Can someone help me, please?

The radius r for the circle C is equal to 39 using the Pythagoras rule for the right triangle ABC

Since the line AB is tangent to the circle at point B, then the triangle ABC is a right triangle and the Pythagoras rule can be applied as follows:

(50 + r)² = r² + 80²

r² = (50 + r)² - 80²

r² = (50 + r - 80)(50 + r + 80) {difference of two square}

r² = (r - 30)(r + 130)

r² = r² + 130r - 30r - 3900 {expansion of brackets}

r² - r² + 130r - 30r = 3900 {collect like terms}

100r = 3900

r = 3900/100 {divide through by 100}

r = 39

Therefore, the radius r for the circle C is equal to 39 using the Pythagoras rule for the right triangle ABC.

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Using trigonometric functions, we can find that the value of the angle N is 3°.

The six fundamental trigonometric operations make up trigonometry. Trigonometric ratios are useful for describing these methods. The sine, cosine, secant, co-secant, tangent, and co-tangent functions are the six fundamental trigonometric functions. On the ratio of a right-angled triangle's sides, trigonometric identities and functions are founded. Trigonometric formulas are used to determine the sine, cosine, tangent, secant, and cotangent values for the perpendicular side, hypotenuse, and base of a right triangle.

Here, using the cosine theorem:

CosM = n² + l² - m²/2nl

⇒ Cos 149° = 27² + 70² - m²/2 × 27 × 70

⇒ -0.981 = 729 + 4900 - m²/3780

⇒ 5629 - m² = -3708

⇒ m² = 9337.

Now Cos N = m² + l² - n²/2ml

= (9337 + 4900 - 729) / (2 × √9337 × 70)

= 0.9985

Cos N = 0.9985

Putting [tex]Cos^{-1}[/tex] on both sides:

[tex]Cos^{-1}[/tex] Cos N = [tex]Cos^{-1}[/tex] 0.9985

⇒ N ≈ 3°

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The complete question is:

In ΔLMN, n = 27 inches, l = 70 inches and ∠M=149°. Find ∠N, to the nearest degree.

Answer:

(200x20%)(12)=$480

Step-by-step explanation:

1. 200x20%=$40

There are 12 months in a year

2. 40x12= $480

Answer:y=0.5

Step-by-step explanation:Comme tu peux le voir, y est égal à au tiers de 3, se qui équivaut à 1. Si 2x=y, cela signifie que x=y/2, soit 0,5

Answer:

To find the amount in the bank after 7 years, we can use the formula:

A = P(1 + r/n)^(nt)

where:

A = the amount in the bank after 7 years

P = the principal amount (initial investment)

r = the annual interest rate (as a decimal)

n = the number of times the interest is compounded per year

t = the number of years

For the given problem:

P = $4000

r = 10% = 0.1

t = 7 years

a) Compounded Annually:

n = 1

A = 4000(1 + 0.1/1)^(1*7) = $7449.36

b) Compounded Quarterly:

n = 4

A = 4000(1 + 0.1/4)^(4*7) = $7650.13

c) Compounded Monthly:

n = 12

A = 4000(1 + 0.1/12)^(12*7) = $7727.27

d) Compounded Continuously:

n → ∞ (as n approaches infinity)

A = Pe^(rt) = 4000e^(0.1*7) = $8193.85

Therefore, the amount in the bank after 7 years increases as the compounding frequency increases. If interest is compounded continuously, the amount in the bank will be the highest.

Answer:

a_2 = 16

a_3 = -32

a_4 = 64

Step-by-step explanation:

Multiply each term by r to get the next term.

a_1 = -8

a_2 = -8 × (-2) = 16

a_3 = 16 × (-2) = -32

a_4 = -32 × (-2) = 64

Answer:

The correct answer is option B.

To find the function with an average rate of change of -4 over the interval [-2,2], we need to calculate the slope of the function between the two points -2 and 2.

Average rate of change = (f(2) - f(-2))/(2 - (-2)) = (-4)

Option B has the function qx with values {-4, 0, 0, -4, -12} at x values {-2, -1, 0, 1, 2}. The average rate of change of this function over the interval [-2,2] is indeed -4.

Answer$81

Step-by-step explanation:

A 90 degree clockwise rotation about the point (0,0), the new coordinates of Point B are (3, -1) and the new coordinates of Point C are (1, -2).

A quadrilateral can be proven to be a rectangle in a number different ways. Here are the three simplest methods: 1. Establish that all angles are 90 degrees; 2. Establish that two opposed angles are 90 degrees; and 3. Establish that the diagonals are equally long and intersect one another.

The following transformation matrix can be used to rotate a point (x,y) 90 degrees clockwise with respect to the origin (0,0):

|0 1|\s|-1 0|

This transformation matrix can be applied to each point to determine its new coordinates upon rotation.

Point B is the first point, and its initial coordinates are (-1, 3). The transformation matrix in use:

|0 1| |-1| |3|

|-1 0| x |3| = |-1|

After rotating Point B 90 degrees clockwise, the new coordinates are: (3, -1).

The transformation matrix is then applied to Point C, whose initial coordinates are (2, 1):

|0 1| |2| |1|

|-1 0| x |1| = |-2|

After rotating in a clockwise direction by 90 degrees, Point C's new coordinates are (1, -2).

As a result, after rotating 90 degrees in a clockwise direction around Point 0, Point B's new coordinates are (3, -1), while Point C's new coordinates are (1, -2).

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Answer: x= 6241/2

Step-by-step explanation:

Rewriting 4 x 3/6 as the product of a unit fraction and a whole number is: 12 * 1/6

The parameters are given as:

Number - 4

Fraction - 3/6

The following steps can be used to determine the product as the product of a whole number and a unit fraction:

Step 1 - Remember the whole number are those numbers that involve all positive integers and zero.

Step 2 - Also remember that the unit fraction is nothing but a fraction whose numerator is 1.

Step 3 - Write the given expression.

4 * 3/6

Step 4 - Convert the given fraction into a unit fraction by multiplying 4 by 3 in the above expression.

4 * 3 * 1/6

Step 5 - Simplify the above expression.

12 * 1/6

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Answer: x=25

Step-by-step explanation:

log 10 4x = 2

10^2 = 4x

100 = 4x

25 = x

The circle E with diameter CD and radius EA having the length of AC is approximately 4.2 units.

What is Pythagoras' Theorem?

In a right-angled triangle, the square of the hypotenuse side equals the sum of the squares of the other two sides.

Since EA is a radius of circle E, and AB is tangent to E at A, we know that AB is perpendicular to EA. Thus, triangle EAB is a right triangle.

Let x be the length of AC. Then, by the Pythagorean Theorem in triangle EAC, we have:

[tex]AC^{2} = EA^{2} +EC^{2}[/tex]

[tex]AC^{2} = 3^{2} + 3^{2}[/tex]

[tex]AC^{2} = 18[/tex]

AC ≈ 4.2 (rounded to the nearest tenth)

Therefore, the length of AC is approximately 4.2 units.

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The zeros of the polynomial are given as follows:

Option B: (3,0) and (-2,0)

The zeros of a polynomial function are the values of the independent variable (usually denoted by x) that make the function equal to zero. In other words, they are the values of x for which the function crosses the x-axis.

The values of x for which the graph of the polynomial crosses the x-axis are given as follows:

x = -2 and x = 3.

At these points, the y-coordinate is of zero, hence the points on the graph are given as follows:

(3,0) and (-2,0).

Meaning that the correct option is given by option B.

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Answer:

The inequality that represents this situation is 15x + 10y ≥ 1100, since Ezra needs to earn at least $1100 to buy the laptop.

To check if (60, 20) is a solution to this inequality, we need to substitute x = 60 and y = 20 into the inequality and see if it is true:

15(60) + 10(20) ≥ 1100

900 + 200 ≥ 1100

1100 ≥ 1100

Since 1100 ≥ 1100 is true, this means that (60, 20) is a solution to the inequality. This means that if Ezra works 60 hours mowing lawns and 20 hours walking dogs, he will earn enough money to buy the laptop.

The point (60, 20) represents the combination of hours worked for mowing lawns (x) and walking dogs (y) that will result in Ezra earning enough money to buy the laptop. The x and y values are the inputs or variables, while the inequality 15x + 10y ≥ 1100 is the constraint that must be satisfied. The solution (60, 20) is the output or result of the system of inequalities, and represents the combination of hours worked that will satisfy the constraint.

Answer:

[tex]x + y = 150[/tex]

[tex]2x + y = 250[/tex]

Step-by-step explanation:

In French, "bidule" is a slang term that can be used to refer to an unspecified object or thing. It can also be used to refer to a person in a vague or non-specific way

Answer:

93 million

Step-by-step explanation:

93 Million

Answer:

Step-by-step explanation: it is -2x + 430298= -9n79000.

Answer:

Step-by-step explanation:

To calculate unadjusted cost of goods sold, sum the beginning inventory value and the cost of goods manufactured, then subtract the ending inventory value.

The parameter for determining the diameter of an object depends on the specific object being measured. Here are some examples of parameters that can be used to determine diameter  the answer is  5276.7 cm3. Thus, option D is correct.

The formula for the volume of a sphere is  [tex]V = (4/3)πr^3[/tex] , where r is the radius of the sphere.

Since we are given the diameter of the sphere, we can find the radius by dividing the diameter by 2:

[tex]r = 21.6 cm / 2 = 10.8 cm[/tex]

Substituting this value into the formula, we get:

[tex]V = (4/3)\pi(10.8)^3[/tex]

[tex]= 4.18879 \times (10.8)^3[/tex]

[tex]= 5276.794 cm^3[/tex]

Rounding to the nearest tenth, we get:

[tex]V \approx 5276.8 cm^3[/tex]

Therefore, the answer is D) 5276.7 cm3.

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The given question is incomplete. the complete question is given below.

The diameter of a sphere is 21.6 cm. What is the sphere's volume? Round to the nearest tenth, if necessary. A) 693.2 cm3 B) 1453.8 cm3 C) 1868.5 cm3 D) 5276.7 cm3

Answer:

Step-by-step explanation: 1

Answer: is d

explain your answer

Step-by-step explanation:

The length of the rectangle is 4 feet longer than its width w, which means the length is w + 4

The perimeter of a rectangle is the sum of the lengths of all four sides which can be expressed as:

Perimeter = 2(length + width)

Substituting w + 4 for length and w for width, we get:

Permiter = 2(w + 4 + w)

Simplifying this expression, we get:

Perimeter = 2(2w + 4)

Perimeter = 4w + 8

Therefore, the algebraic expression to find the perimeter of the rectangular box is 4w + 8

The demand equation for commodity A is Xa = (4/10)Xb.

A demand equation is a mathematical representation of the relationship between the quantity of a good or service that consumers are willing to buy and the various factors that influence that demand, such as price, income, and preferences.

In the given question,

To find the consumer's demand equation for A, we need to use the utility maximization rule, which states that a consumer will allocate their budget in such a way as to maximize their total utility subject to their budget constraint.

Let Xa be the quantity of commodity A and Xb be the quantity of commodity B. We know that the consumer has $30 to spend, so the budget constraint is:

3Xb + pXa = 30

where p is the price of commodity A. We also know the utility function:

U = 4XgXb

To maximize U subject to the budget constraint, we can use the Lagrangian method:

L = 4XgXb + λ(30 - 3Xb - pXa)

where λ is the Lagrange multiplier.

To find the demand equation for A, we need to take the partial derivative of L with respect to Xa and set it equal to zero:

∂L/∂Xa = -λp = 0

This gives us λ = 0, which we can substitute back into the Lagrangian equation to get:

L = 4XgXb + 0(30 - 3Xb - pXa)

L = 4XgXb

To find the demand equation for A, we need to take the partial derivative of L with respect to p and solve for Xa:

∂L/∂p = -4XgXb/Xa = -30/3

Xa = (4/10)Xb

So the demand equation for commodity A is Xa = (4/10)Xb.

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The demand equation for commodity A is Xa = (4/10)Xb.

What is demand equation?

A demand equation is a mathematical formula that expresses the relationship between the quantity of a good or service that consumers are willing and able to purchase and various factors that affect that quantity, such as price, income, and the prices of other goods.

To find the consumer's demand equation for A, we need to use the utility maximization rule, which states that a consumer will allocate their budget in such a way as to maximize their total utility subject to their budget constraint.

Let Xa be the quantity of commodity A and Xb be the quantity of commodity B. We know that the consumer has $30 to spend, so the budget constraint is:

3Xb + pXa = 30

where p is the price of commodity A. We also know the utility function:

U = 4XgXb

To maximize U subject to the budget constraint, we can use the Lagrangian method:

L = 4XgXb + λ(30 - 3Xb - pXa)

where λ is the Lagrange multiplier.

To find the demand equation for A, we need to take the partial derivative of L with respect to Xa and set it equal to zero:

∂L/∂Xa = -λp = 0

This gives us λ = 0, which we can substitute back into the Lagrangian equation to get:

L = 4XgXb + 0(30 - 3Xb - pXa)

L = 4XgXb

To find the demand equation for A, we need to take the partial derivative of L with respect to p and solve for Xa:

∂L/∂p = -4XgXb/Xa = -30/3

Xa = (4/10)Xb

So the demand equation for commodity A is Xa = (4/10)Xb.

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The  X, Y, and Z values ​​are 84, 90, and 90, respectively. To answer this question, we need to understand the meaning of the words "median", "mean" and "range".

Median is the middle number of a set of numbers - it is the number in the middle when the numbers are ordered from smallest to largest.

Since the median is 90, this means that Y (the mean number) is 90. Since the average is 92, this means that the sum of the three numbers is 276 (92 x 3). The interval is 6, which means that the difference between the largest number and the smallest number is 6.

To solve for X and Z, we can use the equation X Y Z = 276. We know that Y is 90, so we can plug 90 into Y:

X 90 Z = 276

Then we can  subtract 90 from both sides to find the value of X and Z:

X Z = 186

Since the range of the three numbers is 6, this means that X and Z must be 6 plus. The only two numbers that differ by six and add up to 186 are 84 and 90.

Therefore the  X, Y, and Z values ​​are 84, 90, and 90, respectively.

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Answer:

2√2 km south and 2√2 km west of the volcano's crater.

Step-by-step explanation:

If the scientist is at the center of the circle with the volcano's crater, then the new vent is located 45° east of due south, or 135° counterclockwise from due north.

To describe the position of the new vent relative to the crater, we can use the bearing or direction angle, which is the angle between the north direction and the line connecting the crater and the new vent, measured counterclockwise.

To find the bearing, we can draw a right triangle with the hypotenuse equal to the distance from the center of the circle to the new vent, which is also the radius of the circle, or 4 km. The opposite side of the triangle is the north-south component of the line connecting the crater and the new vent, which is equal to the radius times the sine of the angle between the line and due south. The adjacent side is the east-west component of the line, which is equal to the radius times the cosine of the angle.

Using trigonometric functions, we can calculate:

Opposite side = 4 km x sin(135°) = 4 km x (-√2/2) = -2√2 km (southward direction)

Adjacent side = 4 km x cos(135°) = 4 km x (-√2/2) = -2√2 km (westward direction)

Therefore, the new vent is located 2√2 km south and 2√2 km west of the volcano's crater. Its position relative to the crater can be described as "southwest by south."

The answers f(g(x)) = x and g(f(x)) = x tell us that the two functions f(x) and g(x) are inverses of each other.

The inverse of a function is a second function that "undoes" the effect of the first function. More specifically, if f is a function that maps elements from a set A to a set B, then its inverse function, denoted as f^(-1), maps elements from B back to A.

(a) To find f(g(x)), we need to substitute the expression for g(x) into f(x):

f(g(x)) = g(x) / (6 + g(x))

Substituting the expression for g(x) yields:

f(g(x)) = (6x / (1 - x)) / (6 + (6x / (1 - x)))

This equation can be made simpler by first locating a common denominator:

f(g(x)) = (6x / (1 - x)) / ((6(1 - x) / (1 - x)) + (6x / (1 - x)))

f(g(x)) = (6x / (1 - x)) / ((6 - 6x + 6x) / (1 - x))

f(g(x)) = (6x / (1 - x)) / (6 / (1 - x))

f(g(x)) = 6x / 6

f(g(x)) = x

To find g(f(x)), we need to substitute the expression for f(x) into g(x):

g(f(x)) = 6f(x) / (1 - f(x))

Substituting the expression for f(x) yields:

g(f(x)) = 6(x / (6 + x)) / (1 - (x / (6 + x)))

To simplify this expression, we can first find a common denominator:

g(f(x)) = 6(x / (6 + x)) / (((6 + x) / (6 + x)) - (x / (6 + x)))

g(f(x)) = 6(x / (6 + x)) / ((6 + x - x) / (6 + x))

g(f(x)) = 6(x / (6 + x)) / (6 / (6 + x))

g(f(x)) = x

(b) The answers f(g(x)) = x and g(f(x)) = x tell us that the two functions f(x) and g(x) are inverses of each other. This means that when we apply one function and then the other, we get back to the original input value. Specifically, if we apply f(x) to x and then apply g(x) to the result, we get x back, and if we apply g(x) to x and then apply f(x) to the result, we also get x back. This is a useful property when analyzing functions and their relationships.

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FACE is a rhombus the following measures are 9. CY= 39.05 cm, 10. FC= 40 cm, 11. AY ≈ 39.05 cm, 12. YE = 20 cm, 13. FA ≈ 39.05 cm, 14. AC ≈ 48.99 cm, 15. Perimeter ≈ 156.20 cm.

A rhombus is a quadrilateral with all four sides of equal length. It is also known as a diamond or a lozenge. The opposite sides of a rhombus are parallel to each other, and the diagonals of a rhombus bisect each other at a right angle. Additionally, the diagonals of a rhombus are perpendicular bisectors of each other. This means that they split the rhombus into four congruent right triangles.

Since FACE is a rhombus, all four sides are equal in length. Additionally, the diagonals bisect each other at a right angle, so we can use the Pythagorean theorem to find the lengths of various segments in the figure.

9. CY: Since FC is a diagonal of the rhombus, it bisects angle FCE. This means that triangle FCY is a right triangle with FC as the hypotenuse and FY and CY as the legs. Using the Pythagorean theorem, we can find that CY is:

CY² = FC² - FY²

CY² = 40² - 15²

CY² = 1525

CY ≈ 39.05 cm

10. FC: We already know that FC = 40 cm, since it is one of the diagonals of the rhombus.

11. AY: By symmetry, we know that AY is equal in length to CY, so AY ≈ 39.05 cm.

12. YE: Since YE is half of EA, and we know that EA = 40 cm, we can find that YE = 20 cm.

13. FA: Since all four sides of the rhombus are equal, FA has the same length as CY and AY, so FA ≈ 39.05 cm.

14. AC: Since AC is a diagonal of the rhombus, it bisects angle EAF. This means that triangle ACE is a right triangle with AC as the hypotenuse and AE and EC as the legs. We can use the Pythagorean theorem to find that:

AC² = AE² + EC²

AC² = 40² + 2*(YE)²

AC² = 40² + 2*(20²)

AC² = 1600 + 800

AC² = 2400

AC ≈ 48.99 cm

15. Perimeter of the given rhombus FACE: Since all four sides of the rhombus are equal, we can find the perimeter by multiplying the length of one side by 4. Using any of the values we found above for the length of a side, we get:

Perimeter = 4*CY

Perimeter ≈ 156.20 cm

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Answer:

9. CY = 15 cm

10. FC = 30 cm

11. AY = 20 cm

12. YE = 20 cm

13. FA = 25 cm

14. AC = 25 cm

15. Perimeter FACE = 100 cm

Step-by-step explanation:

In a rhombus:

Given the diagonals bisect each other, Y is the point of intersection, and CY = 15 cm, then:

[tex]\begin{aligned}\overline{FY} &= \overline{CY} \\&= 15 \; \sf cm\end{aligned}[/tex]

[tex]\begin{aligned}\overline{FC} &= \overline{FY} + \overline{CY} \\&= 15 + 15 \\&= 30 \; \sf cm\end{aligned}[/tex]

Given the diagonals bisect each other, Y is the point of intersection, and EA = 40 cm, then:

[tex]\begin{aligned}\overline{AY}&=\overline{EA} \div 2\\&=40 \div 2\\&=20\; \sf cm\end{aligned}[/tex]

[tex]\begin{aligned}\overline{YE} &= \overline{AY} \\&= 20 \; \sf cm\end{aligned}[/tex]

As the diagonals bisect each other at 90°, m∠FYA = 90°. Therefore, triangle FYA is a right triangle.

As we know the lengths of legs of the triangle FYA, we can use Pythagoras Theorem to calculate the length of the hypotenuse (FA).

[tex]\begin{aligned}\overline{FY}^2+\overline{AY}^2&=\overline{FA}^2\\15^2+20^2&=\overline{FA}^2\\225+400&=\overline{FA}^2\\625&=\overline{FA}^2\\\overline{FA}&=\sqrt{625}\\\overline{FA}&=25\; \sf cm\end{aligned}[/tex]

As the sides of a rhombus are equal in length:

The perimeter of rhombus FACE is the sum of its side lengths:

[tex]\begin{aligned}\sf Perimeter&=\overline{FA}+\overline{EC}+\overline{AC}+\overline{FE}\\&=25+25+25+25\\&=100\; \sf cm\end{aligned}[/tex]

Note: The attached diagram is drawn to scale.