Emmet went blueberry picking along a 3-mile walking path. He picked blueberries steadily along the walk. When he was finished, he had collected 50 ounces of blueberries.
How many ounces of blueberries did Emmet pick each mile?
Write your answer as a proper fraction or mixed number.

Answers

Answer 1

Answer:

16 2/3 ounces

Step-by-step explanation:

Emmet collected 50 ounces of strawberries along a 3 mile walk, he collected 50/3 = 16 2/3 ounces of strawberries each mile


Related Questions

graph the sequence 2, 4, 6, 8, 10

Answers

Answer:

going up in even numbers

Step-by-step explanation:

its like the two times table, and it goes up in even numbers

Answer:

any number you can take

Step-by-step explanation:

like 4'6'8''12

help with this problem plz

Answers

Answer:

22

Step-by-step explanation:

All thats need to do in this problem is add both line lengths to find the length of FH.

8 + 14 = 22

Best of Luck!

-2y-2 pls solve
pls hard for me

Answers

Answer:

−2(y+1)

Step-by-step explanation:

factor ..................

Please help ASAP pleaseeee no links or fake answers

Answers

1) 50x30
2) 2000+409
3) 500+800

Write the number in expanded form 99,763

Answers

Answer:

90,000+9,000+700+60+3

Answer:

90,000 + 9,000 + 700 + 60 + 3 I hope this helped

1) A spinner is divided into equal red, blue, green,
red, black, and yellow sections. What's the
probability of spinning green and then red.

Answers

Answer:

1/18

Step-by-step explanation:

Probability of spinning red=2/6=1/3

Probability of spinning green=1/6

probability of spinning green and then red=(1/6)*(1/3)=1/18

Mackenzie purchased a ticket to the local music festival for $25. The ticket
includes entry and access to up to 3 events at the festival. Each additional
event costs $6. The total cost for attending x events is given by the
functions T(x) and E(x).
T(x) = 6(x-3) + 25, where x>3
E(X) = 25, where 0 sxs3

Answers

After a small search, I've found that we want to find the inverses of both functions. We will find that E(x) does not have an inverse function, and the inverse function of T(x) is h(x) = x/6 - 1/6

Here we have a piecewise function:

T(x) = 6(x-3) + 25  if x > 3

E(x) = 25    if 0 ≤ x ≤ 3

First, remember that two functions f(x) and g(x) are inverses if:

f(g(x)) = x

g(f(x)) = x

From that definition we can see that E(x) does not have an inverse, because for any function g(x), we will have:

E(g(x)) = 25

So E(x) can't meet the condition.

Now let's analyze the function T(x)

T(x) = 6(x-3) + 25  

We can rewrite it as:

T(x) = 6x - 6×3 + 25

T(x) = 6x + 1

Note that T(x) is a linear equation, so the inverse will also be a linear equation. Let's assume that the inverse is h(x) = ax + b

We will have:

T(h(x)) = 6×h(x) + 1 = 6(ax + b) + 1  

Now, if these are inverses, we have:

6(ax + b) + 1 = x

6ax + 6b + 1 = x

Then we must have:

6b + 1 = 0

6ax = x

From the first equation, we can get:

6b + 1 = 0

6b = -1

b = -1/6

From the second equation we have:

6ax = x

6a = 1

a = 1/6

Then:

h(x) = x/6 - 1/6

And this is the inverse function of T(x)

If you want to learn more, you can read:

https://brainly.com/question/10300045

Snell Co. performs and completes services for a client in May and bills the client $1,000. In June, the client makes a partial payment of $300 cash for the services. In July, the remaining $700 cash is paid. Determine the monthly revenue recorded in May, June, and July for this service

Answers

The financial statement performed by Snell Corporation shows how the revenue recognition provides financial statement users(i.e. the client that uses Snell Co. service in May, June, and July) with relevant information regarding the services associated with revenue from customer contracts.

In the given case, the Snell Co. service charge was hiked in May since the entire service income must be accounted for in May. The amount owed from a client is seen as a current asset on the balance sheet, and once the amount is received from a client, it is removed off from the current asset. Thus it is added to the zero dollars ($0) company's cash balance. In this case, the cash collected in June and July is not recorded as revenue.

We can conclude that the monthly revenue recorded from Snell Co. performance and services for the client in May, June, and July for this service is as follows:

Months                               Revenue

May                                     $1000

June                                       0

July                                         0

Learn more about revenue here:

https://brainly.com/question/19682087?referrer=searchResults

Revenue is only earned after the required obligation (goods delivered or service rendered) has been fulfilled. From the question, we noted that Snell Co. performs and completes services for a client in May hence the revenue was earned in May irrespective of when money was received for the service rendered.

As such revenue earned in;

May is $1,000

June is $0

July is $0

for the service rendered

Solve M = 5rt^2- 2rv for v.

Can someone please help with this I’ll put it to 100 points

Answers

Answer:

(M-5rt^2)/(-2r) =v

Step-by-step explanation:

M = 5rt^2- 2rv

Subtract  5rt^2 from each side

M-5rt^2 = 5rt^2- 2rv -5rt^2

M-5rt^2 = - 2rv

Divide each side by -2r

(M-5rt^2)/(-2r) =- 2rv / (-2r)

(M-5rt^2)/(-2r) =v

Answer:

[tex]v = -\frac{M-5rt^2}{2r}[/tex]

Step-by-step explanation:

[tex]M = 5rt^2 - 2rv[/tex]

Switch sides

[tex]5rt^2-2rv=M[/tex]

Subtract [tex]5rt^2[/tex] from both sides

[tex]5rt^2 - 2rv-5rt^2= M -5rt^2[/tex]

Simplify

[tex]-2rv = M - 5rt^2[/tex]

Divide both sides by [tex]-2r[/tex]

[tex]\frac{-2rv}{-2r} =\frac{M}{-2r} -\frac{5rt^2}{-2r}[/tex]

Simplify

[tex]-\frac{M-5rt^2}{2r}[/tex]

I need help, NO LINKS

Answers

If you distribute each side of the equation, you’d get 12g+18 = 12g+18
This statement is always true, no matter what you put in place of g.
That means any and every real number will be a solution.
Therefore there are infinitely many solutions.

If the equation had worked out to be 12g+18 = 12g+7 or something else where the variable terms were identical, but the numbers weren’t, then there’d be no solution, since there’s no way to make 18=7.

3 kom 2.7 Eve carves a shape out of wood. What is the volume of the shap 3 cm 1 cm 2 cm 3 cm 4 cm ​

Answers

Answer:

50cm

Step-by-step explanation:

oh apdiya I just wanted to let you

Find the LCM of 315,420,525 using prime factorisation method with slove it​

Answers

[tex]\boxed{\sf \:\begin{cases}\\\begin{gathered} {\underline{{ \sf {\blue{\Large\bf \underbrace{ {\rm {\purple{\begin{array}{r | l}\large\rm{\red{ 5}}&\underline{315,420,525}\\\large\rm{\red{ 3}}& \underline{63,84,105}\\\large\rm{\red{3}}&\underline{21,28,35}\\\large\rm{\red{ 7}}&\underline{7,28,35}\\\large\rm{\red{2}}&\underline{1,4,5}\\\large\rm{\red{2}}&\underline{1,2,5}\\\large\rm{\red{5}}&\underline{1,1,5}\\&1,1,1\end{array}}}}} }}}}}\end{gathered}\\\end{cases}}[/tex]

LCM = 5 × 3 × 3 × 7 × 2 × 2 × 5

LCM = 6300

Hence, the LCM of 315 , 420 , 525 is 6300

Answer:

6300

Step-by-step explanation:

Prime factors of given numbers:

315 = 3*3*5*7420 = 2*2*3*5*7525 = 3*5*5*7

The LCM is:

LCM(315, 420, 525) = 2*2*3*3*5*5*7 = 6300

What is the range of exponential function g?

Answers

In general, the range is all the y-values used by the function. This function never gets to or goes below -6, so the range is all y-values greater than -6.

g(x) > -6

The range of the exponential function is: B. [tex]g(x)>-6[/tex]

Recall:

Range of any function includes all possible values of y (output)

Domain of any function includes all possible values of x (input).

Thus:

The values of y in the exponential function greater than -6 on the y-axis as shown in the graph given.

Therefore:

Range of the exponential function given in the graph is: B. [tex]g(x)>-6[/tex].

Learn more about exponential function here:

https://brainly.com/question/19554225

What is the length of the ladder? It is 6 ft. from the house at the bottom and touches the wall 14 ft. up at the top. Simplify your answer

Answers

Answer:

15.2

[tex] {c }^{2} = {a}^{2} + {b}^{2} \: \\ {c}^{2} ={6}^{2} + {14}^{2} \\ {c}^{2} = 36 + 196 \\ {c}^{2} = 232 \\ \sqrt{c } = \sqrt{232} \\ c = 15.23154621[/tex]

8 thousands + 4 thousands
What is the answer in standard form?

Answers

Answer:

12000

Step-by-step explanation:

8000+4000=12000

8000
4000

8,000+4,000= 12,000

HELP PLEASE
Find the length of AB

Answers

Step-by-step explanation:

hopefully it makes sense and is visible

:)

Answers and step by step explanations please?(Just one example)​

Answers

Answer is 4x x 3y >e3£

Any mathematics genius around. To solve this question.. am giving the brainliest

Answers

Well
It is in the form of a/b + b/a = (a sqr + b sqr)ab

Substitute
(Sin sqr theta + cos sqr theta) +2 cos theta + 1. 2 + 2cos theta
———————————————————————— = ————————-
Sin theta(1+cos theta). Sin theta (1 + cos theta)

2(1+ cos theta)/sin theta(1 + cos theta). {1 + cos theta cancelled}
2/sin theta. Hope it helps :}

what is the distance between the points (7, 8) and (9, 10).

Answers

Answer:

√8 or 2√2

Step-by-step explanation:

√[(x₂ - x₁)² + (y₂ - y₁)²]

√[(9 - 7)² + (10 - 8)²]

√[2² + 2²]

√[4 + 4]

√8 or 2√2

Choose the best description of the commutative property of addition,
O A. When zero is added to a number, the sum is that number.
OB. If two numbers are added in opposite orders, their sum is 0.
O C. The order in which numbers are added does not affect the sum.
D. Numbers should be added in order from smallest to largest.

Answers

9514 1404 393

Answer:

  C. The order in which numbers are added does not affect the sum.

Step-by-step explanation:

In symbols, the commutative property of addition is ...

  a +b = b +a

The order in which numbers are added does not affect the sum.

Simplify the expression. 8c2 x –3c7

Answers

Answer:

the solution is (-2^3 · 3C^9)

Step-by-step explanation:

Step 1(8 • (c2)) • (0 -  3c7)Step 223c2 •  -3c7Step 3c2 multiplied by c7 = c(2 + 7) = c9

Please help me with this Geometry problem

Answers

TS = 26 but i don’t know how to explain

Which answer shows three ways to write 2/3 as a ratio?

Answers

Answer:

2/3 can be wrtten in three ways

Step-by-step explanation:

1: 6/9

2. 4/6

3.20/30

2. Which group of numbers is in size order?

A. 3.10 - 3.20 - 3.09 - 3.55
B. 3.09 - 3.10 - 3.2 - 3.5
C. 3.10 - 3.20 - 3.09 - 3.55
D. 3.1 - 3.55 - 3.2 - 3.09

Answers

Answer:

B. 3.09-3.10-3.2-3.5 is the answer

Translate and solve: Three-fourths of p is 18.

Answers

hi <3

just form a quick equation:

3/4p = 18

divide both sides by 3/4 to get your answer:

p = 24

hope this helps :)

A product is introduced into the market. Suppose a products sales quantity per month q(t) is a function of time t in months is given by q(t) = 5000t-120t^2. And suppose the price in dollars of that product. p(t). is also a function of time t in months and is given by p(t) = 120-t^2.

Required:
a. Find, R'(t). the rate of change of revenue as a function of time t
b. What is the the rate of change of revenue with respect to time 3 months after the introduction?

Answers

Answer:

Part A)

[tex]\displaystyle R'(t) = (5000-240t)(120-t^2)+(5000t-120t^2)(-2t)[/tex]

Part B)

After three months, the revenue is increasing at a rate of $391,560 per month.

Step-by-step explanation:

A product is introduced into the market. The quantity per month q sold is given by the function:

[tex]q(t) = 5000t - 120t^2[/tex]

And the price p (in dollars) of the product is given by the function:

[tex]p(t) = 120-t^2[/tex]

Part A)

R(t), or the revenue, will be the product of the quantity sold and its respective price during the month. Hence:

[tex]\displaystyle R(t) = q(t)\cdot p(t)[/tex]

Substitute:

[tex]\displaystyle R(t) = \left(5000t-120t^2\right)\left(120-t^2\right)[/tex]

To find R'(t), take the derivative of both sides with respect to t:

[tex]\displaystyle R'(t) = \frac{d}{dt}\left[ \left(5000t-120t^2\right)\left(120-t^2\right)\right][/tex]

Since the function is a product of two expressions, we can consider using the Product Rule:

[tex]\displaystyle \frac{d}{dx} \left[uv\right] = u'v+uv'[/tex]

Hence:

[tex]\displaystyle R'(t) = \frac{d}{dt}\left[5000t-120t^2\right]\left(120-t^2\right) + \left(5000t-120t^2\right)\frac{d}{dt}\left[120-t^2\right][/tex]

Differentiate. Therefore:

[tex]\displaystyle R'(t) = (5000-240t)(120-t^2)+(5000t-120t^2)(-2t)[/tex]

(We may simplify if we desire, but this is not required by the problem.)

Part B)

To find the rate of change of revenue with respect to time three months after the introduction, we can evaluate R'(t) at t = 3. Hence:

[tex]\displaystyle R'(3) = (5000-240(3))(120-(3)^2)+(5000(3)-120(3)^2)(-2(3))[/tex]

Evaluate:

[tex]R'(3) = 391560\text{ dollars/month}[/tex]

In conclusion, after three months, the revenue is increasing at a rate of $391,560 per month.

(Note: it is increasing because the final value is positive.)

how to calculate bearing​

Answers

Answer:

Step-by-step explanation:

You will have to interpret the question with the aid of a diagram and make out the relevant angles and either make use of cosine rule,sine rule etc....Your knowledge on angles should be sound

HELP!! TRUTH TABLE

I would really appreciate it, if someone could walk me through how they did it! Thanks.

Answers

pq (i.e. "p and q") is true only if both p and q are true. This is the case for the first two rows, but not the third.

Similarly, (pq) ∧ r is true only if both pq and r are true. We know when pq is true, so (pq) ∧ r is true only when all three of p, q, and r are true. This happens only in the first row.

All other cases are false.

The table should look like this:

[tex]\begin{array}{c|c|c|c|c}p&q&r&p\land q&(p\land q)\land r) \\---&---&---&---&--- \\T&T&T&\boxed T&\boxed T\\&&&&\\T&T&F&\boxed T&\boxed F\\&&&&\\T&F&T&\boxed F&\boxed F\end{array}[/tex]

An Olympic diver jumps off of a platform that is 10 meters high. The diver goes 2 meters underwater after a dive. How far is it from the starting point at the top of the platform to the depth under water?​

Answers

Answer:

12 meters far.

Step-by-step explanation:

The question translates to 10+2. The word problem states that the height of the platform is 10 meters. That means we can say that he'd have already traveled 10 meters down when he dived. And the problem also states that the diver goes two meters under the water, meaning that he had traveled 2 meters, in addition to the 10 meters. And so, we add the 10 and 2 to get 12 meters in total.

The perimeter of the square with side length y

Answers

Answer:

4y

Step-by-step explanation:

Answer:

perimeter=4y

Step-by-step explanation:

y+y+y+y=4y

..........

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