 in the given matrices = [2 0]

To multiply row by 1/4, we will multiply each entity by 1/4 as shown below;

[2 0] x 1/4 = 1/4(2 0)

= [¹/₂  0 ]

Thus, the result of the row multiplication is determined by multiplying each entry in row 1, that is 2, and 0 by 1/4.

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The equation of the line representing Main Street is option C. y = -2x + 11

The slope of the parallel lines is ½. The Main Street is perpendicular to Oak and Maple. So, the slope of Main Street is -2.

[The product of slopes of perpendicular Lines is -1.)

y - 1 = -2 (x -5)

y - 1 = -2x +10

y = -2x + 10 + 1

y = -2x + 11

Therefore, the best choice is option C. y = -2x + 11

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Since Main Street is perpendicular to Oak and Maple, its slope will be the negative reciprocal of the slope of Oak and Maple. Let's first find the equation of Oak Street.

We don't have enough information to determine the equation of Oak Street, so we need to make an assumption about its equation. Let's assume that Oak Street passes through the point (0,3) and has a slope of 2 (since the options suggest that Oak Street has a positive slope).

Using the point-slope form of a line, we have:

y - 3 = 2(x - 0)

y - 3 = 2x

y = 2x + 3

Now we can find the slope of Maple Street by noticing that it is parallel to Oak Street. Since parallel lines have the same slope, Maple Street also has a slope of 2.

To find the equation of Main Street, we need to use the fact that it passes through the point (5,1). Using the point-slope form of a line, we have:

y - 1 = -1/2(x - 5)

y - 1 = -1/2x + 5/2

y = -1/2x + 7/2

Therefore, the equation of the line representing Main Street is y = -1/2x + 7/2. The answer is (D).

The interest rate if Ted made $56 in interest for 1 year on a principle of $700 will be 8%.

Given, the interest amount is $56.

The principal amount is $700.

The time period of investment is 1 year.

Now, we have to find the interest rate.

The formula to find the simple interest is,

  S.I = PTR/100.

Now, we need to substitute the values in the above formula.

S.I = PTR/100

56 = 700×1×R / 100

56 = 700R/100

5600 = 700R

R = 5600/700

R = 8

Therefore, the interest rate is 8%.

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The required maximum area of the rectangle is 17.5m

The perimeter of a rectangle is = 70m.

We have to find The maximum area of rectangle .

A rectangle will have the maximum possible area for a given perimeter when all the sides are the same length. Since every rectangle has four sides, if you know the perimeter, divide it by four.

Maximum area of rectangle is = 70 / 4

                                                   = 17.5

The required value of maximum area of the rectangle is 17.5m.

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the perimeter of a rectangle is 70m. What are the dimensions that will produce the maximum area of such a rectangle

The length of AB is 27.3m and AD is 113 m.

Using Trigonometry in Triangle ABC

tan 50. 8 = P / B

tan 50.8 = AB / 22.3

1.2261 = AB/ 22.3

AB =  27.34 m

Now, again using Trigonometry

tan 25.4 = P / B

tan 50.8 = AD / 27.34

0.474 = AD/ 27.34

AD =  12.95916 m

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Answer:10-x

Step-by-step explanation:5 containers 2 cups in each. 5 x 2= 10. we don't know how many cups of rice he uses for a recipe so we call it x. Then we subtract it from the 10 cups of rice.

The functions are f(x) = 600 - 10x & g(x) = 20/3x, and the graphs are added as attachments

From the question, we have the following parameters that can be used in our computation:

The table of values

For the membership application, we have the following features

So, the function is

f(x) = 600 - 10x

For the membership available, we have the following features

So, the function is

g(x) = 20/3x

So, the functions are f(x) = 600 - 10x & g(x) = 20/3x

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The number for which the theoretical probability matches the experimental probability is 2.

Experimental probability and theoretical probability are two different ways to determine the likelihood of an event occurring.

Experimental probability is determined by performing an experiment or conducting observations and collecting data to see how often an event occurs. This method involves counting the number of times an event occurs and dividing that number by the total number of trials or observations.

Theoretical probability, on the other hand, is determined by using mathematical principles and calculations to determine the likelihood of an event occurring. It is based on the assumption that all outcomes are equally likely.

In the given table;

For theoretical, P(2) = 1/4

For experimental, P(7) = 7/28 = 1/4

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Answer:

I am sorry this is just so new for me like what even is an "imaginary" solution, i am in 6th grade wth

The equation of the line passing through the points (-7, -3) and (1, 2) is [tex]y = \frac{5}{8}x + \frac{11}{8}[/tex].

The formula for equation of line is expressed as;

y = mx + b

Where m is slope and b is y-intercept.

First, we determine the slope of the line.

Given the two points are (-7, -3) and (1, 2)

We can find the slope of the line by using the slope formula:

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

Substituting the values, we get:

m = (2 - (-3)) / (1 - (-7))

m = 5/8

Using the point-slope form, plug in one of the given points and slope m = 5/8 to find the equation of the line.

Let's use the point (-7, -3:

y - y₁ = m(x - x₁)

[tex]y - (-3) = \frac{5}{8}( x - (-7) ) \\\\y + 3 = \frac{5}{8}(x + 7 )\\\\y + 3 = \frac{5}{8}x + \frac{35}{8} \\ \\y = \frac{5}{8}x + \frac{35}{8} - 3\\\\y = \frac{5}{8}x + \frac{11}{8}[/tex]

Therefore, the equation of the line is [tex]y = \frac{5}{8}x + \frac{11}{8}[/tex].

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The value of p is -3/2, the value of q is -1/(t+1), and the value of r is 2.

Let the first term of the arithmetic series be a, and the common difference be d = 3. Then, we have:

a = 2t + 1

n-th term = a + (n-1)d = 2t + 1 + 3(n-1) = 3n + (2t - 2)

(Notice that the second equation can be found by substituting the expression for a into the formula for the n-th term and simplifying.)

We also know that the n-th term is given by (14t - 5), so we can equate the two expressions:

3n + (2t - 2) = 14t - 5

Simplifying and solving for n, we get:

n = (12t + 3)/3 = 4t + 1

So, the n-th term can also be expressed as:

3n + (2t - 2) = 3(4t + 1) + (2t - 2) = 14t - 5

Simplifying, we get:

14t - 5 = 14t - 5

This confirms that our expressions for the first term, common difference, and n-th term are all consistent with each other.

Now, we can use the formula for the sum of an arithmetic series to find the sum of the first n terms:

S_n = (n/2)(2a + (n-1)d) = (n/2)(4t + 4t + 1 + 3n - 3) = (3/2)n^2 + (5/2)t - 3n/2 + 1/2

We want to rewrite this expression in the form p(qt - 1)^r. To do this, we can try to complete the square in the n term, like this:

S_n = (3/2)[n^2 - 2n(t+1) + (t+1)^2] + (5/2)t - (3/2)(t+1)^2 + 1/2

S_n = (3/2)[n - (t+1)]^2 - (1/2)(t+1)^2 + (5/2)t + 1/2

Let u = n - (t+1), so that:

S_n = (3/2)u^2 - (1/2)(t+1)^2 + (5/2)t + 1/2

We want to rewrite this in the form p(qt - 1)^r, so let's try to match the terms:

p = -3/2

q = -1/(t+1)

r = 2

Therefore, the value of p is -3/2, the value of q is -1/(t+1), and the value of r is 2.

Note that the assumption that t is greater than 0 was not necessary for the derivation of the sum formula, but it is necessary for the existence of the arithmetic series (since otherwise the first term would be negative).

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The text format of the question in the picture:

22. The first term of an arithmetic series is (2t + 1) where t is > 0 The nth term of this arithmetic series is (14t - 5)

The common difference of the series is 3

The sum of the first n terms of the series can be written as p(qt - 1)^r where p, q and r are integers.

Find the value of p, the value of q and the value of r Show clear algebraic working.