The value of sin(A-B) is 2334/6625
What is trigonometric identity?Trigonometric Identities are the equalities that involve trigonometry functions and holds true for all the values of variables given in the equation.
Example of trigonometric identity include;
cos 2 θ + sin 2 θ = 1 cos 2 θ + sin 2 θ = 1.
1 + cot 2 θ = csc 2 θ 1 + cot 2 θ = csc 2 θ
1 + tan 2 θ = sec 2 θ 1 + tan 2 θ = sec 2 θ
Sin(A-B) = = sin A cos B- cos Asin B
if tan A = 4/3, then 4 is the opp and 3 is the adj,
hyp² = 4²+3²
= 16+9
hyp² = 25
hyp = √25
= 5
cos A = 3/5 and sinA = 4/5
if sinB = 28/53, then opp is 28 is the opp and 53 is the hyp
adj = √ 53²-28²
adj = √ 2809 - 784
adj = √2025
adj = 45
cos B = 45/58
sin(A-B) = 4/5 × 45/58 - 3/5× 28/53
= 18/29 - 84/265
= (4770-2436)/6625
= 2334/6625
therefore the value of sin(A-B) = 2334/6625
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In the diagram below, BE intersects AD at C, AB | DE. If CD = 4.2 and AB = 9.6, what is the length of
BC to the nearest tenth of a centimeter?
Dont mind the writing
The length of BC, to the nearest tenth of a centimeter, is calculated as: 12.6 centimeter.
How to Find the Length of the Indicated Side?Recall that two similar triangles will always have side lengths that are proportional in length. The triangles shown are similar to each other, therefore, the proportion below would be true:
AC/CE = BC/CD
Given the following:
AC = 7.2 units
CE = 2.4 units
CD = 4.2 units
BC = ?
Plug in the values:
7.2/2.4 = BC/4.2
Cross multiply:
BC = 7.2 * 4.2 / 2.4
BC = 12.6 cm
Thus, the length of side BC in the similar triangles shown is approximately 12.6 cm.
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At the gift shop, they sell small greeting cards and large greeting cards. The cost of a small greeting card is $1.80 and the cost of a large greeting card is $3.85. How much would it cost to get 4 small greeting cards and 3 large greeting cards? How much would it cost to get
�
x small greeting cards and
�
y large greeting cards?
Answer: 18.75
Step-by-step explanation:
small greeting cards = 1.80
large greeting cards = 3.85
1.80 x 4 = 7.20
3.85 x 3 = 11.55
7.20 + 11.55 = 18.75
where should the linear inequality y ≤ 1/4 x- 3 be shaded?
The required direction of the inequality is below the line.
How to find the direction of inequality in graph?If you're not graphing a vertical line, the inequality's sign will tell you which half-plane to shade. Shade above the line when using the or > sign. Shade below the line if the symbol or is used. Larger solutions are to the right and smaller solutions are to the left, respectively, for a vertical line.
According to question:To check the direction, we will take points from the graph and put in the given inequality.
At point (2, 0)
y ≤ x/4 - 3
0 ≤ 2/4 - 3
0 ≤ -25
It is false
Again
At (2, -4)
y ≤ x/4 - 3
-4 ≤ 2/4 - 3
-4 ≤ -2.5
It is true,
Thus, we can say the direction of the inequality is below the line.
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This is for precalc can someone help please
Can someone help me please
here is the picture
The result of adding -4 (row 1) to row 3 is determined as (0 - 9 2)|12.
What is the result of the row multiplication?The resultant of the row multiplication in the Matrice is calculated by applying the following method;
row 1 in the given matrices = [1 2 1] | -5
To multiply row by -4, we will multiply each entity by 4 as shown below;
= -4(1 2 1) | -5
= (-4 -8 - 4) |20
To add the result to 3;
(-4 -8 - 4)|20 + (4 - 1 6) | -8
= (0 - 9 2)|12
Thus, the result of the row multiplication is determined by multiplying each entry in row 1, by - 4.
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1 Soo divides a square into sixths. She colors one of the
equal parts red. What fraction of the square is red?
The fraction of the square that is red is 1/6.
Define fractionA fraction is a number that represents a part or parts of a whole. It consists of two numbers separated by a horizontal or diagonal line, with the number above the line (numerator) representing the part and the number below the line (denominator) representing the whole. For example, the fraction 3/4 represents three parts out of a whole that is divided into four equal parts.
A square divided into six equal parts has six equal sixths.
If Soo colors one of these equal parts red, then she has colored one-sixth of the square red.
Therefore, the fraction of the square that is red is 1/6.
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PLEASE HELP!!
A cone has a radius of 3 inches and a slant height of 12 inches.
What is the exact surface area of a similar cone whose radius is 6 inches?
Enter your answer in the box.
Surface area of similar cone =
___in²
Surface area of similar cone is 44π square inches
What does a cone in maths ?
A cone is referred to as a "right cone" when its vertex is higher than the base's centre (i.e., when the angle formed by the vertex, base center, and any base radius is a right angle); otherwise, the word "oblique" is used. A cone is referred to as an elliptic cone when the base is assumed to be an ellipse rather than a circle.
The surface area of a cone is given by:
surface area = πr(r + l)
where r is the radius and l is the slant height.
surface area of original cone = π(3)(3 + 12) = 45π
slant height of similar cone = (6/3)(12) = 24 inches
surface area of similar cone = π(6)(6 + 18) = 144π
ratio of surface areas = surface area of similar cone / surface area of original cone
= (144π) / (45π)
= 3.2
Therefore, The exact surface area of the similar cone is 6 times the surface area of the original cone,
6 × 45π = 144π square inches
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what are the answers to these questions?
a) The function of h in terms of r is h=1400/(πr²).
b) The surface area of the can in terms of r is 2800/r+2πr².
c) The corresponding values of r and h that minimize the amount of required material are r≈14.04 cm and h≈2.98 cm.
a) The volume of a cylinder is given by
V = πr²h.
In this case, the volume of the can is
1400 cm³
So we have
1400 = πr²h.
Solving for h, we get
h = 1400/(πr²).
b) The surface area of a cylinder is given by
A = 2πrh+2πr².
Using the expression we obtained for h in part (a), we can substitute it in the equation and get
A = 2πr(1400/(πr²))+2πr²
= 2800/r+2πr².
c) To minimize the amount of required material, we need to find the value of r that minimizes the surface area.
To do this, we take the derivative of the surface area expression with respect to r and set it equal to zero:
dA/dr = -2800/r²+4πr = 0.
Solving for r, we get
r = √(700/π), which is approximately 14.04 cm.
Substituting this value in the expression for h that we obtained in part (a), we get
h = 1400/(π(14.04)²), which is approximately 2.98 cm.
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Factor the polynomial completely. If the polynomial is prime, so state.
15y2 - 19y + 6
Answer: 15y2 - 19y + 6 = 0
Step-by-step explanation:
The first term is, 15y2 its coefficient is 15 .The middle term is, -19y its coefficient is -19 .The last term, "the constant", is +6 Step-1 : Multiply the coefficient of the first term by the constant 15 • 6 = 90 Step-2 : Find two factors of 90 whose sum equals the coefficient of the middle term, which is -19 .
Can you help me with this please
Answer: [tex]\frac{2}{5}[/tex] x [tex]\frac{4}{5}[/tex] = [tex]\frac{8}{25}[/tex]
Step-by-step explanation:
We can do this by counting the boxes for both the Width and the Length.
If we look at the width of these boxes (horizontally) then we see that there are 5 boxes all together, with 2 shaded green.
this means that 2 out of 5 of the boxes are shaded for the width, giving us the fraction: [tex]\frac{2}{5}[/tex]
Then for the Length (vertically) we see that there are also 5 boxes, but this time 4 are shaded. This gives us the fraction: [tex]\frac{4}{5}[/tex].
Then, to fill the equation in, we do: [tex]\frac{2}{5}[/tex] x [tex]\frac{4}{5}[/tex] , which gives us [tex]\frac{8}{25}[/tex]
2 x 4 = 8
5 x 5 = 25
To double check this answer, we can count how many boxes are shaded green.
We see that 8 are shaded green, out of the 25 boxes that are there.
Therefore, giving us a complete answer of: [tex]\frac{2}{5}[/tex] x [tex]\frac{4}{5}[/tex] = [tex]\frac{8}{25}[/tex]
simplify (5^4)^2. 5^6. 5^8. 25^6. 25^8
Therefore here, (5⁴)². 5⁶. (5⁸)².(5⁶)². (5⁸)² simplifies to 5⁸².
The simplest version is what?The integer's basic form is represented by its smallest equivalent fraction. How to determine the simplest form: Look for shared components in the denominator and numerator.
By applying the exponentiation laws, let's us gradually simplify this an expression is:
[tex](5^4)^2 = 5^(4*2) = 5^85^6 * 5^8 = 5^(6+8) = 5^1425^6 = (5^2)^6 = 5^(2*6) = 5^1225^8 = (5^2)^8 = 5^(2*8) = 5^16[/tex]
When all of these simplifications are put back into the original statement, we get the following:
[tex](5^4)^2. 5^6. 5^8. 25^6. 25^8 = 5^8 * 5^14 * 5^12 * 5^16 * 5^16[/tex]
Using the rule that is [tex]a^b * a^c = a^(b+c)[/tex],
The first three terms can be combined to create:
[tex]5^8 * 5^14 * 5^12 * 5^16 * 5^16 = 5^(8+14+12) * 5^(16+16) = 5^50 * 5^32[/tex]
Using the same rule again, we can combine these two terms:
5⁵⁰* 5³²
= 5⁵⁰⁺³²
= 5⁸²
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helpppp
in the figure below, m WXZ=72 degrees, and m 2 is three times m 1. Find m 1
Answer:
Step-by-step explanation:
Confusing
Kerrin is making an input-output table for the rule "add 5." What is the output value for an input value of 5?
Options:
A: 0
B :5
C: 10
D: 25
The calculated output value for an input value of 5 is (c) 10
What is the output value for an input value of 5?From the question, we have the following parameters that can be used in our computation:
Kerrin is making an input-output table for the rule "add 5."
This means that
Output = input + 5
In this case, we have
input = 5
substitute the known values in the above equation, so, we have the following representation
Output = 5 + 5
Evaluate
Output =10
Hence, the output is 10
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I have no idea how to solve this problem.
(a) The domain of f of g is {1, 8}.
(b) The range of f of g is {0, 1}.
What is the domain and range of f of g?The domain of f of g consists of all the inputs in the domain of g that are also in the domain of f.
(a) Domain of f of g:
The inputs in the domain of g that are also in the domain of f are 1, and 8. Therefore, the domain of f of g is {1, 8}.
To find the range of f of g, we need to apply the function composition f(g(x)) to each input in the domain of f of g, and collect all the outputs.
(b) Range of f of g:
The range of f of g consists of all the outputs obtained by applying f(g(x)) to each input in the domain of f of g.
We have:
f(g(1)) = f(8) = 0
f(g(4)) = f(2) = 1
f(g(8)) = f(0) = 1
Therefore, the range of f of g is {0, 1}.
Thus, in set notation, the domain of f of g is {1, 8}, and the range of f of g is {0, 1}.
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9 belongs to the set N
Answer:
9 belongs to set N, natural, whole, integer, rational, and real number
Step-by-step explanation:
* Natural number: use for counting
* Whole number: includes natural number and zero
* Integer : are whole numbers and their opposite
*Rational number:come from fraction, and their results can be positive integer
*Real number: includes all numbers
One option in a roulette game is to bet 11on red. (There are 18 red compartments, 18 black compartments, and two compartments that are neither red nor black.) If the ball lands on red, you get to keep the 11 you paid to play the game and you are awarded 11. If the ball lands elsewhere, you are awarded nothing and the 11 that you bet is collected. Complete parts (a) through (b) below.
The expected value for playing roulette if a person bet $16 on red is -$0.84.
b. The statement that best describes what this value means is option b. Over the long run, the player can expect to lose about $1.05 for each game played.
What is the expected value?To be able to calculate the expected value, you need to multiply the probability of winning by the amount won hence it will be:
Expected value = (18/38) x $16 - (20/38) x $16
= -$0.84
Based on the fact that the expected value has a negative sign, it implies that, on average, the player tend to lose money over the long run.
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See full question below
one option in a roulette game is to bet $16 on red. (there are 18 red compartments, 18 compartments, and two compartments that are neither red nor black) if the ball lands on red, you get to keep the $16 you paid to play the game and you are awarded $16. If the ball lands elsewhere, you are awarded nothing and the $16 that you bet is collected.
a. what is the expected value for playing roulette if you bet $16 on red?
$__________ (round to the nearest cent)
b. chosen the statment below that best describes what this value means???
Pick One!
a. over the long run, the player can expect to win about $1.05 for each game played
b. over the long run, the player can expect to lost about $1.05 for each game player
c. over the lung run, the player can expect to break even
The strength of a beam is proportional to the width and the square of the depth. A beam is cut from a cylindrical log of diameter d = 24 cm. The figures show different ways this can be done. Express the strength of the beam as a function of the angle in the figures. (Use k as your proportionality constant.)
The strength of the beam is proportional to the width and the square of the depth, so we can express it as Strength = k * width * depth²
where k is the proportionality constant.
In the given figures, the beam is cut from a cylindrical log of diameter d = 24 cm, which means the maximum width and depth of the beam are limited by this diameter. We can see from the figures that the width and depth of the beam change depending on the angle at which it is cut from the log.
In Figure 1, the width and depth of the beam are equal, so we can express the strength of the beam as:
Strength = k * width * depth² = k * x² * (d/2 - x)²
where x is the width and depth of the beam.
In Figure 2, the width and depth of the beam are not equal, so we need to express them separately. Let w be the width and d be the depth, then we can express the strength of the beam as:
Strength = k * width * depth² = k * w * d² = k * ((d/2)sinθ)² * ((d/2)cosθ)²
where θ is the angle at which the beam is cut from the log.
In Figure 3, the width and depth of the beam also vary with the angle θ. We can express the width and depth as follows:
w = d sinθ
d = (d/2)cosθ
Then we can express the strength of the beam as:
Strength = k * width * depth² = k * (d sinθ) * [(d/2)cosθ]²
Therefore, depending on the angle at which the beam is cut from the log, the strength of the beam can be expressed using different equations, but in all cases, the strength is proportional to the width and the square of the depth, with a proportionality constant k.
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Complete question is:
The strength of a beam is proportional to the width and the square of the depth. A beam is cut from a cylindrical log of diameter d = 24 cm. The figures show different ways this can be done. Express the strength of the beam as a function of the angle in the figures. (Use k as your proportionality constant.)
Please see the attached
Using the ratios, 1 yd/3 feet, 1 mi/5,280 feet, and 200 yards/1 feet, the number of flags required to mark the racecourse with a flag every 200 yards is 22.
What are the ratios?Ratios are relative sizes of one quantity or value compared to another.
Ratios are depicted as fractional values using decimals, percentages, or fractions, including the standard ratio form (:).
The total distance of the racecourse = 2.5 miles
The common distance between each flag = 200 yards
1 mile = 1,760 yards
2.5 miles = 4,400 yards
1 yard = 3 feel
The number of flags required to cover the distance = 22 (4,400 ÷ 200)
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What is the meaning of "Finally [tex]s _{i}\circ s_{i}=s _{j}\circ s_{i}=1[/tex] hence [tex]s _{j}=s_{i}\circ r_{i-j}[/tex] and [tex]s _{i}=r_{i-j}\circ s_{j}[/tex]?
This statement describes the relationship between symmetries and rotations
Explaining the meaning of the statement as statedThis statement describes a relation between two symmetry operations, denoted by [tex]s_i[/tex] and [tex]s_j[/tex], and a rotation operation denoted by [tex]r_{i-j}[/tex]. The notation [tex]"s_i \circ s_i"[/tex] and [tex]"s_j \circ s_i"[/tex] denotes the composition of these operations, which means applying one operation after the other.
The statement says that [tex]s_i[/tex] and [tex]s_j[/tex] are both symmetries, and that they have a specific relationship with each other: when [tex]s_i[/tex] is composed with itself, it gives the identity operation (denoted by 1), and when [tex]s_j[/tex] is composed with [tex]s_i[/tex], it also gives the identity operation.
Then the statement concludes that this relationship implies that [tex]s_j[/tex] can be obtained by first applying [tex]s_i[/tex] and then applying a rotation operation [tex]r_{i-j}[/tex], and that [tex]s_i[/tex] can be obtained by first applying a rotation operation [tex]r_{i-j}[/tex] and then applying [tex]s_j[/tex].
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If 90% of a number is 110, find 9% of that number.
We can set up the equation :
0.9x = 110 ,
where x is the unknown number. To solve for x, we can divide both sides by 0.9 :
x = 110 ÷ 0.9
x = 122.22 (rounded to two decimal places)
So the unknown number is approximately 122.22.
To find 9% of that number, we can multiply 122.22 by 0.09 :
0.09 × 122.22 = 11.00 (rounded to two decimal places)
Therefore, 9% of the number is approximately 11.
On January 10, 2022, Cullumber Co. sold merchandise on account to Robertsen Co. for $16,600, n/30. On February 9, Robertsen Co. gave Cullumber Co. a 11% promissory note in settlement of this account.
The preparation of the journal entry to record the sale and the settlement of the account receivable is as follows:
Journal Entry:January 10, 2022:
Debit Accounts Receivable $16,600
Credit Sales Revenue $16,600
(To record the sale of merchandise on account to Robertsen Co, n/30.)
February 9, 2022:
Debit Notes Receivable $16,600
Credit Accounts Receivable $16,600
(To record the receipt of a 11% promissory note in settlement of account receivable.)
What are journal entries?Journal entries refer to the initial records maintained about business transactions.
Journal entries show how the transactions will be posted in the general ledger.
Transaction Analysis:January 10, 2022: Accounts Receivable $16,600 Sales Revenue $16,600
Terms n/30
February 9, 2022: Notes Receivable $16,600 Accounts Receivable $16,600
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Question Completion:Prepare the journal entry to record the sale and the settlement of the account receivable.
MODELING REAL LIFE About 5.2% of a population
contracted the flu last year. A test used to diagnose the
flu was 92% accurate for people who had the flu and
85% accurate for people who did not have it. Find and
interpret the ratio of true positives to false positives.
The ratio of true positives to false positives, given the accuracy of the test would be 239 : 711 .
Here. we have,
First, find the number of people who have the flu:
= 5. 2 % x 10, 000
= 520 people
Those who don't have it:
= 10, 000 - 520
= 9, 480 people
True positive :
= 92 % x 520
= 478 people
False negatives:
= 8 % x 520
= 42 people
False positives:
= 15 % x 9, 480
= 1, 422 people
The ratio of true positives to false positives is therefore:
478 : 1, 422
239 : 711
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A framed picture has a total area y, in square inches. The thickness of the frame is
represented by x, in inches. The equation y = (8+2x)(10 + 2x) relates these two
variables.
1. What are the length and width of the picture without the frame?
2. What would a solution to the equation 100 = (8+2x)(10+2x) mean in this
situation?
The given total area including the frame is y = (8+2x)(10+2x).
As per the question the thickness of the frame is x.
The area of a rectangle is given by A=L*B
For a picture with frame it will be A=(L+2t)*(B+2t)
1. Comparing the above equation with the given equation it can be concluded that the Length is 10 and the width is 8.
2. The given equation is 100=(8+2x)(10+2x)
Upon solving it simplifies to [tex]x^2+9x-5=0[/tex]
x=0.525.
Thus the thickness x=0.525.
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En un grupo de 60 alumnos, 12 sacaron 10 en el examen de matemáticas. ¿Cuál es el porcentaje de alumnos que sacaron 10?
We can see that the percentage is 20%, then 20 percent of the students got a 10.
Which percentage of the students got a 10?To find this, we need to use the formula:
Percentage = 100%(number of students with a 10)/(total number of students)
Here we know the that the revelant numbers are:
Number of students with a 10 = 12
total number of students in the class = 60
Replacing that in the formula we will get the percentage:
P = 100%*(12/60)
P = 20%
So 20% of the total number of students got a 10.
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The model for radioactive decay is y=y0e^-kt. a radioactive substance has a half-life of 170 years. if 40 grams are present today. in how many years will 15 grams be present? While solving this problem, round the value of k to seven decimal places. Round your answer to two decimal places.
It will take about 225.25 years of time for 15 grams to be present.
The half-life of a radioactive substance is the time it takes for half of the substance to decay.
For this substance with a half-life of 170 years, we can use the following formula to find the value of k:
[tex]0.5 = e^(^-^1^7^0^k^)[/tex]
Taking the natural logarithm of both sides, we get:
ln(0.5) = -170k
Solving for k, we get:
k = ln(0.5) / (-170)
= 0.004085
Now, we can use the model [tex]y = y_0e^(^-^k^t^)[/tex] to find the time t required for the substance to decay from 40 grams to 15 grams.
We have:
[tex]15 = 40e^(^-^0^.^0^0^4^0^8^5^t^)[/tex]
Dividing both sides by 40 and taking the natural logarithm of both sides, we get:
ln(15/40) = -0.004085t
Solving for t, we get:
t = ln(15/40) / (-0.004085)
= 225.25 years
Therefore, it will take about 225.25 years for 15 grams to be present.
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The volume of a juice box is about 24 cubic inches.
A large department store found that it averages 362 customers per hour. Assume that the standard deviation is 29.6 and a random sample of 40 hours was used to determine the average. Which statements about this situation are true?
The 99% confidence interval of the population mean is (352.32, 371.68).
To find the 99% confidence interval of the population mean, we need to use the following formula:
CI = x; ± zα/2 * (σ/√n)
where:
x' = sample mean (362)
zα/2 = z-score for 99% confidence level (2.576)
σ = population standard deviation (29.6)
n = sample size (40)
Substituting the values, we get:
CI = 362 ± 2.576 * (29.6/√40)
CI = 362 ± 9.68
This means that if we take many random samples of 40 hours from the population, we can be 99% confident that the true population mean of the number of customers per hour falls between 352.32 and 371.68.
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Complete question is:
A large department store found that it averages 362 customers per hour. Assume that the standard deviation is 29.6 and a random sample of 40 hours was used to determine the average. Find the 99% confidence interval of the population mean.
The temperature is dropping at 3 degrees per hour. At noon it was 0 degrees, what was the temperature at 1pm? 2pm? 3pm? 6pm? What was the temperature t hours after noon?
The temperature at 1pm is -3°C, at 2pm it's -6°C, at 3pm it's -9°C, and at 6pm it's -18°C. The temperature t hours after noon is T = 0 - 3t
If the temperature is dropping at a rate of 3 degrees per hour, then the temperature t hours after noon can be represented by the equation T = 0 - 3t, where T is the temperature in degrees Celsius.
To find the temperature at a specific time after noon, we need to substitute the corresponding value of t into the equation and solve for T. For example:
At 1pm (t = 1), T = 0 - 3(1) = -3°C
At 2pm (t = 2), T = 0 - 3(2) = -6°C
At 3pm (t = 3), T = 0 - 3(3) = -9°C
At 6pm (t = 6), T = 0 - 3(6) = -18°C
To find the temperature t hours after noon, we can use the same equation: T = 0 - 3t. For example, if we want to find the temperature 4 hours after noon, we can substitute t = 4 into the equation: T = 0 - 3(4) = -12°C. So the temperature 4 hours after noon is -12°C.
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What are the solutions to the system of equations?
y=x^2−5x−6
y=2x−6
(−1, 0) and (−6, 0)
(7, 8) and (0, −6)
(−6, 0) and (0, −1)
(−1, 0) and (0, −6)
Please answer- I will report you if you do not answer and only want the points.
The solutions of the system of equations are (0, -6) and (7, 8)
How to find the solution of the system of equations?
Here we have the system of equations:
y=x^2−5x−6
y=2x−6
To solve this, we need to solve the equation:
x^2 - 5x - 6 = 2x - 6
x^2 - 7x = 0
x*(x - 7) = 0
We can see that the two solutions are:
x = 0
x = 7
Evaluating the line in these values we get:
y = 2*0 - 6 = -6
y = 2*7 - 6 = 8
Then the solutions are (0, -6) and (7, 8)
Learn more about systems of equations:
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A total of $5550 is plit into
Awo investments. Part of the money.
is invested at 4%, and the reminder
is invested at 5"%.. If the total annual
interest from the two investments is
$259, how much is invested at each rate?
a = amount invested at 4%
how much is 4% of "a"? (4/100) * "a", namely 0.04a.
b = amount invested at 5%
how much is 5% of "b"? (5/100) * "b", namely 0.05b.
we know the total amount invested is 5550, so whatever "a" and "b" might be, we know that a + b = 5550.
we also know that the yielded amount in interest is 259, so if we simply add their interest, that'd be 0.04a + 0.05b = 259.
[tex]a+b=5550\implies b=5550-a \\\\[-0.35em] ~\dotfill\\\\ 0.04a+0.05b=259\implies \stackrel{\textit{substituting from above}}{0.04a+0.05(5550-a)~~ = ~~259} \\\\\\ 0.04a+277.5-0.05a=259\implies 277.5-0.01a=259\implies -0.01a=-18.5 \\\\\\ a=\cfrac{-18.5}{-0.01}\implies \boxed{a=1850}\hspace{9em}\stackrel{ 5550~~ - ~~1850 }{\boxed{b=3700}}[/tex]