helppp me its need to be done quick

Answer:

Put your calculator in degree mode.

sin(35°) = 7/r

r sin(35°) = 7

r = 7/sin(35°) = 12.2 cm

Answer:

[tex]y = -2(x - 1)^2 + 3[/tex]

Step-by-step explanation:

The given figure which is a quadratic is the shape of a parabola

The general vertex form equation of a parabola is
[tex]y = a(x - h)^2 + k[/tex]

where,
( h, k ) is the vertex and a is a constant

Looking at the figure we see the vertex is at [tex](1, 3)[/tex]

So the equation of the parabola is

[tex]y = a(x - 1)^2 + 3[/tex]

To compute the constant [tex]a[/tex] take a point (x, y) through which the parabola passes, plug in these x, y values into the above equation and solve

The parabola passes through point   [tex](3, -5)[/tex]

Plugging

[tex]x = 3, y = -5[/tex]

gives
[tex]- 5 = a(3-1)^2 + 3\\\\-5 = a\cdot 2^2 + 3\\\\-5 = 4a + 3\\\\-5-3=4a\\\\-8 = 4a\\\\a = -8/4 = -2\\\\[/tex]

Therefore the equation of the given quadratic(parabola) is

[tex]y = -2(x - 1)^2 + 3[/tex]

The total cost of the several items that originally cost $128.25 with a coupon for 35% off and sales tax of 4% is C. $86.70.

The original cost is discounted by 35% using a discount factor of 0.65 and increased by a sales tax factor of 1.04.

After the multiplications, the product shows the total cost that Mary incurred for buying the items.

Original cost of several items Mary is buying = $128.25

Coupon discount = 35%

Discount factor = 0.65 (100 - 35)

Sales tax rate = 4%

Sales tax factor = 1.04 (100 + 4)

The total cost of the items = $86.70($128.25 x 0.65 x 1.04)

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The caloric content for ice cream C is 250 calories while the caloric content for ice cream B is 270 calories.

To determine the caloric content, we will assign algebraic notations to each of the dessert types.

1 Icecream + 2 Blueberry pie =   790 calories

3 icecream + 2 Blueberry pie = 1290 calories

Now the first equation will be subtracted from the second equation as follows:

2 icecream = 500 calories

So, 1 ice cream is 250 calories.

Also, since, 1 icecream serving equals 250 calories, 2 Blueberry pies = 790 - 250 = 540 calories, and 1 Blueberry pie equals 270 calories.

Complete question:

Johnny's cafe serves desserts. One serving of ice cream and two servings of blueberry pie provides 790 calories. Three servings of ice cream and two servings of blueberry pie provides 1290 calories. Find the caloric content of each item.

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By the Principle of Mathematical Induction, 2ⁿ≥2n is true for all positive integers.

The given inequality is 2ⁿ≥2n.

Let n = 1

2^1 ≥ 2^1

2 ≥ 2 which is true

Inductive Step: Assume 2ⁿ≥2n is true for some arbitrary positive integer k.

We need to prove that 2^(k+1) ≥ 2^(k+1)

2^(k+1) ≥ 2*2^k (by the inductive hypothesis)

2^(k+1) ≥ 2*2^(k+1)

2^(k+1) ≥ 2^(k+1) which is true

Therefore, by the Principle of Mathematical Induction, 2ⁿ≥2n is true for all positive integers.

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a) There are 2 x 2 = 4 sample points in the sample space

b) Tree Diagram

O D.\nH\nHe\nT\nH\nT\n

Sample space: D. HH, HT, TH, TT

c) P(no tails) = P(HH)

= 1/4

d) P(exactly one tail) = P(HT, TH)

= 2/4

= 1/2

e) P(2 tails) = P(TT)

= 1/4

f) P(at least one tail) = P(HT, TH, TT)

= 3/4

In mathematics, tree diagrams are often used in probability and statistics to show all the possible outcomes of an event. In computer science, they are used to represent the hierarchical structure of files and directories in a file system

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The half-life of the particular compound is approximately 9.4 days. (Correct choice: B)

The statement indicates the decay function of a particular compound, which is an exponential function of the form:

y = a · exp(- λ · t)

Where:

The half-life of the particular compound is determined by the following expression:

t = ㏑ 2 / λ

Where t is the half-life.

If we know that λ = 0.0736, then the half-life of the particular compound is:

t = ㏑ 2 / 0.0736

t = 9.4 days

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The solution of the trigonometric problem is  y = -3

Starting with the equation

3/2 cos^-1(y/6) = pi

First, we can simplify by dividing both sides by 3/2 ....

cos^-1(y/6) = pi / (3/2)

cos^- 1(y/6) = 2pi / 3

Next, we can take the cosine of both sides to get...

cos (cos^-1(y/6 ) )

= cos( 2pi/3)

y/6 = -1/2

y = -3

Therefore, the exact solution to the equation 3/2 cos^-1(y/6) = pi is y = -3.

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The expression can be simplified to get:

2.7^(1)*3.8^(5)

The correct option is C.

Remember that if we have the product of two powers with the same base, we only need to add the exponents.

Then we will get:

2.7^(-3) * 3.8^(2) * 2.7^(4) * 3.8^(3)

= (2.7^(-3)*2.7^(4)*3.8^(2)*3.8^(3))

= (2.7^(-3 + 4)*3.8^(2 + 3))

= 2.7^(1)*3.8^(5)

That is the expression simplified, we can see that the correct option is C.

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Option D is the correct synthetic division of (x^2-4x+7) divided by (x-2)

Synthetic division is a shorthand procedure used to divide a polynomial by a linear factor of (x - a) form, in which "a" is constant. This method gives an expedient way to locate the quotient and remainder without carrying out long division.

x - 2 | x^2 - 4x + 7

            x^2 - 2x

           ---------

                 -2x + 7

                 -2x + 4

                 -------

                        3

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Answer:

i believe 67 its somewhat hard to tell but the line seems to be in the middle between 150 and 140

Step-by-step explanation:

since it heats up to 212 then the person lets it cool down for 10 mins the temp goes to 145 (Answer is 67)

In ΔFGH,  the length of h is 714.2 cm

Let us assume that in ΔFGH, f represents the opposite side to angle F, g represents the opposite side to angle G,  and h represents the opposite side to angle H.

Consider the following figure.

Using sine rule for triangle FGH,

sin F/f = sin G/g = sin H/h

Consider equation sin G/g = sin H/h

sin(98°) / 910 = sin(51°) / h

We solve this equation for h.

h = (sin(51°) × 910)/ sin(98°)

h =  (0.777 × 910)/ 0.99

h = 714.21

h = 714.2 cm

This is the required length of h.

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Unit fractions are the fraction in which the value of numerator is 1. The multiple of the given fraction are,

1/9 = 2/9, 3/9, 4/9,5/9         ......so on.

Here, we have,

To find the multiple of the fraction 1/9 we need to know about the multiple of fraction.

We have,

Multiple of fraction is the number which is n times of the original function. Here  can be any whole or fraction number.

The given number in the problem is the fraction number which is,

The above number is the unit fraction.

Unit fraction-

Unit fractions are the fraction in which the value of numerator is 1.

The multiple of unit fraction is in times the original function. For the given fraction the multiple fraction can be given as,

1/9 = 2/9, 3/9, 4/9,5/9            .......so on.

Hence the multiple of the given fraction are,

1/9 = 2/9, 3/9, 4/9,5/9             ......so on.

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There are 1100 many ways can be done that is when catering service offers 5 appetizers, 11 main courses, and 4 desserts.

Given that,

A catering service offers 5 appetizers, 11 main courses, and 4 desserts. A customer is to select 4 appetizers, 9 main courses, and 3 desserts for a banquet.

We have to find how many ways can this be done.

We know that,

Number of appetizers offered = 5

Number of appetizers customer is to select = 4

Number of main courses offered = 11

Number of main courses customer is to select = 9

Number of desserts offered = 4

Number of desserts the customer is to select = 3

So,

To determine the number of ways this can be selected,

By using the combination formula that is

[tex]^nC_r = \frac{n!}{r!(n-r)!}[/tex]
[tex]^nC_r = ^5C_4\times ^{11}C_9\times^4C_3[/tex]

[tex]^5C_4\times ^{11}C_9\times^4C_3 = \frac{5!}{4!(5-4)!} \times \frac{11!}{9!(11-9)!}\times \frac{4!}{3!(4-3)!}[/tex]

[tex]^5C_4\times ^{11}C_9\times^4C_3 = \frac{5!}{4!1!} \times \frac{11!}{9!2!}\times \frac{4!}{3!1!}[/tex]

[tex]^5C_4\times ^{11}C_9\times^4C_3 = \frac{5!}{4!} \times \frac{11!}{9!(2)}\times \frac{4!}{3!}[/tex]

[tex]^5C_4\times ^{11}C_9\times^4C_3 =[/tex] 5 × 11 × 5 × 4

[tex]^5C_4\times ^{11}C_9\times^4C_3 =[/tex] 1100

Therefore, There are 1100 many ways this can be done.

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Answer:

Expected number of times to roll a total of 5 = Probability of rolling a total of 5 x Total number of rolls

                                                      = (1/9) x 180

                                                      = 20

Step-by-step explanation:

The diagram is not visible in the question. However, I can provide a general method to solve the problem.

a) To find the probability of rolling a total of 5, we need to count the number of ways we can get a sum of 5 and divide it by the total number of possible outcomes. From the diagram, we can see that there are four ways to get a sum of 5: (1,4), (2,3), (3,2), and (4,1). Since each die has six equally likely outcomes, there are 6 x 6 = 36 possible outcomes in total. Therefore, the probability of rolling a total of 5 is:

Probability of rolling a total of 5 = Number of ways to get a total of 5 / Total number of possible outcomes

                                   = 4/36

                                   = 1/9 (in its simplest form)

b) If we rolled a pair of fair dice 180 times, the expected number of times we would roll a total of 5 can be calculated as follows:

Expected number of times to roll a total of 5 = Probability of rolling a total of 5 x Total number of rolls

                                                      = (1/9) x 180

                                                      = 20

The product of the two external segments and the sum of the lengths of each segment in the circle are equal if two secants are drawn to the circle from a single shared exterior point. The x has a value of 2 units.

If two secant segments are drawn to a circle from an exterior point, the product of the measurements of one secant segment and its external secant segment is equal to the product of the measurements of the second secant segment and its external secant segment.

So, we know that:

BE * AE = CE * DE

Now, insert the values as follows:

(x+1) * (x+12) = (x+4) * (x+5)

x² + x + 12x + 12 = x² + 4x + 5x + 20

13x + 12 = 9x + 20

4x = 8x

x= 2

Then: x = 2 units

Therefore, the product of the two external segments and the sum of the lengths of each segment in the circle are equal if two secants are drawn to the circle from a single shared exterior point. The x has a value of 2 units.

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Answer:

15 19/20

Step-by-step explanation:

95 cents means 95/100 then reduce that and you get 19/20 and then on the end you still have the $15

needs more explanation

Step-by-step explanation:

y=m(x-x1)+y1

y=-2(x-4)+0

y=2x-8+0

y=2x-8

The original price of this car is equal to $6,600.

In Mathematics, a percentage can be defined as any number that is expressed as a fraction of hundred (100). This ultimately implies that, a percentage indicates the hundredth parts of any given number.

Assuming the original price is represented by the variable x, we have the following:

12.5/100 × x = x - 5,775

0.125x = x - 5,775

5,775 = (x - 0.125x)

5,775 = 0.875x

x = 5,775/0.875

x = $6,600.

In conclusion, we can logically deduce that the percentage Pat Bain paid is 87.5%.

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Answer:

$12,276.24

Step-by-step explanation:

22000 / (1 + 0.105/12)^4*12

12276.24

Step-by-step explanation:

To solve the inequality:

-3 > 5 - b

We can start by isolating the variable b on one side of the inequality. We can do this by subtracting 5 from both sides of the inequality:

-3 - 5 > -b

Simplifying the left-hand side of the inequality, we get:

-8 > -b

To isolate b, we can multiply both sides of the inequality by -1. When we do this, we need to reverse the inequality sign:

8 < b

So the solution to the inequality is:

b > 8

This means that b must be greater than 8 for the inequality to be true.

The value of k that satisfies the given condition is approximately 0.4041.

In the expansion of (1+kx)⁵, the coefficient of x⁵ is given by the term:

C(5,k) * (kx)⁵ = k⁵ * C(5,k) * x⁵

where C(5,k) is the binomial coefficient or the number of ways to choose 5 items out of k.

So, we have the equation:

k⁵ * C(5,k) = -672

We can use a table of binomial coefficients to find C(5,k) for different values of k, but this can be time-consuming. Alternatively, we can use the fact that C(5,k) = C(5,5-k) and rewrite the equation as:

k⁵ * C(5,5-k) = -672

Expanding C(5,5-k), we get:

k⁵ * C(5,5-k) = k⁵ * C(5,k) = -672

Now, we can use trial and error to solve for k. Using this method, we can find that k = -4 or k ≈ 0.4041. However, since k must be positive (since it appears as a factor in the expansion), the only valid solution is k ≈ 0.4041.

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Answer:

1. f. System of Equations

2. e. No solutions

3. i. One solution

4. h. Like Terms

5. b. Substitution

6. c. Solution

7. a. Elimination

8. d. Infinitely Many Solutions

9. g. Variable

10. j. Coefficients

Step-by-step explanation:

Ur welcome :)

Answer:

gain of 700 or 700

Step-by-step explanation:

A loss of 700 would be -700 and the opposite of that is 700.

Helping in the name of Jesus.

The domain of the 1st piece is -10 < x < 0, for 2nd piece is 0 < x < 4, and for 3rd piece is 4 < x < 8.

A function is a particular kind of relationship where there is a set domain and range, and every input value in the domain is associated with a single output value in the range.

We have a piecewise function shown in the picture:

From the graph:

f(x) = -2, Domain: -10 < x < 0

f(x) = 2x + 1, Domain: 0 < x < 4

f(x) = (-1/2)x, Domaim: 4 < x < 8

Thus, the domain of the 1st piece is -10 < x < 0, for 2nd piece is 0 < x < 4, and for 3rd piece is 4 < x < 8.

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The first 5 terms in the sequence are 5, 4.75, 4.5, 4.25 and 4

From the question, we have the following parameters that can be used in our computation:

Using the above as a guide, we have the following:

a2 = -0.25 + a1

So, we have

a2 = -0.25 + 5 = 4.75

For other terms. we have

a3 = -0.25 + 4.75 = 4.50

a4 = -0.25 + 4.50 = 4.25

a5 = -0.25 + 4.25 = 4.0

Hence, the first 5 terms in the sequence are 5, 4.75, 4.5, 4.25 and 4

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Therefore , the solution of the given problem of unitary method comes out to be once more administer maths and science quizzes on the same day.

The well-known minimalist approach, current variables, and any crucial elements from the initial Diocesan tailored query can all be used to accomplish the work. In response, you can be granted another chance to utilise the item. If not, important impacts on our understanding of algorithms will vanish.

Here,

List the multiples of each integer until we discover a common multiple as one method to determine the least common multiple:

=> 8, 16, 24, 32, 40, 48, 56, 64, 72, and 80 are all multiples of 8.

=> 6, 12, 18, 24, 30, 36, 42, 48, 54, and 60 are multiples of 6.

As an alternative, we can use the prime factorization technique to identify the smallest common multiple:

=> 8's prime factors are 2 x 2 x 2

=> 6's prime factors are 2 x 3

=> 2 x 2 x 2 x 3 = 24

We can see that 24 is the smallest common multiple once more, and in 24 days,

Mrs Hopkins will once more administer maths and science quizzes on the same day.

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Answer:

B) 48

Step-by-step explanation:

3, 13, 22, 30, 37, 43…

3 to 13 is +10

13 to 22 is +9

22 to 30 is +8

We are adding one less each time

3, 13  , 22,   30,   37,    43   …

 +10  +9   +8    +7    +6    +5

Add 5 to 43

43+5 = 48