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Answer:

Part A)

Approximately 318.1318 meters.

Part B)

Approximately 137.7551 meters.

Step-by-step explanation:

The path of a projectile is given by the equation:

[tex]\displaystyle y = \sqrt{3} x -\frac{49x^2}{9000}[/tex]

Part A)

The range of the projectile will be given by the difference between its starting point and landing point. In other words, its two zeros.

Let y = 0 and solve for x:

[tex]\displaystyle 0 = \sqrt{3}x - \frac{49x^2}{9000}[/tex]

Factor:

[tex]\displaystyle 0 = x\left(\sqrt{3} - \frac{49x}{9000}\right)[/tex]

Zero Product Property:

[tex]\displaystyle x = 0 \text{ or } \sqrt{3} - \frac{49x}{9000} = 0[/tex]

Solve for each case:

[tex]\displaystyle x = 0 \text{ or } x = \frac{9000\sqrt{3}}{49}\approx 318.1318[/tex]

Hence, the range of the projectile is approximately (318.1318 - 0) or 318.1318 meters.

Part B)

Since the equation is a quadratic, the maximum height is given by its vertex. Recall that the vertex of a quadratic is given by:

[tex]\displaystyle \text{Vertex} = \left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right)[/tex]

In this case, a = -49/9000 and b = √3.

Find the x-coordinate of the vertex:

[tex]\displaystyle x = - \frac{(\sqrt{3})}{2\left(\dfrac{-49}{9000}\right)} = \frac{4500\sqrt{3}}{49}[/tex]

Then the maximum height will be:

[tex]\displaystyle \displaystyle \begin{aligned} y\left(\frac{4500\sqrt{3}}{49}\right) &=\sqrt{3} \left(\frac{4500\sqrt{3}}{49}\right) -\frac{49\left(\dfrac{4500\sqrt{3}}{49}\right)^2}{9000} \\ \\ &= \frac{13500}{49} -\frac{6750}{49}\\ \\ &=\frac{6750}{49}\\ \\ &\approx 137.7551\text{ meters}\end{aligned}[/tex]

The maximum height reached by the projectile will be 137.7551 meters.

Answer:

Umm, I believe your only correct answer for your equation above would be -1.

Step-by-step explanation:

Using the PEDMAS method:

-2 - 3= -5

= -5 - (-4)

-(-4) = 4

= -5 + 4

-5 + 4 = -1

So, your answer would be -1. Hope this helps!

Answer:

It equals 2900 decigrams

Step-by-step explanation:

29 dekagrams = 290 grams

290 grams = 2900 decigrams

Therefore, 29 dekagrams = 2900 decigrams

The equivalent weight in grams for a given weight in dekagrams is approximately 10 times the weight in dekagrams.

To find the equivalent weight in grams for a given weight in dekagrams, you can use the conversion factor that 1 dekagram (dag) is equal to 10 grams.

Given the information that 29 dekagrams equals 290 grams, you can set up a proportion:

[tex]\(\frac{29 \text{ dag}}{290 \text{ g}} = \frac{1 \text{ dag}}{x \text{ g}}\)[/tex]

Cross-multiplying:

[tex]\(29x = 290 \times 1\)[/tex]

Solving for x:

[tex]\(x = \frac{290}{29}\)\\\\\(x \approx 10\)[/tex]

Therefore, the equivalent weight in grams for a given weight in dekagrams is approximately 10 times the given weight in dekagrams.

To know more about weight, refer here:

https://brainly.com/question/32319871

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Complete Question:

If 29 dekagrams equals 290 grams, what is the equivalent weight in grams for a given weight in dekagrams?

Answer:

Is this a story hmm mm i think

Answer:

a. D = R \ {13}

b. D = [-9;+∞)

D = R \ { [tex]\frac{-1}{2}[/tex] }

Step-by-step explanation:

a. 13 - x ≠ 0

 x ≠ 13

D = R \ {13}

b. 9 + x ≥ 0

x ≥ -9

D = [-9;+∞)

c. 2x + 1 ≠ 0

x ≠ [tex]\frac{-1}{2}[/tex]

D = R \ { [tex]\frac{-1}{2}[/tex] }

Answer:

the answer is 500!!

Step-by-step explanation:

10 x 50=500

Answer:

500

Step-by-step explanation:

50*10=500

50 into 10 equals 500

Answer:

height is 4ft.

Step-by-step explanation:

I used pathagorus theorem .All explaination is in the pic below.

The best approximation of the cost for an additional square foot of living space for homes in this neighborhood is a decrease of $0.125 thousand, or $125, for every one additional square foot of living space.

Since we are looking for an approximation of the cost for an additional square foot of living space, we need to find the slope of the line of best fit for the given scatterplot. The slope of the line represents the change in the cost of the house for every one unit increase in the living space, which in this case is one square foot.

From the scatterplot, we can see that as the living space increases, the cost of the house also increases, indicating a positive linear relationship. We can also see that there is a line of best fit that closely approximates this relationship.

To find the slope of the line of best fit, we can choose any two points on the line and calculate the change in the y-coordinate (the cost) divided by the change in the x-coordinate (the living space). One way to do this is to choose the two points where the line intersects the y-axis and the x-axis. From the scatterplot, we can estimate these points to be approximately (0, 200) and (1600, 0), respectively.

Using these two points, the slope of the line of best fit is:

slope = (change in y) / (change in x)

slope = (200 - 0) / (0 - 1600)

slope = -0.125

Therefore, the best approximation of the cost for an additional square foot of living space for homes in this neighborhood is a decrease of $0.125 thousand, or $125, for every one additional square foot of living space.

To know more about scatter plots follow

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3/8 is smaller than 3/5.

3/8 is smaller than 3/5

Find the LCD of both fractions:

Multiples of 8:

8, 16, 24, 32, 40, 48, 56, 64, 72, …

Multiples of 5:

5, 10, 15, 20, 25, 30, 35, 40, 45, …

40 is the LCD of denominators 5 and 8.

Multiply both denominators by a number that makes it 40, multiply that same number by each numerator:

3/8:

3 x 5 = 15

8 x 5 = 40

15/40

3/5:

3 x 8 = 24

5 x 8 = 40

24/40

15/40 < 24/40

Hope this helps

Answer:

Answer:

10in

Step-by-step explanation:

8-3=5

5+5=10

Answer:

10 inches.

Step-by-step explanation:

Assuming that before Monday, there was no snow.

On Monday, it snowed 8 inches, which is a net positive of 8:

0 + 8 = 8in total.

On Tuesday, it melted 3 inches, which is a net negative of 3:

8 - 3 = 5in total.

On Wednsday, it snowed another 5 inches, which is a net positive of 5:

5 + 5 = 10in total.

10 inches total of snow was on the ground on Wednesday.

~

Answer:

hi,

Step-by-step explanation:

[tex]\left\{\begin{array}{ccc}a&=&3*\vec{i}-4\vec{j}\\b&=&2*\vec{i}-5\vec{j}\\c&=&\lambda*\vec{i}+\mu*\vec{j}\\\end{array}\right.\\\\\\\lambda*c=2a+3b\\=2*(3*\vec{i}-4\vec{j})+3*(2*\vec{i}-5\vec{j})\\=12*\vec{i}-23\vec{j}\\=\lambda*(\lambda*\vec{i}+\mu*\vec{j})\\\\\\\left\{\begin{array}{ccc}\lambda^2&=&12\\\lambda*\mu&=&-23\end{array}\right.\\\\\\\left\{\begin{array}{ccc}\lambda&=&2\sqrt{3}\\\mu&=&\dfrac{-23*\sqrt{3} }{6} \\\end{array}\right.\\[/tex]

Answer:

-3

Step-by-step explanation:

move the constant to the other side and get

X = 2 - 5

and X = -3

Answer:

$38

Step-by-step explanation:

$14+24=38 Amy pays her mom 38 dollars. :)

Here are the formulas

[tex]\boxed{\sf Volume_{(Cylinder)}=\pi r^2h}[/tex]

[tex]\boxed{\sf Volume_{(Cone)}=\dfrac{1}{3}\pi r^2h}[/tex]

[tex]\boxed{\sf Volume_{(Sphere)}=\dfrac{4}{3}\pi r^3}[/tex]

Answer:

The volume for a cylinder is πr2h, for a cone 1/3hπr², and for a sphere is 4/3πr³

Step-by-step explanation:

I hope this will help you

Answer:

I can't answer the B question, but I can answer the A question. First, you need to add 1/3, 1/4, and 5/8 by converting them into having the same denominators (24 is the best) and then subtracting them by 24/24 or the number of your choosing. That's how you find out how much he saves.

Step-by-step explanation:

Step-by-step explanation:

3x²+1+8=27

3x²+9=2

3x²=27-9

3x²=19

x²=19/3

[tex]x = \frac{ \sqrt[]{19} }{ \sqrt{3} } [/tex]

Answer:

[tex]3^{2x} + 1 + 18 = 27\\ 3^{2x} = 18\\2x = log_{3} 18[/tex]

Step-by-step explanation:

Answer:

let Greg's age be X

therefore;

4X - 3 = 3X + 7

4X - 3X = 7 + 3

X = 10

Greg is 10 years old

hope it's helpful

Answer:

342.30.

Step-by-step explanation:

The third decimal place is 6 so we round up  the previous 2 dec places by 1

29 -->> 30 so it is 342.30.

(We round up if the next decimal  place is 5 6 7 8 or 9)

Answer: x= 1.4 or x=7/5

Step-by-step explanation:

2(5x)=14

Divide both sides by 2

5x=7

divide again this time both sides by 5 to solve for x

x=7/5 or 1.4 as a decimal

Answer:

30x + 28

Step-by-step explanation:

To evaluate (f ￮ g)(x), substitute x = g(x) into f(x) , that is

f(g(x))

= f(- 6x - 6)

= - 5(- 6x - 6) - 2 ← distribute parenthesis and simplify

= 30x + 30 - 2

= 30x + 28

Answer:

46 cm

Step-by-step explanation:

To calculate the perimeter of a rectangle, you have to add the length with itself then add the width with itself. After that, you add both of the sums together to get the answer. For this particular question, this is what you have to do.

1.Add the length with itself 15+15=30

2.Add the width with itself 8+8=16

3. Add both sums 30+16=46

In conclusion, the perimeter of the rectangle is 46 centimeters.

Answer:

Yesterday 4/5 and by 5 more people

Step-by-step explanation:

Ok so 3/4 of 100 is just 100/4*3, which is 75. 4/5 of 100 is 100/5*4, therefore, equaling 80. So 80 > 75, and when you find by how much more you do 80-75, which is 5. I hope this helps and if you have any questions you can comment them on this answer

Answer:

The answer is 4/5

Step-by-step explanation:

well 3/4 of 100 is 75. 4/5 of 100 is 80.

one fourth is equal to 25. We know that because we divide 100/4 and since there's 3 out of 4 (25x3=75)

one fifth is equal to 20. (100/5 = 20) 4 times 20 equals 80

F(-2)

is

x2 + 2x

f(0)

=

x2

+

2x

-

10

Answer:

saiufhiuaewriufidnskjnckj

Step-by-step explanation:

sdibadlhjbvfjhbvfsdbhvfsdjh

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\text{3t + 4y + 5t}[/tex]

[tex]\huge\textsf{COMBINE the LIKE TERMS}[/tex]

[tex]\huge\text{(3t + 5t) + 4y}[/tex]

[tex]\huge\text{= 8t + 4y}[/tex]

[tex]\huge\text{Answer: \textsf{8t + 4y}}[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

8t + 4y

Step-by-step explanation:

First, we have to combine LIKE TERMS giving us (3t + 5t) + 4y.

We know that 3 + 5 = 8 so 3t + 5t must be 8t.

We still have the 4y left over so we get 8t + 4y. We cannot simplify this expression anymore

So, the answer is [tex]8t + 4y[/tex] as our answer.

(Hope this helped you!)

Answer: 36π

Step-by-step explanation:

Answer:

B. 1

Step-by-step explanation:

Answer:

Option B is correct

The number of real number solutions for the given equation is, 1.

Step-by-step explanation:

Given the equation:  

Since, this is a quadratic equation of the form of  

where a =1 , b = -10 and c =25.

The discriminant of a quadratic equation is,  

then;

Discriminant =  = (100-100) = 0

Since, a  discriminant of zero means there is only one real solution for x.

Substitute the given values.

Simplify:

x = 5

Therefore, the number of real solution for the given equation is, 1

[tex] \frac{3 {a}^{2} - 9a}{ {a}^{2} - 9} = \frac{3a(a - 3)}{(a + 3)(a - 3)} = \frac{3a}{a + 3} [/tex]

[tex] \frac{ {y}^{2} - 3yz -4 {z}^{2} }{3 {y}^{2} - 12yz } = \frac{(y + z)(y - 4z)}{3y(y - 4z)} = \frac{y + z}{3y} [/tex]

[tex] \frac{ {d}^{2} + 4d + 4}{ {d}^{2} + 2d} = \frac{(d + 2)(d + 2)}{d(d + 2)} = \frac{d + 2}{d} [/tex]

[tex] \frac{5f - 15}{3 {f}^{2} - 13f + 12} = \frac{5(f - 3)}{(3f - 4)(f - 3)} = \frac{5}{3f - 4} [/tex]

I hope I helped you^_^

Answer:

good night

sweet dreams