Calculate E0, E, and ΔG for the following cell reactions (a) Mg(s) + Sn2+(aq) ⇌ Mg2+(aq) + Sn(s) where [Mg2+] = 0. 055 M and [Sn2+] = 0. 055 M

Heat equations are mathematical equations that are used to calculate the amount of heat energy transferred between two objects. The first heat equation, q = mcꕔt, relates the amount of heat transferred (q) to the mass of the object (m), the specific heat capacity (c), and the temperature change (ꕔt).

The specific heat capacity is the amount of heat energy required to raise the temperature of one gram of a substance by one degree Celsius. The second heat equation, q = mlvapor, relates the amount of heat required to vaporize a substance (q) to the mass of the substance (m) and the latent heat of vaporization (lvapor).

The latent heat of vaporization is the amount of heat required to transform a unit mass of a substance from a liquid phase to a gaseous phase. Finally, the third heat equation, q = mlfusion, relates the amount of heat required to melt a substance (q) to the mass of the substance (m) and the latent heat of fusion (lfusion).

The latent heat of fusion is the amount of heat required to transform a unit mass of a substance from a solid phase to a liquid phase.

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When 20.0 g of Potassium reacts with water, 0.256 moles of hydrogen gas are produced.

To determine the moles of hydrogen produced when 20.0 g of potassium reacts with water to form potassium hydroxide and hydrogen gas, follow these steps:

1. Determine the molar mass of potassium (K): The atomic weight of potassium is 39.1 g/mol.

2. Calculate the moles of potassium (K) used: moles = mass / molar mass
  moles of K = 20.0 g / 39.1 g/mol ≈ 0.512 moles

3. Use the stoichiometry of the balanced equation to find the moles of hydrogen (H₂) produced: 2 moles K produce 1-mole H₂, so the ratio is 1:0.5.

4. Calculate the moles of H₂ produced: moles of H2 = moles of K * (1 mole H₂ / 2 moles K)
  moles of H₂ = 0.512 moles * (1/2) ≈ 0.256 moles

So, when 20.0 g of potassium reacts with water to produce potassium hydroxide and hydrogen gas, there are approximately 0.256 moles of hydrogen.

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Answer:

Yes, radioactive decay will change the identity of an atom.

Explanation:

This is because the radioactive decay involves the emission of particles that change the number of protons in the nucleus. The number of protons is what determines the identity of the atom.

Answer:

in most instances, the atom changes its identity to become a new element

Explanation:

The cell potential for the given reaction at 25°C is -2.3895 V.

First, we need to balance the equation;

Mg(s) + Fe³⁺(aq) → Mg²⁺(aq) + Fe(s)

Next, we can use the Nernst equation to calculate the cell potential (Ecell) at 25°C;

Ecell = E°cell - (RT/nF)ln(Q)

where; E°cell is the standard cell potential

R is the gas constant (8.314 J/mol·K)

T is the temperature in Kelvin (298 K)

n is number of electrons transferred in balanced reaction

F is the Faraday constant (96,485 C/mol)

Q is the reaction quotient

Since the reaction is not balanced in terms of electrons transferred, we need to balance it and determine the number of electrons transferred:

Mg(s) + Fe³⁺(aq) → Mg²⁺(aq) + Fe(s) + 2e⁻

n = 2

The reaction quotient (Q) will be calculated using concentrations of the reactants and products;

Q = [Mg²⁺][Fe(s)] / [Mg(s)][Fe³⁺]

Substituting the given values, we get;

Q = (0.000612 M)(1) / (1)(1.29 M)

Q = 0.000474

Now, we can calculate the cell potential (Ecell) using the Nernst equation;

Ecell = E°cell - (RT/nF)ln(Q)

= (-2.37 V) - (0.0257 V)log10(0.000474)

= -2.37 V - 0.0195 V

= -2.3895 V

Therefore, the cell potential is -2.3895 V.

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The mass of CO2 produced is 20.9 g

The formula of the limiting reactant is O2

The reactant that produces the smallest amount of product is the limiting reactant.

Number of moles of glucose = 9.91 g/180 g/mol

= 0.055 moles

Number of moles of oxygen = 15.2 g/32 g/mol= 0.475 moles

1 mole of glucose reacts with 6 moles of oxygen

0.055 moles of glucose reacts with 0.055 * 6/1

= 0.33 moles

Thus oxygen is the limiting reactant

Mass of CO2 produced = 0.475 moles * 44 g/mol

= 20.9 g

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The volume of gas in the neon sign is 2.0 mL.

Neon signs are a popular form of advertising, characterized by bright and colorful lights that make them easily noticeable. These signs are made up of glass tubes that contain a small amount of neon gas at extremely low pressures, typically around 27.0 torr.

When an electrical current is applied to the gas, it emits a bright red-orange light, giving the sign its characteristic glow.

In order to determine the volume of gas in a neon sign, we need to use the ideal gas law equation, PV=nRT. We are given the pressure, temperature, and number of moles of gas in the sign, but we need to find the volume. Rearranging the equation to solve for V, we get V=nRT/P.

Plugging in the given values, we get:

V = (1.075 x 10^-4 moles)(0.0821 L•atm/mol•K)(315.75 K)/(27.0 torr x 1 atm/760 torr)
V = 0.002 L or 2.0 mL

Therefore, the volume of gas in the neon sign is 2.0 mL. It's important to note that the volume of gas in the sign can vary depending on the size and shape of the sign, as well as the pressure and temperature of the gas inside.

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The animal you are describing is a chipmunk. It has a backbone, nurses its offspring, likes to gnaw, has a bushy tail, stores food for winter, and has stripes on its back.

A chipmunk is a small mammal belonging to the Sciuridae family, which also includes squirrels. Chipmunks possess a backbone, making them vertebrates.

As mammals, they nurse theiroffsprin, providing them with nutrients and care. Their sharp incisors allow them to gnaw on various foods, such as nuts and seeds. Their bushy tail is an identifying feature that aids in balance while climbing and jumping.

Chipmunks are known for storing food, particularly during winter months when resources are scarce. This food hoarding is possible due to their cheek pouches, which they use to carry and store food. The distinctive stripes on their back serve as a camouflage, allowing them to blend into their environment and avoid predators.

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The molar enthalpy of combustion of methane in the gas phase is approximately -1360 kJ/mol, which is closest to -297 kJ/mol. The correct option is B.

To determine the molar enthalpy of combustion of methane, we need to use the bond enthalpies provided to calculate the energy released when the bonds in methane are broken and new bonds are formed in the combustion reaction.

The balanced chemical equation for the combustion of methane is:

CH4(g) + 2O2(g) → CO2(g) + 2H2O(l)

Breaking the bonds in methane requires energy while forming the new bonds in carbon dioxide and water releases energy. The molar enthalpy of combustion is the net energy released per mole of methane combusted.

Using the bond enthalpies given, we can calculate the energy required to break the bonds in methane:

4C-H bonds x 413 kJ/mol = 1652 kJ/mol
1C-C bond x 347 kJ/mol = 347 kJ/mol

Total energy required to break bonds in methane = 1652 kJ/mol + 347 kJ/mol = 1999 kJ/mol

Next, we can calculate the energy released by forming the new bonds in carbon dioxide and water:

2C=O bonds x 745 kJ/mol = 1490 kJ/mol
4O-H bonds x 467 kJ/mol = 1868 kJ/mol

Total energy released by forming new bonds = 1490 kJ/mol + 1868 kJ/mol = 3358 kJ/mol

The net energy released in the combustion of methane is the energy released by forming new bonds minus the energy required to break the old bonds:

Net energy released = 3358 kJ/mol - 1999 kJ/mol = 1359 kJ/mol

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The mass of the cube of titanium is 2.02 x 10^6 micrograms.

To find the mass of the cube of titanium in micrograms, we first need to find its volume:

Volume = (edge length)^3 = (3.67 x 10^4 micrometers)^3

            = 4.49 x 10^14 cubic micrometers

Next, we need to convert the density of titanium from grams per cubic centimeter to micrograms per cubic micrometer:

4.5 g/cm^3 = 4.5 x 10^9 micrograms/ (10^4 micrometers)^3

                   = 4.5 x 10^9 micrograms/ (10^12 cubic micrometers)

Now we can calculate the mass of the cube:

Mass = Volume x Density

         = 4.49 x 10^14 cubic micrometers x 4.5 x 10^9 micrograms/ (10^12 cubic micrometers)

         = 2.02 x 10^6 micrograms

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Answer:

air is a solution because it is homogeneous, uniform throughout,and doesn't scatter light

From the given information, we know that the parents are heterozygous, meaning they have two different alleles for the gene that controls coat color in their offspring. Let's use the following symbols to represent the alleles:

- B: the allele for black coat color

- b: the allele for white coat color

Since the offspring have a 25% chance of being black and a 25% chance of being white, we can assume that the parents are both heterozygous for the gene that controls coat color, which means they both have one B allele and one b allele. This is because:

- To be black, an offspring must inherit a B allele from each parent, so the parents must each have one B allele.

- To be white, an offspring must inherit a b allele from each parent, so the parents must each have one b allele.

The fact that the offspring also have a 50% chance of being speckled indicates that speckling is a result of incomplete dominance or co-dominance, where both alleles are expressed together.

Therefore, we can assume that the speckling phenotype is the result of both the B and b alleles being expressed together, rather than a third, intermediate allele.

In summary, based on the phenotype of their offspring, we can infer that the two parents are both heterozygous for the gene that controls coat color, with one B allele and one b allele each.

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The three ions containing phosphorus are phosphate (PO₄³⁻), hydrogen phosphate (HPO₄²⁻), and dihydrogen phosphate (H₂PO₄⁻).

The pattern observed is that adding hydrogen atoms successively reduces the negative charge of the ion by one unit.


1. Observe the formulas of the three ions: PO₄³⁻, HPO₄²⁻, and H₂PO₄⁻.
2. Notice that hydrogen atoms are added successively: 0, 1, and 2.
3. Observe the charges of the ions: -3, -2, and -1.
4. Recognize the pattern: adding hydrogen atoms reduces the negative charge by one unit.

In other instances where hydrogen is added to polyatomic ions, a similar pattern occurs. The negative charge decreases as more hydrogen atoms are added. This pattern is consistent across various polyatomic ions containing hydrogen.

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7.3 mL of NaOH are used to titrate the 10.00 mL aliquot.

The balanced equation for the reaction between NaOH and HCl is:

NaOH(aq) + HCl(aq) → H₂O(l) + NaCl(aq)

To calculate the volume of NaOH used,  determine how much HCl is left after it reacts with the CaCO₃, and then how much NaOH is required to neutralize that remaining HCl.

Step 1: Calculate the moles of HCl used to react with CaCO₃

The balanced equation for the reaction between CaCO₃ and HCl is:

CaCO₃(aq) + 2HCl(aq) → CaCl₂(aq) + H2O(l) + CO₂(g)

From the balanced equation, we can see that 1 mole of CaCO₃ reacts with 2 moles of HCl. Therefore, the number of moles of HCl used to react with the CaCO₃ is:

moles HCl = (7.50 mL)(2.00 mol/L) = 0.015 mol

Step 2: Calculate the concentration of HCl in the 125.0 mL solution

Started with 7.50 mL of 2.00 M HCl, which is equivalent to 0.015 moles of HCl. We added enough water to make a 125.0 mL solution, so the concentration of HCl in the solution is:

C = moles of HCl / volume of solution in L

C = 0.015 mol / 0.125 L = 0.12 M

Step 3: Calculate the moles of HCl remaining in the 10.00 mL aliquot

moles NaOH = moles HCl remaining in aliquot

(C of NaOH)(volume of NaOH) = (C of HCl)(moles of HCl remaining in aliquot)

(0.058 mol/L)(volume of NaOH) = (0.12 mol/L)(moles of HCl remaining in 10.00 mL aliquot)

moles of HCl remaining in 10.00 mL aliquot = moles of HCl in 125.0 mL solution - moles of HCl used to react with CaCO₃

moles of HCl remaining in 10.00 mL aliquot = (0.12 mol/L)(0.125 L) - 0.015 mol = 0.0035 mol

Substituting this into the equation gives:

(0.058 mol/L)(volume of NaOH) = (0.12 mol/L)(0.0035 mol)

volume of NaOH = (0.12 mol/L)(0.0035 mol) / (0.058 mol/L) = 0.0073 L

Step 4: Convert the volume of NaOH to mL

volume of NaOH = 0.0073 L x (1000 mL / 1 L) = 7.3 mL

Therefore, 7.3 mL of NaOH are used to titrate the 10.00 mL aliquot.

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Answer: C. law of conservation of mass

Explanation:

The volume-to-temperature ratio calculated by the students would be affected differently by each procedural change.

A) Failing to replenish boiling water would result in the flask being heated at a lower temperature than intended, leading to a smaller volume-to-temperature ratio.

B) Partially immersing the flask in the ice-water bath would lead to slower cooling and a higher temperature at the end of the cooling period, resulting in a larger volume-to-temperature ratio.

C) Neglecting to close the pinch clamp would allow air to enter the flask during cooling, leading to a lower pressure and a larger volume-to-temperature ratio.

D) Using 125 mL as the volume of the flask would result in an inaccurate volume-to-temperature ratio, as the actual volume of the flask may be different. It is important to measure the volume of the flask accurately to obtain reliable results.

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The given reaction HgO → Hg + O₂ is a decomposition reaction.

The balanced chemical reaction is  2HgO → 2Hg + O₂

A decomposition reaction is a type of reaction in which a particular compound or molecule dissociates or decomposes to form smaller constituent particles.

Combustion is the burning of any substance in presence of oxygen to give out carbon dioxide, water and heat.

In Synthesis reaction , new compounds are synthesized from different reactants.

Displacement reactions involve exchange of cations and anions from reactants to form different products.

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By making a simple division of the Molar concentrations. The correct option is a.

The equilibrium constant Kc is a measure of the equilibrium between the forward and reverse reactions of a chemical reaction. It is a ratio of the concentrations of the products to the concentrations of the reactants at equilibrium.

The equilibrium constant Kc:

Kc = [products]/[reactants]

here [products] is the concentration of the products at equilibrium and [reactants] is the concentration of the reactants at equilibrium.

If the concentrations of the products and reactants are given in molar concentrations (M), we can express the equilibrium constant as a ratio of Molar concentrations using the following equation:

Kc = [products]M / [reactants]M

Therefore, to find the equilibrium constant Kc, we simply need to divide the Molar concentrations of the products and reactants by their respective coefficients.

Therefore, the correct option is a) by making a simple division of the Molar concentrations.  

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Correct Question:

The equilibrium constant Kc is found:

a) by making a simple division of the Molar concentrations

b) with the quotient of the speed of the products over the reactants

c) dividing the speeds of the equations that form the chemical reaction

d) with the quotient of the concentrations of the substances present in the equation​

The wavelength of a 66.8 kg person running at a speed of 2.72 m/s through an opening of width 0.80 m is 1.44 m.

Wavelength is a concept used in physics to describe the distance between two points of a wave. It is usually measured in meters or nanometers and is expressed as the inverse of the frequency of the wave. Wavelength is an important concept in fields such as electromagnetism, optics, and acoustics. It is used to describe the size of a wave, the frequency of a wave, and the speed at which a wave travels.

Wavelength (λ) is the distance between two successive crests of a wave. For a person running at a constant speed, the wavelength is determined by the speed of the person and the frequency of the wave.
Frequency (f) is the number of waves passing through a given point in a given time.
So, the wavelength of a 66.8 kg person running at a speed of 2.72 m/s through an opening of width 0.80 m is calculated as follows:
λ = (2.72 m/s) / (2 x 0.80 m) = 1.44 m
Therefore, the wavelength of a 66.8 kg person running at a speed of 2.72 m/s through an opening of width 0.80 m is 1.44 m.

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The term that describes a pure substance that is composed of only one type of atom is an element.

An element is a substance that cannot be broken down into simpler substances by chemical reactions. Each element has a unique number of protons in the nucleus of its atoms, which gives it a specific atomic number. For example, the element carbon has an atomic number of 6, meaning that each carbon atom has 6 protons in its nucleus.

Elements are the building blocks of all matter, and there are currently 118 known elements, ranging from hydrogen (which has an atomic number of 1) to oganesson (which has an atomic number of 118). Elements can exist in various states of matter, including solids, liquids, and gases, depending on their temperature and pressure.

Pure substances, like elements, have uniform properties and composition throughout. This means that every particle of an element has the same chemical and physical properties, such as its melting point, boiling point, and density. In contrast, a mixture is composed of two or more substances that are physically combined but not chemically bonded.

Mixtures can be separated into their component parts by physical means, while pure substances cannot.

In summary, an element is a pure substance that is composed of only one type of atom. It cannot be broken down into simpler substances by chemical reactions and has uniform properties and composition throughout.

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1. 2 moles of Calcium 8016 grams = 8.01x103 grams, 2. 3 moles of Sodium 69 grams = 2.07x1023 particles, and many more given below:

Calcium is an essential mineral that is found in the human body. It is necessary for the proper functioning of many organs, including the heart and muscles. Calcium is also important for the formation and maintenance of healthy bones and teeth. It plays a role in nerve and muscle function, blood clotting, and hormone secretion. Adequate calcium intake is important for both children and adults to ensure proper growth, development, and overall health.

3. 392 grams of Technetium = 9.10x1022 particles

4. 3.01x1024 particles of Chromium = 8.41x10-2 moles

5. 5 moles of Fluorine = 25 grams

6. 24 grams of Helium = 4.67x1023 particles

7. 1.806x1024 particles of Sulfur = 4.86x10-2 moles

8. 3 moles of Platinum = 195.2 grams

9. 240 grams of Argon = 6.67x1023 particles

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Buffer solutions are made by mixing a weak acid and its conjugate base or a weak base and its conjugate acid. The pH of a buffer solution remains relatively constant when small amounts of an acid or a base are added to it.

Therefore, salt solutions containing the conjugate acid-base pair of a weak acid or a weak base could be used to prepare a buffer solution.

For example, to prepare an acetate buffer solution, one could mix a solution of sodium acetate ([tex]NaOAc[/tex]) with acetic acid ([tex]HOAc[/tex]).

The [tex]OAc^-[/tex]anion in the sodium acetate solution acts as a weak base and reacts with any added[tex]H^+[/tex] ions to form[tex]HOAc[/tex], which acts as a weak acid and buffers the solution's pH. Similarly, the [tex]NH4^+[/tex] cation in ammonium chloride ([tex]NH4Cl[/tex]) can react with [tex]OH^-[/tex]ions to form [tex]NH3[/tex], which acts as a weak base and buffers the pH of the solution.

Therefore, salt solutions containing the conjugate acid-base pair of a weak acid or a weak base can be used to prepare buffer solutions.

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The number of calories in 10 grams of sugar is an example of an intensive property. So the correct answer is 1.

Intensive properties are properties that do not depend on the amount or size of the sample being measured. In this case, the number of calories is a characteristic of sugar that remains constant regardless of the amount of sugar being measured. Other examples of intensive properties include density, boiling point, melting point, and color. On the other hand, extensive properties are properties that do depend on the amount or size of the sample being measured, such as mass, volume, and energy. Unique and chemical are not related to the concept of intensive or extensive properties. Correct Option 1.

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--The complete Question is, Fill in the blanks.

The number of calories in 10 grams of sugar is an example of a(n) ___________________.

The balanced net ionic equation for the given reaction is:

H+ (aq) + OH- (aq) → H₂O (l)

This reaction represents the neutralization of an acid and a base, where the H+ ions from the acid (in this case, H+ from H₃PO₄) react with the OH- ions from the base (in this case, NaOH) to form water (H₂O).

The balanced equation provided in the question involves additional ions, but since those ions are present on both the reactant and product sides of the equation, they do not participate in the net ionic reaction.

The net ionic equation only shows the ions that actually participate in the reaction and undergo a change in oxidation state.

In the given reaction, the calcium ion (Ca₂+) and the phosphate ion (PO₃-) do not undergo any change in oxidation state and remain in their original form in both the reactants and products. Therefore, they cancel out in the net ionic equation.

Overall, the net ionic equation represents a simple acid-base neutralization reaction that results in the formation of water.

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Ans 1  = 2 fe +3 cl2 = 2 fecl3

blank 1 = 2

blank 2 = 3

blank 3 = 2

Ans.2 = 4fe +3 o2 = 2fe2o3

blank 1 = 4

blank 2 = 3

blank 3 = 2

Ans.3 = c6h6o3 +H2o = 2c2h3

blank 1 = 1

blank 2 = 1

blank 3 = 2

The initial temperature of the air in degree Celsius was approximately 33.6°C.

When the hiker inhales air, the air undergoes a temperature change from the initial temperature to the body temperature, and a volume change due to the expansion of the lungs.

Using the ideal gas law, we can relate the initial and final volumes and temperatures of the air.

PV = nRT

Assuming the pressure is constant, we can rearrange the equation to:

(V₁/T₁) = (V₂/T₂)

where V1 is the initial volume of air, T₁ is the initial temperature, V₂ is the final volume of air, and T₂ is the final temperature (body temperature, 37°C).

We can substitute the given values and solve for T₁:

(V₁/T₁) = (V₂/T₂)

(T₁/V₁) = (T₂/V₂)

T₁= (T2 × V₁ / V₂

T₁ = (310.15 K × 0.598 L) / 0.612 L

T₁≈ 303.5 K

Converting to degrees Celsius, we get:

T₁ ≈ 30.5°C

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The gas occupies a volume of approximately 28.18 liters at a temperature of 28°C and a pressure of 1.631 atm

To determine the volume the gas occupies at a temperature of 28°C and a pressure of 1.631 atm, we will use the Ideal Gas Law, which is defined as PV = nRT. In this equation, P represents pressure, V represents volume, n represents the number of moles of the gas, R is the ideal gas constant, and T is the temperature in Kelvin.

First, we need to convert the temperature from Celsius to Kelvin: T(K) = T(°C) + 273.15. In this case, T(K) = 28 + 273.15 = 301.15 K.

Now, we can use the Ideal Gas Law to find the volume of the gas. The ideal gas constant (R) is 0.0821 L atm/mol K. Therefore, we have:

1.631 atm (V) = 3 moles (0.0821 L atm/mol K) (301.15 K)

To find the volume (V), we can rearrange the equation and isolate V:

V = (3 moles * 0.0821 L atm/mol K * 301.15 K) / 1.631 atm

V = 45.98271 L/mol / 1.631 atm

V ≈ 28.18 L

So, the gas occupies a volume of approximately 28.18 liters at a temperature of 28°C and a pressure of 1.631 atm.

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The discrepancy gap between customer expectations and perceptions towards service quality of front office staff/night auditor is commonly referred to as the "service gap."

This gap arises when customers have certain expectations regarding the level of service they will receive, but their actual perceptions of the service fall short of those expectations.

The service gap can be caused by a variety of factors, including inadequate training of front office staff, poor communication between staff and customers, inconsistencies in service delivery, and failure to meet customer needs and preferences.

To reduce the service gap, it is important for organizations to have a clear understanding of customer expectations and to ensure that their service delivery meets or exceeds those expectations.

This may involve implementing better training programs for front office staff, improving communication with customers, and implementing systems for monitoring and measuring customer satisfaction.

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Carbon-4 and Helium-4 are additional products that complete the model. Carbon-4 is an isotope of carbon with four protons and four neutrons.

It is the most common form of carbon in nature and is found in the Earth's crust and the atmosphere. Helium-4 is an isotope of helium with two protons and two neutrons.

It is the most common form of helium in nature and is found in the Earth's atmosphere and in stars. Carbon-8 and Helium-8 are heavier isotopes of carbon and helium respectively, with eight protons and eight neutrons each. Carbon-8 and Helium-8 are not found in nature and are not part of the model.

Carbon-4 and Helium-4 are important components of the model because they are the building blocks of organic compounds and biological systems. For instance, carbon-4 is found in the organic compounds that make up proteins, DNA, and carbohydrates.

Helium-4 is found in the atmosphere and is important for climate regulation. Additionally, both carbon-4 and helium-4 are important components of nuclear reactions, which are used to generate energy.

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The term mole concept is used here to determine the number of grams of sucrose. The mole concept is a convenient method to express the amount of the substance. The grams of sucrose is  1509.5 g.

One mole of a substance is that amount of it which contains as many particles or entities as there are atoms in exactly 12 g of carbon 12. The equation used to calculate the number of moles is:

Number of moles = Given mass / Molar mass

1. Mass = 4.41 × 342.3 = 1509.5 g

2. Moles = 350 / 105.98 = 3.302

3. Mass = 7.38 × 36.45 = 269.001 g

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1674.64 g of sucrose must be burned to liberate 27,584 KJ.

To find the mass of sucrose (C₁₂H₂₂O₁₁) that must be burned to liberate 27,584 KJ, you'll need to use the heat of combustion and the following equation:
mass of sucrose = (energy required) / (heat of combustion)

First, find the heat of combustion of sucrose. The heat of combustion of sucrose is approximately -5640 KJ/mol.
Next, convert the energy required from KJ to mol by dividing by the heat of combustion:
mol sucrose = 27,584 KJ / (-5640 KJ/mol) = -4.89 mol

(Note that the negative sign indicates the reaction is exothermic, but we're interested in the magnitude of the value, so we'll proceed with the absolute value.)

Now, calculate the molar mass of sucrose:
C₁₂H₂₂O₁₁ = (12 × 12.01) + (22 × 1.01) + (11 × 16.00) = 144.12 + 22.22 + 176.00 = 342.34 g/mol

Finally, calculate the mass of sucrose by multiplying the moles by the molar mass:
mass of sucrose = 4.89 mol × 342.34 g/mol = 1674.64 g
So, approximately 1674.64 g of sucrose must be burned to liberate 27,584 KJ.

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