Consider the GBN protocol with a sender window size of 4 and a sequence number range of 1,024. Suppose that at time t, the next in-order packet that the receiver is expecting has a sequence number of k. Assume that the medium does not reorder messages. Answer the following questions: What are the possible sets of sequence numbers inside the sender’s window at time t? Justify your answer. What are all possible values of the ACK field in all possible messages currently propagating back to the sender at time t? Justify your answer.

Answer:

It should be undo, as the deleted text is pasted. You can then, copy it.

Answer:

undo

Explanation:

you can undo the cutting and copy instead

Answer:

is_silver = False

is_gold = False

is_premium = False

balance = float(input("Enter the balance: "))

rate = float(input("Enter the annual interest rate: "))

for i in range(3):

   balance += balance * 0.15

   print("The balance after " + str(i+1) + " year is $" + str(balance))

   if balance > 10000 and is_premium == False:

       print("You are now a premium bank club member.")

       is_premium = True

       print("You are exceeding " + str(balance - 10000) + "$ for that status")

   elif balance > 5000 and is_gold == False and is_premium == False:

       print("You are now a gold bank club member.")

       is_gold = True

       print("You are exceeding " + str(balance - 5000) + "$ for that status")

   elif balance > 1000 and is_silver == False and is_gold == False and is_premium == False:

       print("You are now a silver bank club member.")

       is_silver = True

       print("You are exceeding " + str(balance - 1000) + "$ for that status")

Explanation:

*The code is in Python.

Set the is_silver, is_gold and is_premium as False

Ask the user to enter the balance and rate

Create a for loop that iterates three times. Inside the loop:

Add the interest to the balance (cumulative sum)

Print the balance

Check the balance. If it is greater than 10000 and is_premium is False, state that the customer is a premium member, set the is_premium as True, and state how much s/he is exceeding the minimum balance for that status. If the balance is greater than 5000, is_gold is False and is_premium is False, state that the customer is a gold member, set the is_gold as True, and state how much s/he is exceeding the minimum balance for that status. If the balance is greater than 1000, is_silver is False, is_gold is False and is_premium is False, state that the customer is a silver member, set the is_silver as True, and state how much s/he is exceeding the minimum balance for that status.

Locating a file among set of flies is called file system.

Answer:

A, B and C

Explanation:

A, B and C

(The following is unrelated to the answer just to fill the letters criteria)

For closing the window in Windows 10, the following steps should be considered:

Now if we click on the start button and then click the program icon so the particular program opens instead of closing it.

Therefore the above steps are considered for closing out the window in windows 10.

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Answer:

The answer to this question is given below in the explanation section.

Explanation:

The given compound statement are:

4 < 3 and 5 < 10

4 <3 or 5 < 10

not (5 > 13)

4 < 3 and 5 < 10  this statement is false because "and" logical operator required that both operand (4<3) and (5<10) are true. Statement (4<3) is a false statement so this statement is false. "and" operator becomes true when all its inputs are true otherwise it becomes false.

4 < 3 or 5 < 10  this statement is true because "or" logical operator to be true if one of its input is true and false when all inputs are false. so in this compound statement, the first statement is false and the second statement is true. so this compound statement is true.

not(5>13) this compound statement is true because it has "not" operator and "not" operator makes a false statement to true and vice versa. so (5>13) is a false statement, and when you append "not" operator before it, then this compound statement will become true statement, so this is a true statement.

The given compound conditions would be considered true or false as follows:

i). 4 < 3 and 5 < 10 - False

ii). 4 <3 or 5 < 10 - True

iii). not (5 > 13)  - True

Thus, the first statement is false and the other two are true.

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Answer:

how does the daily path of the sun across the sky change with the seasons?

Answer:

Here is Automobile.java

class Automobile {   //class name

   private int ID, year, milesPerGallon, speed = 0;   // private member variables of Automobile of int type

   private String model, vinNo, make, color;   // private member variables of Automobile of String type

   public void setID(int ID){   //mutator method to set ID

      if (ID >= 0 && ID <= 9999)  // checks ID should not be negative or more than 9999

      this.ID = ID;  

     else this.ID = 0;  }  //if ID is negative or greater than 9999 then set ID to 0

   public void setModel(String model){  // mutator method to set model

       this.model = model;      }  

   public void setYear(int year){// mutator method to set year

      if (year >= 2000 && year <= 2017) //checks that year should not be earlier than 2000 or later than 2017

         this.ID = ID;

       else this.year = 0;     } //if year is less than 2000 or greater than 2017 then set year to 0

   public void setVinNo(String vinNo){  //mutator method to set vin number

       this.vinNo = vinNo;      }

   public void setMilesPerGalon(int milesPerGallon){  //mutator method to set miles per gallon

      if (milesPerGallon >= 10 && year <= 60)  //checks that miles per gallon should not be less than 10 or more than 60

          this.milesPerGallon = milesPerGallon;

      else this.milesPerGallon = 0;      } //if it is more than 60 or less than 10 then set miles per gallon to 0

   public void setSpeed(int speed){ //mutator method to set speed

       this.speed = speed;      }

   public void setMake(String make){  //mutator method to set make

       this.make = make;    }

   public void setColor(String color){  //mutator method to set color

       this.color = color;    }

   public int getID() //accessor method to get or access ID

   {return ID;} //returns the current ID

   public String getModel() //accessor method to get or access model

   {return model;} //returns the current model

   public int getYear()// accessor method to get or access year

   {return year;} //returns the current year

   public String getVinNo() // accessor method to get or access vin number

   {return vinNo;} //returns the current vin number

   public int getMilesPerGallon() //accessor method to get or access miles per gallon

   {return milesPerGallon;} //returns the current miles per gallon

   public int getSpeed() //accessor method to get or access speed

   {return speed;} //returns the current speed

   public String getMake() //accessor method to get or access make

   {return make;} //returns the current make

   public String getColor() //accessor method to get or access color

   {return color;}    //returns the current color

  public int Accelerate() {  //method that increase speed by 5

      setSpeed(speed + 5); //calls set speed to add 5 to the speed field

      return speed;    } //returns the speed after increasing 5

  public int Brake() { //method that decreases speed by 5

      setSpeed(speed - 5);//calls set speed to subtract 5 from the speed field

      return speed;    } //returns the speed after decreasing 5

  public int Accelerate(int spd) {  //overloading methods for Accelerate()that accepts a single parameter spd

      setSpeed(speed + spd);  //increases speed up to specified value of spd

      return speed;    }

  public int Brake(int spd) {  //overloading methods for Brake()that accepts a single parameter spd

      setSpeed(speed - spd); //decreases speed up to specified value of spd

      return speed;    }

   public Automobile(int ID, String make, String model, int year, String vinNo, int milesPerGallon, int speed, String color){  //constructor  that accepts arguments for each field value and uses the set methods to assign the values

      setID(ID);  

      setModel(model);  

      setYear(year);  

      setVinNo(vinNo);

      setMilesPerGalon(milesPerGallon);  

      setSpeed(speed);  

      setMake(make);  

      setColor(color);      } }

Explanation:

Here is TestAutomobiles.java

public class TestAutomobiles {   //class name

  public static void main(String args[]) {  //start of main method

    Automobile auto = new Automobile(123, "ABC", "XYZ", 2010, "MMM", 30, 150, "White");   //creates an object of Automobile class and calls its constructor passing the values for each of the fields

 System.out.println("Initial Speed: " + auto.getSpeed());  //calls getSpeed method to get the current speed using object auto. The current speed is 150

 System.out.println("Speed after applying acceleration: " + auto.Accelerate());   //calls Accelerate() method to increase the current speed to 5

 System.out.println("Speed after applying brake: " + auto.Brake());  //calls Brake() method to decrease the current speed to 5

   System.out.println("Speed after applying acceleration: " + auto.Accelerate(180));  //calls overloading Accelerate() method to increase the current speed to 180

     System.out.println("Speed after applying brake: " + auto.Brake(50));     }  } //calls overloading Brake() method to decrease the current speed to 50

//The screenshot of the output of the program is attached.

The output of the following program is 2.

S = "foo"

t = "bar"

print(((s+t)*3).count("barf"))

here we get The output is 2

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Answer:

1,3,4

Explanation:

They operate on a grid pattern

They search for signals to confirm that service is available.

They provide voice communications and Internet connectivity.

Answer:1, 3, 4

Explanation:edge 2023

Answer:

format

alignment

excel

=

Explanation: i'm an accountant

A change in the appearance of a value or label in a cell is format. The placement of information within a cell at the left edge, right edge is alignment, and spreadsheet can be best classified as Excel. The correct options are b, d, and c respectively.

A spreadsheet, also known as an electronic work sheet, is a computer program that organizes data into graph-like rows and columns. Formulas, commands, and formats can be used to manipulate each row and column.

Spreadsheets are most commonly used to store and organize data such as revenue, payroll, and accounting information. Spreadsheets allow the user to perform calculations on the data and generate graphs and charts.

Format is a change in the appearance of a value or label in a cell. The alignment of information within a cell at the left edge, the alignment of information within a cell at the right edge, as well as spreadsheets are usually best classified as Excel.

Thus, b, d, and c respectively are correct options.

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Answer:

It's A

Explanation:

correct on edg

Answer:

A is correct on edg

Explanation:

Answer:

Here is the C++ program:

#include <iostream>   //to use input output function

#include <vector>   //to use vectors

using namespace std;   //to identify objects like cin cout

int main() {   //start of main method

int size, number;   //to store size of list and input numbers

cout<<"Enter list size: ";   //prompts user to enter size of the list

cin >> size;   //reads list size from user

vector<int> v;   //creates a vector named v

for (int i = 0; i < size; ++i) {  //iterates till the size of list reaches

cin >> number;   //reads the input numbers

v.push_back(number);   }  //push number into a vector from the back

int num1 = v[0], num2 = v[1], current , temp;    //num1 is set to the element at 0-th position of v and num2 is set to be on 1st index of v

if (num1 > num2)  {  //if num1 is is greater than num2

temp = num1;   //assigns value of num1 to temp

num1 = num2;  //assigns value of num2 to num1

num2 = temp;  }  //assigns value of temp to num2

for (int i = 2; i < size; ++i)  {  //iterates size times

current = v[i];  //set current to the i-th index of v

if (current < num1)  {  //if current is less than num1

num2 = num1;   //assigns value of num1 to num2  

num1 = current;  }  //assigns value of current to num1

else if(current < num2)   {  //if value of current is less than num2

num2 = current;  } }  //assigns value of current to num2

cout<<num1<< " "<<num2<< endl;  } //dispalys num1 and num2 i.e. two smallest integers in ascending order

Explanation:

I will explain the program with an example.

Lets say the list size is 4 and numbers are 1 2 3 4

for (int i = 0; i < size; ++i)

This loop reads each number (1,2,3,4) and adds that number to the vector v which is the sequence container. The method push_back is used which inserts each number into the vector at the end, after the current last number and the vector size is increased by 1.

Next num1 = v[0] becomes num1 = 1

and num2 = v[1] becomes num1 = 2

if (num1 > num2) this condition is false so program moves to the statement:

for (int i = 2; i < size; ++i)

current = v[i]; becomes current = v[2]; which is current = 3

if (current < num1) is false so program moves to :

else if(current < num2) this is also false.

So the program moves to the statement:

cout<<num1<< " "<<num2<< endl;

which prints these two numbers 1 and 2 on output screen as the two smallest integers in the list in ascending order. Hence the output of the program is:

1  2

The screenshot of output of the program is attached.

Answer:

integers=[]

while True:

      number=int(input())

      if number<0:

       break

      integers.append(number)  

print("",min(integers))

print("",max(integers))

Explanation:

Answer:

the mistake is in the first statement.

Explanation:

Now lets us put the statement into consideration:

"The sum of any two rational numbers is irrational"

The negation is: " there exists a pair of rational numbers whose sum is irrational". (Existence of at least one of such a pair).

The negation is not "the sum of any two rational numbers is irrational"

Therefore the mistake is in the first statement and it is due to incorrect negation of the proof.

Answer:

heres my answer and my proof

Explanation:

Photo Album is insert image option allows a user to compile, modify, and add captions to images. Hence,  option C is correct.

A piece of software called a digital picture album allows users to upload image files from a computer's hard drive, memory card, scanner, or digital camera to a central database.

A bound or loose-leaf book with blank pages, pockets, envelopes, etc. used for displaying or storing photographs, stamps, and other valuables, as well as for autographs. an audio compilation of various musical selections, a whole drama, an opera, etc.

The paper of your choosing is directly printed with the images for your picture book. In picture albums, photo prints are commonly adhered to the pages. Photo books are frequently lighter and thinner than conventional photo albums, taking up less room on the coffee table or shelf.

Thus, option C is correct.

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Answer:

Replace /* Type your code here. */ with the following lines of code

int quarter =scnr.nextInt();

int dime = scnr.nextInt();

int nickel = scnr.nextInt();

int penny = scnr.nextInt();

double dollars = quarter * 0.25 + dime * 0.1 + nickel * 0.05 + penny * 0.01;

System.out.printf("Amount: $%.2f\n", dollars);

System.out.print((dollars * 100)+" cents");

Explanation:

The next four lines declare the given currencies as integer

int quarter =scnr.nextInt();

int dime = scnr.nextInt();

int nickel = scnr.nextInt();

int penny = scnr.nextInt();

This line calculates the amount in dollars

double dollars = quarter * 0.25 + dime * 0.1 + nickel * 0.05 + penny * 0.01;

The next two lines print the amount in dollars and cents respectively

System.out.printf("Amount: $%.2f\n", dollars);

System.out.print((dollars * 100)+" cents");

Given four values representing counts of quarters, dimes, nickels and pennies, the total amount in dollars and cent can be represented as follows;

#1 quarters = 0.25 dollars

#1 dime  = 0.1 dollar.

#1 nickel = 0.05 dollars

#1 penny = 0.01 dollars

#quarters, dimes, nickels and pennies,

x = input("write your input here: ")

for i in x:

  quarters = 0.25*float(x[0])

  dime = 0.1*float(x[1])

  nickel = 0.05*float(x[2])

  penny = 0.01*float(x[3])

sum1 = quarters + dime + nickel + penny

print(round(sum1, 2))

The commented section of the code is just the conversion rate of quarters, dime, nickel and penny to dollars.

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Answer:

Follows are the code to this question:

import java.util.*;//import package for user input

class GradePrinter//defining class GradePrinter

{

double numericValue = 0;//defining double variable

String grade = "";//defining String variable

GradePrinter()//defining default constructor  

{

Scanner xb = new Scanner(System. in );//defining Scanner  class object

System.out.print("Enter Grade: ");//print message

grade = xb.nextLine();//input string value  

}

double getNumericGrade()//defining double method getNumericGrade

{

if (grade.equals("A+") || grade.equals("A"))//defining if block that check input is A+ or A

{

numericValue = 4.0;//using  numericValue variable that hold float value 4.0

}

else if (grade.equals("A-"))//defining else if that check grade equals to A-

{

numericValue = 3.7;//using  numericValue variable that hold float value 3.7

}

else if (grade.equals("B+"))//defining else if that check grade equals to B-

{

numericValue = 3.3;//using  numericValue variable that hold float value 3.3

}

else if (grade.equals("B"))//defining else if that check grade equals to B

{

numericValue = 3.0;//using  numericValue variable that hold float value 3.0

}

else if (grade.equals("B-"))//defining else if that check grade equals to B-  

{

numericValue = 2.7;//using  numericValue variable that hold float value 2.7

}

else if (grade.equals("C+"))//defining else if that check grade equals to C+  

{

numericValue = 2.3; //using  numericValue variable that hold float value 2.3

}

else if (grade.equals("C")) //defining else if that check grade equals to C  

{

numericValue = 2.0; //using numericValue variable that hold float value 2.0

}

else if (grade.equals("C-")) //defining else if that check grade equals to C-  

{

numericValue = 1.7;//using umericValue variable that hold float value 1.7

}

else if (grade.equals("D+"))//defining else if that check grade equals to D+  

{

numericValue = 1.3;//using umericValue variable that hold float value 1.3

}

else if (grade.equals("D"))//defining else if that check grade equals to D

{

numericValue = 1.0;//using umericValue variable that hold float value 1.0

}

else if (grade.equals("F"))//defining else if that check grade equals to F

{

numericValue = 0;//using umericValue variable that hold value 0

}

else//defining else block

{

System.out.println("Letter not in grading system");//print message

}

return numericValue;//return numericValue

}

}

class Main//defining a class main

{

public static void main(String[] args)//defining main method

{

GradePrinter ob = new GradePrinter();// creating class GradePrinter object

double numericGrade = ob.getNumericGrade();//defining double variable numericGrade that holds method Value

System.out.println("Numeric Value: "+numericGrade); //print Value numericgrade.

}

}

Output:

Enter Grade: B

Numeric Value: 3.0

Explanation:

In the above-given code, a class "GradePrinter" is defined inside the class a string, and double variable "grade and numericValue" is defined, in which the grade variable is used for input string value from the user end.

After input, the sting value a method getNumericGrade is defined, which uses multiple conditional statements is used, which holds double value in the which is defined in the question.

In the main class, the "GradePrinter" object is created and defines a double variable "numericGrade", that calling method and store its value, and also use print method to print its value.

Answer:

Its all 5 of them

Explanation:

Just did it on EDG

Answer:

all 5

Explanation:

all 5

Answer:

C. crop

Explanation:

Answer:

c

Explanation:

public class ChallengeProject3B{

   public static void main(String [] args){

       System.out.println("+-----------------+");

       System.out.println("|   YOURNAME      |");

       System.out.println("+-----------------+");

       System.out.println("\n//////");

       System.out.println("| o o|");

       System.out.println("|\\_/|");

       System.out.println("-----");

       System.out.println("\n/\\");

       System.out.println("/\\");

       System.out.println("/\\");

       System.out.println("/\\");

       System.out.println("--------------");

   }

}

I hope this helps!

Answer:

You could use Print things (mail, books, etc.) or Online things (internet, social media, etc.)

Hope this helps :)

Answer:

Here is the JAVA program:

import java.util.Scanner;  //to accept input from user

public class Main{  //class name

public static void main(String[] args){ //start of main function

String sentence;  //to store the input sentence

int i, length;  //declare variables

int count[] = new int[256];  //creates a counter array

  Scanner input = new Scanner(System.in);  //creates Scanner class object to accept input from user

       System.out.println("Enter a sentence: ");  //prompts user to enter a sentence

       sentence = input.nextLine();  //scans and reads the entire sentence string from user

   String[] words = sentence.split("\\s+");  //splits the sentence into an array with separator as one or more white spaces and stores this array in words

   System.out.println("Number of words: " + words.length);  //display the number of words in sentence by using length which returns the length of the words array

     sentence = sentence.toLowerCase();  // converts the sentence into lower case to ignore case sensitivity

     sentence = sentence.replaceAll("\\s+","");  //removes the empty spaces from sentence

     length = sentence.length();  //stores the length of the sentence string into length variable

       for (i = 0; i < length; i++) {  //iterates through the length of the sentence

           count[(int) sentence.charAt(i)]++;        }  //counts occurrence of each alphabet in the sentence and stores it in count array

       for (i = 0; i < 256; i++) {  displays occurrence of alphabet in sentence

           if (count[i] != 0) {  //if count array is not empty

               System.out.println((char) i + "-" + count[i]);  }}}}

//prints each alphabet and its count

Explanation:

The program prompts the user to enter a sentence. Suppose the user enters "We won" so

sentence = "We won"

Now this sentence splits into an array with white space as separator and stored in words array. So words array has two words of sentence now i.e. "We" and "won"

Next words.length is used to return the length of words array. So length of words array is 2 hence

number of words = 2

Next the sentence is converted to lower case and spaces are removes so sentence becomes:

wewon

sentence.length() returns the length of sentence which is 5.

Next the for loop is used. At each iteration of this loop occurrence each character of sentence is added to the count[] array. charAt() is used to return a character at each index position of string. So the frequency of every character is counted and stored in count array.

Next is a for loop that is used to display each alphabet in the sentence along with its frequency in alphabetic order.

Hence the entire program gives the output:

Number of words: 2                                                                                                             e-1                                                                                                                            n-1                                                                                                                            o-1                                                                                                                            w-2

The screenshot of the output of example given in the question is attached.

Answer:

its C actually

Explanation:

C) Xerox plus i had a quiz

Answer:

xerox

Explanation:

Answer:

most money

Explanation:

common sense

Answer:

Around 2.2 grams.

Explanation:

2.2 g CO2∗1 mol CO244 g CO2=0.05 mol

355 mL∗1 L1000 mL=0.355 L

So here we can see we have about 0.05 mol/0.355 L or about 0.14 mol of carbon dioxide per liter of soda. Of course this value varies by manufacturer, type of drink, container, etc.

Answer:

Its C

Explanation:

On Edg

Answer: Click the apply to all button

Explanation:

Answer:

Freedy Thopson

Explanation:

asking questions is super in this education life

Answer:

why

Explanation:

Answer:

MS-DOS for the IBM PC

Explanation:

Shortly after its launch most personal computer companies adopted MS-DOS as their operating system.

Answer:

basically B

Explanation:

the person above is correct

Answer:

B, C, D, and F are correct answers

Explanation:

On edg

Answer: use alt+tab keys

Use the windows+tab key

Choose arrange all in the view tab

Choose switch windows in the view tab

Explanation: