Answer:
The balanced chemical equation for the reaction between H₂PO₂ and NaOH is:
H₂PO₂ + 3 NaOH → Na₃PO₄ + 3 H₂O
Explanation:
From the equation, we can see that 1 mole of H₂PO₂ reacts with 3 moles of NaOH to produce 1 mole of Na₃PO₄ and 3 moles of H₂O.
The volume of NaOH used in the titration is 150.0 mL, which is equivalent to 0.150 L. The molarity of the H₂PO₂ solution used is 0.16 M, which means that 0.16 moles of H₂PO₂ were used in the titration.
According to the balanced equation, 1 mole of H₂PO₂ reacts with 3 moles of NaOH. Therefore, the number of moles of NaOH used in the titration is three times the number of moles of H₂PO₂ used:
Number of moles of NaOH = 3 × 0.16 = 0.48 moles
The volume of NaOH used is 0.150 L, so the molarity of NaOH can be calculated as follows:
Molarity of NaOH = Number of moles of NaOH / Volume of NaOH used
Molarity of NaOH = 0.48 moles / 0.150 L
Molarity of NaOH = 3.2 M
Therefore, the molarity of NaOH is 3.2 M, which is represented by the sky blue color.
At a constant temperature and pressure, there are initially 0.6400 moles in a balloon with a volume of 4.00 L. Gas is removed until there is a total of 0.3500 moles. Calculate the volume of the balloon after this change.
The volume of the balloon after the change is approximately 2.19 L. The gas laws behaviour of gases by providing relationships between the temperature, moles, volume and pressure
What is gas law?We can use the combined gas law to solve this problem: (P1V1)/(n1T1) = (P2V2)/(n2T2) where P is the pressure, V is the volume, n is the number of moles, and T is the temperature.
We can assume that the temperature and pressure remain constant, so T1 = T2 and P1 = P2.
Therefore, we can simplify the equation to: (V1/n1) = (V2/n2)
Substituting the given values, we get: (V1/0.6400) = (V2/0.3500)
Solving for V2, we get: V2 = (0.3500/0.6400) * V1 V2 = 0.5469 * V1
The volume of the balloon after the change is 0.5469 times the original volume, or: V2 = 0.5469 * 4.00 L = 2.1876 L
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Please does anyone know how to answer these questions?
Given that we don't have the equation mentioned in the question, I will assume that the equation is referred to is the following:
2N2(g) + 5O2(g) → 2N2O5(g)
a) If you start with 2 moles of O2, according to the equation, 5 moles of O2 are needed to react with 2 moles of N2. Therefore, the number of moles of N2O5 created would be (2/5) x 2 = 0.8 moles.
b) If you start with 1 mole of O2, according to the equation, 5/2 moles of O2 are needed to react with 2 moles of N2. Therefore, the number of moles of N2O5 created would be (1/(5/2)) x 2 = 0.4 moles.
c) If you start with 1 mole of N2, according to the equation, 5/2 moles of O2 are needed to react with 2 moles of N2. Therefore, the number of moles of N2O5 created would be (5/2) x 1 = 2.5 moles.
d) If you get 6 moles of N2O5 during your reaction, according to the equation, 2 moles of N2O5 are produced for every 5 moles of O2 used. Therefore, the number of moles of O2 needed would be (5/2) x (6/2) = 7.5 moles.
e) If you get 6 moles of N2O5 during your reaction, according to the equation, 2 moles of N2O5 are produced for every 2 moles of N2 used. Therefore, the number of moles of N2 needed would be (2/2) x (6/2) = 3 moles.
Names: The chemical names for the compounds involved in the equation are:
O2: Oxygen gas
N2: Nitrogen gas
N2O5: Dinitrogen pentoxide gas
Steps
A chemical reaction between nitrogen and oxygen is represented by the balanced chemical equation 2N2(g) + 5O2(g) 2N2O5(g). The quantities of the reactants and products used in this reaction were questioned.
We may use stoichiometry to determine the mole ratio of O2 to N2O5, which will allow us to calculate how many moles of N2O5 is generated when 2 moles of O2 are consumed.
The equation shows that in order to produce 2 moles of N2O5, 5 moles of O2 must react with 2 moles of N2. The result is the production of (2/5) x 2 = 0.8 moles of N2O5.
Similar calculations can be used to determine how many moles of N2O5 are created when 1 mole of O2 or 1 mole of N2 is used.
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A sample of gas at 32.6 torr and 735 K is heated to 1035 K. What is the new pressure of the gas?
Answer: The answer for this question is 45.9.
Explanation: Since there are numbers with different significant figures, the number or numbers that have less significant figures will be the one you round to. In this case, the numbers in the problem are 32.6,735, and 1035. Since we need to find the numbers that have the least significant figures, the numbers 32.6 and 735 have three significant figures while 1035 has 4 significant figures. Since we need to choose the numbers that have the least significant figures, these numbers are 32.6 and 735 since they have three significant figures. Round your answer to three significant figures and you get 45.9 as your answer.
ingitis, but, it also occurs when bacteria dir eninges. This may be caused by an ear or sinus infection and or s Define the term meningitis. 1 2 Mention SIX typical complications of meningitis. List FOUR signs and symptoms of meningitis. Discuss THREE steps of treating a person with meningitis Mention the TWO types of meningitis. right reserved TO
Meningitis is an inflammation of the meninges, which are the membranes that cover the brain and spinal cord. It can be caused by a bacterial or viral infection, with bacterial meningitis being the most serious and potentially life-threatening form.
What are Some common complications of meningitis?Septicemia: This is a serious bloodstream infection that can occur as a result of meningitis. It can cause organ failure and can be fatal.
Brain swelling: Meningitis can cause the brain to swell, which can lead to increased pressure inside the skull and can cause damage to brain tissue.
Hearing loss: Meningitis can damage the inner ear and cause hearing loss, which can be permanent.
Vision loss: In some cases, meningitis can cause damage to the optic nerve and lead to vision loss.
Cognitive impairment: Meningitis can cause long-term cognitive impairment, including problems with memory, attention, and other cognitive functions.
Seizures: Meningitis can cause seizures, which are sudden and uncontrolled bursts of electrical activity in the brain.
Some common signs and symptoms of meningitis include:
Headache
Stiff neck
Fever
Nausea and vomiting
The treatment of meningitis typically involves three main steps:
Antibiotics or antiviral medications: Depending on the cause of the infection, antibiotics or antiviral medications may be prescribed to fight the infection.
Supportive care: This may include medications to reduce fever and pain, as well as intravenous fluids to prevent dehydration.
Hospitalization: Most cases of meningitis require hospitalization for close monitoring and treatment.
Conclusively, there are two main types of meningitis: bacterial meningitis and viral meningitis. Bacterial meningitis is more severe and can be life-threatening if not treated promptly, while viral meningitis is typically less severe and often resolves on its own without treatment.
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if the [H+] of a solution is 8.4 x 10-3 mol/L the pOH of the solution is
The pOH of the solution is 10.92.
Calculation-Equation: The relationship between a solution's pH and pOH is:
pH + pOH = 14
where pH is equal to the negative logarithm of the concentration of hydrogen ions (H+), and pOH is equal to the negative logarithm of the concentration of hydroxide ions (OH-).
We must first determine the [OH-] concentration to determine the solution's pOH. We can apply the following:
Kw = [H+][OH-] = 1.0 x 10^-14 at 25°C
where Kw is the water-specific ion product constant.
If we rewrite this equation, we obtain:
[OH-] = Kw/[H+] = 1.0 x 10^-14 / 8.4 x 10^-3 = 1.19 x 10^-11 mol/L
We can now calculate pOH's value using the definition of the term:
pOH = -log[OH-] = -log(1.19 x 10^-11) = 10.92
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A natural gas (CH4) furnace leaks into the room which is at one atmospheric
pressure and 18°C. The flammability limits of methane are approximately 0.5 to
1.6. When this room is closed and leak tight, it would take between 38 – 56 hours
to reach flammability range. What would you predict happens when the same
scenario occurs in a home in the mountains of New Mexico where the atmospheric
pressure is 0.89 atm? Explain in terms of combustible range and relative ratios.
b) Where do you expect to find methane “residues” in a room?
The flammability of natural gas ranges from 5 to 15 percent. This indicates that no combustion would take place in any mixture with a natural gas to air ratio of less than 5% or greater than 15%.
50% LEL methane – what is it?The lowest concentration of a gas at which combustion can occur is known as the LEL. A reading in%LEL measures the percentage of that LEL value. The LEL, for instance, is 5% by volume for methane. Half of that amount, or 2.5% by volume, is 50% LEL.
How do you determine methane's LEL?Divide the unknown concentration by the LEL specified in the NFPA Handbook to determine the LEL of any gas in air.
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Write the molecular equation and net ionic equation for the reaction of hydroiodic acid and potassium hydroxide. Include phases (states). Enter the formula for water as H2O
find the molar equation and net ionic equation.
The Molecular Equation is : [tex]HI (aq) + KOH (aq) \rightarrow KI (aq) + H_2O (l)[/tex]
The Net Ionic Equation is : [tex]H^+(aq) + OH^-(aq) \rightarrow H_2O(l)[/tex]
This reaction is an acid-base neutralization reaction. Hydroiodic acid (HI) is an acid and potassium hydroxide (KOH) is a base. When the two react, they form water ([tex]H_2O[/tex]) and potassium iodide (KI).[tex]H_2O[/tex] is a chemical formula for water, which consists of two hydrogen atoms and one oxygen atom. Water is a fundamental component of life and is essential for all forms of life on Earth. The reaction is a double displacement reaction, where the positively charged cations, potassium (K⁺) and hydrogen (H⁺), switch places with each other in the reactants to form the products.
It is possible to describe the as:
[tex]HI (aq) + KOH (aq) \rightarrow KI (aq) + H_2O (l)[/tex]
One way to express the net-ionic equation is as follows:
[tex]H^+(aq) + OH^-(aq) \rightarrow H_2O(l)[/tex]
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HELP ASAP PLSSS I don't get it
Answer:
I believe the answer is 120 degrees Celsius.
Explanation:
−15+135=120
CH3CHCHCHCH3 with two CH3 groups and an OH group attached IUPAC name
The IUPAC name for the given molecule, which has four carbon atoms, one OH group, and two methyl (CH3) groups attached, is:
4-methyl-2-pentanol
What is IUPAC?
It is an international organization that aims to advance the chemical sciences and to contribute to the application of chemistry in the service of humankind.
Identify the longest carbon chain that contains the functional group (OH). In this case, the longest chain has five carbon atoms.
Number the carbon atoms in the chain, starting from the end that is closest to the functional group (OH). In this case, we can number the chain from left to right, so that the OH group is on carbon atom 2.
Identify and name the substituents (groups) attached to the main chain. In this case, there are two methyl (CH3) groups attached to carbon atoms 4 and 5, respectively.
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What variables are plotted on the x and y axes of the graph
Answer:
The Axes. The independent variable belongs on the x-axis (horizontal line) of the graph and the dependent variable belongs on the y-axis (vertical line). The x and y axes cross at a point referred to as the origin, where the coordinates are (0,0).Select the options that correctly reflect the mass ratios and mass percentages of the elements in SO3
1. The mass ratio of S is .400
2. The mass percentage of O is 60%
The options "The mass ratio of S is .400 and The mass percentage of O is 60%" , Both are correct of the elements in sulfur trioxide ([tex]SO^3[/tex])
The molecular formula of sulfur trioxide ([tex]SO^3[/tex]) contains one sulfur atom and three oxygen atoms. To calculate the mass ratios and mass percentages of each element in [tex]SO^3\\[/tex], we need to know the atomic masses of sulfur and oxygen:
Sulfur (S): 32.06 g/mol
Oxygen (O): 16.00 g/mol
Mass ratio of S:
The mass ratio of sulfur (S) in [tex]SO^3\\[/tex] is the mass of sulfur divided by the total mass of the compound:
Mass ratio of S = mass of S / (mass of S + mass of O)
Mass ratio of S = [tex]32.06 g/mol / (32.06 g/mol + 3(16.00 g/mol))[/tex]
Mass ratio of S =[tex]32.06 g/mol / 80.06 g/mol[/tex]
Mass ratio of S = 0.400
Therefore, option 1 "The mass ratio of S is .400" is correct.
Mass percentage of O:
The mass percentage of oxygen (O) in [tex]SO^3[/tex] is the mass of oxygen divided by the total mass of the compound, multiplied by 100%:
Mass percentage of O = (mass of O / total mass) x 100%
Mass percentage of O = [tex](3(16.00 g/mol) / (32.06 g/mol + 3(16.00 g/mol))) * 100%[/tex]
Mass percentage of O = [tex]48.00 g/mol / 80.06 g/mol * 100%[/tex]
Mass percentage of O = 59.97%
Rounding to one significant figure, the mass percentage of O in [tex]SO^3\\[/tex] is 60%.
Therefore, option 2 "The mass percentage of O is 60%" is also correct.
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25 points!! And i’ll give brainliest!
Asap
1.
100 grams of ethanol were dissolved in 2 kg of water.
Calculate the boiling and freezing points of the formed solution.
2.
80 grams of benzoic acid were dissolved in 800 g of water. Calculate the boiling and freezing points of the formed solution.
To solve both problems, we need to use the equations for calculating boiling point elevation and freezing point depression:
Boiling point elevation: ΔTb = Kb x molality
Freezing point depression: ΔTf = Kf x molality
where:
ΔTb is the boiling point elevation or increase in boiling pointΔTf is the freezing point depression or decrease in freezing pointKb is the molal boiling point elevation constant for the solventKf is the molal freezing point depression constant for the solventmolality is the concentration of the solute in mol/kg of solventFor both problems, we assume that the solute is completely dissolved in the solvent and that the resulting solution is ideal.
First, we need to calculate the molality of the ethanol solution:
molality = moles of solute / mass of solvent in kg
moles of ethanol = 100 g / 46.07 g/mol = 2.17 molmass of water = 2 kg = 2000 gmolality = 2.17 mol / 2 kg = 1.09 mol/kgNext, we need to find the boiling point elevation and freezing point depression:
ΔTb = Kb x molality
ΔTf = Kf x molality
For water, Kb = 0.512 °C/m and Kf = 1.86 °C/m.
ΔTb = 0.512 °C/m x 1.09 mol/kg = 0.558 °C
ΔTf = 1.86 °C/m x 1.09 mol/kg = 2.03 °C
Therefore, the boiling point of the solution is 100 + 0.558 = 100.558 °C, and the freezing point is 0 - 2.03 = -2.03 °C.
2. First, we need to calculate the molality of the benzoic acid solution:
molality = moles of solute / mass of solvent in kg
moles of benzoic acid = 80 g / 122.12 g/mol = 0.655 molmass of water = 800 g = 0.8 kgmolality = 0.655 mol / 0.8 kg = 0.819 mol/kgNext, we need to find the boiling point elevation and freezing point depression:
ΔTb = Kb x molality
ΔTf = Kf x molality
For water, Kb = 0.512 °C/m and Kf = 1.86 °C/m.
ΔTb = 0.512 °C/m x 0.819 mol/kg = 0.419 °C
ΔTf = 1.86 °C/m x 0.819 mol/kg = 1.52 °C
Therefore, the boiling point of the solution is 100 + 0.419 = 100.419 °C, and the freezing point is 0 - 1.52 = -1.52 °C.
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PLEASE HELP ASAP!!
Consider FIVE types of solids:
Ionic (NaCl)
Metallic (Ca)
Covalent Network (Quartz, SiO2)
Polar Molecular (sugar, C6H12O6)
Non-polar molecule
RECALL THE PHYSICAL PROPERTIES -> hardness, brittleness, the conductivity of electricity and heat, melting and boiling points, solubility in water, etc.
1. Design an experimental procedure to test these properties with the procedures below.
-> the ones I have so far
- ionic solids -> use NaCl and dissolve in water to test the solubility
- conductivity - by putting the solid under two free ends of the wire
-> solubility - using boiling water for all as ionic solids break into ions & conduct electricity
- brittleness - using a hammer or any other form of stress (if brittle, tends to break under stress)
- hardness - using a hydraulic press/Rockwell testing
- melting/boiling point - add heat to a sample after placing in a beaker or test tube to test
SOME OTHER THINGS WE CAN USE (but I'm unsure as to what we can use it for): a thermal camera
2. WRITE A HYPOTHESIS for ONE TYPE of solid with a brief explanation.
3. Design a Table of Observations for your experiments.
Hypothesis: Increasing the cooling rate during the solidification of aluminum will result in a finer grain structure in the final solid.
What is one example of hypothesis and explain?When a liquid metal such as aluminum is cooled and solidified, the atoms in the liquid begin to arrange themselves into a crystalline structure. The rate at which this happens can have a significant effect on the final microstructure of the solid. If the cooling rate is slow, larger grains will form as the atoms have more time to move and arrange themselves into larger clusters. If the cooling rate is faster, there is less time for the atoms to move and larger clusters cannot form, resulting in a finer grain structure. Therefore, the hypothesis proposes that increasing the cooling rate during the solidification of aluminum will lead to a finer grain structure in the final solid. This hypothesis could be tested by varying the cooling rate during the solidification process and then examining the microstructure of the resulting solid.
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Hypothesis: Increasing the cooling rate during the solidification of aluminium will result in a finer grain structure in the final solid.
What are the solid types?The following methods can be used to demonstrate whether a solid is:
Ionic (NaCl):
Solubility test: Since NaCl is extremely soluble in water, its ionic nature can be verified by this fact.
Conductivity test: NaCl transmits electricity when it is molten or dissolved because it contains charged ions.
Metallic (Ca):
Conductivity test: Due to the existence of free electrons within their crystal structure, metals like calcium carry electricity.
Ductility and malleability test: Due to their malleability and ductility, metals are readily deformed when under pressure.
Covalent Network (Quartz, SiO2):
Hardness test: Because of the intense covalent bonds between atoms, covalent network solids like quartz are exceedingly hard.
Melting point test: Due to the powerful intermolecular forces between atoms, covalent network solids frequently have high melting and boiling points.
Polar Molecular (sugar, C6H12O6):
Solubility test: Sugar and other polar compounds can dissolve in polar solvents like water but cannot dissolve in nonpolar solvents.
Melting and boiling point test: Due to weaker intermolecular interactions, polar molecular solids have lower melting and boiling points than ionic or covalent network solids.
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3. A student obtained the following data using the procedure used in this experiment.
BEFORE IGNITION
mass of crucible + crucible cover = 34.12 g
mass of crucible + cover + unknown sample = 36.65 g
AFTER IGNITION
mass of crucible + cover + unknown (1st weighing) = 35.67 g
mass of crucible + cover + unknown (2nd weighing) = 35.23 g
mass of crucible + cover + unknown (3rd weighing) = 35.20 g
Calculate the % water in the unknown sample:_______?
The percent of water in the unknown sample is calculated as 57.3%.
What is ignition?Process of providing energy that is required to initiate a combustion process is called ignition.
mass of crucible + cover + unknown sample = 36.65 g
mass of crucible + cover = 34.12 g
mass of unknown sample = (36.65 g - 34.12 g) = 2.53 g
mass of water lost during ignition:
mass of unknown sample (before ignition) = 2.53 g
mass of unknown sample (after 1st weighing) = 35.67 g - 34.12 g = 1.55 g
mass of unknown sample (after 2nd weighing) = 35.23 g - 34.12 g = 1.11 g
mass of unknown sample (after 3rd weighing) = 35.20 g - 34.12 g = 1.08 g
total mass of water lost during ignition = (2.53 g - 1.08 g) = 1.45 g
As % water in unknown sample = (mass of water lost / mass of unknown sample) x 100%
= (1.45 g / 2.53 g) x 100%
% water in unknown sample = 57.3%
Therefore, percent of water in the unknown sample is 57.3%.
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0.487 grams of quinine (molar mass = 324 g/mol) is combusted and found to produce
1.321 g CO2, 0.325 g H2O and 0.0421 g nitrogen. Determine the empirical and molecular
formulas.
molar mass of empirical formula = (20 x 12.01 g/mol) + (24 x 1.01 g/mol) + (1 x 14.01 g/mol) = 324.44 g/mol ratio = 324.44 g/mol / 324 g/mol = 1.001. The molecular formula of quinine is C20H24N.
What is used for quinine?The active component of cinchona extracts, which have been used for this purpose since before 1633, is utilized as an antimalarial medication. Quinine has been utilized in conventional cold remedies for its use as a mild antipyretic and analgesic.
What drug is quinine?Plasmodium falciparum malaria is treated with quinine. Malaria is brought on by the parasite Plasmodium falciparum, which enters the body through the red blood cells. Quinine functions by either eliminating the parasite or halting its growth.
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Calculate the hydronium ion concentration, [H3O+] , for a solution with a pH of 10.68 . [H3O+]= M
We know that pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance which is defined as the negative base 10 logarithm of the activity of hydrogen ions. Which states -
pH= - log [H⁺]= - log [H₃O⁺]As per question, we are given a pH value which is 10.68 for a solution and have asked to find out the hydronium ion concentration. Since we have the value of pH, so we can put into the formula and solve for [H₃O⁺] -
[tex] \:\:\:\:\:\:\longrightarrow \sf pH = 10.68\\[/tex]
[tex] \:\:\:\:\:\:\longrightarrow \sf - log [H₃O⁺] = 10.68 \\[/tex]
[tex] \:\:\:\:\:\:\longrightarrow \sf [H₃O⁺] = 10^{-10.68}\\[/tex]
[tex] \:\:\:\:\:\:\longrightarrow \sf \underline{[H₃O⁺] = 2.0893 \times 10^{-11}\:M} \\[/tex]
Therefore, the hydronium concentration for the solution is [tex]\underline{\: \sf 2.0893 \times 10^{-11}\:M }\\[/tex]
Match the following phase changes to their energy flow.
Evaporation
Melting
Freezing
Sublimation
Condensation
Deposition
[Choose]
[Choose]
Energy both absorbed and released
Energy absorbed
No energy flow
Energy released
[Choose]
[Choose]
[Choose ]
[Choose
Whereas freezing, condensation, or deposition are exothermic processes, fusion, vaporisation, and were endothermic processes. Changes in a system's energy occur together every phase transition.
During a phase change, what energy is altered?Potential energy is the type of energy that is transforming during a phase change. Either elevated body temperature (PE increases) and released (PE drops) throughout a phase change will permit the molecules either move apart or join together.
What 4 phase modifications are there?Melting is the process of changing from of the solid to liquid state. freezing: the transformation of a liquid into a solid. The process of evaporation is the change from a liquid to a gas. Condensing: The change from a gaseous to a liquid state.
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Hydrogen cyanide is a highly poisonous substance that can be prepared by the reaction of methane and ammonia:
CH4 (g) + NH3 (g) → HCN(g) + 3 H2 (g)
What is the heat of reaction at constant pressure? Provide an answer correct to 3 significant figures. Do not use scientific notation or include units to report your answer. You do need to include the sign as a part of your answer.
N2 (g) + 3 H2 (g) → 2 NH3 (g) ΔHrxn = -91.8 kJ;
C(s) + 2 H2 (g) → CH4 (g) ΔHrxn = -74.9 kJ;
2 C(s) + H2 (g) + N2 (g) → 2 HCN(g) ΔHrxn = +270.3 kJ
The heat of reaction at constant pressure when methane is reacted with ammonia to form hydrogen cyanide is 103.6kJ.
Given that Hydrogen cyanide which is a highly poisonous substance can be prepared by the reaction of methane and ammonia as follows:
[tex]CH_4 (g) + NH_3 (g) -- > HCN(g) + 3 H_2 (g)[/tex]
This is obtained through the following steps:
[tex]N_2 (g) + 3 H_2 (g) -- > 2 NH_3 (g)[/tex]; ΔHrxn = -91.8 kJ;
[tex]C(s) + 2 H_2 (g) -- > CH_4 (g)[/tex]; ΔHrxn = -74.9 kJ;
[tex]2 C(s) + H_2 (g) + N_2 (g) -- > 2 HCN(g)[/tex]; ΔHrxn = +270.3 kJ
The heat of reaction at constant pressure is the sum of the individual reactions such that:
[tex]\delta Hrxn = -91.8 kJ + (-74.9 kJ) + (270.3 kJ) = 103.6 kJ[/tex]
The heat of reaction is the total amount of energy released or absorbed when a chemical reaction occurs. It is calculated by adding the enthalpies of the reactants and subtracting the enthalpies of the products. Hence it concludes that when methane and ammonia react to form hydrogen cyanide, 103.6 kJ of energy is released.
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Define which are endothermic and exothermic
NaOH (s) → NaOH (aq)
NH4Cl (s) → NH4Cl (aq)
CaCl2 (s) → CaCl2 (aq)
HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l)
NaCl (s) → NaCl (aq)
Answer: NaOH (s) → NaOH (aq) is an exothermic process because energy is released when solid NaOH dissolves in water to form an aqueous solution.
NH4Cl (s) → NH4Cl (aq) is also an exothermic process for the same reason as NaOH above.
CaCl2 (s) → CaCl2 (aq) is also an exothermic process because energy is released when solid CaCl2 dissolves in water to form an aqueous solution.
HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l) is an exothermic process because energy is released as the acid-base reaction occurs and the products are formed.
NaCl (s) → NaCl (aq) is not an endothermic or exothermic process since there is no change in the state of the substance (solid to aqueous solution) and therefore no energy is either absorbed or released.
Explanation: Endothermic and exothermic refer to processes that either require energy to be absorbed or release energy to the surroundings.
In the given reactions, NaOH, NH4Cl, and CaCl2 dissolve in water to form aqueous solutions, and in doing so, they release energy to the surroundings, making these processes exothermic.
The reaction between HCl and NaOH also releases energy as the products are formed, and so it is also exothermic.
However, in the case of NaCl, there is no change in the state of the substance, and so no energy is either absorbed or released, making it neither endothermic nor exothermic.
What is the Molarity of a 0.5 Liter solution that contains 3.84 moles of NaCI?
SHOW WORK
Answer:
The molarity of a 0.5 L solution that contains 3.84 moles of NaCl is 7.68 M.
Here’s the work: Molarity (M) = moles of solute / liters of solution Substituting the given values into the equation: Molarity (M) = 3.84 moles / 0.5 L = 7.68 M.
How many total atoms are there in 62.5 g
of carbon disulfide ( CS2)?
Total atoms:
The answer is [tex]4.94 x 10^23[/tex] atoms.
To determine the total number of atoms in 62.5 g of carbon disulfide (CS2), we need to use Avogadro's number and the molecular weight of CS2.
The molecular weight of CS2 is:
Carbon atomic weight = 12.01 g/mol
Sulfur atomic weight = 32.06 g/mol
2 sulfur atoms x 32.06 g/mol + 1 carbon atom x 12.01 g/mol = 76.13 g/mol
Now, we can use the formula:
Number of moles = mass ÷ molecular weight
Number of moles of CS2 = 62.5 g ÷ 76.13 g/mol = 0.821 mol
Finally, we can use Avogadro's number, which is[tex]6.022 x 10^23[/tex] atoms per mole, to calculate the total number of atoms in 62.5 g of CS2:
Total atoms = Number of moles × Avogadro's number
Total atoms = 0.821 mol ×[tex]6.022 x 10^23[/tex] atoms/mol
Total atoms =[tex]4.94 x 10^23[/tex] atoms
Therefore, there are approximately[tex]4.94 x 10^23[/tex]atoms in 62.5 g of carbon disulfide (CS2).
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Question 7 of 10
When naming a molecule, how do you indicate that the carbons on either side
of the double bond are pointing in opposite directions?
OA. Use the prefix cis-.
OB. Use the prefix methyl-.
OC. Use the number 2 as a prefix.
OD. Use the prefix trans-.
Answer:
by using the prefix trans
Explanation:
i hope you find it helpful
At what temperature can you fully dissolve 140g of NaNO3?
Answer: The solubility of NaNO3 (sodium nitrate) in water increases as temperature increases. Therefore, we need to know the solubility of NaNO3 at different temperatures to determine the temperature at which 140 g of NaNO3 can be fully dissolved in water.
According to the solubility curve for NaNO3, the maximum solubility of NaNO3 in water is approximately 88 g per 100 g of water at 80°C. This means that at 80°C, we can dissolve 88 g of NaNO3 in 100 g of water to make a saturated solution.
To fully dissolve 140 g of NaNO3, we need to dissolve it in a sufficient amount of water that can dissolve at least 140 g of NaNO3. Using a proportion, we can calculate the amount of water required to dissolve 140 g of NaNO3 at 80°C:
88 g NaNO3 / 100 g water = 140 g NaNO3 / x g water
Solving for x, we get:
x = 159.1 g water
This means that at 80°C, we need to dissolve 140 g of NaNO3 in at least 159.1 g of water to make a saturated solution, in which all of the NaNO3 will be dissolved.
Therefore, the temperature at which 140 g of NaNO3 can be fully dissolved in water is approximately 80°C.
Explanation:
A mixture of 7.5 g
CH4
and 7.5 g
Xe
is placed in a container and the total pressure is found to be 0.52 atm
Find the partial pressure of CH4?
.
The partial pressure of CH₄ in the mixture is 0.464 atm.
What is the partial pressure of the CH₄?To find the partial pressure of CH₄ in the mixture, we need to use the following formula:
Partial pressure of CH₄ = Total pressure × mole fraction of CH₄
To calculate the mole fraction of CH₄, we need to first calculate the moles of each gas present in the mixture.
The number of moles can be calculated using the following formula:
moles = mass ÷ molar mass
The molar mass of CH₄ is 16.04 g/mol and the molar mass of Xe is 131.29 g/mol.
Moles of CH₄ = 7.5 g ÷ 16.04 g/mol = 0.467 mol
Moles of Xe = 7.5 g ÷ 131.29 g/mol = 0.057 mol
The total number of moles in the mixture is the sum of the moles of CH₄ and Xe:
Total moles = 0.467 mol + 0.057 mol = 0.524 mol
Now we can calculate the mole fraction of CH₄:
Mole fraction of CH₄ = Moles of CH₄ ÷ Total moles = 0.467 mol ÷ 0.524 mol = 0.891
Finally, we can use the formula for partial pressure to find the partial pressure of CH₄:
Partial pressure of CH₄ = Total pressure × mole fraction of CH₄
Partial pressure of CH₄ = 0.52 atm × 0.891 = 0.464 atm
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HELP
If you measured out 49.93 mL of a 1.000 M sodium hydroxide solution, how many moles of sodium hydroxide would be present?
Answer: 0.0499 moles of sodium hydroxide
Explanation:
We can determine the number of moles by using the Molarity equation:
Molarity = Moles / Volume (volume is always in Liters)
We have 2 out of 3 components of this equation
Molarity = 1.000 M
Volume = 49.93 mL / 1000 = 0.0499 L
So we rearrange the equation like the following:
Moles = Molarity x volume
= 1.000 Mx 0.0499 L
= 0.0499 moles of sodium hydroxide
Calculate the pH of 0.16M Ch3cooh which has ka = 1.74 × 10^ -5 mol dm^-3.
Answer: 2.78
Explanation:
To calculate the pH of 0.16M CH3COOH, we need to use the dissociation constant (Ka) of the acid, which is given as 1.74 × 10^-5 mol dm^-3.
The dissociation of CH3COOH is as follows:
CH3COOH + H2O ↔ CH3COO- + H3O+
The equilibrium constant expression for the dissociation of CH3COOH is:
Ka = [CH3COO-][H3O+] / [CH3COOH]
We can assume that [H3O+] is equal to [CH3COO-] since the acid is weak and will not dissociate completely. Therefore, the equilibrium constant expression can be simplified as:
Ka = [H3O+]^2 / [CH3COOH]
[H3O+]^2 = Ka x [CH3COOH]
[H3O+]^2 = 1.74 × 10^-5 x 0.16
[H3O+]^2 = 2.784 × 10^-6
[H3O+] = √2.784 × 10^-6
[H3O+] = 0.00167 M
Therefore, the pH of the solution can be calculated as:
pH = -log[H3O+]
pH = -log(0.00167)
pH = 2.78
Therefore, the pH of the 0.16M CH3COOH solution is 2.78.
A particular form of electromagnetic radiation has a frequency of 6.24 × 1014 Hz.
What is its wavelength in nanometers? In meters? Enter your answers in scientific notation.
Consider the cis and trans structures of 1,5 dimethyl decline.which one will be more stable?..
Explanation:
In the case of trans-decalin, there is no steric interaction between the rings because they are at their maximum distance. As a result, the trans conformation is more stable. Another reason is that trans-decalin does not undergo ring flipping. So, it remains rigid and is more stable.
Stearic interactions between the two rings result in a less stable conformation in case of cis-decalin.It undergoes ring flipping so, unstable conformation. (The First image)
Hence, trans-decalin is more stable than cis-decalin.(The second image)
Hopefully this helps! :)
PLS HELP ANWSER THIS QUESTIONS ILL GIVE YOU BRAINLIST PLEASE HELP
Iron reacts with oxygen gas to form a mixture of FeO and Fe₂O₃ when the supply of oxygen is regulated. A sample of 20.00 g iron metal reacts with oxygen gas to form 27.55 g iron oxide mixture, and all of the iron metal was consumed. What is the mass in g of FeO that were produced in the mixture?
The mass in of [tex]FeO[/tex] that were produced in the mixture is 8.49g when a sample of 20.00 g iron metal reacts with oxygen gas to form 27.55 g iron oxide mixture.
Given the mass of iron metal = 20.00g
The mass of iron oxide = 27.55g
Iron reacts with oxygen gas to form a mixture of [tex]FeO[/tex] and [tex]Fe2O3[/tex].
The reaction is as follows: [tex]3Fe + 2O2 --- > FeO + Fe2O3[/tex]
The mass of [tex]FeO[/tex] produced in the mixture can be determined using the following equation:
Mass of [tex]FeO[/tex] = Mass of Iron Oxide Mixture – Mass of [tex]Fe2O3[/tex]
Mass of [tex]FeO[/tex] = 27.55 g - Mass of [tex]Fe2O3[/tex]
as we can see from reaction that 3 moles of iron react to give 1 mole of [tex]Fe2O3[/tex] and 1 mole of [tex]FeO[/tex].
The molar mass of Fe (iron) is = 55.85g/mole and molar mass of [tex]Fe2O3[/tex] = 159.69g/mole
3 * 55.85g of Fe produces 1 * 159.69g of [tex]Fe2O3[/tex]
Then 20.00g of iron produces = 20 * 159.69/3 * 55.85 = 19.06g of [tex]Fe2O3[/tex]
Hence mass of [tex]FeO[/tex] produced = 27.55 - 19.06 = 8.49g
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