I NEED HELP ON THIS ASAP! PLEASE IT'S DUE TODAY, I WILL GIVE BRAINLIEST!!

Answer: 15 letters.

Step-by-step explanation:

When p is the number of letters being engraved:

12.5 + .4p = 14.75 + .25p

-12.5             -12.5

.4p = 2.25 + .25p

-.25p          -.25p

.15p = 2.25

/.15     /.15

p = 15

There would need to be 15 letters engraved for the cost of the trophies to be the same. Hope this helps!

Applying the arc length formula, the radius of the circle is calculated as: r = 9 units.

In a circle, the measure of an angle in radians is related to the length of the intercepted arc and the radius by the formula:

arc length = radius * angle measure

In this case, we are given that the angle measure is π radians and the arc length is 9π. Substituting these values into the formula, we get:

9π = r * π

where r is the radius of the circle.

Simplifying this equation, we can divide both sides by π:

9 = r

Therefore, the radius of the circle is 9.

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The ratio of the surface area to volume of a right rectangular prism with a square base and a height that is triple the base edge is 6:1.

Let x be the length of one side of the square base of the prism. Then the height of the prism is 3x. The surface area of the prism is given by 2x² + 4(x)(3x) = 14x², since there are two square faces with area x² each and four rectangular faces with area x(3x) each.

The volume of the prism is x²(3x) = 3x³. Therefore, the ratio of surface area to volume is (14x²)/(3x³) = 14/3x = 4.67/x. Since x is a length, it must be positive, so the ratio is minimized when x is as large as possible.

Therefore, the smallest possible ratio is when x approaches infinity, and in this limit, the ratio approaches 0. However, in the real world, x must be finite, so the ratio is always greater than 0.

We can see that the ratio decreases as x increases, so the smallest possible ratio occurs when x is as small as possible.

The smallest possible positive value of x is 0.000000...01, which is very close to 0 but not equal to 0. Therefore, the ratio is always greater than 0 but can be made arbitrarily small.

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The student's use of the t procedure for a confidence interval was appropriate because the sample size was greater than 30 and the population standard deviation was unknown. A 95% confidence interval was calculated using the t-distribution.

It was an appropriate use of the t procedure for a confidence interval. The student wanted to assess the average time spent studying for his most recent exam taken in class, and he used a sample of 45 students to estimate the population mean with a 95% confidence interval.

Since the population standard deviation is not known, the student used the t-distribution to calculate the confidence interval. The t-distribution is used when the sample size is small, and the population standard deviation is unknown.

The student assumed that the sample was randomly selected, and the data was approximately normally distributed. By using the t procedure, the student was able to estimate the population mean with a margin of error and a level of confidence of 95%.

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The optimization problem has a maximum value of P when x = 13 and y = 6.5. The maximum value of P = 13 * 6.5 = 84.5.

To solve the optimization problem and maximize P = xy with the constraint x + 2y = 26, follow these steps:

1. Express one variable in terms of the other using the constraint: x = 26 - 2y

2. Substitute the expression for x into the objective function P: P = (26 - 2y)y

3. Differentiate P with respect to y to find the critical points: dP/dy = 26 - 4y

4. Set the derivative equal to zero and solve for y: 26 - 4y = 0 => y = 6.5

5. Plug the value of y back into the expression for x: x = 26 - 2(6.5) => x = 13

6. Check the second derivative to confirm it's a maximum: d²P/dy² = -4 (since it's a constant negative, this confirms it's a maximum)

Thus, the optimization problem has a maximum value of P when x = 13 and y = 6.5. The maximum value of P = 13 * 6.5 = 84.5.

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Answer:

x = 16

Step-by-step explanation:

Multiply the entire first equation by -5 and the entire second equation by 2.

You then get:

15x + 20y = 200

2x - 20y = 72

Add the two equations and you get:

17x = 272

Divide 17 from both sides and you get the answer you need:

x = 16

Step-by-step explanation:

Los 10 m representan 1/3 del camino, ya que si sumamos 10 + 20 + 30, obtenemos la distancia total del camino, que es 60 m.

Si la casa se encuentra a 25 m del camino, entonces está a una distancia de 5 m del final del camino, ya que 25 + 5 = 30. Por lo tanto, la casa está a 2/3 del camino, es decir, a una fracción de 2/3 de la distancia total del camino.

La casa está representada a 2/3 del camino, lo que corresponde a una distancia de 40 m (2/3 de 60 m). Por lo tanto, la casa está representada a 40 m del comienzo del camino.

Los 20 m representan 1/3 del camino, ya que si sumamos 10 + 20 + 30, obtenemos la distancia total del camino, que es 60 m. Por lo tanto, los 20 m representan la misma fracción que los 10 m, que es 1/3 del camino.

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4.87% of toddlers at home had behavioral problems, according to the parents surveyed.

The Illinois study examined the effect of day care on the behavior of toddlers by surveying randomly selected parents. There were two groups of parents: those with a toddler in full-time day care and those with a toddler at home.

In the first group, 987 parents with a toddler in full-time day care were surveyed. Among these parents, 212 reported that their child had behavioral problems. To calculate the percentage of children with behavioral problems in this group, we can use the following formula:

(212/987) x 100 = 21.48%

In the second group, 349 parents with a toddler at home were surveyed. Among these parents, 17 reported that their child had behavioral problems. To calculate the percentage of children with behavioral problems in this group, we can use the following formula:

(17/349) x 100 = 4.87%

The study found that 21.48% of toddlers in full-time day care had behavioral problems, whereas 4.87% of toddlers at home had behavioral problems, according to the parents surveyed.

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The First derivative: f'(x) = 12x - 15 and the Interval of increasing: (5/4, ∞) and the Interval of decreasing: (-∞, 5/4)

Hi! I'd be happy to help you with your question. Let's compute the first derivative, and then determine the intervals of increasing and decreasing:

Given function: f(x) = 2.3 + 6x^2 - 15x + 3

(a) Compute the first derivative, f'(x):
f'(x) = d(2.3)/dx + d(6x^2)/dx - d(15x)/dx + d(3)/dx
f'(x) = 0 + 12x - 15 + 0
f'(x) = 12x - 15

(c) To find the interval where f is increasing, we need to find where f'(x) > 0:
12x - 15 > 0
12x > 15
x > 15/12
x > 5/4

So, the interval of increasing is (5/4, ∞).

(d) To find the interval where f is decreasing, we need to find where f'(x) < 0:
12x - 15 < 0
12x < 15
x < 15/12
x < 5/4

So, the interval of decreasing is (-∞, 5/4).

Your answer:
- First derivative: f'(x) = 12x - 15
- Interval of increasing: (5/4, ∞)
- Interval of decreasing: (-∞, 5/4)

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The average number of vehicles registered in each borough of NYC is 4.2 x 10^5.

To find the average number of vehicles registered in each borough of NYC, we need to divide the total number of registered vehicles by the number of boroughs. Therefore, the average number of vehicles registered in each borough can be calculated as:

Average number of vehicles = Total number of vehicles registered / Number of boroughs

= 2.1 x 10^6 / 5

= 4.2 x 10^5

Therefore, the average number of vehicles registered in each borough of NYC is 4.2 x 10^5.

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The rate of change for the linear function represented in the table is 3/5.

In Mathematics and Geometry, the gradient, rate of change, or slope of any straight line can be determined by using the following mathematical equation;

Rate of change (slope) = (Change in y-axis, Δy)/(Change in x-axis, Δx)

Rate of change (slope) = rise/run

Rate of change (slope) = (y₂ - y₁)/(x₂ - x₁)

By substituting the given data points into the formula for the slope of a line, we have the following;

Rate of change (slope) = (y₂ - y₁)/(x₂ - x₁)

Rate of change (slope) = (69 - 66)/(5 - 0)

Rate of change (slope) = 3/5

Based on the table, the rate of change is the change in y-axis with respect to the x-axis and it is equal to 3/5.

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After integrating with respect to y and then x, we get the value of the integral accurate to 2 decimal places as -21.98.

First, let us express the limits of integration. Since the region R is defined in the rectangular coordinate system, we can express the limits of integration as follows:

9 < x² + y² < 49

-3 < x < 0

Next, we need to express the integral in terms of these limits of integration. The integral of 2x over the region R can be expressed as:

∫∫R 2x dA = ∫-3⁰ ∫√(9-x²)√(49-x²) 2x dy dx = -21.98

Here, we have used the fact that the region R is defined as {(x, y) | 9 < x² + y² < 49, x < 0}.

The limits of integration for y are determined by the equation of the circle centered at the origin with radius 7 and the equation of the circle centered at the origin with radius 3.

Now, we can evaluate the integral using the double integral formula.

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The equation which represents the volume of each cone is as follows:

V = (1/3)πr²h

Explanation :

In this equation, "V" represents the volume of the cone, "r" represents the radius of the base, and "h" represents the height of the cone.

V represents the volume of the cone. Volume is a measure of the space occupied by an object, and in this case, it refers to the space inside the cone.

π (pi) is a mathematical constant approximately equal to 3.14159. It is used in calculations involving circles and spheres.

r represents the radius of the base of the cone. The radius is the distance from the center of the base to any point on its circumference. Squaring the radius, r², gives us the area of the base.

h represents the height of the cone. It is the perpendicular distance from the base to the vertex (top) of the cone.

When we multiply the area of the base (πr²) by the height (h) and divide the result by 3, we get the volume of the cone. The division by 3 is necessary because the volume of a cone is one-third the volume of a cylinder with the same base and height.

So, the equation V = (1/3)πr²h provides a way to calculate the volume of a cone based on its radius and height.

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Sure, happy to help! So, we have two furniture manufacturers producing chairs, and we'll call them Plant X and Plant Y. Let x represent the number of chairs produced daily at Plant X, and let y represent the number of chairs produced daily at Plant Y.

Now, we don't know what the actual numbers are, but we can use these variables to talk about them in a general way. For example, we could say that Plant X produces 100 chairs per day (so x = 100), and Plant Y produces 200 chairs per day (so y = 200).

Does that make sense? Let me know if you have any other questions!

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Nadia brought five tickets to attend a spaghetti supper fund rasier at her school. The equation 5x = 32.50 can be used to find x, the cost of each ticket in dollars. The equation x = 32.50/5 will represent the cost of each ticket.

This is because the equation 5x = 32.50 is asking us to find the cost of each ticket (represented by x) when there are five tickets in total and the total cost is $32.50.

To solve for x, we need to isolate it on one side of the equation. We can do this by dividing both sides by 5, which gives us:

X=32.50/5.

So, each ticket costs $6.50.

Therfore, the correct equation that represents the cost of each ticket is X=32.50/5, option A.

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The derivative of the equation g(x) = 8x^2 – 4; h(x) = 1.6^x is f'(x) = 40.96x · 1.6^x - 15.040128 · 1.6^x

To find the derivative of f(x) = g(x) · h(x), we use the product rule of derivatives, which states that if f(x) = u(x) · v(x), then f'(x) = u'(x) · v(x) + u(x) · v'(x).

Using this rule, we can find the derivative of f(x) = g(x) · h(x) as follows:

f(x) = g(x) · h(x) = (8x^2 – 4) · (1.6^x)

f'(x) = g'(x) · h(x) + g(x) · h'(x) [applying the product rule]

To find g'(x), we take the derivative of g(x) = 8x^2 – 4, which is:

g'(x) = 16x

To find h'(x), we take the derivative of h(x) = 1.6^x, which is:

h'(x) = ln(1.6) · 1.6^x [using the chain rule and the fact that the derivative of a^x is ln(a) · a^x]

h'(x) ≈ 0.470004 · 1.6^x

Now we substitute these values into the product rule formula:

f'(x) = (16x) · (1.6^x) + (8x^2 – 4) ·0.470004 · 1.6^x

Simplifying this expression, we get:

f'(x) = 25.6^x + (12.8x^2 – 6.4) ·0.470004 · 1.6^x

f'(x) = 40.96x · 1.6^x - 15.040128 · 1.6^x
Therefore, the derivative of f(x) = g(x) · h(x) is:
f'(x) = 40.96x · 1.6^x - 15.040128 · 1.6^x

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For the first question:
There are 6 notes and 6 envelopes, so there are 6! (or 720) possible ways to insert the notes into the envelopes. Only one of these ways will result in all notes being inserted into the correct envelopes. Therefore, the probability is 1/720 or 0.001389.

For the second question:
(A) There are 2 gold courses and twice as many bronzes as silver courses, so there are 2 + 2x + x = 20 courses in total, where x is the number of silver courses. Solving for x, we get x = 6. Therefore, there are 2 + 6 + 12 = 20 possible courses to select from if the golfer decides to play a round at a silver or gold course.

(B) If the golfer decides to play one round per week for 3 weeks, there are 12 possible combinations of courses to play. To see why, consider the following cases:
Week 1: bronze, Week 2: silver, Week 3: gold
Week 1: bronze, Week 2: gold, Week 3: Silver
Week 1: silver, Week 2: bronze, Week 3: gold
Week 1: silver, Week 2: gold, Week 3: bronze
Week 1: gold, Week 2: bronze, Week 3: Silver
Week 1: gold, Week 2: silver, Week 3: bronze

Each case has 2 possible choices for the bronze course, 6 possible choices for the silver course, and 2 possible choices for the gold course, for a total of 2 x 6 x 2 = 24 possible combinations. However, since the order of the courses doesn't matter, we must divide by 3! (or 6) to get rid of the extra permutations. Therefore, there are 24/6 = 4 possible combinations for each case, giving a total of 6 x 4 = 24 possible combinations of courses to play.

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If A car accelerates away from the starting line at 3. 6 m/s2 and has a mass of 2400 kg, Therefore, the net force acting on the vehicle is 8640 N.

The net force acting on the vehicle can be calculated using Newton's second law of motion, which states that the force applied to an object is equal to its mass multiplied by its acceleration:

Net force = mass x acceleration

In this case, the mass of the car is 2400 kg and the acceleration is 3.6 m/s^2. Thus, we can calculate the net force as:

Net force = 2400 kg x 3.6 m/s^2

Net force = 8640 N

Therefore, the net force acting on the vehicle is 8640 N.

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The art room at Johnson Elementary School has a storage room with the are of 165 square feet. The length of one wall is 15 feet. The width of the storage room 11 feet. The perimeter of the room is 52 feet.

Find the width of the storage room, we need to use the formula for area:
Area = Length x Width
We know that the area is 165 square feet and the length is 15 feet, so we can plug those values in and solve for the width:
165 = 15 x Width
Width = 11
So the width of the storage room is 11 feet.
Find the perimeter of the room, we need to add up the lengths of all four walls. We know that one wall is 15 feet, and since the opposite wall must also be 15 feet to maintain the same area, we can add up the remaining two walls:
Perimeter = 2 x (15 + Width)
Perimeter = 2 x (15 + 11)
Perimeter = 2 x 26
Perimeter = 52
So the perimeter of the storage room is 52 feet.

The width of the storage room 11 feet. The perimeter of the room is 52 feet.

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The equation in two variables that describes how the amount of cat food in the bag changes over time is: A = 10 - 0.3t
Where A represents the amount of cat food left in the bag after t days, and t represents the number of days that have passed since Simon bought the bag.

The variable A is the dependent variable because it depends on the value of t. As time passes and t increases, the amount of cat food left in the bag decreases. The variable t is the independent variable because it is the input that determines the value of A.

For example, after one day (t = 1), Simon will have used 0.3 pounds of cat food and there will be 9.7 pounds left in the bag (A = 10 - 0.3(1) = 9.7). After two days (t = 2), he will have used 0.6 pounds of cat food and there will be 9.4 pounds left in the bag (A = 10 - 0.3(2) = 9.4), and so on.

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Using the value of λ = (18 + √130)/18, we get: x = 3λ ≈ 4.895 y = 3λ - 3 ≈ 5.316 So the point on the curve that is furthest from P is approximately (4.895, 5.316).

To use the method of Lagrange multipliers, we first need to define our objective function and our constraint. Our objective function is the distance between the point P and a point on the curve, which can be expressed as:

f(x, y) = (x - 0)^2 + (y - 3)^2 = x^2 + (y - 3)^2

Our constraint is the equation of the curve:

g(x, y) = x^2 + y^2 - 6x + 7 = 0

To use the method of Lagrange multipliers, we need to introduce a new variable λ and solve the following system of equations:

∇f = λ∇g
g(x, y) = 0

where ∇f and ∇g are the gradients of f and g, respectively.

Taking the partial derivatives of f and g with respect to x and y, we have:

∂f/∂x = 2x
∂f/∂y = 2(y - 3)
∂g/∂x = 2x - 6
∂g/∂y = 2y

Setting ∇f equal to λ∇g, we have:

2x = λ(2x - 6)
2(y - 3) = λ(2y)

Simplifying these equations, we get:

x = 3λ
y = 3λ - 3

Substituting these expressions into the equation of the curve, we get:

(3λ)^2 + (3λ - 3)^2 - 6(3λ) + 7 = 0

Simplifying this equation, we get:

18λ^2 - 36λ + 13 = 0

Solving for λ, we get:

λ = (18 ± √130)/18

Substituting these values of λ into our expressions for x and y, we get the coordinates of the points on the curve that are closest to and furthest from the point P.

To find the point that is closest to P, we need to minimize the objective function f(x, y). Using the value of λ = (18 - √130)/18, we get:

x = 3λ ≈ 1.105
y = 3λ - 3 ≈ -0.316

So the point on the curve that is closest to P is approximately (1.105, -0.316).

To find the point that is furthest from P, we need to maximize the objective function f(x, y). Using the value of λ = (18 + √130)/18, we get:

x = 3λ ≈ 4.895
y = 3λ - 3 ≈ 5.316

So the point on the curve that is furthest from P is approximately (4.895, 5.316).

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The lateral surface area of the roof can be found by subtracting the area of the base from the total surface area:1581.84 sq ft

Assuming the roof is a cone:

The slant height of the cone can be found using the Pythagorean theorem:

l = √(r^2 + h^2) = √(15^2 + 30^2) = 33.541 ft

The area of the roof can be found using the formula for the surface area of a cone:

A = πr^2 + πrl = π(15)^2 + π(15)(33.541) ≈ 1800.66 sq ft

The lateral surface area of the roof can be found by subtracting the area of the base from the total surface area:

L = πrl = π(15)(33.541) ≈ 1581.84 sq ft

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Answer:

x = 73, y = 88, z = 45

Step-by-step explanation:

40+52+y = 180 (Angle Sum Property)

=> y = 180-40-52

=> y = 88

x + (15 + 40) + 52 = 180 (Angle Sum Property)

=>x = 180 - 52 - 55

=> x = 73

40 + 43 + (52+z)  = 180

=> z = 180 -53 - 40 -43

=> z = 45

The inequality given by Mrs. Mueller is x>6, which means that x is greater than 6. To check which student has given the correct response, we need to check if their values of x satisfy the given inequality.

Looking at the table, we see that all four students have given values of x that are greater than 6. However, we need to choose the student who has given the correct response to the inequality.

Jacob has given the response 8, which satisfies the inequality x>6. Kendra has given the response 10, which also satisfies the inequality. Luke has given the response 12, which is also greater than 6 and satisfies the inequality. Maya has given the response 10, which is the same as Kendra's response and also satisfies the inequality.

Therefore, we can say that all four students have given correct responses to Mrs. Mueller's inequality.

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The number of dolphins that will be there in the year 2100 is 1003, under the condition that in the Gulf of Mexico has been decreasing at a rate of 4% every 10
years.

Here the population of dolphins in the Gulf of Mexico in 2020 was 4,670.The rate of decrease is 4% every 10 years.
Therefore, the population would  decrease by 4% every 10 years.
We want to evaluate the population in 2100, which is  80 years from now, which is eight 10-year periods.
Now, we have to calculate the population after eight 10-year periods.
Each period would decrease the population by 4%.
Hence, the population after eight periods is
4670 × (1 - 0.04)⁸
= 4670 × (0.96)⁸
= 1003

Then, if things progress like this, the population of dolphins in the Gulf of Mexico in the year 2100 will be close to 1000.
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a. To determine the optimal values of the two thresholds s and S, we can use the Miller-Orr cash management model. The objective is to minimize the total cost of cash management, which includes transaction costs and the opportunity cost of holding cash.

Let's assume that the transaction cost of $5 applies whenever the cash balance in the checking account goes below s or above S. The expected daily cash balance is zero since expenses and earnings are equally likely, and the standard deviation of the cash balance is σ = √(t/2), where t is the time interval.

The optimal value of s is given by:

s* = √(3rT/4C) - σ/2,

where T is the length of the cash management period, and C is the fixed cost per transaction. The optimal value of S is given by:

S* = 3s*,

which ensures that the probability of a cash balance exceeding S is less than 1/3.

Using r = 0.1, T = 1 day, and C = $5, we obtain:

s* = √(30.11/4*5) - √(1/2)/2 = $16.82

S* = 3*$16.82 = $50.47

Therefore, the optimal values of the two thresholds are s* = $16.82 and S* = $50.47.

b. The long run average cost associated with the optimal cash management strategy can be calculated as:

Total cost = (s*/2 + S*) * σ * √(2r/C) + C * E(N),

where E(N) is the expected number of transactions per day. Since expenses and earnings are equally likely, E(N) = (S* - s*)/2 = $16.83. Therefore, the total cost is:

Total cost = ($16.82/2 + $50.47) * √(1/2) * √(2*0.1/$5) + $5 * $16.83 = $1.38 per day.

Now let's consider the strategy with the same s but with a maximum amount of cash equal to 2S. The expected daily cash balance is still zero, but the standard deviation is now σ' = √(t/3). The optimal value of S' is given by:

S' = √(3rT/2C) - σ'/2 = $35.35.

The long run average cost associated with this strategy is:

Total cost' = (s/2 + S') * σ' * √(2r/C) + C * E(N'),

where E(N') is the expected number of transactions per day. Since the maximum amount of cash is now 2S, we have E(N') = (2S - s)/2 = $34.59. Therefore, the total cost is:

Total cost' = ($16.82/2 + $35.35) * √(1/3) * √(2*0.1/$5) + $5 * $34.59 = $1.30 per day.

Therefore, the strategy with the same s but with a maximum amount of cash equal to 2S is slightly more cost-effective in the long run.

c. One common criticism of this model is that it assumes a constant transaction cost, which may not be realistic in practice. In reality, transaction costs may vary depending on the size and frequency of transactions, and may also depend on the banking institution and the type of account. Another criticism is that it assumes a random walk model for expenses and earnings, which may not capture the

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The height of the second bridge that Armando needs to design is 40 feet (Option C).

To get the height of the second bridge designed by Armando, we need to maintain the same ratio between the length and height as in the first suspension bridge drawing. The first bridge has a length of 230 ft and a height of 50 ft.
First, find the ratio of the height to the length of the first bridge:
50 ft (height) / 230 ft (length) = 5/23
Now, we know the length of the second bridge is 184 ft. To get the height of the second bridge, we will use the same ratio (5/23) and multiply it by the length of the second bridge:
(5/23) * 184 ft = 40 ft
So, the height of the second bridge that Armando needs to design is 40 feet (Option C).

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The number of cubical containers which are 9 cm long, 8cm wide, and 6 cm high completely filled with lemonade is 5.

volume of lemonade = 2160 cm³

Dimensions of container

L = 9 cm , B = 8 cm , H = 6 cm

Volume of container = L× B × H

Volume of container = 9×8×6

Volume of container = 432 cm³

To find the number of cubical containers filled we use

Number of containers filled = volume of lemonade/volume of the container

putting the value in formula

Number of container filled = 2160/432

Number of container filled = 5

Total number of container filled with lemonade is 5

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The value of measure of arc QI is,

⇒ m QI = 94°

We have to given that;

⇒ m YS = 180°

⇒ m ∠QBI = 137°

Hence, We can formulate;

⇒ m ∠QBI = 1/2 (m YS + m QI)

⇒ 137 = 1/2 (180 + m QI)

⇒ 274 = 180 + m QI

⇒ m QI = 274 - 180

⇒ m QI = 94°

Thus, The value of measure of arc QI is,

⇒ m QI = 94°

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Answer: x + 4.8 = 14.3

Step-by-step explanation:

Let x be the initial amount of water that was already in the bucket before the additional 4.8 liters of water was poured in.

Then the total amount of water in the bucket after pouring in the 4.8 liters is the sum of the initial amount x and the amount of water poured in, which is 4.8 liters. This can be represented by the equation:

x + 4.8 = 14.3

We can simplify this equation by solving for x:

x = 14.3 - 4.8

x = 9.5

Therefore, the initial amount of water in the bucket was 9.5 liters, and after pouring in 4.8 liters, the bucket contained a total of 14.3 liters.